50POINTS!
Using the ideal gas law (PV=nRT) solve for the missing. Variable. R= 0.08206atm*L/mol*k

If 22.9L of an ideal gas was collected at STP. How many moles of the gas were present?

A. 1.02 moles
B. 5.99 moles
C. 3.05 moles
D. 2.74 moles

Answer:

If a negative number is raised to an even power, the result will be positive. If a negative number is raised to an odd power, the result will be negative. The negative number must be enclosed by parentheses to have the exponent apply to the negative term.

Explanation:

Answer:

D

D...............DDDDDDD

Answer: D

Explanation:

The answer is D as it is the only correctly balanced equation.

The answer is c and possibly a I don't know why im here i dont know what this is so bye...

Explanation:

C I hope this is right for your question.

Answer:

1.5×10⁷ Hz

Explanation:

From the question given above, the following data were obtained:

Wavelength of radio wave (λ) = 20 m

Frequency (f) =?

Frequency and wavelength of a wave are related by the following equation:

v = λf

Where:

'v' is the velocity of electromagnetic wave.

'λ' is the wavelength

'f' is the frequency.

With the above formula, we can obtain the frequency of the radio wave as illustrated below:

Wavelength of radio wave (λ) = 20 m

Velocity (v) = 3×10⁸ m/s

Frequency (f) =?

v = λf

3×10⁸ = 20 × f

Divide both side by 20

f = 3×10⁸ / 20

f = 1.5×10⁷ Hz

Thus the frequency of the radio wave is 1.5×10⁷ Hz

Answer:

i am 50/50 at the memoent but i have a feeling it is the cytoplasm as it isnt a cell like the others. Hope this helps :(

Explanation:

Answer:

C. It would be less likely to be eaten by insects.

Explanation:

The bitter taste and strong odor of the wormwood plant would repel the insects from eating the plant.

16.7 g H₂O

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Stoichiometry

Step 1: Define

[RxN - Balanced] 2NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)

[Given] 1.85 mol NaOH

Step 2: Identify Conversions

[RxN] 2 mol NaOH → 1 mol H₂O

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Stoichiometry

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

16.6685 g H₂O ≈ 16.7 g H₂O

The main differentiation between given windows is that in normal publication window we can edit the document after generation also and the story editor window in desktop publishing we can not able to edit after generation.

Windows in the computer world is a part of the graphical user interface (GUI), which is a separate viewing area on the display of monitor where they allow multiple viewing area.

Hence, in the above paragraph differentiation is given.

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Answer: The empirical formula is [tex]C_3H_3O_2[/tex].

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

[tex]C_xH_yO_z+O_2\rightarrow CO_2+H_2O[/tex]

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of [tex]CO_2[/tex] = 0.8635

Mass of [tex]H_2O[/tex]= 0.1767 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 0.8635 g of carbon dioxide, =[tex]\frac{12}{44}\times 0.8635=0.2355g[/tex] of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 0.1767 g of water, =[tex]\frac{2}{18}\times 0.1767=0.0196g[/tex] of hydrogen will be contained.

Mass of oxygen in the compound = (0.4647) - (0.2355+0.0196) = 0.2096 g

Mass of C = 0.2355 g

Mass of H = 0.0196 g

Step 1 : convert given masses into moles.

Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{0.2355g}{12g/mole}=0.0196moles[/tex]

Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.0196g}{1g/mole}=0.0196moles[/tex]

Moles of O=[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{0.2096g}{16g/mole}=0.0131moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =[tex]\frac{0.0196}{0.0131}=1.5[/tex]

For H =[tex]\frac{0.0196}{0.0131}=1.5[/tex]

For O = [tex]\frac{0.0131}{0.0131}=1[/tex]

The ratio of C : H: O = 1.5 : 1 .5 : 1

Converting to simple whole number ratio:

The ratio of C : H: O = 3 : 3: 2

Hence the empirical formula is [tex]C_3H_3O_2[/tex].

Answer:

I think its A im sorry if im wrong

Explanation:

Answer:

color and odor

Explanation:

Answer:

True

Explanation:

Answer: True

Explanation:

Answer:

12.73 L

Explanation:

Given that,

Initial temperature, [tex]T_i=20^{\circ}=20+273=293\ K[/tex]

Initial volume, [tex]V_i=10\ L[/tex]

We need to find the volume on the gas when the tank is heated to 100 degrees celsius or 373 K.

We know that volume is directly proportional to the temperature of the gas. Using above relation,

[tex]\dfrac{V_i}{T_i}=\dfrac{V_f}{T_f}\\\\V_f=\dfrac{V_iT_f}{T_i}[/tex]

Putting all the values,

[tex]V_f=\dfrac{10\times 373}{293}\\\\V_f=12.73\ L[/tex]

So, the final volume of the gas is 12.73 L.

