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Which summation formula is equivalent to the one below?​

Answer:

The second summation, counting from the top.

Step-by-step explanation:

Remember the relation:

[tex]a^{-n} = \frac{1}{a^n}[/tex]

The first summation is:

4*(  (-1/2)^0 + (-1/2)^1 +  (-1/2)^2 + (-1/2)^3)

4*( 1 - 1/2 + 1/4 - 1/8) = 2.5

Now let's analyze the options.

Let's look at option A, here we only have 2 to different powers, so we never can have a summation equal to 2.5, then we can discard that option.

Let's look at the next one (B), it will be equal to:

= (1/4)*( (-2)^4 + (-2)^3 + (-2)^2 + (-2)^1) =

= (1/4)*( 16 - 8 + 4 - 2) = 2.5

Then this summation is the one equivalent to the first one.

Answer:

B

Step-by-step explanation:

edg 2021

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