"Y is directly related to the square of x" is represented by the polynomial equation y = kx². A polynomial equation is one that has the polynomial factored down to zero.
What is meant by polynomial equation?Polynomial equations would be those created using exponent, variables, and factors. The greater of its potential exponents is referred to as the equation's degree. By multiplying polynomials as according their degree and the variables in the equation, we can find the solutions.
What is a polynomial equation's degree?The highest or greatest power of a variable in a polynomial equation is referred to as the degree of the polynomial. The degree denotes the polynomial's highest exponential power (ignoring the coefficients).
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In a laboratory experiment, a student was exploring the stretch of a spring based on the pull of the force. The student used weights of 1 N, 2 N, 3 N, 4 N, and 5 N. The points were plotted, and the relationship was analyzed. The graph is shown.
A graph titled stretch versus force is shown with stretch on the vertical axis and force on the horizontal axis. The graph is a straight diagonal line from bottom left to top right going through points 0 comma 0, 1 comma 1.0, 2 comma 3.6, 3 comma 5.5, 4 comma 7.2, and 5 comma 9.1.
Which of the following values would be considered an extrapolation?
Force = 1 N, stretch = 1.9 cm
Force = 3 N, stretch = 5.5 cm
Force = 4.6 N, stretch = 8.3 cm
Force = 5.4 N, stretch = 9.6 cm
An extrapolation from the graph given the points on the line of best fit is Force = 5.4 N, stretch = 9.6 cm.
What is Hooke's law?The Hooke's law states that as long as the elastic limit is not exceeded, the extension of the object is proportional to the magnitude of the force that have been applied. This would help us answer the question
Now we can see that in the plot of the Hooke's law, the force have been plotted on the horizontal axis and the extension or the stretch have been plotted on the vertical axis. The areas that runs through the line of best fit have been shown ad from this line of best fit we could be able to obtain an extrapolation.
The point on the graph that can be regarded as an extrapolation is the point that have been marked Force = 5.4 N, stretch = 9.6 cm.
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Answer:
the answer is D
Explanation:
force+5.4N, stretch=9.6
50 POINTS!!!!!
A skier traveling at 31.3 m/s encounters a 20 degree slope. If you could ignore friction, to the nearest meter, how far up the hill does he go?
121 m far up the hill does he go.
Vo = 31.3 m/s
Angle [tex]\theta[/tex] = [tex]20^o[/tex]
Yo = 31.3*sin20
= 28.57 m/s.
[tex]Y^2 = Yo^2 + 2g*h = 0.[/tex]
[tex]28.57^2 - 19.6h = 0 \\19.6h = 816.4\\ h = 41.6 m.[/tex]
[tex]d*sin20 = 41.6\\ d = 121 m. -- > up \ hill.[/tex]
What is friction?Friction is a force that opposes the relative motion of solid surfaces, fluid layers and material elements that slide against each other.
There are four types of friction and they are classified as follows:
Static friction Sliding friction Rolling friction Fluid frictionApplications of friction
Friction is used when matches burn. The movement of the pistons in the cylinder is due to friction. It is possible to write on books and blackboards because there is friction between the pen and the blackboard.To learn more about friction, refer;
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Leah was pulling on a wagon with a force of 156N at an angle of 38 degrees. if she moves the wagon 45.5m how much work has she done
Answer:
W = 5593.3 J
Explanation:
The work can be calculated as
W = Fdcosθ
Where F is the force, d is the distance and θ is the angle.
So, replacing F = 156N, d = 45.5 m and θ = 38, we get:
W = (156N)(45.5m)(cos38)
W = (156N)(45.5m)(0.788)
W = 5593.3 J
the total amount of work that must be done to compress the string against the restoring force represents the
Answer:
Potential energy.When string is stretched x is -ve and during compression x=+ve. In either cases, work will be done by spring to restore itself to the original shape. Hence, this Potential Energy is the work done against its restoring force.Two 5.0-cm-diameter metal disks separated by a 0.68-mm-thick piece of Pyrex glass are charged to a potential difference of 1800 V.
a) What is the surface charge density on the disk?
b) What is the surface charge density on the glass?
The surface charge density on the disk is 1.73 x 10⁻⁸ C/m².
