Answer:
A = (27.95 N, 21 N)
Explanation:
The polar co-ordinates are given as:
(r,θ) = (35 N, 37°)
Now, to convert this into polar co-ordinates (x, y), we will use following relations:
r² = x² + y²
(35)² = x² + y²
1225 = x² + y² ----------- equation (1)
and
tan θ = y/x
tan 37° = y/x
y = 0.753 x ------------------- equation (2)
Substituting this value in equation (1):
1225 = x² + (0.753 x)²
1225 = 1.567 x²
x² = 1225/1.567
x = √781.32
x = 27.95 N
using this value in equation (2)
y = (0.753)(27.95 N)
y = 21 N
Therefore, the vector can be represented in polar co-ordinates as:
A = (27.95 N, 21 N)
A roller coaster speeds up with constant acceleration for 2.3\,\text{s}2.3s2, point, 3, start text, s, end text until it reaches a velocity of 35\,\dfrac{\text{m}}{\text{s}}35
s
m
35, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction over 41\,\text{m}41m41, start text, m, end text. We want to find the initial velocity of the roller coaster before it started to accelerate.
Which kinematic formula would be most useful to solve for the target unknown?
Answer:
This one:
Explanation:
Khan academy answer
PLEASE HELP
uniform motion and nonuniform motion bibliography
Answer:
Abstract
A methodology for designing mechanical non-uniform motion generators is presented. The basic requirements for four-bar and six-bar linkages are established and it is shown how the performance can be evaluated by harmonic analysis applied to the output angular velocity function. A means of creating and searching a library of mechanisms based on normalized output functions is presented. B-spline curves are used as a means of defining a desired performance and it is shown how minimum acceleration can be achieved with continuity in the derivatives. Finally, a means of increasing the quality of motion transmission in the selected mechanisms is given. The techniques are used to synthesize a six-bar linkage.
Parker (73.2 kg) is being dragged down the hall with an applied force of 123 N. If the frictional force is 27.4 N, what is the coefficient of friction in the hall?
Answer:
The coefficient of friction in the hall is 0.038
Explanation:
Given;
mass of the Parker, m = 73.2 kg
applied force on the parker, F = 123 N
frictional force, Fs = 27.4 N
the coefficient of friction in the hall = ?
frictional force is given by;
Fs = μN
Where;
μ is the coefficient of friction
N is normal reaction = mg
Fs = μmg
μ = Fs / mg
μ = (27.4) / (73.2 x 9.8)
μ = 0.038
Therefore, the coefficient of friction in the hall is 0.038
A weight lifter is trying to lift a 1,500 N weight but can apply a force of only 1,200 N on the weight. One of his friends helps him lift it at a constant velocity. What force was applied to the rope
Answer:
400N is applied to the rope
Answer:
300N
Explanation:
Assuming his friend didn't throw the box, they would need a total of 1,500N to lift it, if the first person is already applying 1,200N, the only other amount of force needed is 300N to make a total of 1,500N! Simple math problem :)
Hope this helps! <3
a relationship between two or more variables that is shown is an observational study is a: a. correlation. b. social norm. c. coupling. d. causal relationship.
Answer:
Correlation
Explanation: Answer for Ap3x
is the term used to describe the removal of sand and soil by the wind.
Answer:
erosion
Explanation:
a baby carriage is sitting on the top of a hill that is 21 m high. the carriage with a baby 75kg. the carriage has what energy? calculate it
Answer:
It has potential energy
PE = 15450.75 J
Explanation:
we know its potential energy because the carriage is not moving, although it can
PE = mgh
in this case, m is 75, h is 21, and g is always 9.81
plug these in: PE = (75) (21) (9.81)
your answer: PE = 15450.75 J
which of the following influences healthy sexual attitude
1.family 2.friends 3.media 4.self
Miguel's parents drove him to a track meet that was 305 km away from the school. It took them 3 hours, which included a 30 minute break for breakfast. What was their average speed?
A.101.7 km/h
B.915 km/
C.122 km/h
D.275 km/h
A annoying small child is dropped off a 16.0 m cliff (for complaining about homework). The
speed the child will reach right before they hit the ground is
m/s - Don't worry,
the child will not sustain life threatening injuries as they ended up doing all their homework
and therefore was saved by the magical Physics Creature.
(Record your answer to correct significant digits).
Answer:
i would be that annoying child lol
Explanation:
but i just needed this for points sorry :>
A baseball is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the stone's time in the air until it hits the ground to be 4.3 s. How far does the baseball travel horizontally?
Complete Question
A baseball is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the ball's time in the air until it hits the ground to be 4.3 s. How far does the baseball travel horizontally?
