The circumference of a circle with diameter 2.76 m is 8.66 m.
What is Circumference?
Circumference of a circle is perimeter of circle.
Given that;
Diameter of a circle = 2.76 m
Since, Circumference of a circle = 2πr
Where, r is radius of circle.
Now, Diameter of a circle = 2.76 m
Then, Radius of a circle = 2.76/2 = 1.38 m
Hence, Circumference of a circle = 2πr
Substitute all the values;
Circumference of a circle = 2 x 3.14 x 1.38
= 8.66 m
Thus, The circumference of a circle with diameter 2.76 m is 8.66 m.
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Write a situation in which positive and negative numbers are used to describe values that have opposite meaning. What does 0 represent in this situation you created? (10 points)
A situation in which positive and negative numbers are used to describe values that have opposite meaning is that John is on top of a mountain that is 2000 above sea level and his friend is diving and is below 2000 feet.
The thing that 0 represents is the addition in the sea level.
How to illustrate the information?Based on the information illustrated, the situation will be that John is on top of a mountain that is 2000 above sea level and his friend is diving and is below 2000 feet.
Therefore, the addition will be:
= 2000 + (-2000)
= 2000 - 2000
= 0
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1 3/4 x 4 2/6 nnnnnnnnnnn
The result of the multiplication operation yields 7 7/12
Multiplication of numbersFrom the question, we are to multiply the given fractions. The given fractions are
1 3/4 and 4 2/6
First, we will convert the fractions to improper fractions
Converting 1 3/4 to an improper fraction
1 3/4 = 7/4
Converting 4 2/6 to an improper fraction
4 2/6 = 26/6
Thus,
The multiplication operation becomes
7/4 × 26/6
= 7/4 × 13/3
= 91/12
= 7 7/12
Hence, the product of the given numbers is 7 1/12
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how to find the measure of L
SOLUTION:
Step 1:
In this question, we are given the following:
Step 2:
he deatails of the solution are as follows:
rom tjhe triangle, we can see that Traingle KLM is an isosceles triangle, such that Angle J = 52.3 degrees suchn that:
[tex]Angle\text{ J = Angle K = 52. 3}^0(\text{ base angles are equal\rparen}[/tex]Now, we have that:
[tex]\begin{gathered} Angle\text{ J +Angle K + Angle L = 180}^0 \\ 52.\text{ 3}^0+52.\text{ 3}^0+\text{ Angle L = 180}^0 \\ 104\text{. 6 }^0+\text{ Angle L = 180}^0 \\ Angl\text{e L = 180}^0-104\text{. 6}^0 \\ Angle\text{ L = 75.4}^0 \end{gathered}[/tex]ONCLSUSION:
The measure of Angle L =
[tex]75.\text{ 4}^0[/tex]Stella signed up for a streaming music service that costs $9 per month. The service allows Stella to listen to unlimited music, but if she wants to download songs for offline listening, the service charges $1.25 per song. How much total money would Stella have to pay in a month in which she downloaded 40 songs? How much would she have to pay if she downloaded ss songs?
The money would Stella have to pay in a month in which she downloaded 40 songs is $59.
The amount that she has to pay if she downloaded ss songs is 9 + 1.25s.
How to illustrate the information?From the information, Stella signed up for a streaming music service that costs $9 per month and the service allows Stella to listen to unlimited music, but if she wants to download songs for offline listening, the service charges $1.25 per song.
The money would Stella have to pay in a month in which she downloaded 40 songs is:
= 9 + 1.25s
where s = number of songs
= 9 + 1.25s
= 9 + 1.25(40)
= 9 + 50
= $59.