The surface charge density of the glass is 9.36 x 10⁻⁵ C/m²
What is the magnitude of the charge?The magnitude of the charge is calculated as follows;
V = kQ/r
where;
V is the potential differencek is Coulomb's constantq is magnitude of the charger is the distance of separationkQ = Vr
Q = Vr/k
Q = (1800 x 0.68 x 10⁻³) / (9 x 10⁹)
Q = 1.36 x 10⁻¹⁰ C
The surface charge density of the disk is calculated as follows;
σ = Q/A
σ = Q/(4πr²)
where;
r is the radius of the disk = 5 cm / 2 = 2.5 cm = 0.025 mσ = Q/(4πr²)
σ = (1.36 x 10⁻¹⁰ )/(4π x 0.025²)
σ = 1.73 x 10⁻⁸ C/m²
The surface charge density of the glass is calculated as follows;
σ = Q/A
σ = Q/(4πr²)
where;
r is the radius of the glass = 0.68 mm / 2 = 0.34 mm = 0.00034 mσ = Q/(4πr²)
σ = (1.36 x 10⁻¹⁰ )/(4π x 0.00034²)
σ = 9.36 x 10⁻⁵ C/m²
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Astrologers claim that your personality traits are determined by the positionsof the planets in relation to you at birth. Scientists argue that these gravitationaleffects are so small that they are totally insignificant. Compare the gravitationalattraction between you and Mars to the gravitational attraction between youand your 70.0 kg doctor at the moment of your birth, if the doctor stands0.500 m away (Note: MM = 6.42 x 10^23 ky, de to M = 7.83 x 10^10 m. This is theaverage distance between Earth and Mars. This distance varies as the twoplanets orbit the sun.)
ANSWER:
The force exerted by the doctor is greater
STEP-BY-STEP EXPLANATION:
Given:
Mass of Mars = 6.42 x 10^23 kg
Mass of Doctor = 70 kg
Mass at birth = m
Distance between Earth and Mars = 7.83 x 10^10 m
Distancia Doctor = 0.5 m
G = 6.67 x 10^- 11 N*m^2/kg^2
We calculated the force in each based on the mass at birth.
[tex]\begin{gathered} F_{mars}=\frac{G\cdot M_{mars}\cdot m}{d_{EM}^2}=\frac{6.67\cdot10^{-11}\cdot6.42\cdot10^{23}}{(7.83\cdot10^{10})^2}m=6.98\cdot10^{-9}m \\ F_{doc}=\frac{G\cdot M_{doc}\cdot m}{d_2^2}=\frac{6.67\cdot10^{-11}\cdot70}{\left(0.5\right)^2}\:m=1.87\cdot10^{-8}m \end{gathered}[/tex]Which means that the force exerted by the doctor is greater
What forward force must the ground apply to the foot of a 60.0kg person to result in an acceleration of 1.00 m/s^2?
Answer:
F=ma
=60×1
=60N
Explanation:
straightforward formula
What is the voltage across a 100 Ω resistor with a current of 4.5 amps?
We can use the following equation to solve for V, voltage:
V = IR, where
I: current, and R: resistance
Let's plug in our known variables, current and resistance:
V = 4.5*100
Then solve for V:
V = 450V
PLEASE HELP ME I NEED THIS ASAP
Investigating Energy Systems
Harnessing Human Energy Chapter 1 Lesson 1.2
Reasoning Tool
Possible subclaims:
The Battery System does have energy.
or
The Battery System does not have energy.
The Hand-Crank Generator System does have energy.
or
The Hand-Crank Generator System does not have energy.
The Solar Cell System does have energy.
or
The Solar Cell System does not have energy.
Evidence
(observations about whether the system does or does not have energy)
This matters because . . .
(How does this evidence support the subclaim?)
Therefore, . . .
(subclaim)
Considering the energy systems:
The Battery System does have energy because it can be used to light a bulb for example.The Hand-Crank Generator System does have energy because turning the lever generates electrical energy.The Solar Cell System does have energy because it can light a bulb.What is energy?Energy is the ability to do work.
There are several forms of energy such as:
chemical energy - energy stored in chemical bondsSolar energy - energy from the radiation of the sunLight energy - energy from the sensation of lightSound energy -Mechanical energy - there are two forms; kinetic energy and potential energyElectrical energy is the energy due to the movement of electrons.Generally, all matter possesses energy that can be used to do work.
