0.8058 g of an unknown gas at 298.15 K and 1.000 bar of pressure fills a 500.0 mL flask. What is the molar mass of the gas?

Answers

Answer 1

According to the given statement the molar mass of the gas is 39.400 g/mole.

How is the molar mass calculated?

The mass in grams of one mole of a substance is its molar mass. The molar mass of a substance can be determined by adding the molar masses of its component atoms, as shown in this video. The computed molar mass can then be used to convert the mass and the number of molecules of the substance..

​Briefing:

From ideal gas equation we know,  PV = nRT

PV =w/M * RT

n is number of moles = w/M,  

we = weight of gas,

M = molecular weight of the gas

PV = wRT/M

Value of pressure, P = 1atm and standard temperature, T = 298.15K

Value of universal gas constant,

R = 0.082 lit. atm. K⁻¹.mol⁻¹

Weight of gas,

w = 0.8058g and volume of gas,

V = 500mL = 0.5 Liters

Substituting all the value, we get   :

Molar mass = 0.8058* 0.082 * 298.15 / 1 * 0.5

Molar mass = 39.400 g/mole

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Related Questions

How many degrees will 340 J raise the temperature of 6.8 g of water

Answers

The temperature raised is 11.9 degrees as the heat capacity is 340J

What is heat capacity ?

Heat Capacity is the quantity of energy needed to raise a substance's temperature by one degree Celsius. It can also be thought of as the proportion of energy transmitted to an item to the rise in temperature that follows.

The heat capacity measurement is in Joules per degree Celsius as well. Because it is based on the object's mass. Additionally, it is frequently stated in terms of 100 grammes in order to facilitate comparisons between objects of similar mass.

Q = m*c*T

Q = heat energy

m = mass of substance

c = specific heat capacity

T = temperature

Q = 6.8*4.2*T

T = 340/6.8*4.2

T =11.90 celsius

The temperature raised is 11.9 degrees as the heat capacity is 340J

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Example 1: A gas is expanded from an initial volume of 20.5 L at 0.92 atm at room temperature (23.0°C) to a
final volume of 340.6L. During this expansion, the gas cools to 12.0°C. What is the new pressure?

Answers

The new pressure is .67 atm (atmospheric pressure at sea level)

What is pressure?
The force applied perpendicularly to an object's surface per unit area over which that force is distributed is known as pressure (symbol: p or P). : 445 The pressure relative to the surrounding air is known as gauge pressure, also spelled gauge pressure. Pressure is expressed using a variety of units. Some of these come from dividing a unit of force by a unit of area; the traditional unit of pressure in the imperial and U.S. customary systems is the pound-force per square inch (psi), which is equivalent to one newton per square metre (N/m²) in the SI. The atmosphere (atm), which is equal to this pressure, can also be used to describe pressure. The torr is defined as 1/760 of this.

PV = nRT
P₁V₁ = P₁V₁

P₁ = 0.92 atm

V₁ = 20.5 L

T₁ = 23.0°C

P₂ = ?

V₂ = 340.6L

T₂ = 12.0°C

P₂ = (P₁V₁/T₁)(T₂/V₂)

P₂ = .92(20.5/23)(12/340.6)

P₂ = .67 atm

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The radius of a nickel atom is 125 pm. How many nickel atoms would have to be laid side by side to span a distance of 2.65 mm?

Answers

The number of nickel atoms that would be laid side by side to span a distance of 2.65 mm is 1.06 x 10⁷ atoms of nickel.

What is the diameter of the nickel atom?

The diameter of the nickel atom is the line that divides the nickel atom into two equal halves. The diameter of an object is always double of the radius when the radius of the atom is known.

The diameter of the nickel atom is calculated as follows;

d = 2r

where;

d is the diameter of the nickel atomr is the radius of the nickel atom

d = 2 x 125 pm

d = 250 pm

d = 2.5 x 10⁻¹⁰ m

The number of nickel atoms that would be laid side by side to span a distance of 2.65 mm is calculated as follows;

n(2.5 x 10⁻¹⁰ m) = 2.65 mm

n(2.5 x 10⁻¹⁰ m) = 2.65 x 10⁻³ m

n = (2.65 x 10⁻³) / (2.5 x 10⁻¹⁰)

n = 1.06 x 10⁷ atoms of nickel

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Look at the line segment in the coordinate grid.
A(-4,-2)
B(5,5)
What is the length of segment AB ?

