You are on an academic committee tasked to evaluate state employment math test questions. The following question has come to the attention of the committee:
"Each of the four digits 3, 4, 5, and 8 is placed in one of the boxes to form a fraction. The numerator and the denominator are two-digit whole numbers. What is the smallest value of all the common fractions that can be formed? Express your answer as a reduced fraction."

There are 4 boxes arranged in a square with 2 boxes side-by-side directly on top of the other 2 boxes. There is a horizontal line representing a fraction bar separating the top 2 boxes from the bottom 2 boxes.
Some committee members contend this is not a valid question.
Solve the problem. (If there is no solution, enter NO SOLUTION.)

Explain the solution to prove (or disprove) the question's validity.
The question is valid because to make the fraction as small as possible, you make the numerator as small as possible and make the denominator as large as possible.The question is valid because to make the fraction as small as possible, you make the numerator as large as possible and make the denominator as small as possible. The question is valid because to make the fraction as small as possible, you make both the numerator and the denominator as small as possible.The question is valid because to make the fraction as small as possible, you make both the numerator and the denominator as large as possible.The question is not valid because there is no solution.

Answers

Answer 1

Answer:

no solution that's my answer

Answer 2

The valid solution to the problem is: The smallest value of all the common fractions that can be formed using the digits 3, 4, 5, and 8 is 34/85.The smallest value of all the common fractions that can be formed using the digits 3, 4, 5, and 8 is 34/85.

Let's solve the problem step by step to determine the smallest value of all the common fractions that can be formed using the digits 3, 4, 5, and 8. We'll express the answer as a reduced fraction.

We have 4 boxes arranged in a square as described:

 A  B

 C  D

The fraction can be represented as AB/CD.

To make the fraction as small as possible, we need to arrange the digits in a specific way. We want to minimize the numerator (AB) and maximize the denominator (CD).

For the numerator (AB), we want the smallest two-digit number. The smallest two-digit number that can be formed using the digits 3, 4, 5, and 8 is 34.

For the denominator (CD), we want the largest two-digit number. The largest two-digit number that can be formed using the digits 3, 4, 5, and 8 is 85.

Therefore, the smallest fraction that can be formed is 34/85.

To ensure that this fraction cannot be further reduced, we need to check if 34 and 85 share any common factors greater than 1. If they do not share any common factors other than 1, then the fraction is in its reduced form.

Checking for common factors:

Factors of 34: 1, 2, 17, 34

Factors of 85: 1, 5, 17, 85

The only common factor is 1, which means the fraction 34/85 is already in its reduced form.

Thus, the valid solution to the problem is:

The smallest value of all the common fractions that can be formed using the digits 3, 4, 5, and 8 is 34/85.

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Related Questions

a figure is dilated by a scale factor of 3, if the origin is the center of dilation, what is the new vertex, a', if the old vertex was located. at A(3,4)?

Answers

A figure is dilated by a scale factor of 3 if the origin is the center of dilation, What is the new vertex, a', if the old vertex was located. at A(3,4)?​

_______________________________________

Please, give me some minutes to take over your question

__________________________________________

5. Each term in the second row is deter- mined by the function y=2x-1. 2 4 5 3 7 9 What number belongs in the shaded box? X y 1 1 3 5 12​

Answers

Answer:

23

Step-by-step explanation:

12 * 2= 24

24-1= 23

20. The mean IQ score for 1500 students is 100, with a standard deviation of 15. Assuming the scores have a normal distribution, answer the following b. How many have an IQ between 70 and 130? 2. How many have an IQ between 85 and 115? e. How many have an IQ over 145?

Answers

Given the normal distribution, the following can be illustrated:

1. The number of people who have an IQ between 70 and 130 is 1024.

2. The number of people who have an IQ between 85 and 115 is 1024.

The number of people who have an IQ over 145 is 3.

How to compute the value?

