Answer:
See Explanation
Explanation:
At the anode;
Zn(s) -----> Zn^2+(aq) + 2e
At the cathode;
Cu^2+(aq) + 2e ------> Cu(s)
Overall electrochemical reaction;
Zn(s) + Cu^2+(aq) ------> Zn^2+(aq) + Cu(s)
E°cell = E°cathode - E°anode
E°cell = 0.34 - (-0.76)
E°cell = 1.1 V
Q = [0.3 M]/[0.5 M]
Q = 0.6
From Nernst equation;
Ecell = E°cell - 0.0592/n log Q
Ecell = 1.1 - 0.0592/2 log (0.6)
Ecell = 1.1 - 0.0296 log (0.6)
Ecell = 1.11 V
A chemist needs to determine the concentration of a solution of nitric acid, HNO3. She puts 905 mL of the acid in a flask along with a few drops of indicator. She then slowly adds 0.200 M Ba(OH)2 to the flask until the solution turns pink, indicating the equivalence point of the titration. She notes that 235 mL of Ba(OH)2 was needed to reach the equivalence point.
Required:
a. How many moles of Ba(OH)2 are present in 225 mL of 0.200 M Ba(OH)2?
b. How many moles of HNO3 are present if 4.50 x 10^2 mol of Ba(OH)2 was needed to neutralize the acid solution? (Express your answer numerically in moles)
Answer:
See explanation
Explanation:
The equation of the reaction is;
2HNO3(aq) + Ba(OH)2(aq) -------->Ba(NO3)2(aq) + 2H2O(l)
a) The number of moles of Ba(OH)2 = 225/1000 * 0.200
= 0.045 moles
From the reaction equation;
2 moles of HNO3 require 1 mole of Ba(OH)2
x moles of HNO3 require 4.50 x 10^2 mol of Ba(OH)2
x = 4.50 x 10^2 * 2/1
x = 9 x 10^2 moles of HNO3
What was the purpose of letting the transformed cells sit in LB for a few minutes before spreading them onto the plates?
A. This allows time for the cells to express the antibiotic resistance gene
B. This allows the cells to take up the plasmid after the heat shock procedure
C. This allows time for the cells to warm up before plating
D. This allows cells time to start glowing green
How many moles are in 6 x 10^23 molecules of H2O
I will mark brainliest plz help me!!!
What kind of weather forms with an occluded front?
Which of these would a mechanical engineer do?
Answer:
I dont see the answers
Explanation:
Consider the reaction, C2H4(g) + H2(g) - C2H6(8), where AH = -137 kJ. How many kilojoules are released when 3.5 mol of CH4
reacts?
480 kJ are released
20 x 103 kJ are released
570 kJ are released
137 kJ are released
Answer: 480 kJ of energy is released when 3.5 mol of [tex]C_2H_4[/tex] reacts.
Explanation:
The balanced chemical reaction is:
[tex]C_2H_4(g)+H_2(g)\rightarrow C_2H_6(g)[/tex] [tex]\Delta H=-137kJ[/tex]
Thus it is given that the reaction is exothermic (heat energy is released) as enthalpy change for the reaction is negative.
1 mole of [tex]C_2H_4[/tex] on reacting gives = 137 kJ of energy
Thus 3.5 moles of [tex]C_2H_4[/tex] on reacting gives = [tex]\frac{137}{1}\times 3.5=480 kJ[/tex] of energy
Thus 480 kJ of energy is released when 3.5 mol of [tex]C_2H_4[/tex] reacts.
BIOCR
1 Co
> Co
Answer the question below. Use the rubric in the materials for help if needed.
>
Describe the process used to determine how many atoms of each element are in 2Ca3(PO4)2. Show all
your work.
Answer:
Six atoms of calcium, four of phosphorous and sixteen of oxygen for a total of twenty six
Explanation:
Hello there!
In this case, according to the molecular formula of the two moles of calcium phosphate:
[tex]2Ca_3(PO_4)_2[/tex]
Thus, in order to calculate the atoms of each atom, it is necessary to multiply the two in front of the formula by the subscripts in the reaction:
[tex]atoms Ca=2*3=6\\\\atoms P=2*2=4\\\\atoms O=2*2*4=16[/tex]
Thus, we obtain six atoms of calcium, four of phosphorous and sixteen of oxygen for a total of twenty six.
Best regards!
What causes the lines in the spectrum for elements
Glucose and alcohol Contain hydrogen
but they are not adds Why?
Answer:
Ans. Alcohols and glucose though contain hydrogen but do not ionise in the solution to produce H+ ions. This is proved by the fact that there solutions do not conduct electricity.
I need help pls!!!!
Answer:
A
Explanation:
jsgsnsbnss care about explaimi
suppose you are analyzing an antacid that contains Mg(OH)2 and Al(OH)3 in a 1:1 molar ratio. The antacid was neutralized with an excess of 0.500 M HCl, and the excess HCl was then back titrated with 0.500 M NaOH. The following data was obtained: Volume of 0.500 M HCl utilized: 38.25 mL Volume of 0.500 M NaOH utilized: 3.60 mL Calculate the masses of Mg(OH)2 and Al(OH)3 contained in the antacid.
