a piston-cylinder assembly contains water and is being heated on top of a range. during the process, 65 btu of heat is transferred to the water, and heat losses from the side walls amount to 8 btu. the piston rises as a result of evaporation, and 5 btu of work is done by the vapor. determine the change in the energy of the water for this process.

In general, a proton's charge is q=1.61019 C q = 1.6 10 19 C. As a result, the finished work is 2881019 J 288 10 19 J. The work done as a result is 180 electron volts.

A proton is a subatomic particle that has the symbol p, H+, or 1H+ and an elementary charge of +1 e. Its mass is slightly less than that of a neutron and 1836 times that of an electron.

Hence, the general charge of a proton is q=1.61019 C q = 1.6 10 19 C. The work done as a result is 180 electron volts.

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[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

____________________________________

[tex] \large \tt Explanation \: : [/tex]

Displacement - Time graph is shown in the given figure, and we have to interpret the graph with red slope.

First of all, Slope of a Displacement time graph represents velocity. so we can say that :

Graph has positive (increasing) Slope from 3rd to 6th seconds that represents positive constant velocity.

From 6th to 8th second graph has Slope = 0, that means there is no Displacement taken in the mean time, that means velocity in this interval of time is 0.

From 8th second the graph has negative (Decreasing) Slope that means, the object is retracing its own path with a constant velocity.

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

According to the given statement the resultant displacement of the car is 5 m.

Displacement is the act of removing something from its customary location or position and replacing it with something else in that location or position.

A vector called displacement points from an object's initial position to its ultimate position. Meters are the accepted units of displacement. A vector called velocity depicts the direction and speed of motion. Meters per second are the accepted units for measuring velocity.

East and north are perpendicular to one another.

Displacement is the distance between a car's starting position and its ending position.

Displacement is √(3² + 4²) = √(25) = 5m

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The applied force on the object is 85 N. This answer was obtained by considering forces acting in horizontal direction.

Also the concept of net force by Newton's second law of motion was used to obtain the applied force (85 N).

The applied force on an object is the external force applied or exerted on an object.

The applied force on the object is determined by calculating the net force on the using Newton's second law of motion.

F(net) = F(app) - F(fric)

where;

70 N = F(app) - 15 N

F(app) = 70 N + 15 N

F(app) = 85 N

Thus, we can conclude that the applied force must be obtained from the forces acting on horizontal direction since force of friction exits only when an object is in horizontal motion.

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The gravitational potential energy of the pot plant before it begins to fall is 392 J.

The total mechanical energy of the pot plant after it has fallen two meters is 78.39 J.

The speed with which the pot plant hits the ground is 19.8 m/s.

The gravitational potential energy of the pot plant before it begins to fall is calculated as follows;

P.E = mgh

where;

P.E = (2 kg) (9.8 m/s²) (20)

P.E = 392 J

The total mechanical energy of the pot plant after it has fallen two meters is calculated as follows.

M.E = K.E + P.E

where;

M.E = ¹/₂mv² + mgh

M.E = ¹/₂(2 kg)(6.26 m/s)²  +  (2 kg)(9.8 m/s²)(2 m)

M.E = 78.39 J

The speed with which the pot plant hits the ground is calculated by applying the principle of conservation of energy as follows;

K.E(bottom) = P.E(up)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

v = √(2 x 9.8 x 20)

v = 19.8 m/s

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During dump site operations, the tank baffles must have an opening of sufficient size to allow free movement of water at the bottom of the tank and movement of air at the top during rapid filling or unloading.

Land filling can be defined as a biological method that is typically adopted for the effective and efficient treatment of waste products (garbage).

Generally speaking, there are different types of land filling and these include the following:

In conclusion, the dumping waste landfill involves the dumping of solid waste products (garbage) into the landfill site through the use of trucks.

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Complete Question:

During dump site operations, the _____ must have an opening of sufficient size to allow free movement of water at the bottom of the tank and movement of air at the top during rapid filling or unloading.

Large fan torque requires of 260 ft- lbs operate at 1740 RPM.

