find the number degree of freedom, Critical value X², X² Given 95% confidence; n = 25, s = 0.24 Degree of freedom, df = 24 Critical value: X= [Select] X²= [Select] [Select] 39.364 32.852 12.401

Answer:

B

Step-by-step explanation:

I did it on khan academy

Answer:

(x+2)^2 + (y+2)^2 = 0.75^2

Step-by-step explanation:

equation of a circle in standard form: (x-h)^2 + (y-k)^2 = r^2

center: (-2, -2)

radius: 0.75

equation of the circle in provided graph: (x+2)^2 + (y+2)^2 = 0.75^2

Answer:

20 inches

Step-by-step explanation:

Since the cape is trapezoid shaped and has an area of 600 in², the area of a trapezoid is given by

A =1/2(a + b)h where a = length along the top of the cape = 24 in, b =  length along the bottom of the cape = 36 in and h = height of the cape

So, h = 2A/(a + b)

= 2 × 600 in²/(24 in + 36 in)

= 1200 in²/60 in

= 20 in

So, the height of the cape is 20 inches

Answer:

if you round of. 20 the answer is 10

Answer:

4mph

Step-by-step explanation:

The system of linear differential equations is given as y₁' = 3y₁ + 3y₂² and y₂' = 2y₁ + t*y₂ - 4. By comparing it with the general form y' = P(t)y + g(t), we determine that P(t) = [[3, 3y₂²], [2, t]] and g(t) = [0, -4].

To determine the coefficient matrix P(t) and the forcing term g(t), we can compare the given system of linear differential equations with the general form y' = P(t)y + g(t).

The given system is:

y₁' = 3y₁ + 3y₂²

y₂' = 2y₁ + t*y₂ - 4

Comparing the first equation with the general form, we have:

P₁₁ = 3

P₁₂ = 3y₂²

g₁(t) = 0

Comparing the second equation with the general form, we have:

P₂₁ = 2

P₂₂ = t

g₂(t) = -4

Therefore, the coefficient matrix P(t) and the forcing term g(t) for the given system are:

P(t) = [[3, 3y₂²], [2, t]]

g(t) = [0, -4]

Note that the value of y₂ is not provided in the equation for g₂(t), so it remains as y₂ in the expression.

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Answer:

They will each get 9 pieces of candy.

Step-by-step explanation:

if she has 4 friends and she shares with them, she would be sharing  with 4 people plus herself, so you would do the problem 45 ÷ 5 = 9.

The probability that the bottle contains between 12.19 and 12.25 ounces is 0.1525.

Given, mean (μ) = 12.29 ounces and standard deviation (σ) = 0.04 ounce.

We need to find the probability that the bottle contains between 12. 19 and 12.25 ounces.

So, let X be the amount of beer filled by the machine. Then, X ~ N(12.29, 0.04²)

Let Z be the standard normal random variable.

Then, Z = `(X - μ)/σ`

Substituting the values, we get,Z = `(X - 12.29)/0.04`

For X = 12.19, `Z = (12.19 - 12.29)/0.04 = -2.5`

For X = 12.25, `Z = (12.25 - 12.29)/0.04 = -1

`Now we need to find the probability of Z being between -2.5 and -1.P(Z lies between -2.5 and -1) = P(-2.5 < Z < -1)

We know that P(Z < -1) = 0.1587 and P(Z < -2.5) = 0.0062

From standard normal distribution table, we get

P(-2.5 < Z < -1)

= P(Z < -1) - P(Z < -2.5)P(-2.5 < Z < -1)

= 0.1587 - 0.0062 = 0.1525

Therefore, the probability that the bottle contains between 12.19 and 12.25 ounces is 0.1525.

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Given:

The vertices of a triangle are A(-1,-1), B(-1,-5), C(0.5,-5).

The figure is translated 2 units left.

To find:

The vertices and the diagram of the triangle after the given translation.

Solution:

if a figure is translated 2 units left, then

[tex](x,y)\to (x-2,y)[/tex]

Using the above rule, we get

[tex]A(-1,-1)\to A'(-1-2,-1)[/tex]

[tex]A(-1,-1)\to A'(-3,-1)[/tex]

Similarly,

[tex]B(-1,-5)\to B'(-1-2,-5)[/tex]

[tex]B(-1,-5)\to B'(-3,-5)[/tex]

And,

[tex]C(0.5, -5)\to C'(0.5-2,-5)[/tex]

[tex]C(0.5, -5)\to C'(-1.5,-5)[/tex]

So, the vertices of the triangle after the translation are A'(-3,-1), B'(-3,-5), C'(-1.5,-5).

Therefore, the correct option is B.

