why is m² called derived unit?​

Answers

Answer 1

Explanation:

The unit of energy is a derived unit because it is expressed with the help of fundamental units (kg) unit of mass and four basic units meter (m), meter (m) unit of length second (s), second (s) unit of time.


Related Questions

Some aliens traveling in a group know that their spaceship launchpad is 25 miles from the gas station where they are right now. How many kilometers is that distance?

Answers

The distance between the aliens traveling in group and their launchpad in kilometers is 40.23km.

How many kilometers is that distance?

Given that data in the question;

Distance d = 25 milesDistance in kilometers = ?

Note that;

1 miles = 1.609 kilometers

Now, the distance in kilometers will be;

distance = 25 miles

distance = ( 25 × 1.609 )kilometers

distance = 40.23km

Therefore, the distance between the aliens traveling in group and their launchpad in kilometers is 40.23km.

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Which sequence describes how a convection current forms in the air?
A Warm air rises-Air gets warmer- -Warm air sinks
& Cold air rises-Air warms up-Warm air sinks
C. Warm air rises-Air cools off-Cool air sinks
D. Cold air rises-Air gets cooler-Cool air rises
W
6

Answers

Answer:

C

Explanation:

Cool and dense air falls through more warm and less dense air during convection. The cooler, which is much heavier than warm air, is displacing the warmer, which has less mass. Convection always involves rising air in the atmosphere.

Answer:

C

Explanation:

Imagine a kettle. When you open it, all the hot water vapour will rise up, attempting to burst out. However, when it comes in contact with the cold air, it also becomes cold, causing it to sink back down and giving us the visual effect of steam.

Vector V is 448 m long in a
224° direction. Vector Wis
336 m long in a 75.9°
direction.
Find the direction of their
vector sum.

Answers

The magnitude of the vector sum of the two vectors V and W is determined as 240.84 m toward + x.

What is a vector?

A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.

The following are the x and y axes for the supplied vector:

Vector V in x direction;

[tex]\rm V_x = Vcos \theta \\\\ V_x = 448cos(224^0)\\\\ Vx = -322.26[/tex]

Vector V in y direction;

[tex]\rm V_y = Vsin \theta\\\\ V_y = 448 \times sin224^0\\\\ V_y = -311.2[/tex]

Vector W in x direction;

[tex]\rm W_x = 336 \times cos(75.9^0)\\\\ W_x = 81.86[/tex]

Vector W in y direction;

[tex]\rm W_y = 336 \times sin75.9\\\\\ W_y = 325.88[/tex]

The resultant vector in the x direction is;

∑X = -322.26 + 81.86

∑X == -240.4

The resultant vector in the y direction is;

∑Y = -311.2 + 325.88

∑Y  = 14.68

The resultant vector is found as;

[tex]\rm R =\sqrt{(-240.4)^2+(14.68)^2} \\\\R = 240.84 \ m[/tex]

Hence,  the direction of their vector sum is 240.84 toward +x-axis.

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What is the period of oscillation for a pendulum that completes 3.00 cycles every 2.00 s?

Answers

Answer:

[tex]\huge\boxed{\sf T = 0.67\ seconds}[/tex]

Explanation:

Given Data:

Cycles = c = 3 cycles

Time = t = 2 seconds

Required:

Time period = T = ?

Formula:

1) f = c/t

2) T = 1/f

Solution:

Finding frequency first:

f = c / t

f = 3/2

f = 1.5 Hz

Now, finding period:

T = 1/f

T = 1 / 1.5

T = 0.67 seconds

[tex]\rule[225]{225}{2}[/tex]

Two spherical objects have masses of 8.1 x 10^2kg and 4x.5 10^8kg. The gravitational attraction between them is 1.9 x 10^-3 N.

Answers

Let's see

We need distance between them?

[tex]\\ \rm\Rrightarrow F=\dfrac{GMm}{r^2}[/tex]

[tex]\\ \rm\Rrightarrow r^2=\dfrac{GMm}{F}[/tex]

[tex]\\ \rm\Rrightarrow r^2=\dfrac{6.673\times 10^{-11}\times 8.1\times 10^2\times 4.5\times 10^8kg}{1.9\times 10^{-3}}[/tex]

[tex]\\ \rm\Rrightarrow r^2=128.02\times 10^{2}[/tex]

[tex]\\ \rm\Rrightarrow r^2=12802[/tex]

[tex]\\ \rm\Rrightarrow r=\sqrt{12802}[/tex]

[tex]\\ \rm\Rrightarrow r=113.14m[/tex]

Pick the free body diagram that correctly matches the following situation. An object is not moving.

