Work of art from the Amarna Period that is abstract or descriptive in nature.
What modifications did the Amarna Period bring to the arts?That momentarily altered during the Amarna Period. The neck, arms, and hands were among the longer characteristics on the body. The traditional Egyptian painting form was briefly replaced by this strange new art form, which resulted in portraits of people that were virtually caricatures.
What is renowned about the Amarna Period?Religious iconoclasts are associated with the Amarna Period. Because he only worshiped the Aten, the pharaoh Amenhotep IV changed his name to Akhenaten. At Tell el-Amarna in Middle Egypt, he constructed a brand-new capital and cemetery.
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what is the formula for Mass when you have been provided force, time and distance
Answer:
The mass formula is also given as m = F / a If acceleration itself is the gravity, then M = F / g
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A toy car of mass 2.0kg is made to move in a circular track of radius 10.0m. If the centripetal force is 800.0N, calculate the angular velocity of the car
Answer:
w = 6.325 rad/s
Explanation:
Given the following data;
Mass = 2kg
Radius, r = 10m
Centripetal force = 800N
To find the angular velocity of the car;
First of all, we would use the following formula to solve for the speed of the car;
Centripetal force = mv²/r
800 = 2*v²/10
Cross-multiplying, we have;
8000 = 2v²
4000 = v²
Taking the square root of both sides, we have;
v = √4000
v = 63.25 m/s
Next, we find the angular velocity, w using the formula below;
w = v/r
w = 63.25/10
w = 6.325 rad/s
does altitude has an effect on weight? HELP
Answer: lose weight at high altitudes.
Explanation:
Answer:
Just a week at high altitudes can cause sustained weight loss, suggesting that a mountain retreat could be a viable strategy for slimming down. Overweight, sedentary people who spent a week at an elevation of 8,700 feet lost weight while eating as much as they wanted and doing no exercise
A car covers 8m in the first second and 12m in the second second. Find
a) Initial Velocity
b) Acceleration
c) Distance covered in the third second
Explanation:
Given that,
Distance travelled by the car in first second = 8 m⠀⠀⠀⇒ S′ = u + a/2(2n ― 1)
⠀⠀⠀⇒8 = u + a/2× [2(1) ― 1]
⠀⠀⠀⇒8 = u + a/2× [2 ― 1]
⠀⠀⠀⇒8 = u + a/2× 1
⠀⠀⠀⇒8 = u + a/2⠀⠀⠀⠀⠀ … ( 1 )
And,
Distance travelled by the car in second second = 12 m⠀⠀⠀⇒ S″ = u + a/2(2n ― 1)
⠀⠀⠀⇒12 = u + a/2× [2(2) ― 1]
⠀⠀⠀⇒12 = u + a/2× [4 ― 1]
⠀⠀⠀⇒12 = u + a/2× 3
⠀⠀⠀⇒12 = u + 3a/2⠀⠀⠀⠀ … ( 2 )
Subtract ( 1 ) from ( 2 ).
⠀⠀⠀⇒12 ― 8 = u + 3a/2 ― (u + a/2)
⠀⠀⠀⇒4 = u + 3a/2 ― u ― a/2
⠀⠀⠀⇒4 = 3a/2 ― a/2
⠀⠀⠀⇒4 = 2a/2
⠀⠀⠀⇒4 × 2 = 2a
⠀⠀⠀⇒8 = 2a
⠀⠀⠀⇒8 ÷ 2 = a
⠀⠀⠀⇒4 m/s² = a⠀⠀⠀⠀⠀[Ans]
Substitute the value of a in equation ( 1 ).
⠀⠀⠀⇒8 = u + a/2⠀⠀⠀⠀⠀ … ( 1 )
⠀⠀⠀⇒8 = u + 4/2
⠀⠀⠀⇒8 = u + 2
⠀⠀⠀⇒8 ― 2 = u
⠀⠀⠀⇒6 m/s = u⠀⠀⠀⠀⠀[Ans]
Now, distance travelled in third second.
