Alex has a 100 cm ruler pivoted at the centre. She ties a balloon filled with carbon doxide 16 cm from the pivot The total weight of the balloon and carbon dioxide is 0.06 N The ruler becomes unbalanced. Calculate the turning moment the balloon produces about the pivot on the ruler Give the unit

Answer:

The net magnetic field ta the center of square is[tex]1.36\times10^{-4} T[/tex].

Explanation:

Current, I = 12 A , side ,a = 10 cm =  0.1 m

Let the magnetic field due to the one side is B.

The magnetic field is given by

[tex]B = \frac{\mu o}{4\pi}\times \frac{I}{r}\times \left (Sin A +Sin B \right )\\\\B = 10^{-7}\times \frac{12}{0.05}\times \left ( sin 45 + sin 45 \right )\\\\B = 3.4\times 10^{-5} T[/tex]

Net magnetic field at the center of the square is

B' = 4 B

[tex]B'= 4\times 3.4\times 10^{-5}\\\\B' = 1.36\times10^{-4} T[/tex]

Answer:

105571.2 m/s

Explanation:

Using the formula connecting linear and angular velocity;

V = rω

r = radius of the circular path

ω = angular velocity

Since

1 rpm = 2π60 rad/s

800 rpm = 800 * 2π60 rad/s = 301632 rad/s

Substituting values;

V = 35/100 *  301632 rad/s

V= 105571.2 m/s

Answer:

The screw gauge is an instrument used for measuring accurately the diameter of a thin wire or the thickness of a sheet of metal. It consists of a U-shaped frame fitted with a screwed spindle which is attached to a thimble.

Explanation:

Measure the length of the coil with the help of a meter scale. The thickness of the wire can be found by dividing the length of the coil by the number of turns. Measure the diameter with callipers. Place an electrical wire between the jaws of a set of Vernier callipers. Slide the movable jaw around the cable without compressing the insulation and read the measurement where the line from the moving indicator meets the stationary scale for a diameter.

Answer:

A causes free electrons to flow

Explanation:

The amount of force that causes electrons to flow in a conductor is called electromotive force.

Answer:

tthe body of what it is supplied in its temperature rises

Answer:

To find the slope, we need to have co-ordinates of atleast 2 points lying on the line.

In this case, the 2 points are

(-3,1) and (2,-2)

To find the gradient we put in the following rule :

Rise / Run = (y2 - y1) / (x2-x1) = (-2-1) / (2+3) = -3 /5

Explanation:

Answer:

the kinetic energy lost due to friction is 22.5 J

Explanation:

Given;

mass of the block, m = 0.2 kg

initial velocity of the block, u = 25 m/s

final velocity of the block, v = 20 m/s

The kinetic energy lost due to friction is calculated as;

[tex]\Delta K.E= K.E_f - K.E_i\\\\\Delta K.E= \frac{1}{2}mv^2 - \frac{1}{2}mu^2\\\\\Delta K.E= \frac{1}{2}m(v^2 -u^2)\\\\\Delta K.E= \frac{1}{2} \times 0.2 (20^2 - 25^2)\\\\\Delta K.E= -22.5 \ J[/tex]

Therefore, the kinetic energy lost due to friction is 22.5 J

Answer:

22.5 J

Explanation:

It loses the difference in kinetic energy between the starting and ending speeds and that is (1/2)(M)(V1)^2 - (1/2)(M)(V2)^2 = (1/2)(M)((V1)^2 -(V2)^2) = (1/2)(0.2 kg)((25)^2 - (20)^2) = 22.5 Joules.

Answer:

Increasing or recovering population number for eagle will reduce the number of salmons

Explanation:

Eagle feed upon the salmon  or is a predator for salmon.

If the population of eagle is recovering then it is clear that they will feed upon large number of salmon thereby reducing their numbers.

Hence the increasing or recovering population number for eagle will reduce the number of salmons

The slow recovery of the bald eagle population likely affected the recovery of the salmon population by Increasing  population number for eagle will reduce the number of salmons.

The large group of same or different kinds of species living in the same habitat are collectively called as population.

Eagle feed upon the salmon or said to be a predator for salmon.

If the population of eagle is increasing then it is clear that they will feed upon large number of salmon which will reduce their numbers.

Hence, the increasing population number for eagle will reduce the number of salmons denotes slow recovery.

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Answer:

Its B

Explanation:

a p e x

Answer:

50km/h

Explanation:

Average Speed = Distance/Time

100km/2h = 50km/h

Answer:

B= 4 A=5

Explanation:

The molar mass of a gas is molecular

⇒The molecular weight molar mass of any gas is the mass of one particle of that gas multiplied by Avogadro's number (6.02 x 1023). Knowing the molar mass of an element or compound can help us stoichiometrically balance a reaction equation.

