Write an equation for the line that is parallel to the given line that passes through the given point.
y = -6x + 2; (-1,2)

Answer:

[tex]0.0166[/tex]

Step-by-step explanation:

Let the sample proportion be [tex]\hat{p}=0.14[/tex] and the sample size be [tex]n=439[/tex]:

[tex]\displaystyle \text{Margin of Error}=\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\\\\\text{Margin of Error}=\sqrt{\frac{0.14(1-0.14)}{439}}\\\\\text{Margin of Error}=\pm0.0166[/tex]

Answer:

Step-by-step explanation:

Answer:

It would be about 1/4

Step-by-step explanation:

The value of z if x = 36 and y = 6 is 42

Suppose that y varies directly with x and inversely with z, hence the required expression will be:

y = kx/z

If  y = 4 when x = 8 and z = 14 then;

4 = k(8)/14

8k = 56

k = 7

To  find z when x = 36 and y = 6, we  will have:

6 = 7(36)/z
1 = 7(6)/z

z = 42

Hence the value of z if x = 36 and y = 6 is 42

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Answer:

Keep it simple. Answer:

y=kx/z

  k=7

 z=42

Step-by-step explanation:

Answer:

$48

30/10 is equal to 3/1, 16 x 3 equals to 48.

Answer:$48

Step-by-step explanation:

$30/10p = $3 per person

3x6=18

18+30=48

It will take approximately 5.5 years for the investment to be worth $23,000

From the question, we are to determine when the investments will worth $23,000

Using the compound interest formula,

[tex]A = P (1+\frac{r}{n})^{nt}[/tex]

Where A is the amount

P is the principal

r is rate

n is the number of times it is compounded

and t is the time in years

From the given information,

A = $23000

P =$18000

r = 6.7%

n = 4

t = ?

Putting the parameters into the formula, we get

[tex]23000 = 18000(1+\frac{6.7}{100 \times 4})^{4t}[/tex]

[tex]\frac{23000}{18000} = (1.01675)^{4t}[/tex]

[tex]1.4375= (1.01675)^{4t}[/tex]

[tex]1.4375 = (1.0687)^{t}[/tex]

t = 5.46

t ≅ 5.5 years

Hence, it will take approximately 5.5 years for the investment to be worth $23,000

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Answer:

47.5 games

Step-by-step explanation:

Finding A :

⇒ Games by A : Games by B = 3 : 1

⇒ Games by A : 10 = 3 : 1

⇒ Games by A = 30

==============================================================

Finding C :

⇒ Games by B / Games by C × Games by A / Games by B = 3 × 4/3

⇒ Games by A / Games by C = 4

⇒ Games by C = 30/4

⇒ Games by C = 7.5

==============================================================

Total games won :

⇒ Games by A + Games by B + Games by C

⇒ 30 + 10 + 7.5

⇒ 47.5 games

Answer:

$986.28

Step-by-step explanation:

$124.21 + $211.94 = $336.15

700 - 336.15 = 363.85

622.43 + 363.85 = 986.28

Answer:

864

Step-by-step explanation:

First, you multiply 2 and 6, so it's 12, and multiply it by 144, so it's 1728, and divide it by 2. Therefore, it's 864!

Answer:

3 • 15

Step-by-step explanation:

Add 8 and 7 to factor out the equation, creating an equivalent expression.

answer is 3/5

since there are 3 red, there is a 3 blocks out of 5 blocks chance that a red block will chosen

Answer: [tex]\frac{5}{12}[/tex]

Step-by-step explanation:

   We will subtract the amount of water that leaked out from the amount of water originally in the fish tank.

[tex]\displaystyle \frac{3}{4} - \frac{1}{3} =\frac{3*3}{4*3} -\frac{1*4}{3*4} =\frac{9}{12} -\frac{4}{12}=\frac{5}{12}[/tex]

         The fish tank is [tex]\frac{5}{12}[/tex] of the way full.

Answer:

A) x = [tex]\frac{11}{5}[/tex]

Step-by-step explanation:

3(4 - 2x) = -x + 1

Distribute on the left:

12 - 6x = -x + 1

    + x     + x

12 - 5x = 1

- 12       - 12

-5x = -11

Divide both sides by -5 to get x on its own:

x = [tex]\frac{-11}{-5}[/tex]

OR

x = [tex]\frac{11}{5}[/tex]

Have a nice day!

