Rick recorded the information shown below. What type of graph would be the most appropriate for Rick to use
A Line graph
Sure hope this helps you
Find the sum or difference
(X-2)+(x+6)
The sum of the expression (x - 2) and (x+6) is 2x + 8
How to find sum of an expression?The sum of numbers simply means to add up the numbers.
Therefore,
(x -2) + (x + 6)
Hence,
(x - 2) + (x + 6)
open the brackets
Therefore,
x - 2 + x + 6
combine like terms
x + x + 2 + 6
add or subtract the like terms
2x + 8
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rewrite! Write an new and equivalent equation that is easier to solve
[tex]\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}[/tex]
Given - an equation in it's general formTo do - convert the given equation into a form that is easy to solveGiven equation -
[tex]\bold{(x + 2) {}^{2} + 4(x + 2) - 5 = 0} \\ [/tex]
solve the parenthesis so as to obtain simpler terms
[tex]\bold{\implies \: ( x {}^{2} + 4x + 4 ) + 4x + 8 - 5 = 0}\\ [/tex]
solve the like terms and you'll obtain the required equation !
[tex]\bold{\implies \: x {}^{2} + 8x - 7 = 0}[/tex]
hope helpful ~
[tex]{\large{\red{\mapsto{\maltese{\underline{\green{\boxed{\blue{\underbrace{\overbrace{\pink{\pmb{\bf{Answer:}}}}}}}}}}}}}}[/tex]
x = -7, -1
Step-by-step explanation:
[tex] \sf {(x + 2)}^{2} + 4(x + 2) - 5 = 0[/tex]
let (x + 2) = y
So equation will be
[tex] \sf {y}^{2} + 4y - 5 = 0[/tex]
Further it becomes quadratic equation
we will solve it by breaking middle term method
[tex] \sf \implies {y}^{2} + 5y - y - 5 = 0 \\ \\ \sf \implies y(y + 5) - 1(y + 5) = 0 \\ \\ \sf \implies (y + 5)(y - 1) = 0[/tex]
Now put the value of y
[tex] \sf \implies (x + 2 + 5)(x + 2 - 1) = 0 \\ \\ \sf \implies (x + 7)(x + 1) = 0[/tex]
(x + 7) =0⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀(x + 1) = 0
x = -7⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ x = -1
. A reception hall holds 96 people. If the hall
is filled with 3/4th of the maximum
capacity at a wedding reception, how
many people are at the reception?
A. 48
B. 36
C. 24
D. 72
Answer:
D.72
Step-by-step explanation:
first you have to divide 96 and 4 than it will equal 24 than you multiple by 3 and so 24×3=72
7. AB = AC. AMON is a ____
Justify your answer.
Answer: Cyclic quadrilateral
Step-by-step explanation:
Since angles OMB and ONC are right angles, it follows that AMO and ANO are also right angles. Thus, there is a pair of opposite angles that are supplementary, and thus AMON is a cyclic quadrilateral.
When you use word processor functions such as spell check and thesaurus to write a second draft you are
A. Peer editing
B. Publishing
C. Revising
D. Prewriting
When you use word processor functions such as spell check and thesaurus to write a second draft, you are "C. Revising."
What is word processorRevising means making changes and improvements to a piece of writing to make it better. This includes making it easier to understand, organizing it well, and making sure it is good quality overall.
Using spell check helps you fix mistakes in your spelling, while using the thesaurus helps you find different words that mean the same thing and choose better words to make your writing clearer and more accurate.
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Researchers found a fertilizer treatment to have a mean plant height of 76 in. and a standard deviation of 3 in. Find the height of a plant treated with this fertilizer that has a z-score of 0.25. Round to the nearest tenth.
Answer:
milk because ur dad left the milk
Step-by-step explanation:
ur mum bc she is a pro statue
. Carl bought one book for $3.95 and a second book for $4.95. What is his total cost? $9.90 $9.00 $8.90 $7.90
The Cost of Carl's first item is 3.95. The Cost of his second item is 4.95. To find the total amount we need to add these two numbers together.
3 plus 4 is 7
95 cents plus 95 cents is 1.90
7+1.90 is 8.90
The total cost is $8.90
Hope this helps!
