Answer:
1st one,
Due to inertia it tries to move in straight line, but space is curved because of earth
Answer:
Earth's surface curves away as gravity pulls them toward Earth
Explanation:
Your Welcome (; (:
The pharyngeal tonsil is found in the __________________________ .
Answer:
The pharyngeal tonsils are located near the opening of the nasal cavity into the pharynx. When these tonsils become enlarged they may interfere with breathing and are called adenoids.
At what final position would you be if you began at initial position of 4m and drove at 30m/s for 20 seconds?
Answer:
604m
Explanation:
30 * 20=600
600 + 4 = 604m
A 20.0 cm wrench is used to generate a torque at a bolt. A force of 50 N is applied at the end of the wrench at an angle of 60.0 degrees to the wrench. The torque generated at the bolt is A. 4.9 N•m. B. 5.7 N•m. C. 6.0 N•m. D. 7.5 N•m. E. 8.7 N•m.
Answer:
The correct option is E
Explanation:
From the question we are told that
The length of the wrench which is also the radius of the circle made by the wrench is [tex]l =r = 20.0 \ cm = 0.2 \ m[/tex]
The force is [tex]F = 50 \ N[/tex]
The angle is [tex]\theta = 60^o[/tex]
Generally the torque generated by the bolt is mathematically represented as
[tex]\tau = F * sin (\theta ) * r[/tex]
=> [tex]\tau = 50 * sin (60 ) * 0.2[/tex]
=> [tex]\tau = 8.7 \ N \cdot m[/tex]
What is the acceleration of a proton moving with a speed of 6.5 m/s at right angles to a magnetic field of 1.5 T?
Answer:
The acceleration of the proton is 9.353 x 10⁸ m/s²
Explanation:
Given;
speed of the proton, u = 6.5 m/s
magnetic field strength, B = 1.5 T
The force of the proton is given by;
F = ma = qvB(sin90°)
ma = qvB
where;
m is mass of the proton, = 1.67 x 10⁻²⁷ kg
charge of the proton, q = 1.602 x 10⁻¹⁹ C
The acceleration of the proton is given by;
[tex]a = \frac{qvB}{m}\\\\a = \frac{(1.602*10^{-19})(6.5)(1.5)}{1.67*10^{-27}}\\\\a = 9.353*10^8 \ m/s^2[/tex]
Therefore, the acceleration of the proton is 9.353 x 10⁸ m/s²
Calculate the wavelengths of a 1530 kHz AM radio signal, a 105.1 MHz FM radio signal, and a 1.90 GHz cell phone signal.
Answer:
196.07 m, 2.85 m and 0.15 m
Explanation:
Frequency of AM radio signal, f₁ = 1530 kHz
Its wavelength can be given by :
[tex]\lambda_1=\dfrac{c}{f_1}\\\\=\dfrac{3\times 10^8}{1530\times 10^3}\\\\=196.07\ m[/tex]
Frequency of FM radio signal, f₂ = 105.1 MHz
Its wavelength can be given by :
[tex]\lambda_2=\dfrac{c}{f_2}\\\\=\dfrac{3\times 10^8}{105.1\times 10^6}\\\\=2.85\ m[/tex]
Frequency of cell phone signal, f₃ = 1.9 GHz
Its wavelength can be given by :
[tex]\lambda_2=\dfrac{c}{f_2}\\\\=\dfrac{3\times 10^8}{1.9\times 10^9}\\\\=0.15\ m[/tex]
Hence, the required wavelengths are 196.07 m, 2.85 m and 0.15 m respectively.
When the rate of the forward reaction equals the rate of the backward reaction, the system is said to be in
Answer:
equilibrium
Explanation:
bcoz forward reaction equals backward reaction
Data supporting the theory of a round earth was collected as early as _____.
1570 AD by Galileo
1500 AD by Copernicus
250 BC by Aristarchus
1640 AD by Kepler
250 BC by Aristarchus is the answer ot the question
Data supporting the theory of a round earth was collected as early as _____.
1570 AD by Galileo
1500 AD by Copernicus
250 BC by Aristarchus
1640 AD by Kepler
A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 G to 1.60 M in 0.99 s. What is the resulting induced current if the loop has a resistance of 1.20 Ω?
