Heather drives her Super-Beetle around a turn on a circular track which has a radius of 200 m. The Super-Beetle has a mass of 1500 kg and the coefficient of static friction between the road and tires is 0.6.

a. What is the force of static friction the road can apply batore the car starts to selon (use Ft= uFn).
b. What is the maximum speed the car can travel before it would start to slide?

Answers

Answer 1

Answer:

a) The force of static friction the road can apply before the car starts to move is 8826.3 newtons.

b) The maximum speed that a car can travel before it would start to slide is approximately 34.305 meters per second.

Explanation:

a) Let suppose that the car is on a horizontal ground and travels at constant speed. The vehicle experiments a centripetal acceleration due to friction, which can be seen in the Free Body Diagram (please see image attached for further details). By Newton's Laws, we construct the following equations of equilibrium:

[tex]\Sigma F_{x} = \mu_{s}\cdot N = m\cdot \frac{v^{2}}{R}[/tex] (1)

[tex]\Sigma F_{y} = N -m\cdot g = 0[/tex] (2)

Where:

[tex]\mu_{s}[/tex] - Static coefficient of friction, dimensionless.

[tex]N[/tex] - Normal force from ground to the car, measured in newtons.

[tex]v[/tex] - Maximum speed of the car, measured in meters per second.

[tex]R[/tex] - Radius of the circular track, measured in meters.

[tex]m[/tex] - Mass, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

By applying (2) in (1):

[tex]\mu_{s}\cdot m\cdot g = m\cdot \frac{v^{2}}{R}[/tex] (3)

The force of static friction the road can apply in the car ([tex]f[/tex]), measured in newtons, is: ([tex]\mu_{s} = 0.6[/tex], [tex]m = 1500\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex])

[tex]f = \mu_{s}\cdot m \cdot g[/tex]

[tex]f = (0.6)\cdot (1500\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]

[tex]f = 8826.3\,N[/tex]

The force of static friction the road can apply before the car starts to move is 8826.3 newtons.

b) Then, we calculate the maximum speed of the car by (3):

[tex]\mu_{s}\cdot m\cdot g = m\cdot \frac{v^{2}}{R}[/tex]

[tex]\mu_{s}\cdot g = \frac{v^{2}}{R}[/tex]

[tex]v = \sqrt{\mu_{s}\cdot g\cdot R}[/tex]

If we know that [tex]\mu_{s} = 0.6[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]R = 200\,m[/tex], then the maximum speed of the car can travel before it would start to slide is:

[tex]v =\sqrt{(0.6)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (200\,m)}[/tex]

[tex]v \approx 34.305\,\frac{m}{s}[/tex]

The maximum speed that a car can travel before it would start to slide is approximately 34.305 meters per second.

Heather Drives Her Super-Beetle Around A Turn On A Circular Track Which Has A Radius Of 200 M. The Super-Beetle

Related Questions

describe measurement in our daily life​

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We’re all pretty active and do a lot

If an object has applied force of 20 N and a frictional force of 5 N what is the net force?

Answers

Answer:

Net force = 15 N

Explanation:

Given that,

Applied force on an object = 20 N

Frictional force = 5 N

We need to find the net force acting on the object.

Friction is an opposing force. It acts in the opposite direction.

Net force = Applied force - Frictional force

= 20 N - 5 N

= 15 N

Hence, the net force acting on the object is 15 N.

How is the Moon thought to have formed

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Omg I have the same question

a car moved 60 meters west in 2hours what is its average velocity​

Answers

Answer:

30 m/h

Explanation:

Have A Wonderful Day !!

the earth's moon has a gravitational field strength of about 1.6 n/kg near its surface. the moon has a mass of 7.35x10^22 kg. what is the radius of the moon? please show steps on how to do it please.​

Answers

Answer:

1750km

Explanation:

A ball rolling on the floor eventually comes to a stop. Which statement best describes this situation?

A) The energy on the macroscopic scale and the energy on the molecular scale both decreased.

B) The energy on the macroscopic scale increased, and the energy on the molecular scale decreased.

C) The energy on the macroscopic scale decreased, and the energy on the molecular scale increased.

D) The energy on the macroscopic scale and the energy on the molecular scale both remained constant.

