3. The FFA had a fundraiser by selling hot dogs for $1.50 and drinks for $2.00. Their total sales were $400.
a) Write an equation to calculate the total of $400 based on the hot dog and drink sales.
b) Graph the relationship between hot dog sales.

Answers

Answer 1

The equation that represents the total of $400 based on the hot dog and drink sales is $400= $1.50H + $2.00D

Using equation for expressions

The amount sold for each hot dog = $1.50

The total number of hot dogs sold = H × $1.50

The amount sold for each drink = $2.00

The total number of drinks sold = D× $2.00

The total sales made was = $400

Therefore the equation that represents the total of $400 based on the hot dog and drink sales is;

$400= $1.50H + $2.00D

The relationship that exists between the hot dog sales is that the cost is the drinks is higher than the cost of the hot dog.

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Related Questions

Perimeter and Area Geometry homework! {Jim Thompson}

Answers

Part A

The yard is a quadrilateral with the following corner points

(0,0)(0,40)(40,50)(50,0)

I'll label those points A through D in the order presented above.

From A to B is 40 feet since 40-0 = 40. We can subtract the y coordinates because the x coordinates are the same.

In short: side AB is 40 feet long.

The length of side BC is not as simple. We'll need the distance formula.

[tex]B = (x_1,y_1) = (0,40) \text{ and } C = (x_2, y_2) = (40,50)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(0-40)^2 + (40-50)^2}\\\\d = \sqrt{(-40)^2 + (-10)^2}\\\\d = \sqrt{1600 + 100}\\\\d = \sqrt{1700}\\\\d = \sqrt{100*17}\\\\d = \sqrt{100}*\sqrt{17}\\\\d = 10\sqrt{17}\\\\d \approx 41.2311\\\\[/tex]

Segment BC is exactly [tex]10\sqrt{17}[/tex] feet long, which is about 41.2311 feet.

Use the distance formula again to find the distance from point C(40,50) to D(50,0)

[tex]C = (x_1,y_1) = (40,50) \text{ and } D = (x_2, y_2) = (50,0)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(40-50)^2 + (50-0)^2}\\\\d = \sqrt{(-10)^2 + (50)^2}\\\\d = \sqrt{100 + 2500}\\\\d = \sqrt{2600}\\\\d = \sqrt{100*26}\\\\d = \sqrt{100}*\sqrt{26}\\\\d = 10\sqrt{26}\\\\d \approx 50.9902\\\\[/tex]

Lastly, the side AD is exactly 50 feet because 50-0 = 50. We can subtract x coordinates because the y coordinates are the same. Use of the distance formula from A to D should show a result of 50 exactly.

We have these side lengths:

AB = 40

BC = 41.2311 (approximate)

CD = 50.9902 (approximate)

AD = 50

Add up those four sides and we'll get the perimeter of the quadrilateral.

AB+BC+CD+AD = 40+41.2311+50.9902+50 = 182.2213

Answer: About 182.2213 feet

===================================================

Part B

The garden is a rectangle that is 15 feet across horizontally (since subtracting x coordinates gives us 25-10 = 15) and 20 feet vertically (since subtracting y coordinates gives us 35-15 = 20).

This 15 by 20 rectangle has an area of 15*20 = 300 square feet.

The deck is a trapezoid with the parallel bases of 20 feet up top and 35 feet down below. Like before, we subtract x coordinates to find the horizontal distance (since the y coordinates are the same). The height of this trapezoid is 15 feet. Subtract the y coordinates to find the height.

The area of the trapezoid is

A = h*(b1+b2)/2

A = 15*(20+35)/2

A = 412.5

That decimal value is exact.

Add it onto the area of the rectangle

412.5+300 = 712.5

Answer: 712.5 square feet exactly

What is 5log3+log4 as a single logarithm?

Answers

[tex]~~~5 \log 3 + \log4 \\\\=\log 3^5 + \log 4~~~~~~~~~~~~~~~~~~;[\log_b m^n = n \log_b m]\\\\=\log(3^5 \cdot 4)~~~~~~~~~~~~~~~~~~~~~~;[\log_b(mn) = \log_b m + \log_b n]\\\\=\log(972)[/tex]

If a sprinkler rotated 90˚, paused and then rotated another 90˚, how many degrees
did it rotate altogether

Answers

Answer:180 or halfwayStep-by-step explanation:90 is 1/4 and 360 is a full rotation so it rotated halfway all together.

