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The normal force acting on the car that weighs 1400 kg and drives at 27 m / s is 8390.82 N

The car is not horizontal. So the force mg is resolved into its horizontal and vertical component.

cos θ = Adjacent side / Hypotenuse

cos 30° = r / mg

r = m g cos 30°

Since the path is a circular, the net force acting on the car is equal to the centripetal force,

m g cos 30° - N = m v² / r

m = Mass

g = Acceleration due to gravity

N = Normal force

v = Velocity

r = Radius

N = m g cos 30° - m v² / r

N = ( 1400 * 9.8 * 0.87 ) - [ ( 1400 * 33² ) / 430 ]

N = 11936.4 - 3545.58

N = 8390.82 N

Therefore, the normal force acting on the car is 8390.82 N

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The standard deviation of the sample means X, calculated earlier is the standard deviation of the population divided by the square root of the sample size.

Formula :

Mean : Mean = Sum of X values / N(Number of values)

We find mean=7068.08333

and standard deviation = 226.50003.

The standard deviation of the sample means known as the standard error of the mean is less than the population standard deviation and equal to the population standard deviation divided by the square root of the sample size. the sample mean is the average value found in the sample.

Samples are just a fraction of the total. For example, if you work for a polling company and want to know how much people spend on food each year, you don't need to survey over 300 million people. I also found that the sample mean is the arithmetic mean of all the values ​​in the sample. The sample variance measures how the data are distributed and the sample standard deviation is the square root of the variance.

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We are given the following information

Energy = 2500J

Change in temperature = 40 °C

We are asked to find the mass of steel.

The mass of the steel can be found using the equation below

Where c is the specific heat of the steel that is 420 J/(kg°C)

Re-arranging the equation for m and substituting the given values

Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed if there is no external force acting.

So, the correct option is :

If there is no friction, the ball will roll forever in a straight-line path.

The time taken by a person that is walking at 2 meters per second to travel 1200 meters is 600 s

v = d / t

v = Velocity

d = Distance

t = Time

v = 2 m / s

d = 1200 m

t = d / v

t = 1200 / 2

t = 600 s

Velocity is the rate of change of distance with respect to time. It is denoted using V. Its unit is usually m / s.

Therefore, the time taken by thy person is 600 seconds

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The distance travelled by the runner is 86.8 meters and the final velocity is 3.4 m/s.

Using kinematic equation we can find the distance travelled.

S = ut + 1/2 at^2

Where S = distance, u = initial velocity, t = time and a = acceleration.

The runner decelerates from a velocity of 9.00 m/s at a rate of 0.400 m/s^2. Initial velocity is 9.00 m/s and acceleration is -0.4 m/s^2 here. The distance travelled by the runner in the next 14 seconds is,

S = 9.00*14.0 + 1/2*(-0.4)*196

S = 86.8 m

The final velocity of the runner is using the formula v = u + at

v = 9.00+(-0.4)*14

v = 3.4 m/s

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Geologists research the Earth's components, processes, outcomes, physical characteristics, and past.

Geology examines some of the most crucial challenges facing modern society, such as the use of renewable energy sources, environmental sustainability, climate change.

At higher densities, the atmosphere turns into a dense mixture of steam, hydrogen, and helium when the planet's ocean boils. A planet's atmosphere begins to increase quickly when its mass reaches a few times that of Earth. This atmosphere will eventually create a gas giant planet like Jupiter because it will grow faster than the planet's solid core.

A massive planet that is primarily made of helium or hydrogen is known as a gas giant. In contrast to our solar system's Jupiter and Saturn, these planets feature swirling gases atop a solid core rather than hard surfaces.

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Human memory is located not in one particular place in the brain but is instead a brain-wide process in which several different areas of the brain

Human memory is complex, and genetics are still trying to bare the mechanisms that lead to memories being formed. It seems that our human memory is discovered not in one particular place in the brain but is instead a brain-wide process in which several different areas of the brain or memory is a skill, and just like other skills, it can be improved with practice and healthy overall habits. You can start small. For example, a human memory picks a new challenging activity to learn, incorporates a few minutes of exercise into your day, maintains a sleep schedule, and eats a few more green vegetables, fish, and nuts. Procedural human memories (motor skills) are the last ability to be destroyed.

so we can conclude that human memory is located not in one particular place in the brain but is instead a brain-wide process in which several different areas of the brain are.

