The extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.
The given parameters;
unstrained length, l₁ = 0.201 mextension of the string, x = 0.0176 mspeed of the ball, v = 3.41 m/sThe radius of the circular path when spring is stretched is calculated as;
R = l₁ + x
R = 0.201 + 0.0176
R = 0.2186 m
The spring constant is calculated as follows;
[tex]F = ma\\\\Kx = \frac{mv^2}{R} \\\\K = \frac{mv^2}{Rx} \\\\K = \frac{(3.41)^2 m}{0.2186 \times 0.0176} \\\\K = 3,022.4 m \ N/m[/tex]
The extension of the spring when the ball is allowed to hang straight down, motionless;
[tex]F = mg\\\\Kx=mg\\\\x = \frac{mg}{K} \\\\x = \frac{9.8 m}{3022.4 m} \\\\x = 0.0032 \ m[/tex]
Thus, the extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.
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A car was sitting in sunlight all day long. The heat that is now contained in the car was transferred to the car primarily by which of the following processes? Question 1 options: radiation conduction convection electrical energy transfer.
1kg red-hot iron is put into 1 L of cool water. Explain in detail what will happen to the temperatures of both objects.
The equilibrium temperature of the iron-water mixture will be greater than the initial temperature of the cold water but less than the initial temperature of the hot iron.
According to the principle of conservation of energy, the heat lost by the red-hot iron is equal to heat absorbed by the cold water.
[tex]Q_{I} = Q_{w}\\\\m_IC_I(t_I - T) = m_wC_w (T-t_w)[/tex]
where;
T is the equilibrium temperatureFrom the equation given above, we can conclude that the equilibrium temperature of the iron-water mixture will be greater than the initial temperature of the cold water but less than the initial temperature of the hot iron.
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Two cars a and b are moving along a straight road in the same direction with velocities of 25km/h and 40km/h . Find the velocity of car b relative to car a
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
On some strange planet you find that a 17.4 kg object falls downward 28.8 meters in 5.5 seconds. What is the magnitude of the acceleration due to gravity on this planet
Hi there!
[tex]\large\boxed{g = 1.904 m/s^2}[/tex]
Acceleration of gravity is unaffected by an object's mass.
In the absence of air resistance, we can use the following kinematic equation:
d = vit + 1/2at²
The object falls from rest, so:
d = 1/2at²
The acceleration in this instance is gravity, our unknown. We can rearrange the equation to solve for 'g':
2d/t² = g
2(28.8)/(5.5²) = 1.904 m/s²
some properties of the particles that are sources of electric charge include
In the year 2081 in a shipping port on the moon, workers for Ore-Space, Inc., hoist a 500.0 kg hunk of anorthosite moon rock by a chain. (Neglect the weight of the chain.) The block is initially accelerating at 4.0 m/s.
How much force is being exerted by the chain?
Answer:
2,800 n
Explanation:
hope this helps, have a nice day/night! :D
The force of 2812.5 N is being exerted by the chain.
What is force?An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.
Given that:
Mass of the hunk of anorthosite moon rock : m = 500.0 kg.
Acceleration of the hunk: a = 4.0 m/s².
Acceleration due to gravity in moon = 1.625 m/s².
So, required force = 500.0(4.0 +1.625) n = 2812.5 N.
The force of 2812.5 N is being exerted by the chain.
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A teacher has two radioactive sources, A and B.
Source A has a longer half-life than source B.
What can be deduced about the nuclei in source A compared with the nuclei
in source B?
Do not refer to isotopes in your answer.
Answer:
The nuclei of source have greater stability than those of source B.
A circular coil consisting of 500 turns with an area of 6.0x10-4 m 2 is rotating in a uniform magnetic field. At the start, the normal to the coil is perpendicular to the magnetic field. After 15s, the normal to the coil is 60⸰ with the magnetic field. The average induced emf is -0.058V. What is the magnitude of the magnetic field?
The magnitude of the magnetic field in the coil is 21.65 T.
The given parameters;
number of turns, N = 500 turnsarea of the coil, A = [tex]6\times 10^{-4} \ m^2[/tex]change in time, t = 15 sThe induced emf in the coil is determined by applying Faradays law;
[tex]emf =N \frac{d\phi }{dt} \\\\emf = N ( \frac{\phi _2 - \phi_1}{t} )\\\\emf= N(\frac{BAsin\ 60 - BAsin\ 90}{t} )\\\\emf = NBA(\frac{sin60 - sn90}{t} )\\\\-0.058 = 500(6\times 10^{-4})\times B\times (\frac{0.866 - 1}{15} )\\\\-0.058 = -0.00268B\\\\B = \frac{0.058}{0.00268} \\\\B = 21.65 \ T[/tex]
Thus, the magnitude of the magnetic field in the coil is 21.65 T.
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A car traveling due north at 60 km/hr increased its velocity to 80 m/s due south in 20 seconds. Draw i) speed against time graph, ii) acceleration against time graph.
The slope of the graph is acceleration of the car with a value of 3.2 m/s².
The given parameters;
initial velocity of the car, u = 60 km/hrfinal velocity of the car, v = 80 m/stime of motion of the car, t = 20 sThe initial velocity of the car in m/s is calculated as follows;
[tex]60 \ \frac{km}{hr} \times \frac{1 \ hr}{3600 \ s} \times \frac{1000 \ m}{1 \ km} = 16.67 \ m/s[/tex]
The acceleration of the car is calculated as follows;
[tex]a = \frac{v- u}{t} \\\\a = \frac{80 - 16.67 }{20} \\\\a = 3.2 \ m/s^2[/tex]
The graph of the velocity against time and acceleration against time is in the image uploaded.
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What do you notice about the lines of earthquakes and volcanoes and where they seem to occur on Earth's surface?
