Why do you put a voltmeter in parallel with a resistor in order to measure the change of electric potential energy?.

Answers

Answer 1

Answer:

A voltmeter is an instrument used for measuring electrical potential difference between two points in an electric circuit. An ammeter is a measuring device used to measure the electric current in a circuit. A voltmeter is connected in parallel with a device to measure its voltage, while an ammeter is connected in series with a device to measure its current.

Explanation:

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Related Questions

A circular disk of moment of inertia [tex]I_t[/tex] is rotating in a horizontal plane, about its axis , with a constant angular speed [tex]\omega_i[/tex] . Another disc of moment of inertia [tex]I_b[/tex] is dropped coaxially onto the rotating disk. Initially the 2nd disc has 0 angular speed. Eventually both the disks rotate with a constant angular speed [tex]\omega_f[/tex] . The energy lost initially rotating disk to friction is ? ​

Answers

The kinetic energy of the circular disc in initial state is,

[tex]K^{1r} = \frac{1}{2}I^{t}ω^{ \frac{2}{i} } [/tex]

The initial kinetic energy of the other disc dropped on the first disc is,

[tex]K^{2r} = \frac{1}{2}I^{b}(0)^{2}[/tex]

[tex] = > K^{2r} = 0J[/tex]

As both the disc in the final state are moving with the same angular velocity, thus, the net kinetic energy in the final state is,

[tex]E^{f} = \frac{1}{2}(I^{t} + I^{b})ω^{ \frac{2}{f} }[/tex]

The net kinetic energy in the initial state is,

[tex]E^{i} = K^{1r} + K^{2r}[/tex]

[tex] = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} } + 0[/tex]

[tex] = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} }[/tex]

Thus, the change in the kinetic energy during the change of state is,

[tex]dE = E^{f} - E^{i}[/tex]

[tex] = > dE = \frac{1}{2} (I^{t} + I^{b})ω^{ \frac{2}{f} } - \frac{1}{2}I^{t}ω^{ \frac{2}{i} } [/tex]

[tex] = > dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } [/tex]

This change in value of energy is the energy lost initially rotating the disk to friction.

Hence, the energy lost in the given case is [tex]dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } [/tex]

The energy lost initially by the rotating disk to friction is equal to [tex]\frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2[/tex]

Given the following data:

Angular speed = 0

How to calculate the energy lost.

At the initial state, the kinetic energy of the circular disc is given by this formula:

[tex]K.E = \frac{1}{2} I_t\omega_i^2[/tex]

For the second disc, the initial kinetic energy is given by this formula:

[tex]K.E_2 = \frac{1}{2} I_b\omega_f^{2 }\\\\K.E_2 = \frac{1}{2} I_b(0)^{2 }\\\\K.E_2 = 0[/tex]

At the final state, the discs would move with the same angular velocity and the net kinetic energy is given by this formula:

[tex]E_f = \frac{1}{2} (I_t + I_b)\omega_f^2[/tex]

For the energy lost:

Also, the change in the kinetic energy is given by this formula:

[tex]\Delta E = E^f - E^i\\\\\Delta E = \frac{1}{2} (I_t + I_b)\omega_f^2 - \frac{1}{2} I_t\omega_i^2\\\\\Delta E = \frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2[/tex]

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What is the mass of an object traveling at 30. m/s if it has 33,750 J of energy?​

Answers

Answer:

[tex]30 \div 33750 = 0.008888[/tex]

What is Socio historical context​

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Answer:

It is the combination of social and historical factors.

A car accelerates from to at a constant rate of How far does it travel while accelerating?.

Answers

Distance is the measure of the length of ground covered by an object during its motion. Distance is a scalar quantity. The car will travel 69 m while accelerating.

What is the distance?

Distance is the measure of the length of ground covered by an object during its motion. While the displacement is defined as the shortest distance between the two paths.

Distance is a scalar quantity. While displacement is a vector quantity. Mathematically it is given as the product of speed and time.

The following data are given in the problem as

u is the initial  speed=5.0 m/sec

v is the final speed=21 m/sec

s is the distance covered by the car =?

a= Acceleration of car =3.0 m/sec²

According to Newton's third equation of motion, the formula derived will be

[tex]\rm{v^2=u^2+2as \\\\[/tex]

[tex]\rm s = \frac{v^2-u^2}{2a} \\\\\rm s = \frac{(21)^2-(5)^2}{2\times3.0} \\\\ \rm s=69 m[/tex]

Hence the car will travel 69 m while accelerating.

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Determinati rezistenta unui conductor electric daca prin el circula un curent de 0,3 a, iar tensiunea masurata la capetele lui este 0.05 v

Answers

WHAT? I DON'T UNDERSTAND WHAT ARE YOU SAYING

Jill runs for 20 seconds at 10 m/s, how far did she travel?