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The magnitude of vector B is determined as 8.05 units.

The magnitude of a vector is the scalar value of a vector that can  be used to describe the unit value of the vector.

The magnitude of a vector can also be described as the resultant of the vector because it is usually the single value of the vector that can be used to represent the vector.

The magnitude of vector B is calculated as follows;

|B| = √(x² + y² + z²)

where;

|B| = √(4.3² + 4.5² + 5.1²)

|B| = 8.05 units

Thus, we can conclude that vector B with x, y, and z components of 4.3, 4.5, and 5.1 units, respectively, has a magnitude of 8.05 units.

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According to the given statement:

a)The difference in the time the balls spend in the air is 3s.

b)Each ball travels at a speed of 24.5 m/s as it lands.

c) The balls 0.800 s after they are thrown far apart are 23.52 m.

The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In principle, velocity is a vector quantity. It is the velocity where at distance changes. It is the migration change rate.

A )  

We have u = 14.7 m/s, acceleration = acceleration due to gravity = 9.8 m/s² , we need to find time when s = 19.6 m.

The first ball:

h = v o × t - g t² / 2

19.6 = 14.7 t + 9.8 t²/2

4.9 t² + 14.7 t - 19.6 = 0

t 1/2 = (-14.7 +/- √216.09+384.16 ) / 9.8

= 9.8/9.8 = 1 s

The second ball:

v = v o - g t

0 = 14.7 - 9.8 t

9.8 t = 14.7

t = 1.5 ( upward )

h = 19.6 + 14.7 - 9.8 × 1.5 = 30.625 m

30.625 = 9.8 × t²/2

t² = 6.25

t = 2.5 s ( downward )

1.5 s + 2.5 s = 4 s

The difference: 4 s - 1 s = 3 s.

B )

We have u = 14.7 m/s, acceleration = acceleration due to gravity = 9.8 m/s² , and t = 1 second.

The first ball:

v = v o + g t

= 14.7 + 9.8 × 1

= 24.5 m/s

The second ball:

v = g * t = 9.8 * 3 = 24.5 m/s

Each ball travels at a speed of 24.5 m/s as it lands.

C )  d 1 = 14.7 * 0.8 + 9.8 * 0.8²/2

= 11.76 + 3.136

= 14.896 m

d 2 = 14.7 * 0.8 - 9.8* 0.8²/2

= 11.76 - 3.136

= 8.624 m

d 1 + d 2 = 14.896 + 8.624 = 23.52 m

The balls 0.800 s after they are thrown far apart are 23.52 m.

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The meters in the circuit that shows the amount of charge passing a point each second are A and C ( A )

In the circuit, the meter A and C are connected in series to a resistor and the meters B and D are connected parallel to a resistor. Ammeters should be connected in series and voltmeters should be connected in parallel because the resistance in ammeter is zero and the resistance in a voltmeter is infinite.

Ammeter is used to measure the current flowing through a circuit. It can also be said as amount of charge passing through the circuit. Voltmeter is used to measure the voltage across two points in a circuit.

Therefore, the meters in the circuit that shows the amount of charge passing a point each second are A and C ( A )

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We know that the relative velocity of earth with respect to the object upon it is zero, but it is non-zero with respect to space.

Whenever we measure velocity, we actually are measuring relative velocity, i.e. the velocity of an object wrt another object. So say, we are saying the velocity of a car is 60 m/s, so it actually means that for us observing the car, it is moving at 60 m/s. Now say you are observing the same car while traveling on a bike at a speed of 30 m/s. Then for you, the speed of the car will now be 60- 30 m/s. This is the concept of relative velocity.

Now, when the student asks how quickly the Earth is moving through space, in order to answer that question, we need to know the relative velocity of the Earth with respect to space. But Space surrounds the earth and all other astronomical bodies, and the limits of space is considered to be infinite so there is no way to determine if it is moving at a certain velocity or not moving at all.  Hence, we can't determine the velocity of Earth through space. Hence, the question doesn't have an answer.

