A 2 L balloon filled with gas is warmed from 280 K to 700 K. What is the volume of the gas after it is heated?

Answers

Answer 1

Answer:

New volume, v2 = 0.8L

Explanation:

Given the following data;

Original Volume = 2L

Original Temperature = 280K

New Temperature = 700K

To find new volume V2, we would use Charles' law.

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles is given by;

[tex] VT = K[/tex]

[tex] \frac{V1}{T1} = \frac{V2}{T2}[/tex]

[tex] \frac{V1}{T1} = \frac{V2}{T2}[/tex]

Making V2 as the subject formula, we have;

[tex] V_{2}= \frac{V1}{T1} * T_{2}[/tex]

[tex] V_{2}= \frac{2}{700} * 280[/tex]

[tex] V_{2}= 0.0029 * 280[/tex]

V2 = 0.8L

Therefore, the volume of the gas after it is heated is 0.8L.


Related Questions


An object is lifted upward at a constant speed. The gain in potential energy of the object is due to the
(A) work done on the object
(B) total force applied to the object
(C) weight of the object
(D)change in kinetic energy of the object
PLEASE HELP ME

Answers

Answer:

b

Explanation:

Do larger bodies orbit smaller bodies or do smaller bodies orbit larger bodies? Provide some examples to support your answer.

Answers

Explanation:

the small bodies in the solar system include comets, asteroids, the objects in the Kuiper Belt and the Oort cloud, small planetary satellites, Triton, Pluto, Charon, and interplanetary dust. As some of these objects are believed to be minimally altered from their state in the young solar nebula from which the planets formed, they may provide insight into planet Earth and the formation and evolution of the solar system.

A roller coaster is travelling 1 m/s at the top of the track. At the bottom of the track, 5 seconds later, it is travelling 36 m/s. What is the average acceleration?

7.2 m/s2
0.14 m/s2
36 m/s 2
7 m/s2

Answers

Answer:

7m/s²

Explanation:

Given parameters:

Velocity at the top = 1m/s

Velocity at the bottom  = 36m/s

Time  = 5s

Unknown:

Average acceleration = ?

Solution;

Acceleration is the rate of change of velocity with time. It is expressed as;

  A = [tex]\frac{v -u}{t}[/tex]

v is the velocity at the top

u is the velocity at the bottom

t is the time taken

 Now, insert the parameters and solve;

  A = [tex]\frac{36 - 1}{5}[/tex]   = 7m/s²

The average acceleration will be "7 m/s²".

Given values:

Top velocity,

v = 1 m/s

Bottom velocity,

u = 36 m/s

Time,

t = 5 s

The acceleration is:

→ [tex]A = \frac{v -u}{t}[/tex]

By putting the values,

       [tex]= \frac{36-1}{5}[/tex]

       [tex]= \frac{35}{5}[/tex]

       [tex]= 7 \ m/s^2[/tex]

Thus the answer above i.e., "option d" is correct.

Learn more about acceleration here:

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Three vectors , , and , each have a magnitude of 52.0 m and lie in an xy plane. Their directions relative to the positive direction of the x axis are 29.0 ˚, 191 ˚, and 311 ˚, respectively. What are (a) the magnitude and (b) the angle of the vector (relative to the +x direction in the range of (-180°, 180°)), and (c) the magnitude and (d) the angle of in the range of (-180°, 180°)? What are (e) the magnitude and (f) the angle (in the range of (-180°, 180°)) of a fourth vector such that ?

