[tex]speed_{avg} = \frac{Σ\:distance}{ total\: time}[/tex]
So, according to the question:
distance = 90 miles
time = 1h 45min + 15 min + 1h = 3h
[tex]Therefore:\\ speed_{avg} = \frac{90}{3} mph \\ = \boxed {30 \: mph}[/tex]
A 6.20-kg steel ball at 27.7°C is dropped from a height of 21.7 m into an insulated container with 4.50 L of water at 10.1°C. If no water splashes, what is the final temperature of the water and steel? The specific heat of steel and water is 450J / (kg - K) and 4186J / (kg - K) respectively.
The final temperature of the water and steel mixture after the steel is dropped is determined as 7.12 ⁰C.
Conservation of energy
From the principle of conservation of energy, the energy lost by the steel ball is equal to the energy gained by the water.
P.E(steel) - Thermal(steel) = Thermal(water)
mgh - mcΔθ = mcΔθ
where;
mass of water = density x volume = 1 kg/L x 4.5 L = 4.5 kg(6.2)(9.8)(21.7) - (6.2)(450)(27.7 - T) = (4.5)(4186)(T - 10.1)
1,318.492 - 77,283 + 2790T = 18,837T - 190,253.7
114,289.192 = 16,047T
T = 7.12 ⁰C
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3. What is the distance between New York and London, if an airplane flying at 580 Km per hour takes 7 hours to complete the trip?
Answer:
4060 km
Explanation:
580 km/hr * 7 hr = 4060 km
rate * time = distance
Which circuit contains the smallest voltage?
- A circuit with a current of 20amps and a resistance of 15 ohms?
- A circuit with a current of 10 amps and a resistance of 10 ohms?
- A circuit with a current of 25 amps and a resistance of 10 ohms?
- A circuit with a current of 20 amps and a resistance of 10 ohms?
Answer:
10 amps 10 ohms ( 100 v)
Explanation:
Voltage = current * ohm
the smallest of those listed is 10 amps 10 ohms
Where would sound NOT be
able to travel?
A. through the ground
B. through the ocean
C. through the air
D. through outer space
A 3 kg toy plane is attached to a 1.8 m string that it can be whirled around in a horizontal circle above the users head. If one’s exerts a force of 10 N on the string, what speed should the plane have as it rotates
With the use of formula, The plane should rotate at the speed of 3 m/s
Circular MotionWhen a body is moving rotationally at a point, the motion is said to be a circular motion. There are two types of motion in a circle
Vertical circular motionHorizontal circular motionGiven that a 3 kg toy plane is attached to a 1.8 m string that it can be whirled around in a horizontal circle above the users head rotates.
The given parameters are:
mass m = 3 kg
Length L = 1.8 m = radius
Force F = 10 N
Velocity V = ?
If one’s exerts a force of 10 N on the string, The speed the plane should have can be calculated by using the below formula
F = M[tex]V^{2}[/tex] / r
Substitute all the parameters into the formula
10 = 3 x [tex]V^{2}[/tex] / 1.8
Cross multiply
18 = 3[tex]V^{2}[/tex]
[tex]V^{2}[/tex] = 18/3
[tex]V^{2}[/tex] = 9
V = [tex]\sqrt{9}[/tex]
V = 3 m/s
Therefore, The plane should rotate at the speed of 3 m/s
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In the early 1960s , Cuban anti-communist rebels with the assistance of the United States . Sought to regain control on Cuba from Fidel Castro . This failed military action was called what?
I NEED HELP WILL MARK YOU BRAINLIEST
Answer:
Here is the answer
Here is the answerExplanation:
Here is the answerExplanation:Bay of Pigs Invasion is the answer
An object of mass 20 kg is raised vertically through a distance of 8 m above ground level. If g = 10 m/s2, what is the gravitational potential energy of this object at this position?
Answer:
1600 joules
Explanation:
Potential Energy = m * g * h
= 20 kg * 10 m/s^2 * 8 m = 1600 J
when an Earthquake occurs energy radiates in all direction from its source called the
Answer:
[tex]\huge\boxed{\sf Focus}[/tex]
Explanation:
Focus:The point at which Earthquake occurs is called Focus.It is also called hypocenter.Epicenter:Epicenter is the point on the Earth surface which is just above the focus.Most of the times, epicenter is confused with focus. However, epicenter lies on the Earth surface and focus is the exact point from where the Earthquake originates.
