Answer:
[tex](a)\ (x+6)^2 + (y-5)^2 = 25[/tex]
[tex](b)\ Area = 16.75cm^2[/tex]
Step-by-step explanation:
Solving (a):
Given
[tex](a,b) = (-6,5)[/tex]
[tex]r = 5[/tex]
Required
The equation of the circle
This is calculated as:
[tex](x-a)^2 + (y-b)^2 = r^2[/tex]
So, we have:
[tex](x--6)^2 + (y-5)^2 = 5^2[/tex]
[tex](x+6)^2 + (y-5)^2 = 25[/tex]
Solving (b):
Given
[tex]r = 8cm[/tex]
[tex]\theta = 30^o[/tex] --- Missing from the question
Required
The area of the sector
This is calculated using:
[tex]Area = \frac{\theta}{360} * \pi r^2[/tex]
So, we have:
[tex]Area = \frac{30}{360} * 3.14 * 8^2[/tex]
[tex]Area = \frac{1}{12} * 200.96[/tex]
[tex]Area = 16.75cm^2[/tex]
synthetic division problem... pls help asap
help me with my last question for 30 to 100 points if correct
Answer
Ok i will help
Step-by-step explanation:
Yay!
what is the √n^3 in simplest radical form?
Answer:
Surds. Note: a root we can't simplify further is called a Surd. So √3 is a surd.
Please Answer, Giving Brainliest and 50 points!
8 is the GCF of what two numbers?
24 and 48
14 and 32
16 and 28
16 and 56
Answer:
16 and 56
Step-by-step explanation:
gcf of 24 and 48 is 24
gcf of 14 and 32 is 2
gcf of 16 and 28 is 4
Let's find one by one
#1
24 and 48
GCF=24No
#2
14 and 32
GCF is 2No
#3
16 and 28GCF is 4
No
#4
16 and 56
GCF is 8Yes
The formula for the lateral area of a right cone is LA = rs, where r is the radius of the base and s is the slant height of the cone.
Which are equivalent equations? Select two correct answers.
Step-by-step explanation:
The formula for the lateral area of a right cone is :
LA = rs
Where
r is the radius of the base and s is the slant height of the cone
Equivalent expression,
[tex]r=\dfrac{LA}{s}[/tex]
or
[tex]s=\dfrac{LA}{r}[/tex]
Hence, this is the required solution.
Answer:
The answers are C & E
26. Given that tanθ almost equal to≈ 2.773 where 0<θ<π2, find the values of sinθ and cosθ. 27. Given that tanθ ≈ -1.559 where 3π2<θ<2π , find the values of sinθ and cosθ.
Answer:
a. i. sinθ = +0.941
ii. cosθ = +0.339
b. i. sinθ = -0.842
ii. cosθ = +0.540
Step-by-step explanation:
a. Given that tanθ almost equal to≈ 2.773 where 0<θ<π/2, find the values of sinθ and cosθ.
i. sinθ
Given that 1 + cot²θ = cosec²θ
cotθ = 1/tanθ
Since tanθ = 2.773, cotθ = 1/tanθ = 1/2.773 = 0.3606
So, 1 + cot²θ = cosec²θ
1 + (0.3606)² = cosec²θ
1 + 0.13 = cosec²θ
1.13 = cosec²θ
cosec²θ = 1.13
cosecθ = ±√1.13
cosecθ = ±1.063
1/sinθ = ±1.063
sinθ = ±1/1.063
sinθ = ±0.9407
sinθ ≅ ±0.941
Since we have 0<θ<π/2, sinθ is in the first quadrant, so we choose the positive value.
So, sinθ = +0.941 where 0<θ<π/2
ii. cosθ
Given that 1 + tan²θ = sec²θ
Since tanθ = 2.773,
So, 1 + tan²θ = sec²θ
1 + (2.773)² = sec²θ
1 + 7.6895 = sec²θ
8.6895 = sec²θ
sec²θ = 8.6895
secθ = ±√8.6895
secθ = ±2.9478
1/cosθ = ±2.9478
cosθ = ±1/2.9478
cosθ = ±0.3392
cosθ ≈ ±0.339
Since we have 0<θ<π/2, cosθ is in the first quadrant, so we choose the positive value.