1. The The number of people who have an IQ between 70 and 130 will be:

z(115) = (130-100)/15 = 2

z(85) = (70-100)/15 = -2

P(-2< z < 2) = 0.6827

The number of 1500 that have IQ between 70 and 130 will be:

= 0.6827 × 1500

= 1024

2. The number of people who have an IQ between 85 and 115 will be:

z(115) = (115-100)/15 = 1

z(85) = (85-100)/15 = -1

We need to consult Z-table to find P value with this Z value

P(85< x < 115) = P(-1< z < 1) = 0.6827

Number of people of 1500 that have IQ between 85 and 115:

= 0.6827 × 1500

= 1024

3. The number of people who have IQ over 145?

Z(>145)

=( 145-100)/15

=3

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provide the correct reason for the statement in line 6. (please help)

Answers

Answer:

Step 6: Subtraction Property of =

Step-by-step explanation:

I need help I’m confused and stuck

Answers

Answer:

Step-by-step explanation:

x = -A x 2/7 + 10

Answer:

-3.5 (or -3.50); each cup of coffee is $3.50

Step-by-step explanation:

the slope of the function is what is in front of the x

that is

-3.50 or just -3.5

this means that each cup of coffee is $3.50

A math test has 12 multiplication problems and 24 division problmes what is the ratio value

Answers

The ratio value of multiplication problems to division problems is 1:2.

What is the ratio value?

The ratio value compares two quantities or values.

The ratio value shows the quantity of one variable contained in another.

Ratios are depicted by the ratio sign (:) or in fractions, decimals, or percentages.

The number of multiplications problems in the math test = 12

The number of division problems in the math test = 24

The ratio value of their relationship = 12:24 or 1:2

Thus, the math test shows that there are twice as many division problems as multiplication problems.

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What is the length of segment KL? Round the answer to
the nearest tenth of a units.

K=(-4,-6) L =(5,1)

Answers

Answer:

d ≈ 11.40

Step-by-step explanation:

K: (-4, -6); L: (5, 1)

    (x₁, y₁)     (x₂, y₂)

d = √(x₂ - x₁)² + (y₂ - y₁)²

d = √(5 - (-4))² + (1 - (-6))²

d = √(5 + 4)² + (1 + 6)²

d = √(9)² + (7)²

d = √81 + 49

d = √130 ≈ 11.40

I hope this helps!

Please help I’ll mark you as brainliest if correct !

Answers

For the given 14 digit credit card, the value of first letter A is found as 4.

What is defined as the arithmetic progression?An arithmetic progression (AP) is a succession in which the differences between each successive term are the same. In this type of progression, it is possible to derive a formula for the AP's nth term.

For the given question;

The formula for finding the sun of nth terms of the AP are-

Sn = n/2(a + l)

Where, Sn is the sum of all termsn is the total number of AP.a is the initial term.l is the last term.

From the given 14 digits credit card, consider initial 3 letters.

A,_, 8

The sum of three consecutive numbers is 18.

Thus, applying Sum formula of AP

Sn = n/2(a + l)

n = 3Sn = 18a = Al = 3

Put the values;

18 = 3/2(A + 8)

Simplifying;

3A + 24 = 36

A = 12/3

A = 4

Thus, the value of the first digit of the credit card is found as 4.

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Suppose the top of the minute hand of a clock is 2 in. From the center of the clock. For the duration, determine the distance traveled by the tip of the minute hand (30 minutes)

Answers

yes

yes

yes

yes

yes

yes

no

Find a formula for the exponential function passing through the points (-1,5/4) and (3,320).

Answers

[tex]{\Large \begin{array}{llll} y = ab^x \end{array}} \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} x=-1\\ y=\frac{5}{4} \end{cases}\implies \cfrac{5}{4}=ab^{-1}\implies \cfrac{5}{4}=\cfrac{a}{b} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\begin{cases} x=3\\ y = 320 \end{cases}\implies 320=ab^3\implies 320=ab^{4-1}\implies 320=ab^4 b^{-1} \\\\\\ 320=ab^4\cdot \cfrac{1}{b}\implies \stackrel{\textit{substituting from the previous equation}}{320=\cfrac{a}{b}b^4\implies 320=\cfrac{5}{4}b^4}\implies 320\cdot \cfrac{4}{5}=b^4 \\\\\\ 256=b^4\implies \sqrt[4]{256}=b\implies \boxed{4=b} \\\\\\ \cfrac{5}{4}=\cfrac{a}{b}\implies \cfrac{5}{4}=\cfrac{a}{4}\implies \boxed{5=a}~\hfill {\Large \begin{array}{llll} y =5(4)^x \end{array}}[/tex]

1 2 3 5 9 Find a number between and 10 Write your answer as an improper fraction and as a mixed number

Answers

In finding a number between 9/8 and 10/8, we can use the average of these two.

