3. Each beam of sunlight (a, b, or c above) delivers 1300 joules of energy per second (i.e. 1300 watts) overains
of the upper atmosphere, perpendicular to the direction of the beam (ie. the beam hits a flat surface. Sveta
sunlight spreads out when it hits the Earth, use your answers from 2 above to calculate the amount of enerosta
(c)
actually delivered per 100 m of surface in each of sunlight beams a, b, and c.

Answer:

Hence, f −1 (x) = x/3 + 2/3 is the correct answer.

Step-by-step explanation:

Verify (f ∘ f−1) (x) = x

(f ∘ f−1) (x) = f [f −1 (x)]

= f (x/3 + 2/3)

⟹ 3(x/3 + 2/3) – 2

⟹ x + 2 – 2

= x

Hence, f −1 (x) = x/3 + 2/3 is the correct answer.

Step-by-step explanation:

m(gradient) =y2-y1/x2-x1

=8-(-1) /4-5

=8+1/-1

=9/-1

=-9

y-y1=m(x-x1)

y-(-1)=-9(x-5)

y+1=-9x+45

y=9x+45-1

y=9x+44(rule)

Inverse>y+44=9x

y+44/9=9x/9

x=y+44/9

Therefore inverse is y=x+44/9

Answer:

21

Step-by-step explanation:

Answer:

19

Step-by-step explanation:

Answer:

Option A: 0

Step-by-step explanation:

Given the multiplication of fractions, [tex]\huge\mathsf{\frac{1}{9} \:\times\frac{24}{25}}[/tex]:

Simply multiply the numerators (together), as well as the denominators.

In other words:

[tex]\huge\mathsf{\frac{1}{9} \:\times\frac{24}{25}\:=\frac{1\:\times\:24}{9\:\times\:25}\:=\:\frac{24}{225}}[/tex]

Since 24 and 225 do not have common multiples, then we cannot simplify the fraction into its lowest terms.

Next, in order to find out which is the closest value to the product, [tex]\huge\mathsf{\frac{24}{225}}[/tex], divide the numerator by the denominator, which gives you the following quotient:

[tex]\huge\mathsf{\frac{24}{225}\:=\:24\:\div\:225\:=\:0.1067}[/tex] or 0.11.

We must compare this quotient with the other options:

Option A) 0: This is a possible answer, since rounding 0.11 to the nearest ones (whole number) is 0.

Option B) 0.5:  Unlikely a valid answer, since the digit on the hundreths place is 0.11, and rounding it up to the nearest tenths will become 0.1.

Option C) 1: Definitely not a valid answer, according to the explanations provided in Options A and B.

For Option D) [tex]\huge\mathsf{\frac{21}{20}}[/tex] , we need to find its equivalent decimal form by dividing its numerator by the denominator:  [tex]\huge\mathsf{\frac{21}{20}\:=\:21\:\div\:20\:=\:1.05}[/tex]. Hence, it is also not a valid answer, according to the explanations provided in Options A and B.

Therefore, the closest value to  [tex]\huge\mathsf{\frac{24}{225}\:=\:0.11}[/tex] is Option A) 0.

Answer:

46 boxes of nails

Step-by-step explanation:

She has $187 to spend, the maximum.

187/4 = 46.75

Since she cannot buy 0.75 of a box of nails, she can only buy 46. So she is left with an extra $3 and buys 46 boxes of nails.

Hope this helps, and please mark me the brainliest! :D

Answer:

number 2 is c, number 3 is c

Answer:

There would be 10 more Girls.

Answer:

6,543

Step-by-step explanation:

This is my guess ONLY.

Answer:

920 pages

Step-by-step explanation:

Divide 13,789 by 15, you should get 919.27 so just round up so you can hold all the cards.  

Answer:

the answer is positive.

