A 31.4 mL sample of nitrogen gas was collected over water at 23.7°C and a total pressure of 706 torr. What mass of nitrogen gas was collected

Answer:

a it is a

Explanation:

cause i know

The creation of a sugar solution by adding sugar to water then stirring the mixture, then the mass of the sugar and water is the same as the mass of the sugar solution.

A particular kind of homogenous combination made up of two or more components is known as a solution. A solute is a material that has been dissolved in a solvent, which is the other substance in the combination.

A physical process, not a chemical one, takes place when a solute and a solvent combine to produce a solution. When combined, miscible substances like gases form a single phase in all ratios. Phase-separating substances are immiscible.

When one material dissolves, or separates into another, a solution is created. A solute is the name for the material that dissolves to create a solution. A solvent is the material that a solute will dissolve in. Sugar is the solute and water is the solvent in a sugar-water solution.

Thus, option A is correct.

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Answer:

i think it's C or D.

Explanation:

but if I had to choose i would pick D. sorry if it's wrong. but i hope it's right.

Answer:

D was not correct

Explanation:

Answer:

Explanation:^^

EAS reaction has been the reaction in which the Hydrogen atom of the aromatic ring has been replaced or substituted by the electrophilic group at the ortho, para, or meta position.

1. The reaction of Nitration of methyl benzoate will yield, methyl m- nitrobenzoate as the major product.

The minor products in the reaction will be the dinitro products. The mono nitration product will be  

2. The major product formed with the nitration of methyl meta nitrobenzoate has been the dinitro product.

3. The impurity in the methyl m nitrobenzoate can be determined with the determination of the melting point of the compound. The presence of the impurity will change the melting point of the product.

The purity can be determined with the proton NMR analysis, to confirm the product.

4. The difference expected in the NMR spectra of methyl benzoate and methyl m-nitrobenzoate has been the peaks with the methyl benzoate are predominated in the spectra will in the nitro compound, the peaks have been varied with the pi transitions in the structure.

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Answer:

this is not chemistry

Explanation:

not chemistry

Answer:

In drawing the Lewis structure for C2H2 (also called ethyne) you'll find that you don't have enough valence electrons available to satisfy the octet for each element (if you use only single bonds). The solution is to share three pairs of valence electrons and form a triple bond between the Carbon atoms in C2H2 .

Answer: Magnetic marbles will tend to attract each other

when an atom gains or loses an electron, it becomes an ion. Ions formed by the loss of an electron have a positive charge, and those formed by gaining an electron have a negative charge. Positive ions are called cations, and negative ions are called anions.

Answer: One of the foods was sour and one was sweet

Explanation:

The sweet one has changed because it has more sugar then the sour one, It either got moldy or melted.

Answer:

-7.6755

Explanation:

Calculate

I calculate it

Answer:

so here is the answer

Explanation:

Kinetic is the answer.

Answer:

4.2x10⁻⁴ M or 0.032 g/L.

Explanation:

Hello!

In this case, for solubility product problems, we apply the concepts of equilibrium because an insoluble salt is ionized until a certain point limited by the solubility product constant, Ksp. Thus, we first write the ionization reaction of aluminum hydroxide at equilibrium:

[tex]Al(OH)_3(s)\rightleftharpoons Al^{3+}(aq)+3OH^-(aq)[/tex]

Next, we write the corresponding equilibrium expression:

[tex]Ksp=[Al^{3+}][OH^-]^3[/tex]

Which in terms of [tex]x[/tex], the reaction extent, is:

[tex]Ksp=x*(3x)^3[/tex]

Because [tex]x[/tex] also represents the molar solubility of aluminum hydroxide at the considered temperature; now, we can write:

[tex]8.1x10^{-13}=x*(3x)^3[/tex]

Which can be solved for x as follows:

[tex]x=\sqrt[4]{\frac{8.1x10^{-13}}{27} } \\\\x=4.2x10^{-4}M[/tex]

Thus, the solubility is 4.2x10⁻⁴ M or mol/L and in g/L we have:

[tex]4.2x10^{-4}\frac{mol}{L}*\frac{78g}{1mol} =0.032\frac{g}{L}[/tex]

Best regards!

