The concept of an inverse squared relationship explains the behavior of intensity of light and distance of the light source. As the distance of the light source increases, the intensity of light decreases.
What is concept of an inverse squared relationship?The law of inverse square law says that intensity equals the inverse of the square of the distance from the source.
Mathematically, the formula for the inverse square law is given as;
I ∝ 1/r²
where;
I is the intensity of lightr is the distance from the light sourceWhat is intensity of light?The intensity of light can be defined as the measure of the amount of power emitted by a given surface or reflected by the surface.
Thus, the inverse square law is all about the inverse relation between the intensity of light or power output of a given surface to the distance of the light source.
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A quality assurance engineer at a frying pan company is asked to qualify a new line of nonstick-coated frying pans. The coating needs to be 1.00 mm thick. One method to test the thickness is for the engineer to pick a percentage of the pans manufactured, strip off the coating, and measure the thickness using a micrometer. This method is a destructive testing method. Instead, the engineer decides that every frying pan will be tested using a nondestructive method. An ultrasonic transducer is used that produces sound waves with a frequency of f=25.0 kHz. The sound waves are sent through the coating and are reflected by the interface between the coating and the metal pan, and the time is recorded. The wavelength of the ultrasonic waves in the coating is 0.0760-m. What should be the time recorded if the coating is the correct thickness (1.00 mm)?
Answer:
Δt ≈ 5.3 x 10⁻⁷ s or Δt ≈ 0.5 μs.
Explanation:
Sound waves propagate at a typical speed according to the physical media.
Using the wave equation of speed:
V = λ x f
V = 0.0760 x 25 x 10³
V = 1900 m/s
Then we must use this value to find the time recorded:
V = ΔS / Δt
1900 = 10⁻³ / Δt
Δt = 10⁻³ / 1900
Δt ≈ 5.2632 x 10⁻⁷ s
Δt ≈ 5.3 x 10⁻⁷ s or Δt ≈ 0.5 μs
The wavelength of the Ultrasonic wave in the coating is 0.0760 m, then the time recorded is 0.5 μs if the coating is of correct thickness, that is of 1 mm
What is frequency?Physics refers to frequency as the quantity of waves passing a fixed location in a unit of time. Additionally, it is the quantity of vibrations or cycles that a body in periodic motion experiences in a certain period of time. One cycle or vibration is defined as the movement of a body in periodic motion across a sequence of occasions or locations before returning to its initial state. Under angular velocity, a straightforward harmonic motion is also observed.
According to the question,
Use wave equation of speed :
V = λ (wavelength) x f (frequency)
V = 0.0760 x 25 x 10³
V = 1900 m/s
The time recorded will be :
V = ΔS / Δt
1900 = 10⁻³ / Δt
Δt = 10⁻³ / 1900
Δt = 5.2632 x 10⁻⁷ s
Δt = 5.3 x 10⁻⁷ s or,
Δt = 0.5 μs
Hence, the time recorded will be 0.5 μs if the coating is of correct thickness that is 1 mm.
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a semi permeable membrane is stretched across a chamber filled with water . the membrane is only permeable to water. 60 mg of salt is added to the left side of the chamber what will happen
If 60 mg of salt is added to the left side of the chamber then water will move toward the left side.
Semi permeable membrane :A membrane that permits some molecules to pass through it but not others is said to be semi-permeable. A semipermeable membrane is the cell membrane. Because of the hydrophobic nature of the tails, the phospholipid bilayer prevents most molecules from diffusing across the membrane, making the cell membrane semi-permeable. The most effective membrane is made of cellophane.
What passes through a membrane that is semipermeable?Osmosis is the naturally occurring transfer of solvent molecules from a lower concentration solution to a higher concentration solution across a semi-permeable membrane. Kidney tissue is an example of a semipermeable membrane. Some molecules can pass through kidneys without being blocked by others, such as waste products from people. For water filtration or desalination, semipermeable membranes made of synthetic materials are employed.
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A ride at Six Flags has a frequency of 2.5 Hz. What is the ride's period?
Given:
The frequency of the ride, f=2.5 Hz
To find:
The period of the ride.