Answers

Answer:

a)   A´= A  

b)   θ₁´ = 29º,  θ₂´ = - 169º ,  θ₃´ = -49º

Explanation:

In this exercise you are asked to give the magnitudes and angles of the vectors from another system of

reference

a) The magnitudes

The magnitude of a vector, the size of which is a scalar, this does not depend on the reference system, since it is obtained by subtracting the coordinates of the end point minus the coordinate of the origin of the vector

          A = [tex]x_{f}[/tex]- x₀

if the vectors are measured in another reference frame

         x_{f}´ = xx_{f}- U

         x₀´ = x₀ -U

where U is the distance between the two reference frames

         A´ = x_{f}´ - x₀´

we substitute

         A´ = (x_{f} - U) - (x₀-U) = x_{f} - x₀

         A´ = A

 it does not change

b) Angles

The given angles are measured from the positive part of the x axis in a counterclockwise direction, it is asked to give these angles from the x axis

     θ₁ = 29º

     does not change

     θ₁´ = 29º

    θ₂ = 191º

   we measure clockwise

     θ₂´ = θ₂ - 360

     θ₂´ = 191 - 360

     θ₂´ = - 169º

     θ₃ =311º

    we measure clockwise

     θ₃´ = 311 -360

     θ₃´ = -49º

A box weighing 12,000 N is parked on a 36° slope. What will be the component of the weight parallel to the plane that balances friction *


Fg sin 36 degrees
Fg cos 36 degrees
Fg tan 36 degrees
Fg x N

Answers

Given :

A box weighing 12,000 N is parked on a 36° slope.

To Find :

What will be the component of the weight parallel to the plane that balances friction.

Solution :

The component of that will be parallel to the plane to balance friction is :

[tex]F \ cos ( 90 - 36)^o\\\\F\ ( sin\ 36^o)[/tex]

Therefore, component of force to balance friction is F sin 36° .

Hence, this is the required solution.

How far will you travel in 3.5 hrs if you have an average velocity of 90 km/hr

Answers

Answer:

The answer is 315 km

What quantities belong in cells X and Y?

X: centripetal acceleration
Y: period
X: tangential speed
Y: radius
X: radius
Y: centripetal acceleration
X: period
Y: tangential speed

Answers

Answer:

X: period

Y: tangential speed

Explanation:

100% on quiz your welcome(:

The quantities belonging in cells X and Y is to be considered as the

X: period

Y: tangential speed

Quantities belong in cells X and Y:

The equation for centripetal acceleration is

= v² / r

here,  v should be the tangential velocity of the body

And the radius of curvature.

So based on this, we can say that

Column X. Tangential Speed

Column Y. radius  

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The flaming gorge bridge, in wyoming rises above a dry gulch. If you throw a rock straight out from the bridge, horizontally, and the rock's horizontal displacement is 255 cm, what was the speed that you thew the rock

Answers

Answer:

12.495m/s

Explanation:

Horizontal displacement is the range of the projectile motion.

The range is expressed as;

R = 2U/g

U is the speed at which the rock is thrown (initial speed)

g is the acceleration due to gravity.

Given

R = 255cm = 2.55m

g = 9.8m/s²

Required

Speed U

Substitute the given parameters into the formula as shown;

2.55 = 2U/9.8

Cross multiply

2U = 2.55×9.8

2U = 24.99

U = 24.99/2

U = 12.495m/s

Hence the speed that you thew the rock is 12.495m/s

What is the root of all electrical systems?

1 batteries
2 electrons
3 atoms
4 non of the above

Answers

Answer:

I believe it's 2. I am not sure though.

Which of the following statements is correct.
A. A direct relationship exists between frequency and wavelength, as the frequency increase from Radio waves to Gamma rays so does the wavelength.
B. A direct relationship exists between frequency and wavelength, as the frequency decrease
from Radio waves to Gamma rays so does the wavelength.
C. An indirect relationship exists between frequency and wavelength, as the frequency increase
from Radio waves to Gamma rays the wavelength decrease.
D. An indirect relationship exists between frequency and wavelength, as the frequency decrease
from Radio waves to Gamma rays Wie wavelength increase

Answers

The answer is C, as the frequency gets higher the wavelength gets shorter

Two forces act on a 6.00-kg object. One of the forces is 10.0 N. If the object accelerates at 2.00 m/s2
,
what is the greatest possible magnitude of the other force?

Answers

Given :

Two forces act on a 6.00-kg object. One of the forces is 10.0 N.

