The weight of the suspended object is determined as 39.82 N.
What is resultant force?The resultant force is described as the total amount of force acting on the object or body along with the direction of the body.
The weight of the suspended object is equal to the resultant force of the tension in the two ropes.
Let the resultant force = W
The value of of the resultant force is calculated as follows;
W² = 25² + 31²
W² = 1,586
W = √1586
W = 39.82 N
Thus, the weight of the suspended weight will be greater than the tension in each rope.
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Which of the following is an example of climate?
Answer: Snowy and rainy
Explanation:
Answer explanation pls
The Distance Travels after 5s is 50 m.
What are the equations of motion?First equation of motion: v = u + at.
Second equation of motion: s = ut + 12 at2
Third equation of motion: v2 = u2 + 2as.
A physical system's behavior in terms of how its mobility varies over time is described by equations of motion.
The equations of motion, which are a group of mathematical functions stated in terms of dynamic variables, provide a more thorough description of how a physical system behaves. Space, time, and occasionally components of momentum make up these factors in most cases. The most flexible choice is generalized coordinates, which can represent any meaningful variable present in the physical system. In relativity, curved spaces are employed in place of the Euclidean spaces where the functions are specified in classical mechanics. If the dynamics of a system are known, the equations are the solutions to the differential equations that describe the motion of the dynamics.To learn more about : equations of motion.
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A 900 kg racing car is travelling at a uniform speed of 30m/s around a circular racetrack with a diameter of 360 m. what is the centripetal force acting on the car?
The centripetal force acting on the car is 4500 N
The force that acts on the body to make it follow a circle is known as centripetal Force.
Mass m = 900 kg
speed v = 30 m/s
radius r = diameter/2 = m
To calculate Centripetal force:
[tex]F_{c}[/tex] = mv^2/r
[tex]F_{c}[/tex] = 900×30^2/180
[tex]F_{c}[/tex] = 4500 N
The centripetal force of the car is 4500 N.
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20 POINTS PLEASE HELP
Use the image above to help you respond to this question:
If you were able to float from Earth’s surface and into space, you would notice shifts in the temperature along the way. We know that the density of air molecules is lessening and it SHOULD get colder as you ascend, so explain why
a) the stratosphere behaves differently.
b) the thermosphere behaves differently.
Complete the questions below to help you construct the velocity vs. time graph of a person driving a car
along a straight road. Certain points will be labeled with letters of the alphabet. Please use these points
when referring to the time, displacement, velocity, and acceleration of the car. For example, at point
"B" the velocity would be ve, while t would refer to the time difference between points "B" and "C".
Label all positions on the graph. Any necessary calculations should show work in the spaces provided
and include units.
3/SA
1. Starting at position "A", the driver cruises through town at 13m/s for the first five seconds. The
end of this interval is position "B". Construct the velocity vs. time graph between position "A"
and "B" and determine the variables below.
A graph type called a velocity vs. time graph compares how velocity changes over time. This kind of graph can be used to determine an object's displacement, acceleration, and velocity as well as its direction of motion.
While speed and velocity are similar, they are not the same. Velocity is a vector quantity with direction. There is a magnitude, a direction, and units for every vector quantity. The change in displacement, another vector, over time is referred to as velocity. Speed is a scalar quantity with no direction that calculates how quickly something moves. By dividing the distance by the time, one may calculate speed.
As a result, in a graph of speed vs time, the slope corresponds to acceleration, whereas the area under the curve corresponds to distance rather than displacement.
The driver of an automobile moves onto the highway. They must first accelerate and move into the right lane in order to merge. After a few miles of continuous pace, they run upon some road construction. They slow down, which regrettably causes them to sit in halted traffic for the following few seconds.
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O
1
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Projectile Math review
1
10 points
A soccer ball is kicked with a velocity of 15.7 at an 51.6 degree angle. How far away will the ball land back on the ground?
The ball land back on the ground at the distance of 37.75 meters from the point it was kicked after completing the projectile.
What is projectile?
The term "projectile" refers to an item that is pushed by the application of an external force, then moves freely while being influenced by gravity and air resistance. Even though everything that travels through space is a projectile, they are widely used in both sports and conflict (for example, a thrown baseball, kicked football, fired bullet, shot arrow, stone released from catapult)
the ball is kicked at the speed of 15.7 m/s with degree 51.6° angle.