Answers

The length of segment AB is determined as 11.4 units.

What is distance between two points?

The distance between two points is the length of the line segment that connects the two points in a plane.

The length of segment AB is the distance between point A and point B, which is calculated as follows;

|AB| = √[(x₂ - x₁)² + (y₂ - y₁)²]

where;

x₁ is the x - component of point Ax₂ is the x - component of point By₁ is the y - component of point Ay₂ is the y- component of the point B

|AB| = √[(x₂ - x₁)² + (y₂ - y₁)²]

|AB| = √[(5 - - 4)² + (5 - -2)²]

|AB| = √[(9)² + (7)²]

|AB| = 11.4 units

Thus, the length of segment AB is the distance between point A and B.

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Hydrazine, N2H4 , reacts with oxygen to form nitrogen gas and water.

N2H4(aq)+O2(g)⟶N2(g)+2H2O(l)

If 3.35 g of N2H4 reacts with excess oxygen and produces 0.350 L of N2 , at 295 K and 1.00 atm, what is the percent yield of the reaction?

Answers

Taking into account definition of percent yield, the percent yield of the reaction if 3.35 g of N₂H₄ reacts with excess oxygen and produces 0.350 L of N₂ is 13.82%.

Reaction stoichiometry

In first place, the balanced reaction is:

N₂H₄ + O₂ → N₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

N₂H₄: 1 moleO₂: 1 moleN₂: 1 moleH₂O: 2 moles

The molar mass of the compounds is:

N₂H₄: 32 g/moleO₂: 32 g/moleN₂: 28 g/moleH₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

N₂H₄: 1 mole ×32 g/mole= 32 gramsO₂: 1 mole ×32 g/mole= 32 gramsN₂: 1 mole ×28 g/mole= 28 gramsH₂O: 2 moles ×18 g/mole= 36 grams

Ideal gas law

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

P is the gas pressure.V is the volume that occupies.T is its temperature.R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances. n is the number of moles of the gas.

Percent yield

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield= (actual yield÷ theoretical yield)× 100%

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Actual yield of N₂

In this case, you know:

P= 1 atmV= 0.350 LT= 295 KR= 0.082 [tex]\frac{atmL}{molK}[/tex]n= ?

Replacing in the ideal gas law:

1 atm×0.350 L = n×0.082 [tex]\frac{atmL}{molK}[/tex]× 295 K

Solving:

n= (1 atm×0.350 L) ÷ (0.082 [tex]\frac{atmL}{molK}[/tex]× 295 K)

n= 0.01447 moles

Finally, the actual yield of N₂ is 0.01447 moles.

Theoretical yield of N₂

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 32 grams of N₂H₄ form 1 mole of N₂, 3.35 grams of N₂H₄ form how many moles of N₂?

moles of N₂= (3.35 grams of N₂H₄× 1 moles of N₂)÷ 32 grams of N₂H₄

moles of N₂= 0.1047 moles

Finally, the theoretical yield of N₂ is 0.1047 moles.

Percent yield for the reaction in this case

In this case, you know:

actual yield= 0.01447 molestheorical yield= 0.1047 moles

Replacing in the definition of percent yield:

percent yield= (actual yield÷ theoretical yield)× 100%

Solving:

percent yield= (0.01447 moles÷ 0.1047 moles)× 100%

percent yield= 13.82%

Finally, the percent yield for the reaction is 13.82%.

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This is the correct Lewis structure for the molecule C2H2Cl2?

True or false

Answers

Answer: It is false

Explanation:

Convert 75 ML to GL
Problems
What is the density of an object with a mass of 250 g and a volume of 300 mL?

Answers

The definition of density is the mass of a substance per unit of volume. The Latin letter D may also be used, however the symbol is most usually employed to denote density. Mass divided by volume gives the density value:

D = m/v

   = 250/300

   = 0.833 g/ml

A physical body's mass is its overall amount of matter. Inertia, or the body's resistance to acceleration when a net force is applied, is also measured using this phrase. The strength of a body's gravitational pull on other bodies depends on its mass. The kilogram serves as the foundational mass unit in the SI.