Answer:
Most earthquakes and volcanoes occur because of the movement of the plates, especially as plates interact at their edges or boundaries.
Explanation:
Please help thank you!
Answer:
mass, weight
Explanation:
mass is constant, and weight is dependant on your location
Answer:
I think d
Explanation:
because distance j
has to be the last one that's the only one with distance
ASAP will mark brainlyist
A truck is speeding up (with a constant acceleration) from rest to 45 m/s and it takes it 15 seconds to do so. How far will the car travel?
Answer:
[tex]315meters[/tex]
Explanation:
Solution is attached.
a person sits on a freely spinning lab stool that has no friction in its axle. when this person extends her arms,
Hi there!
[tex]\boxed{\text{Her angular velocity decreases.}}[/tex]
Recall the conservation of angular momentum:
[tex]L_i = L_f\\\\I_iw_i = I_fw_f[/tex]
When this person extends her arms, her moment of inertia increases.
According to the conservation of angular momentum, if the moment of inertia increases, the angular velocity must DECREASE.
Dhdjrjfbjsjfnsmctejzbrnj
The answer is D
I hope this helps :)
1 Which requires more work, lifting a 10kg sack of
coal or lifting a 15kg bag of feathers?
The part of the shore that represents the water's edge and migrates back and forth with the tide is known as the ________.
Answer :It is know as the shore line
Explanation:
....................................
Answer:
yeah
Explanation:
Glucose typically enters the cell through which mechanisms
Answer:
facilitated diffusion
How many revolutions does the motor shaft turn through between the time when the current is reversed and the instant when the angular velocity is zero
Answer:it equals 0
Explanation:hope this is a good answer
Angular velocity is the ratio of angular displacement to time. Then the number of turns by the shaft is zero.
What is angular velocity?The rate of change of angular displacement is called angular velocity. It is a vector quantity.
We know that the angular velocity formula
[tex]\rm Angular \ velocity = \dfrac{Angular \ displacement}{time}[/tex]
The motor shaft turns through between the time when the current is reversed and the instant when the angular velocity is zero.
Then the number of turns will be
[tex]\rm Number \ of\ turns = Angular \ velocty \times time \\\\Number \ of\ turns = 0 *time \\\\Number \ of\ turns = 0[/tex]
The number of turns by the shaft is zero.
More about the Angular velocity link is given below.
https://brainly.com/question/7359669
what do you mean by frequency of sound is 50Hz
Answer:
This means the source of sound vibrates 50 times in one second. Therefore, number of vibrations in 1 minute, i.e. in 60 seconds = 50 x 60 = 3000 times.
Explanation:
plzz explain how it is 66 m
i know that distance =speed × time so how it is 66 m not a
0.4 and if there us another rule plz explain like if u day that 1/2 ×speed ×time plz explain why u used 1/2 or when do I use the 1/2 rule
Hi there!
For someone to hear an echo, the sound must echo and bounce back to the person.
Thus, the sound travels TWICE the distance from the person to the wall (to the wall and back).
We know that:
d = st (distance = speed × time)
Let L = distance from person to wall
Thus:
2L = st
2L = 330 × 0.40
2L = 132
L = 66 m
Image credit: The Hubble Heritage Team (AURASTSCI/NASA)
To which category does galaxy #2 belong? Why does it belong in this category?
WRITER
Can i ask u a question
how to do the next ques for moreBrainliest me please
A block of wood mass 0.60 kg is balanced on top of a vertical port 2.0 m high. A 10 gm
bullet is fired horizontally into the block and the embedded bullet land at a 4.0 m from
the base of the port. Find the initial velocity of the bullet.
A. 10 3 m/s B. 8.32 m/s C. 3.82 m/s D. 1.0 m/s
Answer:
m V1 = (m + M) V2 conservation of momentum
T = time to fall 2 m
2 = 9.8 / 2 T^2 initial vertical velocity zero
T^2 = 4/9.8 T = .639 sec
Sx = V2 * .639 sec distance traveled horizontally
V2 = 4 /.639 = 6.26 m/sec
V1 = (m + M) / m * 6.26 m/sec from first equation
V1 = (600 + 10) / 10 * 6.26 m/s = 382 m/s
There seems to be some confusion on units
Note that 382 m/s is a reasonable answer for speed of bullet
1100 ft/sec is reasonable for a .22 cal bullet
1100 ft/sec / 3.28 ft/m = 335 m/sec
If I travel 100 kilometer in one hour then I have a speed of?
Answer:
100 km /hour
Explanation:
/ or per = every once so every hour you are traveling 100 kilometera
Answer:
100kmh-1
Explanation:
100km÷1hour
100kmh-1
How long does it take a plane, traveling at a constant speed of 200 m/s, to fly once around a circle whose radius is 2750 m
Answer:
2000 and 156300
jade it jawaban nya
can someone pls help me in this q
Answer: B
Explanation:
Which statement indicates that motion has occurred?
A. The reference point has changed.
B. The position of the object has changed.
C.The object has not changed.
D. The object being described has changed
22.13 .. Two very long uniform lines of charge are parallel and are separated by 0.300 m. Each line of charge has charge per unit length 5.20 mC>m. What magnitude of force does one line of charge exert o
Answer:
Two very long uniform lines of charge are parallel and are separated by 0.300 m. Each line of charge has charge per unit length.
Explanation:
What substance is a polymer found in nature?
Silk,wool, DNA, cellulose and protein
How much force is needed to accelerate a 70 kg rider and the 200kg motorcycle the
rider is on at 4m/s?
Answer: F = (200 kg + 70 kg) * 4 m/s² = 270 kg* 4m/s² = 1080 N
Answer:
F = 1080 N
Explanation: