You are studying a biochemical pathway in the mold Neurospora where enzyme 1 converts the initial substrate into intermediate substrate A; enzyme 2 converts intermediate substrate A into intermediate substrate B; enzyme 3 converts intermediate substrate B into intermediate substrate C; and enzyme 4 converts intermediate substrate C into the end product, an amino acid that is essential for growth. You isolate a mutant that is unable to grow on minimal media. Which data would provide the strongest support for the hypothesis that this mutation occurred in the gene that codes for enzyme 2

Answers

Answer 1

Complete question:

You are studying a biochemical pathway in the mold Neurospora where enzyme 1 converts the initial substrate into intermediate substrate A; enzyme 2 converts intermediate substrate A into intermediate substrate B; enzyme 3 converts intermediate substrate B into intermediate substrate C; and enzyme 4 converts intermediate substrate C into the end product, an amino acid that is essential for growth. You isolate a mutant that is unable to grow on minimal media. Which data would provide the strongest support for the hypothesis that this mutation occurred in the gene that codes for enzyme 2?

a. The mold can grow on rich medium plus intermediate substrate C, but not on rich medium plus intermediate substrate B.

b. The mold can grow on minimal medium plus intermediate substrate B, but not on minimal medium plus the initial substrate.

c. The mold can grow on minimal medium plus intermediate substrate B, but not on minimal medium plus intermediate substrate A.

d. The mold can grow on rich medium plus intermediate substrate D, but not on rich medium plus intermediate substrate C.

e. The mold can grow on minimal medium plus intermediate substrate A, but not on minimal medium plus intermediate substrate C.

Answer:

c. The mold can grow on minimal medium plus intermediate substrate B, but not on minimal medium plus intermediate substrate A.

Explanation:

Let us first diagram the pathway for a better understanding.

The normal organism produces four enzymes that convert substrates in the medium that allow it to survive, grow, and reproduce.  

initial substrate ------------> A ----------------> B ----------------> C ----------------> AA

                           Enzyme 1       Enzyme 2        Enzyme 3         Enzyme 4

Any mutation on the Neurospora´s enzymes will not let the organism grow on the minimal medium because it will not be able to convert the minimal substrate into the following one, because the mutated enzyme will not accomplish its original function.

So if the mutation occurs in enzyme 1, the organism will not be able to convert the initial substrate into intermediate substrate A. And the rest of the reaction will not be possible either because of the lack of substance A.

initial substrate -----X----> A -------X-----> B ------X--------> C ------X-------> AA

          mutated Enzyme 1      Enzyme 2       Enzyme 3        Enzyme 4

If the mutation occurs in enzyme 2, the organism will not be able to convert the intermediate substrate A into intermediate substrate B. And the rest of the reaction will not be possible either because of the lack of substance B.

initial substrate ------------> A -------X--------> B -------X------> C --------X-----> AA

                           Enzyme 1   mutated Enz. 2     Enzyme 3         Enzyme 4

If the mutation occurs in enzyme 3, the organism will not be able to convert the intermediate substrate B into intermediate substrate C. And the last reaction will not be possible either because of the lack of substance C.

initial substrate ------------> A ----------------> B -------X--------> C -------X------> AA

                           Enzyme 1       Enzyme 2     mutated Enz. 3     Enzyme 4

And if the mutation occurs in enzyme 4, the organism will not be able to convert the intermediate substrate C into the essential amino acid.

initial substrate ------------> A ----------------> B ----------------> C -------X-------> AA

                           Enzyme 1       Enzyme 2        Enzyme 3      Mutated Enz. 4

But, if we artificially add to the medium the substrate that should be produced by the original enzyme (and that is not converted because of the mutation), then the organism will grow and survive because the other enzymes will be able to produce the essential amino acid.

So, if enzyme 2 is the only enzyme mutated, the organism will not be able to live in a medium with substrate A because the mutated enzyme will not convert the substrate A into B. There will not be B substrate in the medium, and the other enzymes will not produce the essential amino acid. So if the mutation occurs in enzyme 2, substrate A is useless to the organism because it will not survive.