The amount of three-dimensional space that is occupied is measured in volume. Imperial or SI-derived units are frequently used in its mathematical expression. The concepts of volume and length are related.

Typically, there are two forms of density: absolute density and relative density. Relative density, also known as specific gravity, is the ratio of a substance's density to the density of a reference material. Water is frequently used as the reference material.

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which of the following reactions is balanced and shows complete combustion

Answers

The following  reactions is balanced and shows complete combustion are

A)2C₅H₁₂   +   11O₂  ----->   10CO  +   12H₂O

D) C₅H₁₂   +   8O₂  ----->   5CO₂  +   6H₂O

A) 2C₅H₁₂   +   11O₂  ----->   10CO  +   12H₂O

In this reaction,

              Reactants                 products

C                   10                            10

H                   24                           24

O                   22                           22

Reactants and products have same no. of atoms .

therefore this reaction is balanced and shows complete combustion.

B) 2C₅H₁₂   +   11O₂  ----->   12CO  +   10H₂O

                  Reactants             Products

C                        10                        12

H                         24                      20

O                         22                      22

this reaction is not balanced.

C) C₅H₁₂   +   8O₂  ----->   6CO₂  +   5H₂O

                   Reactants             Products

C                         5                             6

H                         12                            10

O                         16                            18

This reaction is not balanced,

D) C₅H₁₂   +   8O₂  ----->   5CO₂  +   6H₂O

                     Reactants             Products

C                           5                          5

H                           12                         12

O                           16                           16

Reactants and products have same no. of atoms .

therefore this reaction is balanced and shows complete combustion.

Thus, The following  reactions is balanced and shows complete combustion are

A)2C₅H₁₂   +   11O₂  ----->   10CO  +   12H₂O

B) C₅H₁₂   +   8O₂  ----->   5CO₂  +   6H₂O

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Answer:

D

Explanation:

I got the answer right

Please help me with question 6!!The neutralization of a weak base and a strong acid should product a solution that is:a. basicb. neutralc. all of aboved. acidic

Answers

INFORMATION:

We have the neutralization of a weak base and a strong acid, and we must determine what should be the product of the reaction

STEP BY STEP EXPLANATION:

To determine it, we need to know that:

- The neutralization of a strong acid and strong base has a pH equal to 7. The neutralization of a strong acid and weak base will have a pH of less than 7, and conversely, the resulting pH when a strong base neutralizes a weak acid will be greater than 7.

In our case, we have the neutralization of a weak base and a strong acid, so our product would have a pH of less than 7. Then, knowing that a pH less than 7 represents an acidic, we can state that the product of the reaction will be an acidic.

A strong acid and a weak base yield a weakly acidic solution, not because of the strong acid involved, but because of the conjugate acid of the weak base.

ANSWER:

d. acidic

You have 2.2mol Xe and 2.0mol F2, but when you carry out the reaction you end up with only 0.25mol XeF4. What is the percent yield of this experiment?: Xe(g) + 2F2(g) -> XeF4(g)

Answers

If 2.2 mol Xe and 2.0 mol [tex]F_2[/tex] reacts to produce 0.25 mol [tex]XeF_4[/tex], the percent yield of the experiment will be 25%.

What is the percent yield of an experiment?

The percent yield of an experiment is the amount of the actual yield of the experiment relative to the theoretical yield of the same experiment.

Mathematically; percent yield = actual yield/theoretical yield x 100%

In the illustrated experiment, the mole ratio of Xe and  [tex]F_2[/tex]  is 1:2. With 2.2 mol Xe reacting against 2.0 mol  [tex]F_2[/tex] , it means  [tex]F_2[/tex]  is limited in availability with Xe being excessive.

The mole ratio of  [tex]F_2[/tex] and [tex]XeF_4[/tex] is 2:1. Thus, the mole of [tex]XeF_4[/tex] that should be theoretically produced would be half of the mole of [tex]F_2[/tex] that reacts.

Thus, mole of  [tex]XeF_4[/tex] = 2/1

                                   = 1

But only 0.25 mol of  [tex]XeF_4[/tex] were produced.