Explanation:
The period of a wave is equal to the inverse of the frequency of the wave. And the frequency of the wave is equal to its period.
Thus the period of the ride is given by,
[tex]T=\frac{1}{f}[/tex]On substituting the known values,
[tex]\begin{gathered} T=\frac{1}{2.5} \\ =0.4\text{ s} \end{gathered}[/tex]Final answer:
The period of the ride is 0.4 s
A runaway train car that has a mass of 13000 kg travels at a speed of 5.2 m/s down a track.
A Compute the time required, in seconds, for a force of 1700 N to bring the car to rest.
The time necessary to bring the automobile to a stop is 54 seconds, and the correct answer is 54 seconds.
t = -81000/-1500
t = 54 seconds
t 54 seconds
Which of these is Newton's Second Law of Motion?F = ma, or force is equal to mass times acceleration, is the second of Newton's three laws of motion. Learn how to compute acceleration using this formula.
According to the first law, an item won't alter its motion unless a force acts on it. According to the second law, an object's force is equal to its mass times its acceleration. The third law asserts that every action has a corresponding and opposing response.
Newton's third rule of motion explains that when two bodies contact, they exert force on one another.
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PLEASE HELP! 20 points!!
The infamous chicken is dashing toward home plate with a speed of 5.8m/s when he decided to hit the dirt. The chicken slides for 1.1s. Just reaching hte plate as he stops(safe, of course). (A)What is the magnitude and direction of the chickens acceleration? (B) How far did the chicken slide?
please show all work!
The chicken needs to have an acceleration such that after time t his Velocity is 0, shown in the equation:
0 = V + at
-5.8 = 1.1 x a
a = -5.8 / 1.1
a = -5.2727 m/s/s.
The distance traveled in a time t with velocity V and acceleration is given by:
D = Vot + 1/2 at2
D = 5.8 x 1.1 - 1/2 x 5.2727 x 1.12
D = 3.19m.
Acceleration is the name we give to the process of changing velocity. Velocity is both speed and direction, so there are only two ways to accelerate. Either change speed, change direction, or change both. There are three main types of accelerated motion uniform acceleration, unequal acceleration, and average acceleration.
The term uniform acceleration refers to the motion of a body moving in a straight line with an increasing velocity at equal time intervals. Velocity is the rate of change of displacement. Acceleration is the rate of change of velocity. Velocity is a vector quantity because it consists of both magnitude and direction. Since acceleration is the rate of change of velocity it is also a vector quantity. Acceleration occurs whenever an object increases or decreases its speed or changes direction.
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In a laboratory experiment, a student was exploring the stretch of a spring based on the pull of the force. The student used weights of 1 N, 2 N, 3 N, 4 N, and 5 N. The points were plotted, and the relationship was analyzed. The graph is shown.
A graph titled stretch versus force is shown with stretch on the vertical axis and force on the horizontal axis. The graph is a straight diagonal line from bottom left to top right going through points 0 comma 0, 1 comma 1.0, 2 comma 3.6, 3 comma 5.5, 4 comma 7.2, and 5 comma 9.1.
Which of the following values would be considered an extrapolation?
Force = 1 N, stretch = 1.9 cm
Force = 3 N, stretch = 5.5 cm
Force = 4.6 N, stretch = 8.3 cm
Force = 5.4 N, stretch = 9.6 cm
An extrapolation from the graph given the points on the line of best fit is Force = 5.4 N, stretch = 9.6 cm.
What is Hooke's law?The Hooke's law states that as long as the elastic limit is not exceeded, the extension of the object is proportional to the magnitude of the force that have been applied. This would help us answer the question
Now we can see that in the plot of the Hooke's law, the force have been plotted on the horizontal axis and the extension or the stretch have been plotted on the vertical axis. The areas that runs through the line of best fit have been shown ad from this line of best fit we could be able to obtain an extrapolation.
The point on the graph that can be regarded as an extrapolation is the point that have been marked Force = 5.4 N, stretch = 9.6 cm.