Answer:

[tex]\dfrac{\sqrt[12]{55296} }{2}[/tex]

Step-by-step explanation:

Given expression:

[tex]\dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}[/tex]

[tex]\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:[/tex]

[tex]\implies \dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}=\dfrac{6^{\frac{1}{4}}}{2^{\frac{1}{3}}}[/tex]

Multiply the numerator and denominator by [tex]2^{\frac{2}{3}}[/tex] :

[tex]\implies \dfrac{6^{\frac{1}{4}}}{2^{\frac{1}{3}}} \times \dfrac{2^{\frac{2}{3}}}{2^{\frac{2}{3}}}[/tex]

[tex]\textsf{Apply exponent rule to the denominator} \quad a^b \cdot a^c=a^{b+c}:[/tex]

[tex]\implies \dfrac{6^{\frac{1}{4}}}{2^{\frac{1}{3}}} \times \dfrac{2^{\frac{2}{3}}}{2^{\frac{2}{3}}}=\dfrac{6^{\frac{1}{4}} \cdot 2^{\frac{2}{3}}}{2^{\frac{1}{3}+\frac{2}{3}}}=\dfrac{6^{\frac{1}{4}} \cdot 2^{\frac{2}{3}}}{2}[/tex]

Rewrite 1/4 as 3/12 and 2/3 as 8/12 :

[tex]\implies \dfrac{6^{\frac{1}{4}} \cdot 2^{\frac{2}{3}}}{2}=\dfrac{6^{\frac{3}{12}} \cdot 2^{\frac{8}{12}}}{2}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^c \cdot b^c=(a \cdot b)^c:[/tex]

[tex]\implies \dfrac{6^{\frac{3}{12}} \cdot 2^{\frac{8}{12}}}{2}=\dfrac{(6^3 \cdot 2^{8})^\frac{1}{12}}{2}[/tex]

Simplify the operation in the parentheses:

[tex]\implies \dfrac{(6^3 \cdot 2^{8})^\frac{1}{12}}{2}=\dfrac{(216\cdot 256)^\frac{1}{12}}{2}=\dfrac{(55296)^\frac{1}{12}}{2}[/tex]

[tex]\textsf{Finally, apply exponent rule} \quad a^{\frac{1}{n}}=\sqrt[n]{a}:[/tex]

[tex]\implies \dfrac{(55296)^\frac{1}{12}}{2}=\dfrac{\sqrt[12]{55296} }{2}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{6^{\dfrac{1}{4}}}{2^{\dfrac{1}{3}}}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{2^{\dfrac{1}{4}}3^{\dfrac{1}{4}}}{2^{\dfrac{1}{3}}}[/tex]

[tex]\\ \rm\Rrightarrow 2^{\dfrac{1}{4}-\dfrac{1}{3}}3^{\dfrac{1}{4}}[/tex]

[tex]\\ \rm\Rrightarrow 2^{\dfrac{-1}{12}}3^{\dfrac{1}{4}}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{3^{\dfrac{1}{4}}}{2^{\dfrac{1}{12}}}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{3^{\dfrac{3}{12}}}{2^{\dfrac{1}{12}}}[/tex]

[tex]\\ \rm\Rrightarrow \left(\dfrac{3^3}{2}\right)^{\dfrac{1}{12}}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt[12]{\dfrac{3^3}{2}}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt[12]{\dfrac{3^3\times 2^82^3}{22^82^3}}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt[12]{\dfrac{27(256)(8)}{2^12}}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{\sqrt[12]{6912(8)}}{2}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{\sqrt[12]{55296}}{2}[/tex]

Answer:

(5, 6)

Step-by-step explanation:

The original coordinate is (1, 1) (3, 1) (1, 4)

Translate four squares : (5, 1) (7, 1) (5, 4)

Translate two squares up: (5, 3) (7, 3) (5, 6)

The vertices of the image is (5, 6)

The function in this graph is constant in the range of -4 ≤x≤-2 , Option B is the correct answer.

A function is a mathematical statement which identifies relation between independent and dependent variable.

A graph is given

The graph will be considered constant when the y value is constant for any value of x

The value of y is constant in the range of

-4 ≤x≤-2

Therefore Option B is the correct answer.

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Answer:

The exponent form of 5670 is 5.67 × 103.

Step-by-step explanation:

you can also use this

it's pretty easy

https://calculator.name/decimal-to-scientific-notation/5670

The probability that a randomly selected pigeon gets an incorrect result is; 0.0103

We are told that;

1.5% pigeons are infected.

Inaccuracy of the test = 1 - 97% = 3%

1.5% of the pigeons are infected. Thus;

1 - 1.5% = 98.5% pigeons are un-infected.

Inaccuracy of test is 1 - 99% = 1% .

Thus;

0.03 and 0.01 are the probability of an error being made in infected and un-infected respectively.

Meanwhile, probability of infected and un-infected are 0.015 and 0.985 respectively.

Thus, the probability of a randomly chosen person gets an incorrect result = (0.03*0.015) + (0.985*0.01) =  0.0103

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Answer:

Yes

Step-by-step explanation:

13 + 5 > 16
16 - 3 < 5
Yes :D

From the curve given we can see that the graph that shows a function where f(2)= 4 is Graph A.

A quadratic graph is in form of a parabola opened upward or downward.

According to the question, we are to select a graph that has a coordinate (2, 4) on its curve.

