A bike with mass of 10 kg is moving with a speed of 5 m/s. What is the magnitude of its momentum?​

Answer:

385 cm^3

Explanation:

375cm3 of a gas has a pressure of 770 mm Hg, find it Volume if the pressure is reduced to 750 mm Hg

​if we reduce the pressure, the volume increase since since PV is constant

so the new volume = 0.375 cm^3 X 770/750 = 385 cm^3

63

Answer:

MgCO 3 is an inorganic salt with chemical name Magnesium Carbonate. It is also called Magnesite or Hydromagnesite or Barringtonite. Hydrated forms of magnesite such as di, tri, tetrahydrates are present as minerals. It acts as a fertilizer and as an antacid.

The alcohol content is 450 proof

In the given example, the measurement of the alcohol content is said to be measured in alcohol proof.

We are going to multiply the given proof of the alcohol with the vodka drink divided by 100 to determine the content of alcohol in the alcoholic beverage.

i.e.

= (750 × 60)/100 proof

= 450 proof

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Answer:

C

Explanation:

Option C should be the correct one, since you have two methyl groups in the alkane (parent) chain.

Answer:

k im silly frrr lol have a great day

Answer :

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Concentration of Solutions

Recall that a solution consists of two components: solute (the dissolved material) and solvent (the liquid in which the solute is dissolved). The amount of solute in a given amount of solution or solvent is known as the concentration. The two most common ways of expressing concentration are molarity and molality.

Molarity

The molar concentration (M) of a solution is defined as the number of moles of solute (n) per liter of solution (i.e, the volume, V solution):

M = n / V solution

The units of molarity are mol/L, often abbreviated as M.

For example, the number of moles of NaCl in 0.123L of a 1.00M solution of NaCl can be calculated as follows:

[tex]0.123 \: l \: \: of \: solution \: \times \: \frac{1.00 \: mole}{1.00 \: l \: of \: solution \: } \: \\ = 0.123 \: moles[/tex]

Molality :

The molal concentration (m) of a solution is defined as the number of moles of solute (n) per kilogram of solvent (i.e., the mass of the solvent, msolvent):

[tex]m = \frac{n}{v \: solution} [/tex]

For example, the number of moles of NaCl dissolved in 0.123kg of H2O (the solvent), in order to make a 1.00m solution of NaCl, can be calculated as follows:

[tex]0.123 \: kg \: of \: solvent \: = \frac{1.00 \: mole}{1.00 \: kg \: of \: solvent \: } \\ = 0.123 \: moles[/tex]

Answer:

C8H12

Explanation:

First find the molar mass

195/1.8 × 1 = 108.3 gmol-1

Then the molecular formula

Mass of C in 1 mole of compound = 88.82×108.3/100

= 96.2 g

Mass of H in 1 mol of.the compound = 108.3×11.18/100 = 12.11 g

Divide the mass by their molar masses to get no. of moles in 108.3 g of compound or 1 mole of compound

Moles of C in one Mole of compound = 96.2g/12 gmol-1 = 8 mol

Moles of H in 1 mole of compound = 12.11g/1 gmol-1 =12 mol

Since we need the molecular formula it's C8H12

Answer:

A student performed titration to find the concentration of acetic acid. Titrant was sodium hydroxide. He went beyond the indicator color change by adding too much titrant.

Explanation:

hope it helps you

Answer:

D: Kinetic Energy​

Explanation:

Temperature is a measure of kinetic energy. Temperature is a measure of the average kinetic energy of the particles in an object. When temperature increases, the motion of these particles also increases.

Hope this helps :)

The water would stand at a height of 1033.6 cm

If the mass of the mercury, m equals the mass of the water, m' at its height,h', then the weight of the mercury W equals the weight of the water, W'

So, W = W'

mg = m'g

ρV = ρ'V' where ρ = density of mercury = 13.60 g/cm³, V = volume of mercury = Ah where A = cross-sectional area of tube = 1.00 cm and h = height of mercury = 76.0 cm, ρ' = density of water = 1.00 g/cm³, V = volume of water = Ah' where A = cross-sectional area of tube = 1.00 cm and h' = height of water.

So, ρV = ρ'V'

ρAh = ρ'Ah'

h' = ρAh/ρ'A

h' = ρh/ρ'

Substituting the values of the variables into the equation, we have

h' = ρh/ρ'

h' = 13.60 g/cm³ × 76.0 cm/1.00 g/cm³

h' = 13.60 × 76.0 cm

h' = 1033.6 cm

So, the water would stand at a height of 1033.6 cm

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Answer:

Explanation:

Determine the treatments you’ll be using on your eggs, and prepare the substances you’ll need. You can make salt-water solutions by dissolving different amounts of table salt in containers of water (e.g. 100g, 200g, 300g of salt (NaCl) per liter). You can make solutions of food coloring by adding a few drops of each color into containers of  

The Eggsperiment with Vinegar solution. The first experiment conducted was the egg placed in vinegar solution which allowed the egg to become soft and bouncy . Vinegar is a weak acid which is 5% acetic acid in water (meaning vinegar is largely just water). The egg has a shell that is made up of calcium carbonate   an air cell forms at the large end of the egg. While the embryo is growing, the shell membranes surround and contain the white or albumen of the egg. The albumen provides the liquid medium in which the embryo develops, and it also contains a large amount of the protein necessary for proper development. I hope this was hopeful

Answer:

Explanation:

These problems are pretty easy, you just need to do to the enthalpy what is done to the equation itself. Numbers one and 3 are reversed, so they become positive values. When a coefficient changes in the equation, you multiply the enthalpy by that number. I have attached my work below. Let me know if there is any confusion left.

