help me please!!!


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Answer:

-2 - 24i

Step-by-step explanation:

a + bi + (7 - 3i) + (5 + 9i) + 13i = 10 - 5i

a + bi + 7 + 5  - 3i + 9i + 13i = 10 - 5i

                a + bi  + 12  + 19i = 10 - 5i

                         a + bi          = 10 - 5i - 12 - 9i

                                 a + bi = 10 - 12 - 5i - 9i

                                 a + bi = -2 - 24i

Use Euler’s Formula to find the missing number.

18

Answer:

Use Euler’s Formula to find the missing number.

Faces: __8__

Edges: 15

Vertices: 9

Answer is 8

Step-by-step explanation:

Answer:

17》6

18》12

19》8

20》3

21》2

the bar with age 18 this is because as you minus from both sides the middle number will be in age 18

Answer:

-6

Step-by-step explanation:

is it

Answer: she has 15 dimes and 45 pennies.

Step-by-step explanation:

01p+1d=1.95

p=3d

01(3d)+.1d=1.95

p=3.15

03d+.1d=1.95

p=45

.13d=1.95

d=15

Step-by-step explanation:

Ratio

= Difference between Prediction and Actual / Prediction

= (99 - 88)/99 = 11/99.

Percentage Error

= Difference between Prediction and Actual * 100%

= (99 - 88) * 100% = 11.1%. (1)

The ratio (a) & percent error (b) will be option A which is a=11/99 and b= 11.11% respectively

Approximate value = 99 frames

Exact value = 88 frames

∴ Ratio (a) = (99-88)/99

∴ a = 11/99

∴ Percent error (b) = (11/99) x 100

∴ b = 11.11%

So, the answer of ratio (a) & percent error (b) will be 11/99 and 11.11% respectively

Learn more about Ratio and percent error here:

https://brainly.com/question/5493941

#SPJ2

True.

Hope this helped!

Answer:

I would say true

Step-by-step explanation:

Answer:

1.9059 x 10 -12

Step-by-step explanation:

Answer:

[tex](a)[/tex] [tex]C(x)=500+20x-5x^{\frac{3}{4}}+0.01x^2[/tex]

    [tex]p(x)=320-7.7p[/tex]

    [tex]R(x)=(320-7.7p)p=320p-7.7p^2[/tex]

[tex](b)[/tex] [tex]x=82 \text{planes}[/tex]

[tex](c)[/tex] [tex]p=\$30.91 M\;\; \text{per plane}[/tex]

[tex](d)[/tex] maximum profit [tex]=\$ 15.90M[/tex]

Step-by-step explanation:

Given that,

The company estimates that the initial cost of designing the aeroplane and setting up the factories in which to build it will be 500 million dollars.

The additional cost of manufacturing each plane can be modelled by the function.

[tex]m(x)=20x-5x^{\frac{3}{4}}+0.01x^2[/tex]

[tex](a)[/tex]  Find the cost, demand (or price), and revenue functions.

   [tex]C(x)=500+20x-5x^{\frac{3}{4}}+0.01x^2[/tex]

   [tex]p(x)=320-7.7p[/tex]

   [tex]R(x)=(320-7.7p)p=320p-7.7p^2[/tex]

[tex](b)[/tex]  Find the production level that maximizes profit.

    [tex]f=R(x)-C(x)[/tex]

 [tex]\Rightarrow f=320p-7.7p^2-(500+20x-5x^{\frac{3}{4}}+0.01x^2)[/tex]

[tex]\Rightarrow df=320dp-15.4pdp-20dx+5(\frac{3}{4} )x^{\frac{-1}{4} }dx-0.02xdx[/tex]

     [tex]x=320-7.7p[/tex]

     [tex]p=\frac{320-x}{7.7}[/tex]

    [tex]\frac{dp}{dx} = \frac{-1}{7.7}[/tex]

[tex]\frac{df}{dx}=\frac{320}{-7.7} -\frac{15.4(320-x) }{7.7(\frac{-1}{7.7} )}-20+5\frac{3}{4} x^{\frac{-1}{4}} -0.02x=0[/tex]

    [tex]\Rightarrow -41.5584+83.1169-0.2597x-20+3.75x^{\frac{-1}{4} }-0.02x=0[/tex]

   [tex]\Rightarrow 21.5585+3.75x^{\frac{-1}{4} }-0.279x=0[/tex]

   [tex]\Rightarrow x=82 \text{planes}[/tex]

[tex](c)[/tex]  Find the associated selling price of the aircraft that maximizes profit.

  [tex]p=\frac{320-82}{7.7}[/tex]

[tex]\Rightarrow p=\$30.91 M\;\; \text{per plane}[/tex]

[tex](d)[/tex]  Find the maximum profit.

Manufacturing cost of one plane is:

[tex]m(1)=20-5+0.01[/tex]

         [tex]=\$15.01 M[/tex]

maximum profit [tex]=\$(30.91-15.01)M[/tex]

                           [tex]=\$15.90M[/tex]

Answer:

B v D v M ;

(B ٨ M) V (B ٨ D) V (M ٨ D) ;

B V (D ٨ M)

Step-by-step explanation:

Given :

B : Applicant present a birth certificate

D: Applicant presents a drivers license

M applicant presents a marriage license

1.)

This means that any one of the three must be presented :

Birth certificate OR Driver's license OR Marriage certificate

B v D v M

2.)

This means any two combination of the three certificates :

(birth certificate and marriage certificate) OR (birth certificate and driver's license) OR (marriage certificate and driver's license)

(B ٨ M) V (B ٨ D) V (M ٨ D)

3.)