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Answer:

f = 0.71 N

Explanation:

Apply the 2º Newton's Law to baseball:

∑F = m.a

So:

W - f = m * a

Where:

W: weight;

f: resistance force;

m: mass;

a: resulting acceleration.

But:

W = m*g

1.42 = m * 9.8

m = 1.42/9.8

Thus:

W - f = m * a

m * g - f = m * a

1.42 - f = (1.42/9.8) * 4.9

f = 1.42 - (1.42/9.8) * 4.9

f = 1.42 - 0.71

f = 0.71 N

Given:

V1= 88 ml

P1= 1 atm

T1= 25°C= 298.15 K

STP conditions:

P2= 1atm

T2= 273.15 K

Apply :

Replacing:

V2= 80.62 ml

The horizontal distance travelled by the package is 180.8 m.

The time of motion of the package is the time taken for the package to travel from its initial position to the given height.

The time taken for the package to travel through the given distance is calculated as follows;

h = vt + ¹/₂gt²

where;

h =  ¹/₂gt²

2h = gt²

t = 2h/g

t = √(2h/g)

t = 4.52 seconds

The horizontal distance travelled by the package is calculated as follows;

X = Vxt

where;

X = (40 m/s) x (4.52 s)

X = 180.8 m

Thus, the distance the package strike relative to where it was released is the horizontal displacement of the package.

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Answer:

What's the source of energy that powers the human brain?

Mainly sugar, glucose. Glucose is broken down, and in the process it is used to create a gradient of hydrogen ions (Oxygen is also needed, which is why we breath).

brainiest please

Answer:

F ≈ 0,879 N

Explanation:

First, we calculate the value of the acceleration needed to stop the projectile.

That is:

V = V₀ + a.t

0 = 255 + a . (1,45)

a = - 255 / 1,45

a = -175,86 m/s²

Using the 2° Law of Newton:

∑F = m.a

F = m . a

F = 0,005 . (175,86)

F ≈ 0,879 N

Given that the mass of each ball is m = 6.8 kg

The distance between them is d = 2r

Here, r is the radius of the ball.

The gravitational force of attraction is

We have to find the radius of the ball.

The gravitational force formula is

Here, the universal gravitational constant is

The radius will be

Thus, the radius of one of these balls is 0.114 m

Transferring the same heat energy to two litres the temperature will rise by 5 degree celsius.

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Given,

The distance of the race, d=100 m

The extended distance of the race, s=200 m

The velocity of the red car throughout the race, u₁=10 m/s

The initial velocity of the blue car, u₂=0 m/s

The blue car gains a velocity of 2 m/s every second.The constant acceleration of the blue car is

hus t

As the red car maintains the same velocity, the speed when it reaches the finish line will be 10 m/s.The time it takes for the red car to reach the finish line when the race was 100 m

On substituting the known values,

The time it takes for the red car to reach the finish line after the race is extended,

On substituting the known values,

From the equation of motion,

The final velocity of the blue car, when it reaches the finish line of 100 m race is given by the equation of motion,

Where v₁₀O is the final velocity of the blue car at the end of the 100 m race.n substituting the known values,₀

hus the speed of the blue car when it reaches the finish line of 100 m race is 20 m/s

he time it takes for the blue car to reach the end of the 100 m race is given by,

Where (t₂)₁₀₀ is the time it takes for the blue car to reach the end of the 100 m race.

On substituting the known values in the above equation,

hus both cars take 10 s to reach the end of the 100 m race. Thus they both reach the finitsh line together.

The time it takes for the blue car to reach the end of the 200 m race can be calculated using the equation,

Where (t₂)₂₀₀ is the time it takes for the blue car to reach the end of the 200 m race.

On substituting the known values,

hus while rthe ed car takes 200 s to reach the finish line of the 200 m race, the blue car takes 14.14 s.

Therefore, if the race was extended, the blue car will reach the finish line first.