⠀⠀⠀⇒ S′″ = u + a/2(2n ― 1)
⠀⠀⠀⇒ S′″ = 6 + 4/2 × [2(3) ― 1]
⠀⠀⠀⇒ S′″ = 6 + 2 × [6 ― 1]
⠀⠀⠀⇒ S′″ = 6 + 2(5)
⠀⠀⠀⇒ S′″ = 6 + 10
⠀⠀⠀⇒ S′″ = 16 m⠀⠀⠀⠀⠀[Ans]
HELP HELP HELP HELP HELP PLEASEEE HELP ME WITH MY OTHER QUESTIONS TOO!! PLEASE
Explain why synovial joints have greater flexibility than fixed and cartilaginous joint.
Answer:Unlike fixed joints or cartilaginous joints, where the bones are connected by either connective tissue or cartilage, the bones in synovial joints are not directly joined by anything, which allows for a much greater range of motion.
Explanation: I got a 100% on my test
A sphere with the same mass and radius as the original cylinder, but a smaller rotational inertia, is released from rest from the top of the ramp. KS and KC are the sphere's and cylinder's total kinetic energy at the bottom of the ramp, respectively. How do KS and KC compare, and why
Answer:
The Kinetic energy of Sphere is higher than the cylinder.
( KS > KC )
Explanation:
Given - A sphere with the same mass and radius as the original cylinder, but a smaller rotational inertia, is released from rest from the top of the ramp. KS and KC are the sphere's and cylinder's total kinetic energy at the bottom of the ramp, respectively.
To find - How do KS and KC compare, and why ?
Proof -
We know that,
The total energy of an object = Potential energy + linear kinetic energy + rotational kinetic energy.
⇒E = mgh + [tex]\frac{1}{2} mv^{2}[/tex] + [tex]\frac{1}{2} l\omega^{2}[/tex]
Now,
Mass of sphere = m
Radius of sphere = r
So,
The moment of inertia of a uniform solid sphere = [tex]\frac{2}{5} mr^{2}[/tex]
Also,
Mass of cylinder = m
Radius of cylinder = r
So,
The moment of inertia of a uniform solid cylinder = [tex]\frac{1}{2} mr^{2}[/tex]
Now,
Total energy for the sphere , Es = mgh + [tex]\frac{7}{10} mv^{2}[/tex]
Total energy for the cylinder, Ec = mgh + [tex]\frac{3}{4} mv^{2}[/tex]
As they always have the same total energy,
So, for height h of the sphere's velocity has to be higher.
Therefore,
The Kinetic energy of Sphere is higher than the cylinder.
Answer:
KS < KC
Explanation:
15. Explain how the atomic mass of an element is
affected by the distribution of its isotopes in nature.
Answer:
The atomic mass of an element is affected by the distribution of its isotopes because each isotope of an element has a different number of neutrons in the nuclei of its atoms.
Explanation:
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CORRECT ANSWER GETS BRAINLIEST
Answer:
Wax melts as it absorb heat from flame
Explanation:
To know which option is correct, it is important that we know what chemical changes and physical changes are all about.
Chemical change is a change in which the process is not easily reversed and it produces new substance.
Physical change is more like the opposite of chemical change. In this change, the process is easily reversed and no new substance is produced.
Considering the options given above,
1. Iron combines with oxygen to produce rust is a chemical change since a new substance (rust) is formed and we can not reverse the process to get back iron and oxygen.
2. Wax melts as it absorb heat from flame is a physical change since no new substance is formed and we obtained the wax by allowing it to solidified.
3. Pure sodium explodes when dropped in water is a chemical change because we can not reverse the process to get back the sodium.
4. Glucose molecules are produced in plant leaf is also a chemical change.
From the illustrations above, it is evident that: 'Wax melts as it absorb heat from flame' is not a chemical
Instead of changing the focal length of the lens, the eyes of amphibians work in a different manner: a set of muscles changes the shape of the eye which increases the distance between the front of the eye and the retina. The world's largest frog, the Goliath frog of west Africa, has an eye with a maximum size similar to a human's: 2.5cm. However, unlike a human, where the focal length is also 2.5cm, the focal length of the Goliath frog's eye is 2.146 cm. What is the maximum distance this frog can see
Answer:
The answer is "15.56 cm".
