Write a cosine function that has an amplitude of 2, a midline of 5 and a period of T.

Answer:

x = 14

Step-by-step explanation:

The different types of angle relationships:

Based off of these three angle relationships we can identify the two angles as supplementary angles as the two angles shown form a line therefore we know the sum of those two angles is 180 degrees. Knowing this we can create an equation.

Creating an equation:

We know that the two angles are supplementary angles and we also know that supplementary angles add up to 180 degrees. So the sum of the two expressions represented by the two given angles must equal 180.

In other words 9x - 14 + 5x - 2 = 180

Solving for x

Know that we have created an equation we can solve for x algebraically.

9x - 14 + 5x - 2 = 180

==> combine like terms

14x - 16 = 180

==> add 16 to both sides

14x = 196

==> divide both sides by 14

x = 14

And we are done!

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[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

[tex] \textbf{Let's solve for x } [/tex]~

[tex] \textsf{As we can see, the sum of measures of the} [/tex][tex] \textsf{ marked two Angles is equal to 180° } [/tex]

[tex] \texttt{[ by linear pair property ]} [/tex]

[tex]\qquad \sf  \dashrightarrow \:9x - 14 + 5x - 2 = 180[/tex]

[tex]\qquad \sf  \dashrightarrow \:9x + 5x - 14 - 2 = 180[/tex]

[tex]\qquad \sf  \dashrightarrow \:14x - 16 = 180[/tex]

[tex]\qquad \sf  \dashrightarrow \:14x = 180 + 16[/tex]

[tex]\qquad \sf  \dashrightarrow \:14x = 196[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 196 \div 14[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 14[/tex]

[tex] \texttt{Therefore, the value of x is 14} [/tex]

I Hope you understood the whole procedure ~

The large fishbowl hold 5.6 gallons of water. The volume of the large. fishbowl is denoted by y in the given problem.

The term “volume” refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its SI unit is in cubic cm.

The volume of the small fishbowl is x

The volume of the large fishbowl is y

From the problem, the large fishbowl holds up to [tex]\rm 2\frac{1}{3}[/tex] times as much water as the small fishbowl.

[tex]\rm y = 2\frac{1}{3} x\\\\\ x= 2\frac{2}{5} =2.4\\\\ y= 2.333\times 2.4 \\\\\ y=5.6 \ gallon[/tex]

Hence, the large fishbowl hold 5.6 gallons of water.

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                  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}[/tex]

              The quotient of b and 3 is greater than or equal to 19.

[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}[/tex]

           ✥First, the word "quotient" indicates that we divide.

Here we have "the quotient of b and 3", so we divide b by 3:-

[tex]\hookrightarrow[/tex][tex]\sf{b\div3}[/tex]

Now, this expression is greater than or equal to 19:-

[tex]\sf{b\div3\geq 19}[/tex]

How to Solve for b

✳︎ Multiply by 3 on both sides:-

[tex]\sf{b\geq 19\times3}[/tex]

On simplification,

[tex]\sf{b\geq 57}[/tex]

So the values of b greater than or equal to 57 will make this inequality true.

Let's solve another one.

✳︎ A number y increased by 5 is at least -21.

First, "increased" means we add 5.

Since y is increased by 5, we add 5 to y:-

[tex]y+5[/tex]

Now this expression is at least -21, which means it can't be less than -21, thus, it's greater than or equal to  -21, which looks as follows:-

[tex]\sf{y+5 \geq -21}[/tex]

[tex]\rule{300}{1}[/tex]

[Solving for y]

Subtract 5 on both sides:-

[tex]\sf{y \geq -21-5}[/tex]

On simplification,

[tex]\sf{y \geq -26}[/tex]

So the values of y greater than or equal to  -26 will make this inequality true.

             - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Answer:

I. 56 cubic feet of water.

II. 5 feet

Step-by-step explanation:

The final expression 2|x+3| shows a vertical compression by 2 units and a horizontal translation to the left by 3units

Transformation is a means of changing the size and shape of an object in a xy-plane.

For the given function, its parent function is f(x) = |x|

The expression f(x) = 2|x| shows that the function is vertically stretched by 2 units.

The final expression 2|x+3| shows a vertical compression by 2 units and a horizontal translation to the left by 3units

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Answer:

x >/= 8.6

Add 9.5 to 42.1 then divide by 6

Step-by-step explanation:

Answer:

I think it is (2,3.5)

Step-by-step explanation:

See im ova here trying my best so if it's wrong don't me coming foe me

Answer:

For the child 8  in.,

for the image(B) 9 1/4in

Step-by-step explanation:

Answer:

B. 9 1/4

Step-by-step explanation:

Covert 1/2 into 4ths.