Percent yield = 0.25/1 x 100%

                      = 25%

The percent yield of the experiment is, therefore, a paltry 25%.

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Consider the reaction: 2Al + 3S = Al2S3If you have 45 grams of aluminum...a. How many grams of aluminum sulfide are produced? (Theoretical)b. When the rxn is performed in the lab, 114 grams of aluminum sulfide is produced. What is the percent yield?

Answers

The reaction they give us is balanced. We must determine the moles of aluminum that are equivalent to that 45 g, for this, we will use the molar mass of aluminum equal to 26.98g/mol

[tex]\begin{gathered} \text{Mol of Al}=GivengAl\times\frac{1molAl}{MolarMass,gAl} \\ \text{Mol of Al}=45gAl\times\frac{1molAl}{26.98gAl}=1.67molAl \end{gathered}[/tex]

Now, in the reaction, we can see that for every 2 moles of aluminum, 1 mole of aluminum sulfate is produced. We can also use the molar mass of aluminum sulfate (101.96g/mol) to calculate the grams of aluminum sulfide produced.

[tex]\begin{gathered} gAl_2O_3=GivenMolAl\times\frac{1molAl_2O_3}{2molAl}\times\frac{MolarMass,gAl_2O_3}{1molAl_2O_3} \\ gAl_2O_3=1.67molAl\times\frac{1molAl_2O_3}{2molAl}\times\frac{101.96gAl_2O_3}{1molAl_2O_3}=85gAl_2O_3 \end{gathered}[/tex]

The grams of aluminum sulfate produced is 85g

The percent yield is calculated with the next equation:

[tex]\begin{gathered} \text{Percent yield=}\frac{\text{Actual yield}}{Theoretical\text{ yield}}\times100\% \\ \text{Percent yield=}\frac{\text{1}14g}{85g}\times100\%=134\% \end{gathered}[/tex]

Percent yield=134%

This is not experimentally possible

Anode? / Cathode? - Oxidation? / Reduction?.

Answers

This example is similar to the previous one. Recall that oxidation reactions occur at the anode and reduction reactions occur at the cathode.

Oxidation is the process in which a compound donates electrons and as a result increases its oxidation state. When a compound receives electrons, it will be reduced and its oxidation state will decrease.

In this case, we have an element in its natural state (Zn), that is, it has a neutral charge equal to zero. After the reaction we have the same element with an oxidation state greater than and equal to +2, therefore the element was oxidized and donated two electrons corresponding to the difference in oxidation state.

Answer: Anode, oxidation

To find the volume of your element, you completed water displacement, which is calculated by Final volume - Initial volume. Originally 14.0 mL of water was placed into the graduated cylinder. After you object was placed into the graduated cylinder, the water level raised to 20.6 mL. Calculate the volume of the object.

Answers

The volume of the object is 6.6 cm³

The amount of space occupied by a three dimensional figure as measured in cubic units and when an object enters water it pushes out water to make room for itself and the object pushes out a volume of water that is equal to its own volume and this is called displacement

So here given data is  14.0 mL of water was placed into the graduated cylinder and then the water level raised to 20.6 mL so we have to find volume = ? here final volume =  20.6 mL and  initial volume =  14.0 mL

Volume = final volume - initial volume

Volume =  20.6 mL - 14.0 mL

Volume = 6.6 cm³

The volume of the object is 6.6 cm³

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4)
If atom A bonds with atom B covalently, and atom A attracts electrons with
greater force, which of the following will be true?
O Atom A will have a greater share of electrons and will have a
slight positive charge.
Atom A will take all of the electrons and have a slight positive
charge.
Atom A will have a greater share of electrons and will have a
slight negative charge.
Atom B will lose its valence electrons and have a slight negative
charge.
с

Answers

Atom A will have a greater share of electrons and will have a slight negative charge according to Polar Covalent bond


What is Polar Covalent Bond ?
A specific type of covalent link is known as a polar bond. It is also the point at which an ionic bond and a pure covalent bond begin to form, according to another definition. A polar covalent bond, on the other hand, is a link that exists between two atoms and is made up of electrons that are scattered unevenly if we want to define it more precisely. The molecules have a tendency to have an electrical dipole moment in which the two ends are slightly positive or negative as a result of this state.