If you have the rest please put them down :)

Answers

Answer:

Explanation:

C. The energy on the macroscopic scale decreased, and the energy on the molecular scale increased.

A. friction converts some energy on the macroscopic scale to energy on the molecular scale.

B. The mechanical energy of the system decreased because of friction.

B. The mechanical energy of the system at the beginning of the experiment is equal to the mechanical energy of the system at the end of the experiment.

B. the mechanical energy of the system decreased due to the transfer of energy on a macroscopic scale to energy on a molecular scale.

The  ball rolling on the floor eventually comes to a stop which means that

the energy on the macroscopic scale decreased, and the energy on the

molecular scale increased.

What is Macroscopic scale?

This is a scale in which an object can be seen with the eyes. When

an object is in motion, the ball rolls away and becomes less visible hence a

decrease in the macroscopic scale.

During motion, friction converts some macroscopic energy into molecular

scale which is why there was an increase in it.

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Two microwave signals of nearly equal wavelengths can gener- ate a beat frequency if both are directed onto the same microwave detector. In an experiment, the beat frequency is 100 MHz. One microwave generator is set to emit microwaves with a wavelength of 1.250 cm. If the second generator emits the longer wavelength, what is that wavelength

Answers

Answer:

the longer wavelength is 1.2552 cm

Explanation:

given that

beat frequency [tex]f_{b}[/tex] = 100 MHz = 100 × 10⁶ Hz

λ₁ = 1.250 cm = 0.0125 m

we know that beat frequency [tex]f_{b}[/tex] of two simultaneous frequencies f₁ and f₂ is expressed as;

[tex]f_{b}[/tex]  = | f₁ - f₂ |

we know that microwave travels at a speed of light, so for any electromagnetic wave traveling at speed of light c with wavelength λ; frequency is;

f = c / λ

hence our beat frequency [tex]f_{b}[/tex] becomes

[tex]f_{b}[/tex] = c ( 1/λ₁ - 1/λ₂)

to find the longer wavelength,  λ₂

[tex]f_{b}[/tex] = c ( 1/λ₁ - 1/λ₂)

divide both side by c

[tex]f_{b}[/tex] /c =  ( 1/λ₁ - 1/λ₂)

1/λ₂ = 1/λ₁ - [tex]f_{b}[/tex] /c

λ₂ =  [1/λ₁ - [tex]f_{b}[/tex] /c ]⁻¹

so we substitute in our values

we know that speed of light c = 3 × 10⁸

so

λ₂ =  [ (1/0.0125) - (100 × 10⁶ /3 × 10⁸) ]⁻¹

λ₂ =  [80 - 0.3333 ]⁻¹

λ₂ =  [79.6667 ]⁻¹

λ₂ =  0.01255 m

λ₂ =  0.012552 × 100 cm

λ₂ =  1.2552 cm

Therefore, the longer wavelength is 1.2552 cm

The most common complaint among patients about their doctors is the time spent waiting in the doctor's office. Patients claim that doctors overbook appointments. Doctors claim that a significant number of patients fail to show or are late for their appointments. Doctors also note that as medical professionals they must tend to anyone who has need of their service. The medical profession is also uncertain because doctors never know when an emergency will occur. Considering the economic concepts of scarcity and economic resources, why must doctors book as many patients as necessary during office hours?

A doctor has the time and resources to choose how many patients to treat

A doctor, by law, must treat every patient who shows up in a medical facility

A doctor must make as much money as possible during normal business hours

A doctor's time is scarce and must be used effectively to see the most patients​

Answers

Answer: B- a doctor, by law, must treat every patient who shows up in a medical facility

Explanation:

Each spring, a crevice in the cliff wall widens and deepens. What is the best explanation for how physical weathering causes the crevice to widen and deepen?
Winds deposit sand into the crevice.

Water freezes and expands in the crevice.

Snow melts and evaporates between the rocks in the crevice.

Air pollution in the area causes a reaction that widens the crevice.

Answers

Answer: water freezes and expands in the crevice

Explanation:

Answer:

Water freezes and expands in the crevice

Explanation:

what is the pressure on a swimmer 50 m below the surface of a lake​

Answers

Answer:

P = 490500 [Pa]

Explanation:

The pressure at the bottom of a vessel and even of a lake or sea can be calculated by means of the following hydrostatic equation.

[tex]P=Ro*g*h[/tex]

where:

P = pressure [Pa] (units of pascal)

Ro = water density = 1000 [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 50 [m]

Now replacing:

[tex]P=1000*9.81*50\\P=490500[Pa][/tex]

. What is the atomic number for calcium?

