11.4 Conversions of Polar and Rectangular Coordinates

What are the approximate coordinates in the rectangular plane that represent the polar coordinates (6,- pi/6)
? Round values to the nearest thousandth.

Each of the statistical jargons will be matched to the corresponding meaning or similarity or example.

The corresponding example of the word can be matched as follows:

Population : All the people in the marketing company region.

In statistics, a population is a group of individuals from which are subject to study.

Sample: The 380 randomly selected people who are observed to see if they will buy the product.

A sample represents the group of interest from a population, this group represent the data.

Variable: The answer Yes or No to whether a person bought the product Variable in statistic are any number or quantity that can be measured.

Data: The list of the 380 Yes or No answers to whether the person bought the product.

Data are the figures that are collected, analysed, and summarized for interpretation.

Parameter: The proportion of all people in the company's region who buy the product

Statistics: The proportion of the 380 observed people who buy the product

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The graph best represents the solution set for all possible combinations of x and sold to the grocery store, for the week is option D.

A graph can be described as a pictorial representation of data. The bushels of corn sold is greater than 120. Thus, the shaded area should be above the line and the line should be a straight line.

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Answer:

4.7 Pounds

Step-by-step explanation:

[tex]14 \div 3≈4.6[/tex]

(Note: This symbol (≈) that looks like a squiggled equal sign means an approximate amount)

Answer:

Not Proportional

Step-by-step explanation:

85:42 :: 18:9

85 x 9 = 42 x 18

765     =     776

They are not equal, so they cant be proportional.

Answer: sin(x)=5/11

Step-by-step explanation:

For #7, the hypotenuse is always the longest side of a triangle and in right triangles it's always the side that's opposite the right angle. MO, the side thats 11, is the hypotenuse in this triangle and not the adjacent side which would be NM. Therefore, you need to use sin=opp/hyp and get sin(x)=5/11

The codomain of the function [tex]g(x) = 2x^2 + 4x - 1[/tex] is [tex]g(x) = 2x^2 + 4x - 1[/tex]

The equation of the function is given as:

[tex]g(x) = 2x^2 + 4x - 1[/tex]

The above function is a quadratic function and it has the following features:

Domain = [tex](-\infty, \infty)[/tex]

Range: [tex][-3, \infty)[/tex]

When the range and the domain are combined, we have:

[tex][-3, \infty)\ and\ (-\infty, \infty)[/tex]

This gives

[tex][-3, \infty[[/tex]

Hence, the codomain of the function [tex]g(x) = 2x^2 + 4x - 1[/tex] is [tex]g(x) = 2x^2 + 4x - 1[/tex]

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Answer:

-4 < x < -2

Step-by-step explanation:

Taking the left part of the inequality :

Taking the right part of the inequality :

Solution :

Answer:

the answer is 1

Step-by-step explanation:

you can type it in your scientific calculator and the answer will be 1

we know the angle is between 90° and 180°, 90° < θ < 180°, that means the angle is in the II Quadrant, where the sine is positive and the cosine is negative, with that info, let's find check a few things

[tex]sin(\theta )=\cfrac{\stackrel{opposite}{3}}{\underset{hypotenuse}{5}}\qquad \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2 - b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2 - 3^2}=a\implies \pm\sqrt{16}=a\implies \pm 4 = a\implies \stackrel{II~Quadrant}{-4=a} \\\\[-0.35em] ~\dotfill[/tex]

[tex]cos(\theta )=\cfrac{\stackrel{adjacent}{-4}}{\underset{hypotenuse}{5}} \\\\\\ tan\left(\cfrac{\theta}{2}\right)\implies \cfrac{sin(\theta)}{1+cos(\theta)}\implies \cfrac{ ~~ \frac{3}{5} ~~ }{1-\frac{4}{5}}\implies \cfrac{ ~~ \frac{3}{5} ~~ }{\frac{1}{5}}\implies \cfrac{3}{5}\cdot \cfrac{5}{1}\implies 3[/tex]

The expression for the change of the variable z is Δz = (0.9 · x² + 0.6 · y²) · cos (x³ + y³).

In this question we must apply the concept of total differential to determine the change of the variable z in terms of the changes in variables x and y. That is:

[tex]\Delta z = \frac{\partial f}{\partial x}\cdot \Delta x + \frac{\partial f}{\partial y}\cdot \Delta y[/tex]     (1)

If we know that z = sin (x³ + y³), Δx = 0.3 and Δy = 0.2, then the expression for the change of z is:

[tex]\Delta z = 3\cdot \cos (x^{3}+y^{3})\cdot x^{2}\cdot (0.3)+3\cdot \cos (x^{3}+y^{3})\cdot y^{2}\cdot (0.2)[/tex]

Δz = (0.9 · x² + 0.6 · y²) · cos (x³ + y³)

The expression for the change of the variable z is Δz = (0.9 · x² + 0.6 · y²) · cos (x³ + y³).

