Find a basis for the eigenspace corresponding to each listed eigenvalue of A below.
A = 4 0 -1 14 5 -10 2 0 1 λ=5,2,3
A basis for the eigenspace corresponding to λ = 5 is { }. (Use a comma to separate answers as needed.) A basis for the eigenspace corresponding to λ = 2 is { }. (Use a comma to separate answers as needed.) A basis for the eigenspace corresponding to λ = 3 is . { }. (Use a comma to separate answers as needed.)

Answers

Answer 1

The basis for the eigenspace corresponding to lambda=5,1,4 are None,[tex]\left[\begin{array}{c}-1 \\\frac{1}{2} \\0\end{array}\right][/tex] and [tex]$\left[\begin{array}{l}2 \\ 1 \\ 1\end{array}\right]$[/tex]

[tex]$$A=\left[\begin{array}{ccc}5 & -12 & 10 \\0 & 7 & -3 \\0 & 6 & -2\end{array}\right]$$[/tex]

Eigenspace corresponding to lambda=5,1,4

The eigenspace E_lambda corresponding to the eigenvalue lambda is the null space of the matrix a [tex]\mathrm{A}-(\lambda) \mathrm{I}"[/tex]

for lambda=5

[tex]$$\mathrm{E}_5=\mathrm{N}(\mathrm{A}-5 \mathrm{I})$$[/tex]

Reducing the matrix A-5I by elementary row operations

[tex]$$\begin{aligned}A-5 I & =\left[\begin{array}{ccc}5-5 & -12 & 10 \\0 & 7-5 & -3 \\0 & 6 & -2-5\end{array}\right] \\& =\left[\begin{array}{ccc}0 & -12 & 10 \\0 & 2 & -3 \\0 & 6 & -7\end{array}\right] \\& \sim\left[\begin{array}{ccc}0 & -12 & 10 \\0 & 1 & -\frac{3}{2} \\0 & 6 & -7\end{array}\right] R_2 \rightarrow \frac{R_2}{2} \\& \sim\left[\begin{array}{ccc}1 & 0 & -8 \\0 & 1 & -\frac{3}{2} \\0 & 6 & -7\end{array}\right] R_1 \rightarrow R_1+2 R_2\end{aligned}$$[/tex]

[tex]\sim\left[\begin{array}{ccc}1 & 0 & -8 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 2\end{array}\right] R_3 \rightarrow R_3-6 R_2$$\\\sim\left[\begin{array}{ccc}1 & 0 & -8 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 1\end{array}\right] R_3 \rightarrow \frac{\mathrm{R}_3}{2}$$\\\sim\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 1\end{array}\right] \mathrm{R}_1 \rightarrow \mathrm{R}_1+8 \mathrm{R}_3$[/tex]

[tex]$\sim\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right] R_2 \rightarrow R_2+\frac{2 R_3}{2}$[/tex]

The solutions x of A-5I=0 satisfy x_1=x_2=x_3=0 that is, the null space solves the matrix

[tex]$$\left[\begin{array}{lll}1 & 0 & 0 \\0 & 1 & 0 \\0 & 0 & 1\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{l}0 \\0 \\0\end{array}\right]$$[/tex]

Hence The null space is [tex]\left[\begin{array}{l}0 \\ 0 \\ 0\end{array}\right] E_5[/tex] has no basis

[tex]$$\begin{aligned}& \text { case: } 2 \\& \text { for } \lambda=1 \\& \mathrm{E}_5=\mathrm{N}(\mathrm{A}-(1) \mathrm{I})\end{aligned}$$[/tex]

we reduce the matrix A-I by elementary row operations as follows.

[tex]$$\begin{aligned}A-1 & =\left[\begin{array}{ccc}5-1 & -12 & 10 \\0 & 7-1 & -3 \\0 & 6 & -2-1\end{array}\right] \\& =\left[\begin{array}{ccc}1 & -3 & \frac{5}{2} \\0 & 6 & -3 \\0 & 6 & -3\end{array}\right] R_1 \rightarrow \frac{R_1}{4} \\& \sim\left[\begin{array}{ccc}1 & -3 & \frac{5}{2} \\0 & 1 & -\frac{1}{2} \\0 & 6 & -3\end{array}\right] R_2 \rightarrow \frac{R_2}{6}\end{aligned}[/tex]

[tex]$$$\sim\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 6 & -3\end{array}\right] R_1 \rightarrow R_1+3 R_2$\\$\sim\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 0 & 0\end{array}\right] R_3 \rightarrow R_3-6 R_2$[/tex]