Step-by-step explanation:

12(-3)(-2)

the 2 negatives cancel out, so you get a positive 6

12(6)

72

positive 72

hope this helped!

mark me brainliest :D

Answer:

go to https://www.rcboe.org/cms/lib010/GA01903614/Centricity/Domain/1030/Ch.%203.3.pdf

Step-by-step explanation:

i think that will help

Step-by-step explanation:

16x²y⁵16x²y⁵ is the answer

f(x)=(x+a)/b

or bf(x)=x+a

let f(x)=y

by=x+a

flip x and y

bx=y+a

or y=bx-a

or f^{-1}(x)=bx-a

also g(x) is inverse of f(x)

bx-a=cx-d

so b=c,a=d

again let g(x)=y

y=cx-d

flip x and y

x=cy-d

cy=x+d

y=(x+d)/c

or g^{-1}(x)=(x+d)/c

also f(x) is inverse of g(x)

so (x+a)/b=(x+d)/c

so a=d,b=c

so in either case a=d,b=c

take b=c=1

a=d=2

f(x)=(x+2)/1=x+2

g(x)=1x-2=x-2

so f(x) and g(x) are two parallel lines f(x) with y- intercept=1 and slope 0

g(x) with y-intercept -2 and slope 0

if we take b=c=2,a=d=3

f(x)=(x+3)/2=x/2+3/2

g(x)=2x-3

here f(x) is of slope 1/2 and y-intercept 3/2

g(x) is of slope 2 and y intercept -3

part 3.

f(f(x))=g((x+a)/b)=c[(x+a)/b]-d=(c/b)(x+a)-d

An inverse function or an anti function exists described as a function, which can change into another function. In other words, if any function “f” carries x to y then, the inverse of “f” will carry y to x.

Part 1: f(x) = (x+2) / 3 and g(x) = 3y-2.

Part 2: g(x) = 3x - 2, the inverse.

Part 3: g(f(x)) = x showing that f(x) and g(x) are mutual inverses.

An inverse function in mathematics exists function which "reverses" the another function.

TASK 1

Part 1

Let y = f(x) = (x + a) / b

x = g(y) = by-a = cy-d,

so c = b and d = a.

Let d = a = 2 and c = b = 3

f(x) = (x+2) / 3 and g(x) = 3y-2.

Part 2

y = f(x) = (x+2) / 3

3y = x+2  

x = 3y-2 = g(y)

so g(x) = 3x - 2, the inverse.

Part 3

g(f(x)) = 3

f(x)-2 = 3(x+2)/3-2 = x+2-2 = x,

so g(f(x)) = x showing that f(x) and g(x) exists mutual inverses.

x       -2  -1        0    1     2

f(x)    0    1/3   2/3   1    4/3

g(x)  -8   -5      -2    1      4

Part 4

The graph is given below.

TASK 2

Part 1

(a) Let a=1, b=2, c=3, d=6: [tex]$\sqrt{x}[/tex]+2+3=6 ; [tex]\sqrt{x}[/tex]-6=-5

(b) Let a=-1, b=2, c=3, d=4

(a) Multiply both sides by

[tex]$\sqrt{x}+6: x-36=-5(\sqrt{x}+6)=-5 \sqrt{x}-30[/tex]

[tex]$ x-36+30=-5 \sqrt{x }[/tex]

[tex]$ x-6=-5 \sqrt{x}$[/tex]

Square both sides:

[tex]$x^{2} -12 x+36=25 x ; x^{2} -37 x+36=0=(x-36)(x-1)$[/tex].

Part 2

(a) So x=36 or 1 (apparently).

Substitute x=36 in the original equation: 6+2+3=6, 11=6 is not true.

So x=36 is an extraneous solution.

substitute x=1: 1+2+3=6 is true, so x=1 exists the actual solution.

(b) [tex]$-\sqrt{x}+2+3=4 ;-\sqrt{x}=-1$[/tex]; multiply both sides by -1: [tex]$\sqrt{x}=1$[/tex]; square both sides: x=1.

Substitute x=1 in the original equation: -1+2+3=4 is true.

So x = 1 is the solution.

Part 3

(a) the act of squaring both sides resulted in creating an extraneous solution [tex]$\left((-5)^{2} =25=5^{2} \right)$[/tex].  

(b) the solution was simpler and there was no ambiguity.

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Answer:

x = 10

Step-by-step explanation:

Perimeter of a triangle = the sum of the three sided of the triangle.

In an isosceles triangle, there are two equal sides and  a base.

Perimeter = ( 3x - 6) + (3x - 6) + x

            58 = 7x - 12

            58 + 12 = 7x

                   70  = 7x

                    [tex]\frac{70}{7} = \frac{7x}{7}[/tex]

                    10 = x

Answer:

Yamete Kodasai

Step-by-step explanation:

Thankyou sa pnts

Answer:

Step-by-step explanation:

One

The exterior angles of a triangle add up to 360. You know two of them. Therefore you can find w.

125 + 90 + w = 360    Combine like terms on the left

215 + w = 360             Subtract 215 from both sides

w = 360 - 215              Combine

w = 145

Two.