Answers

The answer to your promise in b

what is the difference between 1 Newton/ metre² and 1 Pascal

Explain !!​

Answers

Answer:

One pascal is equivalent to 1 newton (N) of force applied over an area of 1 square meter (m2). The pascal is also used to measure stress, specifically tectonic stress in the Earth's plates.

Explanation:

How do you think animals are affected by seasonal change?

Answers

Answer:

Animals follow the seasons very closely. Changes in the length of the day or temperature affect the animals' hormone production and cause them to behave according to the season. For that reason, animals instinctively know when it's time for them to mate, build a nest, fly south or stock up on food for the winter.

A certain FM radio station broadcasts electromag-
netic waves at a frequency of 60,050,000 Hz. These
waves travel at a velocity of 30,000,000 m/s. What is
the wavelength of these radio waves?
v = λ x f

λ = v/f f=v/λ

Answers

Answer:

0.5 m

Explanation:

To find wavelength (λ) : apply the formula

λ = wave speed (v) / frequency (f)

Solving :

λ = 30,000,000 m/s / 60,050,000 Hzλ = 0.5 m (approximately)

the weight of the mass is the force that is stretching out the spring. determine the weight (F) of the mass using 9.81 m/s(to the second power) as the acceleration due to gravity on earth and record this in the column labeled "F(N)".

Answers

Because th Ara of Trish ingle


A pendulum is lifted to a certain height and then released, which causes the
pendulum to swing back and forth. If energy losses due to friction and air
resistance can be ignored, when is the energy of the system at its maximum
value?


Answers

Answer:

Answer is C

Explanation:

Let's say the pendulum starts swinging from its max height from the left. It then will go down and reach the equilibrium position, this will make it lose GPE while gaining KE (the loss in GPE = gain in KE). At the equilibrium position it has the max KE (max velocity) and minimum GPE. After passing the equilibrium it then starts to head up to the max height on the right, the pendulum gains GPE while losing KE and at the top will have minimum KE while having max GPE. Meaning throughout its joruney the total energy remains constant as
Total energy = KE + GPE

I have attached a simple diagram below, the y axis is the energy and x axis being the time (where t = 0 is the pendulum starting from max height left of the equilibrium). The green curve the the GPE and blue curve is KE. Red line shows that at all times the energy is constant.

An object is placed 15.0 cm to the left of a double-convex lens of focal length 20.0 cm. The image of this object is located.​

Answers

The image of this object is located at -60 cm. The formula for the mirror equation is used in the given problem.

What is a mirror equation?

A mirror equation is an equation that relates object distance and image distance to focal length.

The given data in the problem is;

Image distance (u) = 15 cm

Object distance (v) = ?

f is the mirror's focal length=20 cm

The mirror equation is given as;

[tex]\rm \frac{1}{v} +\frac{1}{u} =\frac{1}{f} \\\\ \rm \frac{1}{v} =\frac{1}{20} -\frac{1}{15} \\\\ \frac{1}{v} = 0.01666 \\\\\ v=-60 \ cm[/tex]

Hence, the image of this object is located at -60 cm.

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A 23900N/C electric field points down. What is the value of a charge placed in the field if it experiences a force of 7520N up?

Answers

Answer:

0.315C

Explanation:

Force/Electric field

7520N/23900C

Interference between the red and blue waves in wave set A will result in which wave?

Answers

Answer:

option 1

Explanation:

73. Integrated Concepts
An electron microscope produces electrons with a 2.00-pm wavelength. If these are passed through a 1.00-nm single slit, at what angle will the first diffraction minimum be found?

Answers

The angle will the first diffraction minimum be found will be 0.034895°.

What is diffraction grating?

A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.