Answer with steps pls

Answers

Answer:

A) 2¹²

Step-by-step explanation:

Given :

3x - y = 12

Equate the equation to y :

3x - y + y = 12 + y12 + y = 3x12 + y - 12 = 3x - 12y = 3x - 12

Substituting in the expression :

[tex]\frac{8^{x} }{2^{y} }[/tex][tex]\frac{2^{3x} }{2^{3x-12} }[/tex][tex]{2^{3x-3x+12}}[/tex]2¹²

Use three different values of n to demonstrate that 2 n + 3 n is equivalent to 5 n .

Answers

Answer:

2n + 3n equals to 5n in the end, so just set n equal to literally any number :)

Step-by-step explanation:

Example:

Let n = 1000

2(1000) + 3(1000) = 5(1000)

5000 = 500

Basically, plug in the number and solve on both sides each time. You will know you've demonstrated it if it's equal on both sides

Answer:

2n + 3n equals to 5n in the end, so just set n equal to literally any number

Step-by-step explanation:

Example:

Let n = 1000

2(1000) + 3(1000) = 5(1000)

5000 = 500

Basically, plug in the number and solve on both sides each time. You will know you've demonstrated it if it's equal on both sides

I need the numbers please con y’all help me

Answers

Answer:

y=2/3x+4

Step-by-step explanation:

4 is y-intercept

2/3 is  the slope (rise/run)

Answer: y = [tex]\frac{2}{3}[/tex]x + 4

Step-by-step explanation:

    This is in slope-intercept form. We are missing the m and the b value. See attached for more information.

[m aka the slope]

   Starting from point (-6, 0), counting up 2 units, then right 3 units to point (-3, 2), gives us a slope of [tex]\frac{2}{3}[/tex] via rise-over-run

[b aka the y-intercept]

   The line intersects the y-axis at positive 4.

-> This value is "4"

PLEASE HELP ILL GUVE EXTRA POINTS PLEASE!!!

Answers

Answer:

[tex]\boxed{\bf 7 \times 10 {}^{ - 3}} [/tex]

Step-by-step explanation:

[tex] \cfrac{6.3}{9} \times \dfrac {10 ^{ - 5} }{10 {}^{ - 3} }[/tex][tex]0.7 \times \cfrac{10 {}^{ - 5} }{10 {}^{ - 3} } [/tex][tex]0.7 \times 10 { }^{ - 5 - 3 \times - 1} [/tex][tex]0.7 \times 10 {}^{ - 5 + 3} [/tex][tex]0.7 \times 10 { }^{ - 2} [/tex]

Write 0.7 *10^-2 into scientific notation:

[tex]7 \times 10 {}^{ - 3} [/tex]

Hope this helps! ^^"

Answer:

[tex]7 \times 10^{-3}[/tex]

Step-by-step explanation:

[tex]\begin{aligned}\dfrac{6.3 \times 10^{-5}}{9 \times 10^{-3}} & =\dfrac{6.3}{9} \times \dfrac{10^{-5}}{10^{-3}}\\\\& = 0.7 \times \dfrac{10^{-5}}{10^{-3}}\end{aligned}[/tex]

[tex]\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:[/tex]

[tex]\begin{aligned}\implies 0.7 \times \dfrac{10^{-5}}{10^{-3}} &=0.7 \times 10^{-5-(-3)}\\& = 0.7 \times 10^{-2}\end{aligned}[/tex]

[tex]\textsf{Rewrite}\:0.7\:\textsf{as}\: 7 \times 10^{-1}:[/tex]

[tex]\implies 0.7 \times 10^{-2}=7 \times 10^{-1} \times 10^{-2}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^b \times a^c=a^{bc}:[/tex]

[tex]\implies 7 \times 10^{-1} \times 10^{-2}=7 \times 10^{-3}[/tex]

The triangles are similar. Find the missing measure.

Answers

Step-by-step explanation:

Triangle MŇO is congruent to Triangle UŤS

NO=4

MN=4

MO=5.6( Which is 140% bigger than 4)

UT=10

TS=10(Therefore this also should be 10)

US=14(Which is 140% bigger than 10)

I think this is the solution but I am not 100% sure

Answer:

x=14

Step-by-step explanation:


Find the next two terms of the sequence 10, -11, -32, .

Answers

Answer:

B

Step-by-step explanation:

Answer: A

Step-by-step explanation:

Because.....

  -11 - 10 = -21

-32 - (-11) = -21

This tells us that the sequence is adding by -21, which is why the next 2 terms will be -53 and - 74 since....

-32 + -21 = -53

-53 + -21 = - 74

Hence, the answer is A.

Solids X and Y are similar. X has volume of 64cm^3, Y has a volume of 729cm^3, the surface area of X is 208cm^2, work out the surface area of Y

Answers

The surface area of solid Y given the ratio of volume to surface area of solid X is 2,369.25cm²

How to solve for surface area?