Answer:

B

Step-by-step explanation:

Answer:

the complementary angle is 14°

the supplementary angle is 104°

Step-by-step explanation:

76+14=90

76+104=180

The linear transformation T: R^2 → R^2, defined by T(v) = Av, where A = [[-2, -2], [1, 2]], maps a two-dimensional vector space onto itself. The dimension of R^2 is 2.

In the given linear transformation T: R^2 → R^2, the transformation is defined as T(v) = Av, where A is the transformation matrix. The given matrix A = [[-2, -2], [1, 2]] represents the coefficients of the linear transformation. This means that the transformation T takes a two-dimensional vector v in R^2 and applies the matrix A to it.

The dimension of R^2 is 2, indicating that the vector space R^2 consists of all ordered pairs (x, y) where x and y are real numbers. In this case, the linear transformation T maps a vector in R^2 to another vector in R^2, so both the input and output dimensions are 2.

The dimension of R^n refers to the number of components or variables in a vector in R^n. For example, R^2 consists of vectors with two components, while R^3 consists of vectors with three components. In this case, the dimension of R^2 is 2 because each vector in R^2 has two components.

To summarize, the given linear transformation T: R^2 → R^2, with the matrix A = [[-2, -2], [1, 2]], maps a two-dimensional vector space onto itself. The dimensions of both R^2 and R^2 are 2, representing the number of components in the vectors of each space.

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Answer:

She would have ran 8 laps.

Step-by-step explanation:

4/4 = 1 mile so therefore she would need 8/8 for it to be 2 miles

Area of circle = pi × r squared

A= 3.14....× (1.5×1.5)

A= 7.068583471

A= 7.07in( to nearest hundredth)

To minimize the annual holding and setup costs of purchasing bathroom tissue, you should buy single rolls of bathroom tissue. Purchasing the bathroom tissue in 12-packs is not more economical in this scenario.

To determine the optimal choice between buying single rolls and 12-packs of bathroom tissue, we need to consider the annual holding and setup costs.

a. To minimize the annual holding and setup costs, we need to compare the costs of buying single rolls versus 12-packs.

For single rolls:

Cost per roll = $0.45

Holding cost per roll per year = opportunity cost of money * cost per roll = 0.25 * $0.45 = $0.1125

Setup cost per purchase = $1

Consumption rate = 1 roll every 3 months = 4 rolls per year

For 12-packs:

Cost per pack = $5

Number of rolls in a 12-pack = 12

Holding cost per roll per year = 0.25 * ($5 / 12) = $0.1042

Setup cost per purchase = $1

To minimize the annual holding and setup costs, we need to compare the costs of purchasing the required number of single rolls and the cost of purchasing 12-packs.

b. Comparing the costs, it is more economical to purchase single rolls because the holding cost per roll per year is lower for single rolls ($0.1125) compared to 12-packs ($0.1042). Additionally, the setup cost is the same for both options ($1).

Therefore, to minimize the annual holding and setup costs, you should buy single rolls of bathroom tissue rather than 12-packs.

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The required answer is  based on the given data, we do not have sufficient evidence to support the claim that less than 10 percent of the test results are wrong at a 0.05 significance level.

To test the claim that less than 10 percent of the test results are wrong, use a hypothesis test with a significance level of 0.05. Let's define the null and alternative hypotheses:

Null Hypothesis (H0): The proportion of wrong test results is 10 percent or more.

Alternative Hypothesis (Ha): The proportion of wrong test results is less than 10 percent.

Use the binomial distribution to analyze the data. Let p be the true proportion of wrong test results. Since we want to test that the proportion is less than 10 percent, set p = 0.10 for the null hypothesis.

Given that 29 out of 308 tested subjects had wrong test results,  calculate the sample proportion, denoted by p^, as follows:

p^ = 29 / 308 = 0.094

To conduct the hypothesis test, we can use the z-test for proportions. The test statistic is calculated as:

z = (p^ - p) / [tex]\sqrt{}[/tex]((p x (1 - p)) / n)

In this case, since we are testing whether the proportion is less than 10 percent, calculate a one-tailed z-test.

Substituting the values into the formula:

z = (0.094 - 0.10) / [tex]\sqrt{}[/tex]((0.10 x (1 - 0.10)) / 308)

Simplifying the expression:

z = -0.006 /[tex]\sqrt{}[/tex] (0.09 / 308)

z ≈ -0.006 / 0.017

Calculating the z-value:

z ≈ -0.353

To determine the critical value for a one-tailed test at a significance level of 0.05, we can consult the z-table or use statistical software. For a significance level of 0.05, the critical z-value is approximately -1.645 (since we are testing for less than 10 percent, in the left tail).