The polygon has 4 exterior angles. They too should add up to 360.

88 + x + 108 + 115 = 360     Combine the left had side

x + 311 = 360                       Subtract 311 from both sides

x = 360 - 311                        Combine

x = 49

What have you learned? You should notice that all polygons have exterior angles that add up to 360

Answer:

-44

Step-by-step explanation:

Answer: -44

Step-by-step explanation: same as 36 + 8 and make the answer negative.

Answer:

the answer is b ok understand

Answer:

Option 1:  y = (x - 2)² + 2

Step-by-step explanation:

Given the vertex, (2, 2), of an upward-facing parabola, and using the y-intercept of the graph, (0, 6):

The vertex form of the quadratic equations is:

y = a(x - h)² + k

where:

(h, k) is the vertex.

The sign of a  determines the direction of the graph's opening. The value of a also determines the vertical stretch or shrink of the graph.

Substitute the values of the vertex (2, 2) and the y-intercept, (0, 6) into the  vertex form to solve for the value of the coefficient, a:

y = a(x - h)² + k

6 = a(0 - 2)² + 2

6 = a(-2)² + 2

6 = 4a + 2

Subtract 2 from both sides

6 - 2 = 4a + 2 - 2

4 = 4a

Divide both sides by 4 to solve for a :

[tex]\displaytext\mathsf{\frac{4}{4} \:=\frac{4a}{4}}[/tex]

a = 1

Therefore, given the vertex, (2, 2) and a = 1, the quadratic equation in vertex form is: y = (x - 2)² + 2, thereby matching Option 1.

Answer:

43 1/2

Step-by-step explanation:

answer will be:

original height plus 3 times 8 7/12 inches

3 times 8 7/12 can be done by converting the mixed number to an improper fraction:

[tex]\frac{3}{1}[/tex] · [tex]\frac{103}{12}[/tex] = [tex]\frac{103}{4}[/tex] = 25 3/4

25 3/4 added to 17 3/4 equals 42 6/4 which is 42 + 1 1/2 = 43 1/2

Answer:

ok so you see the equation at the top... you are going to "plug in" the number in the "in" row to get the "out number

Step-by-step explanation:

example

in: 4

-2(-4)+1

8+1

9

so for the out row under -4 you would put 9

-2(-3)+1

6+1

7

so for the out row under 3 you would put 7

Answer:

...

Step-by-step explanation:

Answer:

Julio: 65 soles

Agosto: 85 soles

Step-by-step explanation:

julio: x

agosto: x + 20

x + x + 20 = 150

2x + 20 = 150

2x = 130 x = 65

julio: x = 65

agosto: x + 20 = 85

verificacion: 65 + 85 = 150

julio [65] = 20 menos que agosto [85]

Answer:

Julio: 65 soles

Agosto: 85 soles

The consumption in July was 65 soles and the consumption in August was 85 soles.

An equation contains one or more terms with variables connected by an equal sign.

Example:

2x + 4y = 9 is an equation.

2x = 8 is an equation.

We have,

Let's call the amount of consumption in July "C1" and the amount of consumption in August "C2".

We know that:

C1 + C2 = 150 (the total consumption for both months)

C2 = C1 + 20 (August consumption was 20 soles more than July)

We can substitute the second equation into the first equation to get:

C1 + (C1 + 20) = 150

Simplifying this equation, we get:

2C1 + 20 = 150

Subtracting 20 from both sides, we get:

2C1 = 130

Dividing both sides by 2, we get:

C1 = 65

So the consumption in July was 65 soles.

Using the second equation, we can find the consumption in August:

C2 = C1 + 20 = 65 + 20 = 85

So the consumption in August was 85 soles.

We can check that these values are correct by verifying that they add up to the total consumption of 150 soles:

65 + 85 = 150

Therefore,

The consumption in July was 65 soles and the consumption in August was 85 soles.

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The complete question:

Since the quarantine began, the consumption of electrical energy in my house has increased. It is because we are all at home without going out, using the computer, television and other devices at the same time. The last receipt came to us in July and August, since we could not go out to pay for the quarantine, but the receipt was lost. I can only remember that the total amount was 150 soles and that in July consumption was 20 soles less than in August. How much was our consumption in July and August? Check your answer.