Answer:
The distance covered horizontally is [tex]d = 43 \ m[/tex]
Explanation:
From the question we are told that
The initial horizontal velocity is [tex]u = 10 \ m/s[/tex]
The time taken by the ball in the air is [tex]t = 4.3 \ s[/tex]
Generally the distance traveled by the ball is
[tex]d = u * t[/tex]
=> [tex]d = 10 * 4.3[/tex]
=> [tex]d = 43 \ m[/tex]
What is the relationship between kinetic and potential energy in a roller coaster.
Answer: Kinetic energy is energy that an object has as a result of its motion. Potential energy is stored energy that has not yet been released.
Explanation: All moving objects possess kinetic energy, which is determined by the mass and speed of the object. Potential energy is the energy an object has as a result of its position.
How can you increase the pressure on an object?
An object with a mass of 43 kg measured on Earth is taken to the Moon. What is the mass of the object on the Moon's surface if the acceleration due to gravity on the Moon is one-sixth of that on Earth? O a. 16 kg O b. 43 kg O c. 7.9 kg O d. 26 kg
Answer:
b 43 kg
Explanation:
mass doesn't differ from place to place.
but the weight may
The Tissues of vascular Plants are organized into more complex structures that carry out a Variety of functions in the plant what structure is formed by a Group of tissues that work together to carry out a Specific function
A) Cell
B) Organ system
C)Organism
D Organ
DUE IN 20 MINUTES HELP
.How does the pattern of light that results when it passes through the slits in the double-slit experiment support the wave model of light?
A. .
It is the result of refraction.

B.
It is the result of diffraction.

C.
It is the result of the photoelectric effect.

D.
It is the result of blackbody radiation.
Answer:
B
Explanation:
The pattern that the double slit experiment produces is a diffraction pattern (made as a result of single and double slit interference).
Answer:
B. It is the result of diffraction.
Explanation: a p e x
How do the independent and dependent variables in an experiment compare?
А.
The independent and dependent variables have no effect on each other.
В.
The dependent variable controls the independent variables.
C
The independent and dependent variables are the exact same as each other.
D
The independent variable controls the dependent variables.
The diagram shows the forces acting on an object at an instant of time. Which of the following statements about the forces is true?
Answer:
If you want help, try showing that diagram and the following statements.
would someone just answer this now?
How does the force of gravity change between two planets when the masses ofBOTH planets are doubled?
Fg=G m1m2
d2
O A
2 times the gravity
B.
4 times the gravity
O
C
no change in gravity
Oo
1/2 the gravity
Answer:
B. 4 times
Explanation:
Fg'=G(2m1)(2m2)/d²
Fg'=4Gm1m2/r²
A copper rod of crosssectional area 0.500 cm2 and length 1.00 m is elongated by 2.00 * 10-2 mm and a steel rod of the same cross-sectional area but 0.100 m in length is elongated by 2.00 * 10-3 mm. Which rod is under greater tensile strain?
Answer:
They have the same tensile strainExplanation:
Strain of a material is the ratio of its extension to its original length.
strain = e/lo
e is the extension
lo is the original length
For a copper rod;
e = 2.00 * 10^-2mm
lo = 1.00m
convert 1.00m to mm
1.00m = 1*10^-3mm
get the strain
Strain = 2.00 * 10^-2mm/1*10^-3mm
Strain = 2 * 10^{-2+3}
Strain = 2*10^1 = 20
For the steel
e = 2.00 * 10^-3mm
lo = 0.100m
convert 0.100m to mm
0.1m = 0.1*10^-3mm
0.1m = 10^-4mm
get the strain
Strain = 2.00 * 10^-3mm/10^-4mm
Strain = 2 * 10^{-3+4}
Strain = 2*10^1 = 20
Since the value of their strain are the same, this means that they a re under the SAME tensile strain. No one is greater that the other.
The rod under greater tensile strain is ; Neither of them i.e. They both have the same tensile strain
Given data :
Cross sectional area of copper rod = 0.5 cm²
Length of copper rod = 1.0 m = 1 * 10³ mm
Elongation of copper rod ( Ec ) = 2.0 * 10⁻² mm
For Steel
Cross sectional area of steel = 0.5 cm²
Length of steel rod = 0.1 m = 1 * 10² mm
Elongation of steel rod ( Es )= 2.0 * 10⁻³ mm
Determine the Tensile strain of each rod
i) For copper rod
Tensile strain = Ec / Length of copper rod
= ( 2.0 * 10⁻² ) / ( 1 * 10³ )
= 2.0 * 10⁻⁵
ii) For the steel rod
Tensile strain = Es / Length of steel rod
= ( 2.0 * 10⁻³ ) / ( 1 * 10² )
= 2.0 * 10⁻⁵
The Tensile strain for the copper rod and the steel rod is the same ( 2.0 * 10⁻⁵ ) This means that both rods are under the same tensile strain
Learn more : https://brainly.com/question/24024159
How much voltage is required to run 0.054 A of current through a 152
resistor? Use AV = IR.