Answer:

A. Theoretical yield of CaO is 11.59 g

B. Percentage yield of CaO = 58.76%

Explanation:

The following data were obtained from the question:

Mass of CaCO₃ = 20.7 g

Actual yield of CaO = 6.81 g

Theoretical yield of CaO =?

Percentage yield of CaO =?

The equation for the reaction is given below:

CaCO₃ —> CaO + CO₂

Next, we shall determine the mass of CaCO₃ that decomposed and the mass of CaO produced from the balanced equation. This can be obtained as follow:

Molar mass of CaCO₃ = 40 + 12 + (3×16)

= 40 + 12 + 48

= 100 g/mol

Mass of CaCO₃ from the balanced equation = 1 × 100 = 100 g

Molar mass of CaO = 40 + 16 = 56 g/mol

Mass of CaO from the balanced equation = 1 × 56 = 56 g

SUMMARY:

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

A. Determination of the theoretical yield of CaO.

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

Therefore, 20.7 g of CaCO₃ will decompose to produce =

(20.7 × 56)/100 = 11.59 g of CaO.

Thus, the theoretical yield of CaO is 11.59 g

B. Determination of the percentage yield.

Actual yield of CaO = 6.81 g

Theoretical yield of CaO = 11.59 g

Percentage yield of CaO =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 6.81/11.59 × 100

Percentage yield of CaO = 58.76%

Answer:

Therefore, the specific heat capacity of the iron is 0.567J/g.°C.

Note: The question is incomplete. The complete question is given as follows:

A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm.

Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits

Explanation:

Using the formula of heat, Q = mc∆T  

where Q = heat energy (Joules, J), m = mass of a substance (g)

c = specific heat capacity (J/g∙°C), ∆T = change in temperature (°C)

When the hot iron is placed in the water, the temperature of the iron and water attains equilibrium when the temperature stops changing at 27.6 °C. Since it is assumed that heat exchange occurs only between the iron metal and water; Heat lost by Iron = Heat gained by water

mass of iron  = 59.1 g, c = ?, Tinitial = 85.0 °C, Tfinal = 27.6 °C

∆T = 85.0 °C - 27.6 °C = 57.4 °C

mass of water = 100.0 g, c = 4.184 J/g∙°C, Tinitial = 23.0 °C, Tfinal = 27.6 °C

∆T = 27.6°C - 23.0°C = 4.6 °C

Substituting the values above in the equation; Heat lost by Iron = Heat gained by water

59.1 g * c * 57.4 °C  = 100.0 g * 4.184 J/g.°C * 4.6 °C

c = 0.567 J/g.°C

Therefore, the specific heat capacity of the iron is 0.567 J/g.°C.

Answer:

PbN₂O₆

Explanation:

Empirical formula is the simplest formula of a compound.

To find the empirical formula, we use the system below:

                                  Lead                      Nitrogen                Oxygen

Percentage

Composition              62.6                           8.4                          29

Molar mass                  207.2                         14                           16

Number of

Moles                        62.6/207.2                 8.4/14                     29/16

                                      0.302                        0.6                        1.813

Divide by the

smallest                     0.30/0.302                   0.6/0.302          1.813/0.302

                                            1                                  2                           6

Empirical formula is PbN₂O₆

The empirical formula of the compound containing 62.60% lead, 8.40% nitrogen, and 29.0% oxygen is PbN₂O₆ or Pb(NO₃)₂

From the question given above, the following data were obtained:

Lead (Pb) = 62.60%

Nitrogen (N) = 8.40%

Oxygen (O) = 29.0%

The empirical formula of the compound can be obtained as illustrated below:

Divide by their molar mass

Pb = 62.60 / 207 = 0.302

Nitrogen (N) = 8.40 / 14 = 0.6

Oxygen (O) = 29.0 / 16 = 1.8125

Divide by the smallest

Pb = 0.302 / 0.302 = 1

Nitrogen (N) = 0.6 / 0.302 = 2

Oxygen (O) = 1.8125 / 0.302 = 6

Thus, the empirical formula of the compound is PbN₂O₆ or Pb(NO₃)₂

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Explanation:

First determine the weight of the density bottle(A1) when it's empty.

Then fill it with the liquid you want to determine the density.

Then determine the weight of the bottle with the liquid(A2).

Then the weight of the liquid is equal to (A2 - A1)

You already know the volume of the bottle.

Apply them to density = weight/volume

Make sure to mention the temperature you measured it because density varies from one temperature to another.

Answer:

The thickness of the metal sheet is 0.162 centimeters.

Explanation:

If mass within the coin is uniformly distributed, then the density ([tex]\rho[/tex]), measured in grams per cubic centimeter, can be represented by the following formula:

[tex]\rho = \frac{m}{\frac{\pi}{4}\cdot D^{2}\cdot z }[/tex] (1)

Where:

[tex]m[/tex] - Mass, measured in grams.