Answers

Answer:

200 (m) for 20 seconds

10 times 20 is 200

Answer:

200

Explanation:

Jill is running at 10 meters per second

20 * 10 = 200

A chair is pushed backward with a force of 100 N. The gravitational force of Earth on the
chair is 120 N downward, and the floor exerts a force of 120 N upward on the chair.
Draw a free-body diagram showing the forces acting on the chair.

Answers

Explanation:

he fell down with telling any one,

Describe the magnetic field lines between like poles.(what is the direction indicated and why

Answers

Answer/Explanation:

The magnetic fields line are closer apart at other places. Hence, magnetic field is strongest at the poles. Magnetic Field has Direction The Magnetic Field lines are like closed curves They emerge from North Pole and Merge to South Pole.

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Ata football match between two college teams, the referee ordered a free kick. The ball of mass 1.5 kg was placed at rest. The kick was about to be taken by an eager footballer.

What was the potential energy of the ball just before the kick was taken?​

Answers

The potential energy of the ball just before the kick was taken is zero (0).

What is Potential energy?

Potential energy is the energy possessed by an object due to its position above the ground.

Potential energy of the ball

The Potential energy of the ball is calculated as follows;

P.E = mgh

where;

m is the mass = 1.5 kgh is height of the ball above the ground = 0

P.E = 1.5 x 9.8 x 0

P.E = 0

Thus, the potential energy of the ball just before the kick was taken is zero (0).

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How much power does it take to do 400 joules of work in 5 seconds?

Answers

Answer:

Explanation:

Power = work / time

P = 400 J / 5 s

P = 80 watts

what are the things to consider in planning food for the family?​

Answers

Answer:

tips to get you started

Make a menu. ...

Plan your meals around foods that are on sale. ...

Plan at least one meatless meal a week. ...

Check your pantry, refrigerator and freezer. ...

Enjoy grains more often. ...

Avoid recipes that need a special ingredient. ...

Look for seasonal recipes. ...

Plan to use leftovers.

Explanation:

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When a car of mass 1167 kg accelerates from 10.0 m/s to some final speed, 4.00  10 5J of work are done. Find this final speed.

Answers

Mass=1167kgInitial velocity=u=10m/sAcceleration=a=4m/s^2Work done=105J=WFinal velocity=v=?Force=FDistance=d

Apply Newton's second law

[tex]\\ \tt\hookrightarrow F=ma[/tex]

[tex]\\ \tt\hookrightarrow F=1167(4)=4668N[/tex]

Now

[tex]\\ \tt\hookrightarrow W=Fd[/tex]

[tex]\\ \tt\hookrightarrow d=\dfrac{W}{F}[/tex]

[tex]\\ \tt\hookrightarrow d=\dfrac{105}{4668}[/tex]

[tex]\\ \tt\hookrightarrow d=0.022m[/tex]

Now

d be s

According to third equation of kinematics

[tex]\\ \tt\hookrightarrow v^2=u^2+2as[/tex]

[tex]\\ \tt\hookrightarrow v^2=10^2+2(4)(0.022)[/tex]

[tex]\\ \tt\hookrightarrow v^2=100+8(0.022)[/tex]

[tex]\\ \tt\hookrightarrow v^2=100+0.176[/tex]

[tex]\\ \tt\hookrightarrow v^2=100.176[/tex]

[tex]\\ \tt\hookrightarrow v=10.001m/s[/tex]

The area of a room that is 10 feet wide and 12 feet long is
13.3 square feet
14 square yards
120 square feet
12 squa2 yards

Answers

A=length *wide =12*10=120square feet. Note/1feet=30cm

A lightening rod saves us from lightening give reason
Can you tell me by looking this book
Please fast ​

Answers

Answer:

Because Rod protect house from burning down and people from electrocution.

what is the impulse applied to the block

Answers

Answer:

i do not know can i get brainliest im broke

Explanation:

A charge is divided q1 and (q-q1)what will be the ratio of q/q1 so that force between the two parts placed at a given distance is maximum?

Answers

Answer:

[tex]q / q_{1} = 2[/tex], assuming that [tex]q_{1}[/tex] and [tex](q - q_{1})[/tex] are point charges.

Explanation:

Let [tex]k[/tex] denote the coulomb constant. Let [tex]r[/tex] denote the distance between the two point charges. In this question, neither [tex]k[/tex] and [tex]r[/tex] depend on the value of [tex]q_{1}[/tex].

By Coulomb's Law, the magnitude of electrostatic force between [tex]q_{1}[/tex] and [tex](q - q_{1})[/tex] would be:

[tex]\begin{aligned}F &= \frac{k\, q_{1}\, (q - q_{1})}{r^{2}} \\ &= \frac{k}{r^{2}}\, (q\, q_{1} - {q_{1}}^{2})\end{aligned}[/tex].