Complete Question
A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 1.60 T in 0.99 s. What is the resulting induced current if the loop has a resistance of [tex]1.20 \ \Omega[/tex]
Answer:
The current is [tex]I = 0.0007 41 \ A[/tex]
Explanation:
From the question we are told that
The area is [tex]A = 8.00 \ cm^2 = 8.0 *10^{-4} \ m^2[/tex]
The initial magnetic field at [tex]t_o = 0 \ seconds[/tex] is [tex]B_i = 0.500 \ T[/tex]
The magnetic field at [tex]t_1 = 0.99 \ seconds[/tex] is [tex]B_f = 1.60 \ T[/tex]
The resistance is [tex]R = 1.20 \ \Omega[/tex]
Generally the induced emf is mathematically represented as
[tex]\epsilon = A * \frac{B_f - B_i }{ t_f - t_o }[/tex]
=> [tex]\epsilon = 8.0 *10^{-4} * \frac{1.60 - 0.500 }{ 0.99- 0 }[/tex]
=> [tex]\epsilon = 0.000889 \ V[/tex]
Generally the current induced is mathematically represented as
[tex]I = \frac{\epsilon}{R }[/tex]
=> [tex]I = \frac{0.000889}{ 1.20 }[/tex]
=> [tex]I = 0.0007 41 \ A[/tex]
You have learned how to create an effective study space in this learning path.
What has been the biggest change you have made in your study space?
Give at least one specific example.
How has the information you have learned (and the possible changes you have made) already been a benefit to you?
Your answer should be at least two complete sentences.
Answer:
Getting comfy but not too comfy
Explaination : Some people work the majority of their lives in sweat pants and a grungy t-shirt; others dress in full business attire before sitting down at the desk in their study. Because I want to enjoy the place where I study, I say be comfortable—but not too comfortable. I change out of my pajamas before I crack open my books to give my mind another signal that this isn’t lounge time, but study time.
All of the following are categories used to classify problems except problems of
A. arrangement
B. inducing structure
C. transformation
D. schematic completion
Answer:D. schematic completion
Explanation:The rest are actual categoroes
Answer:
schematic completion
Explanation:
got it right on edge
A metal wire of resistance R is cut into six equal pieces that are then placed together side by side to form a new cable with a length equal to one-sixth the original length. What is the resistance of this new cable?
Answer:
d ko alam wag puro asa sa app
To exercise, a man attaches a 4.0 kg weight to the heel of his foot. When his leg is stretched out before him, what is the torque exerted by the weight about his knee, 40 cm away from the weight? Use g = 10 m/s2. A. 160 Nâm B. 16 Nâm C. 1600 Nâm D. 1.6 Nâm
Answer:
B. τ = 16 Nm
Explanation:
In order to find the torque exerted by the weight attached to the heel of man's foot, when his leg is stretched out. We use following formula:
τ = Fd
here,
τ = Torque = ?
F = Force exerted by the weight = Weight = mg
F = mg = (4 kg)(10 m/s²) = 40 N
d = distance from knee to weight = 40 cm = 0.4 m
Therefore,
τ = (40 N)(0.4 m)
B. τ = 16 Nm
The torque exerted by the weight about his knee, 40 cm away from the weight is: D. 1.6 Nm
Given the following data:
Mass = 4.0 kgDistance = 40 cm to m = 0.04 metersAcceleration due to gravity (g) = 10 [tex]m/s^2[/tex].To determine the torque exerted by the weight about his knee, 40 cm away from the weight:
First of all, we would calculate the force being exerted by the weight on his heel.
[tex]Force = mg\\\\Force = 4 \times 10[/tex]
Force = 40 Newton
Mathematically, torque is given by the formula:
[tex]Torque = force \times distance[/tex]
Substituting the given parameters into the formula, we have;
[tex]Torque = 40 \times 0.04[/tex]
Torque = 1.6 Nm
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Rain drops are formed when water vapor _____.
condenses on grass
evaporates
condenses on dust
freezes
Answer:
Condenses on dust
Explanation:
Pls brainiest
Answer:
condenses on dust
Explanation:
7.
As the distance from the Sun increases the time to orbit the Sun
a. Increases
b. Decreases
c. Stays the same
As the distance from the Sun increases the time to orbit the Sun increases. (a)
Examples:
-- Nearest planet to the sun: Mercury. Time to orbit the sun: 88 days
-- 3rd planet from the sun: Earth. Time to orbit the sun: 1 year
-- 5th planet from the sun: Jupiter. Time to orbit the sun: 12 years
-- 9th closest object to the sun: Pluto. Time to orbit the sun: 248 years
Another pair of examples:
-- Object in a near Earth orbit: International Space Station
Time to orbit the Earth: 90 minutes
-- Object in a far Earth orbit: the Moon
Time to orbit the Earth: 27.3 days
The reason for all of this is: Two things about orbits.