3 2/4 + 5 3/4= 7 5/4 = 9 1/4

Hope this helps

The normal distribution is also known as the Gaussian distribution. The mean of this test is 37.

The normal distribution, also known as the Gaussian distribution, is a symmetric probability distribution about the mean, indicating that data near the mean occur more frequently than data distant from the mean. The normal distribution will show as a bell curve on a graph.

On a test that has a normal distribution, a score of 29 falls two standard deviations below the mean, and a score of 49 falls three standard deviations above the mean. Therefore, we can write,

μ - 2σ = 29

μ + 3σ = 49

By subtracting the first equation from the second, then we will get,

μ + 3σ - μ + 2σ = 49-29

5σ = 20

σ = 4

Now, substitute the value of σ in the equation,

μ - 2σ = 29

μ - 2(4) = 29

μ = 29 + 8

μ = 37

Hence, the mean of this test is 37.

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[tex]f(x) = x^2 +x (2a+2b) +4ab-x\\\\f'(x) = 2x+x \cdot 0 + 2a+2b + 0 -1\\\\~~~~~~~~=2x+0+2a+2b-1\\\\~~~~~~~~=2x+2a+2b-1[/tex]

From the definition of the derivative,

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{f(x+h) - f(x)}h[/tex]

We have

[tex]f(x) = x^2 + x(2a+2b) + 4ab - x = x^2 + (2a+2b-1)x + 4ab[/tex]

and so

[tex]\displaystyle f'(x) = \lim_{h\to0} \frac{\left((x+h)^2 + (2a+2b-1)(x+h) + 4ab\right) - \left(x^2 + (2a+2b-1)x + 4ab\right)}h[/tex]

[tex]\displaystyle f'(x) = \lim_{h\to0} \frac{x^2 + 2xh + h^2 + (2a+2b-1)x + (2a+2b-1)h + 4ab - x^2 - (2a+2b-1)x - 4ab}h[/tex]

[tex]\displaystyle f'(x) = \lim_{h\to0} \frac{2xh + h^2 + (2a+2b-1)h}h[/tex]

[tex]\displaystyle f'(x) = \lim_{h\to0} (2x + h + 2a+2b-1)[/tex]

[tex]\displaystyle f'(x) = \boxed{2x + 2a + 2b - 1}[/tex]

The complete factor of the expression x² + 4x - 45 is (x - 5)(x + 9)

The expression is given as:

x² + 4x - 45

Expand the equation

x² + 4x - 45 = x² + 9x - 5x - 45

Factorize the expression

x² + 4x - 45 = x(x + 9) - 5(x + 9)

Factor out x + 9

x² + 4x - 45 = (x - 5)(x + 9)

Hence, the complete factor of the expression x² + 4x - 45 is (x - 5)(x + 9)

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Answer:D

Step-by-step explanation:

i got it on edmentumn

Answer:

0.015

Step-by-step explanation:

We want to know that probability that we draw a green marble for the first AND the second AND the third draws. The act of drawing each marble changes the probabilities of the next draw, so we say that these events (drawing green marbles) are dependent. Mathematically, this means we'll be multiplying the probabilities of each event to get the probability of the whole thing. I'll denote the first, second and third green marble drawing events as A, B, and C.

For our first drawing, we have 5 possible green marbles to pick from out of 4 + 8 + 5 = 17 total marbles, so P(A), the probability of drawing a green marble, is 5/17.

Now, A, B, and C all represent the event of drawing a green marble, but the way they depend on one another is important here. If we want B to be our second draw, it'll depend on what happens in our first draw, A. We call this kind of probability conditional, and we write it as P(B | A), the conditional probability of event B after event A's occurred.

Here, event A is "drawing a green marble." What happens during event A? Well, we draw a green marble, so we have one fewer green marble, and one fewer marble altogether. Our chance of drawing a green marble after event A, P(B | A), is 4/16 or 1/4 then, since we now have 4 green marbles and 16 total marbles.

Using that same reasoning, P(C | B), the probability of event C (drawing a green marble) after event B has occurred, is 3/15, or 1/5, since we'll have 3 green marbles out of 15 total after drawing our second during event B.