Acceleration of object 2 m/s².

To Find :

The greatest possible magnitude of the other force.\

Solution :

Let, other force is f.

So, net force, F = 10 + f.

Now, acceleration is given by :

[tex]a=\dfrac{F}{mass}\\\\a= \dfrac{10+f}{6}\\\\\dfrac{10+f}{6}=2\\\\f = 12 - 10\\\\f = 2 \ N[/tex]

Therefore, the greatest possible magnitude of the other force is 2 N.

Hence, this is the required solution.

If an object has a fast velocity, the dots on a ticker tape diagram will be _____.

very long
far apart
very short
close together

Answers

Answer:

If an object has a fast velocity, the dots on a ticker tape diagram will be far apart.

I’m pretty sure the answer is “very long”

Una fuerza resultante constante de módulo igual a 40 [N], actúa sobre un cuerpo que se mueve en línea recta.¿Que distancia ha recorrido ese cuerpo si su energía cinética varió en 8 [J]?

Answers

Responder:

0,2 m

Explicación:

Usando la fórmula para calcular el trabajo realizado expresada como;

Workdone = Fuerza * Distancia

Dado

Fuerza = 40N

Trabajo realizado = 8 julios

Necesario

Distancia

Sustituya los parámetros dados en la fórmula como se muestra;

Distancia = Trabajo / Fuerza

Distancia = 8/40

Distancia = 0,2 m

Por tanto, el cuerpo recorrió una distancia de 0,2 m

Answer if you know

If you give me a good explanation on how quantum mechanics work, you get 20 points and possibly a brainliest.

Answers

Answer:

spectra.

Atomic spectra is series of colored lines which occures when atoms emit light of certain wavelengths. Element produces a particular set of spectral lines.

Electrons exist in shells and each shell has a specific energy. Electrons absorb photons and jump to higher energy levels.

Explanation:

Calculate the p.e. of a 5 kg mass when it is (i) 3 m, (ii) 6 m, above the ground. (g = 10 N/kg)​

Answers

Explanation:

P.E=MGH

(1) P.E=5×10(G)×3

= 150 kg m^/s^ ( ^ =sqaure)

(2) P.E=5×10×6

= 300 kg m^/s^

Hope it helps, just remember the formula u can solve any question regarding gravition of earth (P.E=Mgh)

the gravitational field strength on mars is 3.7n/kg

Answers

Answer:

True

Explanation:

Is Time and Light both connected in anyway?​

Answers

Answer:

It is not connected by any way

1. Calculate the pressure of an object with an area of 10m2 force of 5N exerted
on it​

Answers

Answer:

2

Explanation:

pressure(p)=force(f)\area(a)

A constant force acting on a body of mass 2 kg changes its
velocity from 1 m/s to 2 m/s in 20 s. If the direction of motion of
the body remains unchanged, the magnitude of the force that acted
on the body was 0.1 N.
True or False

Answers

Answer:

the correct answer is b

Answer:

true

Explanation:

just did it on ck12 lol

A bar magnet is a permanent magnet, While an electromagnetic temperary?​

Answers

yes an electromagnetic is temporary

Do you always need
more than one reactant
or more than one
product to have a
chemical reaction?

Answers

Answer:

no

Explanation:

Determine the gain in the potential energy when a 8.0 kg box is raised 17.2 m.

Answers

Answer:

The answer is 1376 J

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 8 × 10 × 17.2

We have the final answer as

1376 J

Hope this helps you

Explanation:

potential energy = mgh

potential energy = 8 * 10 * 17.2

potential energy = 1376 joules

A car accelerates uniformly from rest to a final speed of 19 m/s in 10. seconds. How far does it travel during this period of acceleration?