We can ensure that this number lies between this two.

[tex]Ave=\frac{1}{2}(a+b)[/tex]

where a and b are the two numbers

So we have :

[tex]\begin{gathered} Ave=\frac{1}{2}\times(\frac{9}{8}+\frac{10}{8}) \\ =\frac{9}{16}+\frac{10}{16} \\ =\frac{19}{16} \end{gathered}[/tex]

Therefore, one number that lies between 9/8 and 10/8 is :

[tex]\begin{gathered} \frac{19}{16} \\ or \\ 1\frac{3}{16} \end{gathered}[/tex]

Write the equation of a Circle with the given information.Center: (-14,9) Point on the Circle: (-11, 12)

Answers

The equation of a circle with center (a, b) and radius r is

[tex](x-a)^2+(y-b)^2=r^2[/tex]

We are given the center as

[tex](a,b)\Rightarrow(-14,9)[/tex]

To find the radius, we can use the formula to find the distance between two points, that is, the point on the circle and the center.

[tex]r=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2_{}_{}}[/tex]

where (x₁, y₁) = (-14, 9)

(x₂, y₂) = (-11, 12)

Thus, we have

[tex]\begin{gathered} r=\sqrt[]{(12-9)^2+(-11-\lbrack-14\rbrack)^2} \\ r=\sqrt[]{3^2+3^2} \\ r=\sqrt[]{9+9} \\ r=\sqrt[]{18} \\ r=3\sqrt[]{2} \end{gathered}[/tex]

Therefore, inputting all the values into the equation for a circle, we have

[tex]\begin{gathered} (x-\lbrack-14\rbrack)^2+(y-9)^2=3\sqrt[]{2} \\ \therefore \\ (x+14)^2+(y-9)^2_{^{}}=3\sqrt[]{2} \end{gathered}[/tex]

The measure of the vertex angle of an isosceles triangle is three times the measure of a base angle. Find the number of degrees in the measure of the vertex angle.

Answers

We will label the base angles of the triangle as "x".

[tex]\text{Base angle=x}[/tex]

Since the vertex angle is 3 times the measure of the base angle, the vertex angle will be equal to 3x:

[tex]\text{Vertex angle =3x}[/tex]

The following image represent the angles in the isosceles triangle:

Now we use the following property of triangles:

The sum of all of the internal angles in a triangle must be equal to 180°.

Thus, we add the angles and equal them to 180°

[tex]3x+x+x=180[/tex]

We combine the terms on the left:

[tex]5x=180[/tex]

And divide both sides by 5:

[tex]\begin{gathered} \frac{5x}{5}=\frac{180}{5} \\ x=36 \end{gathered}[/tex]

And since x=36, the vertex angle will be:

[tex]\text{vertex angle = 3x = 3(36)=108\degree}[/tex]

answer: 108°

What is the y-intercept of the given graph?

A) -4
B) 3
C) 4
D) None of these choices are correct.

Answers

Answer: The Y intercept is B) 3.

Step-by-step explanation:

you just have to see where the line crosses the y axis which in this case is it crosses the y axis on 3

According to one mathematical model, the average life expenctancy for American men born in 1900 was 55 years. Life expectancy has increased by about 0.2 year for each birth year after 1900. If this trend continues, for which birth year will the average life expentancy be 71 years?

a) Write an equation to model the problem. Let t represent the number of years after 1900 and let n represent men's life expectancy at that time. For example t=12 and n=57.4 in the year 1912.
Answer: ?
b) Solve the equation, then answer the question given above. (Note: You are asked for a year, not a value for t.
Answer: ?

Answers

a) An equation to model the problem of determining the birth year when the average life expectancy will be 71 years is y = 55 + 0.2x.

b) From the equation above, from 1980 or in the 80th birth, the average life expectancy will be 71 years.

