The sideways acceleration is required to deflect an ion 2. 0 cm to one side is [tex]6.56[/tex]×[tex]10^{12}[/tex] m/[tex]s^{2}[/tex].
Velocity = 5. 5 × [tex]10^{6}[/tex] m/s
acceleration region = L1 = 5.0 cm = 0.05 m
Ends of the acceleration plates = L2 1. 5 m
D = 0.02 m
a = [tex]\frac{2v^{2}d }{2L1L2+L1^{2}}[/tex]
Putting the values
a = 2×( 5. 5 × [tex]10^{6}[/tex])^2 × 0.02 m / 2 × 0.05m × 1.5m + (0.05m)^2
a = 1×10^12 m^2/s / 0.15m^2+2.5×10^-3m^2
a = 2 ×10^5 m^2/s / 0.1525 m^2
a = [tex]6.56[/tex]×[tex]10^{12}[/tex] m/[tex]s^{2}[/tex]
The sideways acceleration is required to deflect an ion 2. 0 cm to one side is [tex]6.56[/tex]×[tex]10^{12}[/tex] m/[tex]s^{2}[/tex].
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The sideways acceleration required to deflect an ion 2.0cm to one side is [tex]7.9*10^{12} m/s^{2}[/tex] expressed to 2 significant figures
Given the following:
V = 5.5 X10 m/s
Acceleration region (L[tex]^{1}[/tex]) = 5.0 cm long
Ends of the acceleration plates are L[tex]_{2}[/tex] = 1.5m from the patient
Now determine the sideways acceleration to deflect anion
d=2.0cm to one side.
Sideway acceleration is:
[tex]a=\frac{2V^{2}d }{2L_{1}L_{2}+L_{1} ^{2} }[/tex]
[tex]a=\frac{2*(5.5*10^{6})^{2}*0.02 }{(2*0.05*1.5)+0.05^{2} }[/tex]
[tex]a=7.9344*10^{12}m/s^{2} \\[/tex]
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How does a change in the solar constant impact the absorption of shortwave radiation and the emission of longwave radiation by the earth-atmosphere system?.
Solar constant never change, and hence there is no change in shortwave as well as longwave radiation by the earth's atmosphere
Solar constant is the rate at which the solar energy from the sun intercepts the earth's surface. It's value is 1,338watts per square meter.
Long wave radiation is a type of radiation emitted from earth whose wavelength ranges from 4 to 30 micrometers. While shortwave radiation is the radiant energy which is produced by the sun whose wavelength ranges from infrared to ultraviolet through visible.
We know that solar constant never change (constant), and the amount of shortwave that reaches the earth's atmosphere is called solar constant. As the solar constant does not change, there will be no change in shortwave as well as longwave radiation by the earth's atmosphere.
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Timmy is playing on a moving walkway like you find in an airport. He wants to have fun and decides to run backward on the moving walkway at 1.6 m/s with respect to the moving walkway he is on. Both Timmy and the moving walkway are going in the opposite directions. The walkway is going at 6.9 m/s. What speed is Timmy going with respect to a person watching this endeavor who is standing on solid ground beside the walkway?
The relative velocity is obtained as 5.3 m/s from the calculation as shown below.
What is motion?We know that motion refers to the change in the position of an object with time. Give that we know that motion is relative and the position of the two objects that are in motion must always be taken into consideration. In this case, we have the situation in which Timmy and his friends are moving backwards and the runway is moving forward thus they are actually moving in opposite directions as seen.
Let us note that velocity is a vector quantity hence we have to assign the forward direction as positive and the backwards direction as negative. Thus we can then take the relative motion between Timmy and his friend and the walk way can be obtained quite conveniently by the use of;
6.9 m/s - 1.6 m/s = 5.3 m/s
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A woman pulls a crate with a force of 66 N at an angle of 39 o with respect to the horizontal. If a frictional force of 3.9 N acts on the crate, what is the total work done on the crate, in joules (J), after it has moved a distance of 5.8 m?
According to the given statement The total work done on the crate in 17.57 J.