1). The larger the orbit is, the farther the object has to travel around it.
2). The farther out the object is, the slower it travels in its orbit.
This is simply the way gravity works.
Rebecca heated 50mL of water from 0 degrees Celsius to 60 degrees Celsius. How much energy did she use to heat the water? Remember: cal=m*deltaT
(WRITE THE WORK!/Give explanation.)
Answer:
Q = 12540 J
Explanation:
It is given that,
Mass of water, m = 50 mL = 50 g
It is heated from 0 degrees Celsius to 60 degrees Celsius.
We need to find the energy required to heat the water. The formula use to find it as follows :
[tex]Q=mc\Delta T[/tex]
Where c is the specific heat of water, c = 4.18 J/g°C
Put all the values,
[tex]Q=50\times 4.18\times (60-0)\\Q=12540\ J[/tex]
So, 12540 J of energy is used to heat the water.
What changes occurred when you heated sugar ?
Please help
Test
Three polarizing filters are shown in the figure below. The alignment of each filterâs transmission axis is shown, as measured from the vertical. Show calculations to justify all of your answers.Angles: 0, 70, and 90a. Unpolarized light, with an intensity I0 passes through the three filters. What is the intensity of the transmitted light?b. Vertically polarized light, with an intensity I0 passes through the three filters. What is the intensity of the transmitted light?c. Is it possible to remove a polarizer from this collection of filters so that unpolarized light transmitted from the left is not transmitted at all? If so, which filter?
Answer: B.
Explanation:
Hope help :p
A) The intensity of the transmitted light will depend on the angle between the polarization direction of the incident light and the transmission axis of each filter.
B) The intensity of the transmitted light will be equal to the initial intensity, I0.
C) The filter that blocks light vibrating perpendicular to its transmission axis is typically called a "crossed" polarizer.
Polarizing filters are optical devices that allow light waves vibrating in a specific direction to pass through while blocking or attenuating light waves vibrating in other directions. The alignment of a polarizing filter's transmission axis refers to the direction in which it allows light to pass through with maximum intensity.
a. Unpolarized light passing through a polarizing filter will have its intensity reduced by a factor called the transmittance, which depends on the angle between the polarization direction of the incident light and the transmission axis of the filter. If the incident light is unpolarized, it contains an equal distribution of light waves vibrating in all possible directions.
As a result, when unpolarized light passes through a polarizing filter, only the component of light vibrating parallel to the transmission axis will be transmitted, while the perpendicular components will be blocked. Therefore, the intensity of the transmitted light will depend on the angle between the polarization direction of the incident light and the transmission axis of each filter.
b. Vertically polarized light has its electric field oscillating only in the vertical direction. When vertically polarized light passes through a polarizing filter whose transmission axis is aligned with the vertical direction, it will pass through with maximum intensity. Therefore, the intensity of the transmitted light will be equal to the initial intensity, I0.
c. In general, if you have a collection of polarizing filters with different transmission axes, it is possible to remove a polarizer so that unpolarized light transmitted from the left is not transmitted at all. This can be achieved by removing the filter whose transmission axis is perpendicular to the direction of polarization of the incident light. The filter that blocks light vibrating perpendicular to its transmission axis is typically called a "crossed" polarizer.
Specific calculations and analysis of the figure you provided would require more detailed information, such as the transmittance characteristics of each filter at different angles. Without the figure or additional data, it is not possible to provide precise calculations or identify the exact filter that should be removed to block unpolarized light.
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A volume of air increases 0.227 m^3 at a net pressure of 2.07 x 10^7 Pa. How much work is done on the air?
Answer:
The work done on the air is 4.699 x 10⁶ Joules
Explanation:
Given;
increase in air volume, ΔV = 0.227 m³
net pressure of the air, P = 2.07 x 10⁷ Pa
The work done on the air is given by;
W = PΔV
Where;
W is the work done on the air
P is the net pressure
ΔV is the increase in air volume
Substitute the given values and solve for work done;
W = (2.07 x 10⁷ Pa) (0.227 m³)
W = 4.699 x 10⁶ Joules
Therefore, the work done on the air is 4.699 x 10⁶ Joules
if it took 3.7 seconds for the sound to reach john how far away was the firework shell when it exploded in kilometers assume that the speed of sound in air is 1,236 km/h
Answer:
1.2703 km
Explanation:
The speed can be calculated using the formula;
Speed (m/s) = distance (m) ÷ time (s)
Based on the information in this question, it took 3.7 seconds for a sound with speed of 1236 km/h to reach John. The distance will be:
Distance = speed × time
However, we need to convert the time in seconds (s) to hour (hr).