What is the average life expectancy?

The average life expectancy refers to the average time in years that a person is expected to live after birth.

The average life expectancy has been a statistical tool for understanding a person's lifespan on earth based on some demographics.

What is an equation?

An equation is a mathematical statement that equates two or more variables, numbers, or values or regards them as equivalent or equal.

For this situation, we can use the formed equation to predict a person's life expectancy average in the future, given the current years and increasing rate of life expectancy.

Life expectancy in 1900 = 55 years

Life expectancy increase for each birth year after 1900 = 0.2

Life expectancy = y

Year = x

y = 55 + 0.2x ... Equation

71 = 55 + 0.2x

0.2x = 16

x = 16/0.2

= 80 birth year

1980 = (1900 + 80)

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what is x3+y3+z3=k explain what the answer is.

Answers

Answer:

x=1/3k-y-z

Step-by-step explanation:

3x+3y+3z=k

Move the variables to the right

3x= -3y-3z+k

Divide both sides of the equation by 3

x=1/3k-y+z

The ratio of the weight of an object on Planet A to the weight of the same object on Planet B is 100 to 3. If an elephant weighs 2400 pounds on Planet​ A, find the​ elephant's weight on Planet B.

Answers

The weight of the elephant on planet B given the ratio of the weights on planet A an B is 72 pounds.

What is the weight of the elephant on Planet B?

Ratio is used to compare two or more quantities together. It shows the number of times that one quantity is contained in another quantity. In this question, the weight of the elephant on Planet B is 100/3 times that of Planet A.

In order to determine the weight of the elephant on Planet B, multiply the ratio of the weight in planet B by the weight in Planet A and divide by the ratio of weight in planet A.

Weight in Planet B = (3 x 2400) / 100 = 72 pounds

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identify the maxima and minima and intervals on which the function is decreasing and increasing

Answers

Solution

From the given graph,

The maxima is

[tex](1,-1)[/tex]

The minima isThe inetrev

[tex](7,-19)[/tex]

aterval inwh which the function is increasing is

[tex](-\infty,1)\cup(7,\infty)[/tex]

dec

[tex](1,7)[/tex]

Given the example below, the zero product rule is exhibited correctly
because it take the factored form of the quadratic and sets equal to zeros
and solves.
x²+4x-21-
(x+7)(x-3)=0
x+7=0 or x-3=0
x=-7
x=3
True or false

Answers

The statement is true. This is an example of Factorization being correct as it takes the factors of the quadratic equation set them equal to 0 and then calculates the value of x.

In the given question, an example of factorization is taken for the equation x²+4x-21 which is factorized using the Middle-Term split rule. We have to find out if the example is conducted correctly.

Factorization is the rule to factorize an equation such that its factors if multiplied together form the equation itself.

We will verify the factorization, for equation x²+4x-21

=> x² + 4x - 21

=> x² + 7x -3x -21

=> x(x + 7) -3(x + 7)

=> (x + 7)(x - 3) = 0

=> x = -7, x = 3

Hence, the statement is True.

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HURRY On a coordinate plane, a curve goes through (negative 6, 0), has a maximum at (negative 5, 500), decreases to (negative 2.5, negative 450), increases through (0, negative 50), increases again through (1, 0), and then goes through (2, 400).
The real solutions to the equation 3x5 + 25x4 + 26x3 – 82x2 + 76x = 48 are shown on the graph. What are the nonreal solutions?

StartFraction 1 + i StartRoot 5 EndRoot Over 3 EndFraction, StartFraction 1 minus i StartRoot 5 EndRoot Over 3 EndFraction.
StartFraction negative 1 + i StartRoot 5 EndRoot Over 3 EndFraction, StartFraction negative 1 minus i StartRoot 5 EndRoot Over 3 EndFraction.
StartFraction negative 1 + StartRoot 5 EndRoot Over 3 EndFraction, StartFraction negative 1 minus StartRoot 5 EndRoot Over 3 EndFraction.
StartFraction 1 + StartRoot 5 EndRoot Over 3 EndFraction, StartFraction 1 minus StartRoot 5 EndRoot Over 3 EndFraction.