What is work done called?When a force is applied to an item, it is deemed to have "done work" if the object travels a distance in the direction of the force. The result of force and displacement are the same. Displacement times Force equals work.
Briefing:Mass of the crate, m = 66kg
Force applied by the worker, F = 3.9 N
Angle to the horizontal, θ = 39°,
Distance moved by crate, d=5.8m
Work = Force * Displacement
Total work done on the crate
W = Fcosθ × d
W = 3.9× cos 39 × 5.8
W = 17.57 J
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URGENT LAB QUESTIONS
Graded Assignment
Lab Report: Creating and Interpreting Graphs
Answer each question, using complete sentences. When you have finished, submit this assignment to your teacher by the due date for full credit.
Total score: ____ of 25 points
(Score for Question 1: ___ of 6 points)
1. Which variable did you choose for the independent variable? Which variable did you choose for the dependent variable? Explain.
Answer:
(Score for Question 2: ___ of 12 points)
2. How did the masses affect the spring? Which mass stretched the spring the farthest? The least? Explain your answer using your data. Include your data sheet and the graph of your data in your answer.
Answer:
Type your answer here.
(Score for Question 3: ___ of 7 points)
3. Describe your graph, was it linear or nonlinear? What conclusions can you draw based on the shape of the graph?
Answer:
Type your answer here.
Answer:
give the main question as I can not see the information
A tv news reporter once stated that a person was electrocuted when 20,000 volts of electricity surged through his body. What is wrong with this description? What was it that surged through his body?.
Answer:
Current doesn't surge or travel like water through the body, instead it is the electrons that move and make current. The signals sent inside our body are also in the form of electric current but meager to what is 20,000v means. In this case, the body couldn't survive and the 'current' formed inside the body met with the resistance of flesh, and as result gave heat burns. But above all the electricity doesn't flow, it's the electrons that move and make current inside the body.
Explanation:
Hope this helps.
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Projectile Math review
1
10 points
A soccer ball is kicked with a velocity of 15.7 at an 51.6 degree angle. How far away will the ball land back on the ground?
The ball land back on the ground at the distance of 37.75 meters from the point it was kicked after completing the projectile.
What is projectile?
The term "projectile" refers to an item that is pushed by the application of an external force, then moves freely while being influenced by gravity and air resistance. Even though everything that travels through space is a projectile, they are widely used in both sports and conflict (for example, a thrown baseball, kicked football, fired bullet, shot arrow, stone released from catapult)
the ball is kicked at the speed of 15.7 m/s with degree 51.6° angle.
Vertical velocity = 15.7 sin51.6 = 15.7(0.783) = 12.3 m/s
Horizontal velocity = 15.7 cos51.6 = 15.7(0.962) = 15.1 m/s
Lets calculate the time of flight:
v = u + at
Here, v = final vertical velocity, a = gravitational acceleration, u = initial vertical velocity, t = time
putting the values
0 = 12.3 + 9.8(t)
t = -1.25 s
times cant be negative so we consider it as 1.25 seconds
This is half time, IN the compete projectile the ball will reach at the top and then again come to land taking the same time. so,
T = 2t = 2(1.25) = 2.5 seconds
Calculating the range:
Distance = speed(time)
Speed = Horizontal velocity = 15.1 m/s
time = 2.5 s
putting the values
Distance = 15.1(2.5) = 37.75 m
Therefore, the ball land back on the ground at the distance of 37.75 after full projectile.
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what do the terms self-confirmation bias and hindsight bias refer to and how might they contribute to perceiving an illusory correlation?
Self-confirmation bias is looking for information the support a personal perception while hindsight bias is a past predictions.
What is illusory correlation?An illusory correlation is the type of correlation that is perceived to exist between two variables even when there is actually no relationship existing between them.
There are two types of illusory correlation that includes the following:
Distinctiveness-based illusory correlations: This type of illusory correlation that contributes to the to initial formation of predictions.Expectancy-based illusory correlations: This is the type of illusory correlation that contains predictions that are not liable to change.Therefore, looking for the information that supports personal perception and the ability to generate past predictions helps in illusory correlation.