The net inward force that would be required to keep her 50.1-kg body moving in a circle is 114.3 N

[tex]F_{c}[/tex] = m v² / R

[tex]F_{c}[/tex] = Centripetal force

m = Mass

v = Linear velocity

R = Radius

m = 50.1 kg

v = 3.89 m / s

R = 6.63 m

[tex]F_{c}[/tex] = 50.1 * 3.89² / 6.63

[tex]F_{c}[/tex] = 114.3 N

The net inward force acting on Riley to keep her body moving in a circle is called as Centripetal force. A centripetal force is responsible for making a body follow a curved path. The direction of centripetal force is perpendicular to the motion and towards the center of curvature.

Therefore, the net inward force that would be required to keep her 50.1-kg body moving in a circle is 114.3 N

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The acceleration of the Chevrolet Spark around a level turn with a radius of curvature of 70.9 m at a speed of 22.4 m/s is 7.1 m / s / s

a = v² / R

a = Centripetal acceleration

v = Linear velocity

R = Radius

v = 22.4 m / s

R = 70.9 m

a = 22.4² / 70.9

a = 7.1 m / s / s

The acceleration of a body moving around in a circle is called as centripetal acceleration. It is a vector quantity. It can be denoted as m / s²

Therefore, the acceleration of the car is 7.1 m / s / s

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Large atomic bombs undergo nuclear fission.

Nuclear fission is a chain reaction.

A large amount of radiation is produced.

Thus, the damage continues after the initial explosion because the produced radiation makes people sick.

Option C is correct.

The magnitude of the velocity of the passenger on a boat moving at 2.50 m/s on a still lake relative to the water is 2.95 m / s

Velocity of man = 0.6 m / s

Velocity of ship = 2.5 m / s

Resolving the velocity of man walking at an angle of 45° into its X and Y components.

X-components of velocity of man = 0.6 * cos 45°

X-components of velocity of man = 0.42 m / s

Y-components of velocity of man = 0.6 * sin 45°

Y-components of velocity of man = 0.42 m / s

[tex]V_{x}[/tex] = 0.42 + 2.5

[tex]V_{x}[/tex] = 2.92 m / s

[tex]V_{y}[/tex] = 0.42 m / s

V² = [tex]V_{x}[/tex]² + [tex]V_{y}[/tex]²

V² = 2.92² + 0.42²

V² = 8.53 + 0.18

V = √ 8.71

V = 2.95 m / s

Therefore, the magnitude of the velocity of the passenger relative to the water is 2.95 m / s

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Given the statement:

The product of mass and velocity is also known as linear momentum.

Let's determine if the statement is true or false.

Linear momentum can be defined as the product of a body's mass times the velocity.

Therefore, we can say the statement is true.

ANSWER:

1. True

Answer:

At least [tex]0.128[/tex] (rounded up, to three significant figures as in speed,) assuming that the road is level and that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].

Explanation:

When an object is in a circular motion, the magnitude of the net force can be found in terms of the mass and speed of that object, as well as the radius of the circular path:

[tex]\begin{aligned} (\text{net force}) &= \frac{(\text{mass}) \, (\text{speed})^{2}}{(\text{radius})} \end{aligned}[/tex].

Let [tex]m[/tex] denote the mass of this vehicle. Let [tex]v[/tex] denote the speed of this vehicle. Let [tex]r[/tex] denote the radius of this circular path. While in this circular motion, the magnitude of the net force will be on this vehicle will be:

[tex]\begin{aligned} (\text{net force}) &= \frac{(\text{mass}) \, (\text{speed})^{2}}{(\text{radius})} = \frac{m\, v^{2}}{r} \end{aligned}[/tex].

Forces on this vehicle include:

If this road is level, the normal force from the road will balance the weight of this vehicle. The magnitude of the normal force will be equal to that of the weight of this vehicle, [tex]m\, g[/tex].

Let [tex]\mu_{\text{s}}[/tex] denote the static friction coefficient between the tire and the road. The static friction between the vehicle and the road cannot exceed [tex](\text{static friction coefficient}) \times (\text{normal force})[/tex].

