A 6.00-kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the end of the rope, and the height of the crate above its initial position is given by y(t)=(2.80m/s)t+(0.610m/s^3)t^3. What is the magnitude of F when t = 4.00 s?

Answer:

Explanation:

It’s devastating because when a earthquake is 7.7 magnitude the

Answer: water freezes and expands in the crevice

Explanation:

Answer:

Water freezes and expands in the crevice

Explanation:

The distance walked by the woman at the given speed an time, is 15 miles.

The speed of an object is defined as the rate of change of the distance travelled by the object.

Here,

Speed with which the woman is walking,

v = 5 miles/hour

Time taken by the woman for walking,

t = 3 hours

We know speed is the rate of change of distance,

v = d/t  where d is the distance travelled by the woman

So, d = v x t

 d = 5 x 3

 d = 15 miles

Hence,

The distance walked by the woman at the given speed an time, is 15 miles.

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answer is convex mirror

Explanation:

A

Because convex mirror will provide maximum view

Answer:

a 10 kg bag of hot water at the same temperature

Explanation:

A 10kg bag of hot water at the same temperature will retain heat much better and keep the tent warmer at night compared to the iron pellet.

Answer:

D. 45 N​

Explanation:

The weight of the block is 20 N, when the block is fully immerged in water, it weighs 15 N. Hence the loss of weight = 20 N - 15 N = 5 N.

The loss of weight is as a result of the buoyant force. The buoyant force is the upward force exerted by a fluid when an object is fully or partially immersed in a fluid.

The buoyant force of 5 N acts in the upward direction, the weight of the beaker that would be read by the scale when the beaker is immersed in water = 40 N + 5 N = 45 N

Answer:

The charge of the negative one is 13.27 microcoulombs and the positive one has a charge of 58.27 microcoulombs.

Explanation:

Electric potential energy between two point charges is derived from concept of Work, Work-Energy Theorem and Coulomb's Law and described by the following formula:

[tex]U_{e} = \frac{k\cdot q_{A}\cdot q_{B}}{r}[/tex] (1)

Where:

[tex]U_{e}[/tex] - Electric potential energy, measured in joules.

[tex]q_{A}[/tex], [tex]q_{B}[/tex] - Electric charges, measured in coulombs.

[tex]r[/tex] - Distance between charges, measured in meters.

[tex]k[/tex] - Coulomb's constant, measured in kilogram-cubic meters per square second-square coulomb.

If we know that [tex]U_{e} = -24\,J[/tex], [tex]q_{A} = 45\times 10^{-6}\,C+ q_{B}[/tex], [tex]k = 9\times 10^{9}\,\frac{kg\cdot m^{3}}{s^{2}\cdot C^{2}}[/tex] and [tex]r = 0.29\,m[/tex], then the electric charge is:

[tex]-24\,J = -\frac{\left(9\times 10^{9}\,\frac{kg\cdot m^{3}}{s^{2}\cdot C^{2}} \right)\cdot (45\times 10^{-6}\,C+q_{B})\cdot q_{B}}{0.29\,m}[/tex]

[tex]-6.96 = -405000\cdot q_{B}-9\times 10^{9}\cdot q_{B}^{2}[/tex]

[tex]9\times 10^{9}\cdot q_{B}^{2}+405000\cdot q_{B} -6.96 = 0[/tex] (2)

Roots of the polynomial are found by Quadratic Formula:

[tex]q_{B,1} = 1.327\times 10^{-5}\,C[/tex], [tex]q_{B,2} \approx -5.827\times 10^{-5}\,C[/tex]

Only the first roots offer a solution that is physically reasonable. The charge of the negative one is 13.27 microcoulombs and the positive one has a charge of 58.27 microcoulombs.

Answer:

C

Explanation:

Kinetic energy is the energy of motion. It has the most potential energy at the top but the most kinetic at the bottom after it's accelerated fully down the slope.

Answer:

[tex]3.3\cdot 10^3\:\mathrm{N}[/tex]

Explanation:

Impulse on an object is given by [tex]\mathrm{[impulse]}=F\Delta t[/tex].

However, it's also given as change in momentum (impulse-momentum theorem).

Therefore, we can set the change in momentum equal to the former formula for impulse:

[tex]\Delta p=F\Delta t[/tex].

Momentum is given by [tex]p=mv[/tex]. Because the truck's mass is maintained, only it's velocity is changing. Since the truck is being slowed from 26.0 m/s to 18.0 m/s, it's change in velocity is 8.0 m/s. Therefore, it's change in momentum is:

[tex]p=2500\cdot 8.0=20,000\:\mathrm{kg\cdot m/s}[/tex].

Now we plug in our values and solve:

[tex]\Delta p=F\Delta t,\\F=\frac{\Delta p}{\Delta t},\\F=\frac{20,000}{6}=\fbox{$3.3\cdot 10^3\:\mathrm{N}$}[/tex](two significant figures).

Answer:

1750km

Explanation:

Answer:

12.31 m/s

Explanation:

If we recall from the previous knowledge we had about speed,

we will know that:

speed = distance/ time.

As such:

The average speed of the rider bicycle is

average speed = total distance/ total time

Mathematically, it can be computed as:

[tex]v_{avg} = \dfrac{d+d}{\dfrac{d}{v_1}+ \dfrac{d}{v_2}}[/tex]

[tex]v_{avg} = \dfrac{2d}{\dfrac{d}{10 \ m/s}+ \dfrac{d}{16 \ m/s}}[/tex]

[tex]v_{avg} = \dfrac{2}{\dfrac{1}{10 \ m/s}+ \dfrac{1}{16 \ m/s}}[/tex]

[tex]v_{avg} = \dfrac{2}{\dfrac{13}{80 \ m/s}}[/tex]

[tex]\mathbf{v_{avg} =12.31 \ m/s}[/tex]

Answer:

A is the best character that defines an electron.

Answer:

Net force = 15 N

Explanation:

Given that,

Applied force on an object = 20 N

Frictional force = 5 N

We need to find the net force acting on the object.

Friction is an opposing force. It acts in the opposite direction.

Net force = Applied force - Frictional force

= 20 N - 5 N

= 15 N

Hence, the net force acting on the object is 15 N.

Answer:

sultan's displacement is

[tex]20 \sqrt{13} [/tex] km

Answer:

(a) the fundamental frequency of this string is 65 Hz

(b) the harmonics of the given frequencies are third and fourth respectively.

(c) the length of the string is 2.74 m

Explanation:

Given;

mass density of the string, μ = 3 x 10⁻³ kg/m

tension of the string, T = 380 N

resonating frequencies, 195 Hz and 260 N

For the given resonant frequencies;

[tex]195 = \frac{n}{2l} \sqrt{\frac{T}{\mu} } ---(1)\\\\260 = \frac{n+1}{2l} \sqrt{\frac{T}{\mu} } ---(2)\\\\divide \ (2) \ by (1)\\\\\frac{260}{195} = \frac{n+1 }{n} \\\\260n = 195(n+1)\\\\260 n = 195 n + 195\\\\260n - 195n = 195\\\\65n = 195\\\\n = \frac{195}{65} \\\\n = 3[/tex]

(c) From any of the equations, solve for Length of the string (L);

[tex]195 = \frac{n}{2l} \sqrt{\frac{T}{\mu} } \\\\195 = \frac{3}{2l}\sqrt{\frac{380}{3\times 10^{-3}} } \\\\l = \frac{3}{2\times 195}\sqrt{\frac{380}{3\times 10^{-3}} }\\\\l = 2.74 \ m[/tex]

(a) the fundamental frequency is calculated as;

[tex]f_o = \frac{1}{2l} \sqrt{\frac{T}{\mu} } \\\\f_o = \frac{1}{2\times 2.74} \sqrt{\frac{380}{3\times 10^{-3} } }\\\\f_o = 65 \ Hz[/tex]

(b) harmonics of the given frequencies;

the first harmonic (n = 1) = f₀ = 65 Hz

the second harmonic (n = 2) = 2f₀ = 130 Hz

the third harmonic (n = 3) = 3f₀ = 195 Hz

the fourth harmonic (n = 4) = 4f₀ = 260 Hz

Thus, the harmonics of the given frequencies are third and fourth respectively.

The plunger is transferring energy to the gas particles.

When Cecily is applying pressure to the plunger, the gas inside is being compressed, and the speed of gas molecules increases.

When these air molecules enter the tire, adiabatically, the temperature of the gas rises.

It happens due to an increase in the average kinetic energy of the gas particles.

Thus, the gas particles receive energy from the plunger.

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Answer:

The angular velocity of a person standing on the equator is approximately [tex]7.272\times 10^{-5}[/tex] radians per second.

Explanation:

The Earth rotates at constant speed. From Rotational Physics, the angular velocity ([tex]\omega[/tex]), measured in radians per second, is defined by the following formula:

[tex]\omega = \frac{2\pi}{T}[/tex] (1)

Where [tex]T[/tex] is the period of rotation of the Earth, measured in seconds.

If we know that [tex]T = 86400\,s[/tex], then the angular velocity of a person standing on the equator is:

[tex]\omega = \frac{2\pi}{86400\,s}[/tex]

[tex]\omega \approx 7.272\times 10^{-5}\,\frac{rad}{s}[/tex]

The angular velocity of a person standing on the equator is approximately [tex]7.272\times 10^{-5}[/tex] radians per second.

The object Earth, Sun, and Blood are constantly in motion. The correct option is A, D, and E.

if a body changes its position with respect to its surroundings in a given interval of time, Then the body is said to be in motion

.

Motion is generally classified as follows.:

i) Rectilinear motion.

ii) Circular motion.

iii) Rotational motion.

iv) Periodic motion.

The Earth is continuously in motion because it continuously revolves around The Sun in an elliptical orbit, due to which a year is 365 days. and also The earth rotates about its own axis once a day.

The Sun also revolves around the galactic center of our Milkyway galaxy. and it also rotates about its own axis continuously. so that the sun is also continuously in motion.

