Answer:
2838
Explanation:
If the ratio between the frequency of a man's voice and that of a girl's voice is 3/4, what
is the ratio between the speeds of the voices of the man and the girl in air ?
Answer:
it is 34
34 is th answer
Explanation:
Importance of a cell
Explanation:
Cells are the basic building blocks of all living things. The human body is composed of trillions of cells. They provide structure for the body, take in nutrients from food, convert those nutrients into energy, and carry out specialized functions.
How much voltage is required to run 0.054 A of current through a 152
resistor? Use AV = IR.
A. 3.6 x 10-3V
B. 2.8 x 102V
C. 1.2 V
D. 0.81 V
V = I • R
V = (0.054 A) • (152 ohms)
V = 8.208 volts
None of the listed choices is correct.
Un delfín nada en el mar, a una profundidad tal que experimenta es de 2,22 x 10⁵ PA. Si la densidad del agua del mar es de 1030kg/m³, ¿A qué profundidad nada el delfín?
Answer:
El delfín nada a una profundidad de 22 m
Explanation:
El principio fundamental de la hidrostática establece que la presión en un punto del interior de un fluido (presión hidrostática) es directamente proporcional a su densidad, a la profundidad que se encuentre dicho punto y a la gravedad del sitio en el que se encuentre el fluido.
Esto se expresa como:
P=ρ⋅g⋅h
donde:
P es la presión en un punto del fluido. ρ es la densidad del fluido .g es la gravedad del lugar donde se encuentre el fluido. h es la profundidad.En este caso:
P= 2.22*10⁵ Paρ= 1,030 [tex]\frac{kg}{m^{3} }[/tex]g= 9.8 [tex]\frac{m}{s^{2} }[/tex]h= ?Reemplazando:
2.22*10⁵ Pa= 1,030 [tex]\frac{kg}{m^{3} }[/tex] * 9.8 [tex]\frac{m}{s^{2} }[/tex] * h
Resolviendo:
[tex]h=\frac{2.22*10^{5} Pa}{1,030\frac{kg}{m^{3} }*9.8 \frac{m}{s^{2} }}[/tex]
h= 21.993 m ≅ 22 m
El delfín nada a una profundidad de 22 m
PLEASE HELP
uniform motion and nonuniform motion bibliography
Answer:
Abstract
A methodology for designing mechanical non-uniform motion generators is presented. The basic requirements for four-bar and six-bar linkages are established and it is shown how the performance can be evaluated by harmonic analysis applied to the output angular velocity function. A means of creating and searching a library of mechanisms based on normalized output functions is presented. B-spline curves are used as a means of defining a desired performance and it is shown how minimum acceleration can be achieved with continuity in the derivatives. Finally, a means of increasing the quality of motion transmission in the selected mechanisms is given. The techniques are used to synthesize a six-bar linkage.
A 200 g blob of clay moves with a speed of 10 m/s towards a 300 g cart that is initially at rest.
a. What is the momentum of the system before the blob of clay strikes the cart?
b. What must be the momentum of the system after they come together?
c. If the blob of clay sticks to the cart, with what speed will the clay and cart move after they come together?
Answer:
a. 2 kg*m/s
b. [tex]p_{T_{f}} = 0.5v_{f} = 2 kg*m/s[/tex]
c. 4 m/s
Explanation:
a. The momentum of the system ([tex]p_{Ti}[/tex]) before the blob of clay strikes the cart is:
[tex] p_{Ti} = p_{b} + p_{c} [/tex]
Where:
[tex]p_{b}[/tex] is the momentum of the blob clay
[tex]p_{c}[/tex] is the momentum of the car
[tex] p_{Ti} = m_{b}v_{b} + m_{c}v_{c} [/tex]
Since the car is initially at rest, [tex]v_{c}[/tex] = 0
[tex] p_{Ti} = 200 g*\frac{1 kg}{1000 g}*10 m/s + 0 = 2 kg*m/s [/tex]
b. The momentum of the system after they come together:
[tex]p_{T_{f}} = m_{b}v_{b} + m_{c}v_{c}[/tex]
Since they come together, [tex]v_{b}[/tex] =
[tex]p_{T_{f}} = v_{f}(m_{b} + m_{c}) = v_{f}(0.2 kg + 0.3 kg) = 0.5v_{f}[/tex] (1)
Because we do not have the final speed we can not calculate the final momentum.
c. We can find the speed of the clay and car by conservation of the momentum:
[tex] p_{i} = p_{f} [/tex]
The initial momentum of the system was founded in part "a" (p = 2 kg*m/s), so we have:
[tex] 2 kg*m/s = m_{b}v_{b_{f}} + m_{c}v_{c_{f}} [/tex]
Again, when they come together, the final speed is the same:
[tex] 2 kg*m/s = v_{f}(m_{b} + m_{c}) [/tex]
[tex] v_{f} = \frac{2 kg*m/s}{0.2 kg + 0.3 kg} = 4 m/s [/tex]
Now, since we found the final speed we can calculate the momentum of the system after they come together (equation 1):
[tex] p_{T} = 0.5v_{f} = 0.5 kg*4m/s = 2 kg*m/s [/tex]
I hope it helps you!
What is the relationship between kinetic and potential energy in a roller coaster.
Answer: Kinetic energy is energy that an object has as a result of its motion. Potential energy is stored energy that has not yet been released.
Explanation: All moving objects possess kinetic energy, which is determined by the mass and speed of the object. Potential energy is the energy an object has as a result of its position.
.How does the pattern of light that results when it passes through the slits in the double-slit experiment support the wave model of light?
A. .
It is the result of refraction.

B.
It is the result of diffraction.

C.
It is the result of the photoelectric effect.

D.
It is the result of blackbody radiation.
Answer:
B
Explanation:
The pattern that the double slit experiment produces is a diffraction pattern (made as a result of single and double slit interference).
Answer:
B. It is the result of diffraction.
Explanation: a p e x
1. Some penguins are playing turtle hockey on the frictionless ice. Ramona the penguin hits the turtle
with a force of magnitude F, and the turtle experiences an acceleration of magnitude a (Fand a are of
unknown size). Francisco the penguin hits the same turtle with a force of magnitude three times
greater than Ramona's force (3F). What will the resulting acceleration of the turtle be? Answer in
terms of a. Support your answer with reasoning and reference to Newton's Second Law.
Answer:
a' = 3a
Explanation:
Newton's Second Law gives the magnitude of the unbalanced force applied to an object as follows:
F = ma
where,
F = Force Applied
m = Mass of Object
a = acceleration
FOR RAMONA'S PUSH:
F = F
m = m
a = a
Therefore,
F = ma
a = F/m ---------------- equation (1)
FOR FRANSICO'S PUSH:
F = 3F
m = m (mass of turtle will be same)
a = a'
Therefore,
3F = ma'
a' = 3F/m
using equation 1
a' = 3a
A annoying small child is dropped off a 16.0 m cliff (for complaining about homework). The
speed the child will reach right before they hit the ground is
m/s - Don't worry,
the child will not sustain life threatening injuries as they ended up doing all their homework
and therefore was saved by the magical Physics Creature.
(Record your answer to correct significant digits).
Answer:
i would be that annoying child lol
Explanation:
but i just needed this for points sorry :>
A satellite is orbiting the Earth in a circular orbit of radius r. Its frequency is independent of its height above the surface of the Earth. a. TRUE b. FALSE
Answer:
a. TRUE
Explanation:
When a satellite is launched to orbit around earth, it has to produce its own artificial gravity by performing rotations. The frequency of this rotation is given by the following formula:
f = √[ac/4πR²]
where,
f = frequency
ac = centripetal acceleration
R = Radius of the satellite
Therefore, it is clear from this formula that the frequency of rotation of the satellite is independent of its height above the surface of earth. So, the correct option is:
a. TRUE
is the term used to describe the removal of sand and soil by the wind.
Answer:
erosion
Explanation:
Abdul of mass 50 kg is standing in an elevator of his building. The elevator is moving
upwards and is slowing down at a rate of 2.0 m/s? What is Abdul's apparent weight?
Use g = 10 m/s
Answer:
Abdul has an apparent weight of 600 newtons.
Explanation:
The statement is incorrectly written. Its correct form is:
Abdul of mass 50 kg is standing in an elevator of his building. The elevator is moving upwards and is slowing down at a rate of 2.0 m/s2. What is Abdul's apparent weight? Use g = 10 m/s2.