Thus, the solutions x of (A-I) X=0 satisfy

[tex]$\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 0 & 0\end{array}\right]\left[\begin{array}{l}x_1 \\ x_2 \\ x_3\end{array}\right]=\left[\begin{array}{l}0 \\ 0 \\ 0\end{array}\right]$[/tex]

x_3=t

[tex]$\Rightarrow \mathrm{x}_1=-\mathrm{t}, \mathrm{x}_2=\frac{\mathrm{t}}{2}$[/tex]

[tex]$\vec{x}=\left[\begin{array}{c}-t \\ \frac{t}{2} \\ t\end{array}\right]=\left[\begin{array}{c}-1 \\ \frac{1}{2} \\ 1\end{array}\right] t$[/tex]

The Basis for the nullspace A-I will be: [tex]$\left.\left(\begin{array}{c}-1 \\ \frac{1}{2} \\ 1\end{array}\right]\right)$[/tex]

case:3

lambda=4

[tex]$$\mathrm{E}_5=\mathrm{N}(\mathrm{A}-(4) \mathrm{I})$$[/tex]

we reduce the matrix A-4I by elementary row operations as follows.

[tex]$\begin{aligned} A-4 \mid & =\left[\begin{array}{ccc}5-4 & -12 & 10 \\ 0 & 7-4 & -3 \\ 0 & 6 & -2-4\end{array}\right] \\ & =\left[\begin{array}{ccc}1 & -12 & 10 \\ 0 & 3 & -3 \\ 0 & 6 & -6\end{array}\right] \\ & \sim\left[\begin{array}{ccc}1 & -12 & 10 \\ 0 & 1 & -1 \\ 0 & 6 & -6\end{array}\right] R_2 \rightarrow \frac{R_2}{3}\end{aligned}$[/tex]

[tex]$\begin{aligned} & \sim\left[\begin{array}{ccc}1 & 0 & -2 \\ 0 & 1 & -1 \\ 0 & 6 & -6\end{array}\right] \mathrm{R}_1 \rightarrow \mathrm{R}_1+12 \mathrm{R}_2 \\ & \sim\left[\begin{array}{ccc}1 & 0 & -2 \\ 0 & 1 & -1 \\ 0 & 0 & 0\end{array}\right] \mathrm{R}_3 \rightarrow \mathrm{R}_3-6 \mathrm{R}_2\end{aligned}$[/tex]

Thus, the solutions x of (A-4IX)=0 satisfy

[tex]$$\left[\begin{array}{ccc}1 & 0 & -2 \\0 & 1 & -1 \\0 & 0 & 0\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{l}0 \\0 \\0\end{array}\right]$$[/tex]

x_3=t

[tex]$\Rightarrow \mathrm{x}_1=2 \mathrm{t}, \mathrm{x}_2=\mathrm{t}$[/tex]

[tex]$$\vec{x}=\left[\begin{array}{c}2 t \\t \\t\end{array}\right]=\left[\begin{array}{l}2 \\1 \\1\end{array}\right] t$$[/tex]

The Basis for the nullspace A-4 I will be [tex]\left(\left[\begin{array}{l}2 \\ 1 \\ 1\end{array}\right]\right)[/tex]

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Mrs. Katz’s science class has spherical beakers that measure 14 centimeters in diameter. If Mrs. Katz wants to fill the sphere, what is the volume in cubic centimeters that she can fit into the beaker? round your answer to the nearest hundredth.

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The volume of the spherical beaker is 1436.76 cubic centimeters

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In order to determine the volume the spherical beaker, you need the formula for the volume of a sphere.

The volume of sphere is given by the formula:

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\frac { 32 x ^ { 2 } } { y } + \frac { 108 y ^ { 2 } } { x } y 32x 2 ​ + x 108y 2​

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Therefore , the solution of the given problem of fraction comes out to be 4((2x)³ + (3y)³) /xy.

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Answers

Answer:

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Step-by-step explanation:

since the triangles are similar then corresponding angles are congruent, so

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Answers

Answer:

y = 9.75x

Step-by-step explanation:

y = the money earned

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given

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Substituting the value of 'a',

h = (12√3)/2 = 6√3 =

10.39 units.

