a block of lead has dimensions of 4.50 cm by 5.20 cm by 6.00 cm

From the idea that the KCN is made of two ions of opposite charge, then the compound is ionic.

We can say that a compound is ionic if the compound that is in question is composed of ions. Note that ions are species that are positively or negatively charged. As such, ionic compounds are essentially an ion pair and they are different from the covalent compounds.

The compounds that are covalent are the compounds that are forms when two atoms share electrons in a bond. In this case, there are no ions and we do not have species that have a full positive or negative charge as we do have with the ionic compounds that we discussed earlier here.

As we can see, the KCN compound is composed of the potassium ion that is positively charged as well as the cyanide ion that is negatively charged thus the compound must be said to be an ionic compound.

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A balloon with a pressure of 1 atm and a temperature of 17° Celsius has a volume of 1000 mL. The day warms up and increases the temperature to 27° Celsius, which makes the pressure change to 1520 mm Hg.What is the new volume of the balloon, in Liters?

The new volume of the balloon is 0.517 L.

By ideal gas law, PV = nRT

P = pressure

V = volume

n = number of mole of gas

R = gas constant

T = temperature

Using ideal gas law, P₁V₁/ T₁ = P₂V₂/ T₂

P₁= 1 atm

V₁ = 1000 mL = 1 L

T₁ = 17° C = 290 K

After the day warms up:-

P₂ = 1520 mm Hg = 2 atm

T₂ = 27° C = 300 K

Put these values in formula, P₁V₁/ T₁ = P₂V₂/ T₂

V₂ =  P₁V₁T₂/ T₁ P₂

V₂ = 1 atm× 1 L × 300 K/ 290 K × 2 atm

V₂ = 0.517 L = 517 mL

Hence, the new volume of the balloon is 0.517 L.

The ideal gas equation is formulated as: PV = nRT.

In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the overall quantity of ideal gas this is measured in terms of moles, R is the universal gas constant, and T is the temperature.

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The pressure inside the tire, assuming that the gas acts as an ideal gas, will be 1.6253 atm or 23.8 psi.

For calculations like these we utilize the ideal gas equation:
PV = nRT,
where P is the pressure exerted by the gas, V is the volume taken up by the gas, n is the amount of the gas (in moles), R is the universal gas constant (0.082057 Latm/molK) and T is the temperature (in Kelvins). Now we can say that:
P = nRT/V,
and plug all the known values into the equation:
P = 0.552 mol * 0.082057 Latm/molK * 305 K / 8.50 L = 1.6253 atm

Finally, because 1 atm = 14.7 psi, the pressure in the tire will be 1.6253 * 14.7 = 23.9 psi

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The volume of carbon dioxide gas produced at STP during the reaction is equal to 56 L.

Combustion reactions involve the complete oxidation of the fuel a hydrocarbon such reactions commonly liberate only carbon dioxide and water as products.

A hydrocarbon undergoes combustion to yield carbon dioxide and small amounts of water as the product. It can also be noted that no side products are left behind in the combustion reaction.

The given balanced combustion reaction of alcohol:

C₂H₅OH (l)  +  3O₂  (g) →  2CO₂  (g)  +  3 H₂O  (g)

One mole of the ethanol produced carbon dioxide = 2 mol

Then 1.25 mol of the alcohol produced carbon dioxide = 2.5 mol

The volume occupied by one mole of carbon dioxide = 22.4 L

The volume of  2.5 mol of CO₂ = 22.4 × 2 = 56 L

Therefore, the volume of CO₂ gas produced during the reaction is 56 L.

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Answer: 56L

Explanation: The volume of carbon dioxide gas produced at STP during the reaction is equal to 56 L.

1.615304584 ×10⁵⁸ ways can 100 new male students be assigned to these five halls.

A probability is a number that expresses the possibility or likelihood that a specific event will take place. Probabilities can be stated as proportions with a range of 0 to 1, or as percentages with a range of 0% to 100%.

Ways of selecting 10 students out of 100 =  C(100,10) for D1.  

After that 100-10 = 90 students are remaining.

Ways of selecting 5 students out of 90 is C(90,5) for D2.