That is birth certificate alone will suffice or a driver's incense and a marriage certificate

B V (D ٨ M)

Answer:

I am not sure but sold of the say 2,334

Answer:

58 child tickets

Step-by-step explanation:

5.7(x)+9.8(149-x)=1222.40

5.7x+1460.2-9.8x=1222.40

1460.2-4.1x=1222.40

-4.1x=-237.8

x=58

Answer:

okay so look

Step-by-step explanation:

you calculate the area of the whole square then the area of the triangle , then you subtract the area of the square with the area of the triangle so you'll get the area of the blue region

Answer:

13x+23.5

Step-by-step explanation: I dont know how to explain

Graph this function.

f(t) = -1/3x + 8

Find the asymptotes

Vertical Asymptotes:

[tex]x = 0[/tex]

Horizontal Asymptotes:

[tex]y = 8[/tex]

No oblique asymptotes

HopeItHelps you

#CarryOnLearning

Answer:

Bee is correct .

Step-by-step explanation:

AI thought that while proving congruent , he/she need to look at the closest side.This thinking is wrong.

Answer:

z = 25

Step-by-step explanation:

adjacent angles in a rhombus are supplementary

3z - 15 + 7z - 55 = 180

10z - 70 = 180

10z = 250

z = 25

Answer:

152.4 cm

Step-by-step explanation:

multiply the length value by 30.48

Answer:

x=8

Step-by-step explanation:

44-20=24

24/4=8

Answer:

77.3

Step-by-step explanation:

V=lwh

4.6*4.2*4.0=77.28

77.28 to the nearest tenth is 77.3

Answer:

Please check the explanation.

Step-by-step explanation:

Given the quadratic equation

5x²−2x−9 = 0

To factor the quadratic function 5x²−2x−9, we should solve the corresponding quadratic equation 5x²−2x−9 = 0.

Indeed, if x₁ and x₂ are the roots of the quadratic equation ax²+bx+c=0, then

ax²+bx+c = a(x-x₁)(x-x₂)

Now,

solving the quadratic function 5x²−2x−9 = 0

[tex]-5x^2+2x+9=0[/tex]

subtract 9 from both sides

[tex]-5x^2+2x+9-9=0-9[/tex]

Simplify

[tex]-5x^2+2x=-9[/tex]

Divide both sides by -5

[tex]\frac{-5x^2+2x}{-5}=\frac{-9}{-5}[/tex]

[tex]x^2-\frac{2x}{5}=\frac{9}{5}[/tex]

Add (-1/5)² to both sides

[tex]x^2-\frac{2x}{5}+\left(-\frac{1}{5}\right)^2=\frac{9}{5}+\left(-\frac{1}{5}\right)^2[/tex]

[tex]x^2-\frac{2x}{5}+\left(-\frac{1}{5}\right)^2=\frac{46}{25}[/tex]

[tex]\left(x-\frac{1}{5}\right)^2=\frac{46}{25} \\[/tex]

[tex]\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}[/tex]

so solving

[tex]x-\frac{1}{5}=\sqrt{\frac{46}{25}}[/tex]

[tex]x-\frac{1}{5}=\frac{\sqrt{46}}{\sqrt{25}}[/tex]

Add 1/5 to both sides

[tex]x-\frac{1}{5}+\frac{1}{5}=\frac{\sqrt{46}}{5}+\frac{1}{5}[/tex]

[tex]x=\frac{\sqrt{46}+1}{5}[/tex]

similarly solving

[tex]x-\frac{1}{5}=-\sqrt{\frac{46}{25}}[/tex]

[tex]x-\frac{1}{5}=-\frac{\sqrt{46}}{5}[/tex]

Add 1/5 to both sides

[tex]x-\frac{1}{5}+\frac{1}{5}=-\frac{\sqrt{46}}{5}+\frac{1}{5}[/tex]

[tex]x=\frac{-\sqrt{46}+1}{5}[/tex]

Thus, the roots are:

[tex]x_{1} =\frac{\sqrt{46}+1}{5},\:x_{2}=\frac{-\sqrt{46}+1}{5}[/tex]

Conclusion:

Since the roots are irrational, we do not factor further.

Therefore, we leave 5x²−2x−9 as it is.

Answer:

x= -2

Step-by-step explanation:

Answer:

167

Step-by-step explanation:

from 50-60 we have 30 students

60-70. 50 students

70-80. 45 students

80-90. 27 students

90-100. 15 students

30+50+45+27+15= 167

167 students passed

Answer:

167

Step-by-step explanation:

30+50+45+27+15=167

Answer:

I am not sure about that

Answer: D. The equation has infinitely many solutions.

Step-by-step explanation:

Given equation: [tex]-9(x + 3) + 12 = -3(2x + 5) - 3x[/tex]

[tex]\Rightarrow -9(x)+(-9)(3)+12=(-3)(2x)+(-3)(5)-3x\\\\\Rightarrow\ -9x-27+12=-6x-15-3x\\\\\Rightarrow\ -9x-15=-9x-15\\\\\Rightarrow\ -9x+9x=-15+15\\\\\Rightarrow\ 0=0[/tex]

which is true.

This happens when all numbers are solutions.

i.e. The equation has infinitely many solutions.

Correct option : D.

Answer:

[tex]Mean = 7[/tex]

Step-by-step explanation:

Given

[tex]Data: 2, 4, 6, 12, 8, 10.[/tex]

Required

Determine the mean

The mean of a data is calculated as thus:

[tex]Mean = \frac{\sum x}{n}[/tex]

In this case:

[tex]n = 6[/tex]

So, the formula becomes:

[tex]Mean = \frac{2+4+6+12+8+10}{6}[/tex]

[tex]Mean = \frac{42}{6}[/tex]

[tex]Mean = 7[/tex]