The equation of diffraction grating is given as

[tex]\rm d= \frac{m \lambda}{sin \theta }[/tex]

The angle between the incident ray and the point of the occurrence of the diffraction is found as;

[tex]\theta = sin^{-1}(\frac{m\lambda}{d} )\\\\\ \lambda= (2.0))(\frac{1.00 \times 10^{-12}}{1\ pm} )\\\\\ \lambda=2.00 \times 10^{-12}[/tex]

The angle will the first diffraction minimum be found is;

[tex]\theta = sin^{-1}(\frac{m\lambda}{d} )\\\\\ \theta = sin^{-1}(\frac{1 \times 2.000 \times 10^{-12}}{1\times 10^{-12}} )\\\\\ \theta= 0.0348995^0[/tex]

Hence,the angle will the first diffraction minimum be found will be 0.034895°.

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You take a trip to Oklahoma City. The turnpike between Tulsa and OKC
is 90 miles long. You drive slowly for an hour and forty-five minutes, stop
at the rest area for fifteen minutes, then drive very fast from the rest
area to the City, arriving an hour after you left the rest area.
What was your average speed for the trip?

Answers

[tex]speed_{avg} = \frac{Σ\:distance}{ total\: time}[/tex]

So, according to the question:

distance = 90 miles

time = 1h 45min + 15 min + 1h = 3h

[tex]Therefore:\\ speed_{avg} = \frac{90}{3} mph \\ = \boxed {30 \: mph}[/tex]

What is the length of the shortest pipe closed on one end and open at the other end that will have a fundamental frequency of 0.060 kHz on a day when the speed of sound is 340 m/s?

Answers

The answer to the question above would be 30.8

Dodgems A has a mass of 120 kg, is initially moving to the right at a speed of 10 m/s. It collides with Dodgems B, which has a mass of 160 kg, moving to the right at a speed of 7 m/s. After collision, Dodgems A continues to move to the right but with a speed of 5 m/s. What is the speed of Dodgems B after collision?

Answers

Answer:

10.75 m/s

Explanation:

let  velocity of Dodgems b  be y

law of conservation of momentum

120 x 10 + 160 x 7=120x5+ 160 x y

1200+1120 = 600 + 160 x y

160y = 1720

y = 10.75 m/s

if the initial velocity of body is 2 metre per second and final velocity is four metre per second calculate average velocity​

Answers

Answer:

3 m/s

Explanation:

Average velocity = Initial velocity + Final velocity / 2

Solving :

⇒ Average velocity = 2 + 4 / 2

⇒ Average velocity = 6/2

⇒ Average velocity = 3 m/s

Velocity

if the initial velocity of body is 2 metre per second and final velocity is four metre per second calculate average velocity

Solution:AV = 2 + 4 / 2AV = 6/2AV = 6 ÷ 2AV = 3m/s

So the average velocity is 3ms.

Explain the mechanism of hearing​

Answers

Explanation:

The pinna collects the sound waves and conducts them to the auditory canal. Sound waves struck at the ear drum and set it into vibration. Eustachian tube equalizes the pressure on either side of the ear drum and thus allows it to vibrate freely. Ear drum transmits the vibrations to ear ossicles.

Compare the level of energy of radio and microwaves when compared to other waves on the spectrum.

Answers


Radio waves have photons
with the lowest energies.
Microwaves have a little
more energy than radio
waves. Infrared has still
more, followed by visible,
ultraviolet, X-rays and
Gamma rays.

2.25 A car's speed is 30m/s, then it slows down in rate 6m/s2, after 4 seconds its speed will be ..... m/s

Answers

Answer:

A

Explanation:

Applying the First Equation of Motion :

⇒ v = u + at

⇒ v = 30 + (-6)(4)

⇒ v = 30 - 24

⇒ v = 6 m/s

Two differences between science activities carried out in a science laboratory and those carried out side of science laboratory.

Please answer quickly for brainliest​

Answers

In a science lab.there is the adequate availability of raw materials for experiments such as chemicals while outside a science lab there isnt.In a science lab the availability of apparattuses and sources of heat is higher than outside a science lab.

In a science lab, there is the adequate availability of raw materials for experiments such as chemicals while outside a science lab there isn't.

In a science lab, the availability of apparatuses and sources of heat is higher than outside a science lab.

What is science laboratory?

The science lab is a place where the experiments related to the science background are performed with the use of apparatus.

The science lab has plenty of equipment to perform the experiment whether related to physics or chemistry or biology.