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Answer:
the answer is D
Explanation:
force+5.4N, stretch=9.6
A graph of a relationship is shown.
A graph titled force versus distance is shown with force on the vertical axis and distance on the horizontal axis. The graph is a downward curve from top left to bottom right but sits very close the axes.
Which of the following best describes the relationship between the two variables?
Distance is directly related to force.
Distance is inversely related to force.
Force is directly related to the square of distance.
Force is inversely related the square of distance.
From the direction of the line of best fit, we can say that; distance is inversely related to force.
What is a graph?The term graph has to do with the relationship between two variables that have been shown by the use of the cartesian axes. We know that the cartesian axis are vertical and horizontal. The nature of the line of best fit gives us an idea of the relationship between the variables. This also helps us to understand the slope of the graph
In this case, we can see that a graph titled force versus distance is shown with force on the vertical axis and distance on the horizontal axis. The graph is a downward curve from top left to bottom right but sits very close the axes.
Now we can see that the slope of the graph must be a negative slope. The implication of this is that distance is inversely related to force.
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Astrologers claim that your personality traits are determined by the positionsof the planets in relation to you at birth. Scientists argue that these gravitationaleffects are so small that they are totally insignificant. Compare the gravitationalattraction between you and Mars to the gravitational attraction between youand your 70.0 kg doctor at the moment of your birth, if the doctor stands0.500 m away (Note: MM = 6.42 x 10^23 ky, de to M = 7.83 x 10^10 m. This is theaverage distance between Earth and Mars. This distance varies as the twoplanets orbit the sun.)
ANSWER:
The force exerted by the doctor is greater
STEP-BY-STEP EXPLANATION:
Given:
Mass of Mars = 6.42 x 10^23 kg
Mass of Doctor = 70 kg
Mass at birth = m
Distance between Earth and Mars = 7.83 x 10^10 m
Distancia Doctor = 0.5 m
G = 6.67 x 10^- 11 N*m^2/kg^2
We calculated the force in each based on the mass at birth.
[tex]\begin{gathered} F_{mars}=\frac{G\cdot M_{mars}\cdot m}{d_{EM}^2}=\frac{6.67\cdot10^{-11}\cdot6.42\cdot10^{23}}{(7.83\cdot10^{10})^2}m=6.98\cdot10^{-9}m \\ F_{doc}=\frac{G\cdot M_{doc}\cdot m}{d_2^2}=\frac{6.67\cdot10^{-11}\cdot70}{\left(0.5\right)^2}\:m=1.87\cdot10^{-8}m \end{gathered}[/tex]Which means that the force exerted by the doctor is greater
If the temperature of a gas were to decrease, what would happen to the volume of a gas?
Answer:
The volume will decrease also.
increase in temperature leads to an increase in volume and vice versa.
what is the voltage across a 1.5 ohm resistor when a current of 4 amps flow through it
Answer:
6 v
Explanation:
V = I R
4 * 1.5 = 6V
Victor is driving south. He is traveling at 12m/s, when he enters an area with a new speed limit. Aver a period of 6 seconds, his speed increases for 12m/s to 29m/s. What is Victors acceleration during this period?
Victor's acceleration when he increases from 12 m/s to 29 m/s over a period of 6 seconds is 2.83 m/s².
What is acceleration?
Acceleration can be defined as the rate of change of velocity.
The S.I unit of acceleration is m/s².
To calculate Victor's acceleration, we use the formula below.
Formula:
a = (v-u)/t........... Equation 1Where:
a = Accelerationv = Final velocityu = Initial velocityt = Time.From the question,
Given:
v = 29 m/su = 12 m/st = 6 secondsSubstitute these values above into equation 1
a = (29-12)/6a = 2.83 m/s²Hence, Victor's acceleration when he increases from 12 m/s to 29 m/s over a period of 6 seconds is 2.83 m/s².
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Help! I have tried several times to figure out this question on coordinates and turning counter clockwise from the x axis. My professors notes indicate I’m way off!
Given,
The coordinates (-5,-1.3)
To find
The polar coordinates,
Explanation
The polar coordinates are written in the form
[tex](r,\theta)[/tex]Thus,
[tex]r=\sqrt{(-5)^2-(-1.3)^2}=5.16[/tex][tex]\begin{gathered} \theta=tan^{-1}(-\frac{-1.3}{-5}) \\ \Rightarrow\theta=-14.57^o \\ \Rightarrow\theta=360-14.57=345.43^o \end{gathered}[/tex]Conclusion
The polar coordinates are
[tex](5.16,345.43)[/tex]What is the mass of a 1.2 N book?
Answer:
w= MG
m=g/w
m=g/1.2 (g Constant= 10mls)
m= 8.33Kg
A homogeneous mxture of salt and water needs to separate, how?
Answer: Evaporation. Evaporation is a technique used to separate out homogeneous mixtures that contain one or more dissolved salts. The method drives off the liquid components from the solid components. The process typically involves heating the mixture until no more liquid remains.
John recently suffered a gunshot wound to the abdomen and has undergone surgery. He is 37 years old, 6’ 0”, and weighs 200 lbs. John is currently on a medical ventilator to help him breathe.
1. Describe the metabolic response to injury (ebb phase and flow phase
Answer:
The flow phase is the "all or nothing" phase. it is trying to prevent bleeding and infection. It is compensating for the trauma and volume replacement.
Explanation:
hope it helps ;-;
assume you have a cart with a mass m = 0.530 kg. the cart accelerates from rest to a final velocity of 2.1 m/s.
1. what is the net work done on the cart?
2. if the work is done over the displacement of 0.71 m, what is the average net force on the cart?
3. if there is an uncompensated frictional force f = 0.11 n, what is the work done by friction over the same displacement?
The net work done on the cart is 1.17 J.
The average net force on the cart is 1.65 N.
The work done by frictional force over the same distance is 0.078 J.
What is net work done on the cart?The net work done on the cart is calculated by applying the principle of conservation of energy as follows;
W = ΔK.E
W = ¹/₂m(v² - u²)
where;
v is the final velocity of the caru is the initial velocity of the cartm is mass of the cartW = ¹/₂(0.53)(2.1² - 0²)
W = 1.17 J
The average net force on the cart is calculated as follows;
W = Fd
where;
F is the net forced is the displacement of the cartF = W/d
F = (1.17) / (0.71)
F = 1.65 N
The work done by frictional force over the same distance is calculated as follows;
W = fd
W = 0.11 x 0.71
W = 0.078 J
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Which statement describes the horizontal motion of a horizontally launched projectile? The projectile’s acceleration is zero, so its velocity is zero. The projectile’s acceleration is –9.8 m/s2, so its velocity is changing. The projectile’s acceleration is zero, so its velocity is constant. The projectile’s acceleration is –9.8 m/s2, so its velocity is constant.
The statement that describes horizontal motion is the projectile’s acceleration is –9.8 m/s2, so its velocity is constant.
How does velocity of a projectile motion change with time?
During the upward motion of a projectile, the vertical velocity decreases with increase in the height of the motion due to the opposing force of gravity.
The vertical velocity of the projectile will be zero at maximum height. As the projectile begins to the descend, the vertical velocity starts to increase and eventually becomes maximum before the projectile hits the ground.
The horizontal velocity of the projectile will be constant since the effect of gravity is not felt in a horizontal motion.
Thus, we can conclude that during a projectile motion, the vertical velocity will change, the horizontal velocity will be constant and the acceleration due to gravity will 9.8 m/s².
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Answer:
C : The projectile’s acceleration is zero, so its velocity is constant.
Explanation:
7/21/22, 7:37 AMProblem Set ThreeNotes: Use 9.8 m/s 2 for the acceleration due to gravity. Formust be expressed in m/sLaw calculations, mass must be expressed in kg and velocity.A force of 3.2 N is applied to an 8.5 gram rifle bullet. What is the bullet’s acceleration?
ANSWER:
376.47 m/s²
STEP-BY-STEP EXPLANATION:
Given:
Force (F) = 3.2 N
Mass (m) = 8.5 gram = 0.0085 kg
We can determine the acceleration by the following formula:
[tex]\begin{gathered} F=m\cdot a \\ \\ \text{ We replacing:} \\ \\ 3.2=0.0085\cdot \:a\: \\ \\ a=\frac{3.2}{0.0085} \\ \\ a=376.47\text{ m/s^^b2} \end{gathered}[/tex]The acceleration is 376.47 m/s²
In the particle model, the object in the motion diagram is replaced by
Answer:
Single Points
Explanation:
In the particle model, the object in the motion diagram is replaced by ____.
a. an arrow showing direction
b. a series of single points
c. a large dot
d. a scalar-colored green
Hope this helps.
In outer space, a constant force is applied to a 33.2 kg probe initially at rest. The probe moves a distance of 101 m in 15 s. What acceleration does this force produce? What is the magnitude of the force?
Answer:
a
=
F
M
a
=
137
30.8
x
=
1
2
a
t
2
x
=
1
2
⋅
137
30.8
⋅
13
2
x
=
375.86
Explanation: Hope this helps ;)
This object is located 6.0 cm to the left of the lens, and the image forms at 28.7 cm to the right of the lens.What is the focal length of the lens?
Let's use the common formula:
1/f = 1/i + 1/o, where
f: focal length, i: image distance, o: object distance
1/f = 1/28.7 + 1/6
1/f = 0.2015
f = 4.9625 cm
A woman is sitting at a bus stop when an ambulance with a siren wailing at 440 Hz approaches at 31.5 m/s (about 70 mph). Assume the speed of sound to be 343 m/s.
(a)
What frequency (in Hz) does the woman hear?
Considering the Doppler effect, the woman sitting at the bus stop hears a frequency of 484.484 Hz.
Doppler effectThe Doppler effect is defined as the change in the apparent frequency of a wave produced by the relative motion of the source with respect to its observer.
When both the transmitter and the receiver are in motion, the frequency perceived by the receiver will increase as the receiver and transmitter increase their separation distance and will decrease whenever the separation distance between them decreases. The following expression is considered the general case of the Doppler effect:
f'=f× [(v ± vR)÷ (v ∓ vE)]
Where:
f', f: Frequency perceived by the receiver and frequency emitted by the transmitter, respectively. Its unit of measurement in the International System (S.I.) is the hertz (Hz), which is the inverse unit of the second (1 Hz = 1 s⁻¹)v: Wave propagation speed in the medium. It is constant and depends on the characteristics of the medium. In this case, the speed of sound in air is considered to be 343 m/s.vR, vE: Receiver and transmitter speed respectively. Its unit of measure in the S.I. is the m/s±, ∓:You will use the + sign:In the numerator if the receiver approaches the senderIn the denominator if the sender moves away from the receiverYou will use the - sign:In the numerator if the receiver moves away from the senderIn the denominator if the sender approaches the receiverFrequency in this caseIn this case, you know:
f= 440 Hzv= 343 m/svR= 0vE= 31.5 m/sIn the denominator you use the - sign because the sender approaches the receiver.Reemplacing in the expression in the general case of the Doppler effect:
f'= 440 Hz× [(343 m/s ± 0)÷ (343 m/s - 31.5 m/s)]
f'= 440 Hz× [343 m/s÷ (343 m/s - 31.5 m/s)]
f'= 440 Hz× [343 m/s÷ 311.5 m/s]
f'= 440 Hz× 1.1011
f'= 484. 484 Hz
Finally, the woman hears a frequency of 484.484 Hz.
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The light from the sun has higher frequencies from one side of the sun than from the other side. What does that tell you about the sun?
If the light from the sun has higher frequencies from one side of the sun than from the other side, it is proof that the Sun is rotating.
Doppler effect states that, if a person is standing still and a source ( sound / light ) is moving towards him, the frequency of the wave emitted from the object will increase and if the source ( sound / light ) is away from him, the frequency of the wave emitted from the object will decrease.
So, if the light from the sun has higher frequencies from one side of the sun than from the other side, it means that the Sun is rotating. The higher frequencies points are the points that rotating towards Earth and lower frequencies points are the points that rotating away from Earth.
Therefore, if the light from the sun has higher frequencies from one side of the sun than from the other side, it is proof that the Sun is rotating.
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Archerfish are known for their ability to take down insect prey by precisely shooting water jets, but they can also leap from the surface of the water to capture prey directly. A 10-cm-long archerfish begins such a leap with its body vertical in the water, using its fins and undulating its body to propel itself sharply upward. Its acceleration steadily decreases as it leaves the water because less of its body and fewer of its fins are in contact with the water. The (Figure 1) is somewhat idealized data for the acceleration of an archerfish from the instant it begins a leap until the instant it leaves the water.
a) With what speed does the fish leave the water?
b) What height above the water does it reach?
1. The speed at which the fish leave the water is 1.69 meter per seconds.
2. The height above the water that it will reach is 1.45 × 10^-1 meters.
How to illustrate the information?From the information, the 10-cm-long archerfish begins such a leap with its body vertical in the water, using its fins and undulating its body to propel itself sharply upward and its acceleration steadily decreases as it leaves the water because less of its body and fewer of its fins are in contact with the water.
The speed at which the fish leave the water will be calculated as:
= 1/2 × 45 × 75 × 10^-3
= 1687.5 × 10^-3.
= 1.69 m/s.
The height above the water that it will reach will be:
h = u² / 2g
h = (1.6875)² / 2 × 9.8
h = 0.145288
h = 1.45 × 10^-1 meters
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A ship travels at a velocity of 42 m/s in north-westerly direction. A man on the ship is walking at a velocity of 3,2 m/s from the back of the ship to the front of the ship.
What is the man’s resultant velocity in magnitude and direction?
The man’s resultant velocity is 4m/s in the north-westerly direction.
What exactly is relative speed?According to mathematics, the relative velocity is the vector difference between the velocities of two objects. The difference between the velocities of body A and body B determines the relative velocities between them.
What is the speed of resultant?The total of an object's component vector velocities is the resulting vector velocity. The sum of the vector forces acting on an object is equal to the scalar product of its mass and acceleration vector.
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An object starts at the -4 meter position; when does it get to a position of 55 meters?
The original velocity was 8 m/s and the acceleration is 3 m/s². [1.5p point]
The object at -4-meter position, gets to a position of 55 meters after a time of 2 secs if the original velocity was 8 m/s and the acceleration is 3 m/s².
Slope of a location graphThe velocity of an object is represented by the slope of a location graph. Thus, the slope’s value at a given instant corresponds to the object’s velocity at that precise moment.
What is the position-time graph of an object’s slope?The idea behind this is that an object’s velocity is equal to the slope of the line on a position-time graph. The slope of the line will be +4 m/s if the object is travelling at a velocity of +4 m/s.
What does the slope indicate about the velocity of an object?The object’s acceleration is shown by the slope of a velocity graph. Therefore, the slope’s value at a given instant corresponds to the object’s current rate of acceleration.
The time can be calculated as
disp = 55 + 4
= 59m
u = 8 m/s
a = 3 m/s².
t =?
s = ut + 1/2 at²
59 = 8(t) + 1/2 x 3 t²
⇒ 3/2 t² + 8t - 59 = 0
⇒ t = [tex]\frac{-8\sqrt{64+354} }{6}[/tex]
= 12/6
= 2sec
Thus, the time taken is 2 sec.
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5. Three skiers were racing across flat, smooth snow. The skiers in yellow and purple sweaters have the same mass,
which is more mass than the skier in the red sweater. Each skier was bumped by another skier, but not from the same
direction. Which skier(s) experienced the strongest force when bumped? How do you know?
The skier(s) who will experienced the strongest force when bumped are the yellow and purple skiers.
What is force?
A force is an effect which has the power to change any object's motion. When a mass-containing object increases its velocity, such as when it travels away from rest, a force can cause it to accelerate. A push or a pull is a straightforward method to explain force. Since a force has both magnitude and direction, it is a vector quantity. It is computed using the SI unit of newton (N). F is used to represent force (formerly P).
