Answer:
Incomplete combustion produces carbon monoxide (CO), a toxic gas.
Explanation:
Combustion is the rapid chemical reaction of oxygen in the air or direct oxygen, which is defined as oxidizer, with the different elements that make up the fuel (mainly carbon (C) and hydrogen (H)). These chemical reactions release energy producing local increases in temperature, which causes a flow of heat to the outside.
In other words, on the one hand you have the fuel, which is the substance that oxidizes and that you can find in a solid, liquid or gaseous state and which is made up mostly of carbon and hydrogen.
The oxidizer, for its part, is the substance that oxidizes the fuel, and it is generally the oxygen found in the air.
Certain amounts of oxidizer and fuel must come into contact for combustion to occur.
Incomplete combustion occurs when part of the fuel does not fully react. Incomplete combustion produces carbon monoxide (CO), a toxic gas.
If n = 7 and 1= 5 then what are the possible values of m?
4-,3-,2-,1-,0,1,2,3,4
What is the percent composition by mass of sulfur in Na2SO4
Answer:
22.6%
Explanation:
I just answered and got it right
PLZ HELP ME!!!! BEING TIMED!!!!
Answer:
it will A. d. e. f option above
If the theoretical yield of a reaction was calculated to be 39.2 grams and when the experiment was conducted the amount produced was 12.7 grams, the what is the percent yield of the experiment?
Answer:
32.4%
Explanation:
%Yield = Actual Yield/Theoretical Yield x 100% = (12.7/39.2)100% = 32.4%
any two substances whih are tasteless
Answer:
Taste comes from the stimulation of chemical receptors in nerve cells on the tongue by particular chemical structures of substances. If there are no chemical structures pertaining to any of the chemical sensors, the substance would appear to be tasteless. All of these chemicals interact with the sensors with the help of the medium of saliva which has a lot of water. For example: the salt sensors might be susceptible to ions and the sweet sensors might be susceptible to hydroxyl groups on the sugars.
Now, taste is not a very precise field of study. A same substance may taste subtly different to different people. Can we be sure that water has no taste? The chemical sensors are always exposed to water. It might be that there are no sensors for water. It might also be that the signal for water is negated as a background signal. If water did have a particular taste, one thing is for certain, we would be tasting water in every bite of food and even at times when we are not eating as we always have saliva in your mouth.
Hope this helps, have a wonderful day/night, and stay safe!
In order to heat a round bottom flask in a heating mantle, plug the heating mantle into _______.Turn the heat up _________, and do not exceed _______ of the maximum output of the device.
Answer:
A Variac or Powermite; gradually; 50-60%.
Explanation:
A chemical reaction can be defined as a chemical process which typically involves the transformation or rearrangement of the atomic, ionic or molecular structure of an element through the breakdown and formation of chemical bonds to produce a new compound or substance.
Some of the laboratory apparatus (equipment) used for conducting a chemical reaction are conical flask, Bunsen burner, beaker, tongs, crucible, round bottom flask etc.
In order to heat a round bottom flask in a heating mantle, plug the heating mantle into a Variac or Powermite which is typically used for controlling the level of temperature. Turn the heat up gradually, and do not exceed 50-60% of the maximum output of the device, so as to avoid any electrical issues such as overloading, short-circuit etc.
The safety precautions that must be taken when using a round bottom flask are;
I. A proper inspection of the round bottom flask for cracks, irregularities or any imperfection.
II. Ensure you avoid heating the flask while it is closed.
III. When suspending the round bottom flask on a stand, you should ensure that you use a clamp for stability.
Convert 0.760 atm to mmHg
Answer:
577.6 mmHg
Explanation:
What is the conversion between atm (standard atmosphere) and mmHg (millimeters of mercury)?
Multiply the atm amount by 760 to get the mmHg amount.
19/25 * 760/1
19/5 * 152/1
(19*152)/5
2888/5
577 3/5 or 577.6 mmHg
Shivani measures out 6.0 moles of epsom salt (MgSO) to put her bath. How many grams MgSO4 went in the bath?
Answer: 720 g
Explanation:
To solve this we must be knowing each and every concept related to mole. Therefore, shivani measures out 6.0 moles of epsom salt (MgSO[tex]_4[/tex]) to put her bath. 1,566g MgSO[tex]_4[/tex] went in the bath.
What is mole?A mole is merely a measuring unit. In reality, it is one of its International System of Units' seven foundation units. When current units are insufficient, new units are created.
Chemical reactions frequently occur at levels where employing grams would be inappropriate, but using absolute quantities of atoms/molecules/ions would also be misleading.
For all practical reasons, one mole of a substance in grams is nearly equal to 1 molecule for the compound per daltons.