The various forms of energy can be interconverted.
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Which of the following statements accurately describe a scientific law?
Answer:
Explanation:
Scientific laws or laws of science are statements, based on repeated experiments or observations, that describe or predict a range of natural phenomena.
a skier has just begun descending a 20 degrees slope. assuming that the coeffecient of the friction 0.10 calculate
acceleration of the skier
the final velocity of the skier after 8.0 s
A skier has just begun descending a 20° slope, so the Acceleration of the skier will be -4.7 m/s².
What is average velocity?Average velocity is a vector quantity. The change in position or displacement divided by the periods during which the displacement happens is known as average velocity. Depending on how the displacement is displaced, the average velocity may be positive or negative. Meters per second (m/s), the SI unit of average velocity, is used.
Average Velocity= [tex]Total\ Displacement/ Total\ Time[/tex]
According to the question,
Skier is on a 20° down slope.
Portion of weight parallel to and down slope.
f₁ = (sin20°)mg = 0.3 × mg
The friction force resists motion parallel to the slope, therefore its sign is opposite that of f1, and it is equal to the kinetic coefficient of friction times the weight's surface normal component.
f₂ = -μ(cos30°)mg = -0.9*0.8660 × mg
f₂ = -0.7794 × mg
The net force on the skier parallel to and down the slope
F = f₁ + f₂ = (0.3 -0.7794)mg
F = -0.4794 × mg
By Newton’s second law, net acceleration parallel to and down slope.
a = F/m = -0.4794 × g
For g = 9.807 m/s²,
a = -0.4794 × 9.807 = -4.7 m/s².
So, the acceleration of the skier will be -4.7 m/s².
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Calculate the energy needed to raise the temperature of 1 kg of lead (specific heat capacity of 130 J/kg °C) from 40.0 °C to 60.0 °C
The energy needed to raise the temperature of 1 kg of lead from 40 °C to 60°C will be 2600 Joules.
We can calculate the energy of a substance by using the given formula:
Q = mc∆T
where;
Q = quantity of heat absorbed or released
m = mass of the substance
c = specific heat capacity
∆T = change in temperature(°C)
Now, according to the given question, 1 kg of lead has to be raised from 40°C to 60°C and we also have the specific heat capacity(c) of lead that is 130J/kg°C.
We can calculate the energy by putting the given values in the above equation:
Q = mc∆T
= 1 × 130 × (60-40)
= 20 × 130
Q = 2600J
Therefore, the amount of energy required to raise the temperature of 1 kg of lead from 40°C to 60°C is 2600J.
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PLS HELP
What group and period would this element be in from the picture below?
Describe how you determined it’s place.
What family does it belong to?
PLSSSS HELP
Based on the structure of the element shown, the element belongs to group 2A of the periodic table.
What are families in the periodic element?Families of elements in the periodic table refer to the elements that are found in the same vertical column in the periodic table.
The families of elements in the periodic table are also called groups.
Elements belonging to the same family in the periodic table have similarities in their properties, both physical and chemical.
The group or family to which an element belongs to depends on the number of electrons found in the valence shell of the element.
Elements in the same group have the same number of electrons in their valence shells. For example, elements in group 1A of the periodic table have one valence electron in their valence shell.
Considering the given element;
The element has three electron shells.
In the valence or outermost shell, there are 2 electrons in the atom of the element. This means that the element would belong to the family of elements that have two valence electrons, group 2A.
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Which factor is a direct cause of surface currents
Answer: global wind systems
Explanation: Surface currents in the ocean are driven by global wind systems that are fueled by energy from the Sun. Patterns of surface currents are determined by wind direction, Coriolis forces from the Earth's rotation, and the position of landforms that interact with the currents.
Which is expected to have the largest dispersion forces?
options:
C9H20
F2
CH4
PH3
C9H20 is expected to have the largest dispersion forces among the given four options.
The strength of dispersion force increases with number of electrons in the molecule.