Answer:

Mass ratio: 71:112

Atomic ratio: 2:7

Explanation:

1. To get the mass ratio of of the compound Cl2O7, the following steps are followed:

- The atomic mass of Cl = 35.5g/mol, O = 16g/mol

- The mass of each element in the compound is as follows:

Cl2 = 35.5(2) = 71g

O7 = 16(7) = 112g

The mass ratio is the ratio of one mass of an element to another in the compound, hence, the mass ratio is 71:112

- The molar mass of the compound, Cl2O7, is determined:

71 + 112 = 183g/mol

- The mass percent of each element is determined by dividing the mass of each element present by the Molar Mass:

Cl = 71/183 = 0.3879 × 100 = 38.8%

O = 112/183 = 0.612 × 100 = 61.2%

2. Atomic ratio is the ratio of one atom in a molecule to another. It can be calculated this:

In Cl2O7, there are 9 total atoms (2 atoms of Cl + 7 atoms of oxygen).

Hence, that atomic ratio of Cl to oxygen in Cl2O7 is 2:7

The mass ratio of Cl₂O₇ is 71:112 and atomic ratio of Cl₂O₇ is 2:7.

Mass ratio define as the ratio of the masses of constitute particles of the compound and atomic ratio is define as the ratio of the numbers of atoms present in that compound.

Given compound = Cl₂O₇

Mass of chlorine = 2×35.5 = 71g

Mass of oxygen = 7×16 = 112g

Mass ration of Cl₂O₇ is 71:112

And atomic ratio of Cl₂O₇ is 2:7

Hence, 71:112 is the mass ratio and atomic ratio is 2:7.

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Answer:

3.80x1024 grams containing if not that then above 80 grams 6 grams

Explanation:

Answer:

C

Explanation:

plato

3.80 x10^24

Answer:

I think that gravity can be considered a force.

Explanation:

As the object falls, it moves faster and faster. Gravity is considered a universal force because it acts between any two masses anywhere in the universe. For example, there is a gravitational pull between the Sun and the Moon. Even small masses attract one another.

Hope this helped! :)

Answer:

1. The empirical formula is C₄H₅N₂O

2. The molecular formula is C₈H₁₀N₄O₂

Explanation:

The following data were obtained from the question:

Mass of compound = 200 g

Carbon (C) = 98.061 g

Hydrogen (H) = 10.381 g

Oxygen (O) = 32.956 g

Empirical formula =?

Molecular formula =?

Next, we shall determine the mass of nitrogen in the compound. This can be obtained as follow:

Nitrogen (N) = 200 – (98.061 + 10.381 + 32.956)

Nitrogen (N) = 200 – 141.398

Nitrogen (N) = 58.602 g

1. Determination of the empirical formula of the compound.

C = 98.061 g

H = 10.381 g

O = 32.956 g

N = 58.602 g

Divide by their molar masses

C = 98.061 /12 = 8.172

H = 10.381 /1 = 10.381

O = 32.956 /16 = 2.060

N = 58.602 /14 = 4.186

Divide by the smallest

C = 8.172 /2.060 = 4

H = 10.381 / 2.060 = 5

O = 2.060 / 2.060 = 1

N = 4.186 / 2.060 = 2

Thus, the empirical formula of the compound is C₄H₅N₂O

2. Determination of the molecular formula of the compound.

Empirical formula of the compound => C₄H₅N₂O

Molar mass of compound = 194.101 g/mol

Molecular formula =.?

[C₄H₅N₂O]n = 194.101

[(12×4) + (1×5) + (14×2) + 16]n = 194.101

[48 + 5 + 28 + 16]n = 194.101

97n = 194.101

Divide both side by 97

n = 194.101 /97

n = 2

Molecular formula => [C₄H₅N₂O]n

=> [C₄H₅N₂O]2

=> C₈H₁₀N₄O₂

Answer:

a. the lithosphere

Explanation:

google

Answer:

0.07 M

Explanation:

Given data:

Volume of NaOH = 50.0 mL

Molarity of NaOH = 0.2 M

Volume of H₃PO₄ =  50.0 mL

Concentration of H₃PO₄ = ?

Solution:

3NaOH + H₃PO₄    →   Na₃PO₄  +  3H₂O

Number of moles of NaOH react:

Molarity = number of moles / volume in L

0.2 M = number of moles = 0.05 L

Number of moles = 0.01 mol

Now we will compare the moles of NaOH  with  H₃PO₄ .