The many forms of covalent bonding are mostly determined by the electronegativity of the material. The propensity of an atom to draw a shared pair of electrons to itself is known as electronegativity. It is a trend and has no units. Polar covalent bonds are those created between two atoms in molecules with an electronegative difference.


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If 7.60 kJ of heat is needed to raise the temperature of a sample of metal from 12°C to 27°C, how many kilojoules of heat will be required to raise the temperature of the same sample of metal from 39°C to 55°C?

Answers

Answer: 8.1067 kJ

Explanation: Please mark this brainliest. the joules necessary to raise the heat of a substance only depends on how much change of temp you need and how much substance is there. In this question the amount is constant. Since it is 7.6kJ to change it by 27-12=15C, and 55-39=16C. The number of kilojoules is 16/15 *7.6=8.1067

Which of the following materials is a substance?


gasoline

air

silver

stainless steel

Answers

Answer: The correct answer is silver.

Explanation:

Matter that has a consistent and uniform composition—the same number and kind of atoms bound in the same way—is referred to as a substance. The substances are either elements or compounds. Only silver is a substance out of the alternatives offered because it is an element and all silver materials only contain silver atoms. In the same way that gasoline is a mixture of liquids whose composition can change, air is a mixture of different gases, and steel is an alloy (a mixture of compounds and elements) whose composition can change. Therefore the silver is the correct answer.

**NEED ANSWER ASAP, H.W QUESTION**
How does the Sun's magnetic field affect the corona?

Answers

Answer:

The surface of the Sun is covered in magnetic fields. This is the force that makes magnets stick to metal, like the door of your refrigerator. The Sun's magnetic fields affect charged particles in the corona to form beautiful features. These include streamers, loops, and plumes.

Calculate the wavelength of a photon (in nm) that has the frequency of 5.66x10^14 Hz

Answers

ANSWER

The wavelength of the photon is 0.0053nm

STEP-BY-STEP EXPLANATION:

Given data

Frequency of the photon = 5.66 x 10^-4 Hz

Let x represents the wavelength of the photon

To determine the wavelength of the photon, we need to apply the below formula

[tex]\begin{gathered} C\text{ = f x }\lambda \\ \text{where} \\ c=\text{ sp}eed\text{ of light} \\ f\text{ = frequency} \\ \lambda\text{ = wavelength} \end{gathered}[/tex]

Recall that, the speed of light is 3 x 10^8 m/s

The next process is to substitute the values into the above formula

[tex]\begin{gathered} c\text{ = f}\lambda \\ \text{Divide both sides by f} \\ \frac{c}{f}\text{ = }\frac{f\lambda}{f} \\ \lambda\text{ = }\frac{c}{f} \\ \end{gathered}[/tex][tex]\begin{gathered} \lambda\text{ = }\frac{3\cdot10^8}{5.66\cdot10^{14}} \\ \lambda\text{ = }\frac{3}{5.66}\cdot10^{8\text{ - 14}}^{} \\ \lambda\text{ = 0.53 }\cdot10^{-6} \\ \lambda\text{ = 5.3 }\cdot10^{-7}m \\ \lambda\text{ =}0.0053nm \end{gathered}[/tex]

Therefore, the wavelength of the photon is 0.0053nm

What is the name of the molecule below?
• A. 2-pentyne
B. pentane
• C. 2-pentene
O D. 2-pentane

Answers

The molecule described below is known as :

2-pentene.

What exactly are alkenes?Alkenes are organic compounds that contain a double bond and are composed of carbon and hydrogen atoms.They can be used as starting materials in the synthesis of alcohols, plastics, lacquers, detergents, and fuels.

In the diagram below:

Each corner and joint displays the carbon atoms, and the total number of carbon atoms is 5.In the second position, there is one double bond.

As a result, the compound is 2 pentene.

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The severity of a tropical storm is related to the depressed atmospheric pressure at its center. In August 1985, Typhoon Odessa in the Pacific Ocean featured maximum winds of about 90 mi/hr and pressure that was 40.0 mbar lower at the center than normal atmospheric pressure. In contrast, the central pressure of Hurricane Andrew (pictured) was 90.0 mbar lower than its surroundings when it hit south Florida with winds as high as 165 mi/hr.

