The amount of work done by the boy in pulling the sled is 8064.41 J
Definition of work doneWorkdone is defined as the product of force and distance moved in the direction of the force. It can be expressed mathematically as:
Workdone (Wd) = force (F) × distance (d)
Wd = Fd
Considering angle projection,
Wd = FdCosθ
How to determine the workdone Force (F) = 2.6 lb = 2.6 × 4.448 = 11.5648 NDistance (d) = 2640 ft = 2640 × 0.305 = 805.2 mAngle (θ) = 30°Workdone (Wd) =?Wd = FdCosθ
Wd = 11.5648 × 805.2 × Cos 30
Wd = 8064.41 J
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the nuclues of an atom contains which subatomic particles
Activity 5: My FB (Faulty Block)
Directions: Given the illustration of the fault blocks below, draw how it looks like
after acted upon by stress forces. Draw the direction of forces acting on each type
of stress force in the fault blocks and identify the type of stress acting on the
block.
according to Newton's second law of motion. what is force product
Answer:
Force can be defined as the product of mass and acceleration.
Explanation:
~Cornasha_Weeb
Which statement describes the density of the inner planets?
All the inner planets are dense.
The inner planets are less dense than the outer planets.
Earth is dense, while the other inner planets are not.
Mercury and Venus are dense, while Earth and Mars are no
Answer:
The inner planets are less dense than the outer planets
Please brainliest my answer iam begging you for god sake
Answer:
The inner planets are less dense than the outer planets .
Explanation:
Please Mark Me As a brainliestA 200g ball is accelerated from 5m/s to 25m/s in 0.3sec. What force was applied?
Answer:
30N
Explanation:
30N of force was applied
quizlet
The net force on an object is
Answer:
Net Force. when all combinations of force acting on an object. Force. A push or pull
So it's the third answer
( the combination of all forces acting on it )
Can a convex mirror form a real image?
Answer:
yes !
Explanation:
a mirror transforms and flips , but nonetheless produces a real image.
One day, the distance between the crests of the waves at sea is 2.5m. The shortest time between the lowest and highest positions of the floating boat was 0.625 seconds.
a) Calculate the wave period.
b) Calculate the speed of the wave.
Answer:
1.25 sec, 2 m/s
Explanation:
Period = 2 * 0.625 sec = 1.25 sec
speed = 2.5/1.25 = 2 m/s
3. A wooden block is at rest on a wooden inclined
plane. As the angle the plane makes with the
horizontal is increased, the magnitude of the
force of static friction between the block and
the plane
(1) decreases
(2) increases
(3) remains the same
As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases
Static frictional forceSince the static frictional force between the block and the plane is given by F = μN where
μ = coefficient of static friction and N = normal force on plane = component of weight of block perpendicular to the plane = Wcosθ where W = weight of block and θ = angle of inclined planeNow, F = μN
F = μWcosθ
Since μ and W are constant, we see that
F ∝ cosθ and cosθ ∝ θ
So, F ∝ θ
Since the static frictional force is directly proportional to the angle the plane makes with the horizontal, when the angle the plane makes with the horizontal is increased, the static friction between the block and the plane increases.
So, As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases
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A copper wire has a diameter of 1.947 mm. What magnitude current flows when the drift velocity is 1.79 mm/s
Answer:
72.5 A
Explanation:
There are about 13.6 coulombs of free electron charges in each cubic mm of copper. So, the rate of movement of charge is that quantity multiplied by the volume in the flow.
V = πr²h . . . . . volume of a cylinder
V = π(1.947 mm/2)²(1.79 mm/s) = 5.329 mm³/s
Then the charge flow rate is ...
(13.6 C/mm³)(5.329 mm³/s) = 72.5 C/s
The magnitude of the current is about 72.5 amperes.
______
Additional comment
The volume of free charge in copper can be computed from the density, molar mass, number of atoms in a mole, number of charges in a coulomb, and the number of free charges per atom. Some of the combinations of necessary calculations can be found with a web search, so it is not unreasonable to presume that the charge density is known.
