Which set of real numbers contains 23 and .45?

rational numbers

integers

natural numbers

whole numbers

Answer:

1.5 Oz because it's just a random guess hopefully I'm right

I think

Answer:

Below.

Step-by-step explanation:

(a). The x estimations of the turning points are -1.8 and 1.1, according to the graph.

(b). Where the graph crosses the x axis are the solutions. x = -3, 0, and 2 are the values.

Answer:

3x + 12

Step-by-step explanation:

This is an 'expression'  ...there is no 'answer'  but it can be re-arranged

3(x+4) =   3 * x  +  3 * 4 =   3x + 12

Hey there!

3(x + 4)

= 3(1x + 4)

DISTRIBUTE 3 WITHIN the PARENTHESES

= 3(1x) + 3(4)

= 3(x) + 3(4)

= 3x + 12

Therefore, the answer should be:

3x + 12

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

∠APB = 106°

Step-by-step explanation:

Method 1: Focus on Triangle APB

Every angle of equilateral triangle ABC is 60°

∠BAP = 60°

∠ABP = 60° - 46° = 14°

Total degrees in one triangle is 180°

∠APB = 180° - 60° - 14° = 106°

Method 2: Exterior Angle Theorm

∠APB = ∠PBC + ∠PCB

∠APB = 46° + 60°

∠APB = 106°

Answer:

[tex]\displaystyle z=\frac{5}{2}\biggr(\cos\frac{11\pi}{6}+i\sin\frac{11\pi}{6}\biggr)[/tex]

Step-by-step explanation:

A complex number in polar form is [tex]z=r(\cos\theta+i\sin\theta)[/tex] where [tex]r=\sqrt{x^2+y^2}[/tex] and [tex]\displaystyle \theta=\tan^{-1}\biggr(\frac{y}{x}\biggr)[/tex], thus:

[tex]r=\sqrt{x^2+y^2}=\sqrt{(\frac{5\sqrt{3}}{4})^2+(-\frac{5}{4})^2}=\sqrt{\frac{75}{16}+\frac{25}{16}}=\sqrt{\frac{100}{16}}=\frac{10}{4}=\frac{5}{2}[/tex]

[tex]\displaystyle \theta=\tan^{-1}\biggr(\frac{y}{x}\biggr)=\tan^{-1}\biggr(\frac{-\frac{5}{4}}{\frac{5\sqrt{3}}{4}}\biggr)=\tan^{-1}\biggr(-\frac{\sqrt{3}}{3}\biggr)=\frac{11\pi}{6}[/tex]

Thus, the complex number in polar form is [tex]\displaystyle z=\frac{5}{2}\biggr(\cos\frac{11\pi}{6}+i\sin\frac{11\pi}{6}\biggr)[/tex]

Answer:

circle

Definition: A circle is the set of all points in a plane that are equidistant from a given point called the center of the circle.

Answer:

there is the answer to your question

Using the z-distribution, considering the given data, the lower limit of the 98% confidence interval is of 0.5534.

The confidence interval is:

[tex]p - zs[/tex]

In which:

In this problem, the parameters are given as follows:

p = 0.6, z = 2.33, s = 0.02.

Hence, the lower limit of the 98% confidence interval is:

p - zs = 0.6 - 2.33 x 0.02 = 0.5534.

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The equation that can pair with x + 2y = 5 to generate an inconsistent system is given by:

2x + 4y = 3.

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

A inconsistent system is a system that has no solution, that is, when the coefficients of x and y are multiplies, but the result is not. Hence, the option that gives an inconsistent system is given by:

2x + 4y = 3.

As when we try to solve the system, we would end up with the following situation:

[tex]0x = c, c \neq 0[/tex].

Which is impossible.

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Answer:

417

Step-by-step explanation:

372+45 = 417

Just add both gram values

Answer:

I hope you know what a rectangle is, but it is true.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Here's the table!

1 Kilobyte = 1,024 Bytes

1 Megabyte = 1,024 Kilobytes

1 Gigabyte = 1,024 Megabytes

1 Terabyte = 1,024 Gigabytes

From this we can see that there are

The given expression [tex]3 \dfrac{6}{5}[/tex]  can be written as [tex]\sqrt[5]{3^6}[/tex].

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.

The given value can be written as:-

[tex]3\dfrac{6}{5} = \sqrt[5]{3^6}[/tex]

Therefore the given expression [tex]3 \dfrac{6}{5}[/tex]  can be written as [tex]\sqrt[5]{3^6}[/tex].

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Answer:

y=1, x=3   or (3,1)

Step-by-step explanation:

when you add the two equations together the two x's cancel out, which leaves one solvable equation, 7y=7, so y=1, then you can plug y=1 into one of the equations. 2x+3(1)=9 which is 2x+3=9 then solve, x=3.

Additionally if you want to check answers plug both into one equation- -2(3)+4(1)=-2, -6+4=-2, -2=-2 which is correct.

The solution for the given linear system from the elimination method is x=3 and y=1.