Vertical velocity = 15.7 sin51.6 = 15.7(0.783) = 12.3 m/s
Horizontal velocity = 15.7 cos51.6 = 15.7(0.962) = 15.1 m/s
Lets calculate the time of flight:
v = u + at
Here, v = final vertical velocity, a = gravitational acceleration, u = initial vertical velocity, t = time
putting the values
0 = 12.3 + 9.8(t)
t = -1.25 s
times cant be negative so we consider it as 1.25 seconds
This is half time, IN the compete projectile the ball will reach at the top and then again come to land taking the same time. so,
T = 2t = 2(1.25) = 2.5 seconds
Calculating the range:
Distance = speed(time)
Speed = Horizontal velocity = 15.1 m/s
time = 2.5 s
putting the values
Distance = 15.1(2.5) = 37.75 m
Therefore, the ball land back on the ground at the distance of 37.75 after full projectile.
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2000 kg car at rest has a net force of 500 N being applied to the left. If the force is applied
for 10 sec, what is the final velocity of the car?
The final velocity of the 2000 kg car with a net force of 500 N being applied to the left for 10 sec is - 2.5 m / s
a = ( v - u ) / t
F = Force
m = Mass
a = Acceleration
v = Final velocity
u = Initial velocity
t = Time
t = 10 s
u = 0
a = ( v - 0 ) / 10
a = v / 10
According to Newton's second law of motion,
F = m a
F = Force
m = Mass
m = 2000 kg
F = - 500 N
- 500 = 2000 * ( v / 10 )
v = - 2.5 m / s ( Negative sign indicate the object is moving towards left )
Therefore, the final velocity of the car is - 2.5 m / s
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help plsss
can someone explain me what l means? in this pic?
tysm
Answer:
pie
Explanation:
pie
A woman pulls a crate with a force of 66 N at an angle of 39 o with respect to the horizontal. If a frictional force of 3.9 N acts on the crate, what is the total work done on the crate, in joules (J), after it has moved a distance of 5.8 m?
According to the given statement The total work done on the crate in 17.57 J.
What is work done called?When a force is applied to an item, it is deemed to have "done work" if the object travels a distance in the direction of the force. The result of force and displacement are the same. Displacement times Force equals work.
Briefing:Mass of the crate, m = 66kg
Force applied by the worker, F = 3.9 N
Angle to the horizontal, θ = 39°,
Distance moved by crate, d=5.8m
Work = Force * Displacement
Total work done on the crate
W = Fcosθ × d
W = 3.9× cos 39 × 5.8
W = 17.57 J
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Mary jogs for 15 minutes at 240 m/min, walks the next 10 minutes at 90 m/min, rests for 5
minutes, and jogs back to where she started at -180 m/min. a. Plot a velocity vs. time graph for Mary's exercise run.
b. Find the area under the curve for the first 15 minutes. What does this represent? C. What is the total distance traveled by Mary?
d. What is Mary's displacement from start to finish?
Answer:
B
Explanation:
i hope it hleps
Calculate the gravitational force producedbetween moon and every gram of sand on its surface.[Mass & radius of moon = 7 .2x10²² kg x 1700000m]
The magnitude of the gravitational force produced between moon and every gram of sand on its surface is 1.66 x 10⁻³ N.
What is the gravitational force?The gravitational force between the moon and every gram of sand on its surface is determined by applying Newton's law of universal gravitation.
This law states that every object in the universe attracts each other with force that is directly proportional to the product of the masses and inversely proportional to the square of the distance between the objects.
F = Gm₁m₂/R²
Where;
G is universal gravitation constantm₁ is mass of the sand = 1 g = 0.001 kgm₂ is mass of the moonR is the distance between the moon and the sandF = (6.67 x 10⁻¹¹ x 0.001 x 7.2 x 10²²) / (1,700,000)²
F = 1.66 x 10⁻³ N
Thus, from the magnitude of the gravitational force produced between moon and every gram of sand on its surface, we can say that it is quite small.
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after resting for 10 minutes, you decide to perform another explosive, one-time movement such as a standing vertical jump and again, exert maximal effort. you briskly push yourself up from a chair and walk about 1.5 minutes to arrive at a wall where a vertical jump measurement can be made.
In this case, anaerobic metabolism is utilized.
Anaerobic metabolism: What is it?The process of producing ATP anaerobically, also known as without oxygen or in the absence of oxygen, involves the direct phosphate transfer from phosphorylated intermediates like creatine phosphate or glycolytic intermediates to ADP, which in turn produces ATP.