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Mary jogs for 15 minutes at 240 m/min, walks the next 10 minutes at 90 m/min, rests for 5
minutes, and jogs back to where she started at -180 m/min. a. Plot a velocity vs. time graph for Mary's exercise run.
b. Find the area under the curve for the first 15 minutes. What does this represent? C. What is the total distance traveled by Mary?
d. What is Mary's displacement from start to finish?
Answer:
B
Explanation:
i hope it hleps
What is a force that one object can apply to another object without touching it?
Consider a 0. 5-kg meter stick with a 1. 0 kg mass attached at the 50 cm mark and a 3. 0 kg mass at the very end. Where on the meter stick is the center of mass located?.
Answer:
The effective mass at the 50 cm mark will be 1.5 kg because the meter stick is uniform and .5 kg can be considered to be acting at 50 cm
3 * (50 - x) = 1.5 * x
Balancing torques where x is the distance from the 50 cm mark
150 - 3 x = 1.5 x
x = 150 / 4.5 = 33.3
x would be at 50 - 33.3 = 16.7
Check: 3 * 16.7 = 1.5 * 33.3
50.1 = 50 within rounding
A ferry approaches shore, moving north with a speed of 6.5 m/s m / s relative to the dock. a person on the ferry walks from one side of the ferry to the other, moving east with a speed of 1.1 m/s m / s relative to the ferry. what is the speed of the person relative to the dock?
The relative velocity with respect to the dock is 6.5j + 1.1 i m/s m/s.
We need to know about relative velocity to solve this problem. The relative velocity depends on the object and observer velocity. It can be written as
v = vo ± v'
where v is relative velocity, vo is object velocity and v' is observer velocity.
From the question above, we know that
vo = 6.5 j m/s
v' = 1.1 i m/s
The velocity will be added each other because the direction of the observer is different from the object.
v = vo + v'
v = 6.5j + 1.1 i
v = 6.5j + 1.1 i m/s
Thus, the relative velocity is in vector form.
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what is the purpose of this experiment?group of answer choicesthe purpose of this experiment is to understand series and parallel circuits, how to calculate their equivalent resistance, and how to construct the laboratory.the purpose of this experiment is to understand circuits.the purpose of this experiment is to comprehend ohm’s law and how to compare their percent difference from their experimental and theoretical values.the purpose of this law is to identify non-ohmic devices and how to convert those devices ohmic.
The purpose of this experiment is to understand series and parallel circuits, how to calculate their equivalent resistance, and how to construct the laboratory.
How do parallel circuits function?There are two or more paths that current to travel through in a parallel circuit. Each element of the parallel circuit has the same voltage applied to that too. The total current flowing from the source is equal to the sum of a currents through each path.
What is a parallel circuit example?When one route is blocked, electricity continues to flow thanks to a parallel circuit. Numerous lighting fixtures are a great example. Even if just one light in the fixture fails, led light stays on.
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A wide receiver starts at rest at the line of scrimmage and runs vertically towards the end zone for a pass. If the athlete accelerates at a constant rate of 1.7 meters per second^2, approximately how far did the athlete run if the play lasted 5.0 seconds? * 1 point
The distance travelled by the athlete given the play lasted for 5.0 seconds is 21.25 m
How to determine the distanceWe'll begin by listing out the parameters given from the question. This is given below:
Initial velocity (u) = 0 m/sAcceleration (a) = 1.7 m/s²Time (t) = 5 secondsDistance (s) =?From the given parameters, we can determine the distance as follow:
s = ut + ½at²
s = (0 × 5) + (½ × 1.7 × 5²)
s = 0 + 21.25
s = 21.25 m
From the above calculation, we conclude that the athlete ran 21.25 m during the 5 seconds play.
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a small button placed on a horizontal, rotating platform with diameter 0.320 mm will revolve with the platform when it is brought up to a rotational speed of 40.0 rev/minrev/min, provided the button is no more than 0.140 mm from the axis.
The ratio of friction force to normal force is expressed by the coefficient of friction, a dimensionless number. The platform and button have a friction coefficient of 0.329.