Find the first and second derivative of [tex]F[/tex] with respect to [tex]q_{1}[/tex]. (Note that [tex]0 < q_{1} < q[/tex].)

First derivative:

[tex]\begin{aligned}\frac{d}{d q_{1}}[F] &= \frac{d}{d q_{1}} \left[\frac{k}{r^{2}}\, (q\, q_{1} - {q_{1}}^{2})\right] \\ &= \frac{k}{r^{2}}\, \left[\frac{d}{d q_{1}} [q\, q_{1}] - \frac{d}{d q_{1}}[{q_{1}}^{2}]\right]\\ &= \frac{k}{r^{2}}\, (q - 2\, q_{1})\end{aligned}[/tex].

Second derivative:

[tex]\begin{aligned}\frac{d^{2}}{{d q_{1}}^{2}}[F] &= \frac{d}{d q_{1}} \left[\frac{k}{r^{2}}\, (q - 2\, q_{1})\right] \\ &= \frac{(-2)\, k}{r^{2}}\end{aligned}[/tex].

The value of the coulomb constant [tex]k[/tex] is greater than [tex]0[/tex]. Thus, the value of the second derivative of [tex]F[/tex] with respect to [tex]q_{1}[/tex] would be negative for all real [tex]r[/tex]. [tex]F\![/tex] would be convex over all [tex]q_{1}[/tex].

By the convexity of [tex]\! F[/tex] with respect to [tex]\! q_{1} \![/tex], there would be a unique [tex]q_{1}[/tex] that globally maximizes [tex]F[/tex]. The first derivative of [tex]F\![/tex] with respect to [tex]q_{1}\![/tex] should be [tex]0[/tex] for that particular [tex]\! q_{1}[/tex]. In other words:

[tex]\displaystyle \frac{k}{r^{2}}\, (q - 2\, q_{1}) = 0[/tex].

[tex]2\, q_{1} = q[/tex].

[tex]q_{1} = q / 2[/tex].

In other words, the force between the two point charges would be maximized when the charge is evenly split:

[tex]\begin{aligned} \frac{q}{q_{1}} &= \frac{q}{q / 2} = 2\end{aligned}[/tex].

After the softball leaves your hand, it rises, slowing down.

Answers

Answer:

yes it do rises and then fall down due to gravitational

O True
False
Question 15
2 pts
Kiana rides her skateboard with a constant speed of 6 km/h. How long will she take to travel a distance
of 10 kilometers? Please SHOW YOUR WORK

Answers

T = D/ST = 10/6T = 5 × 2/2 ×3T = 5/3T = 1.67 (approx)

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Why is soccer a great athletic sport

Answers

Answer:

that is the answer

Explanation:

look at it

A neutral atom of Fluorine has seven valence electrons. How many valence electrons are present in the ion F-1?

Answers

Answer:

8 valence electrons

Explanation:

Fluoride is F^-, so it has one additional electron, which is expected to be in a valence level (completing a closed-shell inert-gas structure). Thus fluoride should be 1s^2,2s^2,2p^6 , and have 8 valence electrons.

A rod 7.0 m long is pivoted at a point 2.0 m from the left end. A downward force of 50 N acts at the left end, and a downward force of 200 N acts at the right end. At what distance to the right of the pivot can a third force of 300 N acting upward be placed to produce rotational equilibrium?

Answers

If the rod is in rotational equilibrium, then the net torques acting on it is zero:

∑ τ = 0

Let's give the system a counterclockwise orientation, so that forces that would cause the rod to rotate counterclockwise act in the positive direction. Compute the magnitudes of each torque:

• at the left end,

τ = + (50 N) (2.0 m) = 100 N•m

• at the right end,

τ = - (200 N) (5.0 m) = - 1000 N•m

• at a point a distance d to the right of the pivot point,

τ = + (300 N) d

Then

∑ τ = 100 N•m - 1000 N•m + (300 N) d = 0

⇒   (300 N) d = 1100 N•m

⇒   d ≈ 3.7 m

What is the momentum of a 3-kg object moving at 5 m/s?

Answers

Answer: 15 kg*m/s

Explanation:

Momentum = mass*velocity

Momentum = 3kg*5 m/s

Momentum = 15 kg*m/s

Answer:

15 kg m/s

Explanation:

Momentum = mass xvelocity

Momentum = 3kgx 5 m/s

Momentum = 15 kg m/s

An object weighing 120 n is set on a rigid beam of negligible mass at a distance of 3 m from a pivot, as shown above. A vertical force is to be applied to the other end of the beam a distance of 4 m from the pivot to keep the beam at rest and horizontal. What is the magnitude f of the force required?.