Since the calculated z-value (-0.353) is greater than the critical z-value (-1.645), we fail to reject the null hypothesis. There is not enough evidence to conclude that the proportion of wrong test results is less than 10 percent.

Therefore, based on the given data, we do not have sufficient evidence to support the claim that less than 10 percent of the test results are wrong at a 0.05 significance level.

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Answer:

Is this high school math or middle school?.

Step-by-step explanation:

a²+b² = c²

8²+2²

↓    ↓

64+4

   ↓

square root 68 and it should give you 8.24 and then you round.

You have been investing money in this account for approximately 15 years.

To determine the number of years you have been investing money in the account, we can use the formula for the future value of an ordinary annuity:

FV = P * [(1 + r)ⁿ- 1] / r

Where:

FV = Future value (final balance in the account) = $461,103.46

P = Annual deposit amount = $8,500

r = Annual interest rate = 3.8% or 0.038 (expressed as a decimal)

n = Number of years

By substituting the given values into the formula and solving for n, we can determine the number of years you have been investing:

$461,103.46 = $8,500 * [(1 + 0.038) ⁿ- 1] / 0.038

54.24 = (1.038 ⁿ - 1) / 0.038

To solve for n, we can rearrange the equation:

1.038  ⁿ- 1 = 54.24 * 0.038

1.038  ⁿ= 2.0632

n = log base 1.038 of 2.0632

Using a logarithmic calculator, we find that n ≈ 14.96. Rounding up, we conclude that you have been investing money in this account for approximately 15 years.

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Answer:

33

Step-by-step explanation:

well we know you have a right angle and a right angle is equivalent to 90 degrees and you also have angle 57 now we know a triangle is equal to 180 so take 90+57=180 add the 90 and 57 then subtract the anwser from 180

Answer:

∠ H = 59°

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

121° is an exterior angle of the triangle, then

6x - 1 + 5x + 12 = 121 , that is

11x + 11 = 121 ( subtract 11 from both sides )

11x = 110 ( divide both sides by 11 )

x = 10

Then

∠ H = 6x - 1 = 6(10) - 1 = 60 - 1 = 59°

Let's assume the height of the TV set is h inches.

a. The height of the TV set is h inches.

Given that the length is 21 inches more than the height, the length can be represented as h + 21 inches.

b. The length of the TV set is h + 21 inches.

According to the given information, the diagonal of the TV set is 39 inches. We can use the Pythagorean theorem to relate the height, length, and diagonal:

(diagonal)^2 = (height)^2 + (length)^2

Substituting the values, we have:

39^2 = h^2 + (h + 21)^2

Expanding and simplifying:

1521 = h^2 + h^2 + 42h + 441

2h^2 + 42h + 441 - 1521 = 0

2h^2 + 42h - 1080 = 0

Dividing the equation by 2 to simplify:

h^2 + 21h - 540 = 0

We can solve this quadratic equation by factoring or using the quadratic formula. Factoring gives us:

(h - 15)(h + 36) = 0

So h = 15 or h = -36.

Since the height of the TV set cannot be negative, we discard h = -36.

Therefore, the height of the TV set is 15 inches.

Substituting this value back into the length equation, we have:

Length = h + 21 = 15 + 21 = 36 inches.

So, the dimensions of the TV set are:

a. The height of the TV set is 15 inches.

b. The length of the TV set is 36 inches.

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Answer:

C?

Step-by-step explanation:

Mean of the sampling distribution (wx): $900

Standard error of the mean (σx): Approximately $32.92

To find the mean and standard error of the mean of the sampling distribution, we can use the Central Limit Theorem.

The Central Limit Theorem states that for a large enough sample size, the sampling distribution of the sample means will be approximately normally distributed, regardless of the shape of the population distribution.

In this case, the population mean is μ = $900 and the population standard deviation is σ = $180. We are drawing random samples of size n = 30 from this population.

The mean of the sampling distribution (wx) will be equal to the population mean (μ), which is $900.

The standard deviation of the sampling distribution (σx), also known as the standard error of the mean, can be calculated using the formula:

σx = σ / √n

where σ is the population standard deviation and n is the sample size.

Substituting the given values, we have:

σx = $180 / √30

Calculating this value, we find:

σx ≈ $32.92

Therefore, the mean of the sampling distribution (wx) is $900, and the standard error of the mean (σx) is approximately $32.92.

Please note that the Central Limit Theorem assumes a sufficiently large sample size (typically n ≥ 30) for the approximation to hold.