What is the result of anaerobic metabolism?Lactic acid builds up as a result of the anaerobic metabolism of glucose, which causes metabolic acidosis. A base deficit results from the reaction between lactic acid and bicarbonate, which lowers serum bicarbonate levels.
What does aerobic versus anaerobic metabolism mean?Anaerobic metabolism only produces two ATP molecules for every glucose molecule while aerobic metabolism produces more ATP and depends on oxygen.
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A 2 kg block is pulled with 3.7 N of force to the right. The block experiences 1.7 N of friction. What is the acceleration of the block?
.
Answer:4.7
Explanation:
question 14: how long does the eclipse of an earth-like planet take? how much time passes between eclipses? what obstacles would a ground-based mission to detect earth-like planets face?
When the Sun passes through the nodal eclipse zones, the eclipses would last approximately 6 hours, with there being a chance of two solar eclipses every 34.5 days.
How far apart are eclipses?Each year, there are two to five solar eclipses, with a total eclipse occurring roughly every 18 months. You might be able to see that eclipse, depending on where you are in the world. The view of the eclipse and the Moon's shadow on Earth move from west to east as the Earth rotates.
Why are eclipses 6 months apart?This is due to the fact that there are roughly 15 days (or a fortnight) between a full moon and a new moon, and vice versa. There are enough days (30 days) for two more eclipses if one occurs at the start of the season.
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Which of the following equipment is not usually involved in the production of electricity?
The equipment that are usually involved in the production of electricity are generators.
The most commonly used electricity generation equipment are Turbines. Different types of turbines are used such as:
Steam turbinesWind turbinesHydroelectric turbineCombustion gas turbinesAn electrical generator is used along with the turbine to convert the mechanical energy produced by the turbine into electricity.
Some of the other equipment used to generate electricity are
Solar photovoltaic cellsInternal combustion enginesFuel cells etc.Therefore, the equipment that are usually involved in the production of electricity are generators.
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Answer:
Non-electric appliances you might already own
Coffee percolator. They make delicious coffee and are convenient for camping trips. ...
French press: This is another coffee maker that is as easy to use as a percolator. ...
Manual mixer. ...
Hand flour mill. ...
Dough maker. ...
Food strainer. ...
Manual food processor. ...
Zeer clay pot fridge.
Explanation:
non-electric equipment are use in the production of a work piece that does not involve the use of electrical equipment
What is the weight of a 179 kg football player?
The weight of a 179 kg of football player is 1755.99N.
How to calculate weight?Weight is the force on an object due to the gravitational attraction between it and the Earth.
Weight is a function of an object's mass and acceleration due to gravity, hence, can be calculated by multiplying the mass of the object by its acceleration.
According to this question, the mass of a football player is 179 kg is given. The acceleration due to gravity on Earth is 9.81m/s². The weight can be calculated as follows:
Weight = 179kg × 9.81m/s²
Weight = 1755.99N
Therefore, 1755.99N is the weight of the player.
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What is a force that one object can apply to another object without touching it?
A ferry approaches shore, moving north with a speed of 6.5 m/s m / s relative to the dock. a person on the ferry walks from one side of the ferry to the other, moving east with a speed of 1.1 m/s m / s relative to the ferry. what is the speed of the person relative to the dock?
The relative velocity with respect to the dock is 6.5j + 1.1 i m/s m/s.
We need to know about relative velocity to solve this problem. The relative velocity depends on the object and observer velocity. It can be written as
v = vo ± v'
where v is relative velocity, vo is object velocity and v' is observer velocity.
From the question above, we know that
vo = 6.5 j m/s
v' = 1.1 i m/s
The velocity will be added each other because the direction of the observer is different from the object.
v = vo + v'
v = 6.5j + 1.1 i
v = 6.5j + 1.1 i m/s
Thus, the relative velocity is in vector form.
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what is the purpose of this experiment?group of answer choicesthe purpose of this experiment is to understand series and parallel circuits, how to calculate their equivalent resistance, and how to construct the laboratory.the purpose of this experiment is to understand circuits.the purpose of this experiment is to comprehend ohm’s law and how to compare their percent difference from their experimental and theoretical values.the purpose of this law is to identify non-ohmic devices and how to convert those devices ohmic.
The purpose of this experiment is to understand series and parallel circuits, how to calculate their equivalent resistance, and how to construct the laboratory.
How do parallel circuits function?There are two or more paths that current to travel through in a parallel circuit. Each element of the parallel circuit has the same voltage applied to that too. The total current flowing from the source is equal to the sum of a currents through each path.
What is a parallel circuit example?When one route is blocked, electricity continues to flow thanks to a parallel circuit. Numerous lighting fixtures are a great example. Even if just one light in the fixture fails, led light stays on.
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A wide receiver starts at rest at the line of scrimmage and runs vertically towards the end zone for a pass. If the athlete accelerates at a constant rate of 1.7 meters per second^2, approximately how far did the athlete run if the play lasted 5.0 seconds? * 1 point
The distance travelled by the athlete given the play lasted for 5.0 seconds is 21.25 m
How to determine the distanceWe'll begin by listing out the parameters given from the question. This is given below:
Initial velocity (u) = 0 m/sAcceleration (a) = 1.7 m/s²Time (t) = 5 secondsDistance (s) =?From the given parameters, we can determine the distance as follow:
s = ut + ½at²
s = (0 × 5) + (½ × 1.7 × 5²)
s = 0 + 21.25
s = 21.25 m
From the above calculation, we conclude that the athlete ran 21.25 m during the 5 seconds play.
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in the movie thelma and louise, the two actresses drove off a cliff at the end. in preparation for the scene, their stunt doubles determined that the cliff was 50.0 m high. the director wants the car to land 90.0 m from the base of the cliff close to the camera location. how fast must the car be traveling in order to land at this location?
The car must be travelling at a speed of 28.21 m / s in order to land 90 m from the base of a 50 m high cliff.
According to Equations of motion,
s = ut + 1 / 2 at²
s = Distance
u = Initial velocity
t = Time
a = Acceleration
In vertical motion,
s = 50 m
u = 0
a = 9.8 m / s²
50 = 0 + 1 / 2 * 9.8 * t²
t² = 50 / 4.9
t² = 10.2
t = 3.19 s
In horizontal motion,
s = 90 m
a = 0
90 = 3.19 u + 0
u = 90 / 3.19
u = 28.21 m / s
Therefore, the initial speed of the car must be 28.21 m / s
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Consider a 0. 5-kg meter stick with a 1. 0 kg mass attached at the 50 cm mark and a 3. 0 kg mass at the very end. Where on the meter stick is the center of mass located?.
Answer:
The effective mass at the 50 cm mark will be 1.5 kg because the meter stick is uniform and .5 kg can be considered to be acting at 50 cm
3 * (50 - x) = 1.5 * x
Balancing torques where x is the distance from the 50 cm mark
150 - 3 x = 1.5 x
x = 150 / 4.5 = 33.3
x would be at 50 - 33.3 = 16.7
Check: 3 * 16.7 = 1.5 * 33.3
50.1 = 50 within rounding
A student building a game wants to launch a 0.0060kg using a spring. The spring constant is 380N/m. Assume no mechanical energy is lost from the system
The total mechanical energy of the spring is 4.275 x 10⁻⁶ J.
What is the total mechanical energy of the system?
The total mechanical energy of the system if no energy is lost from the system is calculated as follows;
U = ¹/₂kx²
where;
k is the spring constantx is the extension of the springThe extension of the spring is calculated as follows;
F = kx
x = F/k
x = mg/k
x = (0.006 x 9.8) / 380
x = 0.00015 m
The mechanical energy of the spring is calculated as follows;
U = ¹/₂(380)(0.00015)²
U = 4.275 x 10⁻⁶ J
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The complete question is below:
A student building a game wants to launch a 0.0060kg using a spring. The spring constant is 380N/m. Assume no mechanical energy is lost from the system. find the total mechanical energy of the system
A mountain climber is hanging from a vertical rope, far above the ground and far from the rock face. The rope is vertical
A mountain climber is hanging from a vertical rope, far above the ground and far from the rock face. the forces on the mountain climber are
Tension WeightThis is further explained below.
What is Tension?Generally, Tension is defined as the pulling force that is transmitted axially by the means of a string, a cable, a chain or another object of a similar nature, or by each end of a rod, truss member, or another object of a similar three-dimensional nature.
Alternatively, tension can be defined as the action-reaction pair of forces that act at each end of the elements in question.
The gravitational pull that gravity exerts on an item is quantified by that object's weight.