The amount that she has to pay if she downloaded s songs is:
= 9 + 1.25(s)
= 9 + 1.25s
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I need help with this problem
)
2) So, let's begin with the lower-left product of matrices:
[tex]\begin{gathered} \begin{pmatrix}-2 & 12 \\ -1 & -3\end{pmatrix}\times\begin{pmatrix}2 & 1 \\ 4 & 2\end{pmatrix}= \\ \begin{pmatrix}\left(-2\right)\cdot \:2+12\cdot \:4&\left(-2\right)\cdot \:1+12\cdot \:2\\ \left(-1\right)\cdot \:2+\left(-3\right)\cdot \:4&\left(-1\right)\cdot \:1+\left(-3\right)\cdot \:2\end{pmatrix} \\ \begin{pmatrix}44&22\\ -14&-7\end{pmatrix} \end{gathered}[/tex]Now for the next pair of matrices in the middle:
[tex]\begin{gathered} \begin{pmatrix}2 & 0 \\ 1 & 0\end{pmatrix}\times\begin{pmatrix}3 & -1 \\ 2 & 2\end{pmatrix}= \\ \begin{pmatrix}2\cdot \:3+0\cdot \:2&2\left(-1\right)+0\cdot \:2\\ 1\cdot \:3+0\cdot \:2&1\cdot \left(-1\right)+0\cdot \:2\end{pmatrix} \\ \begin{pmatrix}6&-2\\ 3&-1\end{pmatrix} \end{gathered}[/tex]Notice that each row is multiplied by each correspondent column.
And finally, the pair on the lower-right:
[tex]\begin{gathered} \begin{pmatrix}5&-2\\ \:\:\:4\:&-3\end{pmatrix}\times \begin{pmatrix}2&-1\\ \:\:3&1\end{pmatrix} \\ \begin{pmatrix}5\cdot \:2+\left(-2\right)\cdot \:3&5\left(-1\right)+\left(-2\right)\cdot \:1\\ 4\cdot \:2+\left(-3\right)\cdot \:3&4\left(-1\right)+\left(-3\right)\cdot \:1\end{pmatrix} \\ \begin{pmatrix}4&-7\\ -1&-7\end{pmatrix} \end{gathered}[/tex]) Thus, the se are theanswers .
Write the fractions in order from least to greatest: 2/9, 1/6, 1/5, 3/10
Answer:
1/5,1/6,2/9,3/10
Step-by-step explanation:
hope it helps helps and have a nice day! :)
For f(x) = 3x²-x+5, 2f(-3) - f(2)
Answer:
55
Step-by-step explanation:
First solve for f(-3):
[tex]f(-3) = 3(-3)^2-(-3)+5[/tex]
[tex]f(-3)=3(9)+3+5[/tex]
[tex]f(-3)=27+3+5[/tex]
[tex]f(-3) = 35[/tex]
Second solve for f(2):
[tex]f(2) = 3(2)^2-(2)+5[/tex]
[tex]f(2) = 3(4)-(2)+5[/tex]
[tex]f(2) = 12-2+5[/tex]
[tex]f(2) = 15[/tex]
Now plug in f(-3) and f(2) to the expression:
[tex]2(f(-3))-(f(2)) =[/tex]
[tex]2(35)-(15)=[/tex]
[tex]70-15=55[/tex]
List the angles of the triangle in order from largest to smallest.Question options:A) ∠A, ∠C, ∠BB) ∠C, ∠B, ∠AC) ∠B, ∠C, ∠AD) ∠A, ∠B, ∠C
Angles opposite to shorter sides are shorter. Then, the shortest angle is opposed to the shortest side.
Since the shortest side has a length 2.8 and is opposed to the angle A, then the shortes angle is A.
The next shortest side is that opposite to B, which has a length of 3.4.
And finally, the largest side has a length of 4.7 and it's opposite to the angle C.
Therefore, the list of angles from largest to smallest, is:
[tex]\angle C,\angle B,\angle A[/tex]Katie wants to save at least $280 to go on the math team field trip. He currently has $112 saved.
If he has 8 weeks left to save, which inequality and graph represent the amount of money per week he needs to save to meet the goal?
He must save 21 dollars per week to meet the goal.
How to find the amount to be saved?Given,
Katie wants to save at least $280
He currently has $112 saved.
If he has 8 weeks left to save.
Solution:
The amount to be saved is $280 - $112 = $168
If he has 8 weeks left to save,
Per week he must save = $168/8
= $21
He must save 21 dollars per week to meet the goal.
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Find the direction angle of v for the following vector.v=−6i−2jWhat is the direction angle of v?
Given:
v is the given vector.
[tex]v=-6i-2j[/tex]To find:
Find the direction angle of v.
Formula to find the direction:
[tex]\tan \theta=\frac{y}{x}[/tex]From the given vector x and y are:
[tex]x=-6\text{ \& y=-2}[/tex][tex]\begin{gathered} \tan \theta=\frac{-2}{-6} \\ \theta=\tan ^{-1}(\frac{1}{3}) \\ \theta=18.4\degree \end{gathered}[/tex]Please Help me solve this
The value of f'(x) at x = 1 is 1 for first order derivative of x^x^3.
