Which ordered pairs in the form (x, y) are solutions to the equation

4x−5y=24

Select each correct answer.

Responses

(1, −4)
Begin ordered pair 1 comma negative 4 end ordered pair

(−9, −12)
Begin ordered pair negative 9 comma negative 12 end ordered pair

(4, 8)
Begin ordered pair 4 comma 8 end ordered pair

(6, 0)

The simple interest on $5400 at a rate of 10% per annum for 3 years is $ 1620

The interest on a loan at a fixed rate per annum. The formula used for simple interest is given by

Simple interest (I) = ptr

Where p = principal amount

t = time period

r = rate of interest per year.

Here we have

The sum of $5400 was borrowed from a bank at a rate of 10% per annum for 3 years

Find the simple interest that can be payable

From above observations

Principal amount, P = $5400

Rate of interest = 10% = 10/100 = 0.1

Time period, t = 3 years

The simple interest that can be payable = $5400(3)(0.1) = $ 1620

Therefore,

The simple interest on $5400 at a rate of 10% per annum for 3 years is $ 1620

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Answer:

I would say the answer is 1500/3/7/13

Step-by-step explanation:

con for 3,7,13 find it divife it by 1500 cost of burrito

Answer: 96 R12

Step-by-step explanation:

Answer:

Step-by-step explanation: √240 = 15.49….    √50 = 7.07…

15.5 x 7.07 = 109.58 rounded to 110. Therefore the area is 110 feet so at least 2 can is needed to fill up the wall. But if the problem is being precise it’s 1 can and 5/6 of a can.

2 cans of paint will be needed to cover 110 square feet area.

The area of Rectangle is length times of width.

Given,

A rectangular wall is √240 ft by √50 ft.

Need to paint the wall twice to cover the area with two coats of paint.

Area of wall=Length×Width

=√240×√50

=√12000

=109.5=110

Given that each can of paint can cover 60 square feet,

110/60=1.83

=2

Hence, 2 cans of paint will be needed to cover 110 square feet area.

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Answer:

Unless you wrote the wrong expressions, non of your choice answers are correct!

Step-by-step explanation:

Solve for x:

2 (x - 7) = 36

Divide both sides of (x - 7)×2 = 36 by 2:

(2 (x - 7))/2 = 36/2

2/2 = 1:

x - 7 = 36/2

The gcd of 36 and 2 is 2, so 36/2 = (2×18)/(2×1) = 2/2×18 = 18:

x - 7 = 18

Add 7 to both sides:

x + (7 - 7) = 7 + 18

7 - 7 = 0:

x = 18 + 7

18 + 7 = 25:

Answer: x = 25

The values of the following functions are:

a. (f ºg)(x) = x+2

b.  (g º f)(x) = 3x + 14

c.  (f º g)(-1) = 3

d.  (g º f)(-1) = 11

Given:

f(x) = x+4 and

g(x) = 3x+2

we are asked to determine the following functions:

a.  (f º g)(x)

⇒ f(g(x))

⇒ f(3x+2)

⇒  (f º g)(x) = (3x+2)+4

= 3x+6

divide by 3

= x+2

b.  (g º f)(x)

⇒ g(f(x))

⇒ g(x+4)

⇒  (g º f)(x) = 3(x+4)+2

= 3x+12+2

= 3x+14

c.  (f º g)(-1)

⇒ f(g(-1))

⇒ f(3(-1)+2)

⇒ f(-3+2)

⇒ f(-1)

⇒  (f º g)(-1) = -1+4

= 3

d.  (g º f)(-1)

⇒ g(f(-1))

⇒ g(-1+4)

⇒ g(3)

⇒  (g º f)(-1) = 3(3)+2

= 11

Hence we get the required answer.

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Answer:

y = 5x + 15

Step-by-step explanation:

You can pick any two points on the graph that intersect the trend line. For instance (5,40) and (3,30)

Formula for Slope:

[tex]y = \frac{y_2 - y_1}{x_2 - x_1} = \frac{40 - 30}{5 - 3} = \frac{10}{2} = 5[/tex]

y intercept:

[tex]y = 15[/tex]

Equation of a line:

[tex]y = mx + b\\m = slope \\b = intercept \\\\y = 5x + 15[/tex]

** also be cautious of the different scaling of the x and y axis.

Answer:

Below

Step-by-step explanation:

If -5 is one of the roots then that means  (x+5) is one of the factors

divide (x+5) into x^3 + 3x^2 -12x -10

to get   x^2-2x-2   which you can easily  (using Quadratic Formula) find the roots       1 + sqrt 3   and        1 -sqrt 3

('roots'   and 'zeroes'   are the same thing)

Answer:

39

Step-by-step explanation:

2*3^3+4*3+9

= 39

Mark me as brainliest

Answer:

-10x+4

Step-by-step explanation:

distribute the minus

-4x-1-6x+5

-10x+4

hopes this helps please mark brainliest

The area of the circle with radius 33 cm is 3419.5 square centimeters.