Answers

20 is the atomic number for Calcium.

Cecily is inflating her bicycle tyre with the pump below. When she pushes the plunger down, it is doing work against the gas. This means that the plunger is transferring what to the gas particles?

Answers

Energy is being transferred into the gas particles. Since temperature is also being increased due to the increased pressure. Temperature is a measure of the average kinetic energy of particles. Therefore energy transfers to the gas.

The plunger is transferring energy to the gas particles.

What the plunger is transferring to the gas particles?

When Cecily is applying pressure to the plunger, the gas inside is being compressed, and the speed of gas molecules increases.

When these air molecules enter the tire, adiabatically, the temperature of the gas rises.

It happens due to an increase in the average kinetic energy of the gas particles.

Thus, the gas particles receive energy from the plunger.

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discuss how devastating a 7.7 - magnitude earthquake is.

Answers

Answer:

Explanation:

It’s devastating because when a earthquake is 7.7 magnitude the

Because 163 is ur new home to go to the

In one type of Combustion reaction, _______ is combined with oxygen to create heat and light.

A) nitrogen
B) carbon
C) hydrogen

Answers

Answer:

carbon.

Explanation:

the reaction would then create c02 as a product

A student places an object with a mass of m on a disk at a position r from the center of the disk. The student starts rotating the disk. When the disk reaches a speed of 0.8 m/s, the object starts to slide off the disk. What is the coefficient of static friction between the object and the disk?
mass=100 g, r= 0.75 m​

Answers

Answer:

The coefficient of static friction between the object and the disk is 0.087.

Explanation:

According to the statement, the object on the disk experiments a centrifugal force due to static friction. From 2nd Newton's Law, we can represent the object by the following formula:

[tex]\Sigma F_{r} = \mu_{s}\cdot N = m\cdot \frac{v^{2}}{R}[/tex] (1)

[tex]\Sigma F_{y} = N - m\cdot g = 0[/tex] (2)

Where:

[tex]N[/tex] - Normal force from the ground on the object, measured in newtons.

[tex]m[/tex] - Mass of the object, measured in newtons.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]v[/tex] - Linear speed of rotation of the disk, measured in meters per second.

[tex]R[/tex] - Distance of the object from the center of the disk, measured in meters.

By applying (2) on (1), we obtain the following formula:

[tex]\mu_{s}\cdot m\cdot g = m\cdot \frac{v^{2}}{R}[/tex]

[tex]\mu_{s} = \frac{v^{2}}{g\cdot R}[/tex]

If we know that [tex]v = 0.8\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]R = 0.75\,m[/tex], then the coefficient of static friction between the object and the disk is:

[tex]\mu_{s} = \frac{\left(0.8\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.75\,m)}[/tex]

[tex]\mu_{s} = 0.087[/tex]

The coefficient of static friction between the object and the disk is 0.087.

Two point charges have a total electric potential energy of -24 J, and are separated by 29 cm.
If the total charge of the two charges is 45 μC, what is the charge, in μC, on the positive one?
What is the charge, in μC, on the negative one?

Answers

Answer:

The charge of the negative one is 13.27 microcoulombs and the positive one has a charge of 58.27 microcoulombs.

Explanation:

Electric potential energy between two point charges is derived from concept of Work, Work-Energy Theorem and Coulomb's Law and described by the following formula:

[tex]U_{e} = \frac{k\cdot q_{A}\cdot q_{B}}{r}[/tex] (1)

Where:

[tex]U_{e}[/tex] - Electric potential energy, measured in joules.

[tex]q_{A}[/tex], [tex]q_{B}[/tex] - Electric charges, measured in coulombs.

[tex]r[/tex] - Distance between charges, measured in meters.

[tex]k[/tex] - Coulomb's constant, measured in kilogram-cubic meters per square second-square coulomb.

