Hard corals have a symbiotic relationship with species of microalgae that give the corals their color and provide up to 95% of the corals' energy needs by photosynthesis. Corals get the rest of their food by consuming plankton. The microalgae are damaged by changes in water temperature 2-3C lasting five weeks or more, causing a phenomenon called coral bleaching. What will most likely be the result of increased global temperature on the diversity of hard coral species?
Question 1 options:
The hard corals will make all of their own food.
The rate of photosynthesis in hard corals will increase.
The number of different hard coral species will decrease.
The hard corals will migrate to warmer waters.
Answers
Answer:
The hard corals will make all of their own food
Explanation:
your welcome...
The most likely result with increased global temperature would be ; ( A )
The hard corals will make their own food
Given that the relationship between the corals and the microalgae is symbiotic and not parasitic therefore when the microalgae are damaged the hard corals will most likely look for an alternative food source in order to continue surviving since they do not rely 100% on the plankton for their food. which is The hard corals will be able to make their own food by capturing preys like critters.
Hence we can conclude that the most likely result with increased global temperature would be The hard corals will make their own food
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A: flower,pine tree,or cactus
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12. A
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Please answer fast ASAP I give brainliest
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Explanation: In the open water zone (or photic zone) sunlight supports photosynthetic algae and the species that feed upon them. In the deep water zone, sunlight is not available and the food web is based on detritus entering from the littoral and photic zones.
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1. This question may be completed independently or as a group exercise. Biological anthropologists disagree about the best way to classify the robust australopithecines. Describe the two approaches to classifying these species. Which classification do you support
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Answer:
Some researchers classify Australopithecines into gracile australopithecines and robust australopithecines, while others argue that differences are enough strong to classify robust australopithecines in their own genus called 'Paranthropus'. In my opinion, it seems reasonable to obtain more fossil data in order to support this division
Explanation:
The term Australopithecines comes from the genus Australopithecus, which are the closest known relatives of our genus Homo, and arose around three (3) million years ago. Australopithecines can be classified into two major groups called gracile australopithecines and robust australopithecines. However, robust australopithecines have also been classified in their own genus, Paranthropus, in order to distinguish them from the gracile australopithecines. The major differences between gracile and robust species are associated with facial and cranial features. Paranthropus species had a large sagittal crest, enormous cheek teeth, robust jaws, and strong jaw muscles (suggesting they were herbivores that ate tough food). However, these main features may not be conclusive evidence that supports the separation of Paranthropus in its own clade, thereby in my opinion it should be reasonable to wait until more fossils are found in order to correctly classify Paranthropus species as a different group.
Which of the following explains the conservation of mass during cellular respiration? (4 points) a The total number of atoms when carbon dioxide and oxygen react stays the same when glucose and water are produced. b The total number of atoms when water and oxygen react stays the same when glucose and water are produced. c The total number of atoms when carbon dioxide and water react stays the same when glucose and oxygen are produced. d The total number of atoms when glucose and oxygen react stays the same when carbon dioxide and water are produced.
Answers
Answer:
D- The total number of atoms when glucose and oxygen react stays the same when carbon dioxide and water are produced.
Explanation:
The conservation of mass during cellular respiration can be explained by the fact that after cellular respiration which occurs due to the oxidation of glucose to produce carbon dioxide and water, the number of atoms on the right hand side (RHS) of the reaction remain same as of left hand side (LHS) of the reaction.
The balanced chemical equation is mentioned as under:
C₆H₁₂O₆ + 6 O₂ -> 6 CO₂ + 6H₂O + Energy.
(Glucose) (Oxygen) (Carbon (Water)
dioxide)
If we will see carefully, the number of atoms of each element on RHS & LHS of the equation are same i.e. there are 6 atoms of C, 18 atoms of O and 12 atoms of H on both the sides.
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In order to go through Mitosis, DNA is packaged into structures known as what.
a
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b
Chromosomes
c
Double Helix strands
d
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Answers
Answer:
b:chromosomes
Explanation:
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CURRENTLY ON A POST TEST: 50 POINTS
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C. reduce public transport facilities
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E. implement standards on the smoke emissions from factories
this is supposed to be environmental science, but there isnt even an option for science so im going to put it as Biology
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Answer:
For more than forty-five years the Clean Air Act has cut pollution as the U.S. ... New cars, trucks, and nonroad engines use state-of-the-art emission control technologies. ... EPA has taken initial steps to limit emissions that cause climate change and ... This progress reflects efforts by state, local and tribal governments; EPA; ...
