High silica content lava flow is thick and viscous and does not flow easily.
Though lava rises upwards toward the surface, it is too thick to pass through the Earth's fissures and crevices. Pressure is increasing as the lava continues to surge upward.
Which lava contains more silica?The least dangerous process involved in volcanic eruptions is lava flow. The temperature, silica content, extrusion rate, and slope of the terrain are all factors that affect how far a lava flow travels. A lava flow with a high silica content or one that is chilly will not move very far. Such a flow would be extremely viscous (a high resistance to flow). Low silica content is characteristic of basalt flows like those in Hawaii, OR long-distance flow, and low viscosities.
A MAGMA COMPOSITION AND TYPES OF ROCK
There are various varieties of magmas, ranging from mafic magmas, which have high Fe and Mg contents and relatively little silica, to felsic magmas, which have low Fe and Mg contents and relatively high silica.
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Potassium reacts with fluorine to produce the ionic compound potassium fluoride
Figure 3 shows the transfer of electrons during the reaction.
(d)
o-loilor
Describe what happens when potassium reacts with fluorine to produce potassium
fluoride. Write about electron transfer in your answer.
(5)
When potassium reacts with fluorine to from potassium fluoride one electron transfers from potassium to fluorine .
One electron from potassium is transferred to fluorine during the reaction that produces potassium fluoride.
How does electron transfer work?During the electron transfer mechanism, an iron atom in the pigment of a cytochrome molecule takes an electron, reducing it; the electron is then transferred to the iron atom in the following cytochrome carrier, oxidizing the first iron atom in the chain.
The reaction between potassium and fluorine results in a net positive charge for potassium and a net negative charge for fluorine, which together balance the compound potassium fluoride.
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In the first reaction of the citric acid cycle, oxaloacetate, which contains blank______ carbons, is combined with acetyl-coa, which contains blank______ carbons in its acetyl group, to produce citric acid, which contains blank______ carbons.
Citric acid, which has 6 carbons, is created by combining oxaloacetate, which has 4 carbons, with acetyl-CoA, which has 2 carbons in its acetyl group.
What is citric acid cycle and how it works?Citric acid cycle also called as TCA cycle , which starts with the condensation of acetyl group with oxaloacetic acid( OAA).Citrate synthase is an enzyme which catalyses the initial reaction of TCA cycle .Then the third step is isomerization which isomerizes citrate to isocitrate.The oxaloacetate contains 4 carbon which is combined with acetyl-coa which contains 2C in its acetyl group to produce citric acid which contains 6 carbon.To know more about citric acid cycle visit:
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C₂H5OH (1) + 302(g) → 2CO₂(g) + 3H₂O(g)
1.25 mol C2H5OH reacts with
excess oxygen. What volume of
CO2 gas is produced at STP
during the reaction?
Volume (L) CO₂
Enter
PLEASE HELP IM ON THE LAST QUESTION
The volume of carbon dioxide gas produced at STP during the reaction is equal to 56 L.
What is the combustion reaction?Combustion reactions involve the complete oxidation of the fuel a hydrocarbon such reactions commonly liberate only carbon dioxide and water as products.
A hydrocarbon undergoes combustion to yield carbon dioxide and small amounts of water as the product. It can also be noted that no side products are left behind in the combustion reaction.
The given balanced combustion reaction of alcohol:
C₂H₅OH (l) + 3O₂ (g) → 2CO₂ (g) + 3 H₂O (g)
One mole of the ethanol produced carbon dioxide = 2 mol
Then 1.25 mol of the alcohol produced carbon dioxide = 2.5 mol
The volume occupied by one mole of carbon dioxide = 22.4 L
The volume of 2.5 mol of CO₂ = 22.4 × 2 = 56 L
Therefore, the volume of CO₂ gas produced during the reaction is 56 L.
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Answer: 56L
Explanation: The volume of carbon dioxide gas produced at STP during the reaction is equal to 56 L.
9. Identify each of the following as equations
for a synthesis (S), decomposition (D), single
replacement (SR), or double replacement (DR)
reactions.