So, cosθ = +0.339 where 0<θ<π/2
b. Given that tanθ ≈ -1.559 where 3π/2<θ<2π, find the values of sinθ and cosθ.
i. sinθ
Given that 1 + cot²θ = cosec²θ
cotθ = 1/tanθ
Since tanθ = -1.559, cotθ = 1/tanθ = 1/-1.559 = -0.6414
So, 1 + cot²θ = cosec²θ
1 + (-0.6414)² = cosec²θ
1 + 0.4114 = cosec²θ
1.4114 = cosec²θ
cosec²θ = 1.4114
cosecθ = ±√1.4114
cosecθ = ±1.1880
1/sinθ = ±1.1880
sinθ = ±1/1.1880
sinθ = ±0.8417
sinθ ≈ ±0.842
Since we have 3π/2<θ<2π, sinθ is in the fourth quadrant, so we choose the negative value.
So, sinθ = -0.842 where 3π/2<θ<2π
ii. cosθ
Given that 1 + tan²θ = sec²θ
Since tanθ = -1.559,
So, 1 + tan²θ = sec²θ
1 + (-1.559)² = sec²θ
1 + 2.4305 = sec²θ
3.4305 = sec²θ
sec²θ = 3.4305
secθ = ±√3.4305
secθ = ±1.8522
1/cosθ = ±1.8522
cosθ = ±1/1.8522
cosθ = ±0.5399
cosθ ≈ ±0.540
Since we have 3π/2<θ<2π, cosθ is in the fourth quadrant, so we choose the positive value.
So, cosθ = +0.540 where 3π/2<θ<2π
how do u solve -2x=-26
Answer:
x=-14
Step-by-step explanation:
because -2(-14)=-26
Maggie started collecting teacups on her 13th birthday when she was given 4 teacups. She has purchased a new teacup every month since then. How many teacups will she
have on her 17th birthday?
A.52
B.64
C.38
D.48
Answer:
A. 52
Step-by-step explanation:
Find how many months are in 4 years, since there are 4 years between her 13th and 17th birthdays.
There are 12 months in a year, so multiply 12 by 4:
12(4)
= 48
So, there are 48 months in 4 years. Since she buys a new teacup every month, this means she will have bought 48 more teacups.
Add this to the 4 teacups she got on her 13th birthday:
48 + 4
= 52
So, on her 17th birthday, she will have A. 52 teacups
If a value started at 1000, Increased 7 times, and ended at 12000, how much did the value increase each time?
Answer:
the value of increase each time is 1,571.43
Step-by-step explanation:
Given;
original value of the number, A = 1000
final value of the number, N = 12,000
Assuming the number increased equally each time, let the value of increase each time = x
The following linear equation will be obtained to solve for x;
7x + 1000 = 12,000
7x = 12,000 - 1,000
7x = 11,000
x = 11,000/7
x = 1,571.43
Therefore, the value of increase each time is 1,571.43
Can someone help on this? Please :)
answer:
N(t)=2×[tex]1.7^{t}[/tex]
17
15
step by step explain:
before lesson (t=0), she knows 2 words.
after a week (t=1), she knows
2×(1+70%)=3.4 words
after one more week (t=2), she knows
3.4×(1+70%)=5.78 words
one more week later (t=3), she knows
5.78×(1+70%)=9.826 words
and so on ...
from pattern shown above, we know that she knows
2×[tex]1.7^{t}[/tex] words after t weeks
so N(t)=2×[tex]1.7^{t}[/tex]
after 4 weeks (t=4), she knows 2×[tex]1.7^{4}[/tex]=16.7042≈17 words
for learning 5000 words, she need:
2×[tex]1.7^{t}[/tex]=5000
[tex]1.7^{t}[/tex]=2500
t log(1.7)=log(2500)
t=[tex]\frac{log(2500)}{log(1.7)}[/tex]
=14.7448727
≈15 (round up)
Answer:
(a) N(t) = 2(1.7)^t
(b) 17
(c) 15
Step-by-step explanation:
(a) N(t) = 2(1.7)^t
There is a 2 because she starts with 2 words. The 1.7 is since her vocabulary grows by 70%. Finally, t represents the weeks. (it is an exponent)
(b) Just plug in the equation
N(4) = 2(1.7)^4
N(4) = 2(8.3521)
N(4) = 16.7042
Round, so it is 17
(c) Once again, plug in the equation
5000 = 2(1.7)^t
2500 = (1.7)^t
use a calculator for the part below
log1.7(2500) = log1.7(1.7)*t
t = log1.7(2500)
t = 14.7448
Round, so it is 15
Use the diagram to answer the questions.