Explanation:
Answer:
E. implement standards on the smoke emissions from factories
Explanation:
I hope this helps you! ☺️
I’ll give extra points for who ever does this
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pleaaaseeee helpp meeeeeee
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An adult hemopoietic stem cell found in the bone marrow ______________________. (a) will occasionally produce epidermal cells when necessary. (b) can produce only red blood cells. (c) can undergo self-renewing divisions for the lifetime of a healthy animal. (d) will express all the same transcription factors as those found in an unfertilized egg.
Answers
Answer: (c) can undergo self-renewing divisions for the lifetime of a healthy animal.
Explanation:
The adult hematopoietic tissue or adult hematopoietic stem cells can be found in bone marrow of the animal. These cells have the ability to regenerate and renew so that the production of red blood cells remains continuous till death. Hematopoiesis can be defined as the production of cellular components of blood. The adult hematopoietic stem cells are located in the flat bones and ends of the long bones.
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C. The cell's surface area/volume ratio
D. The cell's DNA
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Answer:
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Answer:
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Explanation:
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Explanation:
Answer:
I say the answer nuclear energy!!
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Answer:
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Answer: A
explanation(from a website)
Stay calm. ...
Remove the stinger. ...
Wash the sting with soap and water.
Apply a cold pack to reduce swelling. ...
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Answer:
must be A
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first A as first aid
and then B
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Answer:
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Explanation:
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wetland
Explanation:
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EXPLAIN and I will make you brainliest!!!
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Answer:
All of the above
Explanation:
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Question 5
How do increases in the carrying capacity of Earth for people affect the carrying capacity of Earth for other species?
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Answer:
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Answers
Answer:
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In mouse, genes X, Y and Z are on chromosome 2. The map of genes X, Y and Z is:
X--------20mu--------Y---------------30mu---------Z.
You cross an individual with genotype XXYYZZ to an individual with genotype xxyyzz, and F1 progeny are collected. Assume interference between regions (X-Y and Y-Z) is 40%. You then perform a cross between an F1 individual and an individual with genotype xYz/xyz. Among 1000 progeny, how many of them will be of the genotype xxyyzz?
Answers
Answer:
36 individuals xxyyzz
Explanation:
Available data:
X-Y = 20MUY-Z = 30MUCross: XXYYZZ x xyyzzF1= XxYyZzI = 40%2nd Cross: XxYyZz x xxYyzzF2 = 1000 individualsWe need to know how many individuals from the F2 are going to be xxyyzz
xxyyzz genotype is the result of a double recombinant event.
First, we need to analyze the given information:
→ Distances between genes
The genetic distance result from multiplying the recombination frequency of each region by 100 and expressing it in map units (MU). So, if we have the genetic distance we can divide it by 100 and get the recombination frequency:
Let us say that region I is the distance between X and Y. And region II is the distance between Y and Z.
GD = genetic distance
RF = Recombination frequency
GD (X-Y) = RF x 10020MU = RF x 100
20MU/100 = RF
0.2 = RF (Region I)
GD (Y-Z) = RF x 10030MU = RF x 100
30MU/100 = RF
0.3 = RF (Region II)
Now we have the recombination frequency of Region I and Region II.
→ Interference
Knowing the interference value will let us know the value of the coefficient of coincidence, which will also lead us to the number of individuals xxyyzz.
I = 40%
I = 1 - CC ⇒ CC = coefficient of coincidence
Clearing this equation gives us the value of CC
CC = 1 - I
CC = 1 - 40% = 1 - 0.4
CC = 0.6
To calculate the coefficient of coincidence, CC, we can also use the next formula:
CC = observed double recombinant frequency/expected double recombinant frequency
Now, we are interested in knowing the value of the observed double recombinant frequency.
Note:
observed double recombinant frequency = total number of observed double recombinant individuals/total number of individuals expected double recombinant frequency = recombination frequency in region I x recombination frequency in region II.So, to get the value of the observed double recombinant frequency, first, we need to get the value of the expected double recombinant frequency. And we can do it because we already have the recombination frequencies in both regions.
expected double recombinant frequency = recombination frequency in region I x recombination frequency in region II
- Recombination Frequency - RI = 0.2
- Recombination Frequency - RII = 0.3
expected double recombinant frequency = 0.2 x 0.3
expected double recombinant frequency = 0.06 = EDRF
Now that we know the value of the CC and the expected DRF, we can get the observed double recombinant frequency.
CC = observed double recombinant frequency/expected double recombinant frequency
- CC = 0.6
- EDRF = 0.06
CC x expected double recombinant frequency = observed double recombinant frequency
0.6 x 0.06 = observed double recombinant frequency
0.036 = observed double recombinant frequency = ODRF
Finally, as this is a frequency, we need to multiply it by the total number of individuals in the F2 to get the number of observed double recombinant individuals.
- ODRF = 0.036
- N = 1000
Double recombinant individuals = 0.036 x 1000 = 36 individuals xxyyzz.