[tex]\rule[225]{225}{2}[/tex]
Describe the population density located along the tectonic plate boundary known as the Ring of Fire and the potential effect that earthquakes or volcanic
activity can have in this area.
Answer:
Seventy-five percent of Earth's volcanoes—more than 450 volcanoes—are located along the Ring of Fire. Ninety percent of Earth's earthquakes occur along its path, including the planet's most violent and dramatic seismic events.
please mark brainliest :)
An 845–g bar of ice is initially at –25 °C. The latent heat of fusion of ice is 334 kJ/kg, the specific heat of ice is 2050 J/(kg·°C), and the specific heat of water is 4180 J/(kg·°C). Determine how much energy is required if the final temperature of the system is to reach 39 °C.
Taking into account the definition of calorimetry, sensible heat and latent heat, the amount of heat required is 463.28 kJ.
Calorimetry, sensible heat and latent heatCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
Latent heat is defined as the energy required by a quantity of substance to change state.
When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.
Energy required in this case-25°C to 0 °CIn firts place, the melting point of water (temperature at which it changes state from solid to liquid) is 0°C.
So, first of all you must increase the temperature from -25 ° C (in solid state) to 0 ° C, in order to supply heat without changing state (sensible heat).
The amount of heat a body receives or transmits is determined by:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
c(ice)= 2050 [tex]\frac{J}{kgC}[/tex] m= 845 g= 0.845 kgΔT= Tfinal - Tinitial= 0 °C - (-25) °C= 25 °CReplacing:
Q1= 2050 [tex]\frac{J}{kgC}[/tex] × 0.845 kg× 25 °C
Solving:
Q1= 43,306.25 = 43.3 kJ
Change of stateThe heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to
Q = m×L
where L is called the latent heat of the substance and depends on the type of phase change.
In this case, you know:
n= 0.845 kgΔHfus= 334 [tex]\frac{kJ}{kg}[/tex]Replacing:
Q2= 0.845 kg× 334[tex]\frac{kJ}{kg}[/tex]
Solving:
Q2= 282.23 KJ
0 °C to 39 °CSimilar to sensible heat previously calculated, you know:
c(liquid)= 4180[tex]\frac{J}{kgC}[/tex]m= 0.845 kgΔT= Tfinal - Tinitial= 39 °C - 0 °C= 39 °CReplacing:
Q3= 4180 [tex]\frac{J}{kgC}[/tex] × 0.845 kg× 39 °C
Solving:
Q3= 137,751.9 J= 137.75 kJ
Total heat requiredThe total heat required is calculated as:
Total heat required= 43.3 kJ + 282.23 kJ + 137.75 kJ
Total heat required= 463.28 kJ
In summary, the amount of heat required is 463.28 kJ.
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The amount of energy required if the final temperature of the system is to reach 39 °C is 463288.15 J
How to determine the heat required change the temperature from –25 °C to 0 °C Mass (M) = 845 g = 845 / 1000 = 0.845 KgInitial temperature (T₁) = –25 °C Final temperature (T₂) = 0 °Change in temperature (ΔT) = 0 – (–25) = 25 °C Specific heat capacity (C) = 2050 J/(kg·°C) Heat (Q₁) =?Q = MCΔT
Q₁ = 0.845 × 2050 × 25
Q₁ = 43306.25 J
How to determine the heat required to melt the ice at 0 °Mass (m) = 0.845 KgLatent heat of fusion (L) = 334 KJ/Kg = 334 × 1000 = 334000 J/KgHeat (Q₂) =?Q = mL
Q₂ = 0.845 × 334000
Q₂ = 282230 J
How to determine the heat required to change the temperature from 0 °C to 39 °C Mass (M) = 0.845 KgInitial temperature (T₁) = 0 °C Final temperature (T₂) = 39 °Change in temperature (ΔT) = 39 – 0 = 39 °C Specific heat capacity (C) = 4180 J/(kg·°C)Heat (Q₃) =?Q = MCΔT
Q₃ = 0.845 × 4180 × 39
Q₃ = 137751.9 J
How to determine the heat required to change the temperature from –25 °C to 39 °CHeat for –25 °C to 0°C (Q₁) = 43306.25 JHeat for melting (Q₂) = 282230 JHeat for 0 °C to 39 °C (Q₃) = 137751.9 JHeat for –25 °C to 39 °C (Qₜ) =?Qₜ = Q₁ + Q₂ + Q₃
Qₜ = 43306.25 + 282230 + 137751.9
Qₜ = 463288.15 J
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7
8
What happens when the thermal energy of a substance increases?