Is line m parallel to line n? Explain.
Is line m perpendicular to line k? Explain.
Answer:
No
Yes
Step-by-step explanation:
Let's find the inclination of the 3 lines.
m:
((-4) -3)/(0 - (-4))
-7/4
n:
((-2) -2)/(3 - 1)
-4/2
-2
k:
(1 -(-3)/(4 -(-3)
(1 +3)/4 +3
4/7
Okay, we find the inclination of all the three lines. For two lines be parallel, they have to have the same inclination. The inclination of m = -7/4 and the inclination of n = -2, so they're not parallel. And now, to know if m is perpendicular to k, they inclination have to be the opposite of the inverse of each other, so it means that they have to have opposite signals, and they need to be inverted fractions (for example a/b are inverted to b/a), and they are these two things: m = -7/4 and n = 4/7, so they're perpendicular
Answer:
No, the slopes are not equal.
Yes, the slopes are negative reciprocals.
Step-by-step explanation:
Just did it on edge.
Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1
Answer:
Two real distinct solutions
Step-by-step explanation:
Hi there!
Background of the Discriminant
The discriminant [tex]b^2-4ac[/tex] applies to quadratic equations when they are organised in standard form: [tex]ax^2+bx+c=0[/tex].
All quadratic equations can be solved with the quadratic formula: [tex]x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}[/tex].
When [tex]b^2-4ac[/tex] is positive, it is possible to take its square root and end up with two real, distinct values of x.
When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.
When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.
Solving the Problem
[tex]3x^2+5x=-1[/tex]
We're given the above equation. It hasn't been organised completely in [tex]ax^2+bx+c=0[/tex], but we can change that by adding 1 to both sides to make the right side equal to 0:
[tex]3x^2+5x+1=0[/tex]
Now that we can identify the values of a, b and c, we can plug them into the discriminant:
[tex]D=b^2-4ac\\D=(5)^2-4(3)(1)\\D=25-4(3)(1)\\D=25-12\\D=13[/tex]
Therefore, because the discriminant is positive, the equation has two real, distinct solutions.
I hope this helps!
Match each product of powers with its simplified expression
= 5-³ -³
= 5-⁶
= 1/5⁶
5⁷ × 5³= 5⁷+³
= 5¹⁰
5⁶×5 -⁴= 5⁶ - ⁴
= 5²
5-⁴×5⁴×5⁰= 5-⁴ + ⁴ × 1
= 5⁰
Answer:
answser in picturew
Step-by-step explanation:
Which integer is farthest from 0?
3
-8
-10
9
Answer:
-10
Step-by-step explanation:
i think this is the answer
Find the y-coordinates of points on the line y = −0.5x that have x-coordinates of 6[tex]coordinates[/tex]
Answer:
y = -3
Step-by-step explanation:
y = -0.5(6)
y = -3
Pls I need help with this
Answer:
the missing side is 6
Step-by-step explanation:
Using the Pythagorean theorem, ([tex]a^{2} + b^{2} = c^{2}[/tex]), for right triangles, you get [tex]4^{2} + (2\sqrt{5}) ^{2} = c^{2}[/tex]. Since the square cancels the square root for side b you get [tex](2^{2})*(5)[/tex] which equals 20. This makes your equation go to 16+20 = [tex]c^{2}[/tex]. Then add the numbers to make [tex]36=c^{2}[/tex] solve for c by taking the square root of both sides to get c = 6.
Pls help. What is the appropriate congruent for these triangles
Answer:
Side-Side-Side (SSS) Congruence - if three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.
Side-Angle-Side (SAS) Congruence - If two sides and the included angle of one triangle are congruent to the corresponding parts of another triangle, the triangles are congruent.
Angle-Side-Angle (ASA) Congruence - If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, the triangles are congruent.
