Find the scale factor of quad JKLM to quad ABCD

Answer:

Step-by-step explanation:

Answer:

Yeah me too buddy :(

Step-by-step explanation:

Answer:

[tex]\frac{2}{3} * \frac{4}{5} = \frac{6}{15}[/tex]

Step-by-step explanation:

Given

[tex]\frac{2}{3} * \frac{4}{5} =[/tex]

The number line is missing from the question.

So, I will answer the question and also draw the number line to show the product.

[tex]\frac{2}{3} * \frac{4}{5} =[/tex]

[tex]\frac{2}{3} * \frac{4}{5} = \frac{6}{15}[/tex]

To represent this on a number line;

We draw a number line of 15 points, and place a dot on the 6th point.

This represents 6/15

See attachment

Answer:

[tex](x+1)(17a-1)[/tex]

Step-by-step explanation:

We are given that

[tex]17ax+17a-x-1[/tex]

We have to factorize the given expression.

Pair up the terms

[tex](17ax+17a)+(-x-1)[/tex]

Now, taking common factor

[tex]17a(x+1)-1(x+1)[/tex]

Taking common (x+1)

[tex](x+1)(17a-1)[/tex]

Now, we get

[tex](x+1)(17a-1)[/tex]

This is required factors of given expression.

Answer:

see explanation

Step-by-step explanation:

The volume (V) of the cuboid is calculated as

V = (2x + 5)(3 - x)(x + 1)

   = (3 - x)(2x + 5)(x + 1) ← expand the pair of factors using FOIL

    = (3 - x)(2x² + 7x + 5)

    = 3(2x² + 7x + 5) - x(2x² + 7x + 5) ← distribute parenthesis

    = 6x² + 21x + 15 - 2x³ -7x² - 5x ← collect like terms and rearrange

    = 15 + 16x - x² - 2x³

The volume of the cuboid is 15 + 16x - x² - 2x³

a three dimensional shape can be defined as a solid figure or an object or shape that has three dimensions—length, width, and height.

The volume (V) of the cuboid is calculated as

Volume of cuboid is length times width times height.

V = (2x + 5)(3 - x)(x + 1)

= (3 - x)(2x + 5)(x + 1)

Expand the pair of factors using FOIL

= (3 - x)(2x² + 7x + 5)

= 3(2x² + 7x + 5) - x(2x² + 7x + 5) ←

Distribute parenthesis

= 6x² + 21x + 15 - 2x³ -7x² - 5x

Combine like terms and rearrange

= 15 + 16x - x² - 2x³

Hence, the volume of the cuboid is 15 + 16x - x² - 2x³

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Answer:

can i see the rest of the problem...

Step-by-step explanation:

Answer:

Hey Mate!

tis is ur answrr!

Option (b) 1.00

Step-by-step explanation:

3.4×1.00 = 3.4

Answer:

1.00

Step-by-step explanation:

1.00 equals one therefore the actual equation is 3.4x 1 = 3.4

Or 3.4x1.00=3.4

Hope this helps.

Answer:

2.4 per pound

Step-by-step explanation:

36÷15=2.4

how do i know this i used my brain

Answer:

[tex]f_{ave}[/tex] = [tex]{\frac{10 }{3\pi }[/tex]

Step-by-step explanation:

To find - Find the average value fave of the function f on the given interval. f(x) = 5 sec²(x/6), [0, 3[tex]\pi[/tex]/2]

Proof -

We know that,

Average value of f in the interval [a, b] is -

[tex]f_{ave}[/tex] = [tex]\frac{1}{b - a}\int\limits^b_a {f(x)} \, dx[/tex]

Now,

Here a = 0, b = [tex]\frac{3\pi }{2}[/tex], f(x) = [tex]5sec^{2}(\frac{x}{6} )[/tex]

Now,

[tex]f_{ave}[/tex] = [tex]\frac{1}{\frac{3\pi }{2} - 0}\int\limits^{\frac{3\pi }{2} }_0 {5sec^2 ({\frac{x}{6} }) } \, dx[/tex]

      = [tex]{\frac{2 }{3\pi }}\int\limits^{\frac{3\pi }{2} }_0 {5sec^2 ({\frac{x}{6} }) } \, dx[/tex]

      = [tex]{\frac{10 }{3\pi }}\int\limits^{\frac{3\pi }{2} }_0 {sec^2 ({\frac{x}{6} }) } \, dx[/tex]

      = [tex]{\frac{10 }{3\pi }}[\ {tan({\frac{x}{6} }) }|^{\frac{3\pi }{2} }_0 \, ][/tex]

      = [tex]{\frac{10 }{3\pi }}[\ {tan({\frac{x}{6} }) - tan({0) } \, ][/tex]

      = [tex]{\frac{10 }{3\pi }}[ {1 - 0 } ][/tex]

      = [tex]{\frac{10 }{3\pi }[/tex]

⇒[tex]f_{ave}[/tex] = [tex]{\frac{10 }{3\pi }[/tex]

Answer:

1,440 calories

Step-by-step explanation:

Divide 640 by 4 to get how many calories there are per scoop.

640 calories ÷ 4 scoops = 160 calories per scoop

Then, we can multiple 160 by 9 to get the calories in 9 scoops.