If we know that [tex]U_{e} = -24\,J[/tex], [tex]q_{A} = 45\times 10^{-6}\,C+ q_{B}[/tex], [tex]k = 9\times 10^{9}\,\frac{kg\cdot m^{3}}{s^{2}\cdot C^{2}}[/tex] and [tex]r = 0.29\,m[/tex], then the electric charge is:

[tex]-24\,J = -\frac{\left(9\times 10^{9}\,\frac{kg\cdot m^{3}}{s^{2}\cdot C^{2}} \right)\cdot (45\times 10^{-6}\,C+q_{B})\cdot q_{B}}{0.29\,m}[/tex]

[tex]-6.96 = -405000\cdot q_{B}-9\times 10^{9}\cdot q_{B}^{2}[/tex]

[tex]9\times 10^{9}\cdot q_{B}^{2}+405000\cdot q_{B} -6.96 = 0[/tex] (2)

Roots of the polynomial are found by Quadratic Formula:

[tex]q_{B,1} = 1.327\times 10^{-5}\,C[/tex], [tex]q_{B,2} \approx -5.827\times 10^{-5}\,C[/tex]

Only the first roots offer a solution that is physically reasonable. The charge of the negative one is 13.27 microcoulombs and the positive one has a charge of 58.27 microcoulombs.

a) A bus of mass 760 kg requires 120 m to reach certain velocity value Vf. Ignore friction and drag forces and assume the bus engine exerts a constant forward force F. When the bus is towing a 330-kg small car, how long distance needed to reach same Vf? b) If the Vf of the bus is 28 m/s, what is the tension in the tow cable between bus and small car?

Answers

Answer:

Given :  A bus of mass 760 kg requires 120 m to reach certain velocity value Vf.

the bus engine exerts a constant forward force F.

To Find : When the bus is towing a 330-kg small car, how long distance needed to reach same Vf?

Solution:

V²  - U² = 2aS

V = Vf

U = 0

S = 120 m

=> Vf² - 0 = 2a(120)

=> Vf² = 240a

m = 760  kg

Force = F

F = ma

=> F =760 a

=> a = F/760

Vf² = 240F/760

Case 2  :When the bus is towing a 330-kg small car,

m = 760 + 330 = 1090 kg

a = F/1090

Vf²  = 2aS

=> 240F/760  = 2 (F/1090) S

=> S = 120 x 1090 /760

=> S = 172.1   m  

172.1   m   distance needed to reach same Vf

Explanation:

The levels of organization are Cell, Tissue, Organs, ____________, and Organism. what goes in the blank?

Answers

Answer:

Organ system because multiple organs make up an organ system and multiple organ systems make up an organism

organ systems is next

A basketball is picked up off the ground and carried to the top of a platform that is 160 feet up. It is then dropped to the ground. The ball rebounds one-half the height each time it hits the ground. What is the total vertical distance the ball will travel from the moment it is picked up to the moment it reaches its maximum height after the fourth bounce

Answers

Answer:

Explanation:

The total distance travelled by ball before first bounce

= 160 + 160 = 320 ft

Distance travelled between first bounce and second bounce

= 80 + 80 = 160 ft

Distance travelled between second bounce and third bounce

= 40 + 40 = 80 ft

Distance travelled between third bounce and fourth bounce

= 20 + 20 = 40 ft .

Distance travelled in fourth bounce = 10 ft

Total distance travelled = 320 + 160 + 80 + 40 + 10

= 610 ft .

an airplane normally flying at 80 km/h north encounters a wind from the west of 10km/h at right angle to its foward motion a crosswind what will its resultant velocity be ?

Answers

Answer:

v = 80.62 km/h

Explanation:

Given that,

An airplane normally flying at 80 km/h north encounters a wind from the west of 10km/h at right angle to its forward motion a crosswind.

We need to find the resultant velocity of the airplane. It can be calculated as follows :

[tex]v=\sqrt{80^2+10^2} \\\\v=80.62\ km/h[/tex]

So, the required velocity is 80.62 km/h.

While camping in a tent on a cold night, which would keep you warmer for a longer period of time. a 10 kg
bag of hot iron pellets or a 10 kg bag of hot water at the same temperature? Explain. PLEASE ANSWER

Answers

Answer:

a 10 kg bag of hot water at the same temperature

Explanation:

A 10kg bag of hot water at the same temperature will retain heat much better and keep the tent warmer at night compared to the iron pellet.

Water has a very large specific heat capacity. The specific heat capacity of water allows for it to retain heat better. It takes a larger amount of heat to warm water compared to iron which is a better conductor. In like manner, it takes more time for water to lose that amount of heat it has gained by the heating process. This is why it is a better choice to keep the room warm

What is one characteristic of an electron?

Answers

Answer:

A is the best character that defines an electron.

how does a battery work?