          NaOH        :       H₃PO₄

             3             :          1

           0.01          :       1/3×0.01 = 0.0033

Concentration of H₃PO₄:

Molarity = number of moles / volume in L

Molarity = 0.0033 mol / 0.05 L

Molarity = 0.07 M

Answer:

A.) 0.07M

Explanation:

I got it right in class!

Hope this Helps!! :))

Answer:

Oxygen and simple sugars.

Explanation:

Water, sunlight and carbon dioxide is taken in to photosynthesise and the product would be oxygen that is breathed out through the stomata and simple sugars that are used as fuel for the plant.  

Answer:

5.7 moles of O2

Explanation:

We'll begin by writing the balanced decomposition equation for the reaction. This is illustrated below:

2KClO3 —> 2KCl + 3O2

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Next, we shall determine the number of mole of O2 produced by the reaction of 3.8 moles of KClO3.

Since 100% yield of O2 is obtained, it means that both the actual yield and theoretical yield of O2 are the same. Thus, we can obtain the number of mole of O2 produced as follow:

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Therefore, 3.8 moles of KClO3 will decompose to produce = (3.8 × 3)/2 = 5.7 moles of O2.

Thus, 5.7 moles of O2 were obtained from the reaction.

Answer:

a. 0.17 M

b. 0.066 M

Explanation:

a.

Step 1: Given and required data

Pressure of CO₂ (P): 5.0 atm

Henry's law constant for CO₂ (k): 3.3 × 10⁻² M atm⁻¹

Step 2: Calculate the molar concentration (C) of CO₂

We will use Henry's law.

C = k × P

C = 3.3 × 10⁻² M atm⁻¹ × 5.0 atm

C = 0.17 M

b.

Step 1: Given and required data

Pressure of CO₂ (P): 2.0 atm

Henry's law constant for CO₂ (k): 3.3 × 10⁻² M atm⁻¹

Step 2: Calculate the molar concentration (C) of CO₂

We will use Henry's law.

C = k × P

C = 3.3 × 10⁻² M atm⁻¹ × 2.0 atm

C = 0.066 M

Answer:

A

Explanation:

as the temperature and speed is higher pressure will be higher

as the temperature is higher particles will be more active

and as speed is they will collide with more force

so the pressure will be higher in container B

The pascal is sorthand for N/m^2

Answer:

a. 100%

b. 133%

c. 300%

Explanation:

To find yield first we need to determine theoretical yield converting each reactant to moles and find limitng reactant for each reaction:

Moles A:

4.5g * (1mol / 150g) = 0.03 moles

Moles B:

4.0g * (1mol / 100g) = 0.04 moles

a. For a complete reaction of 0.03 moles of A are needed:

0.03 moles A * (1 mole B / 3 moles A) = 0.01 moles of B

As there are 0.04 moles of B, A is limiting reactant.

Theoretical moles and mass of C are:

0.03 moles A * (1 mole C / 3 moles A) = 0.01 moles of C.

0.01 moles of C * (200g / mol) = 2g are produced.

Yield is:

2g / 2g * 100 = 100%

b. For a complete reaction of 0.03 moles of A are needed:

0.03 moles A * (3 mole B / 2 moles A) = 0.045 moles of B

As there are 0.04 moles of B, B is limiting reactant.

Theoretical moles and mass of C are:

0.04 moles B * (1 mole C / 3 moles B) = 0.0133 moles of C.

0.0133 moles of C * (200g / mol) = 2.67g are produced.

Yield is:

2.67g / 2g * 100 = 133%

c. For a complete reaction of 0.03 moles of A are needed:

0.03 moles A * (1 mole B / 1 moles A) = 0.03 moles of B

As there are 0.04 moles of B, A is limiting reactant.

Theoretical moles and mass of C are:

0.03 moles A * (1 mole C / 1 moles A) = 0.03 moles of C.

0.03 moles of C * (200g / mol) = 6g are produced.

Yield is:

6g / 2g * 100 = 300%

Answer:

I think it's b because I heard the others

The correct answer is option A: acetone.

For a substance to be classified as an alcohol it must posses the -OH functional group. Compounds that posses this -OH functional group usually have the ending -ol.

Acetone is a ketone, this is evidenced by the ending -one. It has the functional group -C=O.

Hence, acetone is not alcohol. The structure of acetone is shown in the image attached.