1740 RPM = 260 1b-ft N of torque

Torque 1 b. ft = Power in HP X 5252 / Speed in RPM

Power in np =260 X 1740/5252 =86.1386 HP

n= 90% =0.9

Power input = Power in np x 0.746 /n

For input power = (86.1386*0.746)/0.9

=71.4 kw.

What is torque?

The rotating equivalent of force is torque. Depending on the subject of study, it is also known as the moment, moment of force, rotating force, or turning effect. It illustrates how a force can cause a change in the body's rotational motion. Archimedes' studies on the use of levers are where the idea first emerged.

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just substitute whatever number is in the x column for x in the equation, then whatever you get from that equation is the y value

Since displacement is a vector quantity, the largest possible magnitude of the student displacement will be 2 m

Displacement is the distance travel in a specific direction. It is a vector quantity. It is measured in meter.

Given that a student walked straight for 6 meters, turned, then walked straight for another 4 meters. Without knowing how much he turned, the largest possible magnitude of his displacement D will be

D = 6 - 4

D = 2 m

Therefore, the largest possible magnitude of his displacement will be 2 m

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Answer:

Elliptical Orbit

Explanation:

The Moon revolves around Earth in an elliptical orbit with a mean eccentricity of 0.0549. Thus, the Moon's center-to-center distance from Earth varies with mean values of 363,396 km at perigee to 405,504 km at apogee.

Only it's volume changes. Volume is defined as the space an object takes up. The amount of substance, which is the mass stays the exact same. The amount of force that Earth is pulling the car down (the weight) stays the same.

Answer:

a sleep doesnt get to depict whether you get a good grade or not its what you know.

The geologic event that is incorrectly identified is option A) D. Intrusion of magma at Earth's surface.

According to the Law of Superposition, the oldest rocks will be at the bottom and the youngest at the top of a sequence of sedimentary strata that has not undergone any deformation.

If you were to imagine a river dumping sand into an ocean, the sand would eventually pour out onto the ocean floor and settle on top of the seafloor. After the seafloor's sand had already been laid down, this sand was added.

Note that the events are as follows:

Therefore, option A is incorrectly labeled because it is one that is supposed to be labeled as subsidence and deposit layer of geologic event.

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Option B The thickness of the central portion of a thin conveying lens can be determined very accurately by using a micrometer screw gauge.

One micrometer of thickness can be measured with a micron micrometre screw gauge. A Use of Micrometer Screw Gauge as like example Upon turning the screw of the micrometer screw gauge four times, a 2 mm space is covered.

A tool known as a micrometer is used to measure solid objects’ lengths, thicknesses, and other dimensions precisely and linearly.

The SI symbol m is also known as a micron, which is an SI-derived unit of length equaling 1106 meters, where 106 is the SI standard prefix for the prefix “micro-.” A micrometer is one-millionth of a meter.

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Answer:

melting point (a)

Explanation:

The phenomenona of vectors proved.

vector is a quantity that has two independent properties magnitude and direction.

The electric force is given by coulumb's law

          F = k q₁q₂ / r²

Let's apply newtons second law in particle 3

         F = F₃₁ - F₃₂

        F₃₁ = k q₃q₁ / r₃₁²

         F₃₂ = k q₃q₂ / r₃₂²

Let's write the values ​​they give us

         q₁ = -4.0 10⁻⁶ C

         x₁ = 0

         q₂ = q₃ = + 8.0 10⁻⁶ C

         x₂ = 4.0 m

         x₃ = -4.0 m

We look for the distances

        r₃₁ = x₃ -x₁

         r₃₁ = -4.0  - 0 = -4.0 m

         r₃₂ = -4.0 - 4.0 = -8.0 m

Let's write the force equation

         F = k q₃ (q₁ / r₃₁² + q₂ / r₃₂²)

so let's  calculate

          F =  8.99 10⁹ 8 10⁻⁶  (4 10-6/4 2 - 8 10-6 / 8 2)

          F =  71.92 10³ (1/2 - 1/8  )10⁻⁶

         F =   26.97 10-3 N

None of the charge are on the axis and therefore there are no forces on this axis.