A ball is thrown 125 meters upward and then falls the same distance back to Earth. Neglecting air resistance, its total time in the air is
Answer:
the ball is in the air for 10 seconds
Explanation:
let gravity = 10m/s/s
height = 1/2 acceleration • time^2
125 m = 1/2 • 10 m/s/s • time ^2
125m = 5 m/s/s • time^2
25s = time^2
5 s = time
5 seconds is the time required for half of the flight
time total = 2 • time
time total = 2 • 5s
time total = 10 s
what is the relationship between distance, average speed and time
Answer:
average speed= total distance/total time
Explanation:
Related to the distance traveled by the object which means, it is only represented by the magnitude and direction of travel is not important. so average speed= total distance/total time
pysics question can anyone answer me this question
Answer:
Im pretty sure they're equal, i could be wrong though. Hope i helped have an amazing day :D
Explanation:
Answer:
B: equal
Explanation:
A 1,200 kg car accelerates at 3 m/s2. What net force is the car experiencing during this
acceleration?
0 3600 N
0 2000 N
2400 N
O ON
Answer:
3600 N
Explanation:
F=ma
1200*3 = 3600
i’m kinda stuck right now…
7 principles of Exercise and Sports Training
Answer: individuality, specificity, progression, overload, adaptation, recovery, and reversibility.
Explanation:
individuality, specificity, progression, overload, adaptation, recovery, and reversibility.
Answer:
1. individuality
2. specificity
3. overload
4. adaptation
5. recovery
6. reversibility
7. progression
Explanation:
I learned this last year.
Find the charge on capacitor, C2 , in the diagram below if V_ab=24.0 volts,〖 C〗_1=6.00 μF,〖 C〗_2= 3.00 μF,and C_3=10.0 μF.
The charge on the capacitor 2 (C₂) is 48μF.
Analysis of the circuit diagramIn the circuit diagram, C₁ and C₂ are in series connection, while C₃ is parallel to C₁ and C₂.
Same charge flows in a series arrangement (charge on C₁ = charge on C₂).Same voltage flows in a parallel arrangement (voltage on C₁, C₂ = voltage on C₃).Charge on capacitor C₁ and C₂[tex]Q_1 = Q_2 = Q\\\\V = \frac{Q}{C_1} + \frac{Q}{C_2} \\\\V = Q(\frac{1}{C_1}+ \frac{1}{C_2} )\\\\V = Q(\frac{C_2 + C_1}{C_1 C_2} )\\\\Q = V(\frac{C_1 C_2}{C_2+ C_1} )\\\\Q = 24 \times (\frac{6\times 10^{-6} \times 3 \times 10^{-6}}{6\times 10^{-6} \ + \ 3\times 10^{-6}} )\\\\Q = \frac{4.32 \times 10^{-10}}{9\times 10^{-6}} \\\\Q = 4.8\times 10^{-5} \ C\\\\Q = 48 \ \mu C[/tex]
Thus, the charge on the capacitor 2 (C₂) is 48μF.
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Alkali Metals • Most ___________________ metals
Answer: They’re the most reactive metals
Explanation: They have larger ionic radii and low ionization energies
Really need help! ;(
Could you please explain it? :)
GIVING 10 POINTS
Answer:b
Explanation: If you look at the line on the graph, you can see that it is going downward, meaning it has a negative slope, and choice b is the only one that has a negative slope
A car of mass 1000 kg is heading east at 25 m/s. It collides with a car of mass 1200 kg heading north at 30 m/s. When the cars collide, they stick together.
d. At what angle do the cars move after the collision? (2 points)
Given :-
A car of mass 1000 kg is heading east at 25 m/s. It collides with a car of mass 1200 kg heading north at 30 m/s. When the cars collide, they stick together.To Find :-
At what angle do the cars move after the collision?Solution :-
Here it's given that a car of mass 1000kg moving with velocity of 25m/s North . Another car of mass 1200kg is moving with velocity 30m/s East.
So that ,
[tex]v_{1}= 25m/s \ E= 25 \hat{i} m/s [/tex]
And ,
[tex]v_{2}= 30m/s \ N = 30 \hat{j} m/s [/tex]
See attachment .
From Triangle law of vector addition , the resultant of both vectors will be given by third side of the triangle taken in opposite direction.
So , if the resultant velocity makes an angle [tex]\theta[/tex] . Then ,
[tex] tan\theta = \dfrac{v_2}{v_1} [/tex]
Substituting the respective values,
[tex]tan\theta =\dfrac{30m/s}{25m/s} [/tex]
Simplify ,
[tex]tan\theta =\dfrac{6}{5}[/tex]
Take arctan both sides ,
[tex]\theta = tan^{-1}\bigg(\dfrac{6}{5}\bigg)[/tex]
Hence the cars move at an angle of tan-¹(6/5) NE after the collision .
A ray of light bends upon entering a new medium. What is the phenomenon called?
Explanation:
refraction is the change in direction of a wave passing from one medium to another or from a gradual change in the medium.
3) A square coil of sides 0.40 m carries a current of 3.0 A in a uniform magnetic field of 5.0 mT. the plane of the coil is parallel to the magnetic field as shown in figure below.
a) Calculate the force on each side of the coil.
b) What is the resultant effect of the force on the coil?
c) What happen to the coil?
A ball is placed at the top of a hill then released. After 5 seconds it has a speed of 20 m/s. What is the average acceleration of the ball
Answer:2
Explanation:When the ball is released from the top of the hill then it's initial velocity (u)=0 And it's final velocity will be after 5 second (v)=2.
Answer:
Explanation:
a ball is placed at the top of the hill and then released after five seconds and has a speed of 20 m/s. What is the average acceleration of the ball?
Peak expiratory flow readings are Higher in the morning; lower in the evening Lower when patients are well; higher when patient's airway is constricted Lower in the morning; higher in the evening Higher when patients are well; lower when patient's airway is constricted
Peak expiratory flow readings are higher when patients are well, but lower when a patient's airway is constricted.
What is the peak expiratory flow?This term is used in medicine to refer to the maximum rate of a person's exhalation or to how fast and how long can they exhale.
This rate is measured by using the peak expiratory flow test that requires you to deeply inhale and then exhale as fast as hard as possible.
What does the peak expiratory flow indicate?This rate is closely related to the amount of air flowing out of the lungs. This implies the peak expiratory flow is lower if there is a disease such as asthma that can constrict the airways.
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Acar accelerates from 4 meters/second to 16 meters/second in 4 seconds. The car's acceleration is
meters/second?
To understand this question, you need to understand the concept of acceleration first. Have you ever been in a car and noticed that it was getting faster and faster? That "speeding up" of the car is known as acceleration! Acceleration is essentially the rate at which you speed up.
Okay, so we now know what acceleration is. What are its units? The unit of acceleration is the change in velocity over a period of time: [tex]\frac{∆v}{t}[/tex]
If you haven't learned about velocity yet, just think about it as speed for now. The funny-looking triangle, ∆, is a symbol for "the change of." For example, if I started walking at 3 [tex]\frac{feet}{second}[/tex] then sped up to 5 [tex]\frac{feet}{second}[/tex], then the change in my speed would be 2 [tex]\frac{feet}{second}[/tex], because I started walking 2 [tex]\frac{feet}{second}[/tex] faster!
Okay, enough with all the explanations. Hopefully, you understand the units now. Let's take a look at the question. A car accelerates from 4 [tex]\frac{meters}{second}[/tex] to 16 [tex]\frac{meters}{second}[/tex] in 4 seconds. What would the acceleration be? Let's set up an equation:
a = [tex]\frac{∆v}{t}[/tex]
a is the acceleration, ∆v is the change in velocity, and t is the time elapsed.
Now, let's plug in our values! ∆v is the change in velocity, and to find that we simply have to subtract 16 [tex]\frac{meters}{second}[/tex] by 4 [tex]\frac{meters}{second}[/tex]. That makes sense, right? Back to the equation.
a = [tex]\frac{∆v}{t}[/tex]
a = [tex]\frac{16-4}{4}[/tex]
(16 - 4 is the change in velocity, and 4 is the number of seconds the car was accelerating)
a = [tex]\frac{12}{4}[/tex]
a = 3 ([tex]\frac{meters}{second^{2}}[/tex])
We have our answer! The car's acceleration is 3 meters per second^{2}.
