A diverging lens with f = -33.5 cm is placed 14 cm behind converging lens with f = 20cm. where will an object at infinity be focused?

Answer:

3 m/s

Explanation:

Average velocity = Initial velocity + Final velocity / 2

Solving :

⇒ Average velocity = 2 + 4 / 2

⇒ Average velocity = 6/2

⇒ Average velocity = 3 m/s

if the initial velocity of body is 2 metre per second and final velocity is four metre per second calculate average velocity

So the average velocity is 3ms.

The acceleration due to gravity g at height 7 times the radius of Earth above the surface of the Earth is  8.933 m/s².

It is the acceleration caused by any object when placed on the surface on the Earth due to its weight.

The acceleration due to gravity is related to the distance as

g =GM/R²

where G is the gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²

Given is the height R = 7 x 6.4 x 10⁶ m and mass of  Earth M = 6 x 10²⁴ kg

Substitute the values into the expression to find the acceleration due to gravity.

g = ( 6.67 x 10⁻¹¹ x 6 x 10²⁴)/ ( 7 x 6.4 x 10⁶)²

g = 8.933 m/s²

Thus,  the acceleration due to gravity g at height 7 times the radius of Earth above the surface of the Earth is  8.933 m/s².

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Answer:

0.315C

Explanation:

Force/Electric field

7520N/23900C

The upward force F exerted by the biceps on the forearm will be 583 N.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

The torque balancing equation is found as;

[tex]\rm \tau_i=\tau_R+\tau_F+\tau_{BB}=0\\\\ R(0)+F(0.0300)-(50.0)(0.350)\\\\ F=583 \ N[/tex]

Hence,the upward force F exerted by the biceps on the forearm will be 583 N.

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In a science lab, there is the adequate availability of raw materials for experiments such as chemicals while outside a science lab there isn't.

In a science lab, the availability of apparatuses and sources of heat is higher than outside a science lab.

The science lab is a place where the experiments related to the science background are performed with the use of apparatus.

The science lab has plenty of equipment to perform the experiment whether related to physics or chemistry or biology.

Thus, source of heat and availability of raw material and equipment are the differences between the science activities carried out in a science laboratory and those carried out side of science laboratory.

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That states that the blackhole ends are working like bridges between one space to another.

This may be possible

Answer:

the units of work and energy is joule and unit of power is Watt

Answer:

A

Explanation:

d = 1/2 a t^2 = 1/2 (4)(28^2) = 1568 m  ~ 1.6 x 10^3

Answer:

10.75 m/s

Explanation:

let  velocity of Dodgems b  be y

law of conservation of momentum

120 x 10 + 160 x 7=120x5+ 160 x y

1200+1120 = 600 + 160 x y

160y = 1720

y = 10.75 m/s

The magnitude of the vector sum of the two vectors V and W is determined as 240.84 m toward + x.

A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.

The following are the x and y axes for the supplied vector:

Vector V in x direction;

[tex]\rm V_x = Vcos \theta \\\\ V_x = 448cos(224^0)\\\\ Vx = -322.26[/tex]

Vector V in y direction;

[tex]\rm V_y = Vsin \theta\\\\ V_y = 448 \times sin224^0\\\\ V_y = -311.2[/tex]

Vector W in x direction;

[tex]\rm W_x = 336 \times cos(75.9^0)\\\\ W_x = 81.86[/tex]

Vector W in y direction;

[tex]\rm W_y = 336 \times sin75.9\\\\\ W_y = 325.88[/tex]

The resultant vector in the x direction is;

∑X = -322.26 + 81.86

∑X == -240.4

The resultant vector in the y direction is;

∑Y = -311.2 + 325.88

∑Y  = 14.68

The resultant vector is found as;

[tex]\rm R =\sqrt{(-240.4)^2+(14.68)^2} \\\\R = 240.84 \ m[/tex]

Hence,  the direction of their vector sum is 240.84 toward +x-axis.

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Let's see

We need distance between them?

[tex]\\ \rm\Rrightarrow F=\dfrac{GMm}{r^2}[/tex]

[tex]\\ \rm\Rrightarrow r^2=\dfrac{GMm}{F}[/tex]

[tex]\\ \rm\Rrightarrow r^2=\dfrac{6.673\times 10^{-11}\times 8.1\times 10^2\times 4.5\times 10^8kg}{1.9\times 10^{-3}}[/tex]

[tex]\\ \rm\Rrightarrow r^2=128.02\times 10^{2}[/tex]

[tex]\\ \rm\Rrightarrow r^2=12802[/tex]

[tex]\\ \rm\Rrightarrow r=\sqrt{12802}[/tex]

[tex]\\ \rm\Rrightarrow r=113.14m[/tex]

Answer:

[tex]\huge\boxed{\sf T = 0.67\ seconds}[/tex]

Explanation:

Given Data:

Cycles = c = 3 cycles

Time = t = 2 seconds

Required:

Time period = T = ?

Formula:

1) f = c/t

2) T = 1/f

Solution:

Finding frequency first:

f = c / t

f = 3/2

f = 1.5 Hz

Now, finding period:

T = 1/f

T = 1 / 1.5

T = 0.67 seconds

[tex]\rule[225]{225}{2}[/tex]

Answer:

One pascal is equivalent to 1 newton (N) of force applied over an area of 1 square meter (m2). The pascal is also used to measure stress, specifically tectonic stress in the Earth's plates.