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The horse takes 16.67 seconds long to go around the carousel twice.

To find the time first thing to note is that, if a line is drawn from the horse to the center of the carousel, all points above the line will take the same amount of time to complete one, two, or as many rounds as they choose.

So, we are going to use the formula,

θ = ωt

Then,

We must see it is similar to a clock in that every point in the minute arrow hits 12 simultaneously as it travels around the clock.

We note that the problem is independent of the distance from the central axis.

The horse's angle is equal to its angular velocity multiplied by the passage of time, so all we need to know is its angular velocity.

Now, applying the formula

θ = ωt

we have,

θ = 2 rev

ω = 0.12rev/s

So,

t = θ / ω

t = 2 / 0.12

t = 16.67 s

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The acceleration due to gravity on the other planet is most nearly 0.25 m/s².

As it is given the length of the pendulum is 1 m

So, the time period is 2s

Now the given are putting in the formula of acceleration

a = Δv / Δt

a = d/t / Δt

So,

a = 1/2 / 2

a = 0.25 m/s²

Hence, the acceleration due to gravity on the other planet is most nearly 0.25 m/s².

The force that pulls objects toward the center of a planet or other body is called gravity. All of the planets are kept in orbit around the sun by gravity. The amount of mass between you and the Earth's center determines how much gravity there is because the material that makes up the Earth's interior is not uniform.

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The height of the cliff, given that the baseball landed 35.9 m away is 25.03 m

First, we shall determine the time taken for the baseball to land. This can be obtained as follow:

s = ut

35.9 = 15.9 × t

Divide both sides by 15.9

t = 35.9 / 15.9

t = 2.26 s

We can obtain the height of the cliff as follow:

h = ½gt²

h = ½ × 9.8 × 2.26²

h = ½ × 9.8 × 5.1076

h = 25.03 m

Thus, we can conclude that the cliff is 25.03 m high

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The moment of inertia of the rod with respect to a parallel axis through one end of the rod is Ml^2/3

To calculate inertia, according to the parallel axis theorem:

[tex]I=I_{cm}+Md^{2}[/tex]

Where,

I is the inertia from an axis that is at distance d from the center of mass and Icm is the inertia when the axis passes through the center of mass.

The distance d = l/2

Now to calculate inertia

[tex]I=I_{cm}+Md^{2}[/tex]

[tex]I=\frac{Ml^{2}}{12} + M\frac{1}{2}\\I=\frac{Ml^{2}}{12}+\frac{Ml^{2}}{4}\\I=\frac{Ml^{2}+3Ml^{2}}{12}\\I=\frac{Ml^{2}}{3}[/tex]

The moment of inertia of the rod with respect to a parallel axis through one end of the rod is Ml^2/3.

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The rock did not knock the spy satellite out of the sky. Detail below

To determine whether the rock will knock out the spy satellite, we shall determine the maximum height reached by the rock. This is obatined as follow:

v² = u² - 2gh (since the ball is going against gravity)

0² = 367² - (2 × 9.8 × h)

0 = 134689 - 19.6h

Collect like terms

0 - 134689 = -19.6h

-134689 = -19.6h

Divide both side by -19.6

h = -134689 / -19.6

h = 6871.89 m

DIvide by 1000 to express in km

h = 6871.89 / 1000

h = 6.87 Km

From the calculation made, we can see that the maximum height reached by the rock is 6.87 Km

Thus, we can conclude that the rock did not knock out the spy satellite becaue the satellite is 400 Km above the ground.

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When the car moves 4km east and then turns 3km  north then the resultant displacement of car will be :

5km

Here initially the car moves 4km east , that is a straight line  towards east direction with a value of 4kms (let the point be A).

then,  from the point A it turns 3km towards north direction. here

North and east are perpendicular to one another.

ie, it forms 90° that means it is a right angle.

The displacement of a car is the distance between its initial and final positions.

The displacement is

S = [tex]\sqrt{3^{2} + 4^{2} }[/tex]  

S = [tex]\sqrt{25}[/tex]

  = 5

so the resultant displcement is 5km

the resultant graph is attached below:

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The magnitude of the net force that acts on the charge is 1.1 x 10^(-2).