Number of electrons in an element = Atomic number * Number of atoms
Atomic number of
C = 6H = 1O = 8F = 9P = 15Number of electrons in C9H20 = ( 6 * 9 ) + ( 1 * 2 ) + ( 8 * 1 )
Number of electrons in C9H20 = 64
Number of electrons in F2 = 9 * 2
Number of electrons in F2 = 18
Number of electrons in CH4 = ( 6 * 1 ) + ( 1 * 4 )
Number of electrons in CH4 = 10
Number of electrons in PH3 = ( 15 * 1 ) + ( 1 * 3 )
Number of electrons in PH3 = 18
Therefore, C9H20 is expected to have the largest dispersion forces.
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A ferry approaches shore, moving north with a speed of 6.2 m/s relative to the dock. A person on the ferry walks from one side of the ferry to the other, moving east with a speed of 1.4 m/s relative to the ferry.
What is the speed of the person relative to the dock?
Express your answer using two significant figures and include the appropriate units
So, we have that the speed of the person relative to the dock is 6.36 m/s
How to calculate the speed of the person relative to the dock?Let
v = velocity of person relative to ferry, V = velocity of ferry relative to dock and V' = velocity of person relative to dockwhere their speeds are the magnitudes of their velocities
Given that a ferry approaches shore, moving north with a speed of 6.2 m/s relative to the dock and a person on the ferry walks from one side of the ferry to the other, moving east with a speed of 1.4 m/s relative to the ferry.
We have that their velocities are
v = (1.4 m/s)iV = (6.2 m/s)jSo, V' = v + V
So, V' = (1.4 m/s)i + (6.2 m/s)j
So, the speed of the person relative to the dock is the magnitude of V which is
V' = √(v² + V²)
So, substituting the value of the variables into the equation, we have
V' = √(v² + V²)
V' = √[(1.4 m/s)² + (6.2 m/s)²]
V' = √[1.96 m²/s² + 38.44 m²/s²]
V' = √[40.4 m²/s²]
V' = 6.36 m/s
So, the speed of the person relative to the dock is 6.36 m/s
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A 16 kg mass travelling to the right at 5 m/s collides with a 4 kg mass travelling to the left, also at 5 m/s. When the masses collide, they stick together and move along the same line as before.
After the collision:
d) What is the total momentum of the masses?
e) What is the velocity of the masses?
Total momentum of masses after collision is : 100kgm/s
velocity of the masses after collision is : 5m/s
Explanation :
The conservation of momentum principle states that the amount of momentum within a problem domain remains constant; momentum is neither created nor destroyed, but only changed by the action of forces as described by Newton's laws of motion.
To find total momentum ,
we have to find momentum of each object .
Momentum of object with 16kg masses,
p = mv
here m = 16 kg and v = 5m/s
p1 =16×5
=80kgm/s
momentum of object with 4kg masses, and v =5m/s
p2 = 4 x 5
= 20kgm/s
total momentum is,
P = p1 + p2
80 + 20 = 100kgm/s
total momentum after collision,
100kgm/s (law of conservation of momentum)
velocity of masses is ,
total p= (m1+m2)×v
100 = (16+4)v
v = 100÷20
v = 5m/s
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A polar bear initially running at 4.0 m/s accerlerates uniformly for 18 s. If the bear travels 135 m in this time what is it's maximum speed
Answer:
Explanation:4.0-135m/ 18s = 131/18s = -7.2 m/
In a restaurant, one cook slides a 215-g delicious pizza down the counter from left to right at 1.63 m/s. At nearly the exact same time, another cook launches a 349-g cheeseburger along the same counter from right to left at 2.10 m/s. The two items collide head‑on at the given speeds – the counter is friction‑free due to accumulated grease – and combine into a single, wonderful concoction. At what speed does the dish move?