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Answer:

94

Step-by-step explanation:

Equating the mean to the scores :

So

Let that be n

Problem 8

The box portion of the shed (ignoring the triangular roof) has a volume of:

length*width*height = 10*8*6.5 = 520 cubic feet

The triangular face on the right side has an area of base*height/2 = 8*2.5/2 = 10. Multiply this with the depth of the triangular prism and we get a volume of 10*10 = 100 cubic feet.

The two sub-volumes combine to 520+100 = 620

===========================================================

Problem 9

Let's find the area of the base

area = side*side = (4.2)*(4.2) = 17.64 sq inches

Then we plug that into the formula below, along with the height of the pyramid

V = volume of a pyramid

V = (1/3)*(area of the base)*(height)

V = (1/3)*(17.64)*(5)

V = 29.4

Your teacher made a typo. She or he should have written [tex]\text{in}^3[/tex] instead of [tex]\text{in}^2[/tex]

Answer:

Okay so you basically need to break this shape into sensible pieces. Such as rectangular and triangular prisms.

first let's find the rectangular prisms' volume, we need to multiply 6.5 with 10 and 8.

6.5×10×8 gives us 520

520 is the volume of the rectangular prism (below the shape)

to find the triangular prism's volume follow these steps:

2.5×8×10×1/2 which gives us 100

now we need to take the sum of these

100+520=620

the answer is C good luck!

Answer:

30 mm, 2.5cm,20cm and 1m

Answer:

True (-∞, ∞)

Step-by-step explanation:

−11 + 16 ≤ −5 + 16

5 ≤ 11

Answer: 3

Step-by-step explanation:

Simplified

[tex](2^3\cdot3\cdot5^3j^5)[/tex]

Step-by-step explanation:

[tex](((12 \cdot (j2)) \cdot 5) \cdot 52j3) \cdot 2[/tex]

[tex](((22\cdot3j2) \cdot 5) \cdot 52j3) \cdot 2[/tex]

[tex]((22\cdot3\cdot5j2) \cdot 52j3) \cdot 2[/tex]

[tex]2^(^2^+^1^) = 2^3[/tex]

[tex](2^3\cdot3\cdot5^3j^5)[/tex]

Answer:

12ft

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

Answer:

3.14159265359 or simplify it to 3.14...

Step-by-step explanation:

4:12 there are four vowels and 12 letters?

Answer: 42 easy!

Step-by-step explanation: 42 hope this helps

Answer:

10% maybe

Step-by-step explanation:

because 90% said no and 10% said yes

I hope it helps you

Don’s Clothing advertised a clothing sale and Following the markdowns, prices will be marked 4/5, or 80% off on : The Fourth Day

Meaning of advert and sale

An advert is a form of publicity or awareness done to increase sale or increase the purchase of goods from a company or organization. it makes the public aware of an offer made by an organization or company.

Sale is the exchange of goods or services for money. it is between the company or organization and the consumer.

In Conclusion, Don’s Clothing advertised a clothing sale and Following the markdowns, prices will be marked 4/5, or 80% off on The Fourth Day

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The length of time needed for the dough to last if 40 pizzas is required is 4 hours.

let

l = k / p

where,

k = constant of proportionality

If l = 5 and p = 32

l = k / p

5 = k / 32

5 × 32 = k

160 = k

Find l when p = 40

l = k / p

l = 160/40

l = 4 hours

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Let's examine what the problem gives us:

What does the problem want:

  ⇒ time (in hours)

Must find the relationship between distance, speed, and time:

   ⇒ Distance = Speed * Time

       ⇒  [tex]Time = \frac{Distance}{Speed}[/tex]

Let's convert some units:

               ⇒ let's convert

                  ⇒ [tex]\frac{200_.ft}{1_.s}*\frac{3600_.s}{1_.hr}*\frac{1_.mi}{5280_.ft}=136.36_. mi/hr[/tex]

Now let's solve:

   [tex]Time = \frac{Distance}{Speed}=\frac{10000_.mi}{136.36.mi/hr} =73.33_.hrs[/tex]

Answer: 73.33 hrs (estimated)

Answer:

Q1 = -4, Q2 = 6

Step-by-step explanation:

In this box-and-whisker plot, the first vertical line is the first quartile (-4), the second vertical line is the median (4), and the vertical line is the third quartile (6). The box contains the middle 50% of the data set.

Answer:

dilation with respect to the origin by a scale factor of 1/3 followed by a translation of 2 units down

Step-by-step explanation:

The sides of the △ HIJ are:

IH = 6

IJ = 3

Applying the scale factor we obtain the sides of △ H'I'J '.

The scale factor is k = 1/3.

Therefore, we have:

I'H '= 2

I'J '= 1

Then, we move the △ H'I'J 2 units down.

Answer:

1.85 because: 9.25 divided by 5 equals 1.85

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