A derivative in calculus is the rate of change of a quantity y with respect to another quantity x. It is also termed the differential coefficient of y with respect to x. Differentiation is the process of finding the derivative of a function.
Given that, x^x^3 and we have to find the first order derivative with respect to x and then find the value at x = 1.
Let's proceed to solve this question accordingly.
let f(x) = x^x^3
The first order derivative = f'(x) = d/dx(x^x^3)
First apply the generalized power rule, then we have
= x^x^3.d/dx(ln(x)x^3)
Applying the power rule, we get
= x^x^3 (d/dx(x^3).ln(x)+x^3.d/dx(ln(x)))
= x^x^3 (3x^2 ln(x) +x^3.1/x)
= x^x^3 (3x^2ln(x) +x^2)
On simplifying, we will get
= x^x^3+2(3ln(x)+1)
f'(x) = d/dx(x^x^3) = x^x^3+2(3ln(x)+1)
Now, at x = 1, we get
f'(x) = d/dx(x^x^3) = x^x^3+2(3ln(x)+1) = 1
Therefore, f'(x) = d/dx(x^x^3) = x^x^3+2(3ln(x)+1) = 1 is the required answer.
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help pls!! In the figure below, N is between M and O, and O is between N and P. If NO=2, NP = 8, and MP=15, find MO.
The distance between MO is 9.
How to find MO ?From the question MP is straight line and O & N is points between M & P.
No is 2NP is 8MP is 15so the total length of line is 15
Need to find MO , To find MO = MP - (NP - NO)
= 15 - (8 -2)
= 15 - 6 = 9
The MO is 9.
To find points in graph :
To find a line that's parallel to a line and goes through a particular point, use the point's coordinates for (x1, y1) in point slope form: y - y1 = m (x - x1).The slope intercept formula y = mx + b is used when you know the slope of the line to be examined.Use the slope and one of the points to solve for the y-intercept.One of your points can replace the x and y, and the slope you just calculated replaces the m of your equation y = mx + b. Then b is the only variable left. Use the tools you know for solving for a variable to solve for b.To learn more about finding distance refer :
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write 7843 to nearest thousand with explanations
b(x)=18-0.5x 6 and 18
The solution of B(x) = 18 - 0.5x with x being -2, 0, 5 is 19, 18 and 15.5.
How to evaluate functions?Finding the value of f(x) =... or y =... that corresponds to a certain value of x is what it means to evaluate a function. Simply swap out all instances of x with the value of x to do this. For example, if we are requested to evaluate f(4), then the value 4 has been given to x.Given:
B(x) = 18-0.5x
x = -2, 0, 5
Putting the values of x to find the result of the function.
B(-2) = 18 - 0.5 × (-2) = 18 + 1 = 19
The required solution of the function at x = -2 is f(-2) = 19.
B(0) = 18 - 0.5 × (0) = 18
The required solution of the function at x = 0 is f(0) = 18.
B(5) = 18 - 0.5 × (5) = 18 - 2.5 = 15.5
Thus, the required solution of the function at x = 5 is f(5) = 15.5.
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The complete question is :"How do you solve B(x) = 18-0.5x with x being -2, 0, 5."
3. John and Savanah are saving money to go on a trip to Mexico. They need at least $2,545 in order to go. John tutors English and Savanah works as a babysitter to raise money. John charges $15 per hour and Savanah charges $20 per hour. The number of hours that Savanah has scheduled is no more than five times the number of hours John has scheduled. Savanah will babysit at least 40 hours.. Write a set of constraints to model the problem, with x representing the number of hours John tutors and y representing the number of hours Savanah babysits. Answer:
The group of restrictions used to simulate the issue includes
y<5x andy [tex]\geq[/tex] 40hours How to construct a set of restrictions to represent the issue:The issue includes the following information.
They need a minimum of $2,545 divided by the hours John instructs and the hours Savanah watches children.There is a maximum of a five-fold difference between the number of hours Savanah has booked and that John has.At least 40 hours will be spent watching the children by Savanah.The following are the restrictions for modeling the issue: There is a maximum of a five-fold difference between the number of hours Savanah has booked and that John has.