(You might be thinking: Wait. Meters per second squared? The reason for that is because acceleration is the rate at which the speed increases! That makes the unit [tex]\frac{\frac{meters}{second}}{second}[/tex], which can be simplified down to [tex]\frac{meters}{second^{2} }[/tex])
Let me know if you need clarification on anything I explained here!
- breezyツ
In a pulley system, two blocks are connected by a rope as shown below. The coefficient of static friction between block A and the surface is 0.8. Block A has a mass of 20kg. What is the minimum mass that block B can have so that block A moves?
Hi there!
We can begin by doing a summation of forces for each block.
Block A:
This block has the force of tension (in direction of acceleration +) and static friction (opposite direction -) acting on it. Thus:
[tex]\Sigma F_A = T - F_s\\\\m_Aa = T - \mu m_Ag[/tex]
Block B:
This block has the force of tension (opposite of acc. -) and gravity (in direction of acc +), working on it.
[tex]\Sigma F_B = m_Bg - T\\\\ m_Ba = m_Bg - T[/tex]
Add both of the expressions and solve for the maximum mass of Block B.
[tex]\Sigma F = m_Bg - T + T - \mu m_Ag\\\\a(m_A + m_B) = m_Bg - \mu m_Ag[/tex]
To find the minimum value, we can set a = 0, so:
[tex]0 = m_Bg - \mu m_Ag\\\\\mu m_Ag = m_B g\\\\0.8(20)(9.8) = m_B (9.8)\\\\m_B = \frac{0.8(20)(9.8)}{9.8)} = \boxed{16 kg}[/tex]
The block must weigh > 16 kg for block A to move.
HITLOW
SS
1/6
A5 kg body is having a Kinetic energy of 250 J. What is the velocity of the body?
15 m/s
20 m/s
40 m/s
10 m/s
ME
Answer:
10 m/s
Explanation:
KE = 1/2 • m • v^2
250 J = 1/2 • 5 kg • v^2
(2 • 250 J / 5 kg )^1/2 = v
(100)^1/2 = v
10 = v
What does acid rain look like so that anyone can recognize it?
What is the velocity (in metres per second) of a Canadian
Forces CF-18 fighter jet that travels 8.864 km [S] in
0.297 min?
Answer:
497 m/s
Explanation:
(8.864 x 10^3 m)/(0.297 * 60 sec) = 497 m/s
The velocity (in metres per second) of a Canadian Forces CF-18 fighter jet would be 497.41 meters/second.
What is speed?The total distance covered by any object per unit of time is known as speed.
As given in the problem we have to find out the velocity (in meters per second) of a Canadian Forces CF-18 fighter jet that travels 8.864 kilometers [S] in 0.297 minutes,
The distance traveled by the CF-18 fighter jet = 8.864 kilometers
1 kilometer = 1000 meters
8.864 kilometers = 8.864× 1000 meters
=8864 meters
The time taken by CF-18 fighter jet = 0.297 minutes
1 minute = 60 seconds
0.297 minutes = 0.297 ×60 seconds
=17.82 seconds
The velocity of the CF-18 fighter jet =8864 meters/17.82 seconds
= 497.41 meters/second
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What is the difference between molecules and
compounds?
Answer:
All compounds can be classified as molecules, but not all molecules can be called compounds. Molecules are formed by two or more atoms that are bonded by chemical bonding's. Compounds are constructed by two or more elements where the elements are mixed in fixed ratios.
Answer:
Molecules are formed by two or more atoms that are bonded by chemical bondings.
Compounds are constructed by two or more elements where the elements are mixed in fixed ratios
*All compounds can be classified as molecules, but not all molecules can be called compounds.
Explanation:
pls brainliest if you don't mind
anyway i hope this helped have an awesome day bye byee