Help plez . What is the mean absolute deviation of the data set?
8, 5, 12, 4, 5, 8, 7
1
2
5
7
Answer:
2
Step-by-step explanation:
first, add terms
8 + 5 + 12 + 4 + 5 + 8 + 7 = 49
seven terms, therefore we divide by 7
49/7 = 7
find distance
8-7= 1
7-5= 2
12-7=5
7-4=3
7-5=2
8-7=1
7-7=0
added together you get 14,
14/7 = 2
your answer is 2
hope this helps:)
same here, i rlly need help
Answer:
Area = 50.125 cm^2
Perimeter = 26 + 15 = 41 cm
Step-by-step explanation:
Area Rectangle = 6 * 7 = 42 cm^2
Area Triangle = 1/2 * (9.5 - 7) * 6.5
Area Triangle = 1/2 * (2.5) * 6.5 = 8.125 cm^2
Total Area = 42 + 8.125 = 50.125 cm^2
Perimeter Rectangle = 6 + 7 + 6 + 7 = 26 cm
Perimeter or Triangle = 2.5 + 6.5 + 6 = 15 cm
Total Perimeter = 26 + 15 = 41 cm
quadrilateral has angles that measure 90°, 46°, and 120°.
What is the measure of the fourth angle
Answer:
the measure of the fourth angle is 104 degrees
Step-by-step explanation:
Answer:
Fourth angle = 104º
Step-by-step explanation:
Angles in a quadrilateral add to 360º so:
90 + 46 + 120 + fourth angle = 360º
90 + 166 + fourth angle = 360º
256 + fourth angle = 360
fourth angle = 104º
What do u know about Trigonometry in grade 11
Answer:
A lot
Step-by-step explanation:
So basically you learn a lot
USING Pythagoras theorem find the formula of equilateral triangle.
Answer:
Answer with explanation is below~
Step-by-step explanation:
We could easily obtain the formulae/formula of an equilateral triangle not only through Pythagoras Theorem, but also through Heron's formula.
INTRODUCTION:
What's equilateral triangle?
It's an triangle, whose all sides're of equal measurement.What's Heron Formula?
It's just a formula actually,take an example:Let,a,b and c denotes the lengths of 3 sides of any triangle,then the area will be given as:[tex] \boxed{\rm \: Area= \sqrt{s(s - a)(s - b)(s - c)} \: units ^{2}} [/tex]
Where,
s = (a+b+c)/2 {Half of the perimeter, basically}What's Pythagoras' Theorem?
It's actually like a formula but a theorem introduced by Pythagoras.SOLVING:
Let,ABC an equilateral triangle of sides a.
Now:Draw a perpendicular straight line AM to the side BC(Name each part of triangle)
So it's clear that ∆AMB is a right angled triangle at M, BM = (1/2)BC = a/2.
Please note AM here represents the height of ∆ ABC.
Let's use Pythagoras' theorem now.[tex] \boxed{\rm \: AM = \sqrt{AB^2-BM^2}}[/tex]
AB = aBM = a/2[tex] \rm \: AM = \sqrt{a {}^{2} - { \bigg( \cfrac{a}{2} \bigg) }^{2} } [/tex]
[tex] \rm \: AM = 3 \: \cfrac{a {}^{2} }{4} [/tex]
[tex] \rm \: AM = \cfrac{ \sqrt{3} }{2} \: a[/tex]
Now find the area of ∆ABC:
[tex] \rm \triangle \: ABC = \cfrac{1}{2} \times \: BC \times A [/tex]
[tex] \rm \: \triangle \: ABC = \cfrac{1}{2} \times a \times \cfrac{ \sqrt{3}}{4}a [/tex]
[tex] \boxed{\rm\triangle \: ABC = \cfrac{ \sqrt{3 } }{4} a {}^{2} \: units {}^{2}} [/tex]
Hence,the formulae of equilateral triangle using Pythagoras' theorem is {√(3)/4} a^2
[tex] \rule{225pt}{2pt}[/tex]
Extras:
Now let's find the area using Heron's Formula.
Solving:
Let each side of an equilateral triangle be a.