But if we add the intermediate substrate B to the medium, the organism will survive. In a medium with substrate B, all the other reactions will be possible, and the organism will get the essential amino acid. The artificial addition of B substrate will replace the function of the original enzyme 2 -which is the one that converts A into B-.


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Fish provide polar bears with 10 grams of biomass worth of energy.

What is biomass?

Biomass is defined as a fuel made from organic materials; a sustainable and renewable energy source used to produce electricity or other types of power. Our ecology, economy, and energy security might all be significantly improved by using biomass as a clean, renewable energy source.

According to 10% rule.

1000x10%=100

100x10%=10.

When animals from one trophic level are consumed by organisms from the next trophic level, energy is lost when going from a lower trophic level to a higher trophic level because energy is lost as metabolic heat.

Thus, fish provide polar bears with 10 grams of biomass worth of energy.

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Explanation:The correct option is A

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Explanation of correct option:

Option A

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An illustration comes from Murakami Kijo, a Japanese poet who lived from 1865 to 1938:

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The genetic sequences of sister chromatids are identical. Sister chromatids occur only after the S (synthesis) phase, when the DNA is replicated in preparation for mitosis or meiosis.

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the enzyme(s) called __________ break(s) down the substrate called __________.

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The enzyme(s) called peptidases break(s) down the substrate called proteins.

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Classify each phrase as describing an enzyme, an active site, or a substrate.

a. A biological catalyst
b. A protein containing an active site
c. A specific enzyme location that binds with the substrate
d. A substance that the enzyme acts upon
e. May be a phosphate group

Answers

Since there is where the catalytic "action" takes place, the area of the enzyme where the substrate binds is known as the active site.

These amino acids make it possible for an enzyme's active site to specifically bind to its substrate or substrates and facilitate chemical reactions. An enzyme will cling to (bind) one or more reactant molecules in order to catalyze a process. The substrates of the enzyme are these substances. One substrate may be broken down into several products in some reactions. The products then depart the enzyme's active site.

Enzymes are biological catalysts that quicken a living thing's biochemical reactions. Enzymes don't alter the reaction's equilibrium.

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A proteolytic enzyme cleaves _____ bonds.

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Answer:

A proteolytic enzyme cleaves peptide bonds.

Explanation:

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There are many different types of proteolytic enzymes, each of which has a specific function and target in the body. Some proteolytic enzymes, for example, are specifically designed to break down proteins in the stomach and intestines, while others are involved in the regulation of protein levels in the blood or other tissues.

Proteolytic enzymes play a key role in many biological processes, and their activity is carefully regulated in the body. Imbalances or defects in proteolytic enzymes can lead to a variety of health problems, including digestive disorders, immune system disorders, and neurological disorders.

No recombination of homologs occurs?

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No recombination of homologs occurs in mitosis.

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Mitosis is only found in eukaryotic cells. Prokaryotic cells, which lack a nucleus, divide through a process known as binary fission. Mitosis differs from organism to organism. Animal cells, for example, go through "open" mitosis, in which the nuclear envelope breaks down before the chromosomes separate, whereas fungi go through "closed" mitosis, in which the chromosomes divide within an intact cell nucleus.

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Does point mutation increase DNA?

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The point mutation can lead to an increase in the length of DNA sequences depending upon the type of mutation.

A point mutation is a form of mutation in which one single nucleotide base is added, deleted, or modified in DNA or RNA, the genetic material of the organism. In the case of base substitution length of the DNA sequence remains the same because the nucleotide number remains the same after the substitution. In the case of insertions mutation overall size of the DNA increases due to an increased number of nucleotides whereas decreased in the case of deletion mutations.

Hence, the type of point mutation determines DNA length.

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what happens when the body uses its fat stores to provide tissues with energy during fasting, when there is not enough food energy?

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When the body uses its fat stores to provide tissues with energy during fasting, a process called lipolysis occurs. Lipolysis is the breakdown of stored fat into fatty acids and glycerol, which can then be used by the body for energy. The fatty acids are broken down further into molecules called ketone bodies, which can be used by the body for energy.

when the body uses its fat stores to provide tissues with energy during fasting Fat cells release fatty acids into the blood by breaking down stored fat.