Answer:
0.202g of Mg(OH)₂ and 0.270g of Al(OH)₃
Explanation:
The OH⁻ ions of the Mg(OH)2 and Al(OH)3 reacts with the HCl. The HCl in excess reacts with the NaOH. To solve this question we must find the moles of HCl that react in the beginning with the antiacid and as the ratio is 1:1 we can find the moles of Mg(OH)2 and Al(OH)3. The reactions are:
OH⁻ + HCl → Cl⁻ + H₂O
HCl + NaOH → NaCl + H₂O
Moles HCl added:
0.03825L * (0.500mol / L) = 0.019125 moles
Moles NaOH utilized:
0.0036L * (0.500mol / L) = 0.0018 moles
Moles HCl that react = Moles OH⁻ in the antiacid
0.019125 moles - 0.0018moles =
0.017325 moles OH⁻ in the antiacid
As the ratio is 1:1. the moles Mg(OH)2 = Moles Al(OH)3
And these 5 hydroxides produce 0.017325 moles:
5X = 0.017325 moles
X = 3.465x10⁻³ moles
Where X are moles of both Mg(OH)2 and Moles Al(OH)3
Mass -Molar mass: 58.3197 g/mol-:
3.465x10⁻³ moles * (58.3197g/mol) =
0.202g of Mg(OH)₂And
Mass -Molar mass: 78g/mol-:
3.465x10⁻³ moles * (78g/mol) =
0.270g of Al(OH)₃Is lighting a match a chemical change?
Answer:
yes
Explanation:
Lighting a match and letting is burn is an example of a chemical change.
Matches use sulfur, phosphate and a friction agent held together by a binding agent. Together, the oxygen and sulfur burn slowly, igniting the wood of the match for a flame that lasts long enough to see by, light a candle or ignite a campfire.
A 38.22 mL aliquot of weak acid that has a concentration of 0.882 M will be titrated with 0.289 M NaOH. Calculate the pH of of the solution upon neutralization of half of the weak acid. The Ka of the acid is 6.8×10-7.
Answer:
pH = 6.167
Explanation:
The weak acid, HX, reacts with NaOH as follows:
HX + NaOH → NaX + H₂O
Where 1 mole of HX with 1 mole of NaOH produce 1 mole of NaX (The conjugate base of the weak acid).
Now, using H-H equation:
pH = pKa + log [NaX] / [HX]
Where pH is the pH of the buffer
pKa is -log Ka = 6.167
And [NaX] [HX] are the molar concentrations of each specie
Now, at the neutralization of the half of HX, the other half is as NaX, that means:
[NaX] = [HX]
And:
pH = pKa + log [NaX] / [HX]
pH = 6.167 + log 1
pH = 6.167 What can you infer about the air pressures over the land and ocean? Explain your answer.
Answer:
Answer: During the day, the sun heats up both the ocean surface and the land. ... The wind will blow from the higher pressure over the water to lower pressure over the land causing the sea breeze. The sea breeze strength will vary depending on the temperature difference between the land and the ocean.
Explanation:
Which compound contains three elements?
A. Aluminium chloride
B. iron(III) oxide
C. potassium oxide
D. sodium carbonate
Answer:
Sodium Carbonate
Explanation:
Sodium carbonate is made of three elements, that are, sodium, carbon and oxygen.
Its formula is Na2CO3.
Hope it helps:)
What is the highest occupied level of Carbon
Answer:
Highest occupied level of carbon is 3
Explanation:
its called Alkynes
Explanation:
4trust me!#carryonlearning❤The half-life of argon-39 is 269 years. It decays into krypton-39. After 1,076 years, what fraction of the original amount of argon-
1/16
1/4
1/2
1/8
Answer:
The correct answer is - 1/16.
Explanation:
The half-life is the time that is required to decay nuclei to the half amount of its original amount in a radioactive sample. It is represented by the t1/2. The time that is required to reduce to half of its initial value is known as the half-life of a particular sample.
Half-life of argon-39 = 269 years
total time is taken in complete decay = 1076 years
Number of half-lives required = 1076/269
= 4
So the original amount of the sample = (1/2)^n
n = number of half-life
= 1/2^4
= 1/16
The correct answer is = 1/16
Is a cold and b is warm? Please help
Answer:
Label A shows cold area on the mug, while label B shows a warm area.
Explanation:
Have a good day
Use the Gizmo to mix 200 g of copper at 100 °C with 1,000 g of water at 20 °C. Record the data and calculated answers for copper in the 2 tables below. Accepted values for % error calculations can be found below these 2 tables.
DATA
Copper
Lead
Mass of Metal
Initial Temperature of Metal
Mass of Water
Initial Temperature of Water
Final Temperature of Water
CALCULATIONS
Copper
Lead
Temperature Change of Water
Heat Gained by Water
Heat Lost by Metal
Temperature Change of Metal
Specific Heat of Metal
% Error
Use the Gizmo to mix 200 g of lead at 100 °C with 1,000 g of water at 20 °C. Record the data and answers to the calculations for lead in the 2 tables above.