(a) Zn + HCI → ZnCl₂ + H₂
1
(b) NaClO3 → NaCl + O₂
(c) P4 + Cl₂ → PC|3
(d) HCI + Mg(OH)₂ → MgCl₂ + H₂O
(e) BaO + SO3 → BaSO4
BALC
(f) Pb + AgNO3 → Ag + Pb(NO3)2
(g) AgNO3 + Na₂CrO4 → Ag₂ CrO4 + NaNO3
(h) Al + Fe3O4 → Al₂O3 + Fe
(i) HNO3 + Mg(OH)₂ → Mg(NO3)2 + H₂O
(j) Ba(NO3)2 + Na₂SO4 → BaSO4 + NaNO3
sulfuric acid has many uses, making it the most produced chemical in the world (over 150 million tons a year). one of the steps in the manufacture of sulfuric acid is so2(g) 1/2 o2(g) equilibrium reaction arrow so3(g). a sealed flask at 627°c is loaded with 1.48 atm of so2 and 0.74 atm of o2. after reaction, the equilibrium pressure of so3 is found to be 1.10 atm. what is the value of kp for this reaction at 627°c?
The value of the equilibrium constant at 627 °C, based on equilibrium pressures, will be 44.1.
First, we write the balanced reaction equation:
2 SO₂(g) + O₂(g) → 2 SO₃ (g)
Based on the reaction equation, the expression for the equilibrium constant (Kp) will look like this:
[tex]K_{p} =\frac{(pSO_{3} )^{2} }{pO_{2}(pSO_{2} )^{2} }[/tex]
pSO₃ - partial pressure of sulfur(VI) oxide
pO₂ - partial pressure of oxygen
pSO₂ - partial pressure of sulfur(IV) oxide
To calculate Kp, we need the equilibrium pressures for all three gasses. We already know the pressure for sulfur(VI) oxide (1.10 atm), but we need to calculate it for oxygen and sulfur(IV) oxide as well.
Because the molar ratio of sulfur(IV) oxide and sulfur(VI) oxide is 1:1, that means that for the formation of 1.10 atm of sulfur(VI) oxide, 1.10 atm of sulfur(IV) oxide was expended, so the equilibrium pressure of SO₂ will be 1.48 atm - 1.10 atm = 0.38 atm.
We apply the same principle for oxygen, but because oxygen:sulfur(VI) oxide ratio is 1:2, only 1.10 atm / 2 = 0.55 atm of oxygen was expended for the formation of sulfur(VI) oxide, leaving us with the oxygen equilibrium pressure of 0.74 atm - 0.55 atm = 0.19 atm.
We plug these values into the expression above:
Kp = (1.10 atm)² / (0.19 atm * (0.38 atm)²) = 44.1
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how does temperature differ from thermal energy
Super find 40 gauge copper wire is a diameter of only 0.080 mm and Waze only 44.5 g/km. Suppose a spool of 40 gauge wire weighs 471. g Les after some wire is pulled off to wind a magnet. How could you calculate how much wire is used. Set the math up. Do not do any of it just leave your answer as a “math expression”Also be sure your answer includes all correct unit symbols
Answer:
10.58km
Explanations:The formula needed to calculate the amount of wire used is expressed as:
[tex]\text{length of wire used=}\frac{W}{w_g}[/tex]W is the weight of wire used to wind a magnet
wg is the weight of wire per km
Given the following parameters:
[tex]\begin{gathered} W=471g \\ w_g=44.5\text{g/km} \end{gathered}[/tex]Substitute the given parameters into the formula to have:
[tex]\begin{gathered} \text{Length of wire used=}\frac{471\cancel{g}}{44.5\cancel{g}km^{-1}} \\ \text{Length of wire used}=\frac{471}{44.5}km \\ \text{Length of wire used=}10.58\operatorname{km} \end{gathered}[/tex]Hence the length of wire used is 10.58km
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Answer:
Explanation:
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here are three main types of chemical reactions: precipitation, acid-base and oxidation- reduction. classify each of the following as precipitation, acid-base or oxidation-reduction.
Precipitation is any liquid or frozen water that forms in the atmosphere and falls back to the Earth.