The skier(s) who will experienced the strongest force when bumped are the yellow and purple skiers. We can come to these conclusion because they have more mass than the red skier, but they changed speed by the same amount as the red skier did.
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In your own words, answer the following 3 questions about an object experiencing blue shift? 1. Describe the motion of an object experiencing blue shift? 2. What is happening to its wavelength and frequency? 3. Why?
1. when an object is moving towards us the light from the object is known as blueshift.
2. As a wavelength increases in size, its frequency, and energy E decrease.
3. The frequency of a wave increases, and its wavelength decreases.
When an object is moving away from us the light from the object is known as redshift, and when an object is moving towards us the light from the object is known as blueshift. Astronomers use redshift and blueshift to deduce how far an object is away from Earth, the concept is key to charting the universe's expansion.
As the frequency of a wave decreases the wavelength increases as long as the wave's velocity remains constant. If the velocity of a wave does not change when frequency decreases, it means that a smaller number of crests or troughs pass a set point in a given amount of time.
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A student fires a cannonball vertically upwards with an initial speed v. Determine all unknowns and answer the following questions. Neglect drag and the initial height and horizontal motion of the cannonball. Calculate the maximum height (h) and total flight time (t) in each of the following cases.
This is projectile motion. We know that in this kind of motion the maximum height is given by:
[tex]h_{\max }=\frac{v^2_0\sin \theta}{2g}[/tex]and that, when the motion is complete (this means that the object stops at the same height it begins, like in this case) the total time of flight is given by:
[tex]t=\frac{2v_0\sin \theta}{g}[/tex]In both of this equations the angle theta represents the angle of launch.
Now, in this case the student fires the cannonball upwards, this means that the angle of launch is 90°; since:
[tex]\sin 90=1[/tex]Then, for this problem, the equations above reduced to:
[tex]h_{\max }=\frac{v^2_0}{2g}[/tex]and
[tex]t=\frac{2v_0}{g}[/tex]Now that we know this we can plug the initial velocity of each case in the equations above to determine the maximum height and time of flight. For example, if the initial velocity is 13 m/s then we have that:
[tex]\begin{gathered} h_{\max }=\frac{13^2}{2(9.8)}=8.62\text{ m} \\ \text{and} \\ t=\frac{2(13)}{9.8}=2.65\text{ s} \end{gathered}[/tex]With this procedure we have that the table would be:
Question 2
A toddler pushes his 7.0 kg toy box at a relatively constant velocity across the tiled floor of the family room applying a horizontal force of 35 N. Calculate the magnitude of the gravitational
force.
A. 35 N
B. 70 N
C. 135 N
D. 3N
Question 3
A toddler pushes his 7.0 kg toy box at a relatively constant velocity across the tiled floor of the family room applying a horizontal force of 35 N. Calculate the magnitude of the normal force.
A. 3N
B. 35 N
C. 135 N
D. 70 N
Question 4
A toddler pushes his 7.0 kg toy box at a relatively constant velocity across the tiled floor of the family room applying a horizontal force of 35 N. Calculate the coefficient of kinetic friction between the box and the floor.
A. 0.05
B. 0.5
C. 0.7
D. 0.35
When two bodies come into contact, the friction force prevents relative motion
The box's and the floor's coefficient of friction is 1.456 102.
Reason:
Known variables include;
The toy box weighs 7.0 kg
When the toy box is pushed, its velocity is constant
The child's force is equal to 35 N.
Required:
To determine the box's and the floor's coefficient of kinetic friction
Solution:
Given that the box is moving at a constant speed, there is no net force acting on the box, which results in;
Where;
= Force of friction
Coefficient of friction, = N; Normal response, = N
Normal object behavior on a flat surface equals the weight of the object
Box weight and coefficient of friction are same.
The box's weight is W = 7.0 kg x 9.81 m/s2
what is kinetic friction?
An impeding force known as kinetic friction is present when a body or object starts to move. It should be noted that this force acts parallel to the surface and in the opposite direction to the motion of the body that is sliding with respect to the surface.
to learn more abot kinetic friction refer to:
https://brainly.com/question/14111192
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