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WILL MARK BRAINLIEST: A researcher wishes to see if a kelp extract helps prevent frost damage on tomato plants. One hundred tomato plants in individual containers are randomly assigned to two different groups. Plants in both groups are treated identically, except that the plants in group 1 are sprayed weekly with a kelp extract, while the plants in group 2 are not. After the first frost in the autumn, 8 of the 50 plants in group 1 exhibited damage, and 18 of the 50 plants in group 2 showed damage. Why would the use of z-procedures be questionable value in this situation?

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C. Individual plants were not assigned randomly to the two experimental treatments.

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The value of {a} in the given modelled statement equation is 5.

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In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign "=".

Given is that the ages of three cats are (a) , (a + 4) and (2a - 3). Their total age is 21.

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{

Complete question is given below -

The ages of three cats are a, a+4 and 2a-3. Their total age is 21. Determine a.

}

Given triangle ABC, which equation could be used to find the measure of ∠C?

a
tan m∠C = one half

b
sin m∠C = square root of 5 over 5

c
sin m∠C= square root of 5 over 2

d
tan m∠C = 2

Answers

The measure of the angle ∠C in the triangle ABC can be gotten using tan m∠C = 2

What is an equation?

An equation shows how two or more numbers and variables are related to each other.

On the other hand, trigonometric ratios are used to show the relationship between the sides and angles of a right angled triangle.

The basic equations of the trigonometry ratios are

sinФ = opposite/hypotenuse; cosФ = adjacent/hypotenusetanФ = opposite/adjacent

Using the above as a guide, and the given triangle:

We have:

tan m∠C = opposite/adjacent

Substitute the known values in the above equation, so, we have the following representation

tan m∠C = 6/3

Evaluate

tan m∠C = 2

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Mike has $21 to spend at the mall. He spends all of his money on bracelets for his sisters. Bracelets cost $3 each. How many bracelets dose he buy?

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Answer:

7

Step-by-step explanation:

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Answers

Answer:The average rate of the function from x = 2 to x = 4 is 6.

Step-by-step explanation:

Write an inequality with the solution x > or equal to 4. The inequality should have the variable on both sides, a fractional coefficient of the variable on the left side, and a fraction anywhere on the right side.

Answers

The inequality equation ( x ≥ 4 ) is given as ( 1/4 ) + ( 5x/4 ) ≥ ( 5/4 ) + x

What is an Inequality Equation?

Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

In an inequality, the two expressions are not necessarily equal which is indicated by the symbols: >, <, ≤ or ≥.

Given data ,

Let the inequality equation be represented as A

Now , the value of A is

x ≥ 4   be equation (1)

On simplifying the equation , we get

Divide by 4 on both sides of the equation , we get

( x / 4 ) ≥ 1

Adding x on both sides of the equation , we get

x + ( x/4 ) ≥ 1 + x

Now , adding ( 1/4 ) on both sides of the equation , we get

x + ( 1/4 ) + ( x/4 ) ≥ 1 + x + ( 1/4 )

On simplifying the equation , we get

( 1/4 ) + ( 5x/4 ) ≥ ( 5/4 ) + x

Therefore , the value of A is ( 1/4 ) + ( 5x/4 ) ≥ ( 5/4 ) + x

Hence , the inequality equation is ( 1/4 ) + ( 5x/4 ) ≥ ( 5/4 ) + x

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There are 8 employees on The Game Shop's sales team.
Last month, they sold a total of g games. One of the
sales team members, Chris, sold 17 fewer games than
what the team averaged per employee.
How many games did Chris sell?
Write your answer as
an expression.
games

Answers

According to the solving the team average is g/17 and Chris sold (g/8) - 17  games.

What do you mean by average?

The term "Average" refers to a value that should be used to describe the sample as a whole. The average is determined by dividing the total number of values in a set by the total number of values. also known as the arithmetic mean.

How do you calculate the mean?

Average A collection of integers are added, their count is divided, and the sum is used to determine the arithmetic mean.

According to the given information:

average game sold = g/8

since Chris sold 17 games less than average

hence, Chris sold   games

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Can you help me with this

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slope formula =y2-y1/x2-x1

3 -(-9) =12
6-(8) =-2
12/-2=

the slope = -6/1

Please hurry, it's due in two days ​

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Answer:

C (3, -2) is in the Fourth Quadrant.

The equation of the line is Y=2

The Line x=-1 would be a straight vertical line on the point x=-1.

Step-by-step explanation:

I have attached three pictures, one of all the quadrants labeled for you to help in the future, one of a visual of y=2 with the points labeled, and one of a visual of the line x = -1.