Answers

The non-real solutions of the polynomial expression are x = (1 + 2√-5)/3 and x = (1 - 2√-5)/3

How to determine the non-real solutions?

The equation of the polynomial expression is given as:

3x5 + 25x4 + 26x3 – 82x2 + 76x = 48

Rewrite the equation as

3x^5 + 25x^4 + 26x^3 – 82x^2 + 76x - 48 = 0

The points on the graph are given as

(-6, 0), (-5, 500), (-2.5, -450), (0, - 50), (1, 0), (2, 400).

Write out the x-intercepts

(-6, 0) and (1, 0)

This means that

Real solution = -6

Real solution = 1

Rewrite the above as

x = -6 and x = 1

So, we have

x + 6 = 0 and x - 1 = 0

Multiply

(x + 6)(x - 1) = 0

The next step is to divide the polynomial equation 3x^5 + 25x^4 + 26x^3 – 82x^2 + 76x - 48 = 0 by (x + 6)(x - 1) = 0

This is represented as

3x^5 + 25x^4 + 26x^3 – 82x^2 + 76x - 48/(x + 6)(x - 1)

Using a graphing calculator, we have

3x^5 + 25x^4 + 26x^3 – 82x^2 + 76x - 48/(x + 6)(x - 1) = 3x^3 + 10x^2 - 6x + 8

So, we have

3x^3 + 10x^2 - 6x + 8

Factorize

(x + 4)(3x^2 - 2x + 2)

Next, we determine the solution of the quadratic expression 3x^2 - 2x + 2 using a quadratic formula

So, we have

x = (-b ± √(b² - 4ac))/2a

This gives

x = (2 ± √((-2)² - 4 * 3 * 2))/2 * 3

So, we have

x = (2 ± √-20)/6

This gives

x = (2 ± 4√-5)/6

Divide

x = (1 ± 2√-5)/3

Split

x = (1 + 2√-5)/3 and x = (1 - 2√-5)/3

So, the conclusion is that

Using the polynomial expression, the non-real solutions are x = (1 + 2√-5)/3 and x = (1 - 2√-5)/3

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Use the graph below which shows the profit y in thousands of dollars of a company in a given year t where t represents the number of years since 1980 find the linear function y where y depends on t the number of years since 1980 Y=_

Answers

First we need to find the slope by using two points

(15,190)=(t1,y1)

(25,170)=(t2,y2)

[tex]m=\frac{y_2-y_1}{t_2-t_1}=\frac{170-190}{25-15}=\frac{-20}{10}=-2[/tex]

Then we calculate the y-intercept

[tex]190=-2(15)+b[/tex]

we isolate the b

[tex]b=190+30=220[/tex]

The equation is

[tex]y=-2t+220[/tex]

12. (01.02)
Which function below is the inverse of f(x) = x² - 9?

Answers

FOR EQUATION INVERSES IT MEANS ... x and y swap positions.

[tex]x = (f(x))^{2} - 9 \\ (f(x))^{2} = x + 9 \\ \sqrt{(f(x))^{2} } = \sqrt{x + 9} \\ f(x) = \sqrt{x + 9} [/tex]

ATTACHED IS THE SOLUTION.

An object oscillates as it moves along the
x-axis. Its displacement varies with time
according to the equation
x = 4 sin(pi(t)+ pi/2)
where t = time in seconds and
x = displacement in meters
What is the displacement between t = 0
and t = 1 second?
[?] meters

Answers

It is found that the displacement between t= 0  and t = 1 second is of 0.536 m.

The equation of motion is given by:

x(t) = 4 sin(πt + π/2)

The displacement between t= 0  and t = 1 second is given by:

d = x(1) - x(0)

Hence,

position of the object when t = 1

x(1) = 4sin(π(1) + 1 (π/2))

= 4 sin (π + π/2)

= 4 sin (3π/2)

= 4 x √3/2

= 2√3

= 3.464

position of the object when t = 0

x(0) = 4sin(π(0) + (π/2))

= 4 sin (0 + π/2)

= 4 x 1

= 4

Then,

d = x(1) - x(0)

= 4 - 3.464

= 0.536(approx)

Therefore, the displacement of the object between t = 0 and t = 1 is 0.536.