According to the statement, we know that elevator and Abdul himself are moving upwards and decelerating, which means that Abdul feels a force from elevator is the same direction of his weight. From 2nd Newton's Law we find the following equation of equilibrium:
[tex]\Sigma F = F-m\cdot g = m\cdot a[/tex] (1)
Where:
[tex]F[/tex] - Apparent weight, measured in newtons.
[tex]m[/tex] - Mass of Abdul, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]a[/tex] - Net acceleration of the elevator-Abdul system, measured in meters per square second.
In (1) we clear the apparent weight:
[tex]F = m \cdot (a+g)[/tex]
If we know that [tex]m = 50\,kg[/tex], [tex]a = 2\,\frac{m}{s^{2}}[/tex] and [tex]g = 10\,\frac{m}{s^{2}}[/tex], we find that the apparent weight of Abdul is:
[tex]F = (50\,kg)\cdot \left(2\,\frac{m}{s^{2}}+10\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 600\,N[/tex]
Abdul has an apparent weight of 600 newtons.
please help lol
im on my sisters acc btw
Answer:
sitting leg curls= hamstring
shrugs=shoulders
machine curls=biceps
bench press= pectorals
A weight lifter is trying to lift a 1,500 N weight but can apply a force of only 1,200 N on the weight. One of his friends helps him lift it at a constant velocity. What force was applied to the rope
Answer:
400N is applied to the rope
Answer:
300N
Explanation:
Assuming his friend didn't throw the box, they would need a total of 1,500N to lift it, if the first person is already applying 1,200N, the only other amount of force needed is 300N to make a total of 1,500N! Simple math problem :)
Hope this helps! <3
A cannonball is shot from the top of
a 47.8 m high hill at a speed of
53.7 m/s. At its highest point, it is
moving at 31.5 m/s.
How high is it then?
A cannonball is shot from the top of a 47.8 m high hill at a speed of 53.7 m/s. The height then is 61.81 m/s.
What are kinematic equations?The motion of an object with constant acceleration is described by a set of equations known as kinematic equations. Integrals, derivatives, and rates of change must all be understood in order to solve kinematics equations.
Velocity is the rate and direction of an object's movement, whereas speed is the time rate at which an object is moving along a path. In other words, velocity is a vector, whereas speed is a scalar value.
The kinematic equation is:
v² = u² + 2gs (a = g)
Where u is the initial velocity, a is the acceleration, and v is the velocity after the time period t.
(53.7)² + 2 x 9.8 x 47.8 m
Therefore, the height is 61.81 m/s.
To learn more about kinematic equations, refer to the below link:
https://brainly.com/question/23577405
#SPJ2
it’s 144.2 I have it in my notes from when I was in school!!!!
The Tissues of vascular Plants are organized into more complex structures that carry out a Variety of functions in the plant what structure is formed by a Group of tissues that work together to carry out a Specific function
A) Cell
B) Organ system
C)Organism
D Organ
DUE IN 20 MINUTES HELP
Choose:-
The opposite table shows the relation between
the resultant force of two forces and
the angle between them then the values of the
two forces are
a) 4N,3N
b) 6N,5N
c)3N,2N
d)2N,1N
CAN ANYONE ANSWER ME PLZZ?? QUICKLY !
My mommy wants to talk to you
A 25 N force is used to push a box across a floor against a frictional force of 14 N. The box
accelerates from rest to a speed of 4 m/s in 16 s. What is the mass of the box?
Answer:
[tex]m = 44~Kg[/tex]
Explanation:
Net Force
Newton's second law explains the dynamics principles when a number of forces are applied to an object.
The net force vector is the sum of the individual vector forces applied. The magnitude of the net force is related to the magnitude of the acceleration of the body as follows:
[tex]Fn=m.a[/tex]
Furthermore, the acceleration can be calculated if we know the kinematic behavior of the body:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
Where vf, vo, and t are the final speed, initial speed, and time, respectively.
The box is pushed across the floor with a force of 25 N against a frictional force of 14 N.
The net force applied to the box is:
[tex]Fn = 25 N - 14 N = 11 N[/tex]
We also know the box is accelerated from rest (vo=0) to vf=4 m/s in t=16 seconds, thus:
[tex]\displaystyle a=\frac{4-0}{16}[/tex]
[tex]a = 0.25~m/s^2[/tex]
From the equation:
[tex]Fn=m.a[/tex]
We solve for m:
[tex]\displaystyle m=\frac{Fn}{a}=\frac{11~N}{0.25~m/s^2}[/tex]
[tex]\mathbf{m = 44~Kg}[/tex]
A roller coaster speeds up with constant acceleration for 2.3\,\text{s}2.3s2, point, 3, start text, s, end text until it reaches a velocity of 35\,\dfrac{\text{m}}{\text{s}}35
s
m
35, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction over 41\,\text{m}41m41, start text, m, end text. We want to find the initial velocity of the roller coaster before it started to accelerate.
Which kinematic formula would be most useful to solve for the target unknown?
Answer:
This one:
Explanation:
Khan academy answer
How long will it take a plane to fly 1256km
if it travels 500km/hr?
Answer:
The answer is 2.51 sExplanation:
The time taken can be found by using the formula
[tex]t = \frac{d}{v} \\ [/tex]
d is the distance
v is the velocity
From the question we have
[tex]t = \frac{1256}{500} \\ = 2.512[/tex]
We have the final answer as
2.51 sHope this helps you
The path of a projectile is called a ???
Answer:
Projectile motion is a form of motion where an object moves in parabolic path; the path that the object follows is called its trajectory.
Explanation:
A motor with a resistance of 320 is connected to a voltage source. Four amps of current flows
in the circuit. What is the voltage of the source?
I
Answer:
V = 1280 [V]
Explanation:
To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the resistance by the current.
Therefore we have:
V = I*R
where:
V = voltage [V] (Units of volts)
I = current = 4 [amp]
R = resistance = 320 [ohms]
V = 4*320
V = 1280 [V]
How do the independent and dependent variables in an experiment compare?
А.
The independent and dependent variables have no effect on each other.
В.
The dependent variable controls the independent variables.
C
The independent and dependent variables are the exact same as each other.
D
The independent variable controls the dependent variables.
which of the following influences healthy sexual attitude
1.family 2.friends 3.media 4.self
Melanie ran the 100 meters race in 12 seconds what was her avarage speed?
Answer:
melanie ran 8.3 meters per second
Explanation:
I think thats right, hope it helps.
a baby carriage is sitting on the top of a hill that is 21 m high. the carriage with a baby 75kg. the carriage has what energy? calculate it
Answer:
It has potential energy
PE = 15450.75 J
Explanation:
we know its potential energy because the carriage is not moving, although it can
PE = mgh
in this case, m is 75, h is 21, and g is always 9.81
plug these in: PE = (75) (21) (9.81)
your answer: PE = 15450.75 J
Disponemos de datos de presión y volumen de tres situaciones de un gas ideal que se han medido manteniendo la temperatura del gas constante representa los valores de un gráfico p-v expresa matemáticamente la ley de Boyle-Mariotte y calcula el valor de la constante
Answer:
Explanation:
This is an exercise in thermodynamics, the ideal gas equation is
PV = n R T
In this case the temperature is constant, so
n R T = cte
throughout the experiment
We can write the relationship for the three points 1, 2 and 3
P₁ V₁ = P₂ V₂ = P₃ V₃ = cte
In the attached graph we can see a graph of this relationship
the data for this graph are
V(m³) P ( Pa)
V₀ P₀
V₀/2 2 P₀
V₀/4 4 P₀
for the graph, let it be assumed that V₀ = 1 and P₀ = 1
To calculate the value of the constant s, you must know the moles of gas and the temperature at which the experiment is carried out, for example, if we have a mole of gas and room temperature (T = 300K), the constant is
n R T = 1 8,314 300
n R T = 2492.2 J
Parker (73.2 kg) is being dragged down the hall with an applied force of 123 N. If the frictional force is 27.4 N, what is the coefficient of friction in the hall?
Answer:
The coefficient of friction in the hall is 0.038
Explanation:
Given;
mass of the Parker, m = 73.2 kg
applied force on the parker, F = 123 N
frictional force, Fs = 27.4 N
the coefficient of friction in the hall = ?
frictional force is given by;
Fs = μN
Where;
μ is the coefficient of friction
N is normal reaction = mg
Fs = μmg
μ = Fs / mg
μ = (27.4) / (73.2 x 9.8)
μ = 0.038
Therefore, the coefficient of friction in the hall is 0.038
How does the plant lichen quicken the weathering process?