Winston has a savings in a bank and was surprised that his money
accumulated to P 65. 000 after 3 years. He knew that the bank offered him 5%
interest rate compounded bimonthly. How much was his sayings at the start?​

Answers

The initial saving of the Winston was $55952.48

Compound Interest

Compound interest is when you receive interest on both your interest income and your savings.

According to the question given,

Let the initial savings amount be P

We know Compound interest =

[tex]A = P(1+\frac{r}{n} )^{nt}[/tex]

Where,

A = final amount

P = initial principal balance

r = interest rate

n = number of times interest is applied per year

t = number of time periods elapsed

Given,

A = $65000

t = 3 years

r = 5% = 0.05

n = 2 *12 = 24

So

65000 = P(1 + (0.05/24))^72

P =  $55952.48

Therefore the initial savings was  $55952.48

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Can someone help me please? Picture attached

Answers

Answer:

Step-by-step explanation:

A^2 + B^2 = C^2

12^2 + B^2 = 18^2

144 + B^2 = 324

Subtract 144 from both sides

B^2 = 324 - 144

B^2 = 180

[tex]\sqrt{180}[/tex] = 13.416

B^2 = 13.4

What is slope and intercept of the line 2x 3y 6?

Answers

The slope of linear eqution of two variables x and y, i.e., 2x+3y = 6 is -2/3 and intercept is 2 .

The slope-intercept form expression of a linear equation is y = mx + c --------->(1)

Where m --> slope of the straight line and

c --> the x - intercept .

The expression for slope is represented as :

m = (y₂ - y₁) / (x₂ - x₁) ------>(2)

where (x₁, y₁) and (x₂, y₂) are any two points lying on the straight line. Once the slope m is determined then the general equation of the straight line can be determined easily.

Now we have , the equation in the problem statement is 2x + 3y = 6. firstly , we can rewrite it in the slope-intercept form as :

3y = 6 - 2x

=> y = 6/3 - 2x/3

=> y = -2x/3 + 6/3

=> y = (-2/3)x + 2

comparing the above eqution with eqution(1) we get , m = -2/3 and c = 2. So, slope and intercept of eqution 2x + 3y = 6 are -2/3 and 2 respectively.

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Dylan invested some money in his bank.
He agreed a simple interest rate of 3% per annum fo a period of 2 years.
At the end of the 2-year period the value of his investment increased by £72

Work out the value of Dylan's initial investment

Answers

The amount invested by Dylan will be £1200.

What is simple interest?

Simple interest is the amount of borrowing-related interest that is calculated using only the original principal and a constant interest rate.

Given that Dylan invested some money in his bank. He agreed on a simple interest rate of 3% per annum for a period of 2 years. At the end of the 2-year period, the value of his investment increased by £72.

The amount of money invested will be calculated as,

SI = ( P x R x T ) / 100

72 = ( P x 3 x 2 ) / 100

7200 = 6P

P = 7200 / 6

P = £1200

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Shade the points in the plane whose x-coordinates are greater than their y-coordinates. Write the inequality that describes these points.

Answers

The inequality that describes these points is y ≤ -1/2(x) -3. The graph is given the attachment.

How to graph an inequality?

To graph a linear inequality in two variables (say, x and y), start with y on one side. Consider the related equation obtained by changing the inequality sign to an equality sign. This equation's graph is a straight line.

If the inequality is strict (< or >), draw a dashed line. If the inequality is not strict (≤ or ≥), draw a solid line.

Finally, choose one point that is not on either line ((0,0) is usually the easiest) and determine whether these coordinates satisfy the inequality or not. If they do, shade the half-plane containing that point. If they don't, shade the other half-plane.

Graph each of the system's inequalities in a similar way.

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2 + (4-3 (3-6) -4] +12=

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Answer: 23

Step-by-step explanation:

How do you find the dilation of a function?

Answers

Finding the dilation's center point is the first step in determining the scale factor. Next, we measure the distances between the center point and various points on the preimage and the image. The scale factor is equal to the ratio of these distances.

Resizing an item uses a transition called dilation. Dilation is used to enlarge or contract the items. The result of this transformation is a picture with the same shape as the original. However, there is a variation in the shape's size.

A graph's form is altered by dilations, frequently leading to "movement" in the process. In the figure above, the green curve has been "transformed" into the red curve. It has been three times "dilated" (or stretched) horizontally. A dilatation is an axial stretching or contraction brought on by multiplication or division.