Savanah will provide childcare for at least 40 hours, with no more than meaning it is not larger than that which suggests it is less than, Hence, y<5x
Meaning "at least 40 hours" is "at least 40 hours." 40 hours or more may be expressed as
y ≥ 40 hours
The two necessary restrictions are represented as y< 5x and y=> 40 hours in an inequality model.
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Members of the marching band line up in 6 rows of 8.
Answer: 6x8
Ur answers should be 48 and again we did repeated addition so
6+6+6+6+6+6+6+6 or we can do 12+12+12+12 or 24+24 which we should know use 48
Step-by-step explanation:
Find the x-intercept of the function g(x)=8x²-10x-3
To find the x-intercepts of the function g(x), we must set it equal to 0 and solve for x.
We have the following:
[tex]\begin{gathered} g(x)=8x^2-10x-3 \\ if\text{ g(x)=0} \\ \Rightarrow8x^2-10x-3=0 \end{gathered}[/tex]we can use the quadratic formula to get the roots of the polynomial:
[tex]\begin{gathered} a=8 \\ b=-10 \\ c=-3 \\ x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \Rightarrow x_{1,2}=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(8)(-3)}}{2(8)}=\frac{10\pm\sqrt[]{196}}{16} \\ \Rightarrow x_{1.2}=\frac{10\pm14}{16} \\ \Rightarrow x_1=\frac{10+14}{16}=\frac{24}{16}=\frac{3}{4} \\ \Rightarrow x_2=\frac{10-14}{16}=\frac{-4}{16}=-\frac{1}{4} \end{gathered}[/tex]therefore, the x-intercepts of the function g(x) are the points (3/4,0) and (-1/4,0)
(11, 3) and (4, 3) on a coordinate plane?
The midpoint of the given points (11, 3) and (4, 3) on the coordinate plane is ( 15/2, 3 ).
How calculate the midpoint between two point?A midpoint is simply a point that divides a line segment into two equal halves.
The midpoint formula is expressed as;
M = ( (x₁+x₂)/2, (y₁+y₂)/2 )
Given the data in the question;
Point 1( 11, 3 )
x₁ = 11y₁ = 3Point 2( 4, 3 )
x₂ = 4y₂ = 3Midpoint = ?
To find the midpoint, plug the given points into the midpoint formula above and simplify.
M = ( (x₁+x₂)/2, (y₁+y₂)/2 )
M = ( ( 11 + 4 )/2, ( 3 + 3 )/2 )
M = ( ( 15 )/2, ( 6 )/2 )
Midpoint M = ( 15/2, 3 )
Therefore, the midpoint of the given coordinates is ( 15/2, 3 ).
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5. Geometry Audrey draws a triangle that has
these sides: s, s, and is. When the length of s
is doubled, the new perimeter is twice the old
perimeter less 14. What are lengths of
the triangle?
The length of each side is less than sum of the lengths of the other two sides and greater than the difference between these lengths.
2s is not less than 1/2s+ 2/3s
What is a triangle?A triangle is polygon with the three edges and three vertices. It is one of the basic shapes in the geometry. A triangle with the vertices A, B, and C is denoted Δ ABC.
In the Euclidean geometry, any three points, when the non-collinear, determine a unique triangle and simultaneously, a unique plane (i.e. two-dimensional Euclidean space). In the other words, there is the only one plane that contains that triangle, and every triangle is contained in some plane. If the entire geometry is only Euclidean plane, there is only one plane and all triangles are contained in it; however, in the higher-dimensional Euclidean spaces, this is no longer true. This article is about triangles in the Euclidean geometry, and in the particular, the Euclidean plane, except where otherwise noted.
new triangle perimeter is = 2s + 1/2s + 2/3s
This new triangle, however, cannot be created physically because
The length of each side is less than sum of the lengths of the other two sides and greater than the difference between these lengths.
2s is not less than 1/2s+ 2/3s
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2. A different pool had an area that is of the form
▢ × 102 + ▢ × 101 + 6
and that can be written in the form x3 ,
where x is a whole number.
A) Decide what your number could be.
B) What is the perfect square number that is closest to the number you chose? What would the side length of a square pool with that area be?
C) Estimate the side length of a square pool with the area you chose in part a).
The area of the pool given by the expression, ∆ × 102 + ∆ × 101 + 6, gives;
A) The whole number x = 33
B) The perfect square number closest to 33 is 36
The side length of a square pool with an area of 36 square units is 6 units
C) The side length of a square pool with the area chosen in part A is 33•√33
What is a mathematical expression?An expression is a mathematical statement which consists of 2 or more numbers and, or variables joined together by mathematical operators.