If a small weather balloon with a volume of 50.0 L at a pressure of 1.00 atmosphere was deployed at the edge of Typhoon Odessa, what was the volume of the balloon when it reached the center?

Answers

If a small weather balloon with a volume of 50.0 L at a pressure of 1.00 atm was developed at the edge of Typhoon odissa , the volume of the balloon when it reaches the center was 52.63 L

According to boyle's law :

P1V1 = P2V2

here:

P1 = 1 atm

V1 = 50.0 L

P2 = ( 1atm - 0.050 atm )  = 0.95 atm

V2 = ?

V2 = P1V1/P2

V2 = (1  × 50.0 ) / 0.95

     = 52. 63 L

Thus, If a small weather balloon with a volume of 50.0 L at a pressure of 1.00 atm was developed at the edge of Typhoon odissa , the volume of the balloon when it reaches the center was 52.63L

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IF 23 g of FeCl2 reacts with 41g Na3PO4 what is the limiting reactant?

Answers

First, we need to figure the reaction out.

Both reactants are ionic compounds, so their reaction is probably a double displacemente reaction.

The Cl has a charge of 1-, so Fe has a charge of 2+. Na has a charge of +1 and PO₄ has a charge of 3-.

To combine Fe²⁺ with PO₄³⁻, we will need 3 Fe²⁺ and 2 PO₄³⁻, so the compound becomes neutral.

Both Na and Cl have single charge, so their combination is simply 1 Na and 1 Cl.

So, the products are Fe₃(PO₄)₂ and NaCl, so the unbalanced reaction is:

[tex]FeCl_2+Na_3PO_4\to Fe_3(PO_4)_2+NaCl[/tex]

To balance it, We can start by putting a coefficient of 2 on Na₃PO₄, so we have two PO₄³⁻ anions on both sides:

[tex]FeCl_2+2Na_3PO_4\to Fe_3(PO_4)_2+NaCl[/tex]

Now, we put a coefficient of 3 on FeCl₂ and 6 on NaCl to get the balanced equation:

[tex]3FeCl_2+2Na_3PO_4\to Fe_3(PO_4)_2+6NaCl[/tex]

Now, we first need to calculate the number of moles of each reactant, using their molar masses:

[tex]\begin{gathered} M_{FeCl_2}=1\cdot M_{Fe}+2\cdot M_{Cl}=(1\cdot55.845+2\cdot35.453)g/mol=126.751g/mol \\ M_{Na_3PO_4}=3\cdot M_{Na}+1\cdot M_P+4\cdot M_O=(3\cdot22.98976928+1\cdot30.973762+4\cdot15.9994)g/mol=163.94066984g/mol \end{gathered}[/tex]

So:

[tex]\begin{gathered} M_{FeCl_{2}}=\frac{m_{FeCl_2}}{n_{FeCl_{2}}} \\ n_{FeCl_2}=\frac{m_{FeCl_2}}{M_{FeCl_{2}}}=\frac{23g}{126.751g/mol}=0.181458\ldots mol \end{gathered}[/tex][tex]\begin{gathered} M_{Na_3PO_4}=\frac{m_{Na_3PO_4}}{n_{Na_{3}PO_{4}}} \\ n_{Na_3PO_4}=\frac{m_{Na_3PO_4}}{M_{Na_{3}PO_{4}}}=\frac{41g}{163.9406698g/mol}=0.250090\ldots mol \end{gathered}[/tex]

Now, if the coefficient of FeCl₂ is 3, for each 3 FeCl₂ that reacts, one reaction occurs, so the number of reactions that will need to occur to consume all its number of moles is that amount over 3:

[tex]n_{\text{reaction}}=\frac{n_{FeCl_2}}{3}=\frac{0.181458\ldots mol}{3}=0.060486\ldots mol[/tex]

Similarly, we get the number of reactions that would occur if all Na₃PO₄ reacts by dividing its number of moles by its coefficient, that is 2:

[tex]n_{\text{reaction}}=\frac{n_{Na_3PO_4}}{2}=\frac{0.250090\ldots mol}{2}=0.125045\ldots mol[/tex]

This means that the amount we have of FeCl₂ is enough for only about 0.0605 mol of reactions while the amount we have of Na₃PO₄ is enought for about 0.1250 mol of reactions, which is more than the other reactant.