According to the question,

We have the following information:

Radius of the circle = 33 cm

We know that the following formula is used to find the area of the circle:

Area of the circle = π[tex]r^{2}[/tex] where r is the radius of the circle

There are two approximate values of π which are 22/7 and 3.14. In this case, we will use the value of π as 3.14.

So, we have the following expression:

Area of the circle = 3.14*33*33

Area of the circle = 3419.46 square centimeters

Rounding it off to one decimal point:

3419.5 square centimeters

Hence, the area of the circle with radius 33 cm is 3419.5 square centimeters.

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Answer:

linear

Step-by-step explanation:

Because if you graph it. It creates a line which makes it a linear

Rewriting the given term (55.44).33 using the Associative Law of Multiplication, we have 55.(44.33). Therefore, 1st option is correct.

The given terms are written as -

(55.44).33

We have to rewrite the given term using the Associative Law of Multiplication.

According to the Associative Law of Multiplication, the terms or factors can be associated in any expected ways, i.e.,

a(bc) = (ab)c

So, our given term in the question (55.44).33 can be rewritten according to the Associative Law of Multiplication as -

(55.44).33 = 55.(44.33)

Thus, rewriting the given term (55.44).33 using the Associative Law of Multiplication gives us 55.(44.33). Therefore, 1st option is correct.

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Answer:

$9.00 a journal.

Step-by-step explanation:

First off, you can start by subtracting $0.50 from $80.50 because it costs $0.50 to use the card.

You’re left with a new value of $80.00. Since Nabil had $44.00 left over on his card, you can subtract $44.00 from $80.00 to figure out how much he spent.

$80.00

-$44.00

————

$36.00

Since Nabil bought four journals, and they are all equal in cost, you can divide $36.00 by 4 (36/4) and get $9.00.

The tangential speed of the ball is 1.5267

The centripetal acceleration is 2.5897 m/s²

Mass of the ball is m = 7.90 kg

ball moves in a circle having radius r = 0.9 m

angular speed is ω = 0.27 rev /s

given that 1 revolution = 6.283 rad / sec

0.27 rev / sec = ?

ω = 1.696 rad / sec

a. The tangential speed Velocity = rω

w =  1.696

r = 0.9

= 1.696  * 0.9 m

= 1.5267 m / s

b ) centripetal acceleration a = v² / r

= (1.5267 m/s)^2 / 0.9 m

= 2.3308 / 0.9

= 2.5897 m/s²

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The linear equation for the monthly charge C dollars , in terms of the number of miles driven(n) is C(n) = 35 + 0.10×n  .

In the question ,

it is given that ,

the fixed rent for a car is = $35 .

the per mile charge for the car is = $0.10 miles

let the number of miles driven is = n miles

the function C that represents the linear equation for the monthly charge C dollars , in terms of the number of miles driven(n) is given by

C(n) = fixed charge + (per mile charge)×(number of miles)

Substituting the values , we get

C(n) = 35 + 0.10×n

Therefore , The linear equation for the monthly charge C dollars , in terms of the number of miles driven(n) is C(n) = 35 + 0.10×n  .

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Answer:
id say, C=0.10=35

Step-by-step explanation:

not really sure, but I tried!

The probability that you win is 6%, and the two choices are dependent events option (B) is correct.

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

It is given that:

A standard deck of playing cards contains 52 total cards, 13 of which are "spades".

The probability of the first draw:

Probability = favorable outcomes/total outcomes

First draw: 1/4

For the second draw:

Second draw = 12/51

The probability that you win = (1/4)(12/51) = 3/51

In percent:

= (3/51)x100

= 5.88 = 6%

Thus, the probability that you win is 6%, and the two choices are dependent on events option (B) is correct.

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The point only can be on the unit circle and on the second quadrant if:

x = -√55/8

We know that we have a point of the form:

P = (x, y)

And the value of y is:

y = 3/8

Then our point is:

P = (x, 3/8)

And it is on the unit circle, then the values of x and y are solutions of:

x^2 + y^2 = 1

x^2 + (3/8)^2 = 1

x^2 = 1 - (3/8)^2 = 1 - 9/64 =

x^2 =  64/64 - 9/64

x^2 = 55/64

x = ±√(55/64) = ±√55/8

And P is on the second quadrant, then we take the negative option:

x = -√55/8

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The vector having a magnitude √61 and direction 140.2° has been shown in the figure.

Given,

Let the vector v have an initial point at (4, 8) and a terminal point at

(-2, 3).

we are asked to  Plot the vector v .

Given that the initial point of the vector is (4,8) and the termination point of the vector is (-2,3).

So, the tail of the vector is at point (4,8) and the head of the vector is at (-2,3).

The vector , v, has been shown.