SO, then:
s = (3a/2)
We know that, (Heron's formula)
[tex] \rm \: A = \sqrt{s(s - a)(s - b)(s - c)} [/tex]
Now the area A :
[tex]\rm AR(A)= \sqrt{ \cfrac{ 3a } 2 \bigg(\cfrac{ 3a }{2} - a \bigg)\bigg(\cfrac{ 3a }{2} - a \bigg)\bigg(\cfrac{ 3a }{2} - a \bigg)} [/tex]
[tex]\rm AR(A)= \sqrt{ \cfrac{3a}{2} \bigg( \cfrac{a}{2} \bigg)\bigg( \cfrac{a}{2} \bigg)\bigg( \cfrac{a}{2} \bigg)}[/tex]
[tex]\rm \boxed{ \rm AR(A)= \cfrac{ \sqrt{ 3a}}{4} \: a {}^{2} \: \: units {}^{2}} [/tex]
And voila! we're done!
I hope this helps! :)
[Figure of Equilateral triangle is attached, it denotes the triangle we need to draw while finding the formulae through Pythagoras' theorem. ]
suppose the mean height in inches of all 9th grade students at one high school is estimated. The population standard deviation is 4 inches. The heights of 10 randomly selected students are 66, 61, 67, 61, 75, 71, 70, 61, 61, and 74
A mean is an arithmetic average of a set of observations. The height of the 9th-grade students will be 66.7±4 inches.
What is Mean?A mean is an arithmetic average of a set of observations. it is given by the formula,
Mean = (Sum of observations)/Number of observations
Given the height of the 10 selected students is {66, 61, 67, 61, 75, 71, 70, 61, 61, and 74}, also, the standard deviation of the 9th-grade students is 4 inches. Therefore, The mean height in inches of the selected students is,
Mean = (66+61+67+61+75+71+70+61+64)/10 = 66.7inches
Therefore, the height of the 9th-grade students will be 66.7±4 inches.
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Area of circumstances of a circle with radius of 5
anyone understands this?
Answer:
See below
Step-by-step explanation:
Not sure what they are looking for here....unless there is more info
[tex]\sqrt[14]{y}[/tex] = [tex]y^{1/14}[/tex] perhaps?
Can somebody please help me with this please and thankyou!!
Answer:
a) x=loge3 ( log e base 3)
b)4=e^y
Answer:
A.) loge(x)=3
B.) e^y =4
Step-by-step explanation:
A.) loge(x)=3
B.) e^y =4
PLEASE HELP PLEASE PLEASE HELP
Answer:
2:3
Step-by-step explanation:
Simplica Los dos numeros
6 ÷ 3 = 2
9 ÷ 3 = 3
Determine the equation of the line that has an x-intercept of 6 and passes through the point (6,4)
Given that x = 2u + v, y = u/v and z = e^(xy) find dz/du and dz/dv using the chain rule.
Answer:
[tex]\displaystyle \boxed{ \frac{dz}{du} = \frac{e^\big{\frac{u(2u + v)}{v}}}{v} \Bigg[ 4u + v \Bigg] }[/tex]
[tex]\displaystyle \boxed{ \frac{dz}{dv} = \frac{ue^\big{\frac{u(2u + v)}{v}}}{v} \Bigg[ 1 - \frac{2u + v}{v} \Bigg] }[/tex]
General Formulas and Concepts:
Calculus
Differentiation
DerivativesDerivative NotationDerivative Property [Multiplied Constant]:
[tex]\displaystyle (cu)' = cu'[/tex]
Derivative Property [Addition/Subtraction]:
[tex]\displaystyle (u + v)' = u' + v'[/tex]
Derivative Rule [Basic Power Rule]:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Multivariable Calculus
Partial Derivatives
Partial Derivative Rule [Chain Rule]:
[tex]\displaystyle \frac{dw}{dt} = \frac{\partial w}{\partial x} \frac{\partial x}{\partial t} + \frac{\partial w}{\partial y} \frac{\partial y}{\partial t} + \frac{\partial w}{\partial z} \frac{\partial z}{\partial t}[/tex]
Step-by-step explanation:
Step 1: Define
Identify given.
[tex]\displaystyle x = 2u + v[/tex]
[tex]\displaystyle y = \frac{u}{v}[/tex]
[tex]\displaystyle z = e^{xy}[/tex]
Step 2: Find Derivatives
[tex]\displaystyle \frac{dz}{du}[/tex]:
[Derivative] Rewrite [Partial Derivative Rule - Chain Rule]:We can find the partial derivatives by differentiating using basic differentiation rules found under "Calculus":
[tex]\displaystyle\begin{aligned}\frac{\partial z}{\partial x} & = ye^{xy} \\\frac{\partial x}{\partial u} & = 2 \\\frac{\partial z}{\partial y} & = xe^{xy} \\\frac{\partial y}{\partial u} & = \frac{1}{v} \\\end{aligned}[/tex]
Substituting in our partial derivatives and our variables x and y, we can obtain a final derivative:
[tex]\displaystyle\begin{aligned}\frac{dz}{du} & = 2ye^{xy} + \frac{xe^{xy}}{v} \\& = \frac{2ue^\big{\frac{u(2u + v)}{v}}}{v} + \frac{(2u + v)e^\big{\frac{u(2u + v)}{v}}}{v} \\& = \boxed{ \frac{e^\big{\frac{u(2u + v)}{v}}}{v} \Bigg[ 4u + v \Bigg] }\end{aligned}[/tex]
∴ we have found the derivative of z with respect to u.
[tex]\displaystyle \frac{dz}{dv}[/tex]:
[Derivative] Rewrite [Partial Derivative Rule - Chain Rule]:We can find the partial derivatives by using the same method(s):
[tex]\displaystyle\begin{aligned}\frac{\partial z}{\partial x} & = ye^{xy} \\\frac{\partial x}{\partial v} & = 1 \\ \frac{\partial z}{\partial y} & = xe^{xy} \\\frac{\partial x}{\partial v} & = \frac{-u}{v^2} \\ \end{aligned}[/tex]
Substituting in our partial derivatives and our variables x and y, we can obtain a final derivative:
[tex]\displaystyle\begin{aligned}\frac{dz}{dv} & = ye^{xy} + \frac{-uxe^{xy}}{v^2} \\& = \frac{ue^\big{\frac{u(2u + v)}{v}}}{v} + \frac{-u(2u + v)e^\big{\frac{u(2u + v)}{v}}}{v^2} \\& = \boxed{ \frac{ue^\big{\frac{u(2u + v)}{v}}}{v} \Bigg[ 1 - \frac{2u + v}{v} \Bigg] }\end{aligned}[/tex]
∴ we have found the derivative of z with respect to v.
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Topic: Multivariable Calculus
Unit: Partial Derivatives and Applications
solve for BC without working out the size of angle A
Answer:
BC = 6 units
Given following:
AC = 4 unitstan(A) = 3/2Solve for BC:
Formula:
[tex]\rightarrow \sf tan(A) =\dfrac{opposite}{adjacent}[/tex]
insert values and make them proportional
[tex]\rightarrow \sf tan(A) =\dfrac{BC}{AC} = \dfrac{3}{2} = \dfrac{6}{4}[/tex]
So, BC is 6 units.
Answer:
1) BC = 6
2) B = 33.7° (nearest tenth)
3) [tex]\sf AB=2\sqrt{13}[/tex]
Step-by-step explanation:
Trigonometric ratios
[tex]\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}[/tex]
where:
[tex]\theta[/tex] is the angleO is the side opposite the angleA is the side adjacent the angleH is the hypotenuse (the side opposite the right angle)Question 1Given:
Angle = ASide opposite angle = BCSide adjacent angle = AC = 4Substituting the values into the tan ratio:
[tex]\implies \sf \tan A=\dfrac{BC}{AC}=\dfrac{BC}{4}[/tex]
Given:
[tex]\sf \tan A=\dfrac{3}{2}[/tex]
Therefore:
[tex]\implies \tan \sf A = \tan \sf A[/tex]
[tex]\implies \sf \dfrac{BC}{4}=\dfrac{3}{2}[/tex]
[tex]\implies \sf BC=\dfrac{4 \cdot 3}{2}=6[/tex]
Question 2Given:
Angle = BSide opposite angle = AC = 4Side adjacent angle = BC = 6Substituting the values into the tan ratio and solving for B:
[tex]\implies \sf \tan B=\dfrac{AC}{BC}[/tex]
[tex]\implies \sf \tan B=\dfrac{4}{6}[/tex]
[tex]\implies \sf B=\tan ^{-1}\left(\dfrac{4}{6}\right)[/tex]
[tex]\implies \sf B=33.69006753...^{\circ}[/tex]
[tex]\implies \sf B=33.7^{\circ}\:(nearest\:tenth)[/tex]
Question 3Pythagoras’ Theorem
[tex]a^2+b^2=c^2[/tex]
(where a and b are the legs, and c is the hypotenuse, of a right triangle)
Given:
a = AC = 4b = BC = 6c = ABSubstituting the values into the formula and solving for AB:
[tex]\implies \sf AC^2+BC^2=AB^2[/tex]
[tex]\implies \sf 4^2+6^2=AB^2[/tex]
[tex]\implies \sf 16+36=AB^2[/tex]
[tex]\implies \sf AB^2=52[/tex]
[tex]\implies \sf AB=\sqrt{52}[/tex]
[tex]\implies \sf AB=2\sqrt{13}[/tex]
Find the product of
[tex]8(4\sqrt 7-\sqrt18)[/tex]
Answer:
[tex]32\sqrt{7}-24\sqrt{2}[/tex]
Step-by-step explanation:
[tex]8(4\sqrt{7}-\sqrt{18})\\\\8(4\sqrt{7}-3\sqrt{2})\\\\32\sqrt{7}-24\sqrt{2}[/tex]
Draw a line representing “rise” and line representing the “run of the line state the slope of the line .state the slope of the line in the simplest form.
Answer:
slope 4/5
Step-by-step explanation:
The attachment shows the rise in green (4 grid squares), and the run in red (5 grid squares). The slope is the ratio rise/run.
__
The slope is rise/run = 4/5.
Jenny is putting 11 books in a row on her bookshelf. She will put one of the books, The Iliad, in the first spot. She will put another of the books, The Odyssey, in the last spot. In how many ways can she put the books on the shelf?
$800 is deposited in an account
that pays 9% annual interest,
compounded annually. Find the
balance after four years.
$[ ? ]
Answer:
$1,129.27
Step-by-step explanation:
Compounded interest formula is
[tex]A=P(1+\frac{r}{n} )^{nt}[/tex]
Where [tex]A[/tex] is the final amount, [tex]P[/tex] is the principal, [tex]r[/tex] is the anual interest in decimal, [tex]n[/tex] is the numer of compounded periods in one year and [tex]t[/tex] is the time in years.
[tex]P= 800\\r= 0.09\\n= 1\\t= 4[/tex]
So then we plug our numbers...
[tex]A=800(1+\frac{0.09}{1})^{1(4)}=800(1.09)^{4}[/tex]
[tex]A=$1,129.27[/tex]
After 4 years the amount would be $1,129.27
467532 rounded by 100 000
Answer:
Round off value = 500000
Step-by-step explanation:
467532 > 500
- Round up
⇒ 500,000
A marble is 2 centimeters long. A rock is 75% longer than the marble. How long is the rock?
Answer:
3.5 centimeters
Step-by-step explanation:
75% of 2 cm = .75 x 2 = 1.5 cm
2 cm + 1.5 cm = 3.5 cm
Find AUB and AnB for set A and B
Answer:
Option C is the correct answer
Step-by-step explanation:
A= {-4, -6, 6, 4} (Given)B = {-8, -4, -5, -6, 0} (Given)[tex]A \cup B = \{-4, -6,\: 6, \:4, -8, -5, \:0\}[/tex][tex]A\cap B= \{-4, -6\}[/tex]What is plagiarism?
A. Using reliable sources in your paper
B. Letting the reader know where you got your information from
C. Providing constructive criticism.
D. Using another person's ideas or writing without citing them.
Answer: D. Using another person's ideas or writing without citing them.
Step-by-step explanation: Plagiarism is the use of someones work and claiming it as their own without giving them credit
help pls!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
y = -3x - 1
hope this helps!