The speed at which the dish move after combining into a single, wonderful concoction is 1.92 m / s
p = m v
p = Momentum
m = Mass
v = Velocity
According to law of conservation of momentum,
Total initial momentum = Total Final momentum
[tex]m_{1}[/tex] [tex]v_{1}[/tex] + [tex]m_{2}[/tex] [tex]v_{2}[/tex] = [tex]m_{1}[/tex] [tex]v_{1}[/tex]' + [tex]m_{2}[/tex] [tex]v_{2}[/tex]'
Since the dish is combined into a single, wonderful concoction, it will move with the same velocity,
[tex]v_{1}[/tex]' = [tex]v_{2}[/tex]' = v'
[tex]m_{1}[/tex] [tex]v_{1}[/tex]+ [tex]m_{2}[/tex] [tex]v_{2}[/tex] = [tex]m_{1}[/tex] v' + [tex]m_{2}[/tex] v'
[tex]m_{1}[/tex] [tex]v_{1}[/tex] + [tex]m_{2}[/tex] [tex]v_{2}[/tex] = ( [tex]m_{1}[/tex] + [tex]m_{2}[/tex] ) v'
v' = ( [tex]m_{1}[/tex] [tex]v_{1}[/tex] + [tex]m_{2}[/tex] [tex]v_{2}[/tex] ) / ( [tex]m_{1}[/tex] + [tex]m_{2}[/tex] )
[tex]m_{1}[/tex] = 215 g
[tex]m_{2}[/tex] = 349 g
[tex]v_{1}[/tex] = 1.63 m / s
[tex]v_{2}[/tex] = 2.10 m / s
Substituting these values in v'
v' = [ ( 215 * 1.63 ) + ( 349 * 2.10 ) ] / ( 215 + 349 )
v' = ( 350.43 + 732.9 ) / 564
v' = 1083.33 / 564
v' = 1.92 m / s
Therefore, the dish moves at 1.92 m / s
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Serna
All changes saved
3. What stroke of an engine moves the piston down into the engine and causes the top of
cylinder to open and mix air and fuel?
Answer:
See below
Explanation:
INTAKE - compression - power - exhaust for a 4 stroke engine
Answer: intake
Explanation:
I took the quiz.
Calculate the force of attraction between Mars and one of its moon named Phobos given that the mass of Phobos is 10.6 x 1015 kg and the distance from Mars is 9,376 km (convert to m). Mars has a mass 10.7% that of Earth (approx. 1/10th the mass of Earth).
The force of attraction between Mars and one of its moon; F= 5.16*10²¹
What does gravity mean?The gravitational force is the force that the earth exerts on a body to attract it. Examples of motion caused by gravitational force include the downward motion of water in rivers and streams, the upward motion of thrown objects such as balls, and the downward motion of the leaves and fruits of trees as they fall to the earth.
What is a phobos?"The bigger of Mars' two moons, Phobos, measures 17 x 14 x 11 miles (27 x 22 x 18 kilometers) in diameter. It makes three daily circuits around Mars and is so near the planet's surface that it cannot always be seen there."
according to data:The product of mass and mass is directly proportional to the gravitational force between two large objects. The gravitational attraction between Mars and Phobos is.
Newton's law of universal gravitation: Fg = Gm1m2/r2
Where,
F = Force =
G = Gravitational constant = 6.6743 × 10-11 N.m²/kg²
m2 = Mass of Mars = 6.42 x 10²³ (approx 10.7 % of Earth)
m2 = Mass of Phobos = 10.6 x 1015 r = Distance between centers of the masses= 9,376 km
Put the values in the formula,
F = 6.6743 * 10-11 * [tex]\frac{6.42 x 10^2^3 * 10.6 x 10^1^5}{ 9,376^2}[/tex] F= 5.16*10²¹
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Billie travels 3.2 km due east in 0.1 hr, then 3.2 km at 15.0 degrees eastward of due north in 0.21 hr, and finally another 3.2 km due east in 0.1 hr. What is the magnitude of his average velocity for the entire trip?
Average velocity is total distance divided by total time. The magnitude of his average velocity for the entire trip is 23.15 m/s
What is Velocity ?Velocity is the distance travel in a specific direction per time taken. It is a vector quantity. And it is measured in m/s
If Billie travels 3.2 km due east in 0.1 hr, then 3.2 km at 15.0 degrees eastward of due north in 0.21 hr, and finally another 3.2 km due east in 0.1 hr. Then,
Billie total distance S travel = 3.2 + 3.2Cos 15 + 3.2
S = 9.49 Km
Billie total time T = 0.1 + 0.21 + 0.1
T = 0.41 s
The magnitude of his average velocity for the entire trip = S/T
Average velocity = 9.49/ 0.41
Average velocity = 23.15 m/s
Therefore, the magnitude of his average velocity for the entire trip is 23.15 m/s
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module 2 question 10
A ship sets sail from Rotterdam, The Netherlands, heading due north at 9.00 m/s relative to the water. The local ocean current is 1.52 m/s in a direction 40° north of east. What is the velocity of the ship relative to the earth?
m/s
° N of E
The velocity of the ship heading due north at 9.00 m/s relative to the water has a velocity of 10 m / s relative to the earth.