Mathematically,
number of mole =given mass ÷ molar mass
number of mole=6.0 moles
molar mass of epsom= 261.47g/mol
substituting all the given values in the above equation, we get
6.0 moles =mass of epsom ÷ 261.47g/mol
mass of epsom =1,566g
Therefore, 1,566g MgSO[tex]_4[/tex] went in the bath.
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A chemist adds 470.0 mL of a 8.8 times 10^-5 mM silver(II) oxide (AgO) solution to a reaction flask. Calculate the mass in micrograms of silver(II) oxide chemist has added to the flask. Round your answer to 2 significant digits.
Answer:
5.1 μg
Explanation:
Step 1: Given data
Volume of solution (V): 470.0 mL (0.4700 L)
Concentration of the solution (C): 8.8 × 10⁻⁵ mM (8.8 × 10⁻⁸ M)
Step 2: Calculate the moles (n) of AgO added
We will use the following expression.
n = C × V
n = 8.8 × 10⁻⁸ mol/L × 0.4700 L
n = 4.1 × 10⁻⁸ mol
Step 3: Calculate the mass (m) corresponding to 4.1 × 10⁻⁸ moles of AgO
The molar mass of AgO is 123.87 g/mol.
4.1 × 10⁻⁸ mol × 123.87 g/mol = 5.1 × 10⁻⁶ g
Step 4: Convert "m" to micrograms
We will use the conversion factor 1 g = 10⁶ μg.
5.1 × 10⁻⁶ g × 10⁶ μg/1 g = 5.1 μg
For each trial, enter the amount of heat lost by the metal, qmetal.
Hint: The specific heat of water is 4.184 J/goC. Be careful of your algebraic sign here and remember that the change in temperature is equal to the final temperature minus the initial temperature. Your answer should be reported to 4 digits.
Note: You should always carry 1 or 2 extra digits beyond the number of significant figures until your final calculation.
Trial # MASS Metal Ti metal Mass cool water Ti water Tr q metal
#1: 183.428 101.2 70.001 24.2 38.2
#2: 183.430 101.0 70.008 24.0 37.8
#3 183.430 100.7 70.271 23.2 36.6
Answer:
Trial 1: Heat lost by the metal = -4100 J
Trial 2: Heat lost by the metal = -4042 J
Trial 3: Heat lost by the metal = -3940 J
Explanation:
Assuming that all of the heat lost by the metal is transferred to the water and no heat is lost to the surroundings; Heat lost by metal = heat gained by water. Qmetal = -Qwater
Note: If the experiment was carried out in a calorimeter of known heat capacity, some heat is lost to the calorimeter.
Hence, Qmetal = -(Qwater + Qcalorimeter)
Quantity of heat, q = mass * specific heat capacity * temperature change
Trial 1
mass of water = 70.001 g
specific heat capacity of water = 4.184 J/g/°C
Initial temperature of water = 24.2 °C
final temperature of mixture = 38.2 °C
Temperature change of water = 38.2 - 24.2 = 14.0 °C
Heat gained by water = -(70.001 * 4.184 * 14.0) = -4100 J
Therefore, heat lost by the metal = -4100 J
Trial 2
mass of water = 70.008 g
specific heat capacity of water = 4.184 J/g/°C
Initial temperature of water = 24.0 °C
final temperature of mixture = 37.8 °C
Temperature change of water = 37.8 - 24.0 = 13.8 °C
Heat gained by water = -(70.008 * 4.184 * 13.8) = -4042 J
Therefore, heat lost by the metal = -4042 J
Trial 3
mass of water = 70.271 g
specific heat capacity of water = 4.184 J/g/°C
Initial temperature of water = 23.2 °C
final temperature of mixture = 36.6 °C
Temperature change of water = 36.6 - 23.2 = 13.4 °C
Heat gained by water = -(70.271 * 4.184 * 13.4) = -3940 J
Therefore, heat lost by the metal = -3940 J
Rank the following in order of increasing molar mass: H2O2, I2, LiF, CH6N.
A. I2< LiF < H2O2 < CH6N
B. LiF < CH6N
C. H2O2 < LiF < I2 < CH6N
D. CH6N < H2O2 < I2 < LiF
Answer:
B. LiF < CH6N < H2O2 <I2
Explanation:
Find the molar mass of LiF
To do that, first look at the atomic mass of each element on the periodic table.
Li = 6.9 amuF = 19.0 amuBut they are one lithium atom and one fluorine atom
So you use this equation:
6.9(1) + 19.0(1) = 25.9LiF has 25.9 g/mol
Now find the molar mass of CH6N.