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Please tell me the answer and how you got the answer (AKA How you solved it) And the first person to give me the correct answer gets marked (Due In 3.5 Minutes)
• Thanks

Answers

Step-by-step explanation:

the range is the interval or set of all valid y (functional result) values.

we see that y goes continuously through every value between +5 (we see no y values bigger than that) and -5 (we see no y values lower than that).

the filled dots also tell us that the end points would be included (if this would be a necessary information - it is not, because the curve reaches +5 and -5 also in between).

so, the range is

-5 <= y <= +5

A street that is 270 ft long is covered in snow. City workers are using a snowplow to clear the street. A tire on the snowplow has to turn 27 times in traveling the length of the street. What is the diameter of the tire?
Use the value 3.14 for π. Round your answer to the nearest tenth. Do not round any intermediate steps.

Answers

If a street that is 270 ft long is covered in snow. City workers are using a snowplow to clear the street. The diameter of the tire is: 3.2 meters.

Diameter of the tire

First step is to determine the circumference of the tire

Circumference of the tire =  (270 m / 27)

Circumference of the tire = 10 meters

Second step is to make use of  3.14 for π to determine the diameter of the tire using this formula

Diameter of the tire = Circumference of the tire /  π

Let plug in the formula

Diameter of the tire = 10 / 3.14

Diameter of the tire = 3.18 meters

Diameter of the tire = 3.2 meters (Approximately)

Therefore 3.2 meters is the diameter.

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Lorena solved the equation 5k – 3(2k – ) – 9 = 0. Her steps are below.

5k – 6k + 2 – 9 = 0
–k – 7 = 0
–k = 7
k = 1/7
Analyze Lorena’s work to determine which statements are correct. Check all that apply.

Answers

Answer: K= -9

Step-by-step explanation:

5k−3(2k)−9=0

Multiply 3 and 2 to get 6.

5k−6k−9=0

Combine 5k and −6k to get −k.

−k−9=0

Add 9 to both sides. Anything plus zero gives itself.

−k=9

Multiply both sides by −1.

k=−9

(Hope this helps)

For the function ​f(x)=x2−9​, find
​(​a)​ f(x+​h),
​(​b)​ f(x+​h)−​f(x), and
​(​c) f(x+h)−f(x) h

​(​a)​ f(x+​h)=

Answers

The value of f(x+​h) is x² + 2xh + h² - 9, the value of f(x+​h)−​f(x) is 2xh + h², and the value of (f(x+h)−f(x))/h is 2x + h.

What is a function?

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The function:

f(x) = x² - 9

(a) f(x + h)

f(x + h) = (x + h)² - 9

f(x + h) = x² + 2xh + h² - 9

​(​b)​ f(x+​h)−​f(x)

= x² + 2xh + h² - 9 - (x² - 9)

f(x+​h)−​f(x)  = 2xh + h²

​(​c) (f(x+h)−f(x))/h

= (2xh + h²)/h

= 2x + h

Thus, the value of f(x+​h) is x² + 2xh + h² - 9, the value of f(x+​h)−​f(x) is 2xh + h², and the value of (f(x+h)−f(x))/h is 2x + h.

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1. How much does it cost to use a yard of ribbon?
#9 satin ribbon
Cost $4.99 per roll
100 yards per roll

Answers

Step-by-step explanation:

You will want to divide the cost of $4.99 by 100, this will give you the cost per yard.

Answer:

$4.99 / 100 = $0.0499

About 5 cents per yard.

Please give thanks, 5 stars, and brainliest answer :)

A toy manufacturer is going to produce a new toy car. each one costs $3 dollars to make and the company will also have spent 200$ to set up the machinery to make them. what will it cost to produce the first hundred cars?ar. each one costs $3 dollars to make and the company will also have spent 200$ to set up the machinery to make them. what will it cost to produce the first hundred cars?

Answers

Answer:

$500

Step-by-step explanation:

Startup cost: $200

Cost of 1 car: $3

Cost of 100 cars: $3 × 100 = $300

$200 + $300 = $500

If the account is overdue, what is the probability that it is new?

Answers

Answer:

we need more info than this

Step-by-step explanation:

Other Questions
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