Write a program that reads the student information from a tab separated values (tsv) file. The program then creates a text file that records the course grades of the students. Each row of the tsv file contains the Last Name, First Name, Midterm1 score, Midterm2 score, and the Final score of a student. A sample of the student information is provided in StudentInfo.tsv. Assume the number of students is at least 1 and at most 20.
The program performs the following tasks:
Read the file name of the tsv file from the user.
Open the tsv file and read the student information.
Compute the average exam score of each student.
Assign a letter grade to each student based on the average exam score in the following scale:
A: 90 = < X o
B: 80 = < x < 90
C: 70 = < X < 80
D: 60 = < x < 70
E: X < 60
• Compute the average of each exam.
• Output the last names, first names, exam scores, and letter grades of the students into a text file named report.txt. Output one student per row and separate the values with a tab character.
• Output the average of each exam, with two digits after the decimal point, at the end of report.txt. Hint: Use the setprecision manipulator to format the output.
Ex: If the input of the program is:
StudentInfo.tsv
and the contents of StudentInfo.tsv are: 70 45 59
Barrett Edan 96 97 88
Bradshaw Reagan 73 94 80
Charlton Caius 88 61 36
Mayo Tyrese 90 86 45
the file report txt should contain
Barrett Edan 70 45 59 F
Baadha Boagan 9e 157 89 A
Charlton Caius 73 94 80 B
Mayo and Tyrese 58 61 36 D
Stern and Brenda 90 36 45 C
Average midterm 83.40, midterm2 76.60, final 61.60

Answers

Answer 1
#include
#include
#include
#include
#include
#include


using namespace std;

// Class student required to store the data
class Student{
public:
string lname;
string fname;
int marks[3];
char grade;

// Function which generates the grade for student
void calculate_grade(){
double sum = 0;
for(int i=0;i<3;i++){
sum+= marks[i];
}
double average = sum/3;
if(average>=90 && average<100)
this->grade = 'A';
else if(average>=80)
this->grade = 'B';
else if(average>=70)
this->grade = 'C';
else if(average>=60)
this->grade= 'D';
else this->grade = 'F';
}
};

// This function reads the file , and creates a vector of Students data
vector read_file(string fileName){

// Opening the file
fstream fin;
fin.open(fileName);


// Temp variables
vector list;
vector row ;
string line, word, temp;

// Read the data into vector
while(getline(fin,line)){
row.clear();
stringstream s(line);

while(getline(s,word,'\t')){

row.push_back(word);

}
Student st;
st.fname = row[0];
st.lname = row[1];
st.marks[0] = stoi(row[2]);
st.marks[1] = stoi(row[3]);
st.marks[2] = stoi(row[4]);
st.calculate_grade();
list.push_back(st);
}
fin.close();
return list;
}

// This function takes filname to be output as input, and list of student
void writeFile(string filename, vector list){

// Opening the new file
ofstream fin(filename);
for(int i=0;i string line = list[i].fname+"\t"+list[i].lname+"\t"+to_string(list[i].marks[0])+"\t"
+to_string(list[i].marks[1])+"\t"+to_string(list[i].marks[2])+"\t"+list[i].grade+"\n";
fin<
}


// Find the stats required
double average1 =0,average2 =0 ,average3 = 0;
for(int i=0;i average1+=list[i].marks[0];
average2+=list[i].marks[1];
average3+=list[i].marks[2];
}
average1/=list.size();
average2/=list.size();
average3/=list.size();

// Writting the stats
fin<<"\n"<<"Average: "<<"mid_term1 "<
// Closing the file
fin.close();
}
int main(){

// Taking the input
cout<<"Enter the filename: ";
string filename;
cin>>filename;
vector list;

// Reading and Writting to the file
list = read_file(filename);
writeFile("report.txt",list);


}
Answer 2

In this exercise we have to use the knowledge of the JAVA language to write the code, so we have to:

The code is in the attached photo.

So to make it easier the code can be found at:

using namespace std;

// Class student required to store the data

class Student{

public:

string lname;

string fname;

int marks[3];

char grade;

// Function which generates the grade for student

void calculate_grade(){

double sum = 0;

for(int i=0;i<3;i++){

sum+= marks[i];

}

double average = sum/3;

if(average>=90 && average<100)

this->grade = 'A';

else if(average>=80)

this->grade = 'B';

else if(average>=70)

this->grade = 'C';

else if(average>=60)

this->grade= 'D';

else this->grade = 'F';

}

};

// This function reads the file , and creates a vector of Students data

vector read_file(string fileName){

// Opening the file

fstream fin;

fin.open(fileName);

// Temp variables

vector list;

vector row ;

string line, word, temp;

// Read the data into vector

while(getline(fin,line)){

row.clear();

stringstream s(line);

while(getline(s,word,'\t')){

row.push_back(word);

}

Student st;

st.fname = row[0];

st.lname = row[1];

st.marks[0] = stoi(row[2]);

st.marks[1] = stoi(row[3]);

st.marks[2] = stoi(row[4]);

st.calculate_grade();

list.push_back(st);

}

fin.close();

return list;

}

// This function takes filname to be output as input, and list of student

void writeFile(string filename, vector list){

// Opening the new file

ofstream fin(filename);

for(int i=0;i string line = list[i].fname+"\t"+list[i].lname+"\t"+to_string(list[i].marks[0])+"\t"

+to_string(list[i].marks[1])+"\t"+to_string(list[i].marks[2])+"\t"+list[i].grade+"\n";

fin<

}

// Find the stats required

double average1 =0,average2 =0 ,average3 = 0;

for(int i=0;i average1+=list[i].marks[0];

average2+=list[i].marks[1];

average3+=list[i].marks[2];

}

average1/=list.size();

average2/=list.size();

average3/=list.size();

// Writting the stats

fin<<"\n"<<"Average: "<<"mid_term1 "<

// Closing the file

fin.close();

}

int main(){

// Taking the input

cout<<"Enter the filename: ";

string filename;

cin>>filename;

vector list;

// Reading and Writting to the file

list = read_file(filename);

writeFile("report.txt",list);

}

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Write A Program That Reads The Student Information From A Tab Separated Values (tsv) File. The Program
Write A Program That Reads The Student Information From A Tab Separated Values (tsv) File. The Program

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Answer:

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Answers

Answer:

A.

Explanation:

Consider the following declaration:
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A. int k = s.length;
B. int k = s.length();
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Answers

Answer:

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Answers

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Answers

Answer:

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Answers

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Answer:

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Answers

Answer:

What challenge?

Explanation:

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Answers

The first Cognitive Process that was in play according to the excerpt is Perceptual System. It is also called Perceptual Representation and Intelligence.

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Double click the letter doc, it s hold open automatically

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Answer:

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Answers

Answer:

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Answers

Answer:3

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Answers

Answer:

numbers = []

for i in range(3):

 numbers.append(eval(input("Enter number: ")))

print('Sum is:', sum(numbers))

Explanation:

You want to use a loop to prevent repeating your code.

Answer:

numbers = []

for i in range(3):

numbers.append(eval(input("Enter number: ")))

print('Sum is:', sum(numbers))

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Answer:

what's the question or answer you want or is it a joke?

Explanation:

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bool match( const char exp [ ], const int s);
The input math express is store in the char array exp, and the size of exp is s. It returns true if all parentheses are matched or false otherwise.

Answers

C++ Code

#include
using namespace std;

bool match(const char exp[],const int s)
{
// declare a character array to perform stack operations
char stack[s];

// declare top and initialize to -1 and flag to 0
int top=-1,i,flag=0;

// visit all characters in the expression string
for(i=0;i {
// if the character is [ or ( or { then push it into stack
if(exp[i]=='[' || exp[i]=='(' || exp[i]=='{')
{
top++;
stack[top]=exp[i];
}
// if the character is ] or ) or } then check conditions
else if(exp[i]==']' || exp[i]==')' || exp[i]=='}')
{
// check stack is empty or not
if(top!=-1)
{
// check all possible failure conditions
if(exp[i]==')' && (stack[top] == '{' || stack[top]=='['))
{
flag = 1;
break;
}
else if(exp[i]==']' && (stack[top] == '{' || stack[top]=='('))
{
flag = 1;
break;
}
else if(exp[i]=='}' && (stack[top] == '(' || stack[top]=='['))
{
flag = 1;
break;
}
top--;
}
else
{
flag=1;
break;
}
}
}
// after visiting all characters of expression string check if stack is not empty and flag is 1. if any one of the condition is true return false. otherwise return true

if(top>=0 || flag==1)
return false;
else
return true;
}

int main()
{

// declare character array to store expression
char exp[10000];
cout<<"Enter an Expression"<
// read expression from user
cin.getline(exp, 10000);
int s=0;