Hope this helped! :^)

Answer: -13% to 3 sig figs

Explanation:

A piece of potato had an original mass of 3.2g and after being left in a sugar solution for 24 hours it then had a mass of 2.8g. Calculate the percentage mass decrease of the potato.

the change in mass is 2.8 -3.2 = -0.4 gm

the % change fro  the origial piece is ( -0.4/3.2) X 100 = -12.5%

or  -13% to 3 sig figs

Answer:

13.C

14.B

15.C

16.Chemical element

Chemical Element are called substance or element that cannot be decomposed or broken down into simpler substances by ordinary chemical process.

Chemical elements are those elements which cannot be chemically broken down into simpler substances and are primary constituents of all matter. They are fundamental ingredients of all matter in existence which can be combined in reaction to create chemical substance each chemical element in the universe has unique properties that distinguish it from all of the Other chemical elements. For example hydrogen is an element.

Hope that helps

Answer:

17) b

18) c

19) c

20) c

21) b

22) D

23) b

24) b

25) a

26)?

27) D

28) b

29) D

30) c

Answer:

Rb, Zn, P, S, F, Ca, Co, Cr

Rb, Zn, P, S, F, Ca, Co, Cr elements in order of decreasing metallic character.

The metallic character of an element is defined as the properties typical of metal, especially the tendency to lose electrons in chemical reactions.

Metallic character depends on the ability of an element to lose its outer valence electrons. Examples of properties related to metallic character include thermal and electrical conductivity, metallic lustre, hardness, ductility, and malleability. The most "metallic" element is francium, followed by caesium.

Hence, Rb, Zn, P, S, F, Ca, Co, and Cr elements in order of decreasing metallic character.

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Answer: 2.43 x 10^23 molecules

Explanation:

Molar mass of H2S: 2(1.008) + 32.06 = 34.1 g/mole

Avogadro’s number for converting moles to atoms or molecules: 6.02 x 10^23

(13.751375g H2S)(1 mole H2S)(6.02x10^23 molecules) / (34.1g/mole H2S)(1mole H2S) = 2.43 x 10^23 molecules H2S

Answer:

Glycerin

Explanation:

The stronger the intermolecular forces of attraction the more energy is required to break those forces, if you need more energy to break these forces it means that these certain elements would have a higher boiling point. Which is why the answer is Glycerin, the highest boiling point of an element means that it has the strongest forces, which in this case is electrostatic forces.

Answer:

Glycerin

Explanation:

Answer:

[tex]2al + 3h2so4 = > al2(so4)3 + 3h2 \\ eqvt \\ = > \frac{5.4}{27} = > \frac{5 \times 50}{1000} \\ .2 \: mol = > .25 \: mol \\ \\ so \: .25 \: is \: limiting \: reagent \\ according \: to \: ideal \: gas \: equation \\ pv = nrt \\ v = \frac{nrt}{p} \\ v = \frac{.25 \times .082 \times 300}{1} \\ = \frac{1}{4} \times 8.2 \times 3 \\ = 2.05 \times 3 \\ = 6.15litre \\ thank \: you[/tex]

Answer:

cotton

Explanation:

which is typically spun into fine yarn for mechanical weaving or knitting into cloth.

Answer:

The answer is A and B

Explanation:

Answer:

Use the Rydberg Equation 1/λ = R(1/n²(final) - 1/n²(initial) where R = 109,678 cm⁻¹. Substitute initial orbital number and final orbital number and solve for wavelength (λ).

Explanation:

Example:

Assume an electron transition from n = 5 to n = 2.

1/λ = 109,678cm⁻¹(1/2² - 1/5²) = 109,678(0.25 - 0.04)cm⁻¹ = 23,032cm⁻¹

λ = 1/23,032cm⁻¹ = 4.34 x 10⁻⁵cm x 10⁻²m/cm x 10⁹nm/m = 434nm

Answer: ELEMENT

Explanation:

Answer:

-106°C

Explanation:

1558 mmHg / 1 × 1 atm / 760. mmHg = 2.05 atm

PV = nRT

2.05 atm (10.0 L) = 1.50 mol (0.082 atmL/molK) T

20.5 atmL = (0.123 atmL/K) T

K/0.123 atm L × 20.5 atmL = (0.123 atmL/K) T × K/0.123 atmL

166.666 K = T

167 K = T (sig figs)

K = °C + 273

167 - 273 = °C - 273

-106 = °C

Answer:

The dipole forces (particularly H-bonds) that keep polar solute molecules together can be replaced by polar solute-solvent interactions, so substances that are predominantly polar (like glucose) dissolve in polar solvents like water but not in nonpolar solvents like hexane (H-bonds).

Explanation:

Answer:

ok

Explanation:

Answer:

false because if you round both of them

Answer:

You are correct it is NaCl

perdon no se es que es para que me dé ingreso

Explanation:

Our Direct Nanofiltration (dNF) membranes offer the unique combination of a low fouling hollow fiber configuration with the ability to remove organics and salinity (hardness) from water in one simple step. Other than a strainer, no further pre-treatment is required. We manufacture our membranes with a patented layer-by-layer process, where multiple nano-scale layers are deposited on a membrane support. This method enables very precise and controlled rejection and flux properties of the membrane. A unique solution for troubled water.