A. 3.6 x 10-3V
B. 2.8 x 102V
C. 1.2 V
D. 0.81 V
V = I • R
V = (0.054 A) • (152 ohms)
V = 8.208 volts
None of the listed choices is correct.
Which of the following is the best example of positive peer pressure?
Answer:
1.Your friend says "no thanks" to the dinner your dad cooked and prefers to just hang out with friends instead.
2. Your teammates keep making fun of you for spending so much time studying for Friday's math test.
3. Your coworkers spend every weekend watching movies at Tim's house and invite you to join them.
4. Your friends all sign up for a free class at the gym and suggest you sign up for it, too.
The path of a projectile is called a ???
Answer:
Projectile motion is a form of motion where an object moves in parabolic path; the path that the object follows is called its trajectory.
Explanation:
Melanie ran the 100 meters race in 12 seconds what was her avarage speed?
Answer:
melanie ran 8.3 meters per second
Explanation:
I think thats right, hope it helps.
Why is it important to lean forward and listen
Abdul of mass 50 kg is standing in an elevator of his building. The elevator is moving
upwards and is slowing down at a rate of 2.0 m/s? What is Abdul's apparent weight?
Use g = 10 m/s
Answer:
Abdul has an apparent weight of 600 newtons.
Explanation:
The statement is incorrectly written. Its correct form is:
Abdul of mass 50 kg is standing in an elevator of his building. The elevator is moving upwards and is slowing down at a rate of 2.0 m/s2. What is Abdul's apparent weight? Use g = 10 m/s2.
According to the statement, we know that elevator and Abdul himself are moving upwards and decelerating, which means that Abdul feels a force from elevator is the same direction of his weight. From 2nd Newton's Law we find the following equation of equilibrium:
[tex]\Sigma F = F-m\cdot g = m\cdot a[/tex] (1)
Where:
[tex]F[/tex] - Apparent weight, measured in newtons.
[tex]m[/tex] - Mass of Abdul, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]a[/tex] - Net acceleration of the elevator-Abdul system, measured in meters per square second.
In (1) we clear the apparent weight:
[tex]F = m \cdot (a+g)[/tex]
If we know that [tex]m = 50\,kg[/tex], [tex]a = 2\,\frac{m}{s^{2}}[/tex] and [tex]g = 10\,\frac{m}{s^{2}}[/tex], we find that the apparent weight of Abdul is:
[tex]F = (50\,kg)\cdot \left(2\,\frac{m}{s^{2}}+10\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 600\,N[/tex]
Abdul has an apparent weight of 600 newtons.
Under what conditions can an object have forces acting on it, but its motion does not change ?
Answer: An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion.
Explanation: I hoped that helped!!
A satellite is orbiting the Earth in a circular orbit of radius r. Its frequency is independent of its height above the surface of the Earth. a. TRUE b. FALSE
Answer:
a. TRUE
Explanation:
When a satellite is launched to orbit around earth, it has to produce its own artificial gravity by performing rotations. The frequency of this rotation is given by the following formula:
f = √[ac/4πR²]
where,
f = frequency
ac = centripetal acceleration
R = Radius of the satellite
Therefore, it is clear from this formula that the frequency of rotation of the satellite is independent of its height above the surface of earth. So, the correct option is:
a. TRUE
Un delfín nada en el mar, a una profundidad tal que experimenta es de 2,22 x 10⁵ PA. Si la densidad del agua del mar es de 1030kg/m³, ¿A qué profundidad nada el delfín?
Answer:
El delfín nada a una profundidad de 22 m
Explanation:
El principio fundamental de la hidrostática establece que la presión en un punto del interior de un fluido (presión hidrostática) es directamente proporcional a su densidad, a la profundidad que se encuentre dicho punto y a la gravedad del sitio en el que se encuentre el fluido.
Esto se expresa como:
P=ρ⋅g⋅h
donde:
P es la presión en un punto del fluido. ρ es la densidad del fluido .g es la gravedad del lugar donde se encuentre el fluido. h es la profundidad.En este caso:
P= 2.22*10⁵ Paρ= 1,030 [tex]\frac{kg}{m^{3} }[/tex]g= 9.8 [tex]\frac{m}{s^{2} }[/tex]h= ?Reemplazando:
2.22*10⁵ Pa= 1,030 [tex]\frac{kg}{m^{3} }[/tex] * 9.8 [tex]\frac{m}{s^{2} }[/tex] * h
Resolviendo:
[tex]h=\frac{2.22*10^{5} Pa}{1,030\frac{kg}{m^{3} }*9.8 \frac{m}{s^{2} }}[/tex]
h= 21.993 m ≅ 22 m
El delfín nada a una profundidad de 22 m