You are attempting to move a new couch into your house. You apply 200 N of force and
your friend Jake applies 150 N of force in the same direction. The friction of the couch
on the carpet resists the pushing with 100 N of force. There are five forces
Explanation:
try to write complete question
but
200 Newton + 150 Newton -100 Newton
if you are asking this
Se colocan tres objetos, muy cerca uno del otro, dos al mismo tiempo. Cuando se juntan los objetos A y B, se repelen. Cuando se acercan los objetos B y C, se repelen. De los siguientes enunciados, ¿cuál es el verdadero? a) Los objetos A y C tienen cargas del mismo signo. b) Los objetos A y C poseen cargas de signos opuestos. c) Los tres objetos tienen cargas de distinto signo. d) Uno de los objetos es neutro. e) Es necesario llevar a cabo experimentos adicionales para determinar los signos de las cargas.
Answer:
Los objetos A y C tienen cargas del mismo signo (opcion a)
Explanation:
Hay dos tipos de cargas : cargas positivas y cargas negativas.
La Ley de Coulomb dice que la fuerza electrostática entre dos cargas puntuales es proporcional al producto de las cargas e inversamente proporcional al cuadrado de la distancia que las separa, y tiene la dirección de la línea que las une y se cumple que:
La fuerza ejercida sobre una carga apunta hacia la otra cuando las dos tienen distinto signo (fuerza atractiva). El sentido de la fuerza se dirige hacia el lado opuesto de la carga cuando ambas tienen el mismo signo (fuerza repulsiva).Es decir que las cargas de igual signo se repelen, mientras que las de diferente signo se atraen.
Entonces, si se juntan los objetos A y B y se repelen significa que la carga es del mismo signo.
Cuando se acercan los objetos B y C, se repelen. Entonces significa que posee carga de igual signo.
Por lo que podes concluir que los objetos A y C tienen cargas del mismo signo (opcion a)
Examine the diagram of the cell cycle.
Which label identifies the step labeled W?
Anaphase: chromosomes thicken
Metaphase: chromosomes thicken
Anaphase: chromosomes are pulled apart
Metaphase: chromosomes are pulled apart
Answer:
Anaphase: chromosomes are pulled apart
Explanation:
Anaphase is a very rapid phase of meiosis and mitosis where sister chromatids (during mitosis or meiosis II) or homologous chromosomes (during meiosis I) separate and migrate to opposite poles of the cell. In the image, the diagram represents mitosis (thus separation of sister chromatids).
During this phase, following a specific signal, the sister chromatids separate abruptly. They are then "pulled" by the "microtubules" towards the pole to which they are attached. Chromatids migrate rapidly at a rate of about 1 μm / min. Anaphase is usually divided into two distinct phases.
Answer:
The answer is C
Explanation:
A roller coaster is stopped on a track. When the engineer presses a launch button on the coaster, the coaster moves forward. Explain this change in terms of balanced and unbalanced forces.
Psychology:
_________ is focusing on something specific in the environment.
A.
Attention
B.
Stimuli
C.
Memory
D.
Rehearsal
The answer is A. Attention
Answer:
ans is a .attention
plsssssssssssss mark meeee brainlist
Explanation:
kinetic energetic plus potential energy is called
The diagram shows the forces acting on an object at an instant of time. Which of
the following statements about the forces is true? Select one answer.
Answer:
The correct option is;
The object is in horizontal equilibrium but NOT in vertical equilibrium
Explanation:
The given given forces in the force diagram are expressed in vector form as follows;
Topmost force = 2·i + 3·j
The horizontal force = 3·i
The force at the lower section = -5·i - 2·j
Adding the forces together to find the resultant force gives;
[tex]F_R[/tex] = 2·i + 3·j + 3·j + (-5·i - 2·j) = 5·i + 3·j - 5·i - 2·j = 0·i + j = j
[tex]F_R[/tex] = j
Therefore, the horizontal component of the forces are balanced as they cancel out and the object is said to be in horizontal equilibrium
However, the object has a net total resultant force component in the positive vertical direction, the object is not in vertical equilibrium.
What is the radius of an automobile tire that turns with a period of 0.091 s and has a linear
speed of 20.0 m/s? What kind of force is the centripetal force?