Since [tex](\text{normal force}) = m\, g[/tex], the maximum possible value of static friction will be:

[tex]\begin{aligned} & (\text{static friction coefficient}) \times (\text{normal force}) \\ =\; & (\mu_{\text{s}})\, (m\, g) \\ =& \mu_{\text{s}}\, m\, g\end{aligned}[/tex].

Under the assumptions, the weight and normal force on this vehicle will be balanced. As a result, the net force on this vehicle will be equal to static friction and should also be no greater than [tex](\text{static friction coefficient}) \times (\text{normal force}) = \mu_{\text{s}}\, m\, g[/tex].

In other words:

[tex]\begin{aligned}(\text{net force}) &= (\text{static friction}) \\ &\le (\text{maximum static friction}) = \mu_{\text{s}}\, m\, g \end{aligned}[/tex].

Additionally, from circular motion:

[tex]\begin{aligned} (\text{net force}) &= \frac{m\, v^{2}}{r} \end{aligned}[/tex].

Therefore:

[tex]\begin{aligned}\frac{m\, v^{2}}{r} \le \mu_{\text{s}}\, m\, g \end{aligned}[/tex].

Rearrange this inequality to separate the coefficient of static friction, [tex]\mu_{\text{s}}[/tex]:

[tex]\begin{aligned} \mu_{\text{s}} \ge \frac{v^{2}}{r\, g}\end{aligned}[/tex].

(Note that [tex]m[/tex] and [tex]g[/tex] are both greater than [tex]0[/tex].)

Substitute in [tex]v = 25.0\; {\rm m\cdot s^{-1}}[/tex], [tex]r = 500\; {\rm m}[/tex], and [tex]g \approx 9.81\; {\rm m\cdot s^{-2}}[/tex]:

[tex]\begin{aligned} \mu_{\text{s}} &\ge \frac{v^{2}}{r\, g} \\ & \approx \frac{(25.0\; {\rm m\cdot s^{-1}})^{2}}{(500\; {\rm m})\, (9.81\; {\rm m\cdot s^{-2}})} \\ &\approx \frac{25.0^{2}}{500\times 9.81} \\ &\approx 0.128\end{aligned}[/tex].

(Rounded up.)

A vertical wire suspended from one stop is tensioned by attaching a 20N weight to the lower stop. If you have weight, use Imon to stretch the wire. Energy source​: `W=(1)/(2) f xx l=(1)/(2) xx 20 xx 10^(-3)` `= 0.01J`.

In physics, power is a quantitative property that is transferred to an identifiable frame or physical device in the form of labor productivity and warmth and tenderness. Electricity is a stored quantity. Energy conservation regulations state that energy can be transformed into form, but cannot be created or destroyed.

Energy exists in various characteristic documents. Examples include light energy, thermal energy, mechanical energy, gravity, electrical energy, sound electricity, chemical power, and nuclear or nuclear energy. Each form can be transformed or transformed into a different bureaucracy. Power is in everything we consume, eat, and use. Power supplies and regulates the body's natural internal abilities. It is used to support cells and tissues in the body, build muscle, and is important for maintaining homeostasis. The harsher the environment, the more energy it takes to maintain.

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Answer:

The friction of the moving object is proportional and perpendicular to the normal force.

The friction experienced by the object is dependent on the nature of the surface it is in contact with.

Explanation: two laws of friction

Answer:  The friction of the moving object is proportional and perpendicular to the normal force.

The friction experienced by the object is dependent on the nature of the surface it is in contact with.

iven:

he aangles of the stars;

Star A: p_A=0.67 arcsec

Star B: p_B=1.2 arcsec

Star C: p_C=0.35 arcsec

To find:xoplanation:

Order of the stars according to their distance.

he distacnce of a star in parsec is calculated using the formula,

Where p is the angles made by the stars in arcseconds.

On substituting the known values:

Star A,

Star B,

Star C,

inal answer:

Thus the closest star is star B and the farthest star is star C.

Thus the correct answer is option B.

Answer: 1140 km

Explanation: You would just add 760 to 760/2 because the airplane travels 760 km in 1 hour (760 km/h means 760 km every 1 hour)  and travels 380 km in half an hour. Add those up and you would get 1140 km.