[tex]D[/tex] - Diameter, measured in centimeters.

[tex]z[/tex] - Thickness, measured in centimeters.

If we know that [tex]m = 83.956\,g[/tex], [tex]D = 8.62\,cm[/tex] and [tex]\rho = 8.90\,\frac{g}{cm^{3}}[/tex], then the thickness of the coin is:

[tex]z = \frac{m}{\frac{\pi}{4}\cdot D^{2}\cdot \rho }[/tex]

[tex]z = \frac{83.956\,g}{\frac{\pi}{4}\cdot (8.62\,cm)^{2}\cdot \left(8.90\,\frac{g}{cm^{3}} \right) }[/tex]

[tex]z = 0.162\,cm[/tex]

The thickness of the metal sheet is 0.162 centimeters.

A. It is in the gas phase. The carbon dioxide in at -20°C and 1 atm pressure is in the gas phase.

Carbon dioxide is an odorless, colorless, barely acidic, and non-flammable gas at room temperature (20–25 C). A molecule having the chemical formula CO2 is carbon dioxide.

The general Y-shape of the phase diagrams for water and carbon dioxide is the same, although they are offset from one another. This change happens because the liquid phase in ice can occur at lower temperatures and pressures than it can in dry ice, which can only happen at greater temperatures and pressures.

A gas, solid, or liquid form of carbon dioxide is possible. Beer and soft drinks are generally carbonated using gaseous carbon dioxide. It also functions as a chemical in the purification of water.

To know more about the gas phase visit:

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#SPJ1

Answer:

E

Explanation:

Anything going down Column 1 is going to be more reactive than anything else.

So the only contenders that are in column 1  are Li and Cs. The most reactive ones are the ones going down.

Cs is at the bottom of column 1. The answer is E

Answer:

The molecular formula for sulfur hexafluoride is SF6 S F 6 , in which there is 1 sulfur atom and 6 fluorine atoms.

Explanation:

hope this helps

Answer:

54.66 liters

Explanation:

First of all, remember this. 1 mole equals 22.4 liters.

Second of all, to show your work use dimensional analysis.

Write 2.44 moles and then put moles on the bottom and liters on top.

2.44 moles of O * 22.4 liters / 1 mol of O

Moles will cancel out.

2.44 x 22.4 = 54.656

Usually I would have used sig figs. But the question said to round your answer to two digits after the decimal point.

54.656 rounds to the hundreths place.

So 54.656 = 54.66

All in all, the final answer is 54.66 liters(don't forget the units).

Hope it helped!

The mole fraction of the other gases : 0.52

Given

P tot = 2.5 atm

P x = 1.2 atm, n = 0.85 moles

Required

mole fraction

Solution

P tot = P gas X + P other gases

mol fraction = mol x : mol total

P gas X = mol fraction gas X x P total

1.2 atm = mol fraction gas X x 2.5 atm

mol fraction gas X = 0.48

mol fractionof the other gases = 1 - 0.48 = 0.52

Or we can use

P other gases = 2.5 - 1.2 = 1.3 atm

mol fraction the other gases = 1.3 : 2.5 = 0.52

Answer:

Chalcogen

Explanation:

Answer:

C2H8N

Explanation:

it wont change since there is no common factor between the 2:8:1 which will give us a whole number so it stays the same

Answer:

The answer is 79.904.

Explanation:

We assume you are converting between grams Br and mole.

You can view more details on each measurement unit:

molecular weight of Br or mol

The SI base unit for amount of substance is the mole.

1 grams Br is equal to 0.012515018021626 mole.

Note that rounding errors may occur, so always check the results.

Use this page to learn how to convert between grams Br and mole.

Type in your own numbers in the form to convert the units!

give 5 stars rn

Answer:

Compound 1 is molecular

Compound 2 is ionic

Compound 3 can't really be decided

Explanation:

A molecular substance does not conduct electricity, has very low melting and boiling points and is held together by very weak intermolecular forces.

An ionic substance conducts electricity in solution or in molten state but never in the pure solid state, has a high melting and boiling point and has a dull appearance most times.

Compounds 1 shows the properties of molecular substances hence it are designated as such.

On the other hand, compound 2 shows the properties of an ionic substance and is also designated as such.

We can't really decide on compound 3 because it shows some properties of ionic substances and some properties of molecular substances.

Answer:

See attached picture.

Explanation:

Hello!

In this case, according to the given instructions, on the attached picture you will find the required Lewis structure, whereas there is a double bond between the two carbon atoms, and one of those is bonded to the nitrogen; moreover the terminal carbon has two out of five hydrogen atoms, the middle carbon, one out of five and the nitrogen atom has two out of five hydrogen atoms; therefore the molecule would be ethenamine.

Best regards!