To do that, first look at the atomic mass of each element on the periodic table.
C = 12.0 amuH = 1.0 amuN = 14.0 amuBut they are six hydrogen atoms, one carbon atom, and one nitrogen atom.
So you use this equation:
12.0 + 1.0(6) + 14.0 = 32CH6N has 32 g/mol
Now find the molar mas of H2O2
To do that, first look at the atomic mass of each element on the periodic table.
H = 1.0 amuO = 16.0But they are two oxygen atoms and two hydrogen atoms.
So you use this equation:
1.0(2) + 16.0(2) = 34H2O2 has 34 g/mol.
Lastly, find the molar mass of I2
To do that, first look at the atomic mass of each element on the periodic table.
I = 126.9 amuBut they are two iodine atoms.
So you use this equation:
126.9(2) = 253.8I2 has 253.8 g/mol
Now that we calculated the molar mass of all elements. We rank it in the following of increasing atomic mass.
So LiF has the lowest molar mass(which is 25.9).CH6N has the second lowest molar mass(which is 32). H2O2 has the second highest molar mass(which is 34)I2 has the highest molar mass(which is 253.8)25.9 < 32 < 34 < 253.8Therefore, the final answer is B. LiF < CH6N < H2O2 <I2
Hope it helped!
Which atom is most likely to partake in chemical bonding given the number of valence electrons?
A. Krypton
B. Argon
C. Xenon
D. Boron
Need help****
Answer:
D
Explanation:
I hope this helps and have a great day
PLZ HELP IM NO SURE IF I PUT THE RIGHT ANSWER!!!!!!!!
that is the correct answer don't worry :))
Write three complete and balanced pairs of below mention electrochemical half reactions. For each pair of reactions, identify which reaction is the cathode reaction and which reaction is the anode reaction,
a. Cu → Cu2+ +2e-
b. 2H+ 2e →H2
c. O2- → 1/2O2 + 2e
Answer: a) [tex]Cu\rightarrow Cu^{2+}+2e^-[/tex] : anode
b. [tex]2H^++2e^-\rightarrow H_2[/tex] : cathode
c. [tex]O^{2-}\rightarrow \frac{1}{2}O_2+2e^-[/tex]: anode
Explanation:
Electrochemical cell is a device which converts chemical energy into electrical energy. It consist of two electrodes, anode and cathode.
Oxidation i.e. loss of electrons , which results in an increase in oxidation number occurs over anode.
Reduction i.e. gain of electrons, which results in decrease in oxidation number occurs over cathode.
a. [tex]Cu\rightarrow Cu^{2+}+2e^-[/tex] : oxidation : anode
b. [tex]2H^++2e^-\rightarrow H_2[/tex] : reduction : cathode
c. [tex]O^{2-}\rightarrow \frac{1}{2}O_2+2e^-[/tex]: oxidation : anode
Peeling a banana is an example of a
A. no change
B. chemical change
C. physical change
Answer:
C. Physical Change
Explanation:
Peeling a banana is not changing the banana's structure, it's still the same banana, but it looks different, which is a chemical change! Hope I helped!
An ionic compound contains 2 potassium cations for every 1 oxygen anion. What is the chemical formula of the compound?
Answer:
Chemical formula of the compound = K₂O
Explanation:
Given:
Number of potassium cation = 2
Number of oxygen anion = 1
Cross valency
Symbol of potassium = k
Symbol of oxygen = o
So;
Chemical formula of the compound = K₂O
What happens to the number of protons in a cation?
Answer:
number of protons is more than the number of electrons.
Explanation:
A cation is a positively charged ion.
An ion is an atom that has lost or gained electron(s). In an ion, the number of protons and electrons are not the same.
Number of protons is the number of positively charged particles
Number of electrons is the number of negatively charged particles.
For a cation, which is positively charged, the number of protons is more than the number of electrons.
Therefore, in cations, we have more protons than electrons.
Need help asap
1. All nonmetals (except hydrogen) have 8 valence electrons?
True or False
2. The N^-3 ion is classified as a(n) ____ and has ____.
A. anion, 8 valence electrons
B. cation, 8 valence electrons
C. anion, 15 valence electrons
D. anion, 3 valence electrons
3. If two nonmetals react to form a compound and have very different _____ they form ____ bonds. If there is a small difference, then they form ____ bonds.
A. ionization energy; covalent; nonpolar ionic
B. electronegativity; nonpolar covalent; polar covalent.
C. ionization energy, ionic, nonpolar covalent
D. electronegativity, polar covalent, nonpolar covalent.
Answer:
1: false
2: B
Explanation:
I do not know the 3rd one
Directions: Select the words that make the sentence a true statement Below is a food web showing the flow of energy through a marine ecosystem marine mammals tuna fish aquida craba zooplankton amall fishes doad animal material 3 phytoplankton In this ecosystem are considered predators and are their prey
Answer: in this ecosystem tuna fish are considered predators and small fishes are their prey.