Answer:
1) The radius of the tire is approximately 0.28966 meters
2) The centripetal force is the force that keeps a body moving on a circular path
Explanation:
1) The linear speed of the automobile tire = 20.0 m/s
The period with which the tire turns = 0.091 s
The period = The time it takes to make a complete turn
Therefore;
The number of turns in 1 second = 1/0.091 ≈ 10.989 turns
The distance covered with 10.989 turns, assuming no friction = 10.989 × The circumference of the tire
∴ The distance covered with 10.989 turns, assuming no friction = 10.989 × 2 × π × Radius of the tire
From the speed of the car, 20.0 m/s, we have;
The distance covered in 1 second = 20.0 meters
Therefore;
10.989 × 2 × π × Radius of the tire = 20.0 meters
Radius of the tire = (20.0 meters)/(10.289 × 2 × π) ≈ 0.28966 meters
The radius of the tire ≈ 0.28966 meters
2) The centripetal force is the force required to maintain the curved motion of an object, and having a direction towards the center of the rotary motion.
The centripetal force is given by the formula, [tex]F = \dfrac{m \cdot v^2}{r}[/tex]
Where;
F = The centripetal force
m = The mass of the object
v = The linear velocity of the object
r = The radius of the rotational motion.
what would be the velocity
when a dog of 10kg and it's kinetic energy is 20J
Answer:
2 m/s
Explanation:
How are density and buoyancy related to each other?
Answer:
Buoyant force is directly proportional to the density of the fluid in which an object is immersed. Buoyancy is the tendency to rise or float in a fluid. The upward force exerted on objects submerged in fluids is called the buoyant force. where ρ is the density, V is the volume, and m is the mass of the displaced fluid.
Explanation:
Answer:
well It means the plant cells inside of a organism
A 3kg ball moving at 8 m/s strikes a 2kg ball at rest,if the collision is elastic,what is the speed of the lighter ball if the heavier ball moves at 2m/s in the opposite direction
Answer:
Speed of lighter ball is 4 m/s.
Explanation:
Applying the principle of conservation of linear momentum,
momentum before collision = momentum after collision.
[tex]m_{1}[/tex][tex]u_{1}[/tex] + [tex]m_{2}[/tex] [tex]u_{2}[/tex] = [tex]m_{1}[/tex][tex]v_{1}[/tex] - [tex]m_{2}[/tex][tex]v_{2}[/tex]
[tex]m_{1}[/tex] = 3 kg, [tex]u_{1}[/tex] = 8 m/s, [tex]m_{2}[/tex] = 2 kg, [tex]u_{2}[/tex] = 0 m/s ( since it is at rest), [tex]v_{1}[/tex] = 2 m/s, [tex]v_{2}[/tex] = ?
(3 x 8) + (2 x 0) = (8 x 2) - (2 x [tex]v_{2}[/tex])
24 + 0 = 16 - 2[tex]v_{2}[/tex]
2[tex]v_{2}[/tex] = 16 - 24
2[tex]v_{2}[/tex] = -8
[tex]v_{2}[/tex] = [tex]\frac{-8}{2}[/tex]
= -4 m/s
This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.
A 2 L balloon filled with gas is warmed from 280 K to 700 K. What is the volume of the gas after it is heated?
Answer:
New volume, v2 = 0.8L
Explanation:
Given the following data;
Original Volume = 2L
Original Temperature = 280K
New Temperature = 700K
To find new volume V2, we would use Charles' law.
Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Charles is given by;
[tex] VT = K[/tex]
[tex] \frac{V1}{T1} = \frac{V2}{T2}[/tex]
[tex] \frac{V1}{T1} = \frac{V2}{T2}[/tex]
Making V2 as the subject formula, we have;
[tex] V_{2}= \frac{V1}{T1} * T_{2}[/tex]
[tex] V_{2}= \frac{2}{700} * 280[/tex]
[tex] V_{2}= 0.0029 * 280[/tex]
V2 = 0.8L
Therefore, the volume of the gas after it is heated is 0.8L.
a quickly moving house cat has 10 j of kinetic energy at speed v. at what speed will the cat have 20 j of kinetic energy
Answer:
2.00v
Explanation:
45 POINTS!! IF ANYONE IS WILLING TO DO THIS YOU'RE A HERO
Pretend you are in a world with no friction or air resistance. You are on your bicycle at the top of a small hill. You kick off and without pedaling, you roll down the hill. How far will you go without pedaling in this pretend world? How does it compare with how far you might go in the real world? If there is a difference between the two worlds, why is this so? Explain as precisely as you can, using the law of conservation of energy in your explanation.