Answer:

Step-by-step explanation:

.<6 and <3

SOLUTION:  

Interior angles that are non adjacent and lie on

opposite. In the figure, angles <5 and <4 are consecutive interior

angles. sides of the transversal are alternate interior

angles.

<4 and <7

SOLUTION:  

In the figure, angles 1 and 3 are corresponding

angles. Use the Corresponding Angles Postulate:

If two parallel lines are cut by a transversal, then

each pair of corresponding angles is congruent

Answer:

Using the slope-intercept form, the slope is 4 4 .

Answer: Using the slope-intercept form, the slope is 4 4 .

Explanation: so your answer is 4 4.

Answer:

11

Step-by-step explanation:

Answer:

16 5c coins

34 10c coins

Step-by-step explanation:

(I prefer to use whole numbers)

5x + 10y = 420

x+y=50

multiply the bottom problem by -5

5x +10y =420

-5x -5y = -250

combine the problems

5y = 170

divide by 5

y = 34

that means x = 16

34 10c coins

16 5c coins

-- Gage Millar, Algebra 1/2 tutor

The number of 5 cent coins are 16 and the number of 10 cent coins are 34.

A system of linear equations consists of two or more equations made up of two or more variables such that all equations in the system are considered simultaneously. The solution to a system of linear equations in two variables is any ordered pair that satisfies each equation independently.

Given that, a trader has a mixture of 5 c and 10 c coins.

Let the the number of 5 c coins be x and the number of 10 c coins be y.

He has 50 coins in all, with a total value of $4.20.

So, x+y=50 ---------(I)

5x+10y=420 ---------(II)

Multiply equation (I) by 5, we get

5x+5y=250 ---------(III)

Subtract equation (III) from (II), that is

5x+10y-(5x+5y)=420-250

⇒ 5y=170

⇒ y=34

Substitute y=34 in equation (I), we get

x=16

Therefore, the number of 5 cent coins are 16 and the number of 10 cent coins are 34.

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Answer:

Answer is C noumber

Step-by-step explanation:

We know that a combination is a collection of the items where the order doesn't matter. It is a way to calculate the total outcomes of an event where order of the outcomes does not matter. It is denoted by C(n,k) or (n,k) or (n/k).

The formula for the number of combinations of n things taken r at a time is given by :-

C(n,k)=(n/k)=\frac{n!}{k!(n-k)!}C(n,k)=(n/k)=

k!(n−k)!

n!

Hence, C is the right option.

Step step :

-HayabusaBrainly

The midpoint of the sides [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex]  are the points that half way between  [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] respectively.

The option that proves [tex]\overline{FB}[/tex] = [tex]\overline{GC}[/tex] is option 3

Reasons:

The given coordinates of the vertices of rectangle ABCD are;

A(0, 0), B(12, 0), C(12, 6), and D(0, 6)

The midpoint of side [tex]\overline{AB}[/tex] = Point F

The midpoint of side [tex]\overline{CD}[/tex] = Point F

The coordinates of point F is given by the midpoint formula, as follows;

[tex]\displaystyle \mathrm{The \ midpoint \ of \ a \ line \ with \ endpoints \ (x_1, \ y_1) \ and \ (x_2, \ y_2) = \mathbf{ \left(\frac{x_1 + x_2}{2}, \ \frac{y_1 + y_2}{2} \right) }}[/tex]

Which gives;

[tex]\displaystyle \mathrm{The \ coordinate \ of \ F \ the \ midpoint \ of \ \overline{AB} = \mathbf{ \left(\frac{0 + 12}{2}, \ \frac{0 + 0}{2} \right)} =(6,\ 0)}[/tex]

[tex]\displaystyle \mathrm{The \ coordinate \ of \ G \ the \ midpoint \ of \ \overline{CD} = \left(\frac{12 + 0}{2}, \ \frac{6 + 6}{2} \right) =(6,\ 6)}[/tex]

[tex]\overline{FB}[/tex] is parallel to the x-axis, therefore;

Similarly, [tex]\overline{GC}[/tex] is parallel to the x-axis, therefore;

Which gives;

The correct option is that proves [tex]\overline{FB}[/tex] = [tex]\overline{GC}[/tex] is option 3.

By the Midpoint Formula, the coordinates of F are (6, 0) and the coordinates of G are (6, 6). Then [tex]\overline{FB}[/tex] = 6, and [tex]\overline{GC}[/tex] = 6. Thus [tex]\overline{FB}[/tex] = [tex]\overline{GC}[/tex]

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