Answers

Answer:

Essentials. A battery is a device that stores chemical energy and converts it to electrical energy. The chemical reactions in a battery involve the flow of electrons from one material (electrode) to another, through an external circuit. The flow of electrons provides an electric current that can be used to do work.

A protein molecule in an electrophoresis gel has a negative charge. The exact charge depends on the pHpH of the solution, but 30 excess electrons is typical. What is the magnitude of the electric forceon a protein with this charge in a 1500 N/C electric field?

Answers

Answer:

The magnitude of the force = 7.2 × 10⁻¹⁵ C

Explanation:

The total quantization of charge q on an electron = n × e

where;

n = 30

e = 1.6 × 10⁻¹⁸ C

q = 30 ×  1.6 × 10⁻¹⁸ C

q = 4.8 × 10⁻¹⁸ C

Now, the magnitude of the force is determined by using the formula:

F = qE

F = ( 4.8 × 10⁻¹⁸ C) ( 1500  N/C)

F = 7.2 × 10⁻¹⁵ C

Q1. A man wants to install a surveillance mirror in his shop, which mirror should he use?(1)

a) Convex mirror

b) Concave mirror

c) Plane mirror

d) Both (a) and (b)​

Answers

answer is convex mirror

Explanation:

A

Because convex mirror will provide maximum view

3.
What is a star? Why does the sun appear so big whereas the other stars do not?
Ans.​

Answers

The sun is a star,The sun appears larger since it’s only 91.4 million miles from earth which in the other hand the other stars are further way so it all has to do with the range of the stars

Sultan travels 40 km north then 60 km west to reach the stadium and watch the football match. What
is Sultan's displacement?​

Answers

Answer:

sultan's displacement is

[tex]20 \sqrt{13} [/tex] km

If a woman walks at a speed of 5 miles/hour for 3 hours, she will have walked how many miles?

Answers

i think it would be 15, because i think you have to multiply 3x5.

i hope this helps! :)

The distance walked by the woman at the given speed an time, is 15 miles.

What is meant by speed?

The speed of an object is defined as the rate of change of the distance travelled by the object.

Here,

Speed with which the woman is walking,

v = 5 miles/hour

Time taken by the woman for walking,

t = 3 hours

We know speed is the rate of change of distance,

v = d/t  where d is the distance travelled by the woman

So, d = v x t

 d = 5 x 3

 d = 15 miles

Hence,

The distance walked by the woman at the given speed an time, is 15 miles.

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A cell phone weighing 80 grams is flying through the air at 15 m/s what is the kinetic energy

Answers

Answer:

[tex]9\:\mathrm{J}[/tex]

Explanation:

Kinetic energy is given by the following equation:

[tex]KE=\frac{1}{2}mv^2[/tex], where [tex]m[/tex] is mass in [tex]\mathrm{kg}[/tex] and [tex]v[/tex] is velocity in [tex]\mathrm{m/s}[/tex].

Since the cell phone's mass is given in grams, we need to convert this into kilograms:

[tex]80\:\mathrm{g}\cdot \frac{1\:\mathrm{kg}}{1000\:\mathrm{g}}=0.08\:\mathrm{kg}[/tex].

Therefore, the kinetic energy of the cell phone is:

[tex]KE=\frac{1}{2}\cdot 0.08\cdot 15^2=\fbox{$9\:\mathrm{J}$}[/tex].

A bicycle racer rides from a starting marker to a turnaround marker at 10 m/s. She then rides back along the same route from the turnaround marker to the starting marker at 16 m/s. What is her average speed for the whole race?

Answers

Answer:

12.31 m/s

Explanation:

If we recall from the previous knowledge we had about speed,

we will know that:

speed = distance/ time.

As such:

The average speed of the rider bicycle is

average speed = total distance/ total time

Mathematically, it can be computed as:

[tex]v_{avg} = \dfrac{d+d}{\dfrac{d}{v_1}+ \dfrac{d}{v_2}}[/tex]

[tex]v_{avg} = \dfrac{2d}{\dfrac{d}{10 \ m/s}+ \dfrac{d}{16 \ m/s}}[/tex]

[tex]v_{avg} = \dfrac{2}{\dfrac{1}{10 \ m/s}+ \dfrac{1}{16 \ m/s}}[/tex]

[tex]v_{avg} = \dfrac{2}{\dfrac{13}{80 \ m/s}}[/tex]

[tex]\mathbf{v_{avg} =12.31 \ m/s}[/tex]

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