// find the length of the expression string
for(int i=0;exp[i]!='\0';i++)
{
s++;
}

// call the match function
bool status = match(exp,s);

// print the result based on value returned by match() function
if(status == 1)
cout<<"true"< else
cout<<"false"<
}


Sample Input/Output is attached

write a short paragraph (three to four sentences) that explains how it works for computers and internet communications in relation to cybersecurity.

Answers

Answer:

Public and private keys form the basis for public key cryptography, also known as asymmetric cryptography. In public key cryptography, every public key corresponds to only one private key. Together, they are used to encrypt and decrypt messages. If you encode a message using a person’s public key, they can decode it using their matching private key.

Explanation:

Change up the wording.

how to download film​

Answers

Which film are you talking about?
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Write a Boolean expression that tests if the value stored in the variable num1 is equal to the value stored in the variable num2.

Answers

Answer:

num1 = int(input("Enter value: "))

num2 = int(input("Enter value: "))

if num1 == num2:

   print("Equals.")

else:

   print("Unequal.")

Explanation:

The Boolean expression that tests if the value stored in the variable num1 is equal to the value stored in the variable num2 can be found in explanation.

What is boolean expression?

A logical statement that could be either true or false is referred to as a Boolean expression.

As long as both parts of the expression have the same basic data type, Boolean expressions can compare data of any type. Data can be tested to see if it is the same as, greater than, or less than other data.

A Boolean expression is a type of expression used in programming languages that produces a Boolean value when evaluated. A Boolean value can only be true or false.

The boolean expression for the given scenario can be:

num1 = int(input("Enter value: "))

num2 = int(input("Enter value: "))

if num1 == num2:

  print("Equals.")

else:

  print("Unequal.")

Thus, above mentioned is the program for the given code.

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Which type of transaction cannot be tagged at this time within Quickbooks online

Answers

you can't tag general journal entries or transfers. You also can't tag things like customers or items.

The type of transaction cannot be tagged at this time within Quickbooks online is "Invoice Delayed Credit". The correct option is 4.

What is Invoice Delayed Credit?

A delayed credit is a non-posting transaction that you can add to a client's invoice at a later time.

Reimbursing a customer's money involves posting a transaction known as a refund. The use of credit notes to reduce an outstanding customer amount follows from this. Delayed Credits are only permitted on invoices.

In QuickBooks Online, "Invoice Delayed Credit" transaction types cannot currently be tagged.

To aid with organization and tracking, QuickBooks Online users can assign labels or categories to bank deposits, purchase orders, journal entries, and other transactions.

The transaction type "Invoice Delayed Credit" cannot be labeled in QuickBooks Online, nevertheless. Instead, you can change the amount owed by applying a credit memo to an invoice.

Thus, the correct option is 4.

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Which type of transaction cannot be tagged at this time within QuickBooks Online?

Bank deposit O Purchase order O Journal entry O Invoice Delayed credit

Write a program to repeatedly read integers from the standard input until it reads "-1" and exits. For each number before "-1," if it is positive and odd, do the following:

Answers

Answer:

#include <stdio.h>  

int main() {  

int p=0, n=0, z=0, inp=0;  

printf("How do I write a C program to read numbers until -1 "  

 "is encountered and also count the number of positive, negative, "  

 "zeroes encountered by users using a while loop?\n\n\n");  

printf("Enter an integer  (-1 to quit): ");  

scanf("%d",&inp);  

while(inp != -1) {  

 if(inp > 0) p++;  

 else if(inp < 0) n++;  

 else z++;  

 printf("\nEnter next integer (-1 to quit): ");  

 scanf("%d",&inp);  

}  

n++; /* -1 is also a -ve number */  

printf("You have entered ...\n");  

printf("\t\tPositive numbers: %d\n",p);  

printf("\t\tNegative numbers: %d\n",n);  

printf("\t\t          Zeroes: %d\n",z);  

}

Explanation:

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