Given that the button's diameter is 0.520 m and its rotational speed is 35.0 rev/min, its distance from the axis is no greater than 0.240 m. This indicates that the button's placement circle's radius R is this.
The calculation for the angular velocity is shown below.
ω=2πf
where f is the revolution's speed.
ω=2*3.14*35/60
ω=3.67 rad/s
The friction coefficient is determined in the manner shown below.
μmg= mω²R
μ=0.329
The friction force between the button and the platform will be equal to the centripetal force acting on the button.
Hence we can conclude that the friction coefficient between the button and the platform is 0.329.
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A car must be driven a distance of 120 km in 2.5 h. During the first 1.5 h, the average speed was 70 km/h. Calculate the average speed for the remainder of the journey.
The average speed for the remainder of the journey is 15km/h.
How to calculate average speed?Average speed of a moving body can be calculated by dividing the distance moved by the object by the time taken to complete the distance as follows;
Average speed = distance/time
According to this question, a car must be driven a distance of 120 km in 2.5 h, however, during the first 1.5 h, the average speed was 70 km/h.
First, the initial distance moved must be calculated as follows:
Distance = 1.5 hours × 70km/h = 105km
The remaining distance = 120km - 105km = 15km
Average speed for this remaining distance = 15km ÷ 1hr = 15km/h.
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20 POINTS PLEASE HELP
Use the image above to help you respond to this question:
If you were able to float from Earth’s surface and into space, you would notice shifts in the temperature along the way. We know that the density of air molecules is lessening and it SHOULD get colder as you ascend, so explain why
a) the stratosphere behaves differently.
b) the thermosphere behaves differently.
A train changes it’s speed from 3m/s to 17m/s in 2.0 seconds calculate its acceleration.
Answer: acceleration of the train = 7 m/s^2
Explanation: We are going to use the formula for acceleration,
acceleration of a moving body is the change in speed per unit of time, hence the formula for finding acceleration is
a = (v-u)/t
here, a = acceleration
v = final speed
u = initial speed
t = total time taken
here (v-u) will give the change in velocity since it's the difference between the final and initial velocity of the train
Given, v = 17 m/s
u = 3 m/s
t = 2 s
∴ a = (17-3)/2
= 14/2
= 7 m/s^2
2000 kg car at rest has a net force of 500 N being applied to the left. If the force is applied
for 10 sec, what is the final velocity of the car?
The final velocity of the 2000 kg car with a net force of 500 N being applied to the left for 10 sec is - 2.5 m / s
a = ( v - u ) / t
F = Force
m = Mass
a = Acceleration
v = Final velocity
u = Initial velocity
t = Time
t = 10 s
u = 0
a = ( v - 0 ) / 10
a = v / 10
According to Newton's second law of motion,
F = m a
F = Force
m = Mass
m = 2000 kg
F = - 500 N
- 500 = 2000 * ( v / 10 )
v = - 2.5 m / s ( Negative sign indicate the object is moving towards left )
Therefore, the final velocity of the car is - 2.5 m / s
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after resting for 10 minutes, you decide to perform another explosive, one-time movement such as a standing vertical jump and again, exert maximal effort. you briskly push yourself up from a chair and walk about 1.5 minutes to arrive at a wall where a vertical jump measurement can be made.
In this case, anaerobic metabolism is utilized.
Anaerobic metabolism: What is it?The process of producing ATP anaerobically, also known as without oxygen or in the absence of oxygen, involves the direct phosphate transfer from phosphorylated intermediates like creatine phosphate or glycolytic intermediates to ADP, which in turn produces ATP.
What is the result of anaerobic metabolism?Lactic acid builds up as a result of the anaerobic metabolism of glucose, which causes metabolic acidosis. A base deficit results from the reaction between lactic acid and bicarbonate, which lowers serum bicarbonate levels.
What does aerobic versus anaerobic metabolism mean?Anaerobic metabolism only produces two ATP molecules for every glucose molecule while aerobic metabolism produces more ATP and depends on oxygen.