The Human blood is continuously in motion Because our blood is continuously circulating whole over the body with the help of our heart. The heart continuously pumps our blood and circulates it inside the human body.

Hence the Earth, Sun, and blood are continuously in motion.

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Answer:

The magnitude of the force = 7.2 × 10⁻¹⁵ C

Explanation:

The total quantization of charge q on an electron = n × e

where;

n = 30

e = 1.6 × 10⁻¹⁸ C

q = 30 ×  1.6 × 10⁻¹⁸ C

q = 4.8 × 10⁻¹⁸ C

Now, the magnitude of the force is determined by using the formula:

F = qE

F = ( 4.8 × 10⁻¹⁸ C) ( 1500  N/C)

F = 7.2 × 10⁻¹⁵ C

Answer:

Explanation:

The total distance travelled by ball before first bounce

= 160 + 160 = 320 ft

Distance travelled between first bounce and second bounce

= 80 + 80 = 160 ft

Distance travelled between second bounce and third bounce

= 40 + 40 = 80 ft

Distance travelled between third bounce and fourth bounce

= 20 + 20 = 40 ft .

Distance travelled in fourth bounce = 10 ft

Total distance travelled = 320 + 160 + 80 + 40 + 10

= 610 ft .

Answer:

Given :  A bus of mass 760 kg requires 120 m to reach certain velocity value Vf.

the bus engine exerts a constant forward force F.

To Find : When the bus is towing a 330-kg small car, how long distance needed to reach same Vf?

Solution:

V²  - U² = 2aS

V = Vf

U = 0

S = 120 m

=> Vf² - 0 = 2a(120)

=> Vf² = 240a

m = 760  kg

Force = F

F = ma

=> F =760 a

=> a = F/760

Vf² = 240F/760

Case 2  :When the bus is towing a 330-kg small car,

m = 760 + 330 = 1090 kg

a = F/1090

Vf²  = 2aS

=> 240F/760  = 2 (F/1090) S

=> S = 120 x 1090 /760

=> S = 172.1   m  

172.1   m   distance needed to reach same Vf

Explanation:

Answer:

80N/cm^2

Explanation:

Given data

A car of weight 6,400N

Area= 80cm^2

The weight is distributed evenly on the 4 wheels

hence 6400/4

=1600 N

We know that

Pressure = force/Area

Pressure= 1600/80

Pressure= 20 N/cm^2

For the four wheels, the pressure is

=20*4

=80N/cm^2

Answer:

[tex]9\:\mathrm{J}[/tex]

Explanation:

Kinetic energy is given by the following equation:

[tex]KE=\frac{1}{2}mv^2[/tex], where [tex]m[/tex] is mass in [tex]\mathrm{kg}[/tex] and [tex]v[/tex] is velocity in [tex]\mathrm{m/s}[/tex].

Since the cell phone's mass is given in grams, we need to convert this into kilograms:

[tex]80\:\mathrm{g}\cdot \frac{1\:\mathrm{kg}}{1000\:\mathrm{g}}=0.08\:\mathrm{kg}[/tex].

Therefore, the kinetic energy of the cell phone is:

[tex]KE=\frac{1}{2}\cdot 0.08\cdot 15^2=\fbox{$9\:\mathrm{J}$}[/tex].

Answer:

The coefficient of static friction between the object and the disk is 0.087.

Explanation:

According to the statement, the object on the disk experiments a centrifugal force due to static friction. From 2nd Newton's Law, we can represent the object by the following formula:

[tex]\Sigma F_{r} = \mu_{s}\cdot N = m\cdot \frac{v^{2}}{R}[/tex] (1)

[tex]\Sigma F_{y} = N - m\cdot g = 0[/tex] (2)

Where:

[tex]N[/tex] - Normal force from the ground on the object, measured in newtons.

[tex]m[/tex] - Mass of the object, measured in newtons.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]v[/tex] - Linear speed of rotation of the disk, measured in meters per second.

[tex]R[/tex] - Distance of the object from the center of the disk, measured in meters.

By applying (2) on (1), we obtain the following formula:

[tex]\mu_{s}\cdot m\cdot g = m\cdot \frac{v^{2}}{R}[/tex]

[tex]\mu_{s} = \frac{v^{2}}{g\cdot R}[/tex]

If we know that [tex]v = 0.8\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]R = 0.75\,m[/tex], then the coefficient of static friction between the object and the disk is:

[tex]\mu_{s} = \frac{\left(0.8\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.75\,m)}[/tex]

[tex]\mu_{s} = 0.087[/tex]

The coefficient of static friction between the object and the disk is 0.087.

Answer:

Essentials. A battery is a device that stores chemical energy and converts it to electrical energy. The chemical reactions in a battery involve the flow of electrons from one material (electrode) to another, through an external circuit. The flow of electrons provides an electric current that can be used to do work.

Answer:

The sun pulls with more force since the sun is more massive than the earth.

Explanation:

That your answer because the Earth is getting pulled by the gravitational pull from the Sun

Answer:

carbon.

Explanation:

the reaction would then create c02 as a product