1 second = 0.000277778 hour
3.7 seconds = 0.00102778 hours.
Hence,
distance = 1236 × 0.00102778
Distance = 1.2703 km
A spring of spring constant 25 N/m is hung vertically and a 0.300 kg mass is attached to one end, causing a displacement of the end of the spring of _____ m.
Answer:k=1175
Explanation:thank you for asking
Jeff was riding in a car with a textbook sitting on the seat beside him. When would the textbook demonstrate the GREATEST effect of inertia?
А
When the car makes a sudden stop,
B
When the car changes into another lane.
С
When the car slows down gradually.
D
When the car runs out of gas and rolls to a stop
A tennis ball is thrown against a vertical concrete wall that is fixed to the ground. The ball bounces off the wall. How does the force exerted by the ball on the wall compare with the force exerted by the wall on the ball
А The force exerted by the ball is greater
B The forces exerted by the ball and the wall have the same magnitude.
C. The force exerted by the ball is smaller
D The relative magnitudes of the forces cannot be determined without knowing how long the ball and the wall are in contact
Answer:
The forces exerted by the ball and the wall have the same magnitude
Explanation:
Newton's Third Law Dictates Such
When a tennis ball is thrown against a vertical concrete wall that is fixed to the ground. The ball bounces off the wall because the forces exerted by the ball and the wall have the same magnitude but are opposite in direction, therefore the correct answer is option B.
What is Newton's third law of motion?Newton's third law of motion explains that forces exist in pairs. It states that for every action force there exists equal and opposite reaction forces, these pairs of forces are equal in magnitude but opposite in direction.
As given in the problem when a tennis ball is launched up against a fixed-to-the-ground vertical concrete wall.
Because the forces being applied by the ball and the wall are equal in magnitude but directed differently, the ball bounces off the wall.
Thus, the correct answer is option B.
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Find the magnitude of the buoyant force on the block. The acceleration of gravity is 9.8 m/s 2 . Answer in units of N.
What's centrifugal force
GOOGLE: Centripetal force is defined as, "the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation," while centrifugal force is defined as "the apparent force that is felt by an object moving in a curved path that acts outwardly away from the center of
I don't actually know what that is but I hope this helps! Good luck!
If 3 cups are sitting outside on a hot summer day, which cup will gain the most heat? Cup A starts a little above freezing, Cup B is initially room temperature, and Cup C is just below boiling.
A-Hot
B- Room
C- Cold
D- None, the heat doesn't change
Answer:
c- cold
Explanation:
Emmett is lifting a box vertically. Which forces are necessary for calculating the total force?
Fp, Ff, and Fg
Fp and FN
Fp, Fg, and Ff
Fp and Fg
Answer:
Answer is D: D.Fp and Fg
Explanation:
I did the quiz some time ago and rember it hope it helps.
Answer:
i just finish its d
Explanation:
How are all paths that have a displacement of zero similar?
Answer:
Any situation that has a path that stops at the same position that it started from has a displacement of zero
Explanation:
hope it helps
Which of the following substances is a compound?
O A. hydrogen gas
B. nitrogen gas
O c. table sugar
O D. oxygen gas
Table sugar is a compound, it consists of carbon, hydrogen, and oxygen.
Hence, C is the correct answer.
What is the chemical state of matter?The chemical state of matter consists :
ElementCompound andMixturesElement-The substance which contains only one atom and cannot be broken down. Example-Hydrogen.Compound-It is defined as a substance formed when two or more chemical elements are chemically bonded together. The substance can be pure or impure.Mixture-It contains two or more elements or compounds, but they are not chemically combined. Mixtures are of two types :Homogeneous mixture and,Heterogeneous mixtureHence, table sugar is a compound because it is formed by more than 2 chemical elements, and they are chemically bonded together.
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HELP!!
You are traveling at a speed of 70 miles per hour. How long did it take you to travel 2400 miles?
Answer:
So do 2400 divided by 70. I got 34.285714 and the numbers behind the decimal are repeating. If you round it you get 34.3
A 4 kilogram box is at rest on a frictionless floor. A net force of 12 newtons acts on it. What is the acceleration of the box?
Answer:
3 m/s^2Explanation:
Step one:
given
Mass m= 4kg
Force F= 12N
Required
Acceleration the relation between force, acceleration, and mass is Newton's first equation of motion, which says a body will continue to be at rest or uniform motion unless acted upon by an external force
F=ma
a=F/m
a=12/4
a=3 m/s^2