I v I = √(4-(-2))²+(8-3)²

= √(4+2)²+(8-3)²

= √(6)²+(5)²

= √36+25

= √61

The direction of a vector is the angle made by a vector with the positive direction of the x-axis.

θ =  180° tan⁻¹ I 3-8/-2-4I

θ = 180° tan⁻¹ (5/6)

θ = 180° - tan⁻¹(5/6)

θ = 180° - 39.80°

θ = 140.2°

Hence, the required vector having a magnitude √61  and direction  140.2° has been shown in the figure.

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Answer:

Step-by-step explanation:

1. Make Words into Math

6 to the power of -3 =

6^-3=

-6*-6*-6=

0.00462962962

Answer:0.00462962962

Step-by-step explanation:

If you take the 4:3 aspect ratio and divide 4 by 3, the result is 1.33. Therefore, you could alternately describe the 4:3 aspect ratio as 1.33:1, meaning that for every 1.33 units in width, there is 1 unit in height. Again, the same applies for the 16:9.

The values of x that make the equation true are approximately  5.7 and  -0.7  .

The given equation is :

[tex]\frac{x+1}{x} = \frac{2}{x-4}[/tex]

Using cross multiplication this can be written as:

or, ( x + 1 ) ( x - 4 ) = 2 x

or, x² + x - 4x - 4 = 2x

Putting all the like terms together.

or, x² + x - 4x -2x - 4 = 0

or, x² - 5x  - 4 = 0

Now we will use the quadratic formula to find the values of x :

[tex]{\displaystyle x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}\ \ }[/tex]

or, [tex]{\displaystyle x={\frac {5\pm {\sqrt {(-5)^{2}-4(1)(-4)}}}{2(1)}}\ \ }[/tex]

or, [tex]x = \frac{5+\sqrt{41}}{2} , \frac{5-\sqrt{41}}{2}[/tex]

or, x ≈ 5.7 , -0.7

The roots or zeros of the expression, which are also on the left side of the equation, are used to indicate the values of x that satisfy the equation.

There can only be two possible solutions to a quadratic problem. One argues that if there is only one remedy, there are many different causes of the problem. There are only four possibilities: one real double root, two complex solutions that appear to be complex conjugates of one another, two real solutions, or two real solutions if each of the coefficients has a real value.

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The solution to the system of equations y = 1/8x −1 and −5x + 4y = −13 is (2, −3/4). Option D is correct.

We are given:

y = 1/8 x − 1                 ..............equation i.

− 5x + 4y = − 13          ..............equation ii.

We will use the substitution method to solve the given equation.

substitute the value of y from equation i in equation ii, and we will get;

− 5x + 4(1/8 x − 1) = − 13

− 5x + 1/2 x − 4 = − 13

(-10 + 1) / 2 x = -13 + 4

-9/2 x = -9

x = -9 * 2 / -9

x = 2

Put the value of x in equation i, we will get;

y = 1/8 *2 − 1

y = 1/4 - 1

y = 1 - 4 / 4

y = -3 / 4

So, the value of x = 2 and the value of y = -3 / 4.

Thus, the solution to the system of equations y = 1/8x −1 and −5x + 4y = −13 is (2, −3/4). Option D is correct.

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Answer:

7,036,363,636,363,635,660,000

Step-by-step explanation:

this one hert my head

The end points behavior of the function:

(a) If x goes to positive infinity then the function goes to positive infinity. If x goes to negative infinity then the function goes to negative infinity.

(b) The zeros of the function f(x) are -3, -1, -1, and 1.

(c) The y-intercept is at (0,-3).

What is the endpoint behaviors of a polynomial?

A polynomial function's final behaviour is how its graph behaves as x gets closer to positive or negative infinity. The graph's final behavior is determined by a polynomial function's degree and leading coefficient.

What are zeros of a polynomial?

The locations where a polynomial becomes zero overall are known as the zeros of the polynomial. The term "zero polynomial" refers to a polynomial with a value of zero (-1). The highest power of the variable x is referred to as a polynomial's degree. A linear polynomial is a polynomial with degree 1.

Given function is f(x) = (x+3)(x+1)^2(x-1).

If x = ∞, then f(x) = ∞. The one endpoint of the function will go positive infinity.

If x =- ∞, then f(x) = -∞. The one endpoint of the function will go negative infinity.

To find the zeros of the polynomial, equate f(x) with zero.

(x+3)(x+1)^2(x-1) = 0

Either, x + 3 =0 → x = -3

or, (x+1)^2 =0 → x = -1

or, x-1 = 0 → x = 1

The zeros of the function are -3, -1, and 1.

To find y-intercept, put x=0 in the given function:

f(0) = (0+3)(0+1)^2(0-1)

→ f(0) = -3

The y-intercept is at (0,-3).

The x-intercepts of the function are zeros of the function.

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