Angle-Angle-Side (AAS) Congruence - If two angles and the non-included side of one triangle are congruent to the corresponding parts of another triangle, the triangles are congruent.
u see which one fits
Answer: SAS
Step-by-step explanation: because there are Two sides and the angle between them are congruent.
Find k if (x+1) 2x^3+kx^2+1
Find k if (x+1) is a factor of 2x³ + kx² + 1
Answer:
k = 1
Step-by-step explanation:The factor of a polynomial F(x) is another polynomial that divides evenly into F(x). For example, x + 3 is a factor of the polynomial x² - 9.
This is because;
i. x² - 9 can be written as (x - 3)(x + 3) which shows that both (x - 3) and (x + 3) are factors.
ii. If x = -3 is substituted into the polynomial x² - 9, the result gives zero. i.e
=> (-3)² - 9
=> (9) - 9 = 0
Therefore, if (x + a) is a factor of a polynomial, substituting x = -a into the polynomial should result to zero. This also means that, if x - a is a factor of a polynomial, substituting x = a into the polynomial should give zero.
From the question
Given polynomial: 2x³ + kx² + 1
Given factor: x + 1.
Since x + 1 is a factor of the polynomial, substituting x = -1 into the polynomial should give zero and from there we can calculate the value of k. i.e
2(-1)³ + k(-1)² + 1 = 0
2(-1) + k(1) + 1 = 0
-2 + k + 1 = 0
k - 1 = 0
k = 1
Therefore the value of k is 1.
Find the percent of markup on a T-shirt that has a store cost of $4.87 and a selling price of $15.95
Answer:
69.47%
Step-by-step explanation:
Calculation to determine Find the percent of markup
Using this formula
Percent of markup=New price-Old price/Old price
Let plug in the formula
Percent of markup=$15.95-$4.87/$15.95
Percent of markup=$11.08/$15.95
Percent of markup=0.6947*100
Percent of markup=69.47%
Therefore the percent of markup is 69.47%
Can someone please help
Answer:
ummmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm and i Oop
Step-by-step explanation:
The equation of a circle in general form is x2+y2+20x+12y+15=0 .
What is the equation of the circle in standard form?
Will award brainliest!
Answer:
[tex](x +10)^2 + (y+6)^2 = 121[/tex]
Step-by-step explanation:
Given equation :
[tex]x^2 + y^2 + 20x +12y + 15 = 0[/tex]
Standard equation of circle :
[tex](x - a)^2 + (y-b)^2 = r^2[/tex]
We will consider the x terms in the equation first to find a.
[tex](x-a)^2 = x^2 - 2ax + a^2[/tex]
-2ax = 20x
a = -20x/2x = -10
a = -10
Next consider the y terms to find b.
[tex](y - b)^2 = y^2 -2by + b^2[/tex]
-2by = 12y
b = -12y /2y = -6
b = -6
[tex](x+10)^2 + (y-6)^2 = x^2 +20x +100 + y^2 +12y + 36[/tex]
[tex]=x^2 + y^2 + 20x +12y + 136\\[/tex]
But the given equation constant is 15. So find the difference between 136 and 15 to find the radius : 136 - 15 = 121
Therefore, radius = √121 = 11
Equation in standard form :
[tex](x +10)^2 + (y+6)^2 = 121[/tex]
If x-y = b which statement is right b - y = x, X x Y = b2, b = x - y or b = y x X (this is a question to see if the site works, I know the answer)
Answer:
b = x - y
Step-by-step explanation:
Given the expression x - y = b
We are to rewrite the value of b;
We can simply do this by swapping both sides that are putting b at the Left hand side and x - y at the right as shown
b = x - y
Hence the correct expression will be b = x - y
ZEFG and ZGFH are a linear pair, mZEFG = 3n+ 21, and mZGFH = 2n + 34. What are mZEFG and mZGFH?
Answer:
The answer is below
Step-by-step explanation:
∠EFG and ∠GFH are a linear pair, m∠EFG = 3n+ 21, and m∠GFH = 2n + 34. What are m∠EFG and m∠GFH?
Solution:
Two angles are said to form a linear pair if they share a base. Linear pair angles are adjacent angles formed along a line as a result of the intersection of two lines. Linear pairs are always supplementary (that is they add up to 180°).
m∠EFG = 3n + 21, m∠GFH = 2n + 34. Both angles form linear pairs, hence:
m∠EFG + m∠GFH = 180°
3n + 21 + (2n + 34) = 180
3n + 2n + 21 + 34 = 180
5n + 55 = 180
5n = 125
n = 25
Therefore, m∠EFG = 3(25) + 21 = 96°, m∠GFH = 2(25) + 34 = 84°
28 and/or 29 pls. Find the value of x and y.
Answer:
Step-by-step explanation:
for y
take 30 degree as reference angle using sin rule
sin 30=opposite/hypotenuse
1/2=9/y (do cross multiplication)
2*9=y
18=y
for x
using pythagoras theorem
a^2+b^2=c^2
9^2+x^2=18^2
81+x^2=324
x^2=324-81
x^2=243
x=[tex]\sqrt{243[/tex]
x=9[tex]\sqrt{3[/tex]
Will rank brainliest!!
Answer:
x=46 degree
Step-by-step explanation:
32 +x=Angle ABC
32 + x =78 degree
x=78 - 32
x=46 degree
Math C Peasha - Unit 5 Pythagorean Theorem and Irrational Numbers
JIME REMAINING
1
2
3
6
18 | 10
28:42
Which irrational number can be added to to get a sum that is rational?
and
A diagonal of a cube goes from one of the cube's top corners to the opposite corner of the base of the cube, Find the length of a diagonal d in a cube that has an edge of length 10 meters.
d = 17.3 m
Step-by-step explanation:
We can extend Pythagorean theorem to 3 dimensions by writing
[tex] {d}^{2} = {x}^{2} + {y}^{2} + {z}^{2} [/tex]
or
[tex]d = \sqrt{ {x}^{2} + {y}^{2} + {z}^{2} } [/tex]
Since we are dealing with a cube of side 10 m, then
x = y = z = 10 m
so we get
[tex]d = \sqrt{ {10}^{2} + {10}^{2} + {10}^{2} } [/tex]
or
[tex]d = \sqrt{3 \times {10}^{2} } = 10 \sqrt{3} \: m[/tex]
This becomes
d = 17.3 m
Find QR.
PLEASE HELP!!!
Answer:
B.6
Step-by-step explanation:
3 + 2x + 22 = x + 17
Combine like terms
25 + 2x = x + 17
Subtract 17 from both sides
8 + 2x = x
Subtract 2x from both sides
8 = -x
Divide both sides by -1
x = -8
Substitute -8 for x in 2x + 22 to find value of QR
2(-8) + 22
Multiply
-16 + 22
Add
QR = 6
The length of QR in the given figure by combining like terms and applying the substitution method, QR = 6
Used the concept of addition and combining like terms in the mathmatical expression.
Given that,
The length of line segments is,
PQ = 3
QR = (2x + 22)
PR = (x + 17)
Now, from the figure,
PQ = QP + QR
Substitute the given values,
x + 17 = 3 + 2x + 22
Combine like terms
x + 17 = 25 + 2x
Subtract 17 from both sides
x = 8 + 2x
Subtract 2x from both sides
x - 2x = 8
- x = 8
Divide both sides by -1
x = -8
So, for the length of QR,
Substitute - 8 for x in the length of QR,
QR = 2x + 22
= 2(-8) + 22
= -16 + 22
= 6
Learn more about the line segment visit:
https://brainly.com/question/280216
#SPJ4
Simplify (6x^2 − 8x) ÷ (2x) step by step
a. 2x − 3
b. 2x + 3
c. 3x − 4
d. 3x − 8
Answer:
3x - 4
Step-by-step explanation:
(6x^2 − 8x) ÷ (2x) =
(6x^2)/2x - 8x/2x =
3x - 4
Answer:
(C). 3x - 4
Step-by-step explanation:
It will be easily to break this down so,
6/2=3
x^2/x=x
therefore, 6x^2/2x = 3x
Minus stay minus
8/2 = 4
x/x=1
therefore, 8x/2x=4
If we put it all together,
3x - 4
if this helps you, please give brainliest!
What inverse operation should be used to isolate the variable in the equation c ÷ 7 = 2?