O The motion of the particles in the substance increases, and the temperature of the substance decreases.
O The motion of the particles in the substance decreases, and the temperature of the substance increases.
O Both the motion of the particles in the substance and the temperature of the substance decrease.
O Both the motion of the particles in the substance and the temperature of the substance increase
Answer:
D
Explanation:
it is because when the thermal energy increases the particles move faster and the temperature increases.
Why is nuclear energy able to be used for practical purposes? the reactions are controlled to regulate energy output. the reactions are uncontrolled for maximum energy output. all of the products are fed back into the reaction to keep it going. all of the products are immediately removed to inhibit more reactions.
Nuclear energy is able to be used for practical purposes because ; ( A ) The reactions are controlled to regulate energy output
Nuclear energy generationNuclear energy is a clean energy source which has a zero-emission, nuclear energy is used to generate electricity/power following a controlled reaction known as fission of uranium atoms to produce heat energy required to drive a turbine to produce electricity
Hence we can conclude that Nuclear energy is able to be used for practical purposes because ; ( A ) The reactions are controlled to regulate energy output.
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Answer:
option A
Explanation:
Which of the following is a characteristic of a balanced force?
1) equal in size opposite in direction
2) causes a change in the direction of an object
3) causes a change in the motion of an object
What do you like MOST about your chosen learning modality
The farther away you are from a light source, the _____ intense it appears
Answer:
The answer is Less.
Explanation:
The further you are away from a light source, the less intense the light appears.
A satellite with a mass of 150 kg fires its engines to increase velocity, thereby
increasing the size of its orbit about Earth. As a result, it moves from a
circular orbit of radius 7.5 x 106 m to an orbit of radius 7.7 x 106 m. What is
the approximate change in gravitational force from Earth as a result of this
change in the satellite's orbit? (Recall that Earth has a mass of 5.97 x 1024 kg
and G = 6.67 x 10-11 N-m²/kg².)
OA. -113 N
OB. -148 N
O C. -216 N
D. -54 N
The approximate change in gravitational force from Earth as a result of the change in radius of the satellite's orbit is 5. 35N
What is the universal law of gravitation?The universal law of gravitation states that the particle of matter in the universe attracts another particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
It is written thus;
F = G MIM2÷ r∧2
Where
F = Gravitational force
G = Gravitational constant
M1 and M2 are the masses of the object
r = radius
How to calculate the gravitational forceFormula:
F = G MIM2 ÷ r∧2
Given M1 = 150kg, M2 = 5.97 x 1024 kg, r = 7.5 x 106 m, G = 6.67 x 10-11 N-m²/kg²
For the first orbit, substitute the values
F = 6.67 x 10∧-11 × 150 × 5.97 x 10∧24 ÷ (7.5 x 10∧6)²
F = 5.95 × 10∧16 ÷ 56.25 × 10∧12 = 105.77 N
For the second orbit of radius 7.7 x 106 m
F = 6.67 x 10∧-11 × 150 × 5.97 x 10∧24 ÷ (7.7 x 10∧6)²
F = 5.95 × 10∧16 ÷ 59.25 × 10∧12 = 100. 42 N
The approximate change = 105. 77 - 100.42 = 5. 35N
Hence, the approximate change in gravitational force from Earth as a result of the change in radius of the satellite's orbit is 5. 35N
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1. The sketch shows two 4 kg blocks on a horizontal surface, joined by a string S. They are attached to a 2 kg mass by another string which passes over a frictionless pulley, allowing the 2 kg mass to hang freely. Each of the blocks experiences 6 N of friction.
a) Show that the system accelerates to the right at 0.8 m/s². Calculate the tension in string S.
b) 4 kg S 4 kg 2 kg [4] [4]
Answer:
M g - T = M a acceleration of hanging block (M = 2)
2 g - T = 2 a where M = 2
T = 2 g - 2 a
T = 8 * a + 12 N acceleration of blocks on table
2 g - 2 a = 8 a + 12
10 a = 2 g - 12
a = .8 m/s^2 (assuming g = 10 m/s^2)
T = 2 g - 2 a = 2 * 10 - 2 * .8 = 20 - 1.6 = 18.4 N
Check: For blocks on table
a = (18.4 - 12) / 8 = 6.4 / 8 = .8 m/s^2
If 20 coulombs of charge move past a given point in 4 s, what is the current?