There is a common conception that weight is a vector quantity that represents the gravitational force that is exerted on the item. Some people consider weight to be a scalar number, which they define as the intensity of the gravitational pull.
In conclusion, One of the mountain climbers is suspended on a rope that runs vertically up the mountain, high above the earth, and away from the rock face. Tension and weight are the forces acting upon the mountain climber.
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CQ
A mountain climber is hanging from a vertical rope, far above the ground and far from the rock face. The rope is vertical. Identify the forces on the mountain climber.
A ball is projected with 40m/s vertically upward. (Ignore air resistance)
Compute A. the total time of flight
B. the maximum height
C. the velocity at t=5s
IN DESPERATE NEED OF HELP!!!
Make us of equation of motion formulas.
a.) the total time of flight = 8.16 s
b.) the maximum height reached = 81.6 m
c.) the velocity at t = 5s = 9 m/s
Motion Under GravityMotion of any object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.
Given that a ball is projected with 40 m/s vertically upward.
A. the total time of flight of the ball will be T = 2t
At maximum height, v = 0.
v = u - gt
0 = 40 - 9.8t
9.8t = 40
t = 40 / 9.8
t = 4.08 s
T = 2 × 4.08
T = 8.16 s
B. the maximum height H can be found by using the formula
v² = u² - 2gH
At maximum height, v = 0
0 = u² - 2 × 9.8 × H
40² = 19.6H
H = 1600/19.6
H = 81.6 m
C. the velocity at t = 5s will be v
v = u - gt
v = 40 - 9.8 × 5
v = 40 - 49
v = - 9 m/s
That is, 9 m/s in the opposite direction ( coming downward )
Therefore, the total time of flight of the ball is 8.16 s, the maximum height reached is 81.6 m and the velocity at t = 5s is 9 m/s
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A train changes it’s speed from 3m/s to 17m/s in 2.0 seconds calculate its acceleration.
Answer: acceleration of the train = 7 m/s^2
Explanation: We are going to use the formula for acceleration,
acceleration of a moving body is the change in speed per unit of time, hence the formula for finding acceleration is
a = (v-u)/t
here, a = acceleration
v = final speed
u = initial speed
t = total time taken
here (v-u) will give the change in velocity since it's the difference between the final and initial velocity of the train
Given, v = 17 m/s
u = 3 m/s
t = 2 s
∴ a = (17-3)/2
= 14/2
= 7 m/s^2
what is the relationship between instantaneous speed and instantaneous velocity? group of answer choices they are unrelated. instantaneous speed is the initial speed minus the final speed. instantaneous speed is the rate at which the instantaneous velocity is changing. instantaneous speed is the magnitude of the instantaneous velocity. they are identical.
The relationship between instantaneous speed and instantaneous velocity is that instantaneous speed is the magnitude of the instantaneous velocity.
Instantaneous velocity is the rate of change of position for a very small interval of time. The interval of time so that that its value is almost zero. Instantaneous speed is the magnitude of instantaneous velocity without any direction.
The instantaneous velocity is vector quantity just like velocity and the instantaneous velocity is a scalar quantity just like speed. The value of if instantaneous velocity with direction is instantaneous velocity.
Therefore, the relationship between instantaneous speed and instantaneous velocity is that instantaneous speed is the magnitude of the instantaneous velocity.
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A moving object always has energy in its ______ ______ ______. What 3 words complete the sentence?
Explanation:
A moving object always has kinetic energy store
An 800 kg car is travelling at 70 mph and overtaking
a 15 000 kg truck travelling at 55 mph. Calculate the
ratio of the momentum of the truck to the momentum
of the car (Ptruck/Pcar).
Value
Units
kg m/s
Check my answer
?
Answer:
????
Explanation:
what do the terms self-confirmation bias and hindsight bias refer to and how might they contribute to perceiving an illusory correlation?
Self-confirmation bias is looking for information the support a personal perception while hindsight bias is a past predictions.
What is illusory correlation?An illusory correlation is the type of correlation that is perceived to exist between two variables even when there is actually no relationship existing between them.
There are two types of illusory correlation that includes the following:
Distinctiveness-based illusory correlations: This type of illusory correlation that contributes to the to initial formation of predictions.Expectancy-based illusory correlations: This is the type of illusory correlation that contains predictions that are not liable to change.Therefore, looking for the information that supports personal perception and the ability to generate past predictions helps in illusory correlation.
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