Ways of selecting 15 students out of 90-5 = 85 is C(85,15) for D3.

Now number of remaining students is 85 -15 = 70.

Now for each of these 70 students we have 2 choices D4 and D5.

So these 70 students can be distributed in 2^70 ways.

So number of ways 100 new male students can be assigned to these five halls is

[tex]\begin{aligned}&=C(100,10) \cdot C(90,5) \cdot C(85,15) \cdot 2^{70} \\&=1.73 * 10^{13} * 43949268 * 1.798 * 10^{16} * 1.1806 * 10^{21} \\&=\mathbf{1 . 6 1 5 3 0 4 5 8 4} * \mathbf{1 0}^{58}\end{aligned}[/tex]

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Chemicals used and/or produced by businesses that, if released, might significantly harm people's health are known as toxic industrial chemicals (tic). The three examples of the tics that are readily available are anhydrous ammonia, hydrogen cyanide, and chlorine.

Chlorine is a material that is used in industries and is found in many items that are used in homes.

Chlorine occasionally manifests as poisonous gas. By applying pressure and chilling, chlorine gas can be transformed into a liquid that can be moved and stored. When liquid chlorine is released, it swiftly transforms into gas that spreads quickly and stays close to the ground.

The strong, unpleasant smell of chlorine gas, which is comparable to that of bleach, can be used to identify it. The pungent stink may give people enough warning that they are exposed.

The chlorine gas seems to be yellow-green in color.

Chlorine is not flammable on its own, but it can react explosively or combine with other chemicals, such as turpentine and ammonia, to form explosive compounds.

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All the stores in the fast food chain combined produce 28,952,381 pounds of carbon dioxide on a yearly level.

Because there's one dryer in the men's restroom and one in the ladies' restroom, we have two dryers per store. If each dryer operates 160 times per day per restroom, the total number of daily operations per store is 2 * 160 = 320. Because there are 6000 stores in North America, the total number of operations per day is 320 * 6000 = 1,920,000. Finally, because the stores in the fast food chain work 360 days a year, the number of hand dryer uses on a yearly level is 1,920,000 * 360 = 691,200,000.

Because each hand dryer use generates 19 g of CO2, the total mass of carbon dioxide produced on a yearly level is 19 g * 691,200,000 = 13,132,800,000 g. As each pound contains 453.60 grams, the approximate number of pounds produced is 13,132,800,000 / 453.60 = 28,952,381

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NO₂  is the example of fewer than eight number of valence electrons due to an odd no. of valence electrons.

N , atomic no. is 7 = 2 , 5

O , atomic no. is 8 = 2, 6

SCl₆ is the example of more than eight valence electrons due to an expanded octet.

S , atomic no. is 16 = 2 , 8 , 6

Cl , atomic no. is 17 = 2 , 8 , 7

BeF₂ is the example of fewer than eight valence electrons due to shortage of valence electrons.

Be, atomic no. is 4 = 2, 2

F , atomic no. is 9 = 2 , 7

These are the examples of odd no. of electrons, expanded octet due to more valence electron and less than eight valence.

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The final concentration of the KOH if 20.00 grams of KOH is added into distilled water and diluted with water to 1000 mL of final volume is 0.35 M.

We know that,

The molar mass of KOH is 56.10 g/mol

The mass of KOH is 20.00 g

To calculate number of moles of KOH -

Moles of KOH = Given mass

                           Molar mass

Moles of KOH =   20.00 g    

                           56.10 g/mol

Moles of KOH = 0.35 mol

The volume to be made up to 1000 mL = 1 L

The final concentration of KOH can be calculated as -

The molarity of solution is the ratio of number of moles to the total volume of solution in liters.

Molarity =  Number of moles

                 volume of solution

Molarity = 0.35 M

                    1

Molarity = 0.35 M

Therefore, the final concentration of the KOH is 0.35 M.

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The value of the equilibrium constant at 627 °C, based on equilibrium pressures, will be 44.1.