Acid–base reaction, a type of chemical process typified by the exchange of one or more hydrogen ions, H+, between species that may be neutral
An oxidation-reduction (redox) reaction is a type of chemical reaction that involves a transfer of electrons between two species.
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How do plants recycle hydrogen during cellular respiration?(1 point) Responses The hydrogen in water is recycled as glucose. The hydrogen in water is recycled as glucose. The hydrogen in glucose is recycled as hydrogen gas. The hydrogen in glucose is recycled as hydrogen gas. The hydrogen in glucose is recycled as water. The hydrogen in glucose is recycled as water. The hydrogen in hydrogen gas is recycled as glucose. The hydrogen in hydrogen gas is recycled as glucose.
Plants recycle hydrogen during cellular respiration, as the hydrogen in glucose is recycled as water. The correct option is d.
What is cellular respiration?Food molecules are broken down into energy, water, and carbon dioxide during cellular respiration. In the presence of oxygen, cells respire. Multiple chemical cycles are involved in cell respiration.
In plants, cellular respiration occurs but in a minimum amount, and in this process the hydrogen in combines with oxygen and forms water.
Therefore, the correct option is d. The hydrogen in glucose is recycled as hydrogen gas.
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Answer: Plants recycle hydrogen during cellular respiration, as the hydrogen in glucose is recycled as water. The correct option is d.
Explanation: What is cellular respiration?
Food molecules are broken down into energy, water, and carbon dioxide during cellular respiration. In the presence of oxygen, cells respire. Multiple chemical cycles are involved in cell respiration.
In plants, cellular respiration occurs but in a minimum amount, and in this process the hydrogen in combines with oxygen and forms water.
Therefore, the correct option is d. The hydrogen in glucose is recycled as hydrogen gas.
toxic industrial chemicals (tic) are chemicals used and/or created by industries that can have a significant impact on human health if released. three examples of tics that are readily available are anhydrous ammonia, hydrogen cyanide, and:
Chemicals used and/or produced by businesses that, if released, might significantly harm people's health are known as toxic industrial chemicals (tic). The three examples of the tics that are readily available are anhydrous ammonia, hydrogen cyanide, and chlorine.
What are the uses of chlorine?Chlorine is a material that is used in industries and is found in many items that are used in homes.
Chlorine occasionally manifests as poisonous gas. By applying pressure and chilling, chlorine gas can be transformed into a liquid that can be moved and stored. When liquid chlorine is released, it swiftly transforms into gas that spreads quickly and stays close to the ground.
The strong, unpleasant smell of chlorine gas, which is comparable to that of bleach, can be used to identify it. The pungent stink may give people enough warning that they are exposed.
The chlorine gas seems to be yellow-green in color.
Chlorine is not flammable on its own, but it can react explosively or combine with other chemicals, such as turpentine and ammonia, to form explosive compounds.
One of the chemicals that are most frequently produced in the US is chlorine. Its primary application is as bleach in the production of paper and fabric, but it is also used to create rubber, pesticides (insecticides), and solvents.Additionally, it is utilized in sewage and industrial waste sanitation process. If household chlorine bleach is combined with specific other cleaning chemicals, chlorine gas may be released. Chlorine was used as a choking (pulmonary) agent during World War I.To know more about anhydrous ammonia visit: https://brainly.com/question/28101131
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Transfer of thermal energy from the movement of particles from warm areas to cooler areas is ______.
A. convection
B. conduction
C. radiation
Answer: convection
Explanation:
no2 no2 drop zone empty. scl6 scl6 drop zone empty. bef2 bef2 drop zone empty. more than eight valence electrons due to an expanded octet fewer than eight valence electrons due to an odd number of valence electrons fewer than eight valence electrons due to a shortage of valence electrons
NO₂ is the example of fewer than eight number of valence electrons due to an odd no. of valence electrons.
N , atomic no. is 7 = 2 , 5
O , atomic no. is 8 = 2, 6
SCl₆ is the example of more than eight valence electrons due to an expanded octet.
S , atomic no. is 16 = 2 , 8 , 6
Cl , atomic no. is 17 = 2 , 8 , 7
BeF₂ is the example of fewer than eight valence electrons due to shortage of valence electrons.
