Write and solve a system of equations to determine how many tickets were sold before and at the music festival. PLEASE HELPPP
Answers
b = number of tickets sold before
a = number of tickets sold after
cost of a ticket = number of tickets times cost per ticket
before cost = 39.95b
after cost = 54.95a
total cost = 925000
39.95b + 54.95a = 925000
total number tickets = 20000
b + a = 20000
we have
39.95b + 54.95a = 925000
b + a = 20000
multiply second equation by -39.95 and add to first equation
39.95b + 54.95a = 925000
-39.95b-39.95a = -799000 +
0b+15a = 126000
15a = 126000
divide bot sides by 15
a = 8400
sub back
b + a = 20000
b+8400 = 20000
minus 8400 both sides
b = 11600
11,600 tickets sold before
8400 tickets sold after
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Hey there!
Your answer is [tex]2(\frac{x}{6} )[/tex]
"Double" represents multiplying by 2. "the quotation of a number (x) and 6" represents division. So, we can double [tex]\frac{x}{6}[/tex], which gives us [tex]2(\frac{x}{6} )[/tex].
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Answer:
Sample space:
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Answers
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Step-by-step explanation:
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Answers
The net that can be folded to form a triangular pyramid is net b
How to determine the net that can be foldedFrom the question, we have the following parameters that can be used in our computation:
The nets in the list of options
As a general rule, a triangular pyramid has 4 triangles such that
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using the above as a guide, we have the following:
The net that can be folded to form a triangular pyramid is net b
Read more about triangular pyramid at
https://brainly.com/question/16205402
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Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
A manufacturing company with 350 employees is changing the employee health insurance plan to either plan A or plan B. The company wants to know if employees have a preference between the two plans and whether or not preference differs between those employees who have family members covered under the current plan (group 1) and those who do not (group 2). The human resources office takes a simple random sample from each of the two groups, sends information about both plans to the employees in each sample, and asks them whether they prefer plan A or plan B. The table summarizes the responses received, with expected cell counts in parentheses.
Plan A Plan B Total
Yes (group 1) 40 (32.5) 20 (27.5) 60
No (group 2) 6 (13.5) 19 (11.5) 25
Total 46 39 85
Which statement is true about whether the conditions for the chi-square test for homogeneity have been met?
a. A simple random sample should have been taken from all the employees, and then each employee in the sample should have been asked their plan preference and whether or not they have family members covered under the current health insurance plan.
b. The expected cell counts are not large enough to apply the chi-square test for homogeneity.
c. The total sample size is not large enough to apply the chi-square test for homogeneity.
d. The total sample size is too large to apply the chi-square test for homogeneity.
e. All conditions necessary to apply the chi-square test for homogeneity are satisfied here.
Answers
Answer: D. The total sample size is too large to apply the chi-square test for homogeneity.
Step-by-step explanation: When sampling without replacement, the sample size should not exceed 10 percent of the population size. Here, the sample size of 85 is just over 24 percent of the population of 350 company employees.
The total sample size is too large to apply the chi-square test for homogeneity.
We have given that,
A manufacturing company with 350 employees is changing the employee health insurance plan to either plan A or plan B.
Plan A Plan B Total
yes(group 1) 40(32.5) 20(27.5) 60
No (group 2) 6 (13.5) (11.5) 25 25
Total 46 39 85
We have to find which statement is true,
What is sampling without replacement?Each sample unit of the population has only one chance to be selected in the sample. we can select one sample only way and after selection we cannot pot this sample in the sample space again.
The sample size should not exceed 10 percent of the population size.when we use sampling without replacement,
Here, the sample size of 85 is just over 25 percent of the population of 350 company employees.
Therefore,the total sample size is too large to apply the chi-square test for homogeneity.
To learn more about the sample space replacement and without replacement visit:
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