First, we write the balanced reaction equation:

2 SO₂(g) + O₂(g) → 2 SO₃ (g)

Based on the reaction equation, the expression for the equilibrium constant (Kp) will look like this:

[tex]K_{p} =\frac{(pSO_{3} )^{2} }{pO_{2}(pSO_{2} )^{2} }[/tex]

pSO₃ - partial pressure of sulfur(VI) oxide

pO₂ - partial pressure of oxygen

pSO₂ - partial pressure of sulfur(IV) oxide

To calculate Kp, we need the equilibrium pressures for all three gasses. We already know the pressure for sulfur(VI) oxide (1.10 atm), but we need to calculate it for oxygen and sulfur(IV) oxide as well.

Because the molar ratio of sulfur(IV) oxide and sulfur(VI) oxide is 1:1, that means that for the formation of 1.10 atm of sulfur(VI) oxide, 1.10 atm of sulfur(IV) oxide was expended, so the equilibrium pressure of SO₂ will be 1.48 atm - 1.10 atm = 0.38 atm.

We apply the same principle for oxygen, but because oxygen:sulfur(VI) oxide ratio is 1:2, only 1.10 atm / 2 = 0.55 atm of oxygen was expended for the formation of sulfur(VI) oxide, leaving us with the oxygen equilibrium pressure of 0.74 atm - 0.55 atm = 0.19 atm.

We plug these values into the expression above:

Kp = (1.10 atm)² / (0.19 atm * (0.38 atm)²) = 44.1

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A rate is what is used when two quantities are in a ratio but have different units. We can predict how one quantity will change as we adjust another using rates.

Volume of a cone = π*r^2*h/3

                              = π*10^2*20/3

                              = 2094.3951 cubic meters.

Volume of water lost when its 8 inches deep = V = π*r^2h/3

                                                                             = π·10^2·12/3

                                                                             = 1256.63706 cubic meters.

Remaining volume = 2094.3951 - 1256.63706

                               = 837.758 cubic meters.

Volume of water lost per minute = 0.5 cubic meters.

Time remaining =  837.758 * 0.5

                          = 7 hours approx.

Volume is a measurement of three-dimensional space that is occupied. It is frequently expressed mathematically using standard or SI-derived units. Volume and the measurement of length are connected.

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The choice from above which is not true about the scientists who made contributions to the development of the atomic theory is:

Dalton was known for the plum pudding model of the atom.

The correct answer choice is option b.

John Dalton did not make a contribution of plum pudding model regarding the atomic theory. Surely, this model was based on the work of sir JJ Thomson. In his contribution, he stated that: " atoms were known to consist of negatively charged electrons "

An atom is an indivisible particle of an element which takes in a chemical reaction. This statement was made by Dalton.

So therefore, John Dalton did not propose the plum pudding model but was made by Thomson.

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Answer:

10.58km

The formula needed to calculate the amount of wire used is expressed as:

W is the weight of wire used to wind a magnet

wg is the weight of wire per km

Given the following parameters:

Substitute the given parameters into the formula to have:

Hence the length of wire used is 10.58km

When potassium reacts with fluorine to from potassium fluoride one electron transfers from potassium to fluorine .

One electron from potassium is transferred to fluorine during the reaction that produces potassium fluoride.

During the electron transfer mechanism, an iron atom in the pigment of a cytochrome molecule takes an electron, reducing it; the electron is then transferred to the iron atom in the following cytochrome carrier, oxidizing the first iron atom in the chain.

The reaction between potassium and fluorine results in a net positive charge for potassium and a net negative charge for fluorine, which together balance the compound potassium fluoride.

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The chemical substance from above chemical equation which is reduced is 2NH3 ( ammonia )

In a chemical reaction such as redox reaction, that substance in the chemical reaction which gains electrons is the reduced substance. The chemical species which looses electrons are oxidized in the process. The ones reduced are the oxidizing agents and the ones oxidized are the reducing agents.

From the task above, ammonia in reduced.

The equation for the reaction is given below:

2NH3 + OCl ---- N2H4 + H2O + Cl−

So therefore, the species which is reduced is ammonia.

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45.6 mL of 0.0600 M of [tex]Ba(OH)_{2}[/tex] is added to 25.0 mL of HCl of unknown concentration then , the  concentration of HCl is 0.032 M .