160 calories per scoop × 9 scoops = 1,440 calories per 9 scoops

Answer:

1,440‬

Step-by-step explanation:

Answer

62

Step-by-step explanation:

Answer:

Options (1), (3) and (5)

Step-by-step explanation:

Coordinates of D → (2, 2)

Coordinates of E → (1, 6)

Coordinates of F → (5, 7)

Coordinates of G → (6, 3)

Length of ED = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

                      = [tex]\sqrt{(2-1)^2+(2-6)^2}[/tex]

                      = [tex]\sqrt{17}[/tex]

Length of FG = [tex]\sqrt{(5-6)^2+(7-3)^2}[/tex]

                      = [tex]\sqrt{17}[/tex]

Length of GD = [tex]\sqrt{6-2)^2+(3-2)^2}[/tex]

                       = [tex]\sqrt{17}[/tex]

Length of EF = [tex]\sqrt{(1-5)^2+(6-7)^2}[/tex]

                     = [tex]=\sqrt{17}[/tex]

Since, all sides of the given quadrilateral are equal in length, quadrilateral will be a square.

Therefore, diagonals EG and DF will be perpendicular, equal in measure, congruent and will bisect each other.

Options (1), (3) and (5) are the correct options.

Answer:

Since the exponent of the scientific notation is positive, move the decimal point 66 places to the right.

4000000

The expression 4 x [tex]10^6[/tex] in decimal notation is 4,000,000.

We have,

In scientific notation, a number is expressed as a product of a decimal number and a power of 10.

In the given expression, 4 x [tex]10^6[/tex], the base number is 4, and it is multiplied by 10 raised to the power of 6.

To convert this into decimal notation, we need to multiply the base number (4) by the power of 10 ([tex]10^6[/tex]), which means moving the decimal point six places to the right.

Starting with 4, we move the decimal point six places to the right, resulting in 4,000,000.

Thus,

The expression 4 x [tex]10^6[/tex] in decimal notation is 4,000,000.

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Answer:

4x + 18

Step-by-step explanation:

This is called a composite function, meaning passing the range of one function as a domain of another function.

For f(f(x)), the inner-function's range is passed as the domain of the outer function.

We can do so by substitution,

The range of f(x) can be written as 2x + 6 for any defined x values,

So we will substitute 2x  + 6 as the 'x' of another function which is in this case

f(x) again, so it looks like this 2(2x+6) + 6 which can be simplified into

4x + 18

Answer: 88

The unknown angle in the left triangle is 80 since the sum of the angles in a triangle is 180.(180-60-40=80)

The unknown angle (the one that doesn't have a "?") is 36 since there's a straight angle which equals 180.(180-80-64)

Therefore the angle with the "?" is 88 since the sum of the angles in a triangle are 180(180-36-56)

Hope this helps!

Answer:

square root of (2+10)²+(-5+3)²

square root of 144+4

square root of 148

Answer:

9.8 in²

Step-by-step explanation:

If A, B and C are the angles of a triangle and a, b, c are the repective sides opposite the angles, then the area of the triangle is given as:

Area = (1/2)absin(C)

In ΔQRS, the area is:

Area = (1/2)rqsin(S)

∠S + ∠Q + ∠R = 180° (sum of angles in a triangle)

∠S + 40 + 101 = 180

∠S = 39°

Using sine rule to find q:

[tex]\frac{q}{sinQ} =\frac{r}{sinR} \\\\\frac{q}{sin40}=\frac{6.9}{sin101} \\\\q=\frac{6.9*sin40}{sin101} =4.52 \ inches\\\\Area\ of\ triangle \ QRS=\frac{1}{2}rqsin(S) =\frac{1}{2}*6.9*4.52*sin(39)=9.8\ in^2[/tex]

You're gonna get caught anyways, just come out. If you don't, figure out a way to undo it.

Answer:

d

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

a) 55 > 48 > 27 > 12 > 0 ×

b) 62 > 40 > 9 > 3 < 25 ×

c) 1 < 8 < 13 < 29 < 42 ✓

d) 15 < 34 > 0 < 7 < 28 ×

Answer:

x = 3

y = 0

Step-by-step explanation:

4(3) + 7(0) = 12

-8(3) - 14(0) = -24

Answer:

$1.00

Step-by-step explanation:

5 (0.05) (4)= $1.00

hope this helps

Answer:

circle

Step-by-step explanation:

Answer:

Step-by-step explanation:

This probability will be the area of the square divided by the area of the circle.

[tex]P=\frac{(4\sqrt{2})^2}{\pi 4^2}\\ \\ P=\frac{32}{16\pi}\\ \\ P=\frac{2}{\pi }\\ \\ \text{As a percentage}\\ \\ P=\frac{200}{\pi}\\ \\ P\approx 63.7\% [/tex]

Answer:

The slope is 1/2. The x-intercept is (2,0). The y-intercept is (0,-1)

Answer:

The slope is 1/2x and -1 is the (y) intercept

Step-by-step explanation:

m is the slope and b is the intercept

Assume 1 small bub side = 2cm

area = 2 × 2

= 4 cm²

total area of small bub

4 × 4 = 16cm²

area of big bub = total area of small bub

= 16cm²

one side of big bub

16 ÷ 4 = 4

1 small bub side : 1 big bub side

2 : 4

1 : 2

the side length of the large square is 2 times bigger than the side length of one small square.