Volume:

Solid X = 64cm³Solid Y = 729cm³

Surface area:

Solid X = 208cm²Solid Y = x

Ratio of volume to surface area of solid X and Y respectively

64 : 208 = 729 : x

64/208 = 729/x

cross product

64 × x = 208 × 729

64x = 151,632

x = 151,632 / 64

x = 2,369.25cm²

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I'm having difficulties with this haha please help :(

Answers

If the function is h(t) = - 4.9t² + 39.2t + 5. Then the maximum height will be 83.4 meters.

What is differentiation?

The rate of change of a function with respect to the variable is called differentiation. It can be increasing or decreasing.

The function is given as

h(t) = - 4.9t² + 39.2t + 5

Then the differentiation of the function will be

h'(t) = - 9.8t + 39.2

For the maximum height, put h'(t) equals zero. Then we have

              h'(t) = 0

- 9.8t + 39.2 = 0

                  t = 4

Then the maximum height will be

h(t) = - 4.9(4)² + 39.2 x 4 + 5

h(t) = - 4.9 x 16 + 39.2 x 4 + 5

h(t) = - 78.4 + 156.8 + 5

h(t) = 83.4 meters

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What fraction is 3 hours of 30 minutes

Answers

Answer:

7/2                

Step-by-step explanation:

3 hours and 30 minutes = 7/2 in improper fraction

1 hour = 60 minutes

30 minutes = 30 minutes * 1 hour/60 minutes =30/60 = 1/2 hour

3 hours and 30 minutes:

= 3 hours + 1/2 hour

= 3 1/2 hours

= [(2 * 3)+1]/2

= [6+1]/2

= 7/2

Kegan thought that the solution to this equation might be around 10.
Does that make sense to you?
4x − 20 = 2x + 8

Answers

Answer:

x=14

Step-by-step explanation:

collect like terms, like so

Answer:4(x−2)−8=4+2x

Use the distributive property to multiply 4 by x−2.

4x−8−8=4+2x

Subtract 8 from −8 to get −16.

4x−16=4+2x

Subtract 2x from both sides.

4x−16−2x=4

Combine 4x and −2x to get 2x.

2x−16=4

Add 16 to both sides.

2x=4+16

Add 4 and 16 to get 20.

2x=20

Divide both sides by 2.

x=

2

20

Divide 20 by 2 to get 10.

x=10

Step-by-step explanation:

please help me I will give brainliest ​

Answers

Answer:

potential to kinetic energy

1. Jessica drove 345 miles on
Friday. To the nearest 100,
about how many miles did she
drive?

Answers

Answer:

To the nearest 100 miles, Jessica drove about 300 miles since we haven't reached 350 miles.  If we have a number that is greater than 350 miles than we would've rounded it up to 400 but since ours is less than that we round down to the nearest hundred which is 300 miles.

enlarge (2,-2) (4,-2) (2,-4) (4,-4) by scale factor 3.5 with centre of enlargement (4, -6)

Answers

The image of dilating the points by a scale factor 3.5 with centre of enlargement (4, -6) is (-7, 14), (0, 14), (-7,7) and (0, 7)

How to dilate the points?

The coordinates are given as:

(2,-2) (4,-2) (2,-4) (4,-4)

The scale factor is given as:

k = 3.5

The center of enlargement is given as:

(a,b) = (4, -6)

The image of dilation is calculated using:

[tex](x,y) \to (k(x -a), k(y -b))[/tex]

So, we have:

A = (3.5(2 -4), 3.5(-2 +6))

A = (-7, 14)

B = (3.5(4 -4), 3.5(-2 +6))

B = (0, 14)

C = (3.5(2 -4), 3.5(-4 +6))

C = (-7,7)

D = (3.5(4 -4), 3.5(-4 +6))

D = (0, 7)

Hence, the image of dilating the points is (-7, 14), (0, 14), (-7,7) and (0, 7)

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The distribution of the number of words in text messages between employees at a large company is skewed right
with a mean of 8.6 words and a standard deviation of 4.3 words. If a random sample of 39 messages is selected,
what is the probability the sample mean is more than 10 words?
0.0210
0.2454
0.3724
0.9790

Answers

The probability the sample mean is more than 10 words for a random sample of 39 messages is 2.12%

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

The z score is given by:

z = (raw score - mean) / (standard deviation / √sample size)

Given mean of 8.6 words and a standard deviation of 4.3 words. If a random sample of 39 messages, hence, for x > 10:

z = (10 - 8.6) / (4.3 / √39) = 2.03

P(x > 10) = P(z > 2.03) = 1 - P(z < 2.03) = 1 - 0.9788 = 0.0212

The probability the sample mean is more than 10 words for a random sample of 39 messages is 2.12%

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Answer:

A. .0210

Step-by-step explanation:

I'm taking the test... could be wrong though...

can you pleas help this is a math question

Answers

Answer:

10.5 baskets

Step-by-step explanation:

The median is the middle value, but for this one just add the two in the middle and divide by 2.