Metal
Accepted Specific Heat (J/g⁰C)
aluminum
0.900
lead
0.160
copper
0.385
tin
0.228
steel
0.460
Insert a picture of your work for the calculations table here.
Answer:
Explanation:Use the Gizmo to mix 200 g of copper at 100 °C with 1,000 g of water at 20 °C. Record the data and calculated answers for copper in the 2 tables below. Accepted values for % error calculations can be found below these 2 tables.
DATA
Copper
Lead
Mass of Metal
In what direction does thermal energy transfer?
Answer:
Either direction
Explanation:
If you cook food it would go from cold to hot. If you were to put a drink in the fridge it would go from hot to cold. So it is either direction.
Use mass-mass calculation, determine how many grams of sodium chloride SHOULD have been produced from the amount of sodium bicarbonate in mass (B.)
Answer:
where is the question???
Which of the following would be considered renewable resources? You may choose more than one.
oil
corn
clean air
forests
Answer:
clean air
Explanation:
The air temperature in a sealed, insulated box.. 20°C An ice cube at O'C is
placed in the box where it slowly melts. How and why does the melting of the ice
affect the air temperature in the box?
Melting is endothermic so the air temperature increases
Melting is exothermic, so the air temperature decreases
Melting is endothermic, so the air temperature decreases
Melting is exothermic, so the air temperature increases
Answer:
Melting is endothermic, so the air temperature decreases.
Explanation:
Hello there!
In this case, according to the given statement, it is possible to infer that the ice is melt because energy is applied to the ice and thereafter its temperature increases; this is possible because the joined particles of a solid substance need energy to undergo such a separation that they become more far away to each other and therefore transcend to the liquid phase due to the new molecules arrangement. Thus, the answer is Melting is endothermic, so the air temperature decreases because as the ice heats up, the air cools down as it gives it energy to the ice.
Best regards!
A gas cylinder is filled with 5.50 moles of oxygen gas at 83°C. The piston is compressed to yield a pressure of
400.0 kPa. What is the volume inside the cylinder?
Answer:
volume=0.04322m3
Explanation:
acording to ideal gas equation that PV=nRT
What's a household item that has  electrical energy
Answer:
Washing machine.
Dryer.
Television.
Cell phone.
Explanation:
Answer:
Washer and dryer, TV, Cell phone
Explanation:
Need help is label a warm area or is b Orr are they both warm
Answer:
your image is a blavk screen so we cant tell
Explanation:
1.20×10−8s to nanoseconds
Answer:
There are 12 nanoseconds in [tex]1.2\times 10^{-8}\ s[/tex].
Explanation:
We need to convert [tex]1.2\times 10^{-8}\ s[/tex] to nanoseconds.
We know that,
[tex]1\ s=10^9\ ns[/tex]
Now using unitary method to solve it such that,
[tex]1.2\times 10^{-8}\ s=1.2\times 10^{-8}\ \times 10^9\\\\=1.2\times 10\\\\=12\ ns[/tex]
So, there are 12 nanoseconds in [tex]1.2\times 10^{-8}\ s[/tex].
How many joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point?
Answer: 1123000 Joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point
Explanation:
Latent heat of vaporization is the amount of heat required to convert 1 mole of liquid to gas at atmospheric pressure.
Amount of heat required to vaporize 1 mole of lead = 177.7 kJ
Molar mass of lead = 207.2 g
Mass of lead given = 1.31 kg = 1310 g (1kg=1000g)
Heat required to vaporize 207.2 of lead = 177.7 kJ
Thus Heat required to vaporize 1310 g of lead =[tex]\frac{177.7}{207.2}\times 1310=1123kJ=1123000J[/tex]
Thus 1123000 Joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point
2. A 0.45g sample of mineral ore is analyzed for chromium and found to contain
0.560mg Cr2O3. Express the concentration of Cr2O3 in the sample as:
(a) Percent (%)
(b) Parts per thousand (ppt)
(c) Parts per million (ppm)
(d) Parts per billion (ppb)
Answer:
Explanation: I don't know
A reaction was experimentally determined to follow the rate law, Rate = k[A] where k = 0.15 s-1. Starting with [A]o = 0.225M, how many seconds will it take for [A]t = 0.0350M?
Answer:
The time the reaction takes is 12.4s
Explanation:
A reaction that follows the rate law:
Rate =k[A] is order 1 and follows the equation:
Ln[A] = -kt + ln[A]₀
Where [A] is concentration of the reaction after time t: 0.0350M
k is rate constant = 0.15s⁻¹
t is time in seconds
[A]⁰ is initial concentration = 0.225M
Ln[0.0350] = -0.15s⁻¹*t + ln[0.225]
-1.86075 = -0.15s⁻¹*t
12.4s = t
The time the reaction takes is 12.4s