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Given that, height of the right-angled triangle = 4m. Width of the right-angled triangle = 1m. Let's assume that the rectangular enclosure will be built at the base of the right-angled triangle. The area of the rectangular enclosure can be obtained using the formula, Area of rectangle = length × breadth. Length of the rectangle = height of the right-angled triangle = 4mLet the breadth of the rectangle be x, then the length is the width of the right-angled triangle + x = 1 + x Hence, the area of the rectangular enclosure is given by: Area = Length × Breadth= (1+x)×4= 4x + 4m²Now, the maximum area can be obtained by differentiating the above expression with respect to x and equating it to zero: dA/dx = 4 = 0x = -1. This is not a valid solution since we cannot have a negative breadth, hence we conclude that the area is maximum when the breadth of the rectangular enclosure is equal to the width of the right-angled triangle, i.e., when x = 1m. Thus, Area of the rectangular enclosure = Length × Breadth= (1+1)×4= 8 m². Hence, the largest the area of Gottfried’s enclosure can be is 8 m².

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Answer:

5! HOPE I HELPED

Step-by-step explanation:

Answer:

Z=[tex]7\sqrt{2}[/tex] m

Step-by-step explanation:

This is a 45º-45º-90º triangle. That means the side lengths are x, x, and [tex]x\sqrt{2}[/tex].

In this case 14 m is equal to [tex]x\sqrt{2}[/tex]. Now solve for X, which is equal to Z.

The rest of the work is written down in the file attached

Don't forget the units though!

hope I could help

Answer:

SECTION C (i think)

Please mark as brainliest

Have a great day, be safe and healthy  

Thank u  

XD

Answer:

section c

it's square root is 4.123......

Answer:

Perimeter of pizza slice = 27.85 inches (Approx.)

Step-by-step explanation:

Given:

Diameter of pizza = 20 inches

So,

Radius of pizza slice = Diameter of pizza / 2

Radius of pizza slice = 20 / 2 = 10 inches

∠IPZ = 45°

Find:

Perimeter of pizza slice

Computation:

Perimeter of pizza slice = 2[Radius of pizza slice] + [θ/360][2πr]

Perimeter of pizza slice = 2[10] + [45/360][(2)(22/7)(10)]

Perimeter of pizza slice = 20 + [0.125][(2)(3.14)(10)]

Perimeter of pizza slice = 20 + [0.125][62.8]

Perimeter of pizza slice = 20 + 7.85

Perimeter of pizza slice = 27.85 inches (Approx.)

The perimeter of the slice of the pizza that is eaten, measured in inches, for the considered case, is 31.9635 inches.

[tex]2\pi^c = 360^\circ = \text{Full circumference}[/tex]

The superscript 'c' shows angle measured is in radians.

If radius of the circle is of r units, then:

[tex]1^c \: \rm covers \: \dfrac{circumference}{2\pi} = \dfrac{2\pi r}{2\pi} = r\\\\or\\\\\theta^c \: covers \:\:\: r \times \theta \: \rm \text{units of arc}[/tex]

For this case, we're given that:

Not using the above formula, but the concept, we know that:

Since diameter of pizza = 20 inches, its radius r = 10 inches.

Thus, the length of the arc IZ = [tex]\dfrac{2 \times \pi \times 10}{8} \approx 1.9635 \: \rm inches.[/tex]

Perimeter of the slice of the pizza eaten = sum of the length of its boundaries = Length of arc IZ + length of line IP + length of line ZP

Since line IP and ZP are radius, thus:

Perimeter of the slice of the pizza eaten ≈ 1.9635 + 10 + 10 = 31.9635 inches.

Thus, the perimeter of the slice of the pizza that is eaten, measured in inches, for the considered case, is 31.9635 inches.

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Answer:

total surface area (TSA) = [tex]2bs[/tex] + [tex]b^{2}[/tex]

                      length      = 6 mi

                    slant height = 7 mi

           ∴ TSA                   = 2 × 6 × 7 + [tex]6^{2}[/tex]

                                       = 84 + 36

                                      = 120

The surface area of the square pyramid is 120 sq. mi.

Given:

side length (s) = 6 mi

slant height (l) = 7 mi

*image of a typical square pyramid is shown in the attachment below.

Recall:

Formula for surface area of square pyramid (SA) = [tex]A + \frac{1}{2} Pl[/tex]

Where,

[tex]A =[/tex] area of the base = [tex]s^2 = 6^2 = 36[/tex] sq mi

[tex]P =[/tex] perimeter of the base = [tex]4(s) = 4\times 6 = 24[/tex] mi

[tex]l =[/tex] slant height = 7 mi

Plug in the values

[tex]SA = 36 + \frac{1}{2}\times 24\times 7\\SA = 36 +84\\SA = 120[/tex]

The surface area(SA) of the square pyramid is 120 sq. mi

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