Explanation:

Answer:

Resistors connected in series

[tex]speed_{avg} = \frac{Σ\:distance}{ total\: time}[/tex]

So, according to the question:

distance = 90 miles

time = 1h 45min + 15 min + 1h = 3h

[tex]Therefore:\\ speed_{avg} = \frac{90}{3} mph \\ = \boxed {30 \: mph}[/tex]

We will take it Cm

Scale factor

So

#Mercury

Ven us

Earth

Mars

Jupiter

Saturn

#Uranus

Neptune

Answer:

[tex]2 \times 10^{-5}\ m[/tex]

Explanation:

[tex]v = f \lambda[/tex]

velocity of wave = frequency x wavelength

I'll assume we're talking about EM radiation here, which is any kind of light (microwave, ultraviolet, visible, etc.).

Every type of EM radiation has the same velocity — the speed of light.

Speed of light, known as [tex]c[/tex] — 300 000 000 = [tex]3 \times 10^8[/tex]

velocity: [tex]c = 3 \times 10^8[/tex] [tex]ms^{-1}[/tex]

frequency: [tex]f = 1.5 \times 10^{13}[/tex] [tex]\text{Hz}[/tex]

wavelength: [tex]\lambda =\ ?[/tex] [tex]m[/tex]

[tex]v = f \lambda\\3 \times 10^8 = 1.5 \times^{13}\ \times \ \lambda\\\text{rearrange for}\ \lambda\\\lambda = \frac{3 \times 10^8}{1.5 \times 10^{13}} = 2 \times 10^{-5}[/tex] [tex]m[/tex]

Explanation:

The pinna collects the sound waves and conducts them to the auditory canal. Sound waves struck at the ear drum and set it into vibration. Eustachian tube equalizes the pressure on either side of the ear drum and thus allows it to vibrate freely. Ear drum transmits the vibrations to ear ossicles.

Answer:

Thermal energy transfers occur in three ways: through conduction, convection, and radiation. When thermal energy is transferred between neighboring molecules that are in contact with one another, this is called conduction.

Explanation:

Answer:

Animals follow the seasons very closely. Changes in the length of the day or temperature affect the animals' hormone production and cause them to behave according to the season. For that reason, animals instinctively know when it's time for them to mate, build a nest, fly south or stock up on food for the winter.

Answer:

0.5 m

Explanation:

To find wavelength (λ) : apply the formula

Solving :

This question involves the concept of Newton's Law of Gravitation.

The force of attraction will be changed to "D. 20 Newtons".

According to Newton's Law of Gravitation, the gravitational force of attraction between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Mathematically,

[tex]F=\frac{Gm_1m_2}{r^2}[/tex]

where,

Now, reducing the distance by half, we get:

[tex]F'=\frac{Gm_1m_2}{(\frac{r}{2})^2}\\\\F'=4\frac{Gm_1m_2}{r^2}\\\\F'=4F\\F'=4(5\ N)[/tex]

F' = 20 N

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Answer:

See image

Explanation:

Plato

The best estimate for the ratio of Power radiated per unit Area on Earth and Power radiated per unit Area on Venus is 1/16. The correct option is D.

Power radiated is directly proportional to the fourth power of Temperature at the surface and also to the cross-section area.

P = σ A T⁴

For 600 K at Venus, σ A T⁴ = σ A (600)⁴

For 300 K at Earth , σ A T⁴ = σ A (300)⁴

Comparing, we get

[σ A (300)⁴/ σ A (600)⁴ ] = 1/16

Thus, the the best estimate for the ratio is 1/16. The correct option is D.

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The angle will the first diffraction minimum be found will be 0.034895°.

A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.

The equation of diffraction grating is given as

[tex]\rm d= \frac{m \lambda}{sin \theta }[/tex]

The angle between the incident ray and the point of the occurrence of the diffraction is found as;

[tex]\theta = sin^{-1}(\frac{m\lambda}{d} )\\\\\ \lambda= (2.0))(\frac{1.00 \times 10^{-12}}{1\ pm} )\\\\\ \lambda=2.00 \times 10^{-12}[/tex]

The angle will the first diffraction minimum be found is;

[tex]\theta = sin^{-1}(\frac{m\lambda}{d} )\\\\\ \theta = sin^{-1}(\frac{1 \times 2.000 \times 10^{-12}}{1\times 10^{-12}} )\\\\\ \theta= 0.0348995^0[/tex]

Hence,the angle will the first diffraction minimum be found will be 0.034895°.

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Answer:

C

Explanation:

Cool and dense air falls through more warm and less dense air during convection. The cooler, which is much heavier than warm air, is displacing the warmer, which has less mass. Convection always involves rising air in the atmosphere.

Answer:

C

Explanation:

Imagine a kettle. When you open it, all the hot water vapour will rise up, attempting to burst out. However, when it comes in contact with the cold air, it also becomes cold, causing it to sink back down and giving us the visual effect of steam.

Answer:

A

Explanation:

Applying the First Equation of Motion :

⇒ v = u + at

⇒ v = 30 + (-6)(4)

⇒ v = 30 - 24

⇒ v = 6 m/s

The image of this object is located at -60 cm. The formula for the mirror equation is used in the given problem.

A mirror equation is an equation that relates object distance and image distance to focal length.

The given data in the problem is;

Image distance (u) = 15 cm

Object distance (v) = ?

f is the mirror's focal length=20 cm

The mirror equation is given as;

[tex]\rm \frac{1}{v} +\frac{1}{u} =\frac{1}{f} \\\\ \rm \frac{1}{v} =\frac{1}{20} -\frac{1}{15} \\\\ \frac{1}{v} = 0.01666 \\\\\ v=-60 \ cm[/tex]

Hence, the image of this object is located at -60 cm.

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The distance between the aliens traveling in group and their launchpad in kilometers is 40.23km.

Given that data in the question;

Note that;

1 miles = 1.609 kilometers

Now, the distance in kilometers will be;

distance = 25 miles

distance = ( 25 × 1.609 )kilometers

distance = 40.23km

Therefore, the distance between the aliens traveling in group and their launchpad in kilometers is 40.23km.

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