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Answer:

Metal, Copper, and Alluminum

Explanation: It is what it is

Answer:

The answer is False

hope this helpes

Answer:

8.279

Explanation:

The pH can be determined by hydrolysis of a conjugate base of weak acid at the equivalence point.

At the equivalence point, we have

[tex]$n_{NaOH}=n_{HNO_2}$[/tex]

           = 25.00 x 0.200

           = 5.00 m-mol

           = 0.005 mol

Volume of the base that is added to reach the equivalence point is

[tex]$\frac{0.005}{1.00} \times 1000= 5.00 \ mL$[/tex]

Number of moles of [tex]$NO^-_{2}=n_{HNO_2}$[/tex]

                                           = 0.005 mol

Volume at the equivalence point is 25 + 5 = 30.00 mL

Therefore, concentration of [tex]$NO^-_{2}= \frac{5}{30}$[/tex]

                                                        = 0.167 M

Now the ICE table :

            [tex]$NO^-_2 + H_2O \rightarrow HNO_3 + OH^-$[/tex]

I (M)       0.167                   0            0

C (M)         -x                      +x          +x

E (M)      0.167-x                  x           x

Now, the value of the base dissociation constant is ,

[tex]$K_w=K_a \times K_b$[/tex]            [tex]$(K_w \text{ is the ionic product of water })$[/tex]

[tex]$K_b =\frac{K_w}{K_a}$[/tex]

[tex]$K_b =\frac{1 \times 10^{-14}}{4.6 \times 10^{-4}}$[/tex]

    = [tex]$2.174 \times 10^{-11}$[/tex]

Base ionization constant, [tex]$K_b = \frac{\left[HNO_2\right] \left[OH^- \right]}{\left[NO^-_2 \right]}$[/tex]

[tex]$2.174 \times 10^{-11}=\frac{x^2}{0.167 -x}$[/tex]

[tex]$x= 1.9054 \times 10^{-6}$[/tex]

So, [tex]$[OH^-]=1.9054 \times 10^{-6 } \ M$[/tex]

pOH =- [tex]$\log[OH^-]$[/tex]

       = [tex]$- \log(1.9054 \times 10^{-6} \ M)$[/tex]

        =5.72

Now, since pH + pOH = 14

           pH = 14.00 - 5.72

                = 8.279

Therefore the ph is 8.279 at the end of the titration.

Titration is a chemical process used to determine the concentration of an unknown sample from the known sample. At the equivalence point, the pH is 8.279.

In titration, the point at which the titrant neutralizes the unknown analyte solution is called the equivalence point.

The moles of equivalence point of sodium hydroxide and nitrous acid are:

[tex]\begin{aligned}\rm n_{NaOH} &= \rm n _{HNO_{2}}\\\\&= 25.00 \times 0.200\\\\&= 0.005 \;\rm mol\end{aligned}[/tex]

The volume of the added base is 5.00 mL.

The moles of nitrogen dioxide are 0.005 moles and the volume at the equivalence point is 30 mL.

The molar concentration of nitrogen dioxide will be, 0.167 M.

From the ICE table, the base dissociation constant is calculated as:

[tex]\begin{aligned}\rm K_{w} &= \rm K_{a} \times K_{b}\\\\\rm K_{b} &= \dfrac{1 \times 10^{-14}}{4.6 \times 10^{-14}}\\\\&= 2.174 \times 10^{-11}\end{aligned}[/tex]

The ionization constant of the base is given as,

[tex]\begin{aligned}\rm K_{b} &= \rm \dfrac{[HNO_{2}][OH^{-}]}{[NO_{2}^{-}]}\\\\2.174 \times 10^{-11} &= \rm \dfrac{x^{2}}{0.167- x}\\\\&= 1.905 \times 10^{-6} \end{aligned}[/tex]

Now, pOH is calculated as:

[tex]\begin{aligned} \rm pOH &=\rm - log [OH^{-}]\\\\&= \rm -log (1.905 \times 10^{-6})\\\\&= 5.72\end{aligned}[/tex]

The pH of the titration is calculated as:

[tex]\begin{aligned} \rm pH + pOH &= 14\\\\\rm pH &= 14.00 - 5.72\\\\&= 8.279\end{aligned}[/tex]

Therefore the pH is 8.27.

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Answer:

Gas D

Explanation:

liters at 30 °C