Calculation ,

Formula used : [tex]M_{1} V_{1}[/tex] =  [tex]M_{2} V_{2}[/tex]                 ...( 1 )

Where  [tex]M_{1}[/tex]= concentration of [tex]Ba(OH)_{2}[/tex]  =  0.0600 M ( given )

[tex]M_{2}[/tex] = concentration of HCl = ? ( to be find )

 [tex]V_{1}[/tex]= volume of [tex]Ba(OH)_{2}[/tex]  = 25.0 mL  ( given )

[tex]V_{2}[/tex] = volume of HCl = 45.6 mL  ( given )

Now , put the value of all volume and concentration in equation ( 1 ) we get .

0.0600 M ×  25.0 mL =  [tex]M_{2}[/tex]  × 45.6 mL

[tex]M_{2}[/tex]  =  0.0600 M ×  25.0 mL / 45.6 mL = 0.032 M

Therefore , concentration of  unknown concentration of HCl is 0.032 M .

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Answer:

The answer would be E, gymnosperm

Explanation: Gymnosperms are an ancient group of plants that do not have flowers, they have a unique reproductive process, and produce seeds that are bare—, that is the seeds are not enclosed in a fruit!

Based on the rate constant of the reaction, the reaction rate, r 4.8 * 10⁻⁷ mol/L.s

The rate of a reaction is the number of moles of reactant molecules converted or the number of moles of product molecules formed per unit time.

It is the rate at which product molecules are formed or reactant molecules disappear.

The rate equation of a chemical reaction is an expression that describes the relationship between the rate of the chemical reaction and the concentration of the reactants in the chemical reaction.

The rate equation includes a rate constant which is a constant that is unique for a given reaction. The rate constant numerically describes the rate and direction of a chemical reaction.

Considering the given rate equation:

reaction rate = k [NH4 + (aq) ] [NO2(aq) ]

the data provided is as follows;

k =  3.20 x 10⁴ L/(mol⋅s)

[NH4+ ] = 0.100 mol/L and,

[NO2] = 0.0150 mol/L

The reaction rate, r will be:

r = 3.20 x 10⁻⁴ L/(mol⋅s) * 0.100 mol/L *  0.0150 mol/L

r = 4.8 * 10⁻⁷ mol/L.s

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According to the Bohr model, electrons orbit the nucleus at constant energies then the speed of the electron is I = 1.05 mA.

The Bohr model, also known as the Rutherford-Bohr model, was first proposed by Niels Bohr and Ernest Rutherford in 1913 and describes an atomic system with an orbiting system of electrons and a small, dense nucleus that is similar to the Solar System in structure but is attracted by electrostatic forces rather than gravity.

Speed of electron = v = 2.19 × 1[tex]$$0^6[/tex]  m/s

Radius of circular path = [tex]$\gamma[/tex] = 5.29 × 1[tex]0^{11}[/tex] m

The period of electron Pn its orbits is,

T = 2π[tex]\gamma[/tex] / V

To find the current represented by the orbiting electron

I (ΔQ/Δf) = |e|/T = |e|V /2πr

substitute the value in the above equation, we get

[tex]$I=\frac{\left(2.19 \times 10^6\right)\left(1.60 \times 10^{-19}\right)}{2(8.14)\left(5.29 \times 10^{-11}\right)} \\[/tex]

simplifying the equation, we get

I = 1.75 × 10-³  C/s

I = 1.05 mA

Therefore, the speed of the electron is I = 1.05 mA.

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The air behind a cold front is always cooler than the air in front of it.

The air behind a cold front is much colder and drier than the air in front of it. When a cold front passes the temperature can drop by more than 15 degrees in the first hour. Air masses behind a cold front can be cooler and drier than those in front of the front. When a cold front approaches, precipitation may occur just before or during the passage of the front.

Clear skies cooler temperatures and lower relative humidity behind the front are expected. The answer is the boundary between two different air masses where cold air is retreating and warm air is advancing. A front represents the boundary between two different air masses, such as warm and cold air. A cold front occurs when cold air turns into warm air.