4+3 = 7

Each ball is 3 baskets

7×3 = 21

21/2 = 10.5

A 5kg sample of plutonium-239 has a half-life of 21,400 years by emitting a 5.157 mev (million or mega electron volts) alpha particles. assume that the rate of decay is constant, how long will it take for the sample to degrade to 4.5kg?

Answers

Using an exponential function, it is found that it will take 3,252 years for the sample to degrade to 4.5kg.

What is the exponential function for the amount of a substance?

It is given by:

[tex]A(t) = Pe^{-kt}[/tex]

In which:

P is the initial amount. k is the decay rate, as a decimal.

The half-life is of 21,400 years, hence, A(21400) = 0.5P, and this is used to find k.

[tex]A(t) = Pe^{-kt}[/tex]

[tex]0.5P = Pe^{-21400k}[/tex]

[tex]e^{-21400k} = 0.5[/tex]

[tex]\ln{e^{-21400k}} = \ln{0.5}[/tex]

[tex]-21400k = \ln{0.5}[/tex]

[tex]k = -\frac{\ln{0.5}}{21400}}[/tex]

k = -0.00003239005

Hence, considering the initial mass is of P = 5 kg, the amount after t years is given by:

[tex]A(t) = 5e^{-0.00003239005t}[/tex]

The amount will be of 4.5 kg at t for which A(t) = 4.5, hence:

[tex]4.5 = 5e^{-0.00003239005t}[/tex]

[tex]e^{-0.00003239005t} = 0.9[/tex]

[tex]\ln{e^{-0.00003239005t}} = \ln{0.9}[/tex]

[tex]-0.00003239005t = \ln{0.9}[/tex]

[tex]t = -\frac{\ln{0.9}}{0.00003239005}[/tex]

t = 3252.

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A group of students want to determine if a person's height is linearly related to the distance they are able to jump.

To determine the relationship between a person's height and the distance they are able to jump, the group of students measured the height, in inches, of each person in their class and then measured the distance, in feet, they were able to jump from a marked starting point.

Each student was given three tries at the jump and their longest jump distance was recorded. The data the students collected is shown below.

Enter the correlation coefficient. Round your answer to the nearest hundredth.

Answers

The correlation coefficient is 0.92

What is Correlation Coefficient ?

A correlation coefficient is a number between -1 and 1 that tells you the strength and direction of a relationship between variables.

In other words, it reflects how similar the measurements of two or more variables are across a dataset.

When one variable changes, the other variables change in the same direction or opposite direction.

Perfect positive correlation :When one variable changes, the other variables change in the same direction.

Perfect negative correlation :When one variable changes, the other variables change in the opposite direction.

[tex]\rm r = \dfrac{\sum (x_{i}-x')(y_{i}-y')}{\sqrt {\sum (x_{i}-x')^{2} \sum (y_{i}-y')^{2}}}[/tex]

After calculation we get

r = 0.92

Therefore it is a Perfect positive correlation

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is 10 times as much as 20 1/10 of 2,000?

Answers

Answer:

IT IS 43./45455/.34 LIKE WHEN U ADD 10 TIMES 10 AND DIVIDED 2,000 FROM 20 U THAT ANSWER

E
Describe the transformation that maps figure RSTU onto figure RSTU
611
6
4
S
U
S2
R
E
R
6-4-2 O
2
4
6
Drag the labels to explain your answer. Labels may be used once more than once, or not at all
Figure RSTU is the image of figure RSTU after a translation
units left and
units down, and a reflection across
the
#1
.: 2
14
+ X-axis
- y-axis

Answers

Answer:

8 then 2 and reflection on y axes

Solve for the exact values of x and y.
x =
y =

Answers

Answer:

Here is the solution...hope it helps:)

The sum of terms of an A.P. is 136, the common difference 4, and the last term 31, find n​

Answers

Step-by-step explanation:

[tex]\huge{\color{black}{\fbox{\color{pink}{\colorbox{pink}{\color{red}{Answer ✨☑️}}}}}}[/tex]

The number of terms are 8. Step-by-step explanation: Given : The sum n terms of an A.P is 136 the common difference is 4 and last term is 31.