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question 14: how long does the eclipse of an earth-like planet take? how much time passes between eclipses? what obstacles would a ground-based mission to detect earth-like planets face?
When the Sun passes through the nodal eclipse zones, the eclipses would last approximately 6 hours, with there being a chance of two solar eclipses every 34.5 days.
How far apart are eclipses?Each year, there are two to five solar eclipses, with a total eclipse occurring roughly every 18 months. You might be able to see that eclipse, depending on where you are in the world. The view of the eclipse and the Moon's shadow on Earth move from west to east as the Earth rotates.
Why are eclipses 6 months apart?This is due to the fact that there are roughly 15 days (or a fortnight) between a full moon and a new moon, and vice versa. There are enough days (30 days) for two more eclipses if one occurs at the start of the season.
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What is the weight of a 179 kg football player?
The weight of a 179 kg of football player is 1755.99N.
How to calculate weight?Weight is the force on an object due to the gravitational attraction between it and the Earth.
Weight is a function of an object's mass and acceleration due to gravity, hence, can be calculated by multiplying the mass of the object by its acceleration.
According to this question, the mass of a football player is 179 kg is given. The acceleration due to gravity on Earth is 9.81m/s². The weight can be calculated as follows:
Weight = 179kg × 9.81m/s²
Weight = 1755.99N
Therefore, 1755.99N is the weight of the player.
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If a car travels 12.0 km south then 5.0 km north in 0.25 h, what is its average velocity? It’s average speed?
The average speed and average velocity of the car is 68 km/h and 28 km/h respectively.
The change in position or displacement divided by the time periods during which the displacement occurs is known as average velocity. Based on the direction of the displacement, the average velocity might either be positive or negative. Average speed is the total distance travelled by an object to the total time taken.
The car travels 12 km then 5.0 km north in 0.25 h. The average speed and average velocity is given below.
Average speed = total distance/time
Average speed = (12+5)/0.25 = 68 km/h
Average velocity = displacement/time
Average velocity = (12-5)/0.25 = 28 km/h
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Near the end of a bicycle race, Krystal accelerates at 0.36m/s^2 [E] for the final 15.0s. If her initial velocity is 11.0m/s [E], what is her final velocity?
The final velocity of Krystal who accelerated at 0.36m/s² for the final 15.0 s, having an initial velocity of 11.0m/s is 16.4m/s.
What is Krystal final velocity?Velocity is simply the speed at which an object moves in a particular direction.
Acceleration is the rate of change of the velocity of a particle or object with respect to time.
From the first equation of motion;
v = u + at
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
Given the data in the question;
Acceleration a = 0.36m/s²Elapsed time t = 15.0sInitial velocity u = 11.0m/sFinal velocity v = ?To determine Krystal's final velocity, plug the given values into the equation of motion above and solve for v.
v = u + at
v = 11.0m/s + ( 0.36m/s² × 15.0s )
v = 11.0m/s + ( 0.36ms/s² × 15.0 )
v = 11.0m/s + ( 0.36m/s × 15.0 )
v = 11.0m/s + 5.4m/s
Final velocity v = 16.4m/s
Therefore, Krystal's final velocity for the final 15.0 seconds is 16.4m/s.
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Starting from rest, a marble first rolls down a steeper hill, then down a less steep hill of the same height. For which is it going faster at the bottom?.
The first and second marble have the same speed at the bottom.
We need to know about the conservation of energy to solve this problem. The energy can not be created or destroyed, the only way is to change to another form. It can be written as
Ei = Ef
where Ei is initial energy and Ef is the final energy
The potential energy of the first marble is the same as the second marble because they have the same height. According to conservation of energy, the potential energy will be converted to kinetic energy and the speed of the marbles will same at the bottom.
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5. A car moves with an avg velocity of +12.5m/s. If it begins 137m behind the origin, where will it be after 7s?
Displacement = 1/2(Initial Velocity + Final Velocity)Time
If we plug in the values (0 as initial velocity, 12.5 as final velocity, 7 as time), we get 43.75 meters.