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Answer: Question 1.: B. Question 2.: D. Question 3.: C. Question 4.: A.

The question requires us to calculate the volume of hydrogen gas in a balloon, given the number of moles of hydrogen, temperature and pressure in the balloon.

We can collect the following information from the question:

number of moles of H2 = n = 0.24 mol

temperature = T = 35°C

pressure = P = 1.05 atm

Since we need to calculate the volume of a gas and the temperature and pressure given are not the under the STP (Standard Temperature and Pressure), we'll need to apply the Ideal Gas Law equation:

Rearranging the equation above to find volume (V), we have:

where n is the number of moles of hydrogen gas, T and P are the temperature and pressure given, and R is a the constant of gases (R = 0.0821 L.atm/mol.K)

Note that we need to use the units following the constant of gases - L for volume, atm for pressure, mol for number of moles and K for temperature. Thus, we need to convert the temperature given (35°C) into Kelvin degrees:

T = 35 + 273.15 = 308.15 K

Now that we have all required variables to calculate the volume, we replace them in the equation:

Therefore, the volume of hydrogen in the ballon, under the given temperature and pressure, is 5.78 L.

As the question requires the answer expressed with two signifcant figures, we can write that the volume of hydrogen is 5.8 L.

the volume of hydrogen is 5.8 L

The first step we have to follow is to find the molar mass of FeCl2 using the atomic masses of each element:

It means that each mole of FeCl2 has a mass of 126.745g/mol.

Use the molar mass to find the mass of the given amount of moles:

It means that there are 110,141.405 grams of FeCl2.

In scientific notation it would be 1.10x10^5g.

there are 110,141.405 grams of FeCl2

Answer:

True

Explanation:

Density is an intensive property. This means that regardless of the object's shape, size, or quantity, the density of that substance will always be the same. Even if you cut the object into a million pieces, they would still each have the same density

Oxaloacetate contains 4C and is combined with acetyl-CoA which contains 2C in its acetyl group to produce citric acid which contains 6 carbon.

The tricarboxylic acid (TCA) cycle, also known as the Krebs or citric acid cycle, is the main source of energy for cells and a crucial step in aerobic respiration. The cycle transforms the chemical energy of acetyl coenzyme A (acetyl CoA) into nicotinamide adenine dinucleotide's reducing force (NADH).

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Most of the space in an atom is empty and a small, dense, positively charged nucleus is present at the center, which contained most of the mass of the atom, with the electrons orbiting the nucleus.

In 1909, Rutherford's alpha scattering experiment. In this experiment a stream of high speed alpha particles is directed at a thin piece of gold foil. During this experiment he observed that some of the particles passed through, some were deflected, and some bounced straight back. From this He concluded the following main points:

⇒ Most of the space in an atom is empty. Due to which some of the particles passed through without any change in their paths.

⇒ Some alpha particles were deflected, and some bounced straight back. This indicated a very small, dense, positively charged nucleus at the center, which contained most of the mass of the atom, with the electrons orbiting the nucleus.

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Answer:

Answer:

This ammonium laurel sulfates anion consists of a nonpolar hydrocarbon chain and a polar sulfate end group. It means it has a hydrophilic head and hydrophobic tail. There are ammonium ions, sulfate, and fatty acids present.

Lauryl sulfate has lauric acid attach to sulfate ions with carbon-sulfur bond, the fatty acid formed by the covalent bonds between C-C attached to hydrogens. Sulfur also bound to oxygen by covalent bonds. Nitrogen is surrounded by the four hydrogen atoms in the hydrophilic head.

Two different samples of matter are measured in each of these glass containers. Both of the containers show the same measure for both samples of matter. The samples most likely to have volume in common.

The specific inertial and gravitational mass, as well as the volume it takes up, can be used to identify matter. A substance can exist in three basic states: solid, liquid, and gas.

Volume is a three-dimensional measurement that's used to gauge a solid shape's capacity. It implies that a closed form's volume determines how much space it can occupy in three dimensions.

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Answer:

The correct answer is volume

Hope it helps

Explanation:

Answer: convection

Explanation: