Which side lengths could form a triangle? Check all that apply.

A) 20,6,15
B) 8,8,17
C) 2,11,12
D) 19,34,15

Answer:

D . 8x - 3

proof

16x - (3 + 8x ) = 8x - 3

16 -3 - 8x = 8x - 3

8x -3 = 8x - 3

Answer:

CB = sqrt62

Step-by-step explanation:

The pythagorean theorem will help with this! First take triangle ACD, AD^2 + CD^2 = AC^2. Plug in, AD^2 + 16 = 25. AD^2  = 9. AD = 3. I'm not exactly sure how to find DB, but I can assume it's double of AD< so 6. We know CD is 4, so  4^2 + 6^2 = CB^2. 16 + 36 = CB^2. CB = sqrt62

Sorry if this isn't exactly right, there's no exact way to find DB.

Answer:

CB = sqrt62

Step-by-step explanation:

The Pythagorean theorem will help with this! First take triangle ACD, AD^2 + CD^2 = AC^2. Plug in, AD^2 + 16 = 25. AD^2  = 9. AD = 3. I'm not exactly sure how to find DB, but I can assume it's double of AD< so 6. We know CD is 4, so  4^2 + 6^2 = CB^2. 16 + 36 = CB^2. CB = sqrt62

Answer: the answer is B

Step-by-step explanation:

The duty of the Vaishyas is sacrifice, giving gifts, agriculture, breeding, and trade. However, later the Sudras take over agriculture and breeding and the Vaishyas become traders, merchants, landowners, and money-lenders. ... The Vaishyas also focused on religious education, because they wanted to be “twice-born”

Answer:

Is B. Vaishyas

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

A

explanation:

i answered the question

btw thanks for the brainliest

Answer:12

Step-by-step explanation:12

Answer:

C. a reflection or the x-axis,then a translation 6 units to the left

Answer:

377.62 m³

Step-by-step explanation:

V = 16 × 3.95 × 8 - 8 × 3.95 × (8 - 3.95)

V = 377.62

Answer:

5. B 6A. True 6B. True 6C. False 6D. True

Step-by-step explanation:

Answer:

[tex]Q = 96.4^\circ[/tex]

[tex]R = 58.4[/tex]

[tex]P =25.2[/tex]

Step-by-step explanation:

Given

See attachment for PQR

Required

Solve the triangle

From the attached triangle, all sidea of the triangle are known.

i.e.

[tex]PQ = 6\\QR=3\\PR=7[/tex]

So, we are to solve for [tex]\angle P, Q \& R[/tex]

Using cosine rule:

[tex]a^2 = b^2 + c^2 - 2bcCosA[/tex]

To solve for Q, we have:

[tex]PR^2 = PQ^2 + QR^2 - 2 * PQ * QR Cos(Q)[/tex]

[tex]7^2 = 6^2 + 3^2 - 2 * 6 * 3 * \cos(Q)[/tex]

[tex]49 = 36 + 9 - 36 * \cos(Q)[/tex]

Collect like terms

[tex]49 - 36 - 9 = - 36 * \cos(Q)[/tex]

[tex]4 = - 36 * \cos(Q)[/tex]

Divide both sides by -36

[tex]\cos(Q) = \frac{-4}{36}[/tex]

[tex]\cos(Q) = -0.1111[/tex]

Take arc cos of both sides

[tex]Q = cos^{-1}(0.1111)[/tex]

[tex]Q = 96.4^\circ[/tex]

To solve for R, we make use of sine rule;

[tex]\frac{a}{\sin A} = \frac{b}{\sin B}[/tex]

So, we have:

[tex]\frac{PQ}{\sin R} = \frac{PR}{\sin Q}[/tex]

[tex]\frac{6}{\sin R} = \frac{7}{\sin 96.4}[/tex]

Cross multiply

[tex]\sin R * 7 = 6 * \sin 96.4[/tex]

Solve for sin R

[tex]\sin R = \frac{6 * \sin 96.4}{7}[/tex]

[tex]\sin R = \frac{6 * \0.9938}{7}[/tex]

[tex]\sin R = 0.8518[/tex]

Take arc sin of both sides

[tex]R = sin^{-1}(0.8518)[/tex]

[tex]R = 58.4[/tex]

Solving P:

[tex]P+ Q + R = 180[/tex] --- angles in a triangle

Solve for P

[tex]P =180-Q-R[/tex]

[tex]P =180-96.4-58.4[/tex]

[tex]P =25.2[/tex]

Answer: 1/4

Step-by-step explanation:

In a stack of 24, the 2 mediums are odd and even cards in this question. This means that 1/2 the cards are even and 1/2 are odd. To get a even card once is a 1/2 chance, then to get it again is 1/2 x 1/2 chance or 1/4 chance. This is what I think.

Answer:

5/9

Step-by-step explanation:

You have 10 movies in total. You take 1 out of 6 action movies. Now you have 5 action movies left, so that means the probability is 5/9. It's 5/9 because you chose 1 action movie out of 10 movies in total, so that means there are 9 movies in total left.

Hopes this helps and makes sense!

Answer:

Jess needs to pick 4/5 pounds more of blueberries

Step-by-step explanation:

Jess needs 2 pounds, which can be written as a fraction as 10/5.

(10/5) - (2/5) - (4/5) = (4/5) more pounds of blueberries

Answer:

2:3

Step-by-step explanation:

8:12

divide by 4

2:3

Good luck on your test

Answer:Well it's probably 1:5

Step-by-step explanation:

Tell me If I was wrong :<

Answer:

Step-by-step explanation:

I think it's got 4, one on the X axis, one on the y axis,   one on the y=x  line and one on the y =-x line  :P

Simplify A:

2(x+3)-2

Use distributive property:

2x+6-2

Combine like terms:

2x+4

This is the same as B.