According to the given condition we are 137 meters behind the origin. That would mean our initial displacement is -137 meters. After driving for 7 seconds, the car would be 43.75 meters closer to the origin.
-137 + 43.75 = - 93.25 meters (or 93.25 meters behind the origin).
A moving object always has energy in its ______ ______ ______. What 3 words complete the sentence?
Explanation:
A moving object always has kinetic energy store
A 900 kg racing car is travelling at a uniform speed of 30m/s around a circular racetrack with a diameter of 360 m. what is the centripetal force acting on the car?
The centripetal force acting on the car is 4500 N
The force that acts on the body to make it follow a circle is known as centripetal Force.
Mass m = 900 kg
speed v = 30 m/s
radius r = diameter/2 = m
To calculate Centripetal force:
[tex]F_{c}[/tex] = mv^2/r
[tex]F_{c}[/tex] = 900×30^2/180
[tex]F_{c}[/tex] = 4500 N
The centripetal force of the car is 4500 N.
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Answer explanation pls
The Distance Travels after 5s is 50 m.
What are the equations of motion?First equation of motion: v = u + at.
Second equation of motion: s = ut + 12 at2
Third equation of motion: v2 = u2 + 2as.
A physical system's behavior in terms of how its mobility varies over time is described by equations of motion.
The equations of motion, which are a group of mathematical functions stated in terms of dynamic variables, provide a more thorough description of how a physical system behaves. Space, time, and occasionally components of momentum make up these factors in most cases. The most flexible choice is generalized coordinates, which can represent any meaningful variable present in the physical system. In relativity, curved spaces are employed in place of the Euclidean spaces where the functions are specified in classical mechanics. If the dynamics of a system are known, the equations are the solutions to the differential equations that describe the motion of the dynamics.To learn more about : equations of motion.
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A ball is projected with 40m/s vertically upward. (Ignore air resistance)
Compute A. the total time of flight
B. the maximum height
C. the velocity at t=5s
IN DESPERATE NEED OF HELP!!!
Make us of equation of motion formulas.
a.) the total time of flight = 8.16 s
b.) the maximum height reached = 81.6 m
c.) the velocity at t = 5s = 9 m/s
Motion Under GravityMotion of any object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.
Given that a ball is projected with 40 m/s vertically upward.
A. the total time of flight of the ball will be T = 2t
At maximum height, v = 0.
v = u - gt
0 = 40 - 9.8t
9.8t = 40
t = 40 / 9.8
t = 4.08 s
T = 2 × 4.08
T = 8.16 s
B. the maximum height H can be found by using the formula
v² = u² - 2gH
At maximum height, v = 0
0 = u² - 2 × 9.8 × H
40² = 19.6H
H = 1600/19.6
H = 81.6 m
C. the velocity at t = 5s will be v
v = u - gt
v = 40 - 9.8 × 5
v = 40 - 49
v = - 9 m/s
That is, 9 m/s in the opposite direction ( coming downward )
Therefore, the total time of flight of the ball is 8.16 s, the maximum height reached is 81.6 m and the velocity at t = 5s is 9 m/s
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Which of the following equipment is not usually involved in the production of electricity?
The equipment that are usually involved in the production of electricity are generators.
The most commonly used electricity generation equipment are Turbines. Different types of turbines are used such as:
Steam turbinesWind turbinesHydroelectric turbineCombustion gas turbinesAn electrical generator is used along with the turbine to convert the mechanical energy produced by the turbine into electricity.
Some of the other equipment used to generate electricity are
Solar photovoltaic cellsInternal combustion enginesFuel cells etc.Therefore, the equipment that are usually involved in the production of electricity are generators.
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Answer:
Non-electric appliances you might already own
Coffee percolator. They make delicious coffee and are convenient for camping trips. ...
French press: This is another coffee maker that is as easy to use as a percolator. ...
Manual mixer. ...
Hand flour mill. ...
Dough maker. ...
Food strainer. ...
Manual food processor. ...
Zeer clay pot fridge.
Explanation:
non-electric equipment are use in the production of a work piece that does not involve the use of electrical equipment