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For which values of x does each expression make sense? square root of x-2 over square root of x-3

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the answer is x>3

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In ΔSTU, = 670 inche, u = 630 inche and ∠U=67°. Find all poible value of ∠S, to the nearet degree

Answers

The measure of ∠S is 59.4° for trignometric identities

What are trigonometric identities?

There are three commonly used trigonometric identities.

Sin x = 1/ cosec x

Cos x = 1/ sec x

Tan x = 1/ cot x or sin x / cos x

Cot x = cos x / sin x

We have,

ΔSTU:

s = 50 inches

t = 58 inches

u = 630 inches

Applying the cosines rule on ΔSTU.

s² = t² + u² - 2 x t x u x cos S

cos S = (t² + u² - s²) / 2tu

cos S = (58² + 27² - 50²) / (2 x 58  x 27)

cos S = (3364 + 729 - 2500) / 3132

cos S = 0.5086.

∠S = (0.5086)

∠S = 59.4°

Thus,

∠s angle value is  59.4°.

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The cost to hire a tent consists of two parts. $c + $d per dayThe total cost for 4 days is $27. 10 and for 7 days is $34. 30. Write down two equations in c and d and solve them

Answers

The cost to hire a tent consists of a fixed cost of $17.50 and a variable cost of $2.40 per day.

Let's call the total cost of hiring a tent for 4 days as T4, and the total cost of hiring a tent for 7 days as T7.

The first equation is the cost for 4 days:

T4 = c + 4d

The second equation is the cost for 7 days:

T7 = c + 7d

We know the values of T4 and T7 from the problem statement:

T4 = $27.10 and T7 = $34.30

We can now use these two equations and their corresponding values to solve for c and d:

Substitute the value of T4 into the first equation:

$27.10 = c + 4d

Substitute the value of T7 into the second equation:

$34.30 = c + 7d

Now we have a system of two equations with two variables (c and d).

Subtract 4d from both sides of the first equation:

$27.10 - 4d = c

Subtract c from both sides of the second equation:

$34.30 - c = 7d

Now we can substitute the value from step 4 into step 5:

$34.30 - $27.10 + 4d = 7d

7d = $34.30 - $27.10 + 4d

3d = $7.20

d = $7.20 / 3 = $2.40

Now we have the value of d, we can substitute it back into the first equation to find the value of c:

$27.10 = c + 4d

$27.10 = c + 4($2.40)

$27.10 = c + $9.60

c = $27.10 - $9.60

c = $17.50

Therefore, c= $17.50 and d= $2.40

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30PTS 30PTS don’t explain just answer

Answers

Answer:

y = 95°

Step-by-step explanation:

x + 120° = 180°

x = 180° - 120°

x = 60°

25° + y + x = 180°

25° + y + 60° = 180°

y + 85° = 180°

y = 180° - 85°

y = 95°

What is the volume, in cubic in, of a rectangular prism with a height of 3in, a width of 10in, and a length of 2in

Answers

On solving the provided question, we can say that w = 10 in; l = 2 in; volume of prism = WL = 10 X 2 = 20 in sq

what is prism?

The definition of a prism in geometry is a polyhedron with an n-sided polygonal base, a second base that is a shifted copy of the first base, and n additional faces (necessarily all parallelograms), with two Connect the corresponding sides of the base. Translations of the base are all cross sections that are parallel to it. A prism is a two-sided, solid, three-dimensional object. It consists of equal cross-sections, flat sides, and identical bases. A prism has faces that are parallelograms or rectangles without bases. A prism is a homogenous, solid, transparent, refracting object enclosed by two planes that are obliquely angled to one another. Two triangular faces and three parallel rectangular faces make up a typical prism. They are constructed of either glass.

here,

w = 10 in

l = 2 in

volume of prism = WL = 10 X 2 = 20 in sq

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Does 4 8 10 make a right triangle?

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No, 4, 8 and 10 cannot be the sides of a right triangle. So 4, 8 and 10 does not make a right triangle.

In a right triangle, the side opposite the right angle (the hypotenuse) is the longest side. The side opposite the 90-degree angle is the hypotenuse and it follows the Pythagorean theorem which states that the square of the hypotenuse is equal to the sum of the squares of the legs, so:

c² = a² + b²

In this case, c = 10, a = 8 and b = 4,

so 8² + 4² = 64 + 16 = 80 ≠ 10²

That is it does not follows the theorem. Therefore, 4, 8 and 10 cannot be the sides of a right triangle.

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