Answer:
5A
Explanation:
[tex]=> Current (I) = \frac{q}{t} [/tex]
Here q = 20 C and t = 4sec
=> I = 20/4 = 5A
Consider an object of mass 2kg on a ramp with βs=0.5 and βk=0.4.
If we keep increasing the ramp angle, what is the angle() that the object starts to move downward? Give your answer in degree with 1 decimal place.
Answer:
bs angle will move in 1.5
A 95kg fullback was running downfield at 8m/s. A defensive player (110kg) was running upfield at 6m/s straight at the fullback. What was the momentum of each player before they impacted?
A)Fullback: 760kgm/s, Defender: 660kgm/s
B)Fullback: 760kgm/s, Defender: -660kgm/s
C)Fullback: 570kgm/s, Defender: 880kgm/s
D) Fullback: 570kgm/s, Defender: -880kgm/s
A 95 kg fullback was running downfield at 8 m/s. A defensive player (110 kg) was running upfield at 6 m/s straight at the fullback. The momentum of each player before they impacted Fullback 760 kgm/s, Defender: 660 kgm/s.
What is impulse?In classical mechanics, the integral of a force, F, over the time period over which it acts, t, is referred to as the "impulse." Impulse is a vector quantity because force is one as well. When an item receives an impulse, it experiences an equivalent vector change in its linear momentum and also in the direction that results.
momentum = mass *velocity
momentum = 95*8 = 760 kg-m/sec Fullback
momentum = 110*6 = 660 kg-m/sec Defender
A 95 kg fullback was running downfield at 8 m/s. A defensive player (110 kg) was running upfield at 6 m/s straight at the fullback. The momentum of each player before they impacted Fullback 760 kgm/s, Defender: 660 kgm/s.
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5 postulates of neil bohr atomic model
Answer:
What is Bohr’s Model of an Atom?
The Bohr model of the atom was proposed by Neil Bohr in 1915. It came into existence with the modification of Rutherford’s model of an atom. Rutherford’s model introduced the nuclear model of an atom, in which he explained that a nucleus (positively charged) is surrounded by negatively charged electrons.
A student repeats a reaction several times to test the effects of various
changes on the reaction rate. The data table shows the results. How does
increasing the temperature of the system change thereaction rate?
A. Increasing the temperature decreases the reaction rate.
B. Increasing the temperature increases the reaction rate.
C. More information is needed to determine what happens to the reaction rate.
D. Increasing the temperature has no effect on the reaction rate.
Answer:
B. Increasing the temperature increases the reaction rate.
Explanation:
This is as with a higher temperature the particles have more kinetic energy, this is the consequece of the increase in reaction rate as the frequency of particles colliding is increased.
Answer: B
Explanation:
10. As a pharmacy technician, you will receive prescription orders with many different abbreviations, which will require conversions to calculate the dose. Now that you have learned about conversions and abbreviations, what would you do to fill a prescription with abbreviations? Also, what would you do with conversions you were not sure how to convert to the required dose. Explain
When you receive prescriptions that contain some abbreviations, you have to translate it into plain language that the patient can understand.
Who is a pharmacy technician?A pharmacy technician is a skilled personnel who assists a pharmacist in a health facility. The pharmacy technician usually writes out prescriptions for patients.
When you receive prescriptions that contain some abbreviations, you have to translate it into plain language that the patient can understand. If you are not clear about the abbreviation you can ask the pharmacist for help or the doctor.
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HELP MEEE!!!!!!!!!
A series circuit is made up of a battery and 4 Resistors.
The Resistors are:
R1 = 10 ohms
R2 = 20 ohms
R3= 5 ohms
R4= 10 ohms
What is the total resistance in the circuit is...
ohms
A triangular prism made of crown glass (n=1.52) with base angles of 30.0 is surrounded by air. If parallel rays are incident normally on its base as shown in fig., what is the angle of ϕ between the two emerging rays?