This means that the reactant that limits the amount of reaction that can occur is FeCl₂, so the limiting reactant is FeCl₂.

What might happen if your lab group had such a cluttered lab area

Answers

Answer:

depending on what you guys are doing someone could get hurt or knock something over and break it

Explanation:


Consider the following ionic
compounds and determine which
has the higher melting point.

A. BeCl₂

B.Al₂S3

Answers

Answer:

Al2S3

Explanation:

Al2S3 has ions which have a higher magnitude of charge compared to BeCl2. This higher charge creates stronger attractive forces between molecules, holding them together even at high temperatures. Another simple way to compare the melting points is to multiply the charges of the ions together and compare those values. BeCl2 would be 2*1 because of Be2+ and Cl (1)-. Al2S3 would be 2*3 because of S2- and Al3+. Since 2*3 is more than 2*1, Al2S3 has a higher melting point. I think this is a repeat question

The diagram shows a controlled experiment designed to test how much time it takes for seeds to
germinate under four different conditions. Four bean seeds were placed in each of four pots. Each pot
contained 100 cubic centimeters of soil. All four pots were placed on the same sunny windowsill. A
different amount of water was placed in each pot.
Identify the independent variable:

Answers

The independent variable is amount of water

It is a variable that stands alone and isn't changed by the other variables you are trying to measure called independent variable

Here given data is four bean seeds were placed in each of four pots. Each pot contained 100 cubic centimeters of soil All four pots were placed on the same sunny windowsill A different amount of water was placed in each pot then in the first pot 0ml of water are placed and in the second pot 10ml water are placed and in the third pot 20ml water are placed and in the fourth pot 40ml water are placed so, because of high concentration of water the seed germinate in fourth pot are fast other than three pot and all constant in all four pot are soil seed sunrays or container this all are same only amount of water are different and dependent variable is germination

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Write the ionic and net ionic equations for the following reaction:

Co(NO3)2(aq) +Na2CO3(aq)->

Co(NO3)2(aq) +Na2CO3(aq)+CH3COOH->

Answers

The ionic and net ionic equations for the following reaction is

Co(NO3)2(aq) +Na2CO3(aq)->NaNo3 + CaCO3

Co(NO3)2(aq) +Na2CO3(aq)+CH3COOH-> NaNo3 + CH3COOCo + H2O

What is ionic equation?

Ionic equation is defined as a chemical equation that expresses electrolytes in aqueous solution as dissociated ions.

An ionic equation can also be defined as one that solely depicts the atoms and ions that really participate.

Net ionic equation is defined as only those elements, molecules, and ions actually involved in the chemical process are shown in the chemical equation.

It can also be defined as an equation that simply includes the components that are really involved in the reaction.

Thus, the ionic and net ionic equations for the following reaction is

Co(NO3)2(aq) +Na2CO3(aq)->NaNo3 + CaCO3

Co(NO3)2(aq) +Na2CO3(aq)+CH3COOH-> NaNo3 + CH3COOCo + H2O

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Calculate the molarity of an acetic acid solution if 38.9 mL of an HC2H3O2 solution is titrated with 26.7 mL of a 0.114 MKOH solution:HC2H3O2(aq)+ KOH(aq)→H2O(l)+ KC2H3O2(aq) Express your answer with the appropriate units.

Answers

Explanation

Given:

CH₃COOH(aq) + KOH(aq) → H2O(l)+ KC2H3O2(aq)

Volume of acetic acid = 38.9 mL = 0.0389 L

Voume of KOH = 26.7 mL = 0.0267 L

Molarity of KOH = 0.114 M

Required: The molarity of an acetic.