Answers

The force required to keep the beam in equilibrium is 90 N.

Principle of moments of forces

It states that for a system at equilibrium, the sum of the clock-wise moment is equal to the sum of anti clock wise moment.

To calculate the magnitude of the force required to keep the beam at equilibrium, we use the Formula below.

Formula:

Fd = fD............... Equation 1

Where

F = Force/ weight of the objectd = Distance of the object from the pivotf = Vertical force applied on the other endD = Distance of the vertical force from the pivot.

Make f the subject of the equation

f = Fd/D............... Equation 2

From the question,

Given:

F = 120 Nd = 3 mD = 4 m

Substitute the given values into equation 2

f = (120×3)/4f = 90 N

Hence, The force required to keep the beam in equilibrium is 90 N.

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A person invests money, or ___, in a business.

Answers

Explanation:

A person invests money, or resources in a business .

How does the behaviour of s-waves and p-waves indicate the properties of the earth?.

Answers

Answer:

S waves are transverse and cannot travel through liquids. P waves are longitudinal and can travel through liquids. When an earthquake happens on one side of the Earth, P and S waves can be detected all around the world.  S waves cannot be detected on the opposite side of the earth but can be detected at angles less than or equal to 90 degrees or slightly more. This is because there is a liquid core in the centre of the earth preventing the S waves from travelling to the direct opposite side of the Earth. P waves can be detected all around the world

Explanation:

Four people return home from work and walk up the stairs to their own apartments
in the same building. Which person has gained the most gravitational potential
energy upon arriving at the door of their apartment?

A 50kg person who lives on the second floor
A 50kg person who lives on the third floor
A 100kg person who lives on the second floor
A 100kg person who lives on the third floor

Answers

Answer:

A 100 kg person who lives on the third floor

Explanation:

its ^ the answer above

Answer:
100kg person who lived on the third floor
Explanation:

The frequency, or number of waves that pass a given point per second, of
sound is measured in:
A. hertz
B. meters
C. cycles
D. frequencies

Answers

Answer:

Hertz is the answer for this question

What is the period of a pendulum that is 1.3 m long?

Answers

Answer:

T≈2.2876585681s

Explanation:

Since you were not given the degrees of amplitude or radians of amplitude, we assume that the degrees of amplitude are less than 20∘ or 20∘ and we also assume that this is a simple pendulum

Consider a gas at STP in a container of 22. 4 L. What is the approximate value of n according to the ideal gas law? 0. 5 1 2008. 31 224.

Answers

STP is defined as the standard temperature and pressure. These are some standard values given in 1982. the approximate value of n according to the ideal gas law will be 0.986.

What is the ideal gas equation?

The ideal gas equation is derived from the Boyle and Charles law states that the product of pressure and volume is directly propotional to the temperature at STP.

It is mathematically given as

[tex]\rm pv=nRT[/tex]

P is the pressure =100kPa at STP.

R is universal gas constant=8.314 j/kgk

v is the volume=22.4 L=22.4×10³ m³

T is the temperature =273.15 K at STP

[tex]\rm pv=nRT\\\\\rm n=\frac{RT}{pv} \\\\\ \rm n=\frac{8.314\times273.15}{100\times10^3\times10^{-3}} \\\\\rm n=0.986[/tex]

Hence the approximate value of n according to the ideal gas law will be 0.986.

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Answer:

1

Explanation:

1 mol = 22.4 L

BRAINLIEST OF CORRECT
Match the atom to the number of electrons it is likely to gain/lose,​

Answers

Answer:

Na: lose 1

O: gain 2

Al: lose 3

Be: lose 2

N: gain 3

Cl: depends on the limit of your study im grade nine and the energy level M can hold only eight electrons so i would have answered (gain 1)

Explanation:

The atoms according to the number of electrons it will lose or gain is matched as follows;

Sodium → lose 1

Nitrogen → gain 3

Sulphur → gain 2

Fluorine → gain 1

Boron → lose 3

Beryllium → lose 2

Atoms

Atoms are the building block of matter. The outermost electron of an atom determines the number of electron an atom loose during bonding. Therefore,

Na(sodium) with an outermost electron of one will lose 1 electron to attain the octet rule.Nitrogen with an outermost electron of 5 will easily gain 3 electrons to attain the octet ruleSulphur(S) with an outermost electron of 6 will easily gain 2 electrons to attain the octet ruleFluorine with an outermost electron of 7 will easily gain 1 electrons to attain the octet rule Boron with an outermost electron of  3 will easily loose 3 electrons to attain the octet ruleBeryllium with an outermost electron of 2 will easily loose 2 electrons to attain the octet rule

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