Answer:
es lo que es
Explanation:
es lo que es es que slep vaka vee
the angle ϕ= will be equal to angle of refraction and it is equal to 49.4°C.
What is refractive index ?When a light is going from medium 1 to medium 2. The refractive index is defined as a ratio of velocity of light in medium 1 to velocity of light in medium 2. Refractive index is the factor which deals with the amount of bending of light. More refractive index means more it will bend in the medium 2. When it is 1 we can say that light has not been bent.
By Snell's law, Refractive index is given by,
sin (i) ÷ sin (r) = μ₂÷μ₁
where i is the the angle of incidence
r is the angle of refraction
μ₂ & μ₁ are refractive index of medium 2 and 1 resp.
Hence it is due to Refractive index.
In this problem the light is going from prism to air, the refractive index of air is 1. From figure it is clear that the angle of incidence is 30°C.
From snell's law,
sin (30) ÷ sin (r) = μ₂÷1.52
0.5 ÷ sin (r) = 1÷1.52
0.5×1.52 = 1×sin (r)
0.76 = sin (r)
The angle of refraction r = sin⁻¹(0.76) =49.4°C
Hence angle ∅ = 49.4°C.
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Determine the CM of the uniform thin L-shaped construction brace shown in (Figure 1) . Suppose that a = 2.20 m and b = 1.63 m Determine the x coordinate of the CM
By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is [tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex] meters.
How to determine the coordinates of the center of mass of a compound figure
Let suppose that the entire construction has a uniform mass, then the coordinates of the center of mass can be determined by definition of weighted average:
[tex]\bar x = \frac{\sum \limits_{i = 1}^{n}x_{i}\cdot m_{i}}{\sum \limits_{i=1}^{n}m_{i}}[/tex] (1)
[tex]\bar y = \frac{\sum \limits_{i = 1}^{n}y_{i}\cdot m_{i}}{\sum \limits_{i=1}^{n}m_{i}}[/tex] (2)
If we know that a = 2.20 m and b = 1.63 m, then the x-coordinates of the center of mass of the compound figure is:
[tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex]
By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is [tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex] meters.
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What is the purpose of an acid-base titration?
Answer:
the detection of the equivalence point, the point at which chemically equivalent amounts of the reactants have been mixed.
a) First write down what you see in the picture.
Answer:
which picture please,I don't get you
A stationary sound waves has a series of nodes. The distance between the first and the 6th node is 30cm. What is the wavelength of the sound wave
Answer:
Assume a node at the left end and the right end
N-A-N-A-N-A-N-A-N-A-N shows nodes and anti-nodes
10 quarter wavelengths are shown (or 2.5 wavelengths)
30 / 2.5 = 12 cm wavelength since there is 1/4 wavelength between node and anti-node
Nodes and anti-nodes are displayed in N-A-N-A-N-A-N-A-N.
The difference between the node and the anti-node exists 12 cm wavelength.
What is meant by stationary sound waves?Standing waves are created when two identical waves move in opposition to one another along a line. Despite being composed of two waves that are moving in opposition to one another, standing waves do not travel through space or along a string.
A wave that is stationary is one that is not moving, is at a standstill, or is in a relaxed position. A standing wave is created whenever two waves with nearly identical frequencies, wavelengths, and amplitudes that are traveling in opposite directions collide.
A waveform signal that is carried in space or down a wire has a wavelength, This is the distance between two identical locations (contiguous crests) in the following cycles. This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm).
The distance over which a periodic wave's shape repeats is known as the wavelength in physics.
Assume that there exists a node at both the left and right ends.
Nodes and anti-nodes are displayed in N-A-N-A-N-A-N-A-N.
it displays 10 quarter wavelengths.
Since there exists a 1/4 wavelength difference between the node and the anti-node, 30 / 2.5 = 12 cm wavelength.
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When you are making cold calls while job hunting, be
o 20 minutes early
O on time
O prepared with a résumé and cover letter
O casual
Answer:
The answer is O prepared with a résumé and cover letter
Explanation:
That will get you very far if you are prepared with a résumé and cover letter