Let S represent ship, W represent water and E represent Earth.
[tex]V_{SW}[/tex] = 9 m / s N
[tex]V_{WE}[/tex] = 1.52 m / s NE
Resolving [tex]V_{OE}[/tex] into its x and y components.
cos θ = Adjacent side / Hypotenuse
cos 40° = [tex]V_{OE}_{x}[/tex] / [tex]V_{OE}[/tex]
[tex]V_{WE}_{x}[/tex] = 0.77 * 1.52
[tex]V_{WE}_{x}[/tex] = 1.17 m / s
sin θ = Opposite side / Hypotenuse
sin 40° = [tex]V_{OE}_{y}[/tex] / [tex]V_{OE}[/tex]
[tex]V_{WE}_{y}[/tex] = 0.64 * 1.52
[tex]V_{WE}_{y}[/tex] = 0.97 m / s
[tex]V_{SE}[/tex] = [tex]V_{SW}[/tex] + [tex]V_{WE}[/tex]
[tex]V_{X}[/tex] = [tex]V_{SW}_{x}[/tex] + [tex]V_{WE}_{x}[/tex]
[tex]V_{X}[/tex] = 0 + 1.17
[tex]V_{X}[/tex] = 1.17 m / s
[tex]V_{Y}[/tex] = [tex]V_{SW}_{y}[/tex] + [tex]V_{WE}_{y}[/tex]
[tex]V_{Y}[/tex] = 9 + 0.97
[tex]V_{Y}[/tex] = 9.97 m / s
R = √ [tex]V_{X}[/tex]² + [tex]V_{Y}[/tex]²
R = √ 1.17² + 9.97²
R = √ 1.37 + 99.4
R = √ 100.77
R = 10 m / s
Therefore, the velocity of the ship relative to the earth is 10 m / s
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PLEASE HELP! 20 points!!
The infamous chicken is dashing toward home plate with a speed of 5.8m/s when he decided to hit the dirt. The chicken slides for 1.1s. Just reaching hte plate as he stops(safe, of course). (A)What is the magnitude and direction of the chickens acceleration? (B) How far did the chicken slide?
please show all work!
The chicken needs to have an acceleration such that after time t his Velocity is 0, shown in the equation:
0 = V + at
-5.8 = 1.1 x a
a = -5.8 / 1.1
a = -5.2727 m/s/s.
The distance traveled in a time t with velocity V and acceleration is given by:
D = Vot + 1/2 at2
D = 5.8 x 1.1 - 1/2 x 5.2727 x 1.12
D = 3.19m.
Acceleration is the name we give to the process of changing velocity. Velocity is both speed and direction, so there are only two ways to accelerate. Either change speed, change direction, or change both. There are three main types of accelerated motion uniform acceleration, unequal acceleration, and average acceleration.
The term uniform acceleration refers to the motion of a body moving in a straight line with an increasing velocity at equal time intervals. Velocity is the rate of change of displacement. Acceleration is the rate of change of velocity. Velocity is a vector quantity because it consists of both magnitude and direction. Since acceleration is the rate of change of velocity it is also a vector quantity. Acceleration occurs whenever an object increases or decreases its speed or changes direction.
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A +15μC point charge is placed 10cm from a +7µC point charge. 1. Find the force experienced by the +15μC charge.
The electric force on the charge Fc = 9.439 x 10⁹N(m/C)²
Equation :To calculate the electric force on different charges and a certain distance,
Use formula,
Fc = k (q₁q₂)/r²
Where,
Fc is electric force
k is coulomb's constant
q₁ is charge at one point
q₂ is charge at second point
r is the distance
Known values,
q₁ = 15μC
q₂ = 7μC
k = 8.99 × 10⁹ Nm² /C²
r = 10cm
Fc = ?
Now, putting the values
Fc = 8.99 × 10⁹ Nm² /C² (15μC x 7μC)/(10cm)²
Fc = 8.99 × 10⁹ N(m/C)² x 1.05
Fc = 9.439 x 10⁹N(m/C)²
Hence, the electric force is Fc = 9.439 x 10⁹N(m/C)².