Explanation: This is just an easy smart guess why? because the Tuna fish(predator) eat the small fishes(prey) as if what it looks like in the chart.
Im not sure about this question but i hope this helps
Answer:
in this ecosystem tuna fish are considered predators and small fishes are their prey.
Explanation:
A student puts some sugar in a glass of water and stirs until the sugar is dissolved.
Why is sugar dissolving in water an example of a physical change?
O because the sugar and water are both clear
B. because the sugar gives off gas bubbles when it is dissolved in the water
O c because the student started with sugar and water, and ended with sugar and water
O D. because the sugar and water molecules break apart, and then recombine in different ways
Answer:
It does not change the identity of a substance. Sugar if dissolved in water is still sugar.
Explanation:
describe the difference between a physical and chemical change explain what happens during a checmical reaction
Explanation:
A physical change is a change that alters the physical properties of matter particularly the form and state.
In many cases the change is easily reversible. Examples are changes of state such as freezing, boiling, melting e.t.c
A chemical change is a change in which a new kind of matter is formed. It is always accompanied by energy changes which can either be evolution or absorption of heat or light or both.
The process is not easily reversible. Examples are combustion, rusting of iron, precipitation, e.t.c
During a chemical reaction, the reactants undergo a chemical change.
How is the temperature scale different than a typical thermometer?
What are the names of the compounds containing silver?
Show the compound formula and their names. (WRITE CLEARLY AND NEATLY OR THE QUESTION WILL BE CONSIDERED WRONG)
Answer:
the silver compounds include:
silver chloride agcl ,
silver bromide agbr ,
and silver iodide agi.
What volume is occupied by 2.719 x 1013 moles of methane gas, CH4?
Answer:
6.5256×10¹⁴
Explanation:
n= v/24
v= n×25
v= 2.719×10¹³ × 24= 6.5256×10¹⁴ moles/dm³
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According to ideal gas equation, the volume occupied by 2.719 x 10¹³ moles of methane gas is 6174.76×10¹³cm³.
What is ideal gas equation?The ideal gas equation is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.Ideal gases exist in hypothetical state.The law was proposed by Benoite Paul Emile Clapeyron in 1834.
Substituting values of pressure=1 atmosphere,number of moles=2.719 x 10¹³ ,R=8.314 ,T=273.15 K.
Therefore volume=nRT/P=2.719x 10¹³×8.314×273.15/1=6174.76×10¹³ cm³.
Thus, the volume occupied by 2.719 x 10¹³ moles of methane gas is 6174.76×10¹³cm³.
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A canister containing air has a volume of 85 cm3 and a pressure of 1.45 atm when the tenoerature is 310 k. What is the pressure when the volune is increased to 180 cm3 and the temeprarje is reduced to 280 k?
Answer:
Pressure = 0.62 atm
Explanation:
[tex]V_{1}[/tex] = 85 [tex]cm^{3}[/tex], [tex]P_{1}[/tex] = 1.45 atm, [tex]T_{1}[/tex] = 310 K, [tex]V_{2}[/tex] = 180 [tex]cm^{3}[/tex], [tex]T_{2}[/tex] = 280 K.
Applying the general gas law,
[tex]\frac{P_{1} V_{1} }{T_{1} }[/tex] = [tex]\frac{P_{2} V_{2} }{T_{2} }[/tex]
[tex]\frac{1.45*85}{310}[/tex] = [tex]\frac{P_{2}*180 }{280}[/tex]
[tex]P_{2}[/tex] = [tex]\frac{1.45*85*280}{180*310}[/tex]
= [tex]\frac{34510}{55800}[/tex]
= 0.62
[tex]P_{2}[/tex] = 0.62 atm
The pressure when the volume is increased and the temperature reduced to the given values is 0.62 atm.
What is the molar mass of Mg(CIO3)2
CaC12 + NaCO3–>CaCO3 +NaC1
when the equation above is correctly balanced with integer coefficients the sum of the coefficients is
A:4
B:5
C:6
D:10
How many moles are in the following:
7.36 x 1024 of free Oxygen atoms
Answer: 12.2 moles
Explanation:
7.36x10^24/6.02214076x10^23 = 12.2 moles of free oxygen atoms
What is the kinetic energy of a ball when it stops moving?
Question 2 options:
3
2
1
Answer:0
Explanation:
do all atoms only have one oxidation state