A 2-4 paragraph expository essay. This will include a full explanation of the normal conditions scenario and the frictionless world scenario in paragraph form.
No matter the format, the work must include:
A description of the bike’s behavior in our normal world with friction and air resistance, including distance traveled.
A description of the bike’s behavior in a frictionless, air resistance free world including distance traveled.
An explanation of forces at play in both scenarios and the kinetic and potential energy levels of the bike at various points in its travel down the hill. This will include application of the Law of Conservation of Energy using appropriate vocabulary words.
Spelling, grammar conventions, sentence structure and visual choices that allow your reader to access the information you are providing.
Answer:
you will go no where as far as you wish because there is no air resistance or friction, causing you to not stop. In the real world, you would stop a little bit after you got done with the hill because you have friction and air Resistance to bring you to a stop. There is a huge difference because in real life, there is a lot of friction and air resistance in the real world, which will eventually bring someone to a stop no matter how fast they are going.
Explanation:
The south pole of one bar magnet is near the south pole of another bar magnet. What happens between the magnets?
A. They attract each other.
B. They twist toward each other.
C. They neither attract nor repel each other.
D. They repel each other.
PLEASE HELP!!!!!!!!!!
The south pole of one bar magnet brings near the south pole of another bar magnet, they repel each other. Therefore, option (D) is correct.
What are the magnets?A magnet can be defined as an object which is capable of producing a magnetic field and attracting unlike poles and repelling like poles. When a magnet dropped in iron filings, the iron filings cling to the end of the magnet as the attraction is maximum at the ends of the magnet.
Magnetic poles always exist in pairs whenever a magnet is suspended freely in the air, and always points in the north-south direction. The pole pointing towards the geographic north is called the North Pole and the pole pointing towards the geographic south is called the South Pole.
Similar poles of a magnet repel while unlike poles attract each other. The magnetic force between the two magnets is higher when the distance between these magnets is lesser. There are three types of magnets which are Permanent magnets, Temporary magnets, and electromagnets.
Learn more about magnets, here:
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A projectile is fired with an initial speed of 37.0 m/s at an angle of 43.7 ∘ above the horizontal on a long flat firing range. What is the maximum height.
Answer:
The maximum height reached by the projectile is 33.34 m
Explanation:
Given;
initial velocity of the projectile, u = 37 m/s
angle of projection, θ = 43.7°
The maximum height reached by the projectile = ?
Apply the following kinematic equation, to determine the maximum height reached by the projectile.
Maximum height (H) is given as;
[tex]H = \frac{u^2 sin^2\theta}{2g}\\\\ H = \frac{(37)^2 (sin 43.7)^2}{2*9.8}\\\\H = 33.34 \ m[/tex]
Therefore, the maximum height reached by the projectile is 33.34 m
What is the net force on this box?
Answer:
I believe 0
Explanation:
this is due to the fact that the box will not move anywhere the forces are canceling themselves out.
Convert 14 minutes to seconds.
(What unit do we want)
1. Seconds
2. Minutes
Answer:
Seconds...
Explanation:
Consider the line graph depicting the motion of two cars. What statement regarding the cars motion is accurate?
Answer:
Its C
Explanation:
I did it on usatestprep
A 12 kg object speeds up from an initial velocity of 10 m:s-1
north to a final velocity of 15 m.s-north. Calculate the
change in momentum.
Select one:
a. -60 kg.m/s
b. 60 kg.m/s
C. -80 kg.m/s
d. 300 kg.m/s
Momentum = m • v
Original momentum = m • 10 m/s north
Final momentum = m • 15 m/s north
Change = m • (15 - 10) m/s north
Change = m • +5 m/s north
Change = +60 kg-m/s north
29. Identify whether each of the following is a form of mechanical energy:
elastic potential energy, chemical potential energy, gravitational potential
energy.
Explanation:
elastic potential energy, chemical potential energy, and gravitational potential energy are all forms of mechanical energy.