A and B are equivalent.

Answer:

area = 228 m^2

Step-by-step explanation:

here's your solution

=> length = 20 m. , width = 12 m

=> Area of rectangle = length*width

=> Area of rectangle = 12*20

=> Area of rectangle = 240 m^2

now we need to find area of traingle

=> base = 4 m. , height = 6 m

=> area of traingle = 1/2*base*height

=> area of traingle = 1/2*4*6

=> area of traingle = 12 m^2

=> now , area of figure = 240 m^2 - 12 m^2

=> 228 m^2

hope it helps

Answer:

p= 66.32 m

a= 228 m squared

Step-by-step explanation:

Answer:

3+2=5

Step-by-step explanation:

Answer:

3+1+1

Step-by-step explanation:

3+1+1=5, and 1+1=2, and 3+2=5.

Answer:

C) -8 + 3a + 10 -a = 2a + 2

Step-by-step explanation:

I think the answer might be C.

Step-by-step explanation:

That is because if you look at C, it is -8 + 3a + 10 - a. Since it says -a, it means you have to subtract 3a - a = 2a, since a variable equals one in algebra.  Then all that is left is -8 + 10, which will give you 2, which will give you 2a + 2. Hope this helps.

Answer:

[see below]

Step-by-step explanation:

[tex]5x+13\geq -37\\\\5x+13-13\geq -37-13\\\\5x\geq -50\\\\\frac{5x\geq -50}{5}\\\\ \boxed{x\geq -10}[/tex]

Hope this helps.

I already answer this on the other one, but here it is again.

Answer:

13 5/8 Or 13.625

Explanation:

• Let's start with 1/4. There are five days that has the amount of 1/4 of rainfall.

So we have to add all five of the 1/4 or just multiply:

1/4 x 5 = 5/4

• Now for the 3/8. There are twelve days that has that amount of rainfall.

3/8 x 12 = 36/8

· For 1/2. There are five days.

1/2 x 5 = 5/2

· For 5/8. There's five days.

5/8 x 5 = 25/8

• Lastly for 3/4. There is three days.

3/4 x 3 = 9/4

• Now we add all of the amount together: 5/4 + 36/8 + 5/2 + 25/8 + 9/4

- To add, we have to find the Least Common Denominator (LCD), which is 8.

So we have to make all of the fractions into a denominator of 8 by multiplying:

5/4 –> 10/8 (Multiply by 2)

36/8 (Stays the same, already have the denominator of 8)

5/2 –> 20/8 (Multiply by 4)

25/8 (Stays the same, already have the denominator of 8)

9/4 –> 18/8 (Multiply by 2)

• Now add:

10/8 + 36/8 + 20/8 + 25/8 + 18/8 = 109/8

109/8 = 13 5/8

Or as decimal form: 13.625

Answer:

9)  3.7 in

10) 12 in²

11) 18 in³

12) V=432π cm³

   TSA= 216π cm²

13)V=448π ft³

   TSA=240π ft²

Step-by-step explanation:

9) Since all side of the trapezium are the same the height = perpendicular line which is 3.7 in

10) 3×4 (the quadrilateral at the bottom)

11)∵ A= Cross-sectional area× height

  ⇒A= Area of the trapezium × 4

  ∴ A=[tex]\frac{1}{2} \\[/tex] (sum of the parallel sides) × 4

  A=[tex]\frac{1}{2} \\[/tex] (3+6) × 4

  A= 18 in²

12) V=πr²h

    V=π(6)²(12)

⇒V=432 cm³

   TSA=2(πr²)+2πrh

  TSA=2(π(6)²)+2π(6)(12)

 ⇒TSA=240π cm²

13. V=πr²h

    V=π(8)²(7)

   V=448π ft³

TSA=2(πr²)+2πrh

TSA=2(π(8)²)+2π(8)(7)

TSA=240π ft²

9)  3.7 in

10) 12 in²

11) 18 in³

12) V=432π cm³

   TSA= 216π cm²

13)V=448π ft³

   TSA=240π ft²

Answer:

x = 0

Step-by-step explanation:

take the root of both sides and solve

I hope this helps :)

Answer:

87

Step-by-step explanation:

Answer:

Non-statistical

Step-by-step explanation:

Answer:

If you are asking just me, or one person, non statistical, OR if you were asking more than one person, that would be statistical

Step-by-step explanation:

Answer:

[tex]A_f=470ft[/tex]

[tex]P_f=88ft[/tex]

Step-by-step explanation:

From the question we are told that:

Width of Portrait [tex]w=10inches[/tex]

length of Portrait [tex]l=13inches[/tex]

Frame each [tex]l_W=21/4inch each[/tex]

Generally the equation for area of portrait A is mathematically given by

[tex]A=w*l\\A=10*13\\A=130m^2[/tex]

Generally the equation for Perimeter of portrait is mathematically given by

[tex]P=2(w+l)\\P=2(10+13)\\P=46m[/tex]

Generally the equation for area of portrait  with frame is mathematically given by

[tex]A=w_f*l_f[/tex]

where

w_f=width of portrait with frame

[tex]w_f=2*21/4+w\\w_f=2*21/4+10\\w_f=20.5ft[/tex]

l_f=Length of portrait with frame

[tex]l_f=2*21/4+l\\l_f=2*21/4+13\\l_f=23.5ft[/tex]

Therefore Area of picture with frame

[tex]A_f=w_f*l_f[/tex]

[tex]A_f=20.5*23.5[/tex]

[tex]A_f=470ft[/tex]

Generally the equation for Perimeter of portrait is mathematically given by

[tex]P_f=2(w_f+l_f)\\P_f=2(20.5+23.5)\\P_f=88ft[/tex]