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You are holding a 200-g apple.
What is the force that you exert on the apple?
What is the force that the apple exerts on you? Support your answer with free
body diagrams.
On the apple, we apply "antigravitational force."
The apple exerts "gravitational force" on us.
The gravitational attraction, an attractive force whose magnitude is directly proportional to the masses of the two objects and inversely proportional to the square of their distance from one another, draws all mass-containing things together.
You can never decrease the gravitational pull produced by adding mass. It is possible for gravitational forces acting in opposition to one another to cancel one another out and leave no net force. It would be conceivable for gravity to push objects instead of always dragging them if it weren't always additive.
A place or thing being free from the pull of gravity is the goal of the hypothetical phenomena known as anti-gravity. It doesn't mean balancing the force of gravity with another force, like electromagnetism or aerodynamic lift, or the lack of weight under gravity felt in free fall or orbit.
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A motorcycle travels at 55m / s, taking 5s to stop and relax Relax. Calculate the acceleration of that motor.
The acceleration of the motorcycle = -11m/s²
Explanation:The initial speed of the motorcycle, u = 55 m/s
The motorcycle takes 5 seconds to stop and relax
That is, the final speed, v = 0 m/s
Time, t = 5 seconds
Acceleration = (Change in speed)/Time
[tex]\begin{gathered} a=\frac{v-u}{t} \\ a=\frac{0-55}{5} \\ a=\frac{-55}{5} \\ a=-11m/s^2 \end{gathered}[/tex]The acceleration of the motorcycle = -11m/s²
1. A Styrofoam box (k=0.01 J/(s*m*C) containing ice water at 0 C has a total area of 0.950m^2 and walls with thickness 2.50 cm in a 35 C room. What is the heat flow through the walls?1. 13.3 W2. 0.133 W3. 0.147 W4. 14.7 W
Explanation:
The heat flow can be calculated as
[tex]Q=kA\frac{T_1-T_2}{L}[/tex]Where k is the thermal conductivity, A is the area, T1 is the temperature of the ice water, T2 is the temperature of the room, and L is the thickness.
Replacing k = 0.01 J/(s m °C), A = 0.950 m², T1 = 0°C, T2 = 35 °C and L = 2.50 cm = 0.025 m, we get
[tex]\begin{gathered} Q=(0.01\frac{J}{s\text{ m }\degree C})(0.95\text{ m}^2)\frac{0\degree C-35\degree C}{0.025\text{ m}} \\ \\ Q=-13.3\text{ W} \end{gathered}[/tex]Therefore, the heat flow through the walls is 13.3 W.
The negative sign indicates the direction of the heat flow, in this case, the heat goes to the water.
During the experiment, the angular velocity will be allowed to vary. If the mass of the rotating object is 5 kg and the radius of rotation is 0.2 m, what will be the angular velocity, ω, when the force sensor reads 3.4 N?
Answer: w=1.84 rad/s
Explanation:
During the experiment, the angular velocity will be allowed to vary. If the mass of the rotating object is 5 kg and the radius of rotation is 0.2 m, what will be the angular velocity, ω, when the force sensor reads 3.4 N?
first we set 3.4N = to the equation [tex]5kg(w)^{2}* .20[/tex]
solving for w [tex]w^2=17/5[/tex]
[tex]w=(\sqrt{85})/5 \\[/tex]
[tex]w=1.84391[/tex]
w=1.84 rad/s
Sanjay uses 225 N of force to move a wheelbarrow 18 m at a velocity of 1.8 m/s. What was the amount of power used?
Considering the definition of power, the amount of power used was 405 W.
Definition of powerPower is the amount of work (force or energy applied to a body) in a unit of time.
In this sense, mechanical power is the amount of force applied to a body in relation to the speed with which it is applied.
Mathematically, the power P is the result of multiplying the force by the execution speed:
P = F×v
where
P is the power expressed in Watts (W).F is the force expressed in newtons (N).v is the speed expressed in meters per second (m/s).Amount of power used in this caseIn this case, you know:
Force applied F = 225 N Distance moved = 18 mVelocity v = 1.8 m/sReplacing in the definition of power:
P = 225 N× 1.8 m/s
Solving
P= 405 W
Finally, the amount of power in this case is 405 W.
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