System of linear equations is the given term math for two or more equations with the same variables. The solution of these equations represents the point at which the lines intersect.

You can solve a linear system by the adding or substitution methods. In the addition method, you eliminate a variable, on the other hand, in the substitution method you replace a variable for the other.

-2x+4y=-2 (1)

2x+3y=9   (2)

You should sum the equations 1 and 2, for eliminate the variable x.

-2x+4y+2x+3y=-2+9

7y=7

y=1

If y=1 from equation 2, you have:

2x+3*1=9

2x+3=9

2x=9-3

2x=6

x=3

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Answer:

its 1.6

Step-by-step explanation:

2 squared minus 1.2 squared is 2.56

the square root of that is 1.6

Answer:

pi/2

Step-by-step explanation:

We know that,

Length of arc=r*(theta) where r=radius and theta is angle

Given- unit circle, it means  circle have raduis=1

       Theta=90° or (pi/2)

Hence,

Length of arc is = 1*(pi/2)

                            = pi/2

Hence option two is correct

Answer:

answer should be 4.3

Step-by-step explanation:

8.9^(2)-7.8^(2)

=18.37

\sqrt(18.37)

=4.28602379

and round to the nearest tenths should give you 4.3

Answer: 31.0

Step-by-step explanation:

Answer:

x ≥ - 1

Step-by-step explanation:

the solid circle above - 1 on the number line indicates that x can equal - 1

the arrow points right indicating x is greater than or equal to - 1 , that is

x ≥ - 1

Answer:

18.7 units

Step-by-step explanation:

Diagonal² = 1² + 1²

                 = 2

[tex]\sf diagonal = \sqrt{2} = 1.41\\[/tex]

Perimeter = 3 + 3 + 9 *1.41

                =  3 + 3 + 12.69

                = 18.7 units

Answer:

38cm

Step-by-step explanation:

set 3x-5 and 19-x equal to eachother, since, given as its an isoscles triangle, they should be equal. After you work out the equation, you're left with x=6. So now you plug that it.

3(6)-5=13

19-(6)=13

2(6)=12

Now you add them all together, so the perimeter is 38 cm.

Answer:

Determine the equation of the circle.

Equation of a circle

[tex](x-a)^2+(y-b)^2=r^2[/tex]

(where (a, b) is the center and r is the radius)

Given:

Substitute the given values into the formula to determine the equation of the circle:

[tex]\implies (x-0)^2+(y-0)^2=7^2[/tex]

[tex]\implies x^2+y^2=49[/tex]

Given point:  [tex](-3,2\sqrt{10})[/tex]

Input the x and y values of the given point into the derived circle equation.  If it equals 49, then the point is on the circle:

[tex]\implies (-3)^2+(2 \sqrt{10})^2=9+40=49[/tex]

Therefore, the given point is on the circle centered at the origin with a diameter of 14 units.

Quarts they pick altogether 173/24 quarts.

A unit of volume or capacity in the US Customary System, used in liquid measure, equal to 2 pints or 32 ounces (0.946 liter).

Jennifer picked= 1 5/6= 11/6 quarts

Lila picked= 7/4 quarts

Elliott picked =3/2 quarts

Wendie picked= 17/8 quarts

Total quarts they picked together is= 11/6+7/4+3/2+17/8

                                                           = 44+42+36+51/24

                                                           = 173/24 quarts

Hence, they picked 173/24 quarts together.

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The domain of the function is D: x ∈ (-3, 7) here the points -3 and 7 are excluded from the domain.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

As we can see in the picture, a graph is shown.

The hollow points denote that at x = -3 and x = 7 the function value is not defined, that's why these points should be excluded from the domain of the functions.

The domain of the function:

D: x ∈ (-3, 7)

Thus, the domain of the function is D: x ∈ (-3, 7) here the points -3 and 7 are excluded from the domain.

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Answer:

x=-10

Step-by-step explanation:

2(x+3)=x-4

2x+6=x-4

-2x   -2x

6=-x-4

+4    +4

10=-x

-1    -1

-10=x

[tex] \Large{\boxed{\sf x = 10}} [/tex]

[tex] \\ [/tex]

Given equation:

[tex] \sf 2(x + 3) = x - 4 [/tex]

[tex] \\ [/tex]

Expand the left side using the following distributive property:

A(B + C) = AB + AC

[tex] \\ [/tex]

Here, A = 2, B = x, and C = 3.

We get:

[tex] \sf 2(x) + 2(3) = x - 4 \\ \\ \sf 2x + 6 = x - 4 [/tex]

[tex] \\ [/tex]

Now, subtract 6 from both sides:

[tex] \sf 2x + 6 - 6 = x - 4 - 6 \\ \\ \sf 2x = x - 10 [/tex]

[tex] \\ [/tex]

Subtract x from both sides :

[tex] \sf 2x - x = x - 10 - x \\ \\ \\ \boxed{\boxed{\sf x = -10}} [/tex]

[tex] \\ \\ [/tex]

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