Multiplying these all together, we have

Let the length of the room = L = 12m

width of the room = b = 8m

Height of the room = h = 4m

• Area of the four walls of the room = Perimeter of the base x Height of the room.

[tex] = 2(l + b) \times h = 2(12 + 8) \times 4[/tex]

[tex] = 2 \times 20 \times 4 = 160 {m}^{2} [/tex]

Hence , the total cost of white washing four walls of the room ;-

Cost of white washing the ceiling.

So , the total cost of white washing ;

Hope this helps you :)

#Carry on learning# :) ..

Answer:

Step-by-step explanation:

17 + 4 = 21

Answer:

B + 4 = 17+4

21 is the answer

Answer:

15.7cm

Step-by-step explanation:

the circumference of x=L1=2π =15cm

L2=2π =20cm

L2-L1

=20π-15π

=5π

=5×3.14

=15.70cm

Answer:

A-B = {2,8,10]

this is the correct answer

i hope my answer was helpful to you

Answer:

Slope-Intercept: C,H,F,I,P,T

Standard: B,D,K,N,O,Q,S

Point-Slope: A,E,G,F,L,M,R

Step-by-step explanation:

Anything with the Y on one side of the equation and an X on the other is Slope-Intercept.

All the standard equations are the ones with the terms (X and Y) on one side of the equation, and a real number on the other.

The Point-Slope are all equations containing a Y value on one side, and an undistributed X value on the other.

Answer:

The answer is option A

Step-by-step explanation:

The solution is in the image

Answer:

I think it would be 2,8

Step-by-step explanation:

hope it helps u

First note the intersections of each pair of lines.

x = 3   ⇒   y = 2•3 + 1 = 7   ⇒   (3, 7)

y = -3   ⇒   -3 = 2x + 1   ⇒   x = -2   ⇒   (-2, -3)

y = -3 and x = 3   ⇒   (3, -3)

Using the disk method, we consider disks with thickness ∆y and radius equal to the horizontal distance between the line y = 2x + 1 (or x = (y - 1)/2) and the axis of revolution, x = 3. Each disk will then contribute a volume of

∆V = π (radius)² (thickness) = π/4 (y - 1)² ∆y

As we let ∆y go to zero and let the number of disks go to infinity, the total volume of the resulting cone will be given by the integral

[tex]\displaystyle \frac\pi4 \int_{-3}^7 (y-1)^2 \, dy[/tex]

Answer:

4-4

Step-by-step explanation:

Substitute the actual values of the points into the distance formula.

Answer:

w=8

Hope this helps!!

Answer:

y = -3x

Step-by-step explanation:

Equation of the line going through the origin: y = mx

Substitute any point in the above equation.

Here, Chosen point( 1 ,-3)

-3 = m*1

m = -3

Equation of the line: y = -3x

Answer:

-22

Step-by-step explanation:

It would be negative -22

6*(-4)+2

-24+2

-22

Hope this helps :)

Answer -

[tex]f(x) = 6x + 2 \\ \\ \implies \: f( - 4) = 6( - 4) + 2 \\ \\ \implies \: f( - 4) = - 24 + 2 \\ \\ \implies \: f(x) = - 22[/tex]

hope helpful ~

Answer:

D

Step-by-step explanation:

everything that should happen at x+4 happens now at x. that is what that means.

so, the graph shifts 4 units to the left.

Volume is a three-dimensional scalar quantity. The amount of water that the tub can hold is 4,981.75 litres.

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

Given the circumference of the tub is 25.12 feet, therefore, the radius of the circumference of the tub will be,

Circumference = 2πr

25.12 = 2×π×r

r = 3.9979ft ≈ 4ft

Now, the volume of the tub will be,

Volume = πr²h = π×(4²)×3.5 = 175.929 ft³

Since 1 ft³ is equal to 28.3168 litres, therefore, the amount of water that a tub can store is

Volume of water = 175 × 28.3168 = 4,981.75 litres

Hence, the amount of water that the tub can hold is 4,981.75 litres.

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Answer:

Your answer is 11CM

Step-by-step explanation:

The height of cylinder b is 11 cm.

The volume of the cylinder is related to the capacity of this geometric figure. Remember that the cylinder or circular cylinder is an elongated and rounded geometric solid.

The formula for the volume of a cylinder is given by:

[tex]V = \pi.r^2.h[/tex]

Where:

In this case, as the cylinders are congruent, both will have the same radius, thus:

[tex]V = \pi.r^2.h\\176\pi=\pi(4)^2(h)\\h=11[/tex]

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