To determine thus, we will locate the value of 2 on the x-axis and value of 4 on the y-intercept and trace whether the intersecting point is on the curve.

From the curve given we can see that the graph that shows a function where f(2)= 4 is Graph A.

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Answer:

the two selected are correct.

Step-by-step explanation:

A relation is a function only if it relates each element in its domain to only one element in the range. When you graph a function, a vertical line will intersect it at only one point. You can determine whether each element of the domain is paired with exactly one element of the range. For example, if given a graph, you could use the vertical line test; if a vertical line intersects the graph more than once, then the relation that the graph represents is not a function. The best way to find out whether an equation represents a function or not is by graphing the equation and then applying the vertical line test. Graph the two-variable equation on graph paper. For a straight line this means graphing two or more points on the line and connecting the dots.

Answer:

£74

Step-by-step explanation:

£55.50 = 75%

Find 1% of discounted price by dividing both sides by 75 :

£0.74 = 1%

Using 1%, multiply by 100% to find original price :

£74 = 100%

Check our answer :

£74 × 0.75 (75%) = £55.50 ✅

Hope this helped and brainliest please

Answer:

the original price is 416.25. because you take the 55.50 and times ... percent of discount is 75%, sale price is 55.50

Step-by-step explanation:

The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is [tex]\frac{x^2}{10} + \frac{y^2}{15} = 1[/tex]

The given parameters are:

The foci of a hyperbola are represented as:

Foci = (k ± c, h)

The center is:

Center = (h,k)

And the directrix is:

Directrix, x = h ± a²/c

By comparison, we have:

k ± c = ±5

h = 0

h ± a²/c = ±2

Substitute h = 0 in h ± a²/c = ±2

0 ± a²/c = ±2

This gives

a²/c = 2

Multiply both sides by c

a² = 2c

k ± c = ±5 means that:

k ± c = 0 ± 5

By comparison, we have:

k = 0 and c = 5

Substitute c = 5 in a² = 2c

a² = 2 * 5

a² = 10

Next, we calculate b using:

b² = c² - a²

This gives

b² = 5² - 10

Evaluate

b² = 15

The hyperbola is represented as:

[tex]\frac{(x - k)^2}{a^2} + \frac{(y - h)^2}{b^2} = 1[/tex]

So, we have:

[tex]\frac{(x - 0)^2}{10} + \frac{(y - 0)^2}{15} = 1[/tex]

Evaluate

[tex]\frac{x^2}{10} + \frac{y^2}{15} = 1[/tex]

Hence, the equation of the hyperbola is [tex]\frac{x^2}{10} + \frac{y^2}{15} = 1[/tex]

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The given example is inductive reasoning.

The method of arriving at a conclusion based on a series of observations is known as inductive reasoning. It is not a valid method of proof in and of itself.

We have the information that. Janelle got invited to a shopping spree with a friend and is supposed to meet her at the mall at 4:00 p.m. when she has gone to the mall in the past,

she has noticed that it takes about two hours for her to travel to the mall. she has also noticed that it takes her 30 minutes to get ready before leaving her apartment. she concludes that she needs to start getting ready at 0:30 p.m.

The given information is giving us the series of the data like we are having a sequence of the timing at what time what she did so we have a series of observations here.

Therefore the given example is inductive reasoning.

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Answer:

62.8ft

Step-by-step explanation:

20/2=10 so 10*2=20 so 20*3.14=62.8

62.8

Answer:

314

Step-by-step explanation:

20/2 = 10

10 * 10 = 100

3.14 * 100 = 314

Answer:

281x

Step-by-step explanation:

each hat (x) cost 281. x times cost is total

[tex]~~~~~~~~y = (x-4)^2 +6\\\\\implies (x-4)^2 = y-6 \\\\\implies x -4 = \pm\sqrt{y-6}\\\\\implies x = \pm\sqrt{y-6} +4[/tex]

Answer:

y = 6

Step-by-step explanation:

4y + 2x = 8 → (1)

5y + 2x = 14 → (2)

subtracting (1) from (2) term by term will eliminate x

y + 0 = 6

y = 6

The least amount of money that should be budgeted to paint the monument is $1692.

First step

Using Pythagorean theorem to find the surface area

Since POR is a right triangle

Hence:

PO=20

BR=12

OR=12

PR=√20²+12²

PR=400+144

PR=544

Area of PBC=1/2×24×√544

Area of PBC=12√544

Lateral surface area=4×12√544

Lateral surface area=48√544

Lateral surface area=1119.54²ft

Second step

Since regular paint is  2 coats 200 sq. ft per gallon

Hence:

Number of gallons=1119.54×2/200

Number of gallons= 11.2 gallons

11.2×35= 392

1119.54/80=13 gallons

13×100 =1300

Last step

Least amount=392+1300

Least amount= $1692

Therefore the least amount of money that should be budgeted to paint the monument is $1692.

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