Solution

Step 1: Find the moles of KOH

n = C x V where n is the moles, C is the concentration and V is the volume

n = 0.114 M x 0.0267 L

n = 0.00304 mol

Step 2: Find the moles of acetic acid using stoichiometry

The molar ratio between acetic acid and KOH is 1:1

Therefore the moles of acetic acid = 0.00304 mol

Step 3: Calculate the molarity of acetic acid

C = n/V

C = 0.00304/0.0389

C = 0.0781 M

Solution

Molarity of acetic acid = 0.0781

Draw the net force arrow on the diagram and state the direction. Net force direction =​

Answers

The magnitude of the net force is 20.12 N in a direction 26.56° South of East.

What is the net force and the direction of the force?

The net force in the given forces in the diagram s given below as follows:

Force  1, F₁ =  18 N force acting in a direction to the east

Force 2, F₂ = 9 N force acting in a direction south of the object.

The two forces form two sides of a right-angle triangle

Net force is determined using Pythagoras' rule as follows:

Net force, F = √(F₁² + F₂²)

Net force = √ (18² + 9²)

Net force = √ (324 + 81)

Net force = √ 405

Net force = 20.12 N

The direction of the Net force, θ, is determined as follows;

θ = tan⁻¹ (9 / 18)

θ = tan⁻¹ 0.5

θ = 26.56° South of East

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What is the Mass for a statue with a volume of 120cm3 made from ceramic which has a density of 2g/cm3

Answers

All matter possesses the fundamental property of inertia, which can be quantified by mass. In essence, it's the resistance of a mass of matter to changing its direction or speed in reaction to the application of a force. A body's ability to resist change from applied forces increases with its bulk.

A three-dimensional space's volume can be calculated. Various imperial units or SI-derived units are routinely used to quantify it numerically. The link between length and volume is reciprocal.

The density of a substance is its mass per unit of volume. Density's sign - ρ, although it can alternatively be represented as the Latin letter D, is most usually written as. Density can be mathematically defined by dividing mass by volume.

Mass = Density * Volume

Mass = 2 * 120

Mass = 240g

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Question 1
Concentrated HCl(aq) is 37.2% HCI by mass. If the density of the solution is
1.19g/mL, how many grams of HCI is in 1.75 L of concentrated HCI?

Answers

438 m g l of HCI is in 1.75 L of concentrated HCI .

What does concentration of acid means?

A specific amount of solution's concentration relates to the amount of acid or basic that is present. If there is a lot of acid or base in a little amount of solution, it is said to be concentrated. If there is little acid or base in a given volume of solution, it is said to be diluted. Acidic is defined as having a pH below 7. Once the pH reaches 7, it is referred to as basic. Hydronium concentrations in acidic solutions are high, while hydroxide concentrations are low. Hydroxide concentrations in basic solutions are high, while hydronium concentrations are lower. The stronger an acid is, the lower the pH is for a given concentration in aqueous solution. Acid solutions have a pH that decreases with increasing concentration.

the quotient….

Molality = moles of solute/kilograms of solvent .

Whereas…

Molarity = moles of solute/volume of solution in liters.

It's only an estimate, but 1.18 g/mL x 1000 mL x 0.37 = around 437 g.

Then, mols in that 1 L = grams/molar mass

= approximately 437/36.5

= roughly 12 M, according to a different calculation.

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Aqueous hydrochloric acid (HCI) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H₂O).Suppose 1.46 g of hydrochloric acid is mixed with 2.9 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 3 significant digits.


PLEASE HELP SOLVE

Answers

The balanced chemical equation for this reaction is:

HCl + NaOH = NaCl + H2O

1.46 g of HCl is equal to 0.0400 moles of HCl. (1.46/36.458). (36.485 being the molar mass of HCl in grams/mole).

2.9 g of NaOH is equal to 0.0725 moles of NaOH. (2.9/39.997). (39.997 being the molar mass of NaOH in grams/mole).

- From the reaction we can infer that it takes one mole of HCl and one mole of NaOH to form one mole of water. Therefore the limiting reactant in this case will simply be the one that we have the least amount of. So HCl is the limiting reactant.

- As stated previously, it takes one mole of HCl to produce one mole of H2O so that would mean that 0.0400 moles of HCl would produce 0.0400 moles of H2O.

0.0400*18.01 (18.01 being the molar mass of water in grams/mole) will give you the grams of H2O produced in this reaction.

Answer: 0.720 grams of H2O

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