A) The given equations for the pool is presented as follows;
Area of the pool = ∆ × 102 + ∆ × 101 + 6
Area of the pool = x³
x = A whole number
Expressing the word problem mathematically gives;
∆ × 102 + ∆ × 101 + 6 = x³
203•∆ + 6 = x³
Which gives;
[tex] \displaystyle{ \triangle = \frac{ {x}^{3} - 6}{203} }[/tex]
Using a graphing calculator, when x = 33, we get;
[tex] \displaystyle{ \triangle = \frac{ {33}^{3} - 6}{203} = 177 }[/tex]
The value of the number is x = 33 and ∆ = 177
B) The perfect square that is closest to x = 33 is 36
The side length of a square pool with an area of 36 is √(36) = 6
C).The area of the pool chosen is 33³ = 35937
The side length of a square pool with an area of 35937 is √(35937) = 33•√(33)
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In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or
spend it on gum. The results are summarized in the table. Complete parts (a) through (c) below.
Using the probability concept, we have that:
a) The probability is of 0.244.
b) The probability is of 0.756.
c) A student given a $1 bill is more likely to have kept the money.
What is a probability?A probability is calculated as the number of desired outcomes in the experiment divided by the number of total outcomes in the experiment.
For item a, we have that out of 11 + 34 = 45 students who were given a $1 bill, 11 spent the money, hence the probability is given as follows:
p = 11/45 = 0.244.
For item b, we have that out of 11 + 34 = 45 students who were given a $1 bill, 34 kept the money, hence the probability is given as follows:
p = 34/45 = 0.756.
For item c, we have that a student given a $1 bill is more likely to have kept the money, as 0.756(kept) > 0.244(spent), which are the two probabilities we found in the previous items.
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An actor bought a pearl, diamond, and ruby necklace for his famous wife for $54,000. In 2011 this necklace was auctioned for $11,379,600. The auction price was what percent of the original purchase price?
This necklace sold at auction for $11,379,600 in 2011. The percentage of the initial purchase price was represented by the auction price is 2.1%.
Given that,
For $54,000, an actor purchased a pearl, diamond, and ruby necklace for his well-known wife. This necklace sold at auction for $11,379,600 in 2011.
We have to find what percentage of the initial purchase price was represented by the auction price.
Let us take the percentage as x%.
Necklace sold at auction=the percentage multiplied by the actual price
We get,
$11,379,600 =x%($54,000)
x%=$11,379,600/$54,000
x%=2.1%
Therefore, the percentage of the initial purchase price was represented by the auction price is 2.1%.
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3) Travis International has a one-time expense of $1.13 million that must be paid two years from today. The firm can earn 4.3 percent annually, compounded monthly, on its savings. How much must the firm save each month to fund this expense if the firm starts investing equal amounts each month starting at the end of this month?
A) $38,416.20
B) $45,172.02
C) $51,300.05
D) $47,411.08
E) $53,901.15
please help me to do this problem.
3 is dividing on the right, then it will multiply on the left
B is multiplying on the right, then it will divide on the left
[tex]\frac{V\cdot3}{B}=h[/tex]Taylor wants to use a scale factor of 12 to make a smaller drawing of the door image shown. Part of her work is shown. Finish her work to find the height and width of her scale drawing
the height and width of her scale drawing is respectively:
height = 1*1/2inch
width = 3/4 inch
what is dimension?Dimension are the measure of the size or distance of an object or region or space in one direction.
so, all we needs to do is multiply is dimension of the original door image by the scale factor , to get the height and width of the scale drawing.
height: 3 inch x 1/2 =3x1/2=3/2=1x1/2 inch
width: 1x 1/2 inch x 1/2 =3/2 x 1/2= 3x1/2x2=3/4 inch
hence , the height and width of the scale drawing is respectively= 1x 1/2 inch ,3/4 inch
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15) A sample of 4 different calculators IS randomly selected from a group
containing 46 that are defective and 26 that have no defects. What is the
probability that all four of the
calculators selected are defective? Round to four
decimal places.