What are magnetic and electric forces and how are they calculated?
The Lorentz Force Law, and specifically the magnetic force on a moving charge, is used to define the magnetic field B: F = q (v * B).
The magnetic field B and the charge q's velocity v are both perpendicular to the force.
F = q(v*BsinФ), where Ф is the angle less than 180° between the velocity and the magnetic field, gives the force's magnitude. This suggests that there is no magnetic force acting on a charge that is stationary or travelling perpendicular to the magnetic field.
The right hand rule specifies the force's direction. The aforementioned force relationship takes the shape of a vector product.
Even when they are not in contact, charged particles can nevertheless attract or repel one another. Electric fields are said to be created by charged particles. Additionally, the probes that find an electric field are charged particles. Charged particles experience force from an electric field. The strength of the electric field E that a charged particle at a place P creates is the amount of positive electric force that particle applies to another charged particle at that same position. The force acting on a positive charge is exerted in the direction of the electric field. F = q*E gives the real force acting on a particle with charge q. In the case of a negative charge, it points away from the electric field E.

Let F₁ denote the magnetic field and F₂ denote the electric field.
Since F₁ is perpendicular to F₂, we can use Pythagorian theorem to find the magnitude of the net force(F) by using F = √(F₁² + F₂²)
Therefore, F₁ = qvBsin(90°) = qvB = (1.8 * 3.1 * 1.2)/10³ = 6.70/10³ N
Again, F₂ = q*E = (1.8 * 4.6)/10³ = 8.28/10³ N
Thus, magnitude of the net force = F = √(F₁² + F₂²) = √[(6.70/10³)² + (8.28/10³)²] = 1.1 x 10^(-2) N (approx).

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In the given electric dipole, the charge q = 0.2 C and the electric field strength at the point (x,y) = (10 cm, 0 cm) N/C is E = 138.37 10⁹ N/C.

What is electric dipole?

Any electromagnetic system has an electric dipole separating the positive and negative charges. A simple illustration of this system is a pair of opposite-sign, equal-sized electric charges that are separated from one another by a relatively short distance. (A permanent electric dipole is known as an electret.)

a) Let's calculate the field for each of the both charge at the point y = 10 cm, x=0 or in the dipole line, for that we calculate the field that creates each charge and add them vectorially  

For the Charge 1  

y₁ = (0.1 - 0.035) = 0.065 m  

(Electric field) E1 = k q / y₁²  

E1 = 8.99 10 9 q / 0.065²  

E1 = 2127.8 q  

For the Charge 2  

y₂ = (0.1 - (-0.035) = 0.135 m  

(Electric field) E2 = k (-q) / y₂²  

E2 = 8.99 109 q / 0.135²  

E2 = - 493.3 q  

In an electric dipole the value of the two charges is of equal magnitude, but otherwise, suppose the positive charge is the highest  

Et = E1 -E2  

Et = 2127.8q -493.3q  

330 = q (2127.8 -493.3)  

q = 330 / 1634.5  

q = 0.2 C

Now let the negative charge is higher  

Et = (-2127.8 +493.3) q  

330 = -1634.5 q  

q = -0.2 C  

b) calculate the field for the point x = 0.1 m y = 0 m  

This is a point perpendicular to the midpoint of the dipole, so that we can use the dipole equation  

E = k 2qa / √(x² + a²)³  

E = 8.99 10⁹ 2 0.2 0.07 / √(0.1² + 0.07²)³  

E = 0.2517 10⁹ / (0.001819)  

E = 138.37 10⁹ N/C

Therefore, the charge q is 0.2 C  and electric field E is 138.37 10⁹ N/C.

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Complete Question

An electric dipole is formed from two charges, ±q, spaced 0.700 cm apart. The dipole is at the origin, oriented along the y-axis. The electric field strength at the point (x,y)=(0cm,10cm) is 330 N/C . What is the charge q? Give your answer in nC what is the electric field strength at the point (x,y) = (10 cm, 0 cm) N/C = ?