Answer:

Sn=2n{2a+(n−1)d}

a+(n−1)d=31⇒a=31−4(n−1)

∴136=2n{2[31−4(n−1)]+(n−1)d}

n[70−8n+4n−4]=272

n(66−4n)=272

4n2−66n+272=0

2n2−33n+136=0

2n(n−8)−17(n−8)=0

(2n−17)(n−8)=0

∴n=8

Does anybody know this? I keep getting the wrong answer. ABC~PRT AC=15 BC=12 and PT=6 find the ares of ABC if the area of PRT=24mm^2

Answers

Answer:

The area of triangle ABC is 60 mm^2

Step-by-step explanation:

x = the area of triangle ABC

15/6 * x/24

x=60

Answer:

  (d)  150 mm²

Step-by-step explanation:

The scale factor between the triangles is the ratio of the lengths of corresponding sides. The area ratio is the square of the scale factor.

__

scale factor

ΔABC is larger than ΔPRT by the factor ...

  AC/PT = 15/6 = 5/2

area

The area of ΔABC is the square of this factor times the area of ΔPRT:

  area ABC = (5/2)²×area PRT

  area ABC = (25/4)×(24 mm²)

  area ABC = 150 mm²

.The figure below includes a semicircle and
trapezoid. Find the area of the figure.

Answers

Answer:

244.93

Step-by-step explanation:

area formula for trapezoid:1/2*(b1+b2)*h

area formula for semi circles: (3.14*r^2)/2

so then we cut the figure to make a semi cirlce and trapazoid

semicircle- 14 is the full diameter, divide by 2 to make 7, 7×3.14×7)/2=76.93

trapezoid: base one is 18. base 2 is 14. 18+14=32 then times that by 10.5 which is 336 and divide that by 2 is 168

add both and you get 244.93

Which side is adjacent to Angle Q?

48
14
50

Answers

Answer: 48

Step-by-step explanation: 50 is the hypotenuse

14 is the opposite side - its opposite of angle Q

a student was asked to multiply a number by 3/2. instead he divided the number by 3/2 and obtained a number smaller by 2/3, the number is:

Answers

Answer:

[tex]\boxed{\bf \sf number : \ \frac{4}{5} }[/tex]

Explanation:

Let the number be n

According to students Condition:

[tex]\rightarrow \sf \dfrac{3}{2} \ x \ n \quad = \quad \dfrac{3n}{2}[/tex]

What He actually Did:

[tex]\rightarrow \sf n \div \dfrac{3}{2} \quad = \quad n \ x \ \dfrac{2}{3} \quad = \quad \dfrac{2n}{3}[/tex]

He got a smaller number by 2/3, so:

[tex]\rightarrow \sf \dfrac{3n}{2} - \dfrac{2n}{3} = \dfrac{2}{3}[/tex]

make the denominator's same

[tex]\rightarrow \sf \dfrac{3(3n)}{6} - \dfrac{2(2n)}{6} = \dfrac{2}{3}[/tex]

multiply the integers

[tex]\rightarrow \sf \dfrac{9n}{6} - \dfrac{4n}{6} = \dfrac{2}{3}[/tex]

Join the fractions

[tex]\rightarrow \sf \dfrac{9n-4n}{6} = \dfrac{2}{3}[/tex]

Subtract integers

[tex]\rightarrow \sf \dfrac{5n}{6} = \dfrac{2}{3}[/tex]

Cross multiply

[tex]\rightarrow \sf n = \dfrac{6 \ * \ 2}{5 \ * \ 3} \quad = \quad \dfrac{4}{5}[/tex]

Lets see

the number be x

The expression is

3x/2-2x/3=2/39x-4x)6=2/35x)6=2/315x=12x=12/15=4/5

What is a simpler form of the expression?
(4k + 5)(3k^2 - 4k - 4)

Answers

Answer:

[tex]12k^3 -k^2-36k-20[/tex]

Step-by-step explanation:

Step 1:  Distribute

[tex](4k + 5)(3k^2 - 4k - 4)[/tex]

[tex](4k * 3k^2)+(4k*-4k)+(4k*-4)+(5*3k^2)+(5*-4k)+(5*-4)[/tex]

[tex]12k^3-16k^2-16k+15k^2-20k-20[/tex]

Step 2:  Combine like terms

[tex]12k^3+(-16k^2+15k^2)+(-16k-20k)-20[/tex]

[tex]12k^3 -k^2-36k-20[/tex]

Answer: [tex]12k^3 -k^2-36k-20[/tex]

Lance paid 6% sales tax on a $30 game. What is the total amount did Lance pay?

Answers

Answer:

The answer is attached.

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