Answers

Answer:

x = 95 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f} =v_{o} +a*t[/tex]

where:

Vf = final velocity = 19 [m/s]

Vo = initial velocity = 0 (starts from the rest)

a = acceleration [m/s²]

t = time = 10 [s]

Now we can find the acceleration

19 = 0 *a*(10)

a = 1.9 [m/s]

With the second equation we can find the distance:

[tex]v_{f} ^{2} =v_{o} ^{2} +(2*a*x)[/tex]

where:

x = distance [m]

(19)² = (0)² + (2*1.9*x)

3.8*x = 361

x = 95 [m]

In a physics lab, students take a long piece of string and cut it into two unequal pieces. One piece is used to suspend a large weight. The second piece is tied to the bottom of the weight as seen in the diagram below. Student 1 predicts that the upper string will always break first since it has to support the weight and the applied force, while Student 2 disagrees and predicts that the shorter piece of string will always break first if you pull slowly but with enough force to exceed the strength of the string.

(a) Which aspect(s) of Student 1’s reasoning, if any, are correct? Explain your answer.


(b) Which aspect(s) of Student 2’s reasoning, if any, are correct? Explain your answer.


(c) Which aspect(s) of both Student 1’s and 2’s reasoning, if any, are incorrect? Explain your answer.

(d) The experiment is performed and both students are surprised to learn that whether
the upper or lower string breaks first depends on whether you pull slowly or with a
sudden pull. Resolve the two lines of reasoning of Student 1 and Student 2 by
explaining the results of the experiment in a clear, concise paragraph.

Answers

Answer:

(a) The aspect of the upper string supporting the weight and the applied force

Student 1 is correct because the upper string is the source of support of the large weight and the force applied to the short string reacts at the support of the long string

(b) The aspect of Student's (2) reasoning that is correct is that the shorter piece of string will always break first, however, the statement is only true for sudden pull due to the increased force experienced by the shorter string from a more rapid change in momentum

(c) The aspect of Student 1's statement that is incorrect is the that the upper string will always break first

The aspect of Student 2's statement that is incorrect is the that the shorter piece of string will always break first

(d) A string will break when subject to a force equivalent to its breaking force. The force experienced by the string increases as the rate of pull (suddenness) increases and the suddenness increases inversely with the length of the string, as such the shorter lower string will break first from a sudden pull before the force of the pull is completely transmitted to the upper string. Whereby the lower string is slowly pulled, the force is evenly transmitted to the upper string which is then taking up the load of the weight and the applied force together and is likely to break first

Explanation:

1. A pumpkin with a mass of 2 kg accelerates 2 m/s/s when an unknown force is applied to it. What is the amount of the force? ​

Answers

Answer:

The answer is 4 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 2 × 2

We have the final answer as

4 N

Hope this helps you

1. Day and Night are caused by
10 points
A. The Tilt of the Earth’s Axis.
B. Earth’s Revolution around the sun
C. Earth's ellipical orbit
D. Earth's rotation on its axis.

Answers

answer : D , I know i’m correct !

When the car was stopped by the tree, its change in velocity during the collision was -6 meters/second. This change in velocity occurred in 2 seconds. What was the acceleration of the car?

Answers

6 meters per second

You will need to add six two times to find the acceleration

s the statement, "You run faster than I do," qualitative or quantitative?

Answers

Answer:

qualitative, its an expression, not specific #'s

Explanation:

It is Qualitative

What is Qualitative or Quantitative?

Quantitative : Data is number based , countable or measurable

Qualitative : Data is interpretation based , descriptive and relating to language

Since , the statement given in question does not in include any kind of number or measurable quantity and its just an descriptive and relating to language . It is Qualitative

Learn more about Qualitative or Quantitative:

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If Chris throws the baseball 60 meters forward in 4.2 sec, what is the velocity of the ball? I need answer immediately

Answers

Answer:

14.3 m/s

Explanation:

velocity equation

v= d/t

v= 60/4.2

v=14.28

round it to 1 decimal place

v= 14.3m/s

15. Which element will donate electrons?
nitrogen
chlorine
aluminum
sulfur

Answers

I think its nitrogen sorry if I’m wrong
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