A) 0.1021
B) 0.1586
C) 0.1666
D) 10.9154
Answer:
C) 0.1666
Step-by-step explanation:
The probability of selecting a calculator that is defective can be defined as: [tex]\frac{46}{46+26}[/tex]
The 46 in the numerator is the number of calculators that are defective in the group. The 46 + 26 represents the total amount of calculators since 46 are defective and 26 are not defective and assuming a calculator can only be defective or not defective then these are the total number of calculators in the group.
This gives you a probability of approximately: [tex]\frac{46}{72}[/tex] or approximately 0.638889
We can multiply independent events to find the combined probability of these events occurring. So we have to assume you put the calculator back into group after selecting one.
If this is the case we simply multiply 46/72 * 46/72 * 46/72 * 46/72 or (46/72)^4 to get an approximate probability of: 0.1666
For the function f(x)=4x+4,
find (a) f(x+h),
(b) f(x+h)−f(x), and
(c) f(x+h)−f(x) h.
(a) f(x+h)=?
Step-by-step explanation:
a)
[tex]f(x+h) = 4(x+h)+4[/tex]
[tex]f(x+h)=4x+4h+4[/tex]
b)
[tex]f(x+h)-f(x)=4x+4h+4-(4x+4)[/tex]
[tex]f(x+h)-f(x)=4x+4h+4-4x-4[/tex]
[tex]f(x+h)-f(x)=4h[/tex]
c)
[tex]f(x+h)-f(x)h=4x+4h+4-h(4x+4)[/tex]
[tex]f(x+h)-f(x)h=4x+4h+4-4hx+4h[/tex]
[tex]f(x+h)-f(x)h=-4hx+8h+4x+4[/tex]
Use the data in the following table, which lists drive-thru order accuracy at popular fast food chains. Assume that orders are randomly selected from those included in the table.
If one order is selected, find the probability of getting an order that is not accurate or is from Restaurant C. Are the events of selecting an order that is not accurate and selecting an order from Restaurant C disjoint events?
The probability is 0.334 and the events are not disjoint events
How to determine the probability?The table of values represents the given parameters
The probability to calculate is given as
The probability of getting an order that is not accurate or is from Restaurant C
This can be represented as
P(Not accurate or Restaurant C)
This is calculated as
P(Not accurate or Restaurant C) = [n(Not accurate) + n(Restaurant C) - (Not accurate and Restaurant C)]/Total
So, we have
P(Not accurate or Restaurant C) = (37 + 52 + 34 + 19 +237 + 34 - 34)/(330 + 276 + 237 + 150 + 37 + 52 + 34 + 19)
Evaluate the sum and the difference
P(Not accurate or Restaurant C) = 379/1135
Evaluate the quotient
P(Not accurate or Restaurant C) = 0.334
Lastly, the events of selecting an order that is not accurate and selecting an order from Restaurant C are not disjoint events
This is so because it is possible to select an order from restaurant C that is not accurate
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I’m struggling on question number 16, me and friend are getting VERY different answers and I would like to get a good grade in this class!
Solution:
Given a sphere of diameter, d, 2.5ft.
To find the volume, V, of the sphere, the formula to apply is
[tex]V=\frac{4}{3}\pi r^3[/tex]Where, the radius, r, is
[tex]\begin{gathered} r=\frac{d}{2}=\frac{2.5}{2}=1.25ft \\ r=1.25ft \end{gathered}[/tex]Substitute for r into the formula to find the volume of a sphere above
[tex]\begin{gathered} V=\frac{4}{3}\pi r^3 \\ V=\frac{4}{3}\times\pi\times1.25^3 \\ V=8.18123\text{ ft}^3 \\ V=8.2\text{ ft}^3\text{ \lparen nearest tenth\rparen} \end{gathered}[/tex]Hence, the volume, V, of the given sphere is 8.2 ft³ (the nearest tenth)
If a nonlinear system of equations contains one linear function that touches the quadratic function at its minimum, then the system has which of the following?
A. No solution
B. Infinitely many solutions
C. One solution
D. Two solutions
Answer:
C. One solution
Step-by-step explanation:
You want to know the number of solutions of a system of equation such that the graph of the linear function touches the graph of the quadratic function at its minimum.
SolutionsThe number of real solutions of the system of equations is equal to the number of points of intersection of their graphs. The problem statement tells you the graphs intersect at one point, so there is one solution.
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Additional comment
The linear function can only touch the minimum of a quadratic if its graph is a horizontal line.
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