Answer:

a)   i₈ = 0.5 i₄,  b)   i₁₀ = 0.3 i₃,    i₁₀ = 0.8 i₈

Explanation:

For this exercise we use ohm's law

       V = i R

        i = V / R

we assume that the applied voltage is the same in all cases

let's find the current for each resistance

R = 4 Ω

         i₄ = V / 4

R = 8 Ω

         i₈ = V / 8

we look for the relationship between these two currents

         i₈ /i₄ = 4/8 = ½

         i₈ = 0.5 i₄

R = 3 Ω

        i₃ = V3

R = 10 Ω

        i₁₀ = V / 10

we look for relationships

       i₁₀ / 1₃ = 3/10

       i₁₀ = 0.3 i₃

       i₁₀ / 1₈ = 8/10

       i₁₀ = 0.8 i₈

Answer:

The answer is below

Explanation:

A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the

cable for the following cases:

a. The load moves downward at a constant velocity

b. The load accelerates downward at a rate 0.4 m/s??

C. The load accelerates upward at a rate 0.4 m/s??

Solution:

Acceleration due to gravity (g) = 10 m/s²

a) Given that the mass of the crane (m) is 140 kg. If the load moves downward, the tension (T) is given by:

mg - T = ma

Since the load has a constant velocity, hence acceleration (a) = 0. Therefore:

mg - T = m(0)

mg - T = 0

T = mg

T = 140(10) = 1400 N

T = 1400 N

b)  If the load moves downward, the tension (T) is given by:

mg - T = ma

T = mg - ma = m(g - a)

T = 140(10 - 0.4) = 140(9.96) = 134.4

T = 134.4 N

c)  If the load moves upward, the tension (T) is given by:

T - mg = ma

T = ma + mg = m(a + g)

T = 140(0.4 + 10) = 140(10.4)

T = 145.6 N

2) To find the distance (s) if the load move from rest (u= 0) and accelerates for 20 seconds (t = 20). We use:

s = ut + (1/2)gt²

s = 0(20) + (1/2)(10)(20)²

s = 2000 m

Answer:

Time = 80.91 seconds

Explanation:

Given the following data;

Velocity = 5.50 m/s.

Distance = 445 meters

To find the time;

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

[tex]Velocity = \frac{distance}{time}[/tex]

Substituting into the formula, we have;

5.5 = 445/time

Time = 445/5.5

Time = 80.91 seconds

Explanation:

average speed =(first velocity + second velocity)/2

=(10 +20)/2=15m/s

distance=average speed × time

= 15 × t ( but time not given)

Answer:

Explanation:

What a lot of words to solve such a simple problem! The perpendicular force is the one that is pushing straight down on the plane. There is no side to side movement here or friction acting on this dimension at all. Perpendicular force is the same as the weight of the block. That's it! Perpendicular force is also normal force which is the same thing as weight:

w = mg so

w = (4.04)(9.8) and

w = 4.0 × 10¹ N

The magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the incline plane is 34.3N

The given parameter are:

mass M = 4.04 kg

Angle of inclination = 30 degree

Acceleration due to gravity = 9.8 m/s^s

To calculate the magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the plane, The force will be the weight of the block which is equal to the normal reaction.

Normal N = mgcosФ

N = 4.04 x 9.8 x cos30

N = 34.28 Newtons

At all point in the plane,  the magnitude of the perpendicular force that the block exerts on the surface of the plane will be the same.

Therefore,  the magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the incline plane is 34.3N

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Answer:

a. Final velocity, V = 88 m/s

b. Distance, S = 960 meters

Explanation:

Given the following data;

Initial velocity = 8 m/s

Acceleration = 4 m/s²

Time = 20 seconds

a. To find the final velocity, we would use the first equation of motion;

V = u + at

V = 8 + 4*20

V = 8 + 80

Final velocity, V = 88 m/s

b. To find the distance covered, we would use the second equation of motion.

S = ut + ½at²

S = 8*20 + ½*4*20²

S = 160 + 2*400

S = 160 + 800

S = 960 meters

Answer:

i. Cv =3R/2

ii. Cp = 5R/2

Explanation:

i. Cv = Molar heat capacity at constant volume

Since the internal energy of the ideal monoatomic gas is U = 3/2RT and Cv = dU/dT

Differentiating U with respect to T, we have

= d(3/2RT)/dT

= 3R/2

ii. Cp - Molar heat capacity at constant pressure

Cp = Cv + R

substituting Cv into the equation, we have

Cp = 3R/2 + R

taking L.C.M

Cp = (3R + 2R)/2

Cp = 5R/2

Answer:

True

Explanation:

I took the quiz and got it right.

TRUST

The "max out" method, also known as the "1RM" (One Repetition Maximum) method, is commonly used in strength training to determine the maximum amount of weight an individual can lift for a particular exercise.

The purpose of this method is to assess muscular strength accurately. While it is essential to perform warm-up sets to prepare the body for intense lifting, the process of determining the 1RM involves a specific protocol:

Warm-up Sets: Before attempting the 1RM, it is crucial to warm up the muscles and joints properly. Warm-up sets are typically performed with lighter weights and higher repetitions to gradually prepare the body for the heavier load.

Complete Sets: After the warm-up sets, the individual performs one or more "complete sets" with progressively heavier weights, but not at maximal effort. These sets help acclimate the body to heavier loads and prepare the nervous system for the upcoming maximal lift.

1RM Attempt: Once adequately warmed up and prepared, the individual makes an attempt to lift the heaviest weight possible for one repetition. It is essential to have a spotter or a qualified trainer to ensure safety during this maximal effort lift.

Rest: After the 1RM attempt, it is essential to allow sufficient rest and recovery, as attempting maximal lifts can be physically and mentally demanding.

It's important to note that determining 1RM carries a higher risk of injury compared to typical strength training. It's best to perform 1RM assessments under the guidance of a qualified trainer or coach who can provide proper instruction and ensure safety throughout the process. Additionally, the 1RM should be assessed periodically, as it can change over time with training and adaptation.

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Answer:While walking, one foot is in contact with the ground at a time. The surface area of one foot is less than two feet. Therefore, the pressure is more than the pressure exerted while standing, as the surface area of both feet is more.

Answer:

The first law states that an object at rest will stay at rest, and an object in motion will stay in motion unless acted on by a net external force. Mathematically, this is equivalent to saying that if The second law states that the rate of change of momentum of a body over time is directly proportional to the force applied, and occurs in the same direction as the applied force. the net force on an object is zero, then the velocity of the object is constant. The third law states that all forces between two objects exist in equal magnitude and opposite direction: if one object A exerts a force FA on a second object B, then B simultaneously exerts a force FB on A, and the two forces are equal in magnitude and opposite in direction

Explanation:

Answer:

Comencemos con la primera:

si tenemos algo como:

7.1*10^n

Simplemente lo que tenemos que hacer es:

si n es positivo, movemos n veces el punto para la derecha, si no tenemos dígitos, completamos con ceros.

si n es negativo, movemos n veces el punto a la izquierda.

a) 7.1*10

aca tenemos n = 1

entonces movemos una vez el punto a la derecha:

7.1*10 = 71. = 71

b) 2.3*10^3

aca n = 3, entonces movemos el punto 3 veces a la derecha:

2.3*10^3 = 23__.

Tenemos dos huecos ahí, los cuales serán completados con ceros, entonces:

2.3*10^3 = 2,300. = 2,300

c) 1.56*10

n = 1, entonces movemos el punto una vez a la derecha:

1.56*10 = 15.6

d) 4.10^4

acá tenemos n = 4

entonces movemos el punto 4 veces a la derecha, recordar que debemos completar con ceros:

4.10^4 = 40,000. = 40,000

Answer:

property of matter by which it continues in its existing state of rest or uniform motion in a straight line, unless that state is changed by an external force.

Answer:

Law of inertia, also called Newton's first law, postulate in physics that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Hope this answer is right!

Answer:

matter is any substance that has mass and takes up space by having volume.

Explanation:

Matter is anything that has a mass and it takes up space or has a volume .

matters are made up many atoms or molecules .

hope it is helpful to you

stay safe, happy and healthy

Answer:

[tex]U_x = \frac{1}{2} kx^2[/tex]

Explanation:

Find the image uploaded for the chart.

The energy stored in a stretched elastic material is known as elastic potential energy. Mathematically this energy is expressed as follows;

[tex]U_x = \frac{1}{2} fx\\\\where ;\\\\f = kx\\\\U_x = \frac{1}{2}kx^2[/tex]

The terms are defined as follows;

f is the load applied to the elastic material (N)

k is the spring constant (N/m)

x is the extension of the material (m)

Ux is the elastic potential energy (J)

Answer:

The distance between the diver and the shipwreck is approximately 130.76 m

Explanation:

The depth of the shipwreck below the surface of the water = 35 m

The location of the wreck = 55° South of West

The angle of depression of the wreck = 18°

The location of the diver = 27° South of East

The angle of depression of the diver = 30°

The distance of the wreck from the ship = 35 m/(sin(18°)) ≈ 113.26 m

The horizontal distance of the wreck from the ship = 35 m/(sin(18°)) × (cos(18°)) ≈ 107.72 m

The x-coordinate of the shipwreck, x₁ = 107.72 m × cos(55°) ≈ 61.79

The y-coordinate of the shipwreck, y₁ = 107.72 m × sin(55°) ≈ -88.24

The z-coordinate of the shipwreck, z₁ = -35

The distance of the diver from the ship = 35 m/(sin(30°)) = 70 m

The horizontal distance of the diver from the ship = 70 m × cos(30°) ≈ 60.62 n

The x-coordinate of the diver from the ship, x₂ = -60.62 m × cos(27°) ≈ -54.013

The y-coordinate of the diver from the ship, y₂ = 60.62 × sin(27°) ≈ -27.52

The z-coordinate of the diver from the ship, z₂ = -35

The distance between the diver and the shipwreck, 'd', is given by the distance between two points given the x, y, z coordinates as follows;

d = √((x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²)

Therefore, we have;

d = √((61.79 - (-54.013))² + (-88.24 - (-27.52))² + (35 - 35)²) ≈ 130.76

The distance between the diver and the shipwreck, d ≈ 130.76 m.