Be, atomic no. is 4 = 2, 2
F , atomic no. is 9 = 2 , 7
These are the examples of odd no. of electrons, expanded octet due to more valence electron and less than eight valence.
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Imagine that you have set up a genetic screen to identify e. Coli mutants that cannot metabolize the amino acid tryptophan for energy. Beginning with a master plate containing many colonies, you prepare replica plates on medium with glucose or tryptophan as the only energy source. You would look for colonies that _____.
Replica plates on medium with glucose or tryptophan as the only energy source. You would look for colonies that can grow only on the plates with glucose
How does the termination of transcription in E. coli relate to RNA hairpin turns?The turns, which separate the RNA transcript from the transcription bubble, are created by complementary base pairing. Genes that are constitutively expressed, or "housekeeping" genes, have the highest frequency of GbM, while genes with the most variable expression have the lowest frequency.
What transpires when an mRNA hairpin loop forms?During transcription, the mRNA strand develops a hairpin loop that separates the RNA polymerase from the DNA template strand. The sequences involved in this process are referred to as terminator sequences, and the process is known as rho-independent or intrinsic termination.
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Which statement best describes the air behind a cold front?The air is warm and dry.
The air is warm and dry.
The air is colder and drier.
The air is warmer and more humid.
The air is cold and filled with moisture.
The air behind a cold front is always cooler than the air in front of it.
The air behind a cold front is much colder and drier than the air in front of it. When a cold front passes the temperature can drop by more than 15 degrees in the first hour. Air masses behind a cold front can be cooler and drier than those in front of the front. When a cold front approaches, precipitation may occur just before or during the passage of the front.
Clear skies cooler temperatures and lower relative humidity behind the front are expected. The answer is the boundary between two different air masses where cold air is retreating and warm air is advancing. A front represents the boundary between two different air masses, such as warm and cold air. A cold front occurs when cold air turns into warm air.
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Answer: Question 1.: B. Question 2.: D. Question 3.: C. Question 4.: A.
Which of these are elements?
Au, C, K, O
H₂O, CO₂, NaCl
Milk, Mud, Air
Answer:
Au, C, K, O
Explanation:
Au = Gold
C = Carbon
K = Potassium
O = Oxegen
H20 = Not an element on the periodic table
CO2 = Not an element on the periodic table
NaCl = Not an element on the periodic table
Milk = Not an element on the periodic table
Mud = Not an element on the periodic table
Air = Not an element on the periodic table
Hope this helps! :)
in the bohr model of the hydrogen atom, an electron in the lowest energy state follows a circular path at a distance of 5.29 ✕ 10−11 m from the proton. (a) show that the speed of the electron is 2.19 ✕ 106 m/s. (submit a file with a maximum size of 1 mb.)
According to the Bohr model, electrons orbit the nucleus at constant energies then the speed of the electron is I = 1.05 mA.
What is meant by Bohr model?The Bohr model, also known as the Rutherford-Bohr model, was first proposed by Niels Bohr and Ernest Rutherford in 1913 and describes an atomic system with an orbiting system of electrons and a small, dense nucleus that is similar to the Solar System in structure but is attracted by electrostatic forces rather than gravity.
Speed of electron = v = 2.19 × 1[tex]$$0^6[/tex] m/s
Radius of circular path = [tex]$\gamma[/tex] = 5.29 × 1[tex]0^{11}[/tex] m
The period of electron Pn its orbits is,
T = 2π[tex]\gamma[/tex] / V
To find the current represented by the orbiting electron
I (ΔQ/Δf) = |e|/T = |e|V /2πr
substitute the value in the above equation, we get
[tex]$I=\frac{\left(2.19 \times 10^6\right)\left(1.60 \times 10^{-19}\right)}{2(8.14)\left(5.29 \times 10^{-11}\right)} \\[/tex]
simplifying the equation, we get
I = 1.75 × 10-³ C/s
I = 1.05 mA
Therefore, the speed of the electron is I = 1.05 mA.
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Electrons have a ___________ charge and are found in the area of an atom called _________ _____________.
Answer:
Electrons have a negative charge and are found in the area of an atom called Outer Shell
Electrons have a negative charge and are found in the area of an atom called electron shells.
Describe the structure of ammonium lauryl sulfate. Refer to the given diagram. Your answer should include the type of bonding, the elements contained, and the size and shape of the molecule. Write a short paragraph.
Answer:
Answer:
This ammonium laurel sulfates anion consists of a nonpolar hydrocarbon chain and a polar sulfate end group. It means it has a hydrophilic head and hydrophobic tail. There are ammonium ions, sulfate, and fatty acids present.
Lauryl sulfate has lauric acid attach to sulfate ions with carbon-sulfur bond, the fatty acid formed by the covalent bonds between C-C attached to hydrogens. Sulfur also bound to oxygen by covalent bonds. Nitrogen is surrounded by the four hydrogen atoms in the hydrophilic head.
What species is reduced in the following reaction?
2NH3 + OCl− ↔ N2H4 + H2O + Cl−
The chemical substance from above chemical equation which is reduced is 2NH3 ( ammonia )
Understanding what species is reduced or oxidized in a redox reaction.In a chemical reaction such as redox reaction, that substance in the chemical reaction which gains electrons is the reduced substance. The chemical species which looses electrons are oxidized in the process. The ones reduced are the oxidizing agents and the ones oxidized are the reducing agents.
From the task above, ammonia in reduced.
The equation for the reaction is given below:
2NH3 + OCl ---- N2H4 + H2O + Cl−
So therefore, the species which is reduced is ammonia.
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No matter how much of a substance you have, the density always remains the same.
True or false
Answer:
True
Explanation:
Density is an intensive property. This means that regardless of the object's shape, size, or quantity, the density of that substance will always be the same. Even if you cut the object into a million pieces, they would still each have the same density
How many grams are in 869 moles of FeCL2?
The first step we have to follow is to find the molar mass of FeCl2 using the atomic masses of each element:
[tex]\begin{gathered} Fe=55.845g/mol \\ Cl=35.45g/mol\times2=70.9g/mol \\ FeCl_2=126.745g/mol \end{gathered}[/tex]It means that each mole of FeCl2 has a mass of 126.745g/mol.
Use the molar mass to find the mass of the given amount of moles:
[tex]869molFeCl_2\cdot\frac{126.745gFeCl_2}{1molFeCl_2}=110,141.405gFeCl_2[/tex]It means that there are 110,141.405 grams of FeCl2.
In scientific notation it would be 1.10x10^5g.
there are 110,141.405 grams of FeCl2
For a reaction where the rate equation is
rate = k [NH4 + (aq) ] [NO2(aq) ]
B. Calculate rate at temperature T2 , if the rate constant, k, is 3.20x104 L/(mol⋅s) when [NH4+ ] is 0.100 mol/L and [NO2] is 0.0150 mol/L.
Given:
Reactant A =
Reactant B =
X = Y =
Find:
Based on the rate constant of the reaction, the reaction rate, r 4.8 * 10⁻⁷ mol/L.s
What is the rate of a reaction?The rate of a reaction is the number of moles of reactant molecules converted or the number of moles of product molecules formed per unit time.
It is the rate at which product molecules are formed or reactant molecules disappear.
Reaction rate, r = moles of reactant converted / time or moles of product formed / timeThe rate equation of a chemical reaction is an expression that describes the relationship between the rate of the chemical reaction and the concentration of the reactants in the chemical reaction.
The rate equation includes a rate constant which is a constant that is unique for a given reaction. The rate constant numerically describes the rate and direction of a chemical reaction.
Considering the given rate equation:
reaction rate = k [NH4 + (aq) ] [NO2(aq) ]
the data provided is as follows;
k = 3.20 x 10⁴ L/(mol⋅s)
[NH4+ ] = 0.100 mol/L and,
[NO2] = 0.0150 mol/L
The reaction rate, r will be:
r = 3.20 x 10⁻⁴ L/(mol⋅s) * 0.100 mol/L * 0.0150 mol/L
r = 4.8 * 10⁻⁷ mol/L.s
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Which of the following is NOT true regarding the scientists who
contributed to development of the atomic theory?
Rutherford conducted the gold foil experiment and discovered the nucleus.
Dalton was known for the plum pudding model of the atom.
Thomson discovered the electron using cathode ray tube experiments.
Bohr used spectrum of colors emitted by gas to support evidence of atomic orbitals
The choice from above which is not true about the scientists who made contributions to the development of the atomic theory is:
Dalton was known for the plum pudding model of the atom.
The correct answer choice is option b.
Understanding plum pudding model of the atom.John Dalton did not make a contribution of plum pudding model regarding the atomic theory. Surely, this model was based on the work of sir JJ Thomson. In his contribution, he stated that: " atoms were known to consist of negatively charged electrons "
An atom is an indivisible particle of an element which takes in a chemical reaction. This statement was made by Dalton.
So therefore, John Dalton did not propose the plum pudding model but was made by Thomson.
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In the first reaction of the citric acid cycle, oxaloacetate, which contains blank______ carbons, is combined with acetyl-coa, which contains blank______ carbons in its acetyl group, to produce citric acid, which contains blank______ carbons.
Oxaloacetate contains 4C and is combined with acetyl-CoA which contains 2C in its acetyl group to produce citric acid which contains 6 carbon.
What is a citric acid cycle and how it works?The tricarboxylic acid (TCA) cycle, also known as the Krebs or citric acid cycle, is the main source of energy for cells and a crucial step in aerobic respiration. The cycle transforms the chemical energy of acetyl coenzyme A (acetyl CoA) into nicotinamide adenine dinucleotide's reducing force (NADH).
The citric acid cycle also called as TCA cycle starts with the condensation of the acetyl group with oxaloacetic acid( OAA).An enzyme called citrate synthase catalyses the first step of the TCA cycle.Then the third step is isomerization which isomerizes citrate to isocitrate.The oxaloacetate contains 4 carbon which is combined with acetyl-CoA which contains 2C in its acetyl group to produce citric acid which contains 6 carbon.To know more about the citric acid cycle visit:
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Can someone put their own numbers in this sentence and solve it? Thanks!
A balloon with a pressure of ______ atm and a temperature of ____ Celsius has a volume of ______ mL. The day warms up and increases the temperature to ______ Celsius, which makes the pressure change to _____ mm Hg. What is the new volume of the balloon, in Liters?
A balloon with a pressure of 1 atm and a temperature of 17° Celsius has a volume of 1000 mL. The day warms up and increases the temperature to 27° Celsius, which makes the pressure change to 1520 mm Hg.What is the new volume of the balloon, in Liters?
The new volume of the balloon is 0.517 L.
By ideal gas law, PV = nRT
P = pressure
V = volume
n = number of mole of gas
R = gas constant
T = temperature
Using ideal gas law, P₁V₁/ T₁ = P₂V₂/ T₂
P₁= 1 atm
V₁ = 1000 mL = 1 L
T₁ = 17° C = 290 K
After the day warms up:-
P₂ = 1520 mm Hg = 2 atm
T₂ = 27° C = 300 K
Put these values in formula, P₁V₁/ T₁ = P₂V₂/ T₂
V₂ = P₁V₁T₂/ T₁ P₂
V₂ = 1 atm× 1 L × 300 K/ 290 K × 2 atm
V₂ = 0.517 L = 517 mL
Hence, the new volume of the balloon is 0.517 L.
The ideal gas equation is formulated as: PV = nRT.
In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the overall quantity of ideal gas this is measured in terms of moles, R is the universal gas constant, and T is the temperature.
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In 1909, scientist ernest rutherford directed a stream of high speed alpha particles at a thin piece of gold foil. Some of the particles passed through, some were deflected, and some bounced straight back. This result caused rutherford to conclude that.
Most of the space in an atom is empty and a small, dense, positively charged nucleus is present at the center, which contained most of the mass of the atom, with the electrons orbiting the nucleus.