Explanation:
[tex]v= 2.5 \ cm\\\\f= 2.154 \ cm[/tex]
Calculating object of length is x so:
[tex]u= -x[/tex]
Using formula:
[tex]\to \frac{1}{v}-\frac{1}{u}=\frac{1}{f}\\\\\to \frac{1}{2.5}-\frac{1}{-x}=\frac{1}{2.154}\\\\\to \frac{1}{x}=\frac{1}{2.154}-\frac{1}{2.5}\\\\\to \frac{1}{2.5}-\frac{1}{-x}=\frac{1}{2.154}\\\\\to x= 15.56 \ cm[/tex]
Please help I’m kinda in a rush to get these done
a bag of sugar has a mass of 2.26 kg. what is its weight
Answer:
2260
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Chemical energy may be released during a chemical reaction in the form of heat ..... True or false?
Answer:
heat and gas sometimes so true
Helppppp plsssssssssssssssssssssss thanks 2+2== plzzz help me and 20+67
Answer:
8,6 is the answer to your question
A wheel has an angular speed of 32 rev/s when it experiences a constant angular acceleration of 65 rev/s2 which causes it to spin FASTER. During this time the wheel completes 92 rev. Determine how long the wheel was experiencing this angular acceleration and how fast the wheel was spinning at the end of this period. Assume that the wheel doesn't change the direction of its spin.
Answer:
ωf = 113.95 rev/s
t = 1.26 s
Explanation:
We can use the third equation of motion to find out the final spinning speed of the wheel:
[tex]2\alpha \theta = \omega_f^2 -\omega_i^2\\[/tex]
where,
α = angular acceleration = 65 rev/s²
θ = No. of revolutions completed = 92 rev
ωf = final angular speed = ?
ωi = initial angular speed = 32 rev/s
Therefore,
[tex](2)(65\ rev/s^2)(92\ rev) = \omega_f^2 - (32\ rev/s)^2\\\omega_f^2 = 11960\ rev^2/s^2 + 1024\ rev^2/s^2\\\omega_f = \sqrt{12984\ rev^2/s^2}[/tex]
ωf = 113.95 rev/s
Now, for the time we can use the first equation of motion:
[tex]\omega_f = \omega_i +\alpha t\\113.95\ rev/s - 32\ rev/s = (65\ rev/s^2)t\\t = \frac{81.95\ rev/s}{65\ rev/s^2}\\\\[/tex]
t = 1.26 s
Which statement is true?
A)
All waves travel at the same speed through any medium.
B)
All waves travel at the same speed if no medium is present.
Electromagnetic waves require a medium, but mechanical waves do not.
D)
Mechanical waves require a medium, but electromagnetic waves do not
Answer:
B.
Explanation:
can someone help
pls !
A moving man is lifting a box up an inclined plane. Halfway up he sets the box down and rests. Which of the following explains why the box does not slide back down the inclined plane?
a. The force of friction balances the force of gravity.
b. The force of gravity does not affect inclined planes.
c. The force of friction does not affect inclined planes.
d. The force of friction is less than the force of gravity.
Answer: A or B
Explanation: I’m guessing that they even each other out depending on the incline, gravity will help keeping it in place
Disk A, with a mass of 2.0 kg and a radius of 70 cm , rotates clockwise about a frictionless vertical axle at 50 rev/s . Disk B, also 2.0 kg but with a radius of 50 cm , rotates counterclockwise about that same axle, but at a greater height than disk A, at 50 rev/s . Disk B slides down the axle until it lands on top of disk A, after which they rotate together. After the collision, what is their common angular speed (in rev/s) and in which direction do they rotate?
Answer:
w = - 197.5 rad / s
The negative sign indicates that the rotations are clockwise
Explanation:
To solve this exercise, let's use the concept of conservation of the angular number.
We create a system formed by the two discs, in this case the forces last the shock are internal
initial instant .. just before shock
L₀ = I₀ w₀ + I₁ w₁
instnte final. Right after crash
L_f = (I₀ + I1) w
angular momentum is conserved
I₀ w₀ + I₁ w₁ = (I₀ + I₁) w
w = I₀ w₀ + I₁ w₁ / Io + I1
The moment of inertia of a disk with an axis passing through its thermometric center
I₀ = ½ m² r₀²
I₁ = ½ m₁ r₁²
we substitute
I₀ = ½ 2.0 0.70²
I₀ = 0.49 kg m
I₁ = ½ 2.0 0.5²
I₁ = 0.25
₁
let's reduce the magnitudes the SI system
w₀ = -50 rev / (2pi rad / 1rev) = -314.15 rad / s
w₁ = 70 rev (2pi rad / 1rev) = 439.82 rad / s
we will assume that the counterclockwise turns are positive
w = -0.49 314.15 + 0.25 439.82 / (0.49 + 0.25)
w = (- 4.696 + 1.0995) 102) / 0.74
w = -197.75 + 0.25
w = - 197.5 rad / s
The negative sign indicates that the rotations are clockwise
doing the same amount of work in less time requires more power true or false
You need to load a crate of mass m onto the bed of a truckon earth. One possibility is just to lift the crate straight up over a height h, equal to height of the truck's bed. Theforce exert in this case is F1 and the work done in this case is W1. The other possibility is to slide the crate up the frictionless ramp of length L.. In this case you exert force F2 and perform work W2. Which statement is true?
a. F1 > F2 and W1 > W2
b. F1 = F2 and W1 > W2
c. F1 = F2 and W1 = W2
d. F1 > F2 and W1< W2
e. F1 > F2 and W1 = W2
Answer:
The correct answer is - option E. e. F1 > F2 and W1 = W2
Explanation:
Case 1 - F1 = mg, m= mass and g = gravitational force
Work done W1 = F1h= mgh (h - height of bed of truck)
Case 2 - F2 = mgsinθ
work done W2 = mgsinθ×L (L=length of ramp ans sin θ angle of ramp)
sinθ = h/l, then W2 = mg(h/L)L
W2 = mgh
By comparing both,
F2 = mgsinθ and F1 = mg therefore,
F2>F1
now, W2 = mgh, and W1 = mgh
therefore, W2 = W1.
Help please is for today
Answer:
All of the above.
Explanation:
A person is said to be at rest when he or she is not performing any action. The heartbeat stays normal in this condition.
A person is said to perform a moderate activity when his heart beats faster than the normal rest condition. It requires extra effort within the limit. For example, walking and dancing are examples of moderate activity.
A person is said to perform a vigorous activity when his heart beats much than in moderate activity. It requires a lot of effort over the limit. Running is an example of vigorous activity.
In view of the above information, all the options given in the question are true. Hence, the correct answer will be:
All of the above.
A student is investigating the differences between light waves and sound waves. The student does this by using a capsule filled with solid glass at one end and a vacuum at the other end. The student will transmit waves into the capsule at a 30° angle to the (normal) centerline.
alert your teacher if the image is missing
Which >>TWO<< questions should the student ask, and which predictions are MOST LIKELY correct based on this investigation?
Group of answer choices
question: Can electromagnetic waves and mechanical waves travel from a solid glass medium into a liquid medium?
prediction: The electromagnetic waves will continue through the liquid medium, while the mechanical waves will go no farther.
question: How are electromagnetic waves and mechanical waves affected when traveling from a solid glass medium to a vacuum?
prediction: The electromagnetic waves will continue through the vacuum, while the mechanical waves will go no farther.
question: Can electromagnetic waves and mechanical waves travel from a solid glass medium into a liquid medium?
prediction: Both electromagnetic waves and mechanical waves will bend, showing that they have passed through each medium.
question: How are electromagnetic waves and mechanical waves affected when traveling from a solid glass medium to a vacuum?
prediction: The electromagnetic waves and mechanical waves will continue through the vacuum at a lower speed.
question: How is the speed of electromagnetic waves affected when traveling from a solid glass medium to a vacuum at a 30° angle?
prediction: The electromagnetic waves will travel in a straight line, showing that they have maintained a constant speed.
question: How is the speed of electromagnetic waves affected when traveling from a solid glass medium to a vacuum at a 30° angle?
prediction: The electromagnetic waves will bend downward, showing that they have sped up slightly
Answer:
Explanation:
The investigation is on differences between light waves and sound waves. Because the light and sound are transmitted at a 30° angle at a capsule with glass and vacuum, questions asked should show difference answers for light and sound.
First and third question talk about liquid which is not related here.
Fouth and sixth prediction are wrong as electromagnetic wave will not slow down or speed up in vacuum.
That leaves the second and fifth set as correct answers:
question: How are electromagnetic waves and mechanical waves affected when traveling from a solid glass medium to a vacuum?
prediction: The electromagnetic waves will continue through the vacuum, while the mechanical waves will go no farther.
question: How is the speed of electromagnetic waves affected when traveling from a solid glass medium to a vacuum at a 30° angle?
prediction: The electromagnetic waves will travel in a straight line, showing that they have maintained a constant speed.
Answer:
The two questions and predictions are:
question: How are electromagnetic waves and mechanical waves affected when traveling from a solid glass medium to a vacuum?
prediction: The electromagnetic waves will continue through the vacuum, while the mechanical waves will go no farther.
question: How is the speed of electromagnetic waves affected when traveling from a solid glass medium to a vacuum at a 30° angle?
prediction: The electromagnetic waves will travel in a straight line, showing that they have maintained a constant speed.
Explanation:
light is EM wave which is transverse while sound is longitudinal. speed changes for long wave but not EM.
Ilus
A bat bounces a sound wave off a
bird 19.4 m away, and hears the
echo after 0.117 s. What is the
speed of sound in the air?
(Hint: It is not necessarily 343 m/s.)
(Unit = m/s)
Answer:
332m/s
Explanation:
We know the formula for velocity is v=d/t, but this particular question is asking about an echo. The problem tells us the distance to the bird from the bat, which is 19.4. To find the echo, you need to find the distance from the bat to the bird and back.
So
19.4 x 2 = 38.8
And then plug into the equation
v = 38.8 / 0.117
= 332m/s
what is an axis in social
Answer:
An axis is an invisible line around which an object rotates, or spins. The points where an axis intersects with an object's surface are the object's North and South Poles.
Mass in motion is another way to say
Answer:
Momentum - Momentum is a measurement of mass in motion. Momentum is equal to the mass times the velocity of an object.
CAN YOU HELP MEEEEEEEEEE PLEASEEEE
Answer:
What are your options? also i believe the answer may be ecosystem.
Explanation:
There are both biotic and abiotic factors in an ecosystem. Be cause living organisms Are Biotic. While water and rocks are abiotic which are needed to form an ecosystem.
PLEASE HELP! I'LL GIVE BRAINLEST
Answer:
8.162
Explanation:
W=mg
= 2.2 x 3.71
= 8.162 N
the density of gold is 19g/m³ what is the volume of 38g
let the volume be x
19 = 38/x
x=38/19
x=2
volume is 2 cm^3
HELP 30 POINTS
The picture above shows a cross section of the Earth’s interior including both oceanic crust and continental crust. Along the seafloor, there are mid–ocean ridges where magma rises to the surface and creates new crust. There are also areas where crust is recycled as oceanic crust goes below continental crust. What type of boundary would occur at a mid-ocean ridge?
Mid-ocean ridges happen along divergent plate boundaries, where new ocean floor is created as the Earth’s tectonic plates spread apart. As the plates separate, molten rock rises to the seafloor, producing large volcanic eruptions of basalt.