The activation of hormone-sensitive lipase (HSL) is the first step in the breakdown of triglycerides. During fasting, plasma levels of glucagon, epinephrine, growth hormone, and cortisol all rise, stimulating this enzyme. HSL is triggered by each of these hormones in a different way. Cyclic AMP is produced when glucagon and epinephrine bind to adenylyl cyclase on the cell membrane. Protein kinase A (PKA), which in turn activates HSL, is triggered by cyclic AMP. The glucocorticoid receptor alpha (GR-alpha) in the cell's cytosol is where cortisol binds.

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What is non homeostatic?

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Consuming certain foods or minerals in proportions that do not support health is known as non-homeostatic eating (i.e., disproportional to need). Understanding the neurobiology behind excessive intake of fat and sugar has been the subject of a lot of research.

Non-homeostatic mechanisms include learning, memory, and cognitive processes that can affect feeding based on previously learned experiences and hedonic aspects of food, in contrast to homeostatic mechanisms, which regulate feeding in response to general energy deficit or other types of metabolic need.

The opposite of equilibrium The salt content of ocean waves remains constant. Example of Environmental Response. A chameleon changing their color to their environment.

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there are ___ levels of structural organization within the body.

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There are Six distinct levels of structural organization within the body.

The smallest components of matter, such as atoms and molecules, are taken into consideration by scientists while studying the chemical level of organisation. The elements, which include elements like hydrogen, oxygen, carbon, nitrogen, calcium, and iron, are the building blocks of all matter in the universe. Each of these unadulterated substances (elements) has an atom as its smallest unit. Subatomic particles like the proton, electron, and neutron are the building blocks of atoms. Molecules, like the ones found in water, proteins, and carbohydrates in living things, are made up of two or more atoms. All of the components of the human body are composed of molecules.

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All animal cells are diploid except

options:



gametes.



muscle cells.



nerve cells.



germ-line cells.



somatic cells.

Answers

Except for gametes, all mammal cells are diploid.

With the exception of the gametes, almost all animal cells are diploid, however some are polyploid (three or more copies of each chromosome, often found in plants). The human genome has 46 diploid chromosomes, which is twice as many as the 23 haploid chromosomes found in human ova and sperm.

From the Greek term meaning "double," a cell or organism with two sets or copies (or homologs), typically one from each parent and so twice the number of haploids, of each somatic chromosome.

The right response is (a) gametes. In contrast to diploid cells, which have two sets of chromosomes, haploid cells only have one set.

Due to the fusing of two haploid gametes, all mammals are diploids genetically. The haploid gamete cells make sure that the amount of chromosomes or genetic material is constant from generation to generation.

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Which of the following is most like the formation of identical twins? A) cell cloning. B) therapeutic cloning. C) use of adult stem cells.

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The right answer is (A), which states that cloning is most similar to the development of identical twins.

Cloning, which can be done via artificial or natural methods, is the act of generating unique beings with DNA that is identical or very similar. In the field of biotechnology, cloning is the process of creating organisms (copies) from cells and DNA fragments (molecular cloning). In addition to amplifying DNA segments that contain whole genes, cloning can be used to amplify any DNA sequence, including promoters, non-coding sections, and randomly fragmented DNA. It is used in a number of biological research projects and practical applications, including as mass protein production and the creation of genetic fingerprints. The process of figuring out the chromosomal location of a gene connected to an important feature, such as in positional cloning, is sometimes misleadingly referred to as "cloning." Despite the fact that a gene has been mapped to a certain chromosomal or genomic region, one cannot always extract or amplify the relevant genomic sequence.

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Eukaryotic processing of the primary transcript includes __________.

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The main transcript is processed by eukaryotes by splicing out introns and adding a 5 cap and 3 poly-A tail.

The harder part comes first. Termination does not involve stem-loop structures. Three enzymes carry out transcription (RNA polymerases I, II and III).Transcription is more tightly regulated in prokaryotes. In eukaryotes, translation begins when mRNA leaves the nucleus and begins transcription inside the nucleus. RNA polymerase is directed to start producing RNA by a promoter site on the 5' side of the transcriptional start site. The RNA polymerase transcribes the sense (-) strand of the DNA template.

In eukaryotes, the original RNA transcript is converted into mRNA by a process called maturation.

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