In 1909, Rutherford's alpha scattering experiment. In this experiment a stream of high speed alpha particles is directed at a thin piece of gold foil. During this experiment he observed that some of the particles passed through, some were deflected, and some bounced straight back. From this He concluded the following main points:
⇒ Most of the space in an atom is empty. Due to which some of the particles passed through without any change in their paths.
⇒ Some alpha particles were deflected, and some bounced straight back. This indicated a very small, dense, positively charged nucleus at the center, which contained most of the mass of the atom, with the electrons orbiting the nucleus.
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an 8.50 l tire contains 0.552 mol of gas at a temperature of 305 k . what is the pressure (in atm and in psi ) of the gas in the tire? (1 atm is approximately equal to 14.7 psi .)
The pressure inside the tire, assuming that the gas acts as an ideal gas, will be 1.6253 atm or 23.8 psi.
For calculations like these we utilize the ideal gas equation:
PV = nRT,
where P is the pressure exerted by the gas, V is the volume taken up by the gas, n is the amount of the gas (in moles), R is the universal gas constant (0.082057 Latm/molK) and T is the temperature (in Kelvins). Now we can say that:
P = nRT/V,
and plug all the known values into the equation:
P = 0.552 mol * 0.082057 Latm/molK * 305 K / 8.50 L = 1.6253 atm
Finally, because 1 atm = 14.7 psi, the pressure in the tire will be 1.6253 * 14.7 = 23.9 psi
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7. Students are asked to develop a plan for separating Al,0 (s) from a mixture of powdered Fe₂O3(s) and powdered Al20 (s) using chemical reactions and laboratory techniques. The student recovered 5.5 g of Al2O3 (s) from a 10.0 g sample of the mixture. Calculate the percent of Al by mass in the mixture of the two powdered oxides. (The molar mass of Al2O3 is 101.96g mol-¹, and the molar mass of Fez0, is 159.70 g mol-¹.)
The percent of aluminum (Al) by mass in the given mixture of the two powdered oxides is 29%.
What is the mass percent formula?The mass percent formula can be expressed by mass of the each element in one mole of the compound. The mass percentage of each component can be calculated as:
Mass percentage = (Mass of an element 1 mole of the compound)/ (molar mass of compound) × 100
Given, the mass of the mixture of the oxides Al₂O₃ and Fe₂O₃ is equal to 10.0 g.
The mass of the Al₂O₃ recovered = 5.5 g
The number of moles of Al₂O₃ = 5.5/101.96 = 0.054 mol
One mole of Al₂O₃ has two moles of aluminum.
0.054 mol Al₂O₃ will have moles of aluminum = 0.054 × 2 = 0.108
The molar mass of the aluminum (Al) = 26.98g/mol
The mass of 0.108 mol of Al = 0.108 × 26.98 = 2.9 g
The percentage by mass of Al in mixture = (2.9/10) × 100 = 29%
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45.6 mL of 0.0600 M Ba(OH)2 is added to 25.0 mL of HCl of unknown concentration. What is the concentration of HCl?
Ba(OH)2 + 2HCl --> BaCl2 + 2H2O
45.6 mL of 0.0600 M of [tex]Ba(OH)_{2}[/tex] is added to 25.0 mL of HCl of unknown concentration then , the concentration of HCl is 0.032 M .
Calculation ,
Formula used : [tex]M_{1} V_{1}[/tex] = [tex]M_{2} V_{2}[/tex] ...( 1 )
Where [tex]M_{1}[/tex]= concentration of [tex]Ba(OH)_{2}[/tex] = 0.0600 M ( given )
[tex]M_{2}[/tex] = concentration of HCl = ? ( to be find )
[tex]V_{1}[/tex]= volume of [tex]Ba(OH)_{2}[/tex] = 25.0 mL ( given )
[tex]V_{2}[/tex] = volume of HCl = 45.6 mL ( given )
Now , put the value of all volume and concentration in equation ( 1 ) we get .
0.0600 M × 25.0 mL = [tex]M_{2}[/tex] × 45.6 mL
[tex]M_{2}[/tex] = 0.0600 M × 25.0 mL / 45.6 mL = 0.032 M
Therefore , concentration of unknown concentration of HCl is 0.032 M .
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