Mechanical energy includes elastic potential energy, chemical potential energy, and gravitational potential energy.
What is Mechanical energy?Mechanical energy is the energy that an object has as a result of its motion or position. Because it is stretched out in that position, a pulled bow has mechanical energy (elastic potential energy). Chemical potential energy is the energy that a substance has stored in its chemical bonds. A barbell hoisted high above a weightlifter's head has mechanical energy because of its vertical position above the ground (gravitational potential energy).The sum of kinetic and potential energy in an object used to perform a specific task is known as mechanical energy. In other words, it describes the energy of an object as a result of its motion, position, or both.
To learn more about mechanical energy, refer
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Does water pressure depend on the total amount of water present?
(Will pick brainliest)
Answer:
No, because pressure is determined by force and the area over which that force acts.
Explanation:
help me, please!!!!!!
What do you need help with?
Billy stands on a hill without slipping. In which direction is the force of friction acting?
A. along the surface of the hill, toward the bottom of the hill.
B. perpendicular to the surface of the hill
C. straight up
D. Along the surface of the hill toward the top of the hill.
Answer: D. Along the surface of the hill toward the top of the hill.
Hope I helped you!
D. Along the surface of the hill toward the top of the hill.
A diver is on a board 1.80 m above
the water. She jumps straight up
at 3.62 m/s.
At what speed does she hit the water?
[?] m/s
Answer:
v = 6.95 m/s
Explanation:
Given that,
A diver is on a board 1.80 m above the water, s = 1.8 m
The initial speed of the diver, u = 3.62 m/s
Let v is the speed with which she hit the water. It will move under the action of gravity. Using the equation of motion as follows :
[tex]v^2-u^2=2gs\\\\v=\sqrt{u^2+2gs} \\\\v=\sqrt{(3.62)^2+2(9.8)(1.8)} \\\\v=6.95\ m/s[/tex]
So, she will hit the water with a speed of 6.95 m/s.
The force of a plane's engine is moving the plane toward the right with 800N. Coming from the left you have
resistance forces of air with 60N and friction with 40N. What is the direction and net forces that is being applied
the plane?
Answer:es la F
Explanation:
The planet Jupiter is about 300 times as massive as Earth, but an object on its surface would weigh only 2.5 times as much as it would on earth. Can you come up with an explanation?
Answer:
here you go
Explanation:
so it might seem that a body on the surface of Jupiter would weigh 300 times as much as on Earth. ... But the radius of Jupiter is about 10 times that of Earth, weakening gravity by a factor of 100, resulting in 3 times its Earth weight.
W1 has a weight of 220 N acting 0.6m away from the pivot.
How far does W2 whose weight is 180 N need to sit for the see
saw to be in equilibrium.
&
?
W-220 N
W2 - 180N
a) 0.3 m
Ob) 0.73 m
C) 0.5m
O d) 0.83 m
Answer:
0.73m
Explanation:
Given parameters:
W1 = 220N
D1 = 0.6m
W2 = 180N
Unknown
D2 = ?
Solution:
The torque on each side must be balanced;
Torque = force x distance
T₁ = T₂
W1 x D1 = W2 x D2
Insert the parameters and solve for D2;
220 x 0.6 = 180 x D2
132 = 180D2
D2 = [tex]\frac{132}{180}[/tex] = 0.73m
What is the current in the 10.0 resistor?
Answer:
12.0V
12.0V
Explanation:
.
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Answer:
2.00 A
Explanation:
What is the average acceleration of a tennis ball that has an initial velocity of 6.0 m/s [E] and a final velocity of 7.3 m/s [W], if it is in contact with a tennis racket for 0.094 s?
Given :
The average acceleration of a tennis ball that has an initial velocity of 6.0 m/s.
and a final velocity of 7.3 m/s.
It is in contact with a tennis racket for 0.094 s
To Find :
The average acceleration of the tennis ball.
Solution :
We know, average acceleration is given by :
[tex]a_{avg}=\dfrac{Final \ velocity-Initial\ velocity}{Time\ Taken}\\\\a_{avg}=\dfrac{7.3-6.0}{0.094}\ m/s^2\\\\a_{avg}=13.83\ m/s^2[/tex]
Therefore, average velocity is given by 13.83 m/s².
Hence, this is the required solution.