If the wire were light in weight, this force would be noticeable. The magnetic force is perpendicular to both the direction of current flow and the direction of the magnetic field. Here's a "right-hand rule" to help you determine the magnetic force's direction.

A magnetic field is a vector field that describes the magnetic influence on moving charges, currents, and magnetic materials. A moving charge in a magnetic field is subjected to a force that is perpendicular to both its velocity and the magnetic field.

Atoms make up everything, and each atom has a nucleus made up of neutrons and protons, with electrons orbiting around it.

Each atom generates a small magnetic field because the orbiting electrons are tiny moving charges.

Magnetic force can be found in a compass, a motor, the magnets that hold things on the refrigerator, train tracks, and new roller coasters. All moving charges create a magnetic field, and the charges that move through its regions experience a force.

Hence, if the wire were light in weight, this force would be noticeable. The magnetic force is perpendicular to both the direction of current flow and the direction of the magnetic field. Here's a "right-hand rule" to help you determine the magnetic force's direction.

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The gravitational force between them will change by a factor 1/9.

We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses objects. The magnitude of gravitational force can be determined as

F = G.m1.m2 / R²

where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.

From the question above, we know that

R2 = 3R1

By substituting the following parameters, we get

F2/F1 = G.m1.m2 / R2² / G.m1.m2 / R1²

F2/F1 = G.m1.m2 / (3R1)² / G.m1.m2 / R1²

F2/F1 = 1/9

Hence, the gravitational force between them will change by a factor 1/9.

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Answer:

work = force x displacement

force = 250N

displacement = 15m

work = 250 x 15

work = 3750J

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Answer:

the tendency of an object to resists a change in motion depends on its mass. if the net force acting on an above zero, its inertia is also zero.

when you are moving at a high rate of speed, inertia makes it hard to stop . newton's first law of motion applies only to objects that are already moving.

Explanation:

the answer would be TRUE

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Answer:

True

Explanation:

An object thats in motion will stay in motion with the same direction and speed unless an unbalanced force acts upon it. This means that when moving at a high rate of speed, its hard to stop unless you come in contact with an unbalanced force.

If the lovers both walk toward each other and meet at the center of the boat, at 0.725m and since romeo has greatest mass of the boat moves towards him away from the shore.

Calculating the system's center of mass should come first

X_{CM}=\sum_{n=1}^{n}\frac{X_n*M_n}{M_n}

Romeo, Juliet, and the boat's masses are multiplied by each coordinate's x value, and the result is then divided by the sum of all the masses.referring to Juliet's position as an example.

X_{CM}=\frac{57Kg\times0m+75Kg\times 2.7m+75kg\times1.35m}{57kg+75kg+75kg}

X_{CM}=\frac{307.395kg.m}{207kg}=1.485m

When internal forces are in play, the center of mass remains constant.

After the maneuver, the center of mass shifts in relation to the back of the boat, but it stays at the same distance from the shore.

X_{CM}=\frac{75\times1.35m+(75kg+57kg)\times2.70m}{207kg}=

X_{CM}=\frac{457.65}{207kg}=2.210m

The boat moves toward the shore with this displacement.

0.725m

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The launch velocity of the marble launcher is 34.65 m/s

Given that the launch velocity of marble launcher, launches a 25g marble to a distance of 73 cm (0.73 m) and the marble roll up to 6.2 meters before stopping. The launch height is 20 cm (0.2 m).

The time for landing can be calculated by the second equation of motion formula:

h = ut + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]

Let u = 0

0.2 = 0×t + [tex]\frac{1}{2}[/tex] × 9.8 × [tex]t^{2}[/tex]

[tex]t^{2}[/tex] = [tex]\frac{0.2}{4.9}[/tex]

[tex]t^{2}[/tex] = 0.04

t = 0.2s

Now, the launch velocity of the marble launcher can be calculated by:

Speed = Distance / Time

Speed = [tex]\frac{0.73 + 6.3}{0.2}[/tex]

Speed = [tex]\frac{6.93}{0.2}[/tex]

Speed = 34.65 m/s

Therefore, the launch velocity of the marble launcher is 34.65 m/s

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