Thus, source of heat and availability of raw material and equipment are the differences between the science activities carried out in a science laboratory and those carried out side of science laboratory.

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What is the wavelength of radiation with a frequency of 1.50 x 1013 s-1

Answers

Answer:

[tex]2 \times 10^{-5}\ m[/tex]

Explanation:

[tex]v = f \lambda[/tex]

velocity of wave = frequency x wavelength

I'll assume we're talking about EM radiation here, which is any kind of light (microwave, ultraviolet, visible, etc.).

Every type of EM radiation has the same velocity — the speed of light.

Speed of light, known as [tex]c[/tex] — 300 000 000 = [tex]3 \times 10^8[/tex]

velocity: [tex]c = 3 \times 10^8[/tex] [tex]ms^{-1}[/tex]

frequency: [tex]f = 1.5 \times 10^{13}[/tex] [tex]\text{Hz}[/tex]

wavelength: [tex]\lambda =\ ?[/tex] [tex]m[/tex]

[tex]v = f \lambda\\3 \times 10^8 = 1.5 \times^{13}\ \times \ \lambda\\\text{rearrange for}\ \lambda\\\lambda = \frac{3 \times 10^8}{1.5 \times 10^{13}} = 2 \times 10^{-5}[/tex] [tex]m[/tex]

Describe how energy is transferred in one of the sequences? [3]

Answers

Answer:

Thermal energy transfers occur in three ways: through conduction, convection, and radiation. When thermal energy is transferred between neighboring molecules that are in contact with one another, this is called conduction.

Explanation:

PLEASE HELP 100 POINTS! Please fill in the scale distance from sun and diversion factor, listing off the numbers works

Answers

We will take it Cm

Scale factor

1km=10^5cm

So

1cm=10^{-5}km

#Mercury

580cm

Ven us

1080cm

Earth

1500cm

Mars

2280cm

Jupiter

7780cm

Saturn

14300cm

#Uranus

28700cm

Neptune

45000cm

A 50.0-N bowling ball is held in a person’s hand with the forearm horizontal. The biceps muscle is attached 0.030 0 m from the joint, and the ball is 0.350 m from the joint. Find the upward force F exerted by the biceps on the forearm (the ulna) and the downward force R exerted by the humerus on the forearm, acting at the joint.

Answers

The upward force F exerted by the biceps on the forearm will be 583 N.

What is force?

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

The torque balancing equation is found as;

[tex]\rm \tau_i=\tau_R+\tau_F+\tau_{BB}=0\\\\ R(0)+F(0.0300)-(50.0)(0.350)\\\\ F=583 \ N[/tex]

Hence,the upward force F exerted by the biceps on the forearm will be 583 N.

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The units of Work, Energy and power are________ ________units.

Answers

Answer:

the units of work and energy is joule and unit of power is Watt

Select the correct answer. Object A attracts object B with a gravitational force of 5 newtons from a given distance. If the distance between the two objects is reduced in half, what will be the changed force of attraction between them? A. 2.5 newtons B. 10 newtons C. 15 newtons D. 20 newtons E. 25 newtons

Answers

This question involves the concept of Newton's Law of Gravitation.

The force of attraction will be changed to "D. 20 Newtons".

What is Newton's Law of Gravitation?

According to Newton's Law of Gravitation, the gravitational force of attraction between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Mathematically,

[tex]F=\frac{Gm_1m_2}{r^2}[/tex]

where,

F = force = 5 NG = Gravitatational constantm₁ = mass of first objectm₂ = mass of second objectr = distance between objects

Now, reducing the distance by half, we get:

[tex]F'=\frac{Gm_1m_2}{(\frac{r}{2})^2}\\\\F'=4\frac{Gm_1m_2}{r^2}\\\\F'=4F\\F'=4(5\ N)[/tex]

F' = 20 N

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Answer:

See image

Explanation:

Plato

An airplane on a runway accelerates at 4.0 meters/second2 for 28.0 seconds before takeoff. How far does the plane travel on the runway before
takeoff?
A. 1.6 x 103 meters
B. 1.7 x 103 meters
C. 3.1 x 103 meters
D. 3.3 x 103 meters

Answers

Answer:

A

Explanation:

d = 1